please help me with this

Please Help Me With This

Answers

Answer 1
There are 20 joules of useful energy.

Related Questions

The gravitational force between a satellite and Earth’s moon is 324 N. The mass of the moon is 7. 3 × 1022 kg. If the distance from the moon to the satellite is 2. 6 × 106 m, what is the mass of the satellite? 1. 7 × 10–4 kg 2. 2 × 10–3 kg 230 kg 450 kg.

Answers

The gravitational force is s type of force that has the ability to attract any two objects with mass. The mass of the satellite will be 450 kg.

What is the gravitational force?

The gravitational force is s type of force that has the ability to attract any two objects with mass. Gravitational force tries to pull two masses towards each other.

The given data in the problem is;

F is the gravitational force = 324 N,

m₁ is the mass of the moon = 7.3 * 10²²kg

r is the distance between the moon and satellite  = 2.6 * 10 ⁶m.

m is the mass of satelite =?

G is the gravitational constant = 6.67×10⁻¹¹

The gravitational force is given by

[tex]\rm F= \frac{Gm_1m_2}{r^2} \\\\ \rm m_2 = \frac{Fr^2}{Gm_1} \\\\ \rm m_2 = \frac{324 \times (2.6\times 10^6)^2}{6.67\times 10^{-11} \times 7.3 \times 10^22 } \\\\ \rm m_2= 450 kg[/tex]

Hence the mass of the satellite will be 450 kg.

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A 70.0 kg astronaut is training for accelerations that he will experience upon reentry. He is placed in a centrifuge (r = 10.0 m) and spun at a constant angular velocity of 16.3 rpm. Answer the following:

What is the angular velocity of the centrifuge in ?

What is the linear velocity of the astronaut at the outer edge of the centrifuge?

What is the centripetal acceleration of the astronaut at the end of the centrifuge?

How many g’s does the astronaut experience?

What is the centripetal force and net torque experienced by the astronaut? Give magnitudes and directions.

Answers

Answer:

1.3823 rad/s

20.7345 m/s

28.66129935 m/s²

2006.29095 N radially outward

Explanation:

r = Radius = 15 m

m = Mass of person = 70 kg

g = Acceleration due to gravity = 9.81 m/s²

Angular velocity is given by

Angular velocity is 1.3823 rad/s

Linear velocity is given by

The linear velocity is 20.7345 m/s

Centripetal acceleration is given by

The centripetal acceleration is 28.66129935 m/s²

Acceleration in terms of g

Centripetal force is given by

The centripetal force is 2006.29095 N radially outward

The torque will be experienced when the centrifuge is speeding up of slowing down i.e., when it is accelerating and decelerating.

How are velocity and acceleration related

Answers

Answer:

Acceleration is the rate of change of velocity.  If an object is changing its velocity, its speed, or changing its direction, then it is said to be accelerating.

Explanation:

when you change directions or speed up you are accelerating (or decelerating)  and when you change directions or speed its called velocity.

A car travelling at a speed of 45 m/h takes 20 minutes to reach its destination. What distance has the car travelled.

Answers

Answer:

A car travelling at a speed of 45 m/h takes 20 minutes to reach its destination.

We have to find the distance travelled by the car .

Changing the unit of time into hour

Time = 20/60 hour

Time = 2/3 hour

Now, let's calculate the distance travelled by the car .

[tex] \bf \: Distance \: travelled \: = Speed \: \times Time[/tex]

Put the value we get

[tex] \sf \dashrightarrow \ \: Distance \: travelled \: = 45 \times \frac{2}{3} \\ \\ \sf \dashrightarrow \ \: Distance \: travelled \: = \cancel{45} \: \times \frac{2}{ \cancel3} \\ \\ \sf \dashrightarrow \ \: Distance \: travelled \: = 15 \times 2 \\ \\ \sf \dashrightarrow \ \: Distance \: travelled \: = 30km \: [/tex]

So, the distance travelled by the car is 30Km .

The car has travelled a distance of 15 m

Distance travelled by car

Since distance, d = vt where

v = speed and t = time.

Now, the car travels at a speed of 45 m/h in 20 minutes.

So,

v = 45 m/h = 45 m/h × 1 h/60 min = 0.75 m/min and t = 20 min

Since d = vt,

substituting the values of the variables into the equation, we have

d = vt

d = 0.75 m/min × 20 min

d = 15 m

So, the car has travelled a distance of 15 m

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Define the LAWS OF PHYSICS. State it out in full.
BRAINLIEST WILL BE GIVEN!!!!!!

Answers

Answer:

The laws of thermodynamics define a group of physical quantities, such as temperature, energy, and entropy, that characterize thermodynamic systems in thermodynamic equilibrium.

Two satellites are in circular orbits around Earth. Satellite A has speed vA. Satellite B has an orbital radius nine times that of satellite A. What is the speed of satellite B

Answers

Answer:

option B

Explanation:

given,

Satellite B has an orbital radius nine times that of satellite A.

R' = 9 R

now, orbital velocity of the satellite A

........(1)

now, orbital velocity of satellite B

from equation 1

hence, the correct answer is option B

If there is a new moon today, in how many days will the next full moon occur?.

Answers

Approximately 15 days in between

Walt ran 5 kilometers in 25 minutes, going eastward. What was his average velocity? 0. 17 km/min east 0. 2 km/min east 5 km/min east 25 km/min east.

Answers

Answer:

0.2 km/min east

Explanation:

Walt ran 5 kilometers in 25 min, going eastward. What was his average velocity?

m a t h

A compass needle normally points toward earth’s magnetic pole, which is near the north pole. Which best explains why the needle moves away from the pole when it comes close to a current-carrying wire?.

Answers

Answer:

Magnetism surrounding the wire draws the needle toward the wire.

Explanation:

The wire itself has it's own magnetism also, that's why, if you put a compass near it, then the compass will get confused and point the wrong direction.

Thanks!

MiniMeteorologist

Trains A and B travel at the same constant rate in opposite directions along the same route between Town G and Town H. If Train A travels for exactly two hours before passing Train B, how long does it take Train B to travel the entire distance between Town G and Town H?
(1) Train B started traveling between Town G and Town H 1 hour after Train A started traveling between Town H and Town G.
(2) Train B travels at the rate of 150 miles per hour.

Answers

A and b travel at 56 easily u wpild divide by and multiply it by 5+6/23

Which statement about local and global winds is true?.

Answers

Answer:

Global winds occur in belts around the globe.

Explanation:

This is because they blow over a limited area. They are influenced by local geography, such as nearness to an ocean.

when is homeostasis important

Answers

Answer:

Homeostasis maintains optimal conditions for enzyme action throughout the body, as well as all cell functions. It is the maintenance of a constant internal environment despite changes in internal and external conditions.

If a motionless table has a weight of 50 newtons, what is the value of the normal force acting on the table?

A. 0 N
B. 50 N
C. 100 N
D. This cannot be determined

Answers

Answer:

d

Explanation:

because it also depends upon accleration acting upon it

Determine the horizontal displacement of a projectile if it has a flight time of 8 seconds and a horizontal velocity of 14 m/s

Answers

Velocity=14m/sTime=8s

[tex]\\ \rm\bull\rightarrowtail Displacement=Velocity\times Time[/tex]

[tex]\\ \rm\bull\rightarrowtail Displacement=8(14)[/tex]

[tex]\\ \rm\bull\rightarrowtail Displacement =112m[/tex]

Light with a wavelength of about 490 nm is made to pass through a diffraction grating. The angle formed between the path of the incident light and the diffracted light is 9. 2° and forms a first-order bright band. What is the number of lines per mm in the diffraction grating? Round your answer to the nearest whole number. Lines per mm.

Answers

A diffraction grating is a type of optical instrument obtained with a continuous pattern. The number of lines per mm in the diffraction grating is 326.

What is diffraction grating?

A diffraction grating is a type of optical instrument obtained with a continuous pattern. The pattern of the diffracted light by a grating depends on the structure and number of elements present.

The given data in the problem is

[tex]\theta[/tex] is the angle formed between the path of the incident light and the diffracted light = 9. 2°

λ is the wavelength of the light=490nm=4.9

N is the number of lines per mm in the diffraction grating=?

n is ordered = 1

The formula for diffraction grating will be

[tex]\rm n\lambda=dsin\theta\\\\ \rm d=\frac {n \lambda}{sin\theta} \\\\ \rm d=\frac {1\times4.90\times10^{-7}}{sin9.2^0} \\\\\rm d=3.06\times10^{-6}m=3.06\times10^{-3}mm[/tex]

The number of lines per mm is the inverse of the distance between grating in mm.

[tex]\rm N=\frac{1}{d}[/tex]

[tex]\rm N=\frac{1}{3.06\times10^-3}\\\\\rm N=326.8/mm[/tex]

Hence the number of lines per mm in the diffraction grating is 326.

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Answer:

326

Explanation:

Object 1 has a mass of 3m and is moving to the right at a velocity of
4v. Object 2 has a mass of m is moving to the left at v. After the objects collide inelastically, object A is moving to the left at a velocity of v (one third of its original velocity). Derive an expression for the final velocity V of object B.

I am confused because I thought the when it is an inelastic equation, then that means that the objects stick together. So how can you find the final velocity of object B (also it shows that after the collision, the two objects to in fact split apart)?

Answers

Answer:

In a collision, the velocity change is always computed by subtracting the initial velocity value from the final velocity value. If an object is moving in one direction before a collision and rebounds or somehow changes direction, then its velocity after the collision has the opposite direction as before.

What change slowly occurs during the main-sequence lifetime of a star?.

Answers

Its core temperature slowly increases, increasing the fusion rate and hence the luminosity.

what is the magnetic force value due to 3.5nanocoloumb charge moves to the
east with velocity of 250m/s making angle of 30 degree with the magnetic
filed (25m.T)?

Answers

The force on the charge is 1.1×10⁻⁸ N.

What is force?

Force can be defined as the product of the mass of a body and its acceleration

To calculate the force on the charge, we use the formula below.

Formula:

F = qvBsin∅............. Equation 1

Where:

q = chargev = velocityB = magnetic field∅ = Angle.

From the question,

Given:

B = 25 mT = 0.025 Tv = 250 m/sq = 3.5 nC = 3.5×10⁻⁹ C∅ = 30°

Substitute the given values into equation 1

F = (0.025)(250)(3.5×10⁻⁹)(sin30°)F = 1.093×10⁻⁸ NF ≈ 1.1×10⁻⁸ N

Hence, the force on the charge is 1.1×10⁻⁸ N.

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A 0.50-kg red cart is moving rightward with a speed of 40 cm/s when it collides
with a 1.50-kg blue cart that is initially at rest. The two carts stick together and
move to the right with a speed of 10 cm/s after the collision,
Enter the momentum values of each individual cart and of the system of two
carts before and after the collision. Also indicate the change in momentum of the
carts and of the system,

Answers

The momentum of the red cart before the collision is 0.2 kgm/s and the blue cart is 0.

The momentum of the red cart after the collision is 0.05 kgm/s and the blue cart is 0.15 kgm/s.

The change in momentum of the system of the carts is 0.

Initial momentum of the carts before collision

The momentum of the carts before the collision is calculated as follows;

P(red) = 0.5 kg x 0.4 m/s = 0.2 kgm/s

P(blue) = 1.5 x 0 = 0

Momentum of the carts after collision

The momentum of the carts after the collision is calculated as follows;

P(red) = 0.5 x 0.1 = 0.05 kgm/s

P(blue) = 1.5 0.1 = 0.15 kgm/s

Change in momentum of the carts

[tex]\Delta P = P_f - P_i[/tex]

ΔP = (0.05 + 0.15) - (0.2)

ΔP = 0

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In a rocket-propulsion problem the mass is variable. Another such problem is a raindrop falling through a cloud of small water droplets. Some of these small droplets adhere to the raindrop, thereby increasing its mass as it falls. The force on the raindrop is
Fext=dpdt=mdvdt+vdmdt
Suppose the mass of the raindrop depends on the distance x that it has fallen. Then m=kx, wherek is a constant, and dm/dt=kv. This gives, since Fext=mg,
mg=mdvdt+v(kv)
Or, dividing by k,
xg=xdvdt+v2
This is a differential equation that has a solution of the form v=at, where a is the acceleration and is constant. Take the initial velocity of the raindrop to be zero.
A) Using the proposed solution for v, find the acceleration a.
B) Find the distance the raindrop has fallen in t = 2.00s.
C) Given that k = 2.00g/m, find the mass of the raindrop at t = 2.00s.

Answers

Answer:

a) a = g / 3

b) x (3.0) = 14.7 m

c) m (3.0) = 29.4 g

Explanation:

Given:-

- The following differential equation for (x) the distance a rain drop has fallen has the form:

                           

- Where,                v = Speed of the raindrop

- Proposed solution to given ODE:

                            v = a*t

Where,                  a = acceleration of raindrop

Find:-

(a) Using the proposed solution for v find the acceleration a.

(b) Find the distance the raindrop has fallen in t = 3.00 s.

(c) Given that k = 2.00 g/m, find the mass of the raindrop at t = 3.00 s.

Solution:-

- We know that acceleration (a) is the first derivative of velocity (v):

                            a = dv / dt   ... Eq 1

- Similarly, we know that velocity (v) is the first derivative of displacement (x):

                           v = dx / dt  , v = a*t ... proposed solution (Eq 2)

                            v .dt = dx = a*t . dt

- integrate both sides:

                            ∫a*t . dt = ∫dt

                            x = 0.5*a*t^2  ... Eq 3

- Substitute Eq1 , 2 , 3 into the given ODE:

                           0.5*a*t^2*g = 0.5*a^2 t^2 + a^2 t^2

                                               = 1.5 a^2 t^2

                           a = g / 3

- Using the acceleration of raindrop (a) and t = 3.00 second and plug into Eq 3:

                          x (t) = 0.5*a*t^2

                          x (t = 3.0) = 0.5*9.81*3^2 / 3

                          x (3.0) = 14.7 m  

- Using the relation of mass given, and k = 2.00 g/m, determine the mass of raindrop at time t = 3.0 s:

                          m (t) = k*x (t)

                          m (3.0) = 2.00*x(3.0)

                          m (3.0) = 2.00*14.7

                          m (3.0) = 29.4 g

2. A 6 kg object is initially at rest. A 300 N force acts on the object, moving it forward 4 meters in
2 seconds.
a) How much work does the force do on the object?
b) How much power is exerted on the object?
c) What is the final velocity of the object?

Answers

Answer: a. 1200J b. 600W c. 20m/s

Explanation: W = Fxcos

F = 300, x=4, direction of force is = to direction of object so cos(0) = 1

a) 300*4 = 1200

b) P = W/t

1200/2 = 600W

c) vf^2 = vi^2 + 2ax

vi = 0, x = 4, a= 300/6

vf^2 = 2(50)(4)

vf^2 = 400

vf= 20m/s

A yellow train of mass 100 kg is moving at 8 m/s toward an orange train of mass 200 kg traveling in the opposite direction on the same track at a speed of 1 m/s. They collide and stick together! What is the final momentum of the new combined train?
A. 100 kgm/s
B. 600 kgm/s
C. 800 kgm/s
D. 80 kgm/s

Answers

Answer:

Let the momentum of the orange train be positive

P = 100 * 8 - 200 * 1 = 600 kg-m/s

P(final) = 600 kg-m/s

P / M = 600 kg-m/sec / 300 kg = 2 m/s    

Answer-B     final momentum = 600 kg-m/s

pls help me with this​

Answers

Answer:

needle -attract

wooden spoon -repel

nails -attract

safety pins -attract

paper -repel

Explanation:

Shondra takes notes in class. I. Electromagnetic Waves II. The ability to work - Has many forms - Mechanical III. Potential energy - Chemical - Elastic - Gravitational Kinetic energy - Energy of movement - Electrical IV. Nuclear - Radiant - Thermal One line of Shondra’s notes is irrelevant to the rest of her notes. Which line is about a different topic than the rest of Shondra’s notes? I II III IV.

Answers

The waves that are related to both electricity and magnetism are known as (EM) waves .electromagnetic Waves' this line is about a different topic than the rest of Shondra’s notes.

What is an electromagnetic wave?

The waves that are related to both electricity and magnetism are known as electromagnetic (EM) waves. These waves are made up of time-varying electric and magnetic fields that travel over space.

These waves, which are related to electricity and magnetism, would undoubtedly spread in space. The waves that are related to both electricity and magnetism are known as electromagnetic (EM) waves.

These waves are made up of time-varying electric and magnetic fields that travel over space. These waves, which are related to electricity and magnetism, would undoubtedly spread in space.

Hence option 1 is right because the 'Electromagnetic Waves' these line is about a different topic than the rest of Shondra’s notes.

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It is commonplace to find statements on food cans such as “Net Weight: 16 oz. (454g)” Why do most people find this acceptable?

Answers

People find this acceptable because it is common to use mass and weight as synonyms even if they are not.

What is the difference between mass and weight?

In physics, mass refers to the amount of matter, due to this, mass is often measured in:

GramsKilosTonsAmong others.

On the other hand, weight considers gravity or the force gravity exerts on an object, and due to this it is measured in newtons.

Why do people find the statement “Net Weight: 16 oz. (454g)” acceptable?

Even if weight and mass are different, people often use the word "weight" to refer to the mass, that is why statements such as the above are acceptable. However, if you are a physicist this would be incorrect.

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a stone is thrown at 45 degree with velocity 10m/sec.calculate the range of projectile​

Answers

Answer:

As per Given Information

Angle on which the stone thrown ,theta = 45°

Velocity ,u = 10m/s

Acceleration due to gravity ,g is 10m/

We have to find the "Range of Projectile "

Range of projectile is denoted by R .

Using Formulae

[tex]\\ \bigstar{\boxed{\pink{\bf{R = \frac{ {u}^{2}sin2 \theta }{g} }}}} \\ \\ [/tex]

On putting the value we get

[tex] \sf\dashrightarrow \: R\: = \frac{ {10}^{2} \times sin(2 \times 45) }{10} \\ \\ \sf\dashrightarrow \: R = \frac{100 \times sin90 {}^{ \circ} } {10} \\ \\ \sf\dashrightarrow \: R \: = \frac{100 \times 1}{10} \\ \\ \sf\dashrightarrow \: R \: = \frac{100}{10} \\ \\ \sf\dashrightarrow \: R = \cancel \frac{100}{10} \\ \\ \sf\dashrightarrow \: R = 10m[/tex]

So, the range of projectile is 10m.

PLEASE HELPPPP!!!!


in the diagram, the direction of a current and the magnetic field around it are shown. describe what would happen to the magnetic field if you increased the number of turns in the coil and reversed the direction of the current

Answers

Answer:

more turns in a coil will make stronger magnet field and reversed direction of the current will change the pole of the magnet

Explanation:

by winding a coil , it concentrates magnetic field of the current in smaller space so more turns of coil mean stonger magnetic field.

explanation for change of direction of current is in pic.

i hope it helps.

More turns in a coil will make stronger magnet field and reversed direction of the current will change the pole of the magnet.

What is Current?

By winding a coil , it concentrates magnetic field of the current in smaller space so more turns of coil mean stonger magnetic field.

In a full electrical circuit, current is the rate at which electrons move past a certain point. Current = flow, at its most fundamental level.

The international unit for measuring current is an ampere (AM-pir), sometimes known as an amp. It describes how many electrons.

In a circuit, a current of 1 ampere corresponds to the movement of 1 coulomb of electrons, or 6.24 billion billion (6.24 x 1018) electrons, through a single location in a second.

Therefore, More turns in a coil will make stronger magnet field and reversed direction of the current will change the pole of the magnet.

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#SPJ2

Select the correct answer.
How do we define energy efficiency?
A.
the ratio of the actual output energy to the input energy
B.
the ratio of power gain to power loss
c.
the product of input power and output power
D.
the sumy potential and kinetic energy

Answers

D. The sumy potential and kinetic energy

i need helpp pls!!!!??????

Answers

Answer:

too hard bro others will answer it

Explanation:

sry

What are the uses of a magnet?

Answers

Answer:

A magnet is used in a compass to show the direction.

Magnets are used in medical equipment.

Powerful magnets are used to lift objects

they are used in refrigerator, televisions, earphones etc

Answer:

1. they are used in medical equipment

2. they are used in dynamos

3. they are used in generators and motors

4. powerful magnets are used to lift heavy objects

5. they are used to prevent corrosion in a water heater

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