Answers
From the given table, the quadratic model is given by
[tex]y=1.2x^2+13x+504.3[/tex]which corresponds to option B.
The general quadratic model is given by
[tex]y=Cx^2+Bx+A[/tex]and we need to find the constants A, B and C. They are given by
and
For instance, the variance for x, denoted by S_xx is given by
[tex]S_{x\times}=(0-20)^2+(10-20)^2+(20-20)^2+(30-20)^2+(40-20)^2[/tex]where x is the variable which corresponds to the "years since 1970" and the number 20 in each parenthesis is the mean of the this variable, that is
[tex]\bar{x}=\frac{0+10+20+30+40}{5}=20[/tex]Now, the variance S_xy is given by
Related Questions
Hi, The area of a circle is 100 quare millimeters. The radius is 5.64 millimeters. what is the circumference?
Answers
The area A of a circle is given by
[tex]A=\pi r^2[/tex]where Pi is 3.1416 and r is the radius. In our case, we get
[tex]100\operatorname{mm}=\pi r^2[/tex]and we need to find r. In this regard, if we move Pi to the left hand side we get
[tex]\frac{100}{\pi}=r^2[/tex]then, r is given by
[tex]r=\sqrt[]{\frac{100}{\pi}}[/tex]Now, the circunference C is given by
[tex]C=2\pi\text{ r}[/tex]then, by substituting our last result into this formula, we have
[tex]C=2\pi\sqrt[]{\frac{100}{\pi}}[/tex]since square root of 100 is 10, we get
[tex]C=2\pi\frac{10}{\sqrt[]{\pi}}[/tex]we can rewrite this result as
[tex]\begin{gathered} C=\frac{2\pi\times10}{\sqrt[]{\pi}} \\ C=\frac{2\sqrt[]{\pi\text{ }}\sqrt[]{\pi}\times10}{\sqrt[]{\pi}} \end{gathered}[/tex]and we can cancel out a square root of Pi. Then, we have
[tex]C=2\sqrt[]{\pi}\times10[/tex]and the circunference is
[tex]C=20\text{ }\sqrt[]{\pi}\text{ milimeters}[/tex][tex](3 {s}^{2} +9s + 3) - ( {6}s + 1)[/tex]Add and subtract polynomialsFor this one we're doin subtract!!!!
Answers
Given data:
The given expression is (3 s^2 +9s + 3) - ( 6s + 1).
The given expression can be written as,
[tex](3s^2+9s+3)-(6s+1)=3s^2+3s+2[/tex]Thus, the simplification of the given expression is 3s^2 +3s +2.
MEASUREMENT Choosing metric measurement units Fill in the blanks below with the correct units. (a) Amanda bought a candy bar. Its mass was about 50 ? (b) A dollar bill is about 15 ? long (c) The can of soda held about 350 .
Answers
Explanation
We are asked to fill in the missing blanks
Part 1
The weight of a Candy bar is in grams
So the answer will be
Amanda bought a candy bar. Its mass was about 50 grams
Part 2
A dollar bill should be about 15 centimeters
Therefore, the answer is
A dollar bill is about 15 centimeters long
Part 3
A can of soda should a capacity in mililiters
Therefore, the answer will be
The can of soda held about 350 mililiters
Find the 11th term of the arithmetic sequence -5x- 1, -8x + 4, -11 x+ 9, ...
Answers
Recall that an arithmetic sequence is a sequence in which the next term is obtained by adding a constant term to the previous one. Let us consider a1 = -5x-1 as the first term and let d be the constant term that is added to get the next term of the sequence. Using this, we get that
[tex]a_2=a_1+d[/tex]so if we replace the values, we get that
[tex]-8x+4=-5x-1+d[/tex]so, by adding 5x+1 on both sides, we get
[tex]d=-8x+4+5x+1\text{ =(-8+5)x+5=-3x+5}[/tex]To check if this value of d is correct, lets add d to a2. We should get a3.
Note that
[tex]a_2+d=-8x+4+(-3x+5)=-11x+9=a_3[/tex]so the value of d is indeed correct.
Now, note the following
[tex]a_3=a_2+d=(a_1+d)+d=a_1+2d=a_1+d\cdot(3-1)[/tex]This suggest the following formula
[tex]a_n=a_1+d\cdot(n-1)[/tex]the question is asking for the 11th term of the sequence, that is, to replace the value of n=11 in this equation, so we get
[tex]a_{11}=a_1+d\cdot(10)=-5x-1+10\cdot(-3x+5)\text{ =-5x-1-30x+50 = -35x+49}[/tex]so the 11th term of the sequence is -35x+49
Describe the transformation of f(x) that produce g(x). f(x)= 2x; g(x)= 2x/3+7Choose the correct answer below.
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The vertical translation involves shifting the graph either up or down on the y axis. For example.
[tex]\begin{gathered} y=f(x) \\ \text{translated upward }it\text{ will be } \\ y=f(x)+k \end{gathered}[/tex]When a graph is vertically compressed by a scale factor of 1/3, the graph is also compressed by that scale factor. This implies vertical compression occurs when the function is multiplied by the scale factor. Therefore,
[tex]\begin{gathered} f(x)=2x \\ \text{The vertical compression by a scale of }\frac{1}{3}\text{ will be} \\ g(x)=\frac{1}{3}(2x)=\frac{2}{3}x \end{gathered}[/tex]Finally, the vertical translation up 7 units will be as follows
[tex]g(x)=\frac{2}{3}x+7[/tex]The answer is a. There is a vertical compression by a factor of 1/3 . Then there is a vertical translation up 7 units.
Which linear inequality is represented by the graph?1. y≤ 2x+42. y≤ x+33. y²x+34. y≥ 2x+3
Answers
Given a graph represented a linear inequality.
First, we will find the equation of the shown line.
As shown, the line passes through the points (0, 3) and (2, 4)
the general equation of the line in the slope-intercept form will be:
[tex]y=mx+b[/tex]Where (m) is the slope and (b) is the y-intercept
b = y-intercept = 3
We will find the slope as follows:
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{4-3}{2-0}=\frac{1}{2}[/tex]So, the equation of the line will be:
[tex]y=\frac{1}{2}x+3[/tex]As shown, the point (0, 0) lying in the area of the solution
So, the linear inequality will be as follows:
[tex]y\leq\frac{1}{2}x+3[/tex]An insurance company offers flood insurance to customers in a certain area. Suppose they charge $500 fora given plan. Based on historical data, there is a 1% probability that a customer with this plan suffers aflood, and in those cases, the average payout from the insurance company to the customer was $10,000.Here is a table that summarizes the possible outcomes from the company's perspective:EventFloodPayout Net gain (X)$10,000 -$9,500$0$500No floodLet X represent the company's net gain from one of these plans.Calculate the expected net gain E(X).E(X) =dollars
Answers
The given is a discrete random variable.
For a discrete random variable, the expected value is calculated by summing the product of the value of the random variable and its associated probability, taken over all of the values of the random variable.
It is given that the probability of a flood is 1%=0.01.
It follows that the probability of no flood is (100-1)%=99%.
Hence, the expected net gain is:
[tex]E(X)=0.01(-9500)+0.99(500)=-95+495=400[/tex]Hence, the expected net gain is $400.
The expected net gain is E(X) = $400.
given ABCD is congruent EFGH. solve for x. Round the answers to the nearest hundredth
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As ABCD is congruent withEFGH, it means that both figures have the same mesarurements, even if their orientation is different.
Then, you have that the angle in A is congruente with the angle in E, the angle B is congruent with the angle F, the angle C is congruent with the angle G, the angle D is congruent with the angle H.
[tex]\begin{gathered} \angle A=\angle E \\ \angle B=\angle F \\ \angle C=\angle G \\ \angle D=\angle H \end{gathered}[/tex]Then:
[tex]3x^2-4x+10=16[/tex]You solve the x from the equation above:
1. Equal the equation to 0
[tex]\begin{gathered} 3x^2-4x+10-16=0 \\ 3x^2-4x-6=0 \end{gathered}[/tex]2. Use the quadratic equation:
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex][tex]\begin{gathered} x=\frac{-(-4)\pm\sqrt[]{(-4)^2-4(3)(-6)}}{2(3)} \\ x=\frac{4\pm\sqrt[]{16+72}}{6} \\ x=\frac{4\pm\sqrt[]{88}}{6} \\ x_1=\frac{4-\sqrt[]{88}}{6},x_2=\frac{4+\sqrt[]{88}}{6} \\ x_1=-0.896,x_2=2.230 \end{gathered}[/tex]3. As you get two solutions for x. You need to prove which is the right solution:
with x1:
[tex]\begin{gathered} 3x^2-4x+10=16 \\ 3(-0.896^2)-4(-0.869)+10=16 \\ 11.17\ne16 \end{gathered}[/tex]with x2:
[tex]\begin{gathered} 3x^2-4x+10=16 \\ 3(2.23^2)-4(2.23)+10=16 \\ 15.99\approx16 \end{gathered}[/tex]As you can see the right solution is x2, because if you subtitute the x in the equation of the angle A that must be equal to 16, just the x2 gives an approximate value to 16.
Then, the solution for the x is x=2.23Hi, could I have some help answering this question in the picture attached?simplify the question
Answers
Expand and collect like terms:
[tex]\begin{gathered} =\text{ }7s^{\frac{7}{4}}\times t^{\frac{-5}{3}}\times-6s^{\frac{-11}{4}}\times t^{\frac{7}{3}} \\ =\text{ }7\times s^{\frac{7}{4}}\times-6\times s^{\frac{-11}{4}}\times t^{\frac{-5}{3}}\times t^{\frac{7}{3}} \\ =\text{ 7 }\times-6\text{ }\times\text{ }s^{\frac{7}{4}}\times s^{\frac{-11}{4}}\times t^{\frac{-5}{3}}\times t^{\frac{7}{3}} \\ =\text{ -42}\times\text{ }s^{\frac{7}{4}}\times s^{\frac{-11}{4}}\times t^{\frac{-5}{3}}\times t^{\frac{7}{3}} \end{gathered}[/tex]Bring the exponents having same base together:
[tex]\begin{gathered} \text{The multiplication betwe}en\text{ same base becomes addition } \\ \text{when the exponents are brought together} \\ =-42\text{ }\times\text{ }s^{\frac{7}{4}-\frac{11}{4}}\times t^{\frac{-5}{3}+\frac{7}{3}} \\ =\text{ -42 }\times s^{\frac{7-11}{4}}\times t^{\frac{-5+7}{3}} \\ =\text{ -42 }\times s^{\frac{-4}{4}}\times t^{\frac{2}{3}} \end{gathered}[/tex][tex]\begin{gathered} =\text{ -42 }\times s^{\frac{-4}{4}}\times t^{\frac{2}{3}} \\ =\text{ -42 }\times s^{-1}\times t^{\frac{2}{3}} \\ =\text{ -42}s^{-1}t^{\frac{2}{3}} \end{gathered}[/tex]The path of a race will be drawn on a coordinate grid like the one shown below. The starting point of the race will be at (-5.3, 1). The finishing point will be at(1, -5.3). Quadranto Quadrant P Quadrant Quadrants Part A: Use the grid to determine in which quadrants the starting point and the finishing point are located. Explain how you determined the locations. (6 points) Part B: A checkpoint will be at (5.3, 1). In at least two sentences, describe the difference between the coordinates of the starting point and the checkpoint, and explain how the points are d. (4 points)
Answers
The path of a race will be drawn on a coordinate grid like the one shown below. The starting point of the race will be at (-5.3, 1). The finishing point will be at(1, -5.3). Quadranto Quadrant P Quadrant Quadrants Part A: Use the grid to determine in which quadrants the starting point and the finishing point are located. Explain how you determined the locations. (6 points) Part B: A checkpoint will be at (5.3, 1). In at least two sentences, describe the difference between the coordinates of the starting point and the checkpoint, and explain how the points are d. (4 points)
Part A
we have
starting point of the race is (-5.3, 1)
the x-coordinate is negative and the y coordinate is ;positive
that means-------> is located on quadrant Q
finishing point is (5,3, 1)
x-coordinate is postive and y coordinate is positive
that means -----> is located on Quadrant P
Answer:
Step-by-step explanation:
part A
SOMEONE PLS HELPPPPPPPP
Answers
Answer:
**NEED USEFUL ANSWER ASAP, H.W QUESTION**
Given that hotter blackbodies produce more energy than cooler blackbodies, why do cooler red giants have much higher luminosities than much hotter white dwarfs?
Step-by-step explanation:
The floor of a shed has an area of 80 square feet. The floor is in the shape of a rectangle whose length is 6 feet less than twice the width. Find the length and the width of the floor of the shed. use the formula, area= length× width The width of the floor of the shed is____ ft.
Answers
Given:
The area of the rectangular floor is, A = 8- square feet.
The length of the rectangular floor is 6 feet less than twice the width.
The objective is to find the measure of length and breadth of the floor.
Consider the width of the rectangular floor as w, then twice the width is 2w.
Since, the length is given as 6 feet less than twice the width. The length can be represented as,
[tex]l=2w-6[/tex]The general formula of area of a rectangle is,
[tex]A=l\times w[/tex]By substituting the values of length l and width w, we get,
[tex]\begin{gathered} 80=(2w-6)\times w \\ 80=2w^2-6w \\ 2w^2-6w-80=0 \end{gathered}[/tex]On factorizinng the above equation,
[tex]\begin{gathered} 2w^2-16w+10w-80=0 \\ 2w(w-8)+10(w-8)=0 \\ (2w+10)(w-8)=0 \end{gathered}[/tex]On solving the above equation,
[tex]\begin{gathered} 2w+10=0 \\ 2w=-10 \\ w=\frac{-10}{2} \\ w=-5 \end{gathered}[/tex]Similarly,
[tex]\begin{gathered} w-8=0 \\ w=8 \end{gathered}[/tex]Since, the magnitude of a side cannot be negative. So take the value of width of the rectangle as 8 feet.
Substitute the value of w in area formula to find length l.
[tex]\begin{gathered} A=l\times w \\ 80=l\times8 \\ l=\frac{80}{8} \\ l=10\text{ f}eet. \end{gathered}[/tex]Hence, the width of the floor of the shed is 8 ft.
Let f(x)= 1/x-2 and g(x)=5/x+2Find the following functions. Simplify your answers.F(g(x))=g(f(x))=
Answers
Given:
[tex]\begin{gathered} f(x)\text{ = }\frac{1}{x\text{ - 2}} \\ g(x)\text{ = }\frac{5}{x}\text{ + 2} \end{gathered}[/tex]To find:
a) f(g(x)) b) g(f(x))
[tex]\begin{gathered} a)\text{ f\lparen g\lparen x\rparen\rparen: we will substitue x in f\lparen x\rparen with g\lparen x\rparen} \\ f(g(x))\text{ = }\frac{1}{(\frac{5}{x}+2)-2} \\ \\ f(g(x))\text{ = }\frac{1}{(\frac{5+2x}{x})-2} \\ \\ f(g(x))\text{ = }\frac{1}{(\frac{5+2x-2x}{x})}\text{ = }\frac{1}{\frac{5}{x}} \\ \\ f(g(x))\text{ = }\frac{x}{5} \end{gathered}[/tex][tex]\begin{gathered} b)\text{ g\lparen f\lparen x\rparen\rparen: we will substitue x in g\lparen x\rparen with f\lparen x\rparen} \\ g(f(x))\text{ = }\frac{5}{\frac{1}{x-2}}+2 \\ \\ g(f(x))\text{ = }\frac{5(x\text{ -2\rparen}}{1}+2 \\ \\ g(f(x))\text{ = }5(x\text{ -2\rparen}+2\text{ = 5x - 10 + 2} \\ \\ g(f(x))\text{ = 5x - 8} \end{gathered}[/tex]Parveen wanted to make a temporary shelter for her car, by making a box-like structure with tarpaulin that covers all the four sides and the top of the car (with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height 2.5 m, with base dimensions 4m×3m ?
Answers
Given:
Length = 4m
Width= 3m
Height = 2.5 m
Therefore, the surface area of rectangle prism is 2lh+2bh+lb
[tex]\begin{gathered} 4\times2.5\times2+3\times2.5\times2+4\times3=10\times2+5\times3+12 \\ =20+15+12 \\ =47 \end{gathered}[/tex]Hence, the required answer is 47m^2.
Give. ∆ABC Angle B = 42°, Angle C = 71° and BC = 22. Find AB and round your answer to nearest integer.
Answers
Let's make a diagram to visualize the problem.
First, let's find angle A.
[tex]\begin{gathered} A+B+C=180 \\ A+42+71=180 \\ A=180-71-42 \\ A=67 \end{gathered}[/tex]Then, we use the law of sines to find AB.
[tex]\begin{gathered} \frac{AB}{\sin71}=\frac{BC}{\sin A} \\ \frac{AB}{\sin71}=\frac{22}{\sin 67} \\ AB=\frac{22\cdot\sin 71}{\sin 67} \\ AB\approx23 \end{gathered}[/tex]Therefore, AB is 23 units long, approximately.An object moves at a rate of 9,400 inches each week. How many feet does it move per minute?
Answers
To answer this question, we need to transform each of the values into the corresponding other units:
• Inches ---> Feet
,• Week ---> minutes
And we also have here a ratio:
• Inches/week ---> Feet/minute.
Then we can proceed as follows:
Inches to FeetWe know that the conversion between inches and feet is:
[tex]1ft=12in[/tex]Then
[tex]1in=\frac{1}{12}ft[/tex]If we have 9,400 inches, then:
[tex]9400in=\frac{9400}{12}ft\Rightarrow9400in=783ft+\frac{1}{3}ft=783.33333333ft[/tex]Week to minutesWe know that:
[tex]1\text{hour}=60\min [/tex]In one day we have 24 hours, then:
[tex]24\text{hours}=24\cdot60\min =1440\min [/tex]Then we have 1440 minutes in a day. A week has 7 days. Therefore, we will have:
[tex]1440\frac{\min}{day}\cdot7days=10080\min [/tex]Therefore, we have that there are 10,080 minutes in one week.
Now, to find the ratio of feet per minute, we need to divide:
[tex]\frac{783\frac{1}{3}ft}{10080\min}=0.0777116402116\frac{ft}{\min }[/tex]In summary, we can say that the object moves:
[tex]0.0777116402116\frac{ft}{\min }[/tex]into the
Find the x - and y -intercepts of the graph of the linear equation -6x + 9y = -18
Someone else got x=(3,0) y=(0,-2) but it was wrong
Answers
Answer:
x-intercept = 3y-intercept = -2Step-by-step explanation:
You want the intercepts of the equation -6x +9y = -18.
InterceptsThere are several ways to find the intercepts. In each case, the x-intercept is the value of x that satisfies the equation when y=0, and vice versa.
For y = 0, we find the x-intercept to be ...
-6x + 0 = -18
x = -18/-6 = 3
The x-intercept is 3; the point at that intercept is (3, 0).
For x = 0, we find the y-intercept to be ...
0 +9y = -18
y = -18/9 = -2
The y-intercept is -2; the point at that intercept is (0, -2).
Intercept formThe intercept form of the equation for a line is ...
x/a +y/b = 1
where 'a' is the x-intercept, and 'b' is the y-intercept.
We can get this form by dividing the original equation by -18.
-6x/-18 +9y/-18 = 1
x/3 +y/(-2) = 1
The x-intercept is 3; the y-intercept is -2.
__
Additional comment
When asked for the intercepts, it is sometimes not clear whether you are being asked for the value where the curve crosses the axis, or whether you are being asked for the coordinates of the point there.
Your previous "wrong" answer was given as point coordinates. Apparently, just the value at the axis crossing is required.
You have to have some understanding of your answer-entry and answer-checking software to tell the required form of the answer (or you can ask your teacher).
<95141404393>
FIND THE MEASURE OF EACH EXTERIOR ANGLE OF 40
Answers
Solution
The sum of exterior angles is 360º for any polygon
So then we can find the measure of the exterior angles like this:
360/40 = 9º
The length of a room is twice as its breadth and breadth is 6 cm. If it's height is 4 cm, find the total surface area.
Answers
The breadth of the room = 6 cm
Since the length of the room is twice its breadth
Then
Length of the room = 2 times 6cm = 12cm
The height of the room = 4cm
Since the shape of the room is a cuboid
The surface area of a cuboid is given as
[tex]SA=2(lh+lw+hw)[/tex]Substitute l = 12, w = 6 and h = 4 into the formula
This gives
[tex]SA=2(12\times4+12\times6+4\times6)_{}[/tex]Simplify the expression
[tex]\begin{gathered} SA=2(48+72+24) \\ SA=2(144) \\ SA=288 \end{gathered}[/tex]Therefore, the total surface area of the room is
[tex]288cm^2[/tex]Find the midpoint for the line segment whose endpoints are (-10,11) and (-1,-15).
Answers
Answer:
( -11/2, -2)
Step-by-step explanation:
Finding the midpoint
To find the x coordinate of the midpoint, add the x coordinates of the endpoints and then divide by 2
(-10+-1)/2 = -11/2
To find the y coordinate of the midpoint, add the y coordinates of the endpoints and then divide by 2
(11+-15)/2 = -4/2 = -2
The mid point is ( -11/2, -2)
which answer choice gives the correct surface area for a triangular prism with bases that are 4 cm2 and sides that are 10 cm2? A. 12 cm2 B. 26 cm2 C.38 cm2 D. 40 cm2
Answers
Explanation
A trinagular prism has two bass and theree side surfaces.
Therefore, the suface area pf the prism is
[tex]S.A=3(10)+2(4)=30+8=38cm^2[/tex]Answer: Option C
A carpenter wants to cut a board that is 5/6 ft long into pieces that are 5/16 ft long. The carpenter will use the expression shown to calculate the number of pieces that can be cut from the board.5/6 divided by 5/16How many pieces can be cut from the board?
Answers
The expression which is used to calculate the number of pieces that can be cut from the board is:
[tex]\frac{5}{6}\div\frac{5}{16}[/tex]We solve this by changing the division sign to multiplication and taking the reciprocal of the second fraction.
Therefore:
[tex]\begin{gathered} \frac{5}{6}\div\frac{5}{16}=\frac{5}{6}\times\frac{16}{5} \\ =\frac{16}{6} \\ =2\text{ }\frac{4}{6} \\ =2\frac{2}{3}\text{ pieces} \end{gathered}[/tex]The carpenter can cut 2 2/3 pieces from the board.
How far is the bottom of the ladder from thebottom of the wall? Use the PythagoreanTheorem to determine the solution. Explain howyou found your answer.
Answers
The Pythagorean Theorem is
[tex]c^2=a^2+b^2[/tex]where
c=hypotenuse=13
a=12
b=x
then we substitute the values
[tex]13^2=12^2+x^2[/tex]then we isolate the x
[tex]\begin{gathered} x=\sqrt[]{13^2-12^2} \\ x=\sqrt[]{169-144} \\ x=\sqrt[]{25} \\ x=5 \end{gathered}[/tex]The bottom of the ladder is 5m far from the bottom of the wall
A worker uses a forklift to move boxes that weigh either 40 pounds or 65 pounds each. Let x be the number of 40-pound boxes and y be the number of 65-pound boxes. The forklift can carry up to either 45 boxes or a weight of 2,400 pounds. Which of the following systems of inequalities represents this relationship? 40x + 657 $ 2.400 rty < 45 C) | 40r + 657 $ 45 | x + y < 2.400 B) [xu y < 2.100 40x + 657 $ 2.400 xl y < 1
Answers
Let:
x = number of 40-pound boxes
y = number of 65-pound boxes
The forklift can carry up to either 45 boxes
This means:
[tex]x+y\leq45[/tex]The forklift can carry up a weight of 2,400 pounds:
This means:
[tex]40x+65y\leq2400[/tex]Which of the sketches presented in the list of options is a reasonable graph of y = |x − 1|?
Answers
ANSWER
EXPLANATION
The parent function is y = |x|. The vertex of this function is at the origin.
When we add/subtract a constant from the variable, x, we have a horizontal translation, so the answer must be one of the first two options.
Since the constant is being subtracted from the variable, the translation is to the right. Hence, the graph of the function is the one with the vertex at (1, 0).
4. A pool measuring 24 feet by 16 feet is
surrounded by a uniform path of width x feet.
The total enclosed area is 768 ft².
Find x, the width of the path.
Answers
The width of the path, x, is 48 feet
How to determine the parametersThe formula for determining the area of a rectangle is expressed as;
Area = lw
Where;
l is the length of the given rectanglew is the width of the given rectangleFrom the image shown and the information given, we can see that;
The width is given as = x
The area of the rectangle = 768 ft²
The length of the rectangle = 16
Now, substitute the values, we have;
768 = 16x
Make 'x' the subject of formula by dividing both sides by its coefficient, we have;
768/16 = 16x/16
Find the quotient
x = 48 feet
But, we have;
Width = x = 48 feet
Hence, the value is 48 feet
Learn more about area here:
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help meeeee pleaseeeee!!!
thank you
Answers
Answer:
(f o g) = 464
Step-by-step explanation:
f(x) = x² - 3x + 4; g(x) = -5x
(f o g)(4) = f(g(4))
f(g(4)) = -5(4) = -20
f(g(4)) = (-20)² - 3(-20) + 4
f(g(4)) = 464
I hope this helps!
An earthquake in California measured 3.6 on the Richter scale. Use the formula R=log(A/Ao) to determine approximately how many times stronger the wave amplitude of the earthquake was than .
Answers
The correct option regarding how many times stronger the wave amplitude of the earthquake was than the standard wave Ao is given by:
A = 3981Ao.
Ratio of A and AoTo find the ratio of A and Ao, measuring how many times a earthquake measuring R in the Richter scale was than Ao, we have to solve the following logarithmic function:
R=log(A/Ao)
The power of 10 in inverse to the logarithm, hence it is applied to both sides of the expression, as follows:
10^R = 10^log(A/Ao).
Since they are inverses, we can remove the power and the logarithm as follows:
A/Ao = 10^R
Hence the formula for how many times stronger and earthquake is than Ao is given as follows:
A = 10^R Ao
In this problem, the Richter measure of the earthquake was of:
R = 3.6.
Hence the ratio is:
A = 10^(3.6)Ao
A = 3981Ao.
Missing informationThe problems asks how many times stronger the earthquake was than Ao.
Learn more about logarithmic functions at https://brainly.com/question/14379331
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how do i find the sale price?if original price is $77.00markdown is 32%
Answers
The markdown price can be calculated as,
[tex]\begin{gathered} \text{Markdown price}=\frac{Markdown\text{ Percent}}{100}\times Original\text{ price} \\ \text{Markdown price}=\frac{32}{100}\times77 \\ \text{Markdown price}=24.64 \end{gathered}[/tex]Now, the sale price is,
[tex]\begin{gathered} \text{Sale price=Original price -markdown price} \\ \text{Sale price=}=77-24.64 \\ \text{Sale price=}52.36 \end{gathered}[/tex]Therefore, the sale price is $52.36.
x-y=3x+y=5unit 7 systems of linear equations
Answers
then
[tex]\begin{gathered} x+y=5 \\ 3+y+y=5 \\ 3+2y=5 \\ 3+2y-3=5-3 \\ 2y=2 \\ \frac{2y}{2}=\frac{2}{2} \\ y=1 \end{gathered}[/tex]solve for x
[tex]\begin{gathered} x=3+y \\ x=3+1 \\ x=4 \end{gathered}[/tex]answer: C. (4,1)
