PLZ SOMEONE HELP WITH THESE!!!!!!!!!! WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!

Answer: npo

Step-by-step explanation:

Answer:

135 meters

Step-by-step explanation:

h = 60t - 5t²

t is in seconds and it says to find out the height after 3 seconds

Sub the value '3' into 't'

h = 60(3) - 5(3)²

h = 180 - 5(9)

h = 180 - 45

h = 135 m

Answer:

[tex]f(2x) = 8x^{2} +3[/tex]

Step-by-step explanation:

f (x) = 2x²+3

f(2x) = [tex]2(2x)^{2}[/tex] + 3

f(2x) = [tex]2(4x^{2} )[/tex] + 3

f(2x) = [tex]8x^{2}[/tex] + 3

Answer:

m<CGD = 26°

m<CGF = 100°

Step-by-step explanation:

m<CGD = 2x - 2

m<EGF = 37

m<CGF = 7x + 2

Since GE bisects <DGF, m<DGF = 2*m<EGF.

m<DGF = 2*37 = 74°

m<CGD + m<DGF = m<CGF (angle addition postulate)

(2x - 2) + (74) = (7x + 2)

Find the value of x using the equation above.

2x - 2 + 74 = 7x + 2

Collect like terms

2x + 72 = 7x + 2

-2 + 72 = 7x - 2x

70 = 5x

70/5 = 5x/5

14 = x

x = 14

m<CGD = 2x - 2

Plug in the value of x

m<CGD = 2(14) - 2 = 28 - 2

m<CGD = 26°

m<CGF = 7x + 2

m<CGF = 7(14) + 2 = 98 + 2

m<CGF = 100°

Answer:

it problely 16 is close

Step-by-step explanation:

it dipens where the numeber is place at

The area of the semicircle is 25.133 cm².

[tex]\rm{Area\ of\ semicircle = \dfrac{Area\ of\ Circle}{2}[/tex]

[tex]\rm{Area\ of\ semicircle = \dfrac{\pi \times r^2}{2}[/tex]

diameter, d = 8 cm,

radius, r = [tex]\dfrac{diamter}{2} = \dfrac{8}{2} = 4\ cm[/tex]

[tex]\rm{Area\ of\ semicircle = \dfrac{Area\ of\ Circle}{2}[/tex]

[tex]\rm{Area\ of\ semicircle = \dfrac{\pi \times r^2}{2}[/tex]

[tex]\rm{Area\ of\ semicircle = \dfrac{\pi \times 4^2}{2} = \dfrac{\pi \times 4 \times 4}{2}=8\pi\ cm^2[/tex]

Therefore, the area of the semicircle is 8π cm² = 25.133 cm².

Hence, the area of the semicircle is 25.133 cm².

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The area of a semicircle with diameter 8cm is; 25.14cm²

The area of a circle is given by the formula;

Area = πr²

Therefore, Area of a semicircle is;

Read more on area of a semicircle;

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Answer:

45 = 1.5p

450 = 15p

p=30

Answer:

12

Step-by-step explanation:

Answer:

A & E

Step-by-step explanation:

A. 4/5 x 5/6 = 2/3

B. 7/8 x 9/10 = 63/80

C. 1/3 x 2/3 = 2/9

D. 3/4 x 7/12 = 7/16

E. 6/7 x 7/9 = 2/3

Options A and E are correct.

A. 4/5 x 5/6

E. 6/7 x 7/9

Let us simplify  the expressions one after the other to identify the ones with a product of 2/3

[tex]\frac{4}{5} \times \frac{5}{6} = \frac{4}{6} = \frac{2}{3}[/tex]

[tex]\frac{7}{8} \times \frac{9}{10} = \frac{63}{80}[/tex]

[tex]\frac{1}{3} \times \frac{2}{3} = \frac{2}{9}[/tex]

[tex]\frac{3}{4} \times \frac{7}{12} = \frac{7}{16}[/tex]

[tex]\frac{6}{7} \times \frac{7}{9} = \frac{6}{9} = \frac{2}{3}[/tex]

From the options considered, only options A and E give 2/3 as a product

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Answer:

2[tex]\frac{1}{12}[/tex]

Step-by-step explanation:

1[tex]\frac{2}{3}[/tex] ÷ [tex]\frac{4}{5}[/tex]

[tex]\frac{5}{3}[/tex] ÷ [tex]\frac{4}{5}[/tex]

[tex]\frac{5}{3}[/tex] * [tex]\frac{5}{4}[/tex]

[tex]\frac{25}{12}[/tex]

[tex]2\frac{1}{12}[/tex]

Answer:

2

Step-by-step explanation:

The required triangle KLM and triangle QPR has been proved congruent with Hypotenuse-Leg theorem.

In a right angled triangle, its side, such as hypotenuse, perpendicular and base  is Pythagorean triplets.

From triangle KLM and QPR,
KM = QR
LK = PQ

Square and subtract above equations,
KM² - LK² = QR² - PQ²   - - - - - (1)

From Pythagoras theorem,
hypotenuse ² = perpendicular² + base square,

For triangle KLM
KM²  = LK²  + LM²
KM² - LK² =  LM²  - - - - -(2)

For triangle QPR,
QR² = PQ² + PR²
QR² - PQ² = PR² - -- - - - (3)

From equation 2 and 3 put value in equation 1
LM² = PR²
LM = PR

Thus, triangle KLM and triangle QPR proved  to be congruent. And the theorem is Hypotenuse-Leg theorem.

Learn  more about Pythagorean triplets here:

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Answer:

y = 52

x = 30

Step-by-step explanation:

Hi!

Y is a vertical angle. See <DOB? That's it's vertical pair. So, y = 2x - 8 [vertical angles are congruent].

Now, to find y, we need x. We can find x by using the fact that AB is a straight line. The angles on a straight line add up to 90.

Given the fact that <AOB is 90 degrees, <EOB also has to be 90 degrees.

So, EOB = 90 degrees. Remember that an angle is equal to the sum of the measures of the angles that it is made of.

EOB is therefore equal to <EOD + <DOB.

90 = <EOD + DOB

90 = (x +8) + (2x-8)

90 = 3x

x = 30

Check:

38 + 52 = 90.

So, x = 30

Now, we go back to find y.

y = 2x-8

y = 52

x = 0

Hi there !

9x + 2y = 10

replace y = 5

9x + 2×5 = 10

9x + 10 = 10

9x = 10 - 10

9x = 0

x = 0

Good luck !

Answer:

Step-by-step explanation:

Since, lines l and m are parallel and a transverse is intersecting these lines.

5). (9x + 2)° = 119° [Alternate intrior angles]

    9x = 117 ⇒ x = 13

6). (12x - 8)° + 104° = 180°

     12x = 180 - 96

     x = [tex]\frac{84}{12}[/tex] ⇒ x = 7

7). (5x + 7) = (8x - 71) [Alternate exterior angles]

    8x - 5x = 71 + 7

    3x = 78

    x = 26

8). (4x - 7) = (7x - 61) [Corresponding angles]

    7x - 4x = -7 + 61

    3x = 54

    x = 18

9). (9x + 25) = (13x - 19) [Corresponding angles]

    13x - 9x = 25 + 19

    4x = 44

    x = 11

   (13x - 19)° + (17y + 5)° = 180°[Linear pair of angles are supplementary]

    (13×11) - 19 + 17y + 5 = 180

    129 + 17y = 180

    17y = 180 - 129

     y = 3

10). (3x - 29) + (8y + 17) = 180 [linear pair of angles are supplementary]

     3x + 8y = 180 + 12

     3x + 8y = 192 -----(1)

     (8y + 17) = (6x - 7) [Alternate exterior angles]

     6x - 8y = 24

     3x - 4y = 12 -----(2)

     Equation (1) - equation (2)

     (3x + 8y) - (3x - 4y) = 192 - 12

     12y = 180

     y = 15

     From equation (1),

     3x + 8(15) = 192

     3x + 120 = 192

    x = 24

11). (3x + 49)° = (7x - 23)° [Corresponding angles]

    7x - 3x = 49 + 23

    4x = 72 ⇒ x = 18

    (11y - 1)° = (3x)° [Corresponding angles]

    11y = 3×18 + 1

     11y = 55 ⇒ y = 5  

12). (5x - 38)° = (3x - 4)° [Corresponding angles]

     5x - 3x = 38 - 4

     2x = 34

     x = 17

     (7y - 20)° + (5x - 38)° + 90° = 180°

     [Sum of interior angles of a triangle = 180°]

     7y + 5x - 58 = 90

     5x + 7y = 148

     5×17 + 7y = 148

     85 + 7y = 148

     7y = 148 - 85

     y = [tex]\frac{63}{7}=9[/tex]

Angles can be congruent based n several theorems; some of these theorems are: corresponding angles, vertical angles, alternate exterior angles and several others.

The values of x and y are:

Question 5:

Angles (9x + 2) and 119 are alternate angles.

Alternate angles are equal. So, we have:

[tex]\mathbf{9x +2 = 119}[/tex]

Subtract 2 from both sides

[tex]\mathbf{9x = 117}[/tex]

Divide both sides by 9

[tex]\mathbf{x = 13}[/tex]

Question 6:

Angles (12x - 8) and 104 are interior angles.

Interior angles add up to 180. So, we have:

[tex]\mathbf{12x -8 + 104 = 180}[/tex]

Collect like terms

[tex]\mathbf{12x = 180 - 104 + 8}[/tex]

[tex]\mathbf{12x = 84}[/tex]

Divide both sides by 12

[tex]\mathbf{x = 7}[/tex]

Question 7:

Angles (5x + 7) and (8x - 71) are alternate exterior angles.

Alternate exterior angles are equal. So, we have:

[tex]\mathbf{5x + 7 = 8x - 71}[/tex]

Collect like terms

[tex]\mathbf{8x - 5x= 71 + 7}[/tex]

[tex]\mathbf{3x= 78}[/tex]

Divide both sides by 3

[tex]\mathbf{x= 26}[/tex]

Question 8:

Angles (4x - 7) and (7x - 61) are corresponding angles.

Corresponding angles are equal. So, we have:

[tex]\mathbf{4x - 7 = 7x - 61}[/tex]

Collect like terms

[tex]\mathbf{4x - 7x = 7 - 61}[/tex]

[tex]\mathbf{- 3x = -54}[/tex]

Divide both sides by -3

[tex]\mathbf{x = 18}[/tex]

Question 9:

Angles (9x + 25) and (13x - 19) are corresponding angles.

Corresponding angles are equal. So, we have:

[tex]\mathbf{9x + 25 = 13x - 19}[/tex]

Collect like terms

[tex]\mathbf{9x -13x = -25 - 19}[/tex]

[tex]\mathbf{-4x = -44}[/tex]

Divide both sides by -4

[tex]\mathbf{x = 11}[/tex]

Angles (17y + 5) and (13x - 19) are supplementary angles.

So, we have:

[tex]\mathbf{17y + 5 = 13x - 19}[/tex]

Substitute 11 for x

[tex]\mathbf{17y + 5 = 13\times 11 - 19}[/tex]

[tex]\mathbf{17y + 5 = 124}[/tex]

Subtract 5 from both sides

[tex]\mathbf{17y = 119}[/tex]

Divide both sides by 17

[tex]\mathbf{y = 7}[/tex]

Question 10:

Angles (3x - 29) and (6x - 7)  add up to 180

So, we have:

[tex]\mathbf{3x -29 + 6x - 7 = 180}[/tex]

Collect like terms

[tex]\mathbf{3x + 6x = 180 + 7 + 29}[/tex]

[tex]\mathbf{9x = 216}[/tex]

Divide both sides by 9

[tex]\mathbf{x = 24}[/tex]

Angles (3x - 29) and (8y + 17) are supplementary angles.

So, we have:

[tex]\mathbf{3x - 29 + 8y + 17 = 180}[/tex]

Substitute 24 for x

[tex]\mathbf{3 \times 24 - 29 + 8y + 17 = 180}[/tex]

[tex]\mathbf{43 + 8y + 17 = 180}[/tex]

Collect like terms

[tex]\mathbf{8y = 180 - 43 - 17}[/tex]

[tex]\mathbf{8y = 120}[/tex]

Divide both sides by 8

[tex]\mathbf{y = 15}[/tex]

Question 11:

Angles (7x - 23) and (49 + 3x) are corresponding angles

So, we have:

[tex]\mathbf{7x - 23 = 49 + 3x}[/tex]

Collect like terms

[tex]\mathbf{7x - 3x = 49 + 23}[/tex]

[tex]\mathbf{4x = 72}[/tex]

Divide both sides by 4

[tex]\mathbf{x = 18}[/tex]

Angles 3x and (11y - 1) are corresponding angles.

So, we have:

[tex]\mathbf{3x = 11y - 1}[/tex]

Substitute 18 for x

[tex]\mathbf{3 \times 18 = 11y - 1}[/tex]

[tex]\mathbf{54 = 11y - 1}[/tex]

Collect like terms

[tex]\mathbf{11y =54+ 1}[/tex]

[tex]\mathbf{11y =55}[/tex]

Divide both sides by 11

[tex]\mathbf{y =5}[/tex]

Question 12:

Angles (5x - 38) and (3x - 4) are corresponding angles

So, we have:

[tex]\mathbf{5x - 38 = 3x - 4}[/tex]

Collect like terms

[tex]\mathbf{5x - 3x = 38 - 4}[/tex]

[tex]\mathbf{2x = 34}[/tex]

Divide both sides by 2

[tex]\mathbf{x = 17}[/tex]

Angles (7y - 20) and (5x - 38) are angles at the other legs of a right-angled triangle.

So, we have:

[tex]\mathbf{7y - 20 +5x - 38 = 90}[/tex]

Substitute 17 for x

[tex]\mathbf{7y - 20 +5 \times 17 - 38 = 90}[/tex]

[tex]\mathbf{7y+ 27 = 90}[/tex]

Collect like terms

[tex]\mathbf{7y=- 27 +90}[/tex]

[tex]\mathbf{7y=63}[/tex]

Divide both sides by 7

[tex]\mathbf{y=9}[/tex]

Read more about congruence angles at:

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Answer:

x=1

Step-by-step explanation:

9+4x=15-2x

9+6x=15                    Add two to both sides

6x=6                        divide by 6

x=1

Answer:

-12

Step-by-step explanation:

I set it up as an equation based on the word problem you gave me

So

2n - 15 = 4n + 9

Combine like terms

-2n = 24

Isolate the variable n

-2n/-2 = 24/-2

n = -12

2(-12) - 15 = 4(-12) + 9

-24 - 15 = -48 + 9

-39 = -39

Answer:

An exterior angle of a triangle is an angle formed by one side of the triangle and the extension of an adjacent side of the triangle. FACTS: ... The measure of an exterior angle of a triangle is equal to the sum of the measures of the two non-adjacent interior angles.

Answer:

360 meters

Step-by-step explanation:

15 x 24 = 360

24 is how many seconds

The cheetah runs 15 meter PER second

Answer:The two containers will have the same amount of water in 50 minutes

Step-by-step explanation:

800-6x=1000-10x

Answer:

C

Step-by-step explanation:

You need something to talk about

Answer its C

Step-by-step explanation:

Answer:

The answer is (50) but what does the number sentence mean?

Step-by-step explanation:

Answer:

x = 4

Step-by-step explanation:

From the figure attached,

Two lines l and m are the parallel lines.

Angle BAD is an exterior angle of triangle ABC.

By the theorem of exterior angle of a triangle,

"Exterior angle of a triangle is equal to the sum of two opposite interior angles."

m(∠BAD) = m(∠ABC) + m(∠BCA)

28x = 16x + 48

28x - 16x = 48

12x = 48

x = 4

Therefore, x = 4 will be the answer.  

Using tha appropriate triangle theorem, the value of x in the given triangle is 4

Recall the theorem ;

Expressing as an equation :

16x + 48 = 28x

Collect like terms

16x - 28x = - 48

-12x = - 48

x = 48/12

x = 4

Therefore, the value of x is 4.

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Answer:

r = -0.2

Step-by-step explanation:

5r-50=-51

5r=-1

r= -0.2

Thats what I got based on PEMDAS...

Answer:

[tex]\boxed {r = -\frac{1}{5}}[/tex]

Step-by-step explanation:

Solve for the value of [tex]r[/tex]:

[tex]5(r - 10) = -51[/tex]

-Use Distributive Property:

[tex]5(r - 10) = -51[/tex]

[tex]5r - 50 = -51[/tex]

-Add [tex]50[/tex] on both sides:

[tex]5r - 50 + 50 = -51 +50[/tex]

[tex]5r = -1[/tex]

-Take [tex]5[/tex] and divide it on both sides:

[tex]\frac{5r}{5} = \frac{-1}{5}[/tex]

[tex]\boxed {r = -\frac{1}{5}}[/tex]

Therefore, the value of [tex]r[/tex] is [tex]-\frac{1}{5}[/tex].

===================================================

Work Shown:

5x^3 + 14x^2 + 9x

x( 5x^2 + 14x + 9 )

To factor 5x^2 + 14x + 9, we could use the AC method and guess and check our way to getting the correct result.

A better way in my opinion is to solve 5x^2 + 14x + 9 = 0 through the quadratic formula

[tex]x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(14)\pm\sqrt{(14)^2-4(5)(9)}}{2(5)}\\\\x = \frac{-14\pm\sqrt{16}}{10}\\\\x = \frac{-14\pm4}{10}\\\\x = \frac{-14+4}{10} \ \text{ or } \ x = \frac{-14-4}{10}\\\\x = \frac{-10}{10} \ \text{ or } \ x = \frac{-18}{10}\\\\x = -1 \ \text{ or } \ x = \frac{-9}{5}\\\\[/tex]

Then use those two solutions to find the factorization

x = -1  or  x = -9/5

x+1 = 0  or  5x = -9

x+1 = 0  or  5x+9 = 0

(x+1)(5x+9) = 0

So we have shown that 5x^2 + 14x + 9 factors to (x+1)(5x+9)

-----------

Overall,

5x^3 + 14x^2 + 9x

factors to

x(x+1)(5x+9)

Answer:

9 cm

Step-by-step explanation:

Answer:

3x + 5.

Step-by-step explanation:

factor out 1/6 (1/2 • 1/3)

distribute the 3 from the paranthesis

1/6 (3(8x + 4) + 2(9-3x))

1/6(24x + 12 + 2(9-3x))

distribute 2 through parentheses

1/6(24x+12+18-6x)

collect like terms:

1/6(18x + 12 + 18) > 1/6(18x +30)

factor out 6

1/6 • 6(3x+5)

reduce with GCF (6)

3x + 5

Answer:  The simplified expression is:  " [tex]3x + 5[/tex] " .

______________________________

Step-by-step explanation:

______________________________

Given the expression:

______________________________

" One-half (8 x + 4) + one-third (9 minus 3x) "  ;

We can rewrite that as:

[tex]\frac{1}{2}[/tex] [tex](8x+4) + \frac{1}{3}(9-3x)[/tex]

Now, let us simplify the expression:

Start with:

[tex]\frac{1}{2}(8x+4)[/tex] ;

Note the "distributive property" of multiplication:

  a(b + c)  = ab + ac ;

Likewise:

[tex]\frac{1}{2}{(8x +4) = (\frac{1}{2})8x + (\frac{1}{2})4=\frac{8}{2}x +\frac{4}{2} =4x +2[/tex] ;  '

Now continue with the remaining part of the expression:

[tex]+\frac{1}{3}(9-3x)[/tex] ;

Again, use the "distributive property" of multiplication:

     a(b + c)  = ab + ac ;

[tex]+\frac{1}{3}(9-3x)= (\frac{1}{3})9+(\frac{1}{3})(-3x)=\frac{9}{3}+(-\frac{3}{3}x)=3+(-1x);[/tex]

                                                                          =  3 − 1x ;

                                                                          =  3 − x  ;

________________________________________

Now, combine both terms within the expression; to simplify the expression:  

   [tex](4x + 2) + (3 -x)[/tex] ;

Rewrite as:

   [tex]4x + 2 + 3 - x[/tex] ;

Now, combine the "like terms":

  [tex]^+4x -x = 4x -1x = 3x[/tex] ;

  [tex]^+2 +3 = 5[/tex]  ;

The simplified expression is:  " [tex]3x + 5[/tex] " .

________________________________________

Hope this is helpful to you!  Best wishes!

_________________________________________

Answer: $35,833

There are 12 months in a year. Divide 430,000 by 12.

430,000 divided by 12 = $35,833...

Mr. Bingley makes $35,833 per month.

Wish you the best of luck!

Answer:

$35,833.33

Step-by-step explanation:

Amount Mr.Bingley makes in a year(in 12 months)= $430,000

Hence, the money he earns in a month= $430,000/12=$35,833.33

Answer: n = 10

Step-by-step explanation:

Dividing exponents results to subtracting them. 8-(-6) is 14. Multiplying negative numbers together results in positive numbers. the exponent 14 - 4 is 10. So n = 10.