Let the number be x.
[tex]\begin{gathered} \frac{1}{2}x+16=\frac{2}{3}x-4 \\ \\ \frac{2}{3}x-\frac{1}{2}x=20 \\ \frac{4-3}{6}x=20 \\ \frac{1}{6}x=20 \\ x=120 \end{gathered}[/tex]The number is 120
I need help on this question
Answer:
Real zeros are: x = 0, x = 1 and x =2
***Your graph is incorrect. See mine for the correct graph***
Step-by-step explanation:
We have the polynomial
[tex]$\displaystyle \:x^{4}-3x^{3}+2x^{2}\:=\:0$[/tex]
[tex]\mathrm{Factor\:out\:common\:term\:}x^2:\\\\[/tex]
[tex]=x^2\left(x^2-3x+2\right)[/tex]
[tex]\mathrm{Factor}\:x^2-3x+2:[/tex]
For an expression of the form ax² + bx + c we can find factors if we find two values u and v such uv = c and u + v =b and factor into (ax +ux)+ (vx+c)
We have here a = 1, b = -3 c = 2
==> u = -1, v = -2
[tex]\:x^2-3x+2 = (x-1)(x-2)[/tex]
So the original expression becomes
[tex]\:x^2-3x+2 = x^2\left(x-1\right)\left(x-2\right)[/tex]
To find the zeros, set this equal to 0 and solve for x
[tex]x^2\left(x-1\right)\left(x-2\right)=0[/tex]
We end up with 3 roots corresponding to the 0 values for each of the three terms
[tex]x^2 = 0 == > x = \pm 0 = 0\\\\[/tex]
[tex](x - 1) = 0 == > x = 1\\\\(x - 2) = 0 == > x = 2\\\[/tex]
Answer real zeros are: x = 0, x = 1 and x =2
**** Your graph is incorrect. Check mine. The zeros happen where the curve intersects the x axis and these are at x = 0, x = 1, x =2
Alisa walks 3.5 miles in 30 minutes. At this rate, how many miles can she walk in 45 minutes?385.7 miles5 miles386 miles5.25 miles
Given:
Alisa walks 3.5 miles in 30 minutes.
To find:
The number of miles if she walks 45 mins.
Explanation:
The unit rate for speed is,
[tex]\begin{gathered} Speed=\frac{Distance}{Time} \\ =\frac{3.5}{30} \end{gathered}[/tex]The distance covered when she walks 45mins,
[tex]\begin{gathered} Distance=Speed\times Time \\ =\frac{3.5}{30}\times45 \\ =5.25miles \end{gathered}[/tex]Final answer:
The number of miles she walks in 45mins is 5.25miles.
Which of the following size measures will form a right triangle
From the given side lengths, let's find the measures that will form a right triangle.
Apply Pythagorean Theorem:
[tex]a^2+b^2=c^2[/tex]Where:
• a ,and ,b, are lengths of the legs
,• c is the length of the hypotenuse.
Now, let's start from the first measures in option a.
• 48m, 64m, and 85m
[tex]\begin{gathered} 48^2+64^2=85^2 \\ \\ 2304+4096=7225 \\ \\ 6400\ne7225 \end{gathered}[/tex]The measures in option a will NOT form a right triangle since the left side of the equation does not equal the right side.
• 27 yd, 36 yd, 45 yd
[tex]\begin{gathered} 27^2+36^2=45^2 \\ \\ 729+1296=2025 \\ \\ 2025=2025 \end{gathered}[/tex]The measures in option B will form a right triangle because the Equation is true.
ANSWE
16. Four solids labelled A, B, C, and D are shown below. o A B D a. Which of the solids has a curved face? 1mk b. Which solid has 5 faces? 1mk c. Which solid has 12 edges? Imk
a. A solid has curved surface area.
b. C solid has 5 faces.
c. D solid has 12 edges.
Can someone help me with this please and thank you
The histogram is skewed to the left, the mean is less than the median.
Patrice found airpods on sale for $84. The sale sales tax is 5%. What is the total Patrice will pay for the airpods?
To find the final cost with tax. You find the 5% of $84 and add that result to the initial cost:
[tex]84\cdot\frac{5}{100}=4.2[/tex][tex]84+4.2=88.2[/tex]Then, Patrice will pay $88.2 for the airpods
hi i'm stuck on diameter and radius and chord and the arc measure explanations. And i'm also stuck on this question
• Chord: ,a line segment connecting ,any two points, in a curve (circle).
,• Diameter: ,a chord passing ,through the center ,of the figure.
,• Radius: ,a line segment going ,from the center, to any point in the circumference.
The difference between them is that the chord is any two points touching the circumference, the diameter has to go through the center to any two points, and the radius goes from the center to just one point in the circumference.
Then, the line segment that meets the requirements of being the diameter in circle F is segment CD as it passes through the center.
The radius could be CF, DF, and EF. While a chord could be AB.
Answer: CD
Grandma’s Guide to Cooking MeasurementsDried Seasonings 1 pinch = 2 smidgens1 dash = 2 pinches1 sprinkle = 3 pinches1 teaspoon = 8 dashesBased on Grandma's guide to cooking, how many smidgens are in one teaspoon?Do not include units with your answer.
32
Explanation:1 pinch = 2 smidgens
1 dash = 2 pinches
Therefore, 1 dash = 2 x 2 smidgens
1 dash = 4 smidgens
1 teaspoon = 8 dashes
1 teaspoon = 8 x 4 smidgens
1 teaspoon = 32 smidgens
There are 32 smidgens in 1 teaspoon
hi, i need help finding the mean and standard deviation. the reeses pieces are just a filler for the sample subject.
Solution
For this case we can calculate the mean in the following way:
[tex]E(X)=np=30\cdot0.52=15.6[/tex]And the standard deviation would be:
[tex]Sd(x)=\sqrt[=]{30\cdot0.52\cdot(1-0.52)}=2.736[/tex]In the picture below, line PQ is parallel to line RS, and the lines are cut by a transversal, line TO. The transversal is not perpendicular to the parallel lines.
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
Congruent angles = ?
Step 02:
We must analyze the diagram to find the solution.
Congruent angles:
∠ Y ≅ ∠ E
The answer is:
∠ Y ≅ ∠ E : are congruent
Identify the explicit formula for the sequence given by the following recursive formula: A) f(n) = –2 + 4(n – 1)B) f(n) = –4 + 2(n – 1)C) f(n) = 4 – 2(n – 1)D) f(n) = 2 – 4(n – 1)
Given the recurssive formula;
[tex]f(n)=\begin{cases}f(1)=-2 \\ f(n)=f(n-1)+4\text{ if n>1}\end{cases}[/tex]Let's find the sequence using the recurssive formula, we have;
[tex]\begin{gathered} f(2)=f(2-1)+4 \\ f(2)=f(1)+4 \\ f(2)=-2+4 \\ f(2)=2 \\ f(3)=f(3-1)+4 \\ f(3)=f(2)+4 \\ f(3)=2+4 \\ f(3)=6 \\ f(4)=f(4-1)+4 \\ f(4)=f(3)+4 \\ f(4)=6+4 \\ f(4)=10 \end{gathered}[/tex]Thus, we have the sequence as;
[tex]-2,2,6,10,\ldots[/tex]We observed that the sequence is an arithmetic sequence with a common difference of 4 and first term of -2.
So, the recursive formula is;
[tex]\begin{gathered} f(n)=f(1)+d(n-1)_{} \\ f(n)=-2+4(n-1) \\ f(n)=-2+4n-4_{} \\ f(n)=4n-6 \end{gathered}[/tex]CORRECT OPTION: A
What is the slope of a line parallel to the line whose equation is 12x – 15y = 315.Fully simplify your answer.
Answer:
4/5
Explanation:
Definition: Two lines are parallel if they have the same slope.
Given the line:
[tex]12x-15y=315[/tex]Determine the slope of the given line by expressing it in the slope-intercept form (y=mx+b), where m is the slope:
[tex]\begin{gathered} 12x-15y=315 \\ \text{ Add 15y to both sides of the equation} \\ 12x-15y+15y=315+15y \\ 12x=315+15y \\ \text{ Subtract 315 from both sides:} \\ 12x-315=315-315+15y \\ 12x-315=15y \\ \text{ Divide all through by 15} \\ \frac{15y}{15}=\frac{12}{15}x-\frac{315}{15} \\ y=\frac{4}{5}x-21 \end{gathered}[/tex]• The slope of the line, m = 4/5.
Since the lines are parallel, they have the same slope.
Hence, the slope of a line parallel to the line whose equation is 12x – 15y = 315 is 4/5.
please give a VERY SHORT EXPLANATION NOT LONG! i inserted a picture of the question
If the amount of time spent is lesser than or equal to 250, so the price is $29, so we have the first part of the piecewise equation:
[tex]f(x)=29,\text{ x <= 250}[/tex]Then, for an amount of time greater than 250, the extra minutes are charged by 0.35 per minute, and this extra cost will add the fixed cost of $29, so the second part of the equation is:
[tex]f(x)=29+(x-250)0.35,\text{ x>250}[/tex]The option that shows the correct piecewise equation is option A.
The sum of two numbers is 83. The difference of the 2 numbers is 13. What is the product of the two numbers?A.1632B.1650C.1666D.1680
Answer:
Let the first number be
[tex]=x[/tex]Let the second number be
[tex]=y[/tex]The sum of two numbers is 83 can be represented below as
[tex]x+y=83\ldots\ldots(1)[/tex]The difference of the 2 numbers is 13 can be represented below as
[tex]x-y=13\ldots\ldots\text{.}(2)[/tex]Step 1:
From equation (1) make x the subject of the formula to to give equation (3)
[tex]\begin{gathered} x+y=83\ldots\ldots(1) \\ x=83-y\ldots\text{.}(3) \end{gathered}[/tex]Step 2:
Substitute equation (3) in equation (2)
[tex]\begin{gathered} x-y=13\ldots\ldots\text{.}(2) \\ x=83-y\ldots\text{.}(3) \\ 83-y-y=13 \\ 83-2y=13 \\ \text{collect similar terms,} \\ -2y=13-83 \\ -2y=-70 \\ \text{divide both sides by -2} \\ \frac{-2y}{-2}=\frac{-70}{-2} \\ y=35 \end{gathered}[/tex]Step 3:
Substitute y= 35 in equation (3)
[tex]\begin{gathered} x=83-y\ldots\text{.}(3) \\ x=83-35 \\ x=48 \end{gathered}[/tex]Hence,
The product of the two numbers will be calculated as
[tex]\begin{gathered} =x\times y \\ =35\times48 \\ =1680 \end{gathered}[/tex]Hence,
The final answer is = 1680
OPTION D is the final answer
Pls. Help me ;( thx ur the best
Answer:
**NEED USEFUL ANSWER ASAP, H.W QUESTION**
Given that hotter blackbodies produce more energy than cooler blackbodies, why do cooler red giants have much higher luminosities than much hotter white dwarfs?
Step-by-step explanation:
what is the approximation of 3√200
Given the expression:
[tex]\text{ }\sqrt[3]{200}[/tex]Let's simplify the expression and convert its decimal form to get its approximation.
We get,
[tex]\text{ }\sqrt[3]{200}\text{ = }\sqrt[3]{8\text{ x 25}}[/tex][tex]\text{ =2 }\sqrt[3]{25}[/tex]In decimal form:
[tex]\text{ 2 }\sqrt[3]{25}\text{ = 2 x 2.92401773821 = 5.84803547643 }\approx\text{ 5.8}[/tex]Therefore, the approximate equivalent of 3√200 is 5.8.
what is 6!3! over 2!5!
Answer:
16
Step-by-step explanation:
6!3!
-------
2!5!
(1 × 2 × 3 × 4 × 5 × 6)(1 × 2 × 3)
--------------------------------------------
(1 × 2)(1 × 2 × 3 × 4 × 5)
(720)(6)
-------------------
(2)(120)
4320
------------ = 18
240
I hope this helps!
prove the formula sin 3 A + sin A = 4 sin A cos2A
We proved that formula using the trigonometry relations sin3A + sinA = 4sinAcos^2A.
In the given question,
We have to prove the formula sin 3A+sin A = 4sinAcos^2A
The given expression is sin 3A+sin A = 4sinAcos^2A
To prove the formula we take the left side terms to the right side terms
The left side is sin 3A+sin A.
As we know that sin 3A = 3sinA − 4sin^3A
To solve the left side we put the value of sin 3A in sin 3A+sin A.
=sin 3A+sin A
=3sinA − 4sin^3A+sin A
Simplifying
= (3sinA+sin A) − 4sin^3A
= 4sinA − 4sin^3A
Taking 4sinA common from both terms
= 4sinA(1 − sin^2A)
As we know that cos^2A=1 − sin^2A. So
= 4sinAcos^2A
We proved the right hand side.
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the net of a rectangular prism is shown below. the surface area of each face is labeled. which vakues represent the dimensions, in meters, of the rectangular prism.
The answer is 5, 9, 10
Find the degree of the polynomial.2x6 − 4x2 + 3x − 1
Given:
There are given the equation:
[tex]f(x)=2x^6-4x^2+3x-1[/tex]Explanation:
According to the question, we need to find the degree.
So,
From the concept of degrees:
The degree is the largest exponent of the variable.
Final answer:
Hence, the value of the degree is 6.
You live 3 miles from collage and 2 miles from the business where you work.Let d represent the distance between your work and the collage write an inequality involving d.
The inequality involving the distance is 3 > d > 2.
What is an inequality?An inequality is simply used to illustrate the expressions that aren't equal. This can be illustrated through the use of greater than, less than, etc.
When you live live 3 miles from collage and 2 miles from the business where you work. This will be expressed thus
Let d represent the distance between your work and the collage and the inequality is 3 > d > 2.
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what is the area of the Shaded region used 3.14
In this problem, the area of the shaded region is equal to the area of the complete square, minus the area of the four circles
so
REmember that
The length side of the complete square is equal to two times the diameter of one circle
A=(2*12)^2-4*pi*(12/2)^2
assume pi=3.14
A=576-4(3.14)(36)
the area of the Shaded region is A=123.84 ft^2HELP PLEASEEEEE!!!!!!
A horizontal line with evenly spaced numerical increments is referred to as a number line. How the number on the line can be answered depends on the numbers present. The use of the number is determined by the question that it corresponds to, such as when graphing a point.
The visual depiction of numbers, such as fractions, integers, and whole numbers, spread out uniformly along a single horizontal line is known as a number line. A number line can be used as a tool for operations like addition and subtraction as well as comparison and sorting of numbers.
Given:
As from the Figure we have
-1 3/4 = -7/4 = -1.75, which is represented by point 1 on the number line.
and, 14/8 = 1.75, which is represented by point 7 on the number line.
and, 1.125, which is represented by point 6 on the number line.
and, -0.875, which is represented by point 4 on the number line.
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Solve the following system of inequalities graphically on the set of axes below. State the coordinates of a point in the solution set.y ≥ 3x - 6y < -2x - 1LABEL ALL COORDINATESAnswer
Answer:
(-3, 2)
Explanation:
Given the system of inequalities:
[tex]\begin{gathered} y\ge3x-6 \\ y<-2x-1 \end{gathered}[/tex]To solve the inequalities graphically, follow the steps below:
Inequality 1
First, find the equation of the boundary line.
[tex]y=3x-6[/tex]Next, determine the intercepts to draw the boundary line.
[tex]\begin{gathered} \text{When }x=0,y=3(0)-6=-6\implies(0,-6) \\ \text{When y}=0,0=3x-6\implies3x=6\implies x=2\implies(2,0) \end{gathered}[/tex]Join the points (0,-6) and (2,0) using a solid line.
Finally, determine the required half-plane using the origin test.
[tex]\begin{gathered} At\text{ (0,0)} \\ y\ge3x-6\implies0\ge-6(T\text{rue)} \end{gathered}[/tex]The side that contains the point (0,0) is the required half-plane.
The graph showing the first inequality is given below:
Inequality 2
First, find the equation of the boundary line.
[tex]y=-2x-1[/tex]Next, determine the intercepts to draw the boundary line.
[tex]\begin{gathered} \text{When }x=0,y=-2(0)-1=-1\implies(0,-1) \\ \text{When y}=0,0=-2x-1\implies-2x=1\implies x=-0.5\implies(-0.5,0) \end{gathered}[/tex]Join the points (0,-1) and (-0.5,0) using a broken line.
Finally, determine the required half-plane using the origin test.
[tex]\begin{gathered} At\text{ (0,0)} \\ y<2x-1\implies0<-1(False\text{)} \end{gathered}[/tex]The side that DOES NOT contain the point (0,0) is the required half-plane.
The graph of the system of inequalities is given below:
A point in the solution set is (-3, 2).
I have a bag, with some balls in it. All but four are blue, all but four are green, and all but four are red.
In total, how many balls are there in the bag?
===============================================
Explanation:
x = total number of balls
x-4 = number of blue
x-4 = number of green
x-4 = number of red
3(x-4) = 3x-12 = total number of blue, green, or red
x - (3x-12) = x-3x+12 = -2x+12 = number of other colors
If there are other colors, then we want this quantity to be larger than 0, so,
-2x+12 > 0
-2x > -12
x < -12/(-2)
x < 6
There are less than 6 balls in the bag.
At the same time, we want each x-4 to be greater than zero
x-4 > 0
x > 4
------------------
We found that x > 4 and x < 6
This combines to 4 < x < 6 which has us land on x = 5
This computes x-4 = 5-4 = 1, showing there's one of each blue, green and red. There are 5-1-1-1 = 2 balls of some other color not mentioned.
------------------
If x = 6, then,
x-4 = 2 each of blue, green and red
There wouldn't be any other color since 6-2-2-2 = 0
Solve for x
4x = -5
Put the answer in its simplest form.
Answer:
[tex] \sf x=-1.25 [/tex]
[tex]\sf--------------------------------------------------------------------- [/tex]
Step-by-step explanation:
4x = -5
Divide both sides by 4 to single out the variable
4x/4 = -5/4
x = -1.25
I'll send you the pic a
Let's complete the four equations, as follows:
1. 5 * x = 15
Solving for x:
5x = 15
Dividing by 5 at both sides:
5x/5 = 15/5
x = 3
3 is the value to fill in the box
2. 4 * x = 32
Solving for x:
4x = 32
Dividing by 4 at both sides:
4x/4 = 32/4
x = 8
8 is the value to fill in the box
3. 6 * x = 9
Solving for x:
6x = 9
Dividing by 6 at both sides:
6x/6 = 9/6
x = 1.5
1.5 is the value to fill in the box
4. 12 * x = 3
Solving for x:
12x = 3
Dividing by 12 at both sides:
12x/12 = 3/12
x = 3/12
Simplifying:
x = 1/4
1/4 or 0.25 is the value to fill in the box
Last week Forrest cut the grass exactly 3 times. It takes him between 55 and 75 minutes per cut.
CWrite an inequality to model all of the possible amounts of time (t) Forrest could have spent
cutting the lawn last week. Show or explain all your work.
Explanation:
If he mowed the lawn exactly once, then 55 ≤ t ≤ 75 describes all the possible values of t. Basically t is between 55 and 75 inclusive of both endpoints.
Multiply each value by 3
55*3 = 165
75*3 = 225
That's how we end up with 165 ≤ t ≤ 225 to represent the possible span of time values where he mowed the grass three times. His fastest possible time is 165 minutes (2 hr, 45 min) and his slowest possible time is 225 minutes (3 hr, 45 min).
need help with part a with a summary and all work shown to help me understand better
ANSWER:
[tex]\left(16u^{\frac{1}{3}}\right)^{\frac{3}{4}}=8\sqrt[4]{u}[/tex]STEP-BY-STEP EXPLANATION:
We have the following expression:
[tex]\left(16u^{\frac{1}{3}}\right)^{\frac{3}{4}}[/tex]When you raise an exponent to another exponent, multiply therefore:
Please help. I don't really understand monomials and negative exponets
The standard form of the monomial expression is -1x¹⁰
Monomial expression:
A monomial is an algebraic expression with a single term but can have multiple variables and a higher degree too.
Given,
Here we have the expression
(-2x³)².(-1/4 x⁴)
Now, we have to convert the expression into standard form.
To convert the expression into standard monomial form,
First we have to expand the terms, then we get,
=> (-2²x⁶).(-1/4x⁴)
Then we have to divide the variables and constants separately.
=> (4 x -1/4).(x⁶⁺⁴)
=> -1 . x¹⁰
=> -1x¹⁰
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