Please help me with this please and thank you please actually help me please

Answer:

Lets say we have (-1)^(1.5)

Step-by-step explanation:

(-1)^(1.5) = (-1)^(3/2)

= (√(-1))^3 which has no solution in the real number field, as √(-1) does not exist.

In the complex number field √(-1) = i, and (-1)^(1.5) = i^3 = -i.

The complete factor of the expression [tex]\rm 3x (x +2) + 4 (x +2)[/tex] is [tex]\rm(x+2)(3x + 4)[/tex]. Then the correct option is A.

It is the method to separate the polynomial into parts and the parts will be in multiplication. And the value of the polynomial at this point will be zero.

The expression is [tex]\rm 3x (x +2) + 4 (x +2)[/tex].

To solve the expression properly we have to take common (x+2). Then we have

[tex]\rm 3x (x +2) + 4 (x +2)\\\\(x+2)(3x + 4)[/tex]

The correct factor is (x + 2)(3x + 4).

More about the factorization link is given below.

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Answer:

Yup A

Step-by-step explanation:

Answer: -31

Step-by-step explanation:

5x³- 3x + 2 = 0

a = 5, b = -3, c = 2

(-3)² -4 × 5 × 2

-31

Answer:

35

Step-by-step explanation:

350miles/10=10gallons/10

=35miles=1gallon

Quadrilaterals are shapes with four sides

The description of the quadrilateral is (d)  rectangle, that is not square

The coordinates are given as:

W(-5,5), X(-3, 8), Y(6, 2), and Z(4, -1)

Next, we plot the coordinates on a graph (see attachment)

From the attachment, we can see that the coordinates form a rectangle

Hence, the description of the quadrilateral is (d)  rectangle, that is not square

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[tex]11 = -5x-2\\5x = -2-11\\5x =-13\\x = -13/5[/tex]

Answer: x = -13/5

Ok done. Thank to me :>

By getting the exponential decay that models the situation, we will see that after 8 weeks she uses 0.12 cups.

We know that the first week, she uses 2 cups of sugar, and each week she uses removes one-third of what she used the previous week.

Then the second week she uses:

S₂ = 2 cups - (1/3)*(2 cups) = 2 cups*(1 - 1/3) = 2 cups*(2/3)

The third week she uses:

S₃ = 2 cups*(2/3) - (1/3)*2 cups*(2/3) = 2 cups*(2/3)^2

You already can see the pattern, at week x, she will use:

Sₓ = (2 cups)*(2/3)^(x - 1)

This is an exponential decay.

To get how much sugar does she uses after 8 weeks, we just replace x by 8 in the above equation:

S₈ = (2 units)*(2/3)^(8 - 1) = 0.12 cups of sugar.

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First off, no sides have the same length as the others, so it cannot be an equilateral or an isoceles triangle, as it would required at least 2 sides to have the same length.

So, we're left with scalene triangle options.

There is an angle that is an obtuse angle (as it is more than 90 degrees and less than 180 degrees), so this is a scalene obtuse triangle.

Answer:

X=3, or X=-3   But the positive answer is X=3

Step-by-step explanation:

Rewrite the equation 5x^2+2=47

Subtract 2 from each side -----> 5x^2+2-2=47-2

Simplify   ---------> 5x^2=45

divide each side by 5 ----->  5x^2/5=45/5

Simplify x^2=9

Divide each side by using square root method -->  Sqrt(9)     - sqrt(9)

Now simplify to get X=3, or X=-3

1. x = 60 (in this trapezoid, opposite angles are equal)

2. Find the third angle of the left triangle : 180 - 17 - 133 = 30
In a parallelogram, the side that is opposite to a side is parallel to each other.

x and the 30 degree are alternate angles -> x = 30

3. (I'll call the 4 triangles A,B,C,D respectively in anticlockwise)

Triangle A has the 25 degree angle, and the bottom right angle of triangle C, they are alternate angles (and the sides are parallel due to the property.)

So, the bottom right angle of triangle C = 25

Triangle C and D form an isoceles triangle, so x = 25.


4. This one I'll just do short. There's a right angle in the triangle that contains x.

3 angles in a triangle add up to 180, so x = 180 - 90 - 50 = 40.

a) The approximate reaction distance is 66 feet.

b) The approximate braking distance is 802.304 feet.

c) The total distance is 868.304 feet.

The average reaction time ([tex]t_{R}[/tex]) is 0.75 seconds. Manuel drives at constant velocity in the first 0.75 seconds, then he decelerates the vehicle.

a) The reaction distance ([tex]x_{R}[/tex]), in meters, is found by the following expression:

[tex]x_{R} = v_{o}\cdot t_{R}[/tex] (1)

Where [tex]v_{o}[/tex] is the initial velocity, in feet per hour.

If we know that [tex]v_{o} = 60\,\frac{mi}{h}[/tex] ([tex]v_{o} = 88\,\frac{ft}{s}[/tex]) and [tex]t_{R} = 0.75\,s[/tex], then the approximate reaction distance is:

[tex]x_{R} = (88)\cdot (0.75)[/tex]

[tex]x_{R} = 66\,ft[/tex]

The approximate reaction distance is 66 feet. [tex]\blacksquare[/tex]

b) A normal braking has magnitudes of about 0.15 times the value of gravitational acceleration ([tex]g = 32.174\,\frac{ft}{s^{2}}[/tex]). The approximate braking distance ([tex]d[/tex]), in feet, is found by the following kinematic formula:

[tex]d = \frac{v^{2}-v_{o}^{2}}{2\cdot a}[/tex] (2)

Where:

If we know that [tex]v_{o} = 88\,\frac{ft}{s}[/tex] and [tex]v_{o} = 0\,\frac{ft}{s}[/tex], then the approximate braking distance is:

[tex]d = \frac{\left(0\,\frac{ft}{s}\right)^{2}-\left(88\,\frac{ft}{s} \right)^{2}}{2\cdot \left(0.15\right)\cdot \left(-32.174\,\frac{ft}{s^{2}} \right)}[/tex]

[tex]d = 802.304\,ft[/tex]

The approximate braking distance is 802.304 feet. [tex]\blacksquare[/tex]

c) The total distance is the sum of distances found in a) and b). Then, the total distance is 868.304 feet. [tex]\blacksquare[/tex]

To learn more on accelerated motion, we kindly invite to check this verified question: https://brainly.com/question/8360634

It would take 10 gardeners to plant 45 trees in 45 minutes.

It's a math tool for solving problems about proportion. You can relate more than 2 variables and from the proportion, it's possible to find an unknown number.

The question gives:

6 gardeners can plant 18 trees in 30 minutes.

?  gardeners can plant 45 trees in 45 minutes.

6 gardeners can plant [tex]\frac{18\; tree}{30\; min}=\frac{3}{5}[/tex] trees/min. You can calculate the second rate from   [tex]\frac{45\; tree}{45\; min}=\frac{1}{1}=1[/tex] tree/min.

Write the previous text information in form of proportion.

6 gardeners  ----------- 3/5 trees/min

x gardeners  ----------- 1 tree/min

Then, applying cross multiplication:

[tex]\frac{3x}{5}=6\\ \\ 3x=30\\ \\ x=10[/tex]

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Answer:

y = -(5/4)x - (1 3/4)

Step-by-step explanation:

A line parallel to y= -(5/4)x - 6 will have the same slope, -(5/4), but a different value for the y-intercept, which is -6 in this equation.  This means we can write:

y = -(5/4)x + b

As klong a b is not -6, the line will be parallel.  But we are told that point (5,-8) must be on the new line.  That means we need to select a value of b to make that happen.  By shifting b, we can move the straight line up or down.  To move it so that it goes through (5,8), enter that point in the equation and solve for b:

y = -(5/4)x + b

-8 = -(5/4)*5 + b   for (5,-8)

-8 = -(25/4) + b

b = -8 + (25/4)

b = -(32/4)+(25/4)

b = -(7/4) or - 1 3/4

The parallel line that goes through (5,-8) is y = -(5/4)x - 2

Answer:

y=-5/4x-7/4

Step-by-step explanation:

Answer:

Answer is 4

Step-by-step explanation:

35 times table

35 x 5= 175 too large

35X4= 140

Answer:

x = -24/5

none of the options listed

Step-by-step explanation:

27=−5x+3

the choices all have x listed as a positive number, so we need to fix the question by moving 5x to the other side of the = and changing its sign.

27 +5x= 3

then move the 27

5x= 3 -27

then subtract

5x = -24

then divide both sides by 5

x = -24/5

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1 us liquid quart =

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Answer:

#29983873 is the best answer

Answer:

soln;

given equation is 6x + 5 = 2y

or, 6x -2y + 5 = 0

comparing with ax + by + c = 0

a = 6, b = -2, c = 5

The graph that models the scenarios must increase upwards since it is a growth rate.

Given the exponential function expressed as:

f(x)=250(1.10)^x-4

where

x is the time taken

The graph that models the scenarios must increase upwards since it is a growth rate. The required graph is as shown below;

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Answer:

D on edge

Step-by-step explanation:

Answer:

C

explanation:

if The P-Value is low reject H0

The correct P-value and conclusion based on the null hypothesis. The correct option is C. P-value < 0.005. Reject H₀.

In this problem, we will use the P-value method to test a claim about the mean score of job applicants in a programming test. The claim is whether the sample of 25 job applicants from a large university comes from a population with a mean score greater than 160, given that the population is normally distributed. We'll use a significance level of 0.05 to make our decision. We'll set up the null and alternative hypotheses, calculate the test statistic, and find the P-value to draw a conclusion about the claim.

Let's begin by defining the null and alternative hypotheses:

- Null Hypothesis (H₀): The mean score of job applicants from the university is not greater than 160. H₀: μ ≤ 160.

- Alternative Hypothesis (H₁): The mean score of job applicants from the university is greater than 160. H₁: μ > 160.

Here, μ represents the true population mean score.

Next, we'll calculate the test statistic. Since the population standard deviation (σ) is not known, we'll use the sample's standard deviation (s) and perform a one-sample t-test. The formula for the t-test is:

t = (x' - μ₀) / (s/√n)

Where:

x' is the sample mean,

μ₀ is the hypothesized population mean under the null hypothesis (μ₀ = 160 in this case),

s is the sample standard deviation, and

n is the sample size.

Substituting the given values:

x' = 183 (sample mean)

μ₀ = 160 (hypothesized population mean under H0)

s = 12 (sample standard deviation)

n = 25 (sample size)

t = (183 - 160) / (12/√25)

 = 23 / 2.4

 ≈ 9.583

Now, we need to find the P-value corresponding to this test statistic. Since this is a one-tailed test (claiming that the mean is greater than 160), we look for the area under the t-distribution curve to the right of t = 9.583.

By consulting a t-table or using statistical software, we find that the P-value is significantly less than 0.001. The exact P-value is not provided in the answer options, but it's crucial to note that it is well below 0.005.

Now, we compare the P-value to the significance level (α = 0.05). Since the P-value < α, we reject the null hypothesis (H₀). The data provides strong evidence to support the claim that the mean score of job applicants from the university is greater than 160.

The correct option is C. P-value < 0.005. Reject H₀. The statistical analysis indicates that there is strong evidence to support the claim that the mean score of job applicants from the university is greater than 160.

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Answer:

120 buckets

Step-by-step explanation:

If there are 15 teams and each team gets the same number of buckets (8 buckets as mentioned in the problem), then you can multiply 15 by 8 to get 120.

15 teams * 8 buckets = 120 total buckets

Answer:

The graph shows 2 outliers. The scatter plot consist on a straight pattern. As seen, only 2 points are not within the straight line. We can conclude that only two points are outliers. =

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

I just took the test do not listen to the other persons answer or you will get it wrong. :) no offense. Have a great day everyone.

Answer: none of these

Step-by-step explanation:

They are not supplementary because 101+77 = 178 and not 180.

They are not complementary because 101+77 = 178 and not 90.

They are not vertical because there are no intersecting lines and the two angle measures are not equal.

Therefore, none of these are true.

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{7\% of 47}}{\left( \cfrac{7}{100} \right)47}\implies 3.29[/tex]