plssss help!!!! Right triangle RST is drawn below. A square is drawn on to each leg of the triangle, and a square is drawn onto the hypotenuse of the triangle. The area of square A is 25 cm² . The area of square B is 144 cm². Determine the length in centimeters of x, the hypotenuse of the right triangle.O 13 cmO 17 cm O 169 cmO 119 cm
Answers
the hypotenuse of the right angled triiangle = x = 13cm (option A)
Explanation:
Area of B = 144cm²
Area of a square = length²
length = √Area of a square
shape of B is a square, hence the length of B:
the length of one of the side of B = √144 = 12cm
Area of A = 25cm²
shape of A is a square
the length of one of the side of A = √25 = 5cm
Triangle is a right angled-triangle
From the diagram, the length of the side of B = opposite = 12cm
The length of the side of A = adjacent = 5cm
The length of the third square marked x = hypotenuse
Using pythagoras' theorem:
Hypotenuse² = opposite² + adjacent²
x² = 12² + 5²
x² = 144 + 25
x² = 169
x = √169
x = 13cm
Hence, the hypotenuse of the right angled triiangle = x = 13cm (option A)
Related Questions
Write an equation for the graph below in point-slope form and then solve rewrite in slope-intercept form.
Answers
We are given the graph of a line and we are asked to determine its equation in point-slope form.
The general form in slope point form of a line is:
[tex]y-y_0=m(x-x_0)[/tex]Where:
[tex]\begin{gathered} m=\text{ slope} \\ (x_0,y_0)\text{ is apoint in the line} \end{gathered}[/tex]to determine the slope we will use the following formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Where:
[tex](x_1,y_1);(x_2,y_2)=\text{ points on the line}[/tex]We will choose two points on the line from the graph:
[tex]\begin{gathered} (x_1,y_1)=(0,1) \\ (x_2,y_2)=(2,2) \end{gathered}[/tex]Now, we plug in the values in the formula for the slope:
[tex]m=\frac{2-1}{2-0}=\frac{1}{2}[/tex]Now, we substitute the value of the slope in the equation of the line:
[tex]y-y_0=\frac{1}{2}(x-x_0)[/tex]Now, we plug in the first point we choose for the line:
[tex]\begin{gathered} y-1=\frac{1}{2}(x-0) \\ \\ y-1=\frac{1}{2}x \end{gathered}[/tex]And thus we have determined the equation of the line in point-slope form.
The slope-intercept form is the following:
[tex]y=mx+b[/tex]To convert this equation to slope-intercept form, we will take the previous equations and we will add 1 to both sides:
[tex]y=\frac{1}{2}x+1[/tex]And thus we have determined the slope-intercept form of the equations of the line.
Which calculation and answer show how to convert 13 to a decimal?
Answers
when evalueatong the expression 13/15,
13 serves as the dividend and
15 is the divisor
Divisor is always placed outside the division sign and the dividend inside.
According to the option, you can see that 15 which is the divisor is placed outside and 13 is placed inside.
check the diagram below:
Option A is the correct answer in this case
Aaquib can buy 25 liters of regular gasoline for $58.98 or 25 liters of permimum gasoline for 69.73. How much greater is the cost for 1 liter of premimum gasolinz? Round your quotient to nearest hundredth. show your work :)
Answers
The cost for 1 liter of premium gasoline is $0.43 greater than the regular gasoline.
What is Cost?This is referred to as the total amount of money and resources which are used by companies in other to produce a good or service.
In this scenario, we were given 25 liters of regular gasoline for $58.98 or 25 liters of premium gasoline for $69.73.
Cost per litre of premium gasoline is = $69.73 / 25 = $2.79.
Cost per litre of regular gasoline is = $58.98/ 25 = $2.36.
The difference is however $2.79 - $2.36 = $0.43.
Therefore the cost for 1 liter of premimum gasoline is $0.43 greater than the regular gasoline.
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Hugo averages 42 words per minute on a typing test with a standard deviation of 5.5 words per minute. Suppose Hugo's words per minute on a typing test are normally distributed. Let X= the number of words per minute on a typing test. Then, X∼N(42,5.5). Suppose Hugo types 60 words per minute in a typing test on Wednesday. The z-score when x=60 is ________. This z-score tells you that x=60 is ________ standard deviations to the ________ (right/left) of the mean, ________. Correctly fill in the blanks in the statement above.
Answers
The z score when x = 60 is 3.27.
This z score tells you that x = 60 is 3.27 standard deviations to the right of the mean.
Given,
Consider as a normal distribution:
The mean should be equals to 42 (μ)
The standard deviation (σ) = 5.5
We have to find the z score when x = 60.
That is,
z = (x - μ) / σ = (60 - 42) / 5.5 = 18/5.5 = 3.27
Therefore,
The z score when x = 60 is 3.27.
This z score tells you that x = 60 is 3.27 standard deviations to the right of the mean.
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the answer is red show me how to get to the answer
Answers
The given expression is:
[tex]\frac{5\sqrt{4}}{\sqrt{3}}[/tex]The first step is to find the square root of 4 in the numerator, that is:
[tex]\sqrt{4}\text{ = 2}[/tex]Substitute this into the given expression:
[tex]\frac{5(2)}{\sqrt{3}}[/tex][tex]\frac{10}{\sqrt{3}}[/tex]The next step is to rationalize, that is, multiply the numerator and the denominator by √3
[tex]\frac{10}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}}[/tex][tex]\frac{10\sqrt{3}}{\sqrt{9}}[/tex]Since √9 = 3[tex]\frac{10\sqrt{3}}{3}[/tex]A line's slope is -5. The line passes through the point (5, 30). Find an equation for this line in both point-slope and slope-intercept form A) An equation for this line in point-slope form is:B) An equation for this line in slope-intercept form is.
Answers
Answer:
y - 30 = 5(x - 5) (point slope form)
slope intercept form is y = 5x+5
Explanation:
Given the following
Slope m = -5
Point = (5, 30)
x0 = 5 and y= = 30
The equation of the line in point slope form is expressed as y-y0 = m(x-x0)
Substitute
y - 30 = -5(x - 5) (point slope form)
Express in slope intercept form (y = mx+c)
y - 30 = -5x + 25
y = -5x + 25 + 30
y = -5x + 55
Hence the equation of the line in slope intercept form is y = -5x+55
Find the surface area of the cylinderA). 188.4 ft^2B). 226.08 ft^2C). 244.92 ft^2D). 282.6 ft^2
Answers
To solve this problem, we will use the following formula for the surface area of a cylinder:
[tex]A=2\pi rh+2\pi r^2,[/tex]where r is the radius of the base, and h is the height of the cylinder.
Substituting h= 10 ft, and r = 3 ft in the above formula, we get:
[tex]A=2\pi(3ft)(10ft)+2\pi(3ft)^2.[/tex]Simplifying, we get:
[tex]A=244.92ft^2.[/tex]Answer: Option C.
Gloria's teacher asks her to draw a triangle with a 90° angle and a 42° angle.How many unique triangles can Gloria draw that meet her teacher's requirements?AOne unique triangle can be drawn because the third angle must measure 48º.BNo unique triangle can be drawn because the teacher only gave the measures of two angles.СInfinitely many unique triangles can be drawn because the side lengths of the triangles can be different sizes.DThere is not enough information to determine how many unique triangles can be drawn.
Answers
SOLUTION
Sum of angles in a triangle must be equal to 180°
So, since one of the angle measures 90° and the other is 42°, then
90 + 42 + y = 180°, where y is the third angle
So, 132 + y = 180
y = 180 - 132 = 48°.
Therefore, one unique triangle can be drawn because the third angle must measure 48º.
Option A is the correct answer.
Write the first 4 terms of the sequence defined by the given rule. f(1)=7 f(n)=-4xf(n-1)-50
Answers
The first 4 terms of the sequence defined by the rule f(n) = -4 x f(n - 1) - 50 are 7,
Sequence:
A sequence is an enumerated collection of objects in which repetitions are allowed and order matters.
Given,
The rule of the sequence is f(n) = -4 x f(n - 1) - 50
Value of the first term = f(1) = 7
Now we need to find the other 4 others in the sequence.
To find the value of the sequence we have to apply the value of n.
Here we have to take the value of n as 1, 2, 3, and 4.
We already know that the value of f(1) is 7.
So, now we need to find the value of f(2), that is calculated by apply the value on the given rule,
f(2) = -4 x f(2 - 1) - 50
f(2) = -4 x f(1) - 50
f(2) = -4 x 7 - 50
f(2) = -28 - 50
f(2) = -78
Similarly, the value of n as 3, then the value of f(3) is,
f(3) = -4 x f(3 - 1) - 50
f(3) = -4 x f(2) - 50
f(3) = -4 x - 78 - 50
f(3) = 312 - 50
f(3) = 262
Finally, when we take the value of n as 4 then the value of f(4) is,
f(4) = -4 x f(4 - 1) - 50
f(4) = -4 x f(3) - 50
f(4) = -4 x 262 - 50
f(4) = -1048 - 50
f(4) = -1099
Therefore, the first 4 sequence are 7, - 78, 262 and -1099.
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Karine invests $6,100 in an account with an annual interest rate of 4.5% compounded daily for 2 years.What is the return on investment for Karine's account?
Answers
The return on investment for Katerine's account = 9.4%
Explanation:Amount invested is the principal
Principal, P = $6,100
Annual Interest Rate, r = 4.5% = 0.045
The interest is compounded daily
Number of times the interest is compounded per year, n = 365
Number of years, t = 2 years
The amount after 2 years is calculated as:
[tex]\begin{gathered} A(t)=P(1+\frac{r}{n})^{nt} \\ A=6100(1+\frac{0.045}{365})^{365(2)} \\ A=6100(1.094) \\ A=6673.4 \end{gathered}[/tex]The amount after 2 years = $6673.4
The interest = Amount - Principal
The interest = $6673.4 - $6100
The interest = $573.4
The return on investment is calculated as:
[tex]\begin{gathered} \text{ROI = }\frac{Interest}{Pr\text{incipal}}\times100\text{ \%} \\ \text{ROI}=\frac{573.4}{6100}\times100\text{ \%} \\ \text{ROI = }9.4\text{ \%} \end{gathered}[/tex]The return on investment for Katerine's account = 9.4%
please help me understand how to find the average rate of change of the function over the given interval and please show me work.
Answers
To answer this, you'll need to recall a formula for finding the rate of change of one variable with respect to another. Given f(x)=x^2 + x +1, the rate of change of the variable with respect to x is given by:
[tex]\begin{gathered} \frac{\differentialD yy}{\square}y}{dx}=n(ax^{n-1}),\text{ where n is the power of variable term, and a is the coefficient.}y}{\square}yy}{dx}=\text{nax}^{n-1} \\ So\text{ when f(x)=x\textasciicircum 2+x+1 is differentiated, we will arrive at } \\ \\ \frac{dy}{dx}=2x+1\text{ The average rate of change of the function within the range (-3,-2) means, we have to use x as -3 and also x as -2 into the derivative function } \\ x=-3 \\ \frac{\differentialD yy}{\square}y}{dx}=2(-3)+1=-6+1=-5y}{\square}y}{dx}=2(-3)+1=-6+1=-5 \\ \text{Also, } \\ x=-2 \\ \frac{\differentialD yy}{\square}y}{dx}=2x+1\text{ becomes}y}{\square}yy}{dx} \\ \\ \end{gathered}[/tex]What is the value of the expression below when w = 3?3w² - 6w - 4
Answers
ANSWER:
5
STEP-BY-STEP EXPLANATION:
We have the following expression:
[tex]3w^2-6w-4\:[/tex]We substitute the value of w, when it is equal to 3, just like this:
[tex]\begin{gathered} 3\left(3\right)^2-6\left(3\right)-4\: \\ \\ 3\cdot \:9-6\left(3\right)-4 \\ \\ 27-18-4 \\ \\ 5 \end{gathered}[/tex]The value of the expression is equal to 5
Given that 1 inch = 2.54 centimeters how many centimeters are in 6 feet?
Answers
Answer:
182.88 centimeters are in 6 feet!
Step-by-step explanation:
I hope this helped! c:
Answer:
182.88 centimetersStep-by-step explanation:
If
1 in. = 2.54 cm.
and
12 in. = 1 ft.
lets convert cm into feet
1 * 12 = 12 (how many inches are in a foot )
2.54 * 12 = 30.48 (how many centimeters are in a foot)
so now that we know how many centimeters are in a foot, we can find out how many centimeters are in 6 feet
30.48 * 6 = 182.88
182.88 centimeters are in 6 feetFine all the missing side lengths and angle measured of each triangle.
Answers
Answer:
[tex]\begin{gathered} AT=8\sqrt[]{3} \\ AC=8 \\ mStep-by-step explanation:To find the missing lengths of the triangle, use trigonometric ratios for right triangles, which are represented by the following equations:
[tex]\begin{gathered} \sin (\text{angle)=}\frac{\text{ opposite}}{\text{ hypotenuse}}_{} \\ \cos (\text{angle)}=\frac{\text{adjacent}}{\text{hypotenuse}} \\ \tan (\text{angle)}=\frac{\text{ opposite}}{\text{ adjacent}} \end{gathered}[/tex]Then, find the opposite and adjacent side given the 60 degrees angle:
[tex]\begin{gathered} \sin (60)=\frac{AT}{16} \\ AT=16\cdot\sin (60) \\ AT=8\sqrt[]{3} \\ \\ \cos (60)=\frac{AC}{16} \\ AC=16\cdot\cos (60) \\ AC=8 \end{gathered}[/tex]Now, since the intern angles of a triangle must add up to 180 degrees, given two of the angles find the missing angle:
[tex]\begin{gathered} mAn observer for a radar station is located at the origin of a coordinate system. For the point given, find the bearing of an airplane located at that point. Express the bearing using both methods.(-8,0)
Answers
Given,
The coordinates of the point is (-8, 0).
There are two methods of bearing is:
Compass bearing
True bearing.
The figure of the point is,
The bearing of the point with respect to anticlockwise from north is,
[tex]\begin{gathered} \tan \theta=\frac{y}{x} \\ \tan \theta=\frac{0}{-8} \\ \theta=\tan ^{-1}0 \\ \theta=0^{\circ} \\ \text{Bearing from north=(90}^{\circ}-0^{\circ})=90^{\circ} \end{gathered}[/tex]The bearing of point from west is 0 degree and from anticlockwise north is 90 degree.
The true bearing is,
[tex]\begin{gathered} \theta=0^{\circ} \\ B=(360^{\circ}-90^{\circ}) \\ B=270^{\circ} \end{gathered}[/tex]For the bird, determine the following: The maximum height The axis of symmetry The total horizontal distance travelled A quadratic equation written in vertex form
Answers
Explanation:
The table of values is given below as
Using a graphing tool, we will have the parabola represented below as
Consider an investment whose return is normally distributed with a mean of 10% and a standard deviation of 5%. (2.4)
Justify which statistics methodology needs to be used in the above context and
a) Determine the probability of losing money.
b) Find the probability of losing money when the standard deviation is equal to 10%.
Answers
a) The probability of losing money when standard deviation is 5% is 2.27%
b) The probability of losing money when standard deviation is 10% is 15.87%
Given,
There is an investment whose return is normally distributed.
The mean of the distribution = 10%
The standard deviation of the distribution = 5%
a) We have to determine the probability of losing money:
Lets take,
x = -0.005%
Now,
P(z ≤ (-10.005 / 5) ) = P(z ≤ - 2.001) = 0.02275
Now,
0.02275 × 100 = 2.27
That is,
The probability of losing money is 2.27%
b) We have to find the probability of losing money when the standard deviation is 10%
Let x be 0.01%
Now,
P(z ≤ (-10.01/10)) = P(z ≤ -1.001) = 0.15866
Now,
0.15866 × 100 = 15.87
That is,
The probability of losing money is 15.87%
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6. Refer to the graph in question 5A) graph -f(x)B) graph f(x) -2
Answers
Given the graph of f(x):
Where the points A, B, and C have the coordinates:
[tex]\begin{gathered} A=(0,-2) \\ B=(3,2) \\ C=(5,2) \end{gathered}[/tex]Now, the transformation -f(x) is just a reflection about the x-axis. This is equivalent to a change of sign on the y-coordinate. The new points A', B', and C' are:
[tex]\begin{gathered} A^{\prime}=(0,2) \\ B^{\prime}=(3,-2) \\ C^{\prime}=(5,-2) \end{gathered}[/tex]And the graph looks like this:
Now, for the f(x) - 2 transformation, we see that this is just a shift of 2 units down. Then:
Where:
[tex]\begin{gathered} A^{\prime}^{\prime}=(0,-4) \\ B^{\prime}^{\prime}=(3,0) \\ C^{\prime}^{\prime}=(5,0) \end{gathered}[/tex]1. Write the equation of the line with a slope of -3 that passes through the point (1,9).y=3x + 12y=3x + 6y=-32 +6y=-3x+12
Answers
Answer:
y = -3x + 12
Explanation:
The equation of a line with slope m that passes through the point (x1, y1) can be calculated as:
[tex]y-y_1=m(x-x_1)[/tex]So, replacing m by -3, and (x1, y1) by (1, 9), we get:
[tex]y-9=-3(x-1)[/tex]Finally, solving for y, we get:
[tex]\begin{gathered} y-9=-3x-3(-1) \\ y-9=-3x+3 \\ y-9+9=-3x+3+9 \\ y=-3x+12 \end{gathered}[/tex]Therefore, the answer is:
y = -3x + 12
Who am I? I am a quadrilateral with opposite sidescongruent and parallel, all of my angles are 90° andmy diagonals are congruent.d
Answers
Let's list all information we have:
- quadrilateral (4 sides)
- opposite sides congruent and parallel.
- all angles are 90°
- diagonal are congruent.
So, if we have a quadrilateral, we have something like this:
However, it is given that all anlges are 90°, which limits our possible drawing. So, something like this:
Let's see, this is a rectangle, it has opposite side congruent (equal length), the opposite sides are parallel, all the angles are 90° and the Diagonals have equal lengths, because they form congruent triangles.
It could also be a square:
Beucase it has all of the characteristics given.
Multiply.4y=2y3v2.4v7
Answers
Let's recall one of the properties of exponents:
[tex]x^4\ast x^5=x^{4\text{ + 5}}=x^9[/tex]Therefore, in our exercise we have:
[tex]4y\text{ }\ast2y^3=8y^{4\text{ }}andv^2\ast4v^7=4v^9[/tex][tex]8y^4\ast4v^9=32y^4v^9[/tex]Model x2 + 3x + 5 in the Gizmo by dragging or clicking blue x?-tiles, green x-tiles, and yellow 1-tilesinto the top bin. How many of each type of tile did you use?
Answers
A.
x^2 and 2x^2 means:
3 x^2 tiles
3x - 4x = -x
ONE -x tiles
5 - 1 is "4"
B.
2x^2 - 4x - 1
This is just an expression
so there are 2 x^2 tiles, 4 -x tiles and one 1-tiles
The perimeter of a quarter circle is 3.57 kilometers. What is the quarter circle's radius? Use 3.14 for . kilometers Siubmit explain
Answers
Given:
It is given that the perimeter of a quarter circle is 3.57 km.
To find :
The radius of the quarter circle.
Explanation :
The perimeter of the quarter circle is
[tex]P=\frac{2\pi r}{4}\text{ }+2r[/tex]Substitute the value of perimeter in the above formula
[tex]3.57=\frac{\pi r}{2}+2r[/tex][tex]3.57=(\frac{3.14}{2}+1)r[/tex][tex]3.57=2.57r[/tex][tex]r=1.39[/tex]Answer
Hence the radius of a quarter circle is 1.39 km.
The coordinates of three vertices of a rectangle are (3,7), (-3,5), and (0,-4). What are the coordinates of the fourth vertex?A. (6,-2)B. (-2,6)C. (6,2)D. (-2,-6)
Answers
ANSWER
A. (6, -2)
EXPLANATION
Let's graph these three vertices,
The fourth vertex must be at the same distance from (0, -4) as vertex (3, 7) is from (-3, 5),
Note that the horizontal distance between these two points is 6 units and the vertical distance is 2 units. The fourth vertex is,
[tex](0+6,-4+2)=(6,-2)[/tex]Hence, the fourth vertex is (6, -2)
Which graph shows the same linear equation shown in the table below?
Answers
I'm drawing now
_______________________
Option C
Jerry takes out a 30-year mortgage for $170,000.00 to buy a condo. His monthly mortgage payment is $939.00. How much interest will he pay over the life of the loan? Round your answer to the nearest whole dollar.
Answers
Okay, here we have this:
Considering the provided information we obtain the following:
Mortgage capital=$170,000
Total payment = Monthly payment * 12 months of the year * number of years
Total payment = $939*12*30
Total payment = $338,040
Total payment = Mortgage capital + Interest
Replacing we obtain:
Total payment = Mortgage capital + Interest
$338,040=$170,000+interest
Interest= $338,040-$170,000
Total Interest=$168,040
Finally we obtain that the total interest is $168040.
translate the following into an equation:6 less decreased by twice a number results in 8
Answers
Let the number be x.
Twice the number means 2 * x = 2x
Twice the number decreased by 6 means
2x - 6
Given that the result is 8, we have
2x - 6 = 8
J is the midpoint of CT if CJ=5x-3 and JT=2x+21 find CT
Answers
Since J is the midpoint of the CT segment, then:
[tex]\begin{gathered} CJ=JT \\ 5x-3=2x+21 \end{gathered}[/tex]Now, you can solve the equation for x:
[tex]\begin{gathered} 5x-3=2x+21 \\ \text{ Add 3 from both sides of the equation} \\ 5x-3+3=2x+21+3 \\ 5x=2x+24 \\ \text{ Subtract 2x from both sides of the equation} \\ 5x-2x=2x+24-2x \\ 3x=24 \\ \text{ Divide by 3 from both sides of the equation} \\ \frac{3x}{3}=\frac{24}{3} \\ x=8 \end{gathered}[/tex]Replace the value of x into the equation for segment CJ or segment JT to find out what its measure is. For example in the equation of the segment CJ:
[tex]\begin{gathered} CJ=5x-3 \\ x=8 \\ CJ=5(8)-3 \\ CJ=40-3 \\ CJ=37 \end{gathered}[/tex]Finally, you have
[tex]\begin{gathered} CJ=37 \\ CJ=JT \\ 37=JT \\ \text{ Then} \\ CT=CJ+JT \\ CT=37+37 \\ CT=74 \end{gathered}[/tex]Therefore, the measure of the segment CT is 74.
< BackSee SolutionShow ExampleRecord: 1/3 Score: 1 Penalty: 1 offComplete: 11% Grade: 0%Brianna AllenFinding the Slope from PointsJon 03, 7:15:08 PMWhat is the slope of the line that passes through the points (4, -9) and (8, -3)?Write your answer in simplest form.
Answers
To obtain the slope of the line that passes through the two given points, the following steps are recommended:
Step 1: Recall the formula for the slope of a line that passes through any two points (x1, y1) and (x2, y2), as follows:
[tex]\text{slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]Step 2: Apply the formula to find the slope of the line that passes through the points (4, -9) and (8, -3), as follows:
[tex]\begin{gathered} \text{Given that:} \\ (x_1,y_1_{})=(4,-9) \\ (x_2,y_2)=(8,-3) \\ \text{Thus:} \\ \text{slope}=\frac{y_2-y_1}{x_2-x_1} \\ \Rightarrow\text{slope}=\frac{-3_{}-(-9)_{}}{8_{}-4_{}}=\frac{-3+9}{4}=\frac{6}{4}=\frac{3}{2} \\ \Rightarrow\text{slope}=\frac{3}{2} \end{gathered}[/tex]Therefore, the slope of the line that passes through the points (4, -9) and (8, -3) is 3/2
Third-degree, with zeros of -3, -2, and 1, and passes through the point (4, 10).
Answers
The required third degree expression is 1/7 (x³ + 2x² - 5x - 6)
Given,
Find a third degree expression f(x) that has zeros -3, -2, 1 and the equation y = f(x) passes through (4, 10). ,
If the roots/zeroes of a nth order expression are given as r₁, r₂, r₃....rₙ, the expression is given by f(x) = c(x - r₁) (x - r₂) (x - r₃)....(x - rₙ)
Since we know the three roots of the third degree expression, the function is;
f(x) = c(x - (-3)) (x - (-2)) (x - 1)
= c(x + 3) (x + 2) (x - 1)
= c (x³ + 2x² - 5x - 6)
Also y = f(x), passes through(4, 10) , so
10 = c(4³ + 2 x 4² - 5 x 4 - 6)
10 = c(64 + 32 - 20 - 6)
10 = 70c
c = 10/70 = 1/7
∴Required expression is 1/7 (x³ + 2x² - 5x - 6)
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