please i’m begging someone to solve these for me ..

The dotplot shows the number of days on which the train arrived late in 100 repetitions of the simulation

4. Explain what the dot at 7 represents.

5. Use the results of the simulation to estimate the probability that the train will arrive late on 3 or more of 20 days.

6. Based on the actual result of 3 late arrivals in 20 days and your answer to Question 5, is there convincing evidence that New Jersey Transit's claim is false? Explain your reasoning.

The cat and the squirrel will meet again at the finish line after 10 minutes.

To calculate how long it takes for both animals to meet again at the goal, we must identify the useful information to solve this problem, the information is presented below.

According to the above, we must find a number that when divided by 5 and 2 gives us an integer. For example, 10 divided by 2 would give 5, that is, the cat would turn 2 times in this time. If we divide 10 into 2, they would give us 5, which means that the squirrel would go around 5 times in this time. So the answer would be 10 minutes.

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a. She had in her savings to begin with $212.5

b. She has $127.5 left in her savings after buying the bicycle.

Answer:

a) Molly had $212.50 in her account to begin with.

b) She has $127.50 in her account after buying the bicycle.

Step-by-step explanation:

40% of what number is 85.

.4x = 85  Divide both sides by .4

x = 212.50

212.50 - 85 = 127.50

Another way to look at it is if she spent 40%, she still have 60% left in her account.

.6 x 212.50 = 127.50

To find the linear distance needed for the staircase, you can multiply the number of steps by the width of each step. The length of the railing that would be attached to these stairs would be 7.6m.

3.6 m / (18 cm / 100 cm/m) = 20 steps

20 steps * 28 cm/step = 560 cm = 5.6 m

5.6 m + 2 m = 7.6 m.

The distance between the two specified sites or objects is the linear measurement. Therefore, we may define length as "the total distance measured between an object's outermost left and right ends in the aforementioned system of units." utilizing tape to gauge a banana's length. The length is around 5 inches. Children can measure nearby things such as a pencil, a shoe, a remote control, a toy vehicle, and a spoon using tools like a ruler and tape.

The example that follows shows how to measure the length of a screwdriver by placing a ruler against it. Place the item and ruler such that the ruler's tip is at "0" to get the length. To determine the object's overall length, make a mark with a number at the end.

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Answer:

[tex]c=47[/tex]

Step-by-step explanation:

[tex]c-14=33[/tex]

Step 1: Add 14 to both sides.

[tex]c-14+14=33+14[/tex]

[tex]c=47[/tex]

The completed table that indicates the values of the specified exponential expressions is presented as follows;

[tex]\begin{array}{|c|c|cc|}\\2&1&\dfrac{1}{2} &\\&&&\\\dfrac{\left(3^7\cdot 4^7\right)\cdot \left(2\cdot 5\right)^{-3}\cdot \left(5^2\right)}{12^7\cdot 5^{-1}\cdot 2^{-4}} &\dfrac{\left(2\cdot 3\right)^{-1}\cdot 2^0}{\left(2\cdot 3\right)^{-1}} &\left(3^3\right)\cdot \left(4^0\right)^2\cdot \left(3\cdot 2\right)^{-3}\cdot \left(2^2\right) &\\ &&& \\&\dfrac{\left(2\cdot 3^{-2}\right)^3\cdot \left(5\cdot 3^2\right)^2}{\left(3^{-2}\right)\cdot \left(5\cdot 2\right)^2} & & \\\end{vmatrix}[/tex]

An exponential expression is a mathematical expression that consists of numbers and or variables that have index of numbers and or variables, validly combined together using mathematical operators.

The exponential expressions are;

First expression;

[tex]\dfrac{\left(2\cdot 3^{-2}\right)^3 \times \left(5\cdot 3^2\right)^2}{\left(3^{-2}\right)\cdot \left(5\cdot 2\right)^2}[/tex] = (2³ × 3⁻⁶) × (5² × 3⁴) ÷ ((3⁻²) × (5 × 2)²)

(2² × 3⁻⁶) × (5² × 3⁴) ÷ ((3⁻²) × (5² × 2²)) = 2⁽²⁻²⁾ × 3⁽⁻⁶⁺²⁺⁴⁾ × 5⁽²⁻²⁾

2⁽²⁻²⁾ × 3⁽⁻⁶⁺²⁺⁴⁾ × 5⁽²⁻²⁾ = 2⁰ × 3⁰ × 5⁰ = 1

Second expression;

(3³)×(4⁰)²×(3×2)⁻³(2²) = 3⁽³⁻³⁾ × (4⁰)² × 2⁽² ⁻ ³⁾ = 3⁰ × 4⁰ × 2⁻¹ = 1/2

(3³)×(4⁰)²×(3×2)⁻³(2²) = 1/2

Third expression;

(3⁷·4⁷) × (2·5)⁻³ × (5²) ÷ (12⁷ × 5⁻¹ × 2⁻⁴)

(3⁷·4⁷) × (2·5)⁻³ × (5²) ÷ (12⁷ × 5⁻¹ × 2⁻⁴) = (3×4)⁷ × (2⁽⁻³ ⁺ ⁴⁾) × 5⁽⁻³⁺¹⁺²⁾ ÷ 12⁷

12⁽⁷⁻⁷⁾ × (2⁽⁻³ ⁺ ⁴⁾) × 5⁽⁻³⁺¹⁺²⁾ = 12⁰ × 2 × 5⁰ = 2

Therefore;

(3⁷·4⁷) × (2·5)⁻³ × (5²) ÷ (12⁷ × 5⁻¹ × 2⁻⁴) = 2

Fourth expression;

(2·3)⁻¹ × 2⁰ ÷ (2 × 3)⁻¹

2⁽⁻¹⁺¹⁾ × 3⁽⁻¹⁺¹⁾ × 2⁰  = 2⁰ × 3⁰ × 2⁰ = 1 × 1 × 1 = 1

(2·3)⁻¹ × 2⁰ ÷ (2 × 3)⁻¹ = 1

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The mathematical result applied to prove sin²Ф + cos² = 1 , is the Pythagorean theorem.

Any right triangle has an area equal to the sum of a sides of the squares which sides are the two legs (remember, the hypotenuse is the side opposite the right angle).

Consider the given triangle ABC, right angled at C.

Then,

AC² + BC² = AB²

Divide the equation by AB².

AC²/ AB² + BC²/ AB² = AB²/ AB²

(opposite/ hypotenuse)² + (adjacent/ hypotenuse)² = 1

Thus,

sin²Ф  = (opposite/ hypotenuse)²

cos² =  (adjacent/ hypotenuse)²

Then,

sin²Ф + cos² = 1

Thus, the mathematical result applied to prove sin²Ф + cos² = 1 , is the Pythagorean theorem.

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The consequences of this congruence are AB is parallel to CD( property of parallelogram)

∠ABD is congruent to ∠CDB( Angles opposite of equal sides are congruent)

That quadrilateral in which opposite sides are parallel is called a parallelogram.

Thus, a parallelogram is always a quadrilateral but a quadrilateral can or cannot be a parallelogram.

We are given that ABCD is a parallelogram and [DB] is one of its diagonals.

In  Δs ABD and CDB

The Lines AB and CD are parallel

Therefore Angle B and Angle D are equal ; both angles are equal as they are alternate interior angles.

So An angle is always congruent to itself (Reflexive property of congruence)

Hence, the proved that Δs ABD and CDB are congruent.

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The measure of the given angle is given as 1.25 π radian the measure of the shaded portion is 40 π radian

The given figure is a circle to find the shaded portion we use the formula for area of sector in radian

Area of sector = (1/2) × r²θ

1.25 π radian = θ

8 = radius, r

Area of sector = (1 / 2) × 8² * 1.25 π radian

Area of sector =  (1 / 2) × 64 * 1.25 π radian

Area of sector =  (1 / 2) × 80 π radian

Area of sector =  40 π radian

The area of the sector the shaded portion is 40 π radian

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Answer:

$62091.53

Step-by-step explanation:

Their starting money was 74561.49, so we add that with the interest she gained and her deposits. That comes out to 77442.40. Then we subtract her two withdrawals, and we get to $62,091.53.

Answer:

Part A: From the table, it is clear that as the number of workers increases, the number of units produced also increases. This indicates a positive correlation between the number of workers and the number of units produced. As the number of workers increases by 10, the number of units produced also increases by 50. This pattern is consistent throughout the data, which supports the conclusion that there is a positive correlation between the number of workers and the number of units produced.

Part B: A function that best fits the data is y = 5x + 2, where y is the number of units produced and x is the number of workers. This function can be determined by using the slope-intercept form of a linear equation (y = mx + b) and substituting the values for the slope and y-intercept from the data. The slope (m) of the function is 5 and the y-intercept (b) is 2.

Part C: The slope of the plot (5) represents the rate of change in the number of units produced for every 1 unit change in the number of workers. In this case, for every 1 additional worker, the number of units produced increases by 5. The y-intercept (2) represents the point at which the line intercepts the y-axis when x = 0. In this case, when there are no workers, 2 units are produced.

Answer:

Step-by-step explanation:

Answer: C and D respectively

Step-by-step explanation:

To find the sum "n"  consecutive even/odd integers you need to do x + (x+2) + (x + 4) ... for n times. You can just add them and solve.

To find the sum of "n" consecutive integers you need to do x + (x + 1) + (x + 2) ... for n times. In this problem we do x + (x + 1) + (x + 2) = 96; 3x +3 = 96; x = 31. Then we can find the other numbers by plugging in 31 for x. 31, 32, 33.

The value of x using trigonometric functions will be 5.66.

What are trigonometric functions?

Trigonometric functions are also known as Circular Functions can be simply defined as the functions of an angle of a triangle. It means that the relationship between the angles and sides of a triangle are given by these trigonometric functions. The basic trigonometric functions are sine, cosine, tangent, cotangent, secant and cosecant.

The angles of sine, cosine, and tangent are the primary classification of functions of trigonometry. And the three functions which are cotangent, secant and cosecant can be derived from the primary functions

Now,

In given triangle, 3rd angle will be 54 degree.

                                         (Sum of all angle in triangle=180degree)

Therefore

               sin 54=P/H  (P=Perpendicular, H=Hypotenuse)

                0.809=x/7

               x=7*0.809

              x=5.66

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Answer: The weight of each screwdrivers is 100 grams.

Step-by-step explanation: Solution:

Given,

wrench weight= 600 grams

weight of 1 screwdrivers =?

By the question

wrench weighs 3 times as much as 2 screwdrivers

So,

           2 screw drivers= 600g÷3

                                     = 200g

             1screw drivers = 200g÷2

                                      = 100grams

Therefore, one screwdriver weight is 100 grams.

Using factorization, the algebraic expression 27d⁶ + 8g¹² is equal to (3d² + 2g⁴)(9d⁴ - 6d²g⁴ + 4g⁸)

Factorization, also known as factoring, is the process of breaking down a number or an algebraic expression into its prime factors. It is a mathematical process that helps to simplify complex algebraic equations and it is used in a variety of mathematical applications, including algebra, calculus, and number theory.

In this problem, we have an expression in which can be factored to produce two smaller expressions.

27d⁶ + 8g¹² = (3d² + 2g⁴)(9d⁴ - 6d²g⁴ + 4g⁸)

The expression 27d⁶ + 8g¹² is equal to (3d² + 2g⁴)(9d⁴ - 6d²g⁴ + 4g⁸)

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The solution to the given system of equations as given in the task content.is; x = 6 and y = 4.

It follows that the given system of equations is;

Y equals X minus 2X plus Y equals 10

y = x - 2

x + y = 10

By substituting y into the second equation; we have;

x + x - 2 = 10

2x = 10 + 2

2x = 12

x = 6

Since, y = x - 2;

y = 6 - 2

y = 4.

On this note, it follows that the solution to the system of equations is such that; x = 6 and y = 4.

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Answer:

a. x/24

b. (x+y)/24

c. y/12

Step-by-step explanation:

semimonthly = twice a month or 24 times a year (because 12 months * twice a month = 24 times)

a. as she was paid 24 times a year for x dollars last year,

24 semimonthly payments of d dollars = x

divide both sides by 24 to get d

x / 24 = d dollars per semimonthly payment

b. she is paid x + y dollars this year, so she is paid (x+y)/24 dollars for her semimonthly salary

c. she earns y additional dollars per year. divide by 12 (because 12 months = 1 year) to get one month's worth of additional dollars = y/12 dollars extra per month

The period of the sinusoidal function is 4 s

The period of a sinusoidal function is the time it takes for the sinusoidal function to complete one cycle of revolution.

To find the period of the given sinusoidal function, we observe the graph. The period is the time at which the graph completes one cycle. Now, since the graph passes through the origin at x = 0 and completes one cycle at x = 4. So, the complete cycle is from x = 0 to x = 4.

Thus the period of the function is 4 s

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The rocket will be at a height more than 100 feet for 10 seconds.

Quadratic equations are second degree equations involving a variable of the form [tex]ax^{2} + bx+c = 0[/tex].

We have the equation relating height and time as,

h(t) = -[tex]\frac{1}{2}[/tex] t² + 15 t

When height is 100 feet, equation becomes,

100 = -[tex]\frac{1}{2}[/tex] t² + 15 t

-[tex]\frac{1}{2}[/tex] t² + 15 t - 100 = 0

Multiplying throughout with -2, we get,

t² - 30t + 200 = 0

(t - 10) (t - 20) = 0

t - 10 = 0 or t - 20 = 0

t = 10 or t = 20

When rocket is at maximum height of 112.5 feet,

-[tex]\frac{1}{2}[/tex] t² + 15 t - 112.5 = 0

Multiplying throughout with -2, we get,

t² - 30t + 225 = 0

(t - 15) (t - 15) = 0

t - 15 = 0

t = 15

Hence the rocket reached at a height of 100 feet at t = 10 seconds and after 5 seconds it reached it's maximum height at t = 15 seconds and then the rocket goes down and again reached at a height of 100 m at t = 20 seconds. So the rocket is at height more than 100 m for 10 seconds.

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Step-by-step explanation:

First you simplify the fractions

17/12 × 1/2 × 3

17×1×3=51 and 12×2=24

51/24

Further simplifying after dividing the two numbers by 3 you get

17/8

Answer:

Step-by-step explanation:

If you are looking for an exact form, it will be 17/8

If you are looking for a decimal form, it will be 2.125.

If you are looking for a mixed number form, it will be 2 1/8

I hope this helps.

Due to the earth's rotation, a person would be traveling faster at the equator than they would at a position halfway from the equator to the North Pole. This is true.

The rotation of the planet Earth around its own axis and variations in the orientation of the rotation axis in space are referred to as Earth's rotation or Earth's spin. Earth rotates progradely in an easterly direction. The Earth rotates counter-clockwise when viewed from the northern polar star Polaris.

We cross the line separating day from night every day because the Earth is perpetually rotating. The length of our shadows is yet another pattern brought on by the Earth's rotation.

The circumference of the Earth is largest at the equator because of how the rotation of the Earth causes it to bulge there. In comparison to a location closer to the poles, the equator requires a person to travel a greater distance in a given amount of time. A person at the equator would therefore move more quickly than someone farther from the poles.

In conclusion, it is true.

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Due to the earth's rotation, a person would be traveling faster at the equator than they would at a position halfway from the equator to the North Pole.

True or false?

Answer:

y < 4

Step-by-step explanation:

the broken horizontal line y = 4 means that y cannot equal 4

The shaded area below the line represents the solution, which is

y < 4

The correct answer is y<4.

Recall that the horizontal line has an equation of the type y=b, where b is the perpendicular distance from the x-axis. As the shaded region is below the line y=4, the inequality representing the region is y<4.

The limits of the functions (a) 1, (b) does not exist (c) 2, (d) does not exist, (e) -4 and (f) 3.

Limit of a function is defined as a value that the function tends to the output for the given input values.

(a) [tex]\lim_{x \to 2} [f(x)+g(x)][/tex] =  [tex]\lim_{x \to 2} f(x)[/tex] +  [tex]\lim_{x \to 2} g(x)[/tex]

[tex]\lim_{x \to 2} f(x)[/tex] is the value of y when x is approaching 2 from left and right.

[tex]\lim_{x \to 2} f(x)[/tex] = -1

Similarly,  [tex]\lim_{x \to 2} g(x)[/tex] = 2

[tex]\lim_{x \to 2} [f(x)+g(x)][/tex] = -1 + 2 = 1

(b)  [tex]\lim_{x \to 0} [f(x)-g(x)][/tex] =  [tex]\lim_{x \to 0} f(x)[/tex] -  [tex]\lim_{x \to 0} g(x)[/tex]

[tex]\lim_{x \to 0} f(x)[/tex] = 2

But  [tex]\lim_{x \to 0} g(x)[/tex] does not exist as the function g(x) has different limits 3 and 1 from left and right respectively as x approaches 0.

So [tex]\lim_{x \to 0} [f(x)-g(x)][/tex] does not exist.

(c)  [tex]\lim_{x \to -1} [f(x)g(x)][/tex] =  [tex]\lim_{x \to -1} f(x)[/tex] × [tex]\lim_{x \to -1} g(x)[/tex]

[tex]\lim_{x \to -1} f(x)[/tex] = 1

[tex]\lim_{x \to -1} g(x)[/tex] = 2

[tex]\lim_{x \to -1} [f(x)g(x)][/tex] = 1 × 2 = 2

(d)  [tex]\lim_{x \to 3} [f(x)/g(x)][/tex] =  [tex]\lim_{x \to 3} f(x)[/tex] /  [tex]\lim_{x \to 3} g(x)[/tex]

[tex]\lim_{x \to 3} f(x)[/tex] = 1

[tex]\lim_{x \to 3} g(x)[/tex] = 0

 [tex]\lim_{x \to 3} [f(x)/g(x)][/tex] = 1 / 0, not defined. So does not exist.

(e)  [tex]\lim_{x \to 2}[x^{2} f(x)][/tex] =  [tex]x^{2} \lim_{x \to 2} f(x)[/tex]

[tex]\lim_{x \to 2} f(x)[/tex] = -1

[tex]\lim_{x \to 2}[x^{2} f(x)][/tex] = (2)² × -1 = -4

(f) f(-1) = 1

[tex]\lim_{x \to -1} g(x)[/tex] = 2

f(-1) + [tex]\lim_{x \to -1} g(x)[/tex] = 1 + 2 = 3

Hence the values of the limits are given.

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Answer:

To solve this system of equations using substitution, we first need to solve one of the equations for one of the variables in terms of the other.

Let's solve the first equation for x:

6x - 5y = 10

x = (10 + 5y)/6

Now let's substitute this expression for x into the second equation:

x - 3y = -20

(10 + 5y)/6 - 3y = -20

10/6 + 5y/6 - 3y = -20

(10/6 - 3y) + (5y/6) = -20

(10 - 3y)/6 + 5y/6 = -20

10/6 - 3y/6 + 5y/6 = -20

(-3y + 5y)/6 = -20

2y/6 = -20

y = -10

Now that we have found the value of y, we can substitute it back into one of the original equations to find the value of x. Let's use the first equation:

6x - 5y = 10

6x - 5(-10) = 10

6x + 50 = 10

6x = -40

x = -40/6

x = -40/6

x = -6.666666666666667

So the solution to the system of equations is (x, y) = (-6.666666666666667, -10).

Each dimension increased by 2.86 ft.

Given that A rectangular box has dimensions 5 ft by 3 ft by 3 ft

The volume of the rectangular box = l × w × h , where l , w , h are its dimensions

∵ l = 5 ft , w = 3 ft , h = 3 ft

∴ Its volume = 5 × 3 × 3 = 45 ft³

Since Each dimension of the box is increasing by the same amount to yield a new box

Let each dimension will increase by x ft

∴ The new dimensions are l = (5 + x) , w = (3 + x) , h = (3 + x)

The volume of the new box is six times the old

The volume of the old box is 45 ft³

∴ The volume of the new box = 6 × 45 = 270 ft³

∵ The volume of new box = (5 + x)(3 + x)(3 + x)

∴ (5 + x)(3 + x)(3 + x) = 270

x³+11x²+39x+45=270

Subtract 270 from both sides.

x³+11x²+39x+45−270=270−270

x³+11x²+39x−225=0

Use cubic formula.

x=2.860717

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The probability that[tex]$QR \leq 100$[/tex] is equal to the ratio of the area of the region in which[tex]$QR \leq 100$[/tex] to the area of the region in which [tex]$0 \leq a \leq 75$ and $0 \leq b \leq 75$[/tex]. Therefore,[tex]$m + n$[/tex] is equal to the area of the region in which [tex]$0 \leq a \leq 75$ and $0 \leq b \leq 75$.[/tex]

The probability that

[tex]$QR \leq 100$[/tex]

is equal to the ratio of the area of the region in which

[tex]$QR \leq 100$[/tex]

to the area of the region in which

[tex]$0 \leq a \leq 75$[/tex]

[tex]$0 \leq b \leq 75$[/tex]

. To find this probability, we first need to find the area of the region in which

[tex]$0 \leq a \leq 75$ and $0 \leq b \leq 75$[/tex]

This region is a rectangle with sides of length[tex]$75$,[/tex] so its area is

[tex]$75^2$[/tex]. To find the area of the region in which

[tex]$QR \leq 100$[/tex],

we need to calculate the area of the triangle in which[tex]$QR$[/tex] is the hypotenuse.

This triangle has base [tex]$75$[/tex]and height [tex]$200$[/tex], so its area is [tex]$3750$[/tex]. Therefore, the desired probability is

[tex]$\frac{3750}{75^2}$, and $m + n[/tex]

[tex]= 75^2$.[/tex]

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If the Q and R are on the same side of the line OP and angle OQP and angle ORP are right triangles then the probability that QR ≤ 100 is 16/25 and the value of m+n is 41 .

The angles OQP and angle ORP are given as right angles that means

∠OQP = ∠ORP = 90° ,

In order to find the required probability we draw a semicircle having the diameter OP and points Q and R on the same side of the semicircle .

given that diameter  OP = 200 ,

So , the radius of the circle will be = 100 ,

Let QR = x ≤ 100 , From the figure ,

we can write ,

[tex]OQ = 200 \times Cos(a)[/tex] and [tex]PQ = 200 \times Sin(a)[/tex]

[tex]OR = 200 \times Cos(b)[/tex]  and  [tex]PR = 200 \times Sin(b)[/tex]

From the figure given below , we can conclude that the quadrilateral OQRP is a cyclic quadrilateral .

So , [tex]200x + (200 Cosa)\times(200 Sinb) = (200 Sina)\times(200 Cosb)[/tex]

we get , [tex]x = |200 Sin(a-b)| \leq 100[/tex] ,

| Sin(a-b)| ≤ 1/2 ;

which implies that |a-b| ≤ 30 ,

that means , -30 ≤ (a-b) ≤ 30 ,  

it is given that a and b are chosen independently and uniformly at random in interval (0,75).

which means , 0<a, b <75 .

The Probability that x ≤ 100 is = [tex]\frac{Favorable Area}{Total Area}[/tex]

=  [tex]\frac{75\times75-45\times45}{75 \times75}[/tex] = 1 - [tex]\frac{9}{25}[/tex] ,

On simplifying ,

we get

= 16/25 ,

and it is given that the probability is = m/n ,

So on comparing , we get that , m = 16 and n = 25 ,

and the value of m+n = 16+25 = 41 .

Therefore , the probability is 16/25 and the value of m+n is 41 .

The given question is incomplete , the complete question is

Two real numbers a and b are chosen independently and uniformly at random in the interval (0,75). Let O and P be two points on the plane with OP = 200. Let Q and R be on the same side of line OP such that the degree measures of angle POQ and angle POR are a and b respectively, and angle OQP and angle ORP are both right angles. The probability that QR ≤ 100 is equal to m/n , where m and n are relatively prime positive integers. Find m + n.

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Yes, the values in the table form a proportional relationship, with a constant of 8/3.

A proportional relationship is a linear function with an intercept of zero modeled as follows:

y = kx.

In which k is the constant of proportionality.

The constant then can be written as follows:

k = y/x.

This means that a data-set will only represent a proportional relationship if the division of y by x is constant for all coordinate pairs in the data-set.

The constant for each pair in the data-set given in the table is calculated as follows:

As the constant is equal for all coordinate pairs of the data-set, the table in fact represents a proportional relationship.

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Answer:

Step-by-step explanation:

Answer:

The y intercept of the line is 2

Step-by-step explanation:

y intercept means where the line crosses the y axis which is at the value 2