PLEASE HELP ME!

i’ll mark brainliest if you’re correct!!

[tex]11 = -5x-2\\5x = -2-11\\5x =-13\\x = -13/5[/tex]

Answer: x = -13/5

Ok done. Thank to me :>

Answer:

44 sq. in.

Step-by-step explanation:

Area (total) = (1/2)(3)(4) + 10(3) + (1/2)(8)(2)

= 6 + 30 + 8

= 44 sq. in.

Answer:

Simplify the expression.

X+10x+1

Answer:

X+10x+1

Step-by-step explanation:

this would be your answer

Answer:

soln;

given equation is 6x + 5 = 2y

or, 6x -2y + 5 = 0

comparing with ax + by + c = 0

a = 6, b = -2, c = 5

Answer:

Answer is 4

Step-by-step explanation:

35 times table

35 x 5= 175 too large

35X4= 140

Answer:

B

Step-by-step explanation:

I got it right in ed2022

Answer:

Correct, answer is indeed 24.

Step-by-step explanation:

took the quiz

It would take 10 gardeners to plant 45 trees in 45 minutes.

It's a math tool for solving problems about proportion. You can relate more than 2 variables and from the proportion, it's possible to find an unknown number.

The question gives:

6 gardeners can plant 18 trees in 30 minutes.

?  gardeners can plant 45 trees in 45 minutes.

6 gardeners can plant [tex]\frac{18\; tree}{30\; min}=\frac{3}{5}[/tex] trees/min. You can calculate the second rate from   [tex]\frac{45\; tree}{45\; min}=\frac{1}{1}=1[/tex] tree/min.

Write the previous text information in form of proportion.

6 gardeners  ----------- 3/5 trees/min

x gardeners  ----------- 1 tree/min

Then, applying cross multiplication:

[tex]\frac{3x}{5}=6\\ \\ 3x=30\\ \\ x=10[/tex]

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By getting the exponential decay that models the situation, we will see that after 8 weeks she uses 0.12 cups.

We know that the first week, she uses 2 cups of sugar, and each week she uses removes one-third of what she used the previous week.

Then the second week she uses:

S₂ = 2 cups - (1/3)*(2 cups) = 2 cups*(1 - 1/3) = 2 cups*(2/3)

The third week she uses:

S₃ = 2 cups*(2/3) - (1/3)*2 cups*(2/3) = 2 cups*(2/3)^2

You already can see the pattern, at week x, she will use:

Sₓ = (2 cups)*(2/3)^(x - 1)

This is an exponential decay.

To get how much sugar does she uses after 8 weeks, we just replace x by 8 in the above equation:

S₈ = (2 units)*(2/3)^(8 - 1) = 0.12 cups of sugar.

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Answer:

[tex]11 \frac{2}{3} [/tex]

Years

Step-by-step explanation:

Let x be his current age

[tex] \frac{3}{5} x - 4 = 0 \\ x + 5 = [/tex]

Solve the expression:

[tex] \frac{3}{5} x - 4 = 0 \\ + 4 \\ \frac{3}{5} x = 4 \\ \times \frac{5}{3} \\ x = 4( \frac{5}{3}) \\x = \frac{20}{3} \\ x = 6 \frac{2}{3} [/tex]

[tex]x + 5 \\ 6 \frac{2}{3} + 5 \\ 11 \frac{2}{3} [/tex]

Answer:

-33/16

I'm pretty sure it is c sorry if not may be -39/16

The equations that describe the given circles are:

x^2 + y^2 = 4

x^2 + y^2 = 64

For a circle of radius R, centered at the point (a, b), the equation is:

(x - a)^2 + (y - b)^2 = R^2

In this case, we have two circles, both centered on (0, 0), but one has a radius of 2 units and the other a radius of 8 units, then we have two equations:

x^2 + y^2 = 2^2 = 4

x^2 + y^2 = 8^2 = 64

These are the two equations that describe the given circles.

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Answer:

35

Step-by-step explanation:

350miles/10=10gallons/10

=35miles=1gallon

Answer:

Lets say we have (-1)^(1.5)

Step-by-step explanation:

(-1)^(1.5) = (-1)^(3/2)

= (√(-1))^3 which has no solution in the real number field, as √(-1) does not exist.

In the complex number field √(-1) = i, and (-1)^(1.5) = i^3 = -i.

Answer:

#29983873 is the best answer

First off, no sides have the same length as the others, so it cannot be an equilateral or an isoceles triangle, as it would required at least 2 sides to have the same length.

So, we're left with scalene triangle options.

There is an angle that is an obtuse angle (as it is more than 90 degrees and less than 180 degrees), so this is a scalene obtuse triangle.

Answer:

X=3, or X=-3   But the positive answer is X=3

Step-by-step explanation:

Rewrite the equation 5x^2+2=47

Subtract 2 from each side -----> 5x^2+2-2=47-2

Simplify   ---------> 5x^2=45

divide each side by 5 ----->  5x^2/5=45/5

Simplify x^2=9

Divide each side by using square root method -->  Sqrt(9)     - sqrt(9)

Now simplify to get X=3, or X=-3

a) The approximate reaction distance is 66 feet.

b) The approximate braking distance is 802.304 feet.

c) The total distance is 868.304 feet.

The average reaction time ([tex]t_{R}[/tex]) is 0.75 seconds. Manuel drives at constant velocity in the first 0.75 seconds, then he decelerates the vehicle.

a) The reaction distance ([tex]x_{R}[/tex]), in meters, is found by the following expression:

[tex]x_{R} = v_{o}\cdot t_{R}[/tex] (1)

Where [tex]v_{o}[/tex] is the initial velocity, in feet per hour.

If we know that [tex]v_{o} = 60\,\frac{mi}{h}[/tex] ([tex]v_{o} = 88\,\frac{ft}{s}[/tex]) and [tex]t_{R} = 0.75\,s[/tex], then the approximate reaction distance is:

[tex]x_{R} = (88)\cdot (0.75)[/tex]

[tex]x_{R} = 66\,ft[/tex]

The approximate reaction distance is 66 feet. [tex]\blacksquare[/tex]

b) A normal braking has magnitudes of about 0.15 times the value of gravitational acceleration ([tex]g = 32.174\,\frac{ft}{s^{2}}[/tex]). The approximate braking distance ([tex]d[/tex]), in feet, is found by the following kinematic formula:

[tex]d = \frac{v^{2}-v_{o}^{2}}{2\cdot a}[/tex] (2)

Where:

If we know that [tex]v_{o} = 88\,\frac{ft}{s}[/tex] and [tex]v_{o} = 0\,\frac{ft}{s}[/tex], then the approximate braking distance is:

[tex]d = \frac{\left(0\,\frac{ft}{s}\right)^{2}-\left(88\,\frac{ft}{s} \right)^{2}}{2\cdot \left(0.15\right)\cdot \left(-32.174\,\frac{ft}{s^{2}} \right)}[/tex]

[tex]d = 802.304\,ft[/tex]

The approximate braking distance is 802.304 feet. [tex]\blacksquare[/tex]

c) The total distance is the sum of distances found in a) and b). Then, the total distance is 868.304 feet. [tex]\blacksquare[/tex]

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Answer: -31

Step-by-step explanation:

5x³- 3x + 2 = 0

a = 5, b = -3, c = 2

(-3)² -4 × 5 × 2

-31

Answer:

[tex]\sf 4[/tex]

Explanation:

[tex]\sf \frac{1}{4} (15+h)-g[/tex]

[tex]\sf given: h = 5 , \ g = 1[/tex]

solve:

[tex]\sf \frac{1}{4} (15+5)-1[/tex]

[tex]\sf \frac{1}{4} (20)-1[/tex]

[tex]\sf 5-1[/tex]

[tex]\sf 4[/tex]

Answer:

x = -24/5

none of the options listed

Step-by-step explanation:

27=−5x+3

the choices all have x listed as a positive number, so we need to fix the question by moving 5x to the other side of the = and changing its sign.

27 +5x= 3

then move the 27

5x= 3 -27

then subtract

5x = -24

then divide both sides by 5

x = -24/5

Answer:

I think it's C

Step-by-step explanation:

360°-232° = 128°

The complete factor of the expression [tex]\rm 3x (x +2) + 4 (x +2)[/tex] is [tex]\rm(x+2)(3x + 4)[/tex]. Then the correct option is A.

It is the method to separate the polynomial into parts and the parts will be in multiplication. And the value of the polynomial at this point will be zero.

The expression is [tex]\rm 3x (x +2) + 4 (x +2)[/tex].

To solve the expression properly we have to take common (x+2). Then we have

[tex]\rm 3x (x +2) + 4 (x +2)\\\\(x+2)(3x + 4)[/tex]

The correct factor is (x + 2)(3x + 4).

More about the factorization link is given below.

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Answer:

Yup A

Step-by-step explanation:

Answer: Assume π = 3.14(rounded upto two decimal point)

Case I. 1 year = 365 days

2 years = 730 days

3 years = 1095 days

And .14 years = 51 days 2 hours 24 minutes

So, 3.14 years = 1146 days 2 hours 24 minuts.

Now, suppose you born in a leap-year.

Case II. 1 year = 366 days

2 years = 732 days

3 years = 1098 days

and .14 years = 51 days 5 hours 45 minutes 36 seconds

Then, 3.14 years = 1149 days 5 hours 45 minuts 36 seconds

So, yes, it is possible to be exactly π years old. At exactly 1146 days 2 hours 24 minutes or 1149 days 5 hours 45 minutes 36 seconds (in case of a leap-year born), we could have celebrate at our π years birthday.

Step-by-step explanation:

Answer:

C

explanation:

if The P-Value is low reject H0

The correct P-value and conclusion based on the null hypothesis. The correct option is C. P-value < 0.005. Reject H₀.

In this problem, we will use the P-value method to test a claim about the mean score of job applicants in a programming test. The claim is whether the sample of 25 job applicants from a large university comes from a population with a mean score greater than 160, given that the population is normally distributed. We'll use a significance level of 0.05 to make our decision. We'll set up the null and alternative hypotheses, calculate the test statistic, and find the P-value to draw a conclusion about the claim.

Let's begin by defining the null and alternative hypotheses:

- Null Hypothesis (H₀): The mean score of job applicants from the university is not greater than 160. H₀: μ ≤ 160.

- Alternative Hypothesis (H₁): The mean score of job applicants from the university is greater than 160. H₁: μ > 160.

Here, μ represents the true population mean score.

Next, we'll calculate the test statistic. Since the population standard deviation (σ) is not known, we'll use the sample's standard deviation (s) and perform a one-sample t-test. The formula for the t-test is:

t = (x' - μ₀) / (s/√n)

Where:

x' is the sample mean,

μ₀ is the hypothesized population mean under the null hypothesis (μ₀ = 160 in this case),

s is the sample standard deviation, and

n is the sample size.

Substituting the given values:

x' = 183 (sample mean)

μ₀ = 160 (hypothesized population mean under H0)

s = 12 (sample standard deviation)

n = 25 (sample size)

t = (183 - 160) / (12/√25)

 = 23 / 2.4

 ≈ 9.583

Now, we need to find the P-value corresponding to this test statistic. Since this is a one-tailed test (claiming that the mean is greater than 160), we look for the area under the t-distribution curve to the right of t = 9.583.

By consulting a t-table or using statistical software, we find that the P-value is significantly less than 0.001. The exact P-value is not provided in the answer options, but it's crucial to note that it is well below 0.005.

Now, we compare the P-value to the significance level (α = 0.05). Since the P-value < α, we reject the null hypothesis (H₀). The data provides strong evidence to support the claim that the mean score of job applicants from the university is greater than 160.

The correct option is C. P-value < 0.005. Reject H₀. The statistical analysis indicates that there is strong evidence to support the claim that the mean score of job applicants from the university is greater than 160.

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[tex]\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{7\% of 47}}{\left( \cfrac{7}{100} \right)47}\implies 3.29[/tex]

Answer:

$20.70

Step-by-step explanation:

5 × $3.70 = $18.50 + $2.20 =

$20.70

Answer:

something attained by mental effort and especially by computation

is called a solution, When you solve you get the solution meaning you have to tryed and never given up , to gain the solution.