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Usually scientists will a large isotope such as Uranium-235 with a ____.
The collision results in several more nuclear fissions, also known as a _____. This results in a HUGE release in energy!

Answer:

Explanation:

Here, we want to get the class of lipids that the given substances belong to

These substances are formed from glycerol and fatty acids

From their make up,we know that they are simple lipids

Thus, the answer here is simple

Step 1

The reaction must be written, completed, and balanced:

2 NaOH + H2SO4 => Na2SO4 + H2O

-----------

Step 2

Information provided:

Mass of NaOH = 40.0 g

Mass of H2SO4 = 60.0 g

--

Information needed:

The molar masses:

NaOH) 40.0 g/mol approx.

H2SO4) 98.0 g/mol approx.

-----------

Step 3

The limiting reactant?

By stoichiometry:

1 mole NaOH = 40.0 g

1 mole H2SO4 = 98.0 g

2 NaOH + H2SO4 => Na2SO4 + H2O

2 x 40.0 g NaOH ----------- 98.0 g H2SO4

40.0 g NaOH ----------- X

X = 40.0 g NaOH x 98.0 g H2SO4/2 x 40.0 g NaOH = 49.0 g H2SO4

For 40.0 g of NaOH, 49.0 g of H2SO4 is needed but is provided 60.0 g of H2SO4. Therefore, the excess is the H2SO4, and the limiting reactant is the NaOH.

Answer: the limiting reactant is NaOH

The pressure of the refrigerant using the ideal-gas equation is 1.861 MPa, the generalized compressibility chart is 1.583 MPa and the refrigerant tables is 1.6 MPa.

Ideal gas equation is defined as the state equation for a fictitious perfect gas. Although it has significant drawbacks, it is a decent approximation of the behavior of many gases under various conditions.

Ideal gas equation is expressed as

PV = nRT

By using Ideal gas equation

P x 0.016773 = 1 x 81.49 x 483

P = 1.861 MPa

By using generalized compressibility chart

For r134a

Temperature = 374.2 K

Pressure = 4.06 MPa

vR = V / R x Tc / Pc

    = 0.016773 / 81.49 x ( 374.2 / 4.06 x 10⁶ )

    = 2.2332

Tr = T/Tc = 383 / 374.2 = 1.024

Therefore from the chart Z = 0.85

So, P = Z mRT / V

      P = 0.85 x 1 x 81.49 x 383 / 0.016773

         = 1.582 MPa

By using refrigerant tables

T = 110 C and v = 0.0167763

So, P = 1.6 MPa

Thus, the pressure of the refrigerant using the ideal-gas equation is 1.861 MPa, the generalized compressibility chart is 1.583 MPa and the refrigerant tables is 1.6 MPa.

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Water molecules that have escaped or evaporated from the body of water then water get excited and they begin to gain kinetic energy

A water molecule has a three atom two hydrogen and one oxygen atom and that's why water is sometime refred to as H₂O and a single drop of water contain billion drop of molecule and evaporation is the process in which given to the change that occurs to a substance that changes it from its liquid state to a gaseous state

When water get evaporates the molecule of water in a glass will get excited and they begin to gain kinetic energy and vigorously hit the wall of glass

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It is the same for every sample of every substance present describes an intensive property of matter.

The correct option is C.

An intense property is a greater stability of a system that is independent of the system's size or the volume of its constituent elements. Based on the definitions, internal energy, volume, or density are extensive properties while pressure, temperature, and densities are intensive properties.

Because of the small range of densities present among the samples, density is an intense attribute. Concentrations were roughly the same regardless of the beginning mass. The data show that density is an intense attribute of matter because it is independent of the amount of substance present.

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The complete question is

Which statement describes an intensive property of matter?

A-It is the same for every sample of a single substance.

B-It depends on how a substance was formed.

C-It is the same for every sample of every substance.

D-It depends on the amount of substance present.

Step 1: Write and balance the equation:

3 NaCl + Al(NO3)3 → AlCl3 + 3 NaNO3

Step 2: We need to find the limiting and excess reactant. For this, we need to look at the stoichiometric ratio between the reactants:

3 moles of NaCl reacts with 1 mole of Al(NO3)3.

Now we do a rule of 3 for both.

For 9 moles of NaCl:

3 moles of NaCl --- 1 mole of Al(NO3)3

9 moles of NaCl --- x mole of Al(NO3)3

3x = 9

x = 3 moles of Al(NO3)3

For 4 moles of Al(NO3)3:

3 moles of NaCl --- 1 mole of Al(NO3)3

x moles of NaCl --- 4 moles of Al(NO3)3

x = 12 moles of NaCl

As we can see, to react with 4 moles of Al(NO3)3 we should have 12 moles of NaCl, but we have just 9. So the NaCl is the limiting reactant and the excess reactant is Al(NO3)3.

Step 3: We need to look at the stoichiometric ratio between the limiting reactant (NaCl) and NaNO3:

3 moles of NaCl --- 3 moles of NaNO3

9 moles of NaCl --- x moles of NaNO3

x = 9 moles of NaNO3

Answer: The maximum amount of NaNO3 that was produced during the experiment is 9 moles.

The final pressure of the gas when the sample gas is administered to a new volume of 10.0 L at 20.2℃ would be 0.245 atm.

The problem here has to do with the combined gas law. The law is mathematically expressed as:

[tex]p_1v_1/t_1[/tex] =[tex]p_2v_2/t_2[/tex]

Where [tex]p_1[/tex] = initial pressure, [tex]v_1[/tex] = initial volume, [tex]t_1[/tex] = initial temperature, [tex]p_2[/tex] = final pressure, [tex]v_2[/tex] = final volume, and [tex]t_2[/tex] = final temperature.

In this case,

Rearranging the combined gas equation:

[tex]p_2[/tex] = [tex]p_1v_1t_2/t_1v_2[/tex]

Substituting the different variables:

[tex]p_2[/tex] = 1.2 x 6.02 x 20.2/59.5 x 10.0

      = 145.9248/595

      = 0.245 atm

Thus, the final pressure of the sample gas will be 0.245 atm.

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The shape and bond angle of the molecule will be, H2S =shape= bent, Bond angle =less than 109 degrees

2) CH4 = shape = tetrahedral

bond angle-=109 degrees

1)H2S =shape= bent

Bond angle =less than 109 degrees

2) CH4 = shape = tetrahedral

bond angle-=109 degrees

3) HCN = shape = Linear

Bond angle = 180 degrees

4) NF3 = shape = trigonal planar

Bond angle = less than 109 degrees

5) BCl3 = shape = trigonal planar

Bond angle = 120 degrees

6) NH2Cl = shape = trigonal pyramidal

Bond angle = 107  degrees

7) OF2 = shape = linear

Bond angle = 109 degrees

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Answer

The half-life of the radioactive substance = 12 hours.

Explanation

Given that:

R₀ = 5000 counts/sec

R₁ = 1250 counts/sec

t = 24 hr

What to find:

The half-life of the radioactive substance.

Step-by-step solution:

The half-life of life of the radioactive substance can be calculated using the formula below:

Putting the values of the parameters into the formula, we have:

Thus, the half-life of the radioactive substance is 12 hours.

Of the options given, the correct one for the Lewis structure of CO₂ is option A.  

In the covalent structure of CO₂, each atom will tend to have 8 electrons on its side, in order to comply with the octet rule. In this rule, an atom that has 8 electrons in its valence shell, will gain stability for having a noble gas electronic configuration.      

Hence, the correct lewis structure for CO₂ is option A. In this configuration, each atom has 8 electrons on its side and all of them are neutral (the total charge of the molecule is zero). They all achieve the octet rule.    

Although in option B all the atoms have 8 electrons (thus complying with the octet rule), in this configuration the oxygen atom on the left has a negative charge (-1) and the oxygen on the right side has a positive charge (+1). The total charge on the molecule is zero (it is neutral). In fact, this is a resonance structure of configuration A.    

In option C, the total charge of the molecule is -2, so this is not a stable configuration. The number of electrons on carbon is wrong.  

Finally, in option D the oxygen on the right side does not achieve the octet rule (it only has 6 electrons shared), and also the carbon atom has a charge of -2, and the oxygens have charges of -1 (left) and +3 (right), so this is not a stable configuration.  

Therefore, the correct lewis structure for CO₂ is option A.

The statement they offer personal and professional knowledge is TRUE about expert witnesses (Option A).

The specific role performed by witnesses in a given case is to answer questions associated with a subject matter, which are associated with evidence to confirm or reject a given hypothesis.

Therefore, with this data, we can see that the work performed by witnesses is to provide answers in a given subject matter, which is information that may be used as empirical evidence to confirm or reject a given process.

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To write the numbers with the specific number of significant figures, we need to remember that zeros to the left don't count as a significant figure and also that we can add zeros to the right to add significant figures to the numbers.

1) 1.5408 to 3 significant figures, we start counting from left to right, so we will maintain the numbers until the second decimal place, the "8". Since the next is "0", the rounding is "8", so the number is 1.54.

2) Here is similar, but since we don't have decimal places, we need to put the zeros in place of the numbers we are rounding. Since we want 2 significant figures, we will maintain only the first two. However, since the third is greater than 5, we need to round up, so the number is 4400.

3) To get this, we will maintain the zeros to the elft, but they don't count, so we start counting from the "1". Since the third number is less than 5, we round down, so the number is 0.019.

4) Now, here we have an example we need to add zeros. The way it is, 0.5 has only 1 significant figure, so we need to add 3 more zeros to the right to get to 4 significant figures. The number is 0.5000.

5) Here, is the same as item 3, but we want 3 significant figures and since the fourth is greater than 5 we round it up. So, the number is 0.066.

The pH of the resulting solution  is 10.9 .

given that :

for HClO₄

volume = 25 mL = 0.025 L

M = 0.30 M

no. of moles = 0.025 × 0.30

                     = 0.0075

for CH₃NH₂

no. of moles = 0.35 × 0.06

                    = 0.021

as a resultant no. of moles of CH₃NH₂ that remain in solution

= 0.021-0.0075

= 0.0135

total volume = 0.025 + 0.060

                     = 0.085

the concentration will be :

concentration for HClO₄ = 0.0075 / 0.085

                                         = 0.088 M

concentration for  CH₃NH₂ = 0.0135 / 0.088

                                             = 0.153

kb = 4.4 × 10⁻⁴

pkb = - log kb

pkb = 3.3

the pOH formula is given as :

POH = pKb + log [ acid ] / [ base ]

pOH = 3.3 + log [ 0.088 ] / [ 0.153 ]

pOH = 3.06

pH + pOH = 14

pH = 14 - 3.06

pH = 10.9

Thus, The pH of the resulting solution when 25.0mL of 0.30M HClO₄ is added to 60.0ml of 0.35 M CH₃NH₂. Kb forCH₃NH₂ = 4.4 × 10^-4 . pH is 10.9.

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In order to properly balance an equation, we need to make sure that the same amount of elements on the reactants side matches the number of elements on the products side, we can do that by increasing the number in front of each molecule, the so called stoichiometric coefficient. In the reaction from the question we can properly balance by adding the following stoichiometric coefficients

For this question we have:

CaCl2 -> Ca + 2 Cl

The functional group of the given molecule is located at one of the extremes of it, it is:

This functional group is a carbonyl derived group known as amide. We can recognized because of the carbon that has a double bond with the oxygen and at the same time has a simple bond with nitrogen.

It means that the correct answer is amide.

The total energy to break the hexane bonds will be equal to the sum of each of the energy to break each bond.

So the first thing we're going to do is determine how many and what type of bonds hexane has. Hexane is an alkane, meaning the C-C bonds are all single bonds. We also have C-H bonds. According to the structure of hexane, we will count each of the bonds in the following figure:

The number of C-H bonds is written in blue, we see that there are 14 C-H bonds, which coincides, being an alkane, with the number of hydrogen atoms.

The number of C-C bonds is written in orange. The number of C-C bonds is equal to 5.

Now, we multiply the energy to break each bond by the number of bonds and add the energy of the C-H and C-C bonds.

So, for 1 mol of hexane the energy. required to break all the bonds will be 7514kJ

Answer: The closest value to the answer is 7520. D) 7520 kJ

Answer:

1.11 x 10²³ atoms O

Explanation:

To find the number of oxygen atoms in FeSO₄, you need to (1) convert FeSO₄ from grams to moles (using the molar mass), then (2) convert moles FeSO₄ to moles O (using the mole-to-mole ratio of FeSO₄), and then (3) convert moles O to atoms O (using Avogadro's Number). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs like the given number (7.00 = 3 sig figs).

Atomic Mass (Fe): 55.845 g/mol

Atomic Mass (S): 32.065 g/mol

Atomic Mass (O): 15.999 g/mol

Molar Mass (FeSO₄): 55.845 g/mol + 32.065 g/mol + 4(15.999 g/mol)

Molar Mass (FeSO₄): 151.906 g/mol

1 mole FeSO₄: 1 mole Fe, 2 mole S, 4 moles O

Avogadro's Number:

6.022 x 10²³ atoms = 1 mole

 7.00 g FeSO₄             1 mole                 4 moles O            6.022 x 10²³ atoms
-----------------------  x  -------------------  x  -----------------------  x  ----------------------------
                                   151.906 g           1 mole FeSO₄                  1 mole

=  1.11 x 10²³ atoms O

Organism – Squid

Number of chromosomes after meiosis: 26

Number of chromosomes in the body cells: 52

Number of chromosomes in gametes: 26

Number of chromosomes after mitosis: 52

Organism – Sunflower

Number of chromosomes after meiosis: 19

Number of chromosomes in the body cells: 38

Number of chromosomes in gametes: 19

Number of chromosomes after mitosis: 38

Organism – Pea plant

Number of chromosomes after meiosis: 7

Number of chromosomes in the body cells: 14

Number of chromosomes in gametes: 7

Number of chromosomes after mitosis: 14

Organism – Cow

Number of chromosomes after meiosis: 30

Number of chromosomes in the body cells: 60

Number of chromosomes in gametes: 30

Number of chromosomes after mitosis: 60

Chromosome are made up of genetic material called DNA and it looks like a thread. It is present in the inside of nucleus of a cell.

During meiosis number of chromosomes would be reduced to half whereas in mitosis number of chromosomes remains the same.

The number of chromosomes in body cells is the chromosomal number of an organism and in gametes it would be reduced to half.

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The concentration of C₂H₅OH in the resulting solution is 1.332 M.

given that :

mass of C₂H₅OH = 30.7 g

molar mass =46.07 g/mol

volume =  500 ml = 0.5 L

number of moles can be calculated by the following formula :

number of moles = mass / molar mass

no. of moles = 30.7 g / 46.07 g/mol

no. of moles = 0.666 mol

now, the concentration of C₂H₅OH :

Molarity = no. of mole / volumes in l

Molarity = 0.666 / 0.5

Molarity = 1.332 M

Thus, If 30.7 g of C₂H₅OH (MM = 46.07 g/mol) are added to a 500.0 mL volumetric flask, and water is added to fill the flask, The concentration of C₂H₅OH in the resulting solution is 1.332 M.

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Answer:

Iron 24.03%

Carbon 30.90%

Hydrogen 3.86%

Oxygen 41.20 %

Explanation:

Here, we want to get the percentage composition of the given compound

What this means is that we want to get the percentage composition of each of the elements present in the compound

Firstly, we calculate the molar mass of the given compound

We can calculate the molar mass by adding the atomic masses of the elements and their multiplicities

Mathematically, we have that as:

Now, let us get the percentage compositions

For Iron, we have:

For Carbon, we have:

For Hydrogen, we have:

For Oxygen, we have:

A possible gold variant has a mass of 192. Yes, it has 79 neutrons in this variant.

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A ionic compound is made of two ions, one with positive charge and the other one with a negative charge.

The ion with positive charge is known as cation and the one with negative charge is known a anion.

It means that the correct answer is A. A positive cation and a negative anion.

When the magnesium ribbon is burned, it enters the carbon dioxide gas jar and continues to burn. The carbon is left behind as a black soot and extra energy is released as a result of the reaction where the magnesium atoms join the oxygen in the carbon dioxide to form magnesium oxide.

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The frequency of the green light from a traffic signal is 5.76 * 10¹⁴ Hz

The frequency of the light is 1.85 * 10¹⁶ Hz

The frequency of the light is 4.84 * 10¹⁴ Hz

The energy of the photons is 1.172 * 10⁻³ J

The energy of the photons is 4.34 * 10⁻² J

The frequency of light can be found given the wavelength from the formula below:

8. The frequency of the green light from a traffic signal is calculated below:

velocity of light = 3.0 * 10⁸ m/s

wavelength = 5.2 x 10⁻⁷ m

Frequency = 3.0 * 10⁸ / 5.2 x 10⁻⁷

frequency = 5.76 * 10¹⁴ Hz

9. The frequency of the light is calculated below:

velocity of light = 3.0 * 10⁸ m/s

wavelength = 16.23 x 10⁻⁹ m

Frequency = 3.0 * 10⁸ / 16.23 x 10⁻⁹

frequency = 1.85 * 10¹⁶ Hz

10. The frequency of the light is calculated below:

velocity of light = 3.0 * 10⁸ m/s

wavelength = 6.2 x 10⁻⁷ m

Frequency = 3.0 * 10⁸ / 6.2 x 10⁻⁷

frequency = 4.84 * 10¹⁴ Hz

11. The energy of one of the photons will be calculated as follows:

E = hf

E = hc/λ

Energy of the photons =  2.3 x 10¹¹ x hc/λ

h = 6.626 * 10⁻³⁴Js

λ = 3.9 x 10⁻¹² m

c = 3.0 * 10⁸ m/s

E =   2.3 x 10¹¹ x 6.626 * 10⁻³⁴ * 3.0 * 10⁸ / 3.9 x 10⁻¹²

E = 1.172 * 10⁻³ J

12. The energy of one of the photons will be calculated as follows:

E = hf

E = hc/λ

Energy of the photons =  9.4 x 10¹⁶ x hc/λ

h = 6.626 * 10⁻³⁴Js

λ = 4.3 x 10⁻⁷ m

c = 3.0 * 10⁸ m/s

E =   9.4 x 10¹⁶ x 6.626 * 10⁻³⁴ * 3.0 * 10⁸ / 4.3 x 10⁻⁷

E = 4.34 * 10⁻² J

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The final temperature if the final pressure is 0.65 atm will be 585 K

It is given that

Initial Volume of sample = V1 = 6.5 L

Initial temperature = T1 = 298 K

Initial pressure = P1 = 0.51 atm

Final Volume = V2 = 9.9 L

Final temperature = T2 = ?

Final pressure = P2 = 0.65 atm

Gay-Lussac's law - The pressure of a gas is directly proportional to the. temperature when volume and amount of substance is constant. P1/T1 = P2/T2 Combined gas law P1V1/T1 = P2V2/T2 Use the gas laws for pressure, volume and temperature calculations.

P1V1/T1 = P2V2/T2

0.52 x 6.5/298 = 0.65 x 9.9/T2

0.011 = 6.435/T2

T2 = 585 K

Hence, final temperature if the final pressure is 0.65 atm will be 585 K

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During the electrolysis of the molten lithium chloride, the Lithium ions (Li⁺) at the cathode undergoes reduction, and the electron configuration of lithium becomes 1s²2s¹.

Electrolysis can be described as the process in which the electric current is passed through the chemical compound to break them.  In this process, the atoms and ions are interchanged by the addition or removal of electrons.

The ions are allowed to move freely in this process. When an ionic compound is melted or dissolved in water then ions are produced which can move freely.

During the electrolysis of molten lithium chloride, the lithium ions reach the cathode and accept the electrons while chloride ions reach at anode and loss electrons to become chlorine gas.

At anode :  2 Cl⁻ →    Cl₂ + 2e⁻

At cathode:   2 Li⁺   +   2e⁻  →  Li

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In this question, we have to find the number of atoms in 12.5 moles of Sulfur, and the way to do it is by using the Avogadro's number, which is 6.02*10^23 atoms, this value represents how many atoms we have in 1 single mol of any element. Therefore in 12.5 moles we will have:

1 mol = 6.02*10^23 atoms

12.5 moles = x atoms

x = 7.52*10^24 atoms of Sulfur in 12.5 moles

To solve this problem we can use the Ideal gas law:

The problem give us de following information:

P1= 131kPa

V1=1.82L

T1=-30°C= 243.15 K

P2= 233 kPa

V2= 1.3L

Then we just have to solve for T2 and use the information provided:

Then the answer is T2=35.76°C

Answer: 43.38 number of atoms

Explanation: If you look at this formula, then this one molecule contains six oxygen atoms. That means number of moles of oxygen atoms. That is six times the number of moles and of calcium nitrate, That is six, multiply 7.23, which comes out to be 43.38 moles of oxygen atom.