Given data:
The given sets of equations.
The polynomial in which degree of the variable is 1 is said to be linear expression.
The first option 2x+3y=6 is only linear function.
Thus, the option (A) is correct.
You draw 7 cards from a standard deck of cards. What is the probability of drawing 3 diamonds and 2 clubs?
Solution
For this case we can do the following:
[tex]p=\frac{\text{possible}}{\text{total}}[/tex]and we can find the answer with this:
[tex]p=\frac{(13C3)(13C2)(26C2)}{52C7}=0.0541[/tex]In which month was the average temperature closest to 0°C ?
GWhich inequalities have no solution? Check all of the boxes that apply.XX-3x -3x–4 + x>-2 + xX-2
For every number x, x = x, not x < x. So, the inequality x < x has no solution.
Since -3x = -3x for every real number, the inequality
[tex]-3x\leq-3x[/tex]holds for every real number, that is, every number is a solution.
Consider the inequality
[tex]-4+x>-2+x[/tex]Subtract x on both sides gives -4 > -2, which is not possible.
Hence the inequality - 4 + x > - 2 + x has no solution.
Consider the inequality
[tex]x-2Subtract x on both sides gives -2 < 3, which is true.Every real number is a solution of the inequality. Hence the inequality has solution.
Thus the inequalities with no solution are: x < x and -4+x>-2+x
Julian is decorating the outside of a box in the shape of a right rectangular prism. Thefigure below shows a net for the box.
The surface area of the box equals the sum of the surface area of each of its parts.
And the area of each rectangle that form the box is found by multiplying the width by the height of that rectangle.
We have two ractangles with sides 7 ft and 10 ft. So the area of each one is:
7 ft * 10 ft = 7 * 10 * ft * ft = 70 ft²
Since there's two of this rectangle, their areas sum up to
2 * 70 ft² = 140 ft²
Now, we also have two rectangles with sides 7 ft and 14 ft (the second and the fourth rectangles from left to right in the image). So, their areas sum up to:
2 * (7 ft * 14 ft) = 2 * (98 ft²) = 196 ft²
Finally, we also have two rectangles with sides 10 ft and 14 ft. Then, their area together is:
2 * (10 ft * 14 ft) = 2 * (140 ft²) = 280 ft²
Therefore the total surface area of the box is the sum:
140 ft² + 196 ft² + 280 ft² = 616 ft²
A tree on a hillside casts a shadow c = 215 ft down the hill. If the angle of inclination of the hillside is b = 23° to the horizontal and the angle of elevation of the sun is a = 53, find the height of the tree. (Round your answer to the nearest foot.)
This is the figure, roughly. We want h.
Using smaller triangle, we can write:
[tex]\begin{gathered} \text{Cos}23=\frac{x}{215} \\ x=215\cdot\cos 23 \\ x=197.9 \end{gathered}[/tex]Also,
[tex]\begin{gathered} y=215\cdot\sin 23 \\ y=84 \end{gathered}[/tex]Now, taking the larger triangle:
The angle is 53 (30 + 23).
Let the larger side (right side) be m, which is basically:
m = h + y
Let's find m:
[tex]\begin{gathered} \tan 53=\frac{m}{x} \\ \tan 53=\frac{m}{197.9} \\ m=197.9\cdot\tan 53 \\ m=262.62 \end{gathered}[/tex]Now, we want height, h, which is:
m = h + y
262.62 = h + 84
h = 262.62 - 84
h = 178.62
Rounded to nearest feet
h = 179 feet
plant A produced 3 times as many panels as plant b. two percent of the panels from plant A and 5% of the panels from plant b were defective. how many panels did plant b produce if the two plants together produced 990 defective panels
let x the number of panels that Plant A produced
y the number of panels that Plant B produced
then, we have
x = 3y
0.02x + 0.05y = 990
and solve the system:
[tex]\begin{gathered} 0.02(3y)+0.05y=990 \\ 0.06y+0.05y=990 \\ 0.11y=990 \\ \frac{0.11y}{0.11}=\frac{990}{0.11} \\ y=9000 \end{gathered}[/tex]answer: plant b produced 9000 panels
the prompt is in the photo
By using the given box and whisker plot, the number of students that earned a score from 77 and 90 is: N. 13.
What is a box and whisker plot?A box and whisker plot is also referred to as boxplot and it can be defined as a type of chart that can be used to graphically represent the five-number summary of a data set with respect to locality, skewness, and spread.
In Mathematics, the five-number summary of any box and whisker plot include the following:
MinimumFirst quartileMedianThird quartileMaximumWhat is an interquartile range?IQR is an abbreviation for interquartile range and it can be defined as a measure of the middle 50% of data values when they are ordered from lowest to highest.
Mathematically, interquartile range (IQR) is the difference between first quartile (Q₁) and third quartile (Q₃):
IQR = Q₃ - Q₁
Based on the given box and whisker plot, we can logically deduce the following quartile ranges:
Third quartile, Q₃ = 90
First quartile, Q₁ = 77
Now, we can calculate the interquartile range (IQR) is given by:
Interquartile range, IQR = Q₃ - Q₁
Interquartile range, IQR = 90 - 17
Interquartile range, IQR = 13
Read more on interquartile here: https://brainly.com/question/17083142
#SPJ1
Options for this are: 20 of the best selling cameras, same photographer, 100 pictures with each camera, consistent across all cameras 10 point scale, two were from companies who are major advertisers
It is given that:
A writer for a magazine recently did a test to determine which mid-range digital camera takes the best pictures. Her method is described below.
Which part of the method describes an area of potential bias?
She gathered 20 of the best.selling cameras and used the same photographer to take 100 pictures with each camera .She ensured that the environment and the subject of each picture were consistent across all cameras and used a 10.point scale to determine picture quality. Of the cameras tested, two were from companies who are major advertisers in the magazine.
Now if the reading is done carefully, it can be concluded that the information given by:
"Of the cameras tested, two were from companies who are major advertisers in the magazine." can be considered for a potential bias since the magazine may be pressured by these two companies to give them a higher rating than they deserve.
So the option:two were from companies who are major advertisers is correct.
Gabrielle is 8 years older than Mikhail. The sum of their ages is 104. What is Mikhail's age?
Let x represent Mikhail's age.
Since Gabrielle is 8 years older than Mikhail, it means that Gabrielle's age is
x + 8
If the sum of their ages is 104, it means that
x + x + 8 = 104
2x = 104 - 8
2x = 96
x = 96/2
x = 48
Mikhail's age is 48
35+3(8-4)
(please explain how you did it)
Answer:47
Step-by-step explanation: First multiply 3x8=24 then subtract 3x4=12 from it. Which will get you 12 then add 35 to 12 which will get you 47.
35 + 3(8-4) = ?
Do the parentheses first : 8 - 4 = 4
= 35 + 3(4)
Then multiply- that's the one that is in parentheses : 3 x 4 = 12
= 35 + 12
Then just straight up add : 35 + 12 = 47
35 + 3(8-4) = 47
So ? = 47
A Snack company can pack 15 granola bars in a box how many boxes are needed for 600 granola bars ?
Answer:40
Step-by-step explanation: 15 bars to a box.
600 bars in total.
600/15= 40
40 boxes of granola bars
The table shows the number of hours spent practicingsinging each week in three samples of 10 randomlyselected chorus members.Time spent practicing singing each week (hours)Sample 1 45873 56 579 Mean = 5.9Sample 2 68 74 5 4 8 4 5 7 Mean = 5.8Sample 3 8 4 6 5 6 4 7 5 93 Mean = 5.7Which statement is most accurate based on the data?O A. A prediction based on the data is not completely reliable, becausethe means are not the same.B. A prediction based on the data is reliable, because the means ofthe samples are close together.O C. A prediction based on the data is reliable, because each samplehas 10 data points.D. A prediction based on the data is not completely reliable, becausethe means are too close together.
The means of three samples are close together. Therefore, option B is the correct answer.
In the given table 3 sample means are given.
What is mean?In statistics, the mean refers to the average of a set of values. The mean can be computed in a number of ways, including the simple arithmetic mean (add up the numbers and divide the total by the number of observations).
Here, mean of sample 1 is 5.9, mean of sample 2 is 5.8 and mean of sample 3 is 5.7.
Thus, means of these three samples are close together.
The means of three samples are close together. Therefore, option B is the correct answer.
To learn more about an arithmetic mean visit:
https://brainly.com/question/15196910.
#SPJ1
Evaluate f(2) and f(2.1) and use the results to approximate f '(2). (Round your answer to one decimal place.)f(x) = x(9 − x)f '(2) ≈
Given a function f(x) = x(9 - x).
We need to find the value of f(2) and f(2.1) and use them to approximate the value of f'(2).
The value of f(2) is calculated below:
[tex]\begin{gathered} f(2)=2(9-2) \\ =2(7) \\ =14 \end{gathered}[/tex]The value of the f(2.1) is calculated as follows:
[tex]\begin{gathered} f(2.1)=2.1(9-2.1) \\ =2.1(6.9) \\ =14.49 \end{gathered}[/tex]Now, by the definition of f'(x), we know that
[tex]f^{\prime}(x)=\frac{f(x+\Delta x)-f(x)}{(x+\Delta x)-x}=\frac{f(x+\Delta x)-f(x)}{\Delta x}[/tex]For the given condition, x = 2, and delta x = 0.1. So, the value of f'(2) is
[tex]\begin{gathered} f^{\prime}(2)=\frac{f(2+0.1)-f(2)}{0.1} \\ =\frac{f(2.1)-f(2)}{0.1} \\ =\frac{14.49-14}{0.1} \\ =\frac{0.49}{0.1} \\ =4.9 \end{gathered}[/tex]Thus, the approximate value of f'(2) is 4.9.
P. The Shah family basement floor is shaped like a trapezoid. The basement has sides of and 24 feet and two sides of 21 feet. They are going to carpet the basement. The carpeting will cost $35 per square yard. A. What is the area, in square feet, of the basement foor? Show your work. B. What is the cost to carpet the basement floor? Explain how you found your answer
A.
In order to calculate the area of the trapezoid, we need to calculate its height:
Using the Pythagorean Theorem, we have:
[tex]\begin{gathered} 21^2=h^2+6^2 \\ 441=h^2+36 \\ h^2=441-36 \\ h^2=405 \\ h=20.12 \end{gathered}[/tex]Now, calculating the area:
[tex]\begin{gathered} A=\frac{(B+b)h}{2} \\ A=\frac{(36+24)20.12}{2} \\ A=60\cdot10.06 \\ A=603.6 \end{gathered}[/tex]B.
If each square yard is $35, first let's convert the area from ft² to yd² (1 yard = 3 feet, 1 yd² = 9 ft²):
[tex]A=603.6\text{ ft}^2=\frac{603.6}{9}\text{ yd}^2=67.07[/tex]So the total cost is:
[tex]\text{cost}=67.07\cdot35=2347.45[/tex]So the cost is approximately $2347.45.
Solve the equation. f(x)=g(x) by graphing. f(x) = l x +5 l g(x) = 2x + 2 Select all possible solutions: No Solutions x=3 x=0 X=-1
As you can observe in the graph below, the given functions intercept at one point.
Hence, there is a unique solution and it's x = 3.In a game of cornhole, Sasha tossed a bean bag and it landed at the edge of the hole. The hole can be represented by the equation x^2+ y^2= 5, and the path of the bean bag canbe represented by y = -0.5x^2 -1.5x + 4. To which points could she have tossed her bean bag?(-1,-2) or (-2, 1)(1.-2) or (2,1)(-1,2) or (-2,-1)(1, 2) or (2, -1)
We have two equations, the first is a circle, which we can identify by the characteristic form of the equation:
[tex]x^2+y^2=5[/tex]The second is a quadratic equation:
[tex]y=-0.5x^2-1.5x+4[/tex]We know that Sasha got the bag to land in the edge of the circle defined by the hole, equation 1.
So, to know the points at which the bag landed, we can look for th eintersection of the two equations, which is the same as solving a system of equations:
[tex]\begin{gathered} x^2+y^2=5 \\ y=-0.5x^2-1.5x+4 \end{gathered}[/tex]Since we have been given alternatives, we can check them to get the correct answer.
The first option is (-1,-2) or (-2,1). Since the sign of the alternatives are the only thing that change and the circle equation doesn't differenciate the signs, the best equation to test first is the second one. Let's try that for (-1,-2).
[tex]\begin{gathered} y=-0.5(-1)^2-1.5(-1)+4 \\ y=-0.5+1.5+4=5 \end{gathered}[/tex]We got y = 5, which is not -2, so this alternative is incorrect.
Let's got for the second alternative, (1.-2) or (2,1):
[tex]y=-0.5(1)^2-1.5\cdot1+4=2[/tex]This is also incorrect.
The third alternative is (-1,2) or (-2,-1), we already saw that for x = -1, y = 5, which makes this alternative also incorrect.
Let's check if the last one will be correct, (1, 2) or (2, -1). We already saw that for x = 1, y = 2 in the second equation, let's check if this is also correct for the first:
[tex]\begin{gathered} (1)^2+y^2=5 \\ y^2=5-1=4 \\ y=\pm2 \end{gathered}[/tex]One of the results is y = 2, so this also checks out.
The other point is (2,-1), let's check in both equations:
[tex]\begin{gathered} (2)^2+y^2=5 \\ 4+y^2=5 \\ y^2=1 \\ y=\pm1 \end{gathered}[/tex]Checks out, and:
[tex]\begin{gathered} y=-0.5(2)^2-1.5\cdot2+4 \\ y=-2-3+4=-1 \end{gathered}[/tex]And the "y" checks out too.
So, the correct alternative is the last one: (1, 2) or (2, -1).
Which of the following statements follows from (x - 3)2 = 7? ox2 +9=7 Ox-3=1 / OX-3 = +49 NEXT QUESTION O ASK FOR HELP
So, given the equation:
We could take the square root to both sides of the equation to obtain that:
So the correct option is B.
Which of these steps will eliminate a variable in this system?3x-3y=66x+9y=3OA. Multiply the first equation by 3. Then subtract the second equationfrom the first.B. Multiply the first equation by 2. Then add the equations.C. Multiply the first equation by 2. Then subtract the second equationfrom the first.OD. Multiply the second equation by 2. Then subtract the secondequation from the first.
The given system of equation is:
[tex]\begin{gathered} 3x-3y=6 \\ 6x+9y=3 \end{gathered}[/tex]Multiply through the first equation by 2:
[tex]\begin{gathered} 6x-6y=12 \\ 6x+9y=3 \end{gathered}[/tex]Subtract the second equation from the first equation to get:
[tex]-15y=9[/tex]Therefore, the steps that will eliminate the variable x are:
Multiply the first equation by 2. Then subtract the second equation from the first.
Choice C
(b) The area of a rectangular window is 3740 cmcm?If the length of the window is 68 cm, what is its width?Width of the windoow
Step 1
The area of a rectangle = Length x width
Step 2
Parameters given include
Area of rectangular window= 3740 square cm
Length of window = 68cm
Step 3
Substitute and solve
[tex]\begin{gathered} 3740\text{ = 68 x width} \\ \text{width = }\frac{3740}{68}\text{ = 55cm} \end{gathered}[/tex]Therefore, the width of the window = 55 cm
Solving triangles using the law of cosines . Find m
The law of cosines is defined as follows:
[tex]a^2=b^2+c^2-2bc\cos A[/tex]For the given triangle
a=AC=8
b=AB=14
c=BC=11
∠A=∠B=?
-Replace the lengths of the sides on the expression
[tex]8^2=14^2+11^2-2\cdot14\cdot11\cdot\cos B[/tex]-Solve the exponents and the multiplication
[tex]\begin{gathered} 64=196+121-308\cos B \\ 64=317-308\cos B \end{gathered}[/tex]-Pass 317 to the left side of the expression by applying the opposite operation to both sides of it
[tex]\begin{gathered} 64-317=317-317-308\cos B \\ -253=-308\cos B \end{gathered}[/tex]-Divide both sides by -308
[tex]\begin{gathered} -\frac{253}{-308}=-\frac{308\cos B}{-308} \\ \frac{23}{28}=\cos B \end{gathered}[/tex]-Apply the inverse cosine to both sides of the expression to determine the measure of ∠B
[tex]\begin{gathered} \cos ^{-1}\frac{23}{28}=\cos ^{-1}(\cos B) \\ 34.77º=B \end{gathered}[/tex]The measure of ∠B is 34.77º
Graph the image of rectangular TUVW after a translation 5 units right and 4 units up.
From the rectangle TUVW, the coordinates of the points are shown below:
T(-5, -5), U(-1, -5), V(-1, 4), and W(-5, 4)
If TUVW is translated 5 units right and 4 units up, the coordinates of the new rectangle are in the form (x+5, y+4):
T'(0, -1), U'(4, -1), V'(4, 8), and W'(0, 8)
Given sin(x)=.4 and cot(x) >0 what is cos(x)?
The cotangent is given by the cosine over the sine.
If the cotangent is positive and the sine is positive, that means the cosine is also positive.
Now, in order to find the value of cos(x), we can use the following property:
[tex]\begin{gathered} \sin ^2(x)+\cos ^2(x)=1 \\ (0.4)^2+\cos ^2(x)=1 \\ 0.16+\cos ^2(x)=1 \\ \cos ^2(x)=1-0.16 \\ \cos ^2(x)=0.84 \\ \cos (x)=0.917 \end{gathered}[/tex]18. What is the probability of drawing a BLACK card with an odd number OR a card with a LETTER?A.21261B..ع1726p D. 13
Let:
A = Draw a black card
B = Draw and odd number
C = Draw a card with a letter
so:
[tex]\begin{gathered} P(A\cap B)=\frac{8}{52}=\frac{2}{13} \\ P(C)=\frac{16}{52}=\frac{4}{13} \end{gathered}[/tex]Therefore:
[tex]P((A\cap B)\cup C)=\frac{2}{13}+\frac{4}{13}=\frac{2+4}{13}=\frac{6}{13}[/tex]I don't need Jimmy wants a game for him and his son Jimmy Jr. The game he wants is $79.93 and he only has $100 in his wallet. he found a discount for 60% off for the game. how much will he save?
Answer:
$47.96
Explanation:
The cost of the game = $79.93
He found a discount for 60% off for the game.
Therefore, the amount he will save will be:
[tex]=60\%\text{ of 79.93}[/tex]We simplify our result:
[tex]\begin{gathered} =\frac{60}{100}\times79.93 \\ =\$47.96 \end{gathered}[/tex]Jimmy will save $47.96.
A bookstore sells a college algebra book for $90. If the bookstore makes a profit of 25% on each sale,what does the bookstore pay the publisher for each book?
Okay, here we have this:
Considering the provided information, we obtain that:
The total price = Commission of the bookstore + Payment to the publisher
Replacing:
$90=$90(0.25)+Payment to the publisher
Payment to the publisher=$90-$90(0.25)
Payment to the publisher=$90-$22.5
Payment to the publisher=$67.5
Finally we obtain that the bookstore pay $67.5 to the publisher for each book.
[tex]x \geqslant - 2[/tex]
PLEASE HELP!!
A)
B)
C)
D)
Answer:
B
Step-by-step explanation:
[tex]x\geq -2[/tex] means that [tex]x[/tex] can be all values that are greater than -2, and the line under the inequality sign adds that [tex]x[/tex] can be equal to it as well.
Since B represents all values of [tex]x[/tex] that are greater than -2 along with -2 itself due to the closed circle, it is the correct answer.
Answer:
it is c i took the test i hope this helps
Find all values for which at least one denominator is equal to 0.
Given:
There are given the expression:
[tex]\frac{4}{x+2}-\frac{5}{x}=1[/tex]Explanation:
To find the value of x that is equal to 0, we need to perform LCM in the denominator and then find the value for x:
Then,
From the given expression:
[tex]\begin{gathered} \frac{4}{x+2}-\frac{5}{x}=1 \\ \frac{4x-5(x+2)}{x(x+2)}=1 \end{gathered}[/tex]Then,
According to the question, the values at least one denominator is equal to .
So,
[tex]\begin{gathered} x(x+2)=0 \\ x=0 \\ x+2=0 \\ x=-2 \end{gathered}[/tex]Final answer:
Hence, the value of x is shown below:
[tex]x\ne0,-2[/tex]
What is 4x+10(2x) - 8x
4x+10(2x) - 8x
First, multiply to solve the parentheses:
4x+20x-8x
Add and subtract
16x
A brownie recipe asks for two and two thirds times as much sugar as chocolate chips. If four and one third cups of sugar is used, what quantity of chocolatechips would then be needed, according to the recipe?0308X5?
Let's call C to the cups of chocolate chips and S to the cups of sugar. We are told that the cups of sugar are 2 2/3 times the cups of chocolate, then we can formulate the following equation:
[tex]S=2\frac{2}{3}C[/tex]In the case 4 1/3 of sugar is added, we can replace 4 1/3 for S to get:
[tex]4\frac{1}{3}=2\frac{2}{3}C[/tex]By dividing both sides by 2 2/3 we get:
[tex]\begin{gathered} 4\frac{1}{3}\div2\frac{2}{3}=2\frac{2}{3}C\div2\frac{2}{3} \\ 4\frac{1}{3}\div2\frac{2}{3}=C \end{gathered}[/tex]We can rewrite the mixed fractions to get:
[tex]\begin{gathered} \frac{4\times3+1}{3}\div\frac{2\times3+2}{3}=C \\ \frac{12+1}{3}\div\frac{6+2}{3}=C \\ \frac{13}{3}\div\frac{8}{3}=C \end{gathered}[/tex]By changing the division symbol to a multiplication symbol and flipping the 8/3, we get:
[tex]\begin{gathered} \frac{13}{3}\times\frac{3}{8}=C \\ \frac{13}{8}=C \\ \frac{8+5}{8}=C \\ \frac{8}{8}+\frac{5}{8}=C \\ 1+\frac{5}{8}=C \\ 1\frac{5}{8}=C \\ C=1\frac{5}{8} \end{gathered}[/tex]Then, 1 5/8 cups of chocolate chips are needed
Construct a scatterplot and identify the mathematical model that best fits the data. Assume that the model is to be used only for the scope of the given data and consider only linear, quadratic, logarithmic, exponential, and power models. Use a calculator or computer to obtain the regression equation of the model that best fits the data. You may need to fit several models and compare the values of R2.Average sunset times are taken for six months across the summer. Giving the months April through September values 1 through 6, find the regression equation of the best model.y = –0.357x2 + 2.17x + 17.87y = 21.24 e0.983xy = 21.20 – 0.343xy = 20.62x–0.029
We will have the following:
From the options given we graph each possible solution with the data, that is:
In order:
From this, we can see that the function that best fits the data is:
[tex]y=-0.357x^2+2.17x+17.87[/tex]