Please select the word from the list that best fits the definition
equals the output work divided by the input work
input force
efficiency
mechanical advantage
output force
compound machine

Answers

Answer 1

Answer:input work

Explanation:

Answer 2

Answer:

thankssssssssss\

Explanation:


Related Questions

It is safer for a car driver to be wearing a seat belt, compared with not wearing a seat belt, if the car is involved in a collision.

Explain why.​

Answers

Explanation: It is because when a car is moving both the car and the driver is in inertia of motion. When a car is involved in collision it comes to a sudden stop and the car comes into inertia of rest whereas the person still in inertia of motion moves forward and might result in major injuries. But this can be prevented by wearing a seatbelt

Hope it helps :)

this is an opinion question but

explain why you think it is important to know the three different types of rocks.

Answers

AJAJAJAJ I just going to say what ever I think it is important because imagine you see a rock and think is a normal rock but it ends up being really rare and you can make a lot of money out of it

If a student has a mass of 75 kg, what is her weight on Earth?
7.65 N
075N
76.5 N
735 N

Answers

Answer:

735

Explanation:

w=mg

w=75*9.8=735N

The movement of an object or a point mass at a constant speed around a circle that has a fixed radius is called uniform __________.

Answers

Answer:

circular motion

Explanation:

A circular motion is defined as the movement of the object in a circular direction along a fixed point or the circumference of the circle. The circular motion of the object can be uniform circular motion, non uniform or variable circular motion.

For an object moving in a circular motion at a constant speed, the net force should always acts towards the center of the circle.

A 13561 N car traveling at 51.1 km/h rounds

a curve of radius 2.95 × 102 m.

The acceleration of gravity is 9.81 m/s

a) Find the centripetal acceleration of the

car. Answer in units of m/s


Find the force that maintains circular motion.

Answer in units of N.


c) Find the minimum coefficient of static friction between the tires and the road that will
allow the car to round the curve safely.

Answers

Answer:

a) The centripetal acceleration of the car is 0.68 m/s²

b) The force that maintains circular motion is 940.03 N.

c) The minimum coefficient of static friction between the tires and the road is 0.069.

Explanation:

a) The centripetal acceleration of the car can be found using the following equation:

[tex] a_{c} = \frac{v^{2}}{r} [/tex]

Where:

v: is the velocity of the car = 51.1 km/h

r: is the radius = 2.95x10² m

[tex] a_{c} = \frac{(51.1 \frac{km}{h}*\frac{1000 m}{1 km}*\frac{1 h}{3600 s})^{2}}{2.95 \cdot 10^{2} m} = 0.68 m/s^{2} [/tex]

Hence, the centripetal acceleration of the car is 0.68 m/s².

b) The force that maintains circular motion is the centripetal force:

[tex] F_{c} = ma_{c} [/tex]

Where:

m: is the mass of the car

The mass is given by:

[tex] P = m*g [/tex]

Where P is the weight of the car = 13561 N

[tex] m = \frac{P}{g} = \frac{13561 N}{9.81 m/s^{2}} = 1382.4 kg [/tex]

Now, the centripetal force is:

[tex] F_{c} = ma_{c} = 1382.4 kg*0.68 m/s^{2} = 940.03 N [/tex]

Then, the force that maintains circular motion is 940.03 N.

c) Since the centripetal force is equal to the coefficient of static friction, this can be calculated as follows:

[tex] F_{c} = F_{\mu} [/tex]

[tex] F_{c} = \mu N = \mu P [/tex]

[tex] \mu = \frac{F_{c}}{P} = \frac{940.03 N}{13561 N} = 0.069 [/tex]

Therefore, the minimum coefficient of static friction between the tires and the road is 0.069.

I hope it helps you!                

BRAINLIEST!!!!!!!!
Can someone plz help?

Answers

I think it’s D. But I’m not sure

Answer:

light, sound and heat.

Explanation:

ur correct! just took this as well!

Cuál es la diferencia entre fricción beneficiosa y perjudicial? Pon 5 ejemplos de cada uno.

Answers

Answer:

Difference is given below.

Explanation:

The main difference between beneficial and harmful friction is that beneficial friction is necessary for performing different activities while on the other hand, harmful effect of friction is destroy different parts of products and machines. examples of beneficial friction are walking, holding things, rubbing hands to produce heat, running etc whereas examples of harmful friction are destruction of sole, slipping, tearing of machine's part, Wet roads and Mudslides etc.

What is the heat that is released into the atmosphere when energy is changed into mechanical energy called?

Answers

Answer:

thermal pollution

Explanation:

took exam!

When the heat is discharged into the atmosphere then energy is changed into mechanical energy is known as Thermal pollution.

What is Thermal pollution?

When Thermal pollution is the degradation of water differentia by any procedure that changes ambient water temperature.

A typical motivation for thermal pollution is the usefulness of water as a coolant by power plants and industrial manufacturers.

When the water utilized as a coolant is returned to the biological environment at a more elevated temperature, the sudden transformation in temperature lowers the oxygen supply and affects ecosystem composition.

Find more information about Thermal pollution here:

https://brainly.com/question/8624420

2. At the start of an experiment, a lab cart is moving with a velocity of 0.5 m/s to the right. The lab cart's
trip (motion) lasted 5 seconds. How far did the cart travel?

Answers

Answer:

2.5m

Explanation:

Speed/velocity = 0.5m/s

Time = 5s

speed = Distance/Time

Distance = Speed x Time

Distance = 0.5 x 5

Distance = 2.5m

Piper and Clair are going on sawyer the

For a given force, if the mass is less, the velocity change will be greater.
O True
O False

Answers

REVDERAEROSPUESTA:D  

VDAEDERO

R

Answer: I think it's true

Explanation: Because if the object or the person weighs less it'll go faster! :) I hope I helped!

Help meeee pleaseeee!!!!!!

Answers

Answer:

fuxlxltlusflh I need points sorry

Answer:

Explanation:

Acceleration is gravity which is always downward (negative).

A virtual image formed by convex lens is always
1. diminished
2. erect and magnified
3. inverted
4. formed in other side of the object

Answers

Answer:

2. erect and magnified

Answer is erect and magnified

Students set up a controlled experiment (please help I am so tired and unable to function lol)

Answers

The temp...............

If a 0.8kg ball is thrown with a velocity of 5 m/s,what is its KE?(KE=1/2 x m x v2) ​

Answers

KE = 10 joules

ke = 1/2 x 0.8 x 5 x v2

When a charge is released in an electric field, it moves from a point of potential

Answers

Explanation:

Protons/positive charges will move from higher potentials to lower potentials

While Electrons/Negative charges move from lower potentials to higher potential

Normally, electrons are negatively charged hence they tend to be repelled by the electrons and attracted by protons.

According to Newton's third law of motion, if you push against a wall, the wall will __________.

Answers

Answer:

push up agaisnt you with equal force.

Answer:

c

Explanation:

A plant growing toward a light source is an example of an organism... *

Answers

A plant growing towards a light source is an example of an organism of Phototropism

Phototropism .. hope this helps a lot :)

prove velocity square = U square+2as​

Answers

bad handwriting tho........... hope u understand

What is the speed of an object at rest?
0 m/s
O 1 m/s
O 10 m/s

Answers

Answer:

1 m/s so number 2 is the right one

Explanation:

so when it is at rest it still has some of the left over energy so it would be at 1 m/s

calculate the speed of a person who travels 600km in 8 hrs express in m/s

please urgent will surely mark u the brainliast!!!!!!​

Answers

Answer:

20.83 m/s

Explanation:

The speed of an object can be found by using the formula

[tex]v = \frac{d}{t} \\ [/tex]

d is the distance

t is the time taken

From the question

600 km = 600,000 m

8hrs = 28,800 s

We have

[tex]v = \frac{600000}{28800} = \frac{6000}{288} = \frac{125}{6} \\ = 20.83333...[/tex]

We have the final answer as

20.83 m/s

Hope this helps you

Answer:

20.833333... m/s  or   20 & 5/6 m/s

Explanation:

You want to convert km to meters, and hours to seconds. You do "dimensional analysis," which is just multiplying fractions so that units cancel.[tex]\frac{600 km}{8hr} * \frac{1hr}{60mins} * \frac{1min}{60sec} = \frac{600km}{28,800sec} = \frac{6km}{288sec}[/tex]

so now we have km/sec, but we need m/s, so...

[tex]\frac{6km}{288sec} * \frac{1000m}{1km} = \frac{6000m}{288sec} = \frac{125m}{6sec} = 20\frac{5}{6} m/s = 20.83333... m/s[/tex]

Levi decides to examine the effect of fertilizer on the growth of tomato plants. He chooses four plants for his experiment and applies varying amounts of fertilizer to the three of them. He does not apply fertilizer to one plant.


Over a 15-day period, the plants receive fertilizer on Days 1, 4, 7, 10, and 13. Levi measures the height of all of his plants with a meter stick on Days 3, 6, 9, 12, and 15. He also makes sure to hold all experimental factors constant except for the fertilizer.



Which statement describes what Levi did to prepare the control group in his experiment?



Levi applied different amounts of fertilizer to three of his plants.

Levi did not apply any fertilizer to one of his plants..

Levi held all experimental factors constant except for fertilizer., ,

Levi measured his plants on five separate days.

Answers

Answer:

Levi did not apply any fertilizer to one of his plants..

Explanation:

In an experiment, there are two major groups namely: control group and experimental group. Control group is the group in an experiment that does not receive the experimental treatment i.e. the group which the independent variable is not applied to.

In this case, Levi is trying to examine the effect of fertilizer on the growth of tomato plants where he used varying amounts of fertilizer on three of the four plants he used for the experiment. The fourth plant did not receive any amount of fertilizer, which is the independent variable (variable being manipulated or changed). This means that Levi prepared the control group in his experiment by NOT APPLYING ANY FERTILIZER TO ONE OF HIS PLANTS.

Two pebbles are dropped into a pool of water as shown. If a new wave with a
greater amplitude results, which kind of wave interaction has occurred?

Answers

Answer:

Constructive interference

Explanation:

Answer:

C. Constructive interference

Explanation:

Show that on a hypothetical planet having half the diameter of the Earth but twice its density, the acceleration of free fall is the same as on Earth.

Answers

Answer:

Steps include:

Find the ratio between the mass of this hypothetical planet and the mass of planet earth.Calculate the ratio between the acceleration of free fall (gravitational field strength) near the surface of that hypothetical planet and near the surface of the earth.

Assumption: both planet earth and this hypothetical planet are spheres of uniform density.

Explanation:

Mass of that hypothetical planet

Let [tex]M_0[/tex], [tex]r_0[/tex], and [tex]\rho_0[/tex] denote the mass, radius, and density of planet earth.

The radius and density of this hypothetical planet would be [tex](1/2)\, r_0[/tex] and [tex]2\, \rho_0[/tex], respectively.

The volume of a sphere is [tex]\displaystyle V = \frac{4}{3}\, \pi\, r^3[/tex].

Therefore:

The volume of planet earth would be [tex]\displaystyle V_0 = \frac{4}{3}\, \pi\, {r_0}^{3}[/tex].The volume of this hypothetical planet would be: [tex]\displaystyle V = \frac{4}{3}\, \pi\, \left(\frac{r_0}{2}\right)^3 = \frac{1}{6}\, \pi\, {r_0}^3[/tex].

The mass of an object is the product of its volume and density. Hence, the mass of the earth could also be represented as:

[tex]\displaystyle M_0 = \rho_0\, V_0 = \frac{4}{3}\, \pi\, {r_0}^{3}\, \rho_0[/tex].

In comparison, the mass of this hypothetical planet would be:

[tex]\begin{aligned}M &= \rho\, V\\ &= (2\, \rho_0) \cdot \left(\frac{1}{6}\, \pi\, {r_0}^3\right) \\ &= \frac{1}{3}\, \pi\, {r_0}^{3}\, \rho_0 \end{aligned}[/tex].

Compare these two expressions. Notice that [tex]\displaystyle M = \frac{1}{4}\, M_0[/tex]. In other words, the mass of the hypothetical planet is one-fourth the mass of planet earth.

Gravitational field strength near the surface of that hypothetical planet

The acceleration of free fall near the surface of a planet is equal to the gravitational field strength at that very position.

Consider a sphere of uniform density. Let the mass and radius of that sphere be [tex]M[/tex] and [tex]r[/tex], respectively. Let [tex]G[/tex] denote the constant of universal gravitation. Right next to the surface of that sphere, the strength of the gravitational field of that sphere would be:

[tex]\displaystyle g = \frac{G \cdot M}{r^2}[/tex].

(That's the same as if all the mass of that sphere were concentrated at a point at the center of that sphere.)

Assume that both planet earth and this hypothetical planet are spheres of uniform density.

Using this equation, the gravitational field strength near the surface the earth would be:

[tex]\displaystyle g_0 &= \frac{G \cdot M_0}{{r_0}^2}[/tex].

.

On the other hand, the gravitational field strength near the surface of that hypothetical planet would be:

[tex]\begin{aligned}g &= \frac{G \cdot (M_0/4)}{{(r_0/2)}^2} = \frac{G \cdot M_0}{{r_0}^2}\end{aligned}[/tex].

Notice that these two expressions are equal. Therefore, the gravitational field strength (and hence the acceleration of free fall) would be the same near the surface of the earth and near the surface of that hypothetical planet.

As a side note, both [tex]g[/tex] and [tex]g_0[/tex] could be expressed in terms of [tex]\rho_0[/tex] and [tex]r_0[/tex] alongside the constants [tex]\pi[/tex] and [tex]G[/tex]:

[tex]\begin{aligned}g &= \frac{G \cdot M}{r^2}\\ &= \frac{G \cdot (1/3)\, \pi\, {r_0}^3 \, \rho_0}{(r_0/2)^2} = \frac{4}{3}\,\pi\, G\, r_0\, \rho_0\end{aligned}[/tex].

[tex]\begin{aligned}g_0 &= \frac{G \cdot M_0}{{r_0}^2}\\ &= \frac{G \cdot (4/3)\, \pi\, {r_0}^3 \, \rho_0}{{r_0}^2} = \frac{4}{3}\,\pi\, G\, r_0\, \rho_0\end{aligned}[/tex].

Questions -

4.3 Calculate the unknown forces X and Y for the

balanced beam shown.

1.0 m+

2.5 m

te)

X

400N

Answers

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value of  [tex]X = 1000 \ N[/tex] and  [tex]Y = 1400 \ N[/tex]  

Explanation:

Considering the diagram,

   Taking moment about the pivot , we have

           [tex]X * 1 = 400 * 2.5[/tex]

=>         [tex]X = 1000 \ N[/tex]

Generally given that the bar is at equilibrium then the upward forces is equal to the down ward force

So

        [tex]Y = X + 400[/tex]

=>     [tex]Y = 1000 + 400[/tex]

=>     [tex]Y = 1400 \ N[/tex]    

   

What is the relationship between voltage and power in a circuit?
A. In a circuit, voltage and power remain equal.
О
B. Increasing the voltage in a ciącuit decreases its power.
C. Increasing the voltage in a circuit increases its power.
D. In a circuit, voltage and power are unrelated.

Answers

C. Increasing the voltage in a circuit increases its power.

is the relationship between voltage and power in a circuit

How is voltage impacted by power?

The watt is the unit of power measurement. The power will quadruple if the voltage increases. In a circuit, if the voltage (or electrical pressure) is raised, the current (flow of electrons) will rise in direct proportion; for example, doubling the voltage will result in doubling the current flow.

Several different voltages will produce the same amount of power as long as you can pull adequate current (amps) from the battery. Hence, hypothetically, a higher voltage does not automatically translate into more power. Typical voltage values for peak (max) volts are 40, 80, and 120 volts.

learn more about voltage

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#SPJ1

1 point
1. A bowler uses 10.5 N of force to roll a bowling ball, and the ball
accelerated at 2.5 m/s2 to reach a speed of 50.0 m/s. What is the mass of
the bowling ball to the nearest tenth of a kilogram? Answer in kg.*

Answers

the answer would be 0.21 i believe if you use something we called F/Ma in grade school

1.) How much potential energy does an object with a mass of 3 kg have on top of a stand 12 meters
high have on earth with a gravitational acceleration of 9.8 m/s, assuming no air friction?
a.) 3.673 Joules
b.) 352.8 Joules
c.) 39.2 Joules
d.) 2.45 Joules

Answers

Answer:

352.8 Joules

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

PE = 3 × 9.8 × 12

We have the final answer as

352.8 J

Hope this helps you

What is the current through the battery if the switch S is opened

Answers

Answer: So, our current when our switch is open is going to be equal to the voltage across the resistors, and that's going to be our 12 volts, 12 volts, divided by the equivalent resistance of these resistors. When the switch is open, essentially, we just have R1 and R2 in series, and so this is just gonna be R1+R2.

Hope this helps......... Stay safe and have a Merry Christmas!!!!!! :D

In a chemical reaction, two reactants mix. The resulting substance is called a(n)

Answers

Answer:

⚠WARNING DO NOT JOIN THE ZOOM OF 825 338 1513⚠ OR DO NOT JOIN ANY ZOOMS FROM ANYONE EXCEPT REAL LIFE FRIENDS OR FRIENDS FAMILY OR TEACHERS! HIS ZOOM NAME IS Mysterious Men HE ASKS GIRLS TO DO INAPPROPRIATE THINGS PLS COPY AND PASTE THIS TO OTHER COMMENT SECTIONS! PLS PASS THIS AROUND

Answer:

product

Explanation:

Give me a good explanation for brainliest

Answers

Answer:to past school duhh

Explanation:

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