Predict the shape of the molecule.

A. octahedral
B. Linear
C. Trigonal Pair
D. tetrahedral

When salt dissolves in water, dissociation occurs. This dissociation forms two ions, one positive and one negative. Water is polar and its molecules has poles negatives and positives. So positive poles of water will surround the negative ions. While negative poles will surround the positive ions.

Answer: Alternative "B"

The pH of the resulting solution  is 10.9 .

given that :

for HClO₄

volume = 25 mL = 0.025 L

M = 0.30 M

no. of moles = 0.025 × 0.30

                     = 0.0075

for CH₃NH₂

no. of moles = 0.35 × 0.06

                    = 0.021

as a resultant no. of moles of CH₃NH₂ that remain in solution

= 0.021-0.0075

= 0.0135

total volume = 0.025 + 0.060

                     = 0.085

the concentration will be :

concentration for HClO₄ = 0.0075 / 0.085

                                         = 0.088 M

concentration for  CH₃NH₂ = 0.0135 / 0.088

                                             = 0.153

kb = 4.4 × 10⁻⁴

pkb = - log kb

pkb = 3.3

the pOH formula is given as :

POH = pKb + log [ acid ] / [ base ]

pOH = 3.3 + log [ 0.088 ] / [ 0.153 ]

pOH = 3.06

pH + pOH = 14

pH = 14 - 3.06

pH = 10.9

Thus, The pH of the resulting solution when 25.0mL of 0.30M HClO₄ is added to 60.0ml of 0.35 M CH₃NH₂. Kb forCH₃NH₂ = 4.4 × 10^-4 . pH is 10.9.

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Step 1

The reaction must be written, completed, and balanced:

2 NaOH + H2SO4 => Na2SO4 + H2O

-----------

Step 2

Information provided:

Mass of NaOH = 40.0 g

Mass of H2SO4 = 60.0 g

--

Information needed:

The molar masses:

NaOH) 40.0 g/mol approx.

H2SO4) 98.0 g/mol approx.

-----------

Step 3

The limiting reactant?

By stoichiometry:

1 mole NaOH = 40.0 g

1 mole H2SO4 = 98.0 g

2 NaOH + H2SO4 => Na2SO4 + H2O

2 x 40.0 g NaOH ----------- 98.0 g H2SO4

40.0 g NaOH ----------- X

X = 40.0 g NaOH x 98.0 g H2SO4/2 x 40.0 g NaOH = 49.0 g H2SO4

For 40.0 g of NaOH, 49.0 g of H2SO4 is needed but is provided 60.0 g of H2SO4. Therefore, the excess is the H2SO4, and the limiting reactant is the NaOH.

Answer: the limiting reactant is NaOH

Answer:

A. There is an overall energy increase when bonds form.

Explanation:

Remember that when a chemical reaction occurs, molecular bonds are broken and other bonds are formed to make different molecules. For example, the bonds of two water molecules are broken to form hydrogen and oxygen. Energy is always required to break a bond, which is known as bond energy but we release energy when we form a bond.

Many atoms are unstable because they have to comply with the octet rule, so they form bonds with other atoms and the energy is released. So based on this logic, the answer would be A. There is an overall energy increase when bonds form.

In order to properly balance an equation, we need to make sure that the same amount of elements on the reactants side matches the number of elements on the products side, we can do that by increasing the number in front of each molecule, the so called stoichiometric coefficient. In the reaction from the question we can properly balance by adding the following stoichiometric coefficients

For this question we have:

CaCl2 -> Ca + 2 Cl

The shape and bond angle of the molecule will be, H2S =shape= bent, Bond angle =less than 109 degrees

2) CH4 = shape = tetrahedral

bond angle-=109 degrees

1)H2S =shape= bent

Bond angle =less than 109 degrees

2) CH4 = shape = tetrahedral

bond angle-=109 degrees

3) HCN = shape = Linear

Bond angle = 180 degrees

4) NF3 = shape = trigonal planar

Bond angle = less than 109 degrees

5) BCl3 = shape = trigonal planar

Bond angle = 120 degrees

6) NH2Cl = shape = trigonal pyramidal

Bond angle = 107  degrees

7) OF2 = shape = linear

Bond angle = 109 degrees

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The final pressure of the gas when the sample gas is administered to a new volume of 10.0 L at 20.2℃ would be 0.245 atm.

The problem here has to do with the combined gas law. The law is mathematically expressed as:

[tex]p_1v_1/t_1[/tex] =[tex]p_2v_2/t_2[/tex]

Where [tex]p_1[/tex] = initial pressure, [tex]v_1[/tex] = initial volume, [tex]t_1[/tex] = initial temperature, [tex]p_2[/tex] = final pressure, [tex]v_2[/tex] = final volume, and [tex]t_2[/tex] = final temperature.

In this case,

Rearranging the combined gas equation:

[tex]p_2[/tex] = [tex]p_1v_1t_2/t_1v_2[/tex]

Substituting the different variables:

[tex]p_2[/tex] = 1.2 x 6.02 x 20.2/59.5 x 10.0

      = 145.9248/595

      = 0.245 atm

Thus, the final pressure of the sample gas will be 0.245 atm.

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To write the numbers with the specific number of significant figures, we need to remember that zeros to the left don't count as a significant figure and also that we can add zeros to the right to add significant figures to the numbers.

1) 1.5408 to 3 significant figures, we start counting from left to right, so we will maintain the numbers until the second decimal place, the "8". Since the next is "0", the rounding is "8", so the number is 1.54.

2) Here is similar, but since we don't have decimal places, we need to put the zeros in place of the numbers we are rounding. Since we want 2 significant figures, we will maintain only the first two. However, since the third is greater than 5, we need to round up, so the number is 4400.

3) To get this, we will maintain the zeros to the elft, but they don't count, so we start counting from the "1". Since the third number is less than 5, we round down, so the number is 0.019.

4) Now, here we have an example we need to add zeros. The way it is, 0.5 has only 1 significant figure, so we need to add 3 more zeros to the right to get to 4 significant figures. The number is 0.5000.

5) Here, is the same as item 3, but we want 3 significant figures and since the fourth is greater than 5 we round it up. So, the number is 0.066.

Answer:

Iron 24.03%

Carbon 30.90%

Hydrogen 3.86%

Oxygen 41.20 %

Explanation:

Here, we want to get the percentage composition of the given compound

What this means is that we want to get the percentage composition of each of the elements present in the compound

Firstly, we calculate the molar mass of the given compound

We can calculate the molar mass by adding the atomic masses of the elements and their multiplicities

Mathematically, we have that as:

Now, let us get the percentage compositions

For Iron, we have:

For Carbon, we have:

For Hydrogen, we have:

For Oxygen, we have:

The volume of the base, LiOH required to reach the halfway point will be 170.6 mL.

The balanced chemical equation for this reaction will be:

HCOOH +LiOH → HCOOHLi + [tex]H_{2}O[/tex]

It can be observed that,

The mole ratio of HCOOH ([tex]n_{a}[/tex], acid) = 1

The mole ratio of LiOH ([tex]n_{b}[/tex], base) = 1

Volume of acid, HCOOH ([tex]V_{a}[/tex] = 64.0 mL

Molarity of acid, HCOOH ([tex]M_{a}[/tex]) = 0.4 M

Molarity of base, LiOH ([tex]M_{b}[/tex]) = 0.150 M

The volume of a base can be determined by the formula:

Ma×Va / Mb ×Vb = nA / nB.....(i)

Now, put the given data in above formula:

(0.4 × 64) / (0.150 × [tex]V_{b}[/tex]) = 1

25.6 / (0.150 × [tex]V_{b}[/tex]) = 1

By solving it:

0.150 × [tex]V_{b}[/tex] = 25.6

[tex]V_{b}[/tex] = 25.6 / 0.150

[tex]V_{b}[/tex] = 170.6 mL

Therefore, the volume of the LiOH required to reach the halfway point will be 170.6 mL.

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Answer:

Explanation:

Carbon is the only element listed. Carbon Dioxide consists of Carbon AND Oxygen x2 so this is a compound. As stated earlier, air is a mixture of compounds. Water is another compound consisting of Hydrogen x2 and Oxygen.

The total energy to break the hexane bonds will be equal to the sum of each of the energy to break each bond.

So the first thing we're going to do is determine how many and what type of bonds hexane has. Hexane is an alkane, meaning the C-C bonds are all single bonds. We also have C-H bonds. According to the structure of hexane, we will count each of the bonds in the following figure:

The number of C-H bonds is written in blue, we see that there are 14 C-H bonds, which coincides, being an alkane, with the number of hydrogen atoms.

The number of C-C bonds is written in orange. The number of C-C bonds is equal to 5.

Now, we multiply the energy to break each bond by the number of bonds and add the energy of the C-H and C-C bonds.

So, for 1 mol of hexane the energy. required to break all the bonds will be 7514kJ

Answer: The closest value to the answer is 7520. D) 7520 kJ

Answer:

Explanation:

the answer is D

Answer:

D

Explanation:

capillaries veins and arteries

Sulphur has a larger atomic radius than chlorine, even though chlorine has more protons, neutrons and electrons because sulfur is to the left of chlorine in the periodic table.

Atomic radius is defined as the distance between the atomic nucleus of an atom to the electron which is located at the outermost shell of the atom.

In the periodic table, the elements are being arranged in groups and periods with respect to their various atomic mass and numbers.

The atomic radius decreases across the period but increases down the group of the periodic table.

Therefore, sulphur would probably have a larger atomic radius when compared with chloride because it is located to the left of chloride in the periodic table.

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Explanation:

Raoult's law states that the vapor pressure of a solvent that is a over a solution is equal to the vapor pressure of the pure solvent at the same temperature scaled by the mole fraction of the solvent.

Psolution = Xsolvent * P°solvent

Where Psolution is the vapor pressure of the solution, X is the molar fraction of the solvent and P°solvent is the vapor pressure of the pure solvent.

Our solvent is chloroform, we know its vapor pressure.

P°solvent = 120 mmHg

We still have to find the molar fraction of the solvent. The molar fraction of the solvent will be defined like:

Xsolvent = moles of solvent/(total number of moles)

We know that the concentration of the solution is 0.200 m. That means that we have 0.200 moles of solute in each kg of solvent.

In order to find the mole fraction we have to suppose that the solution has 1 kg of solvent.

mass of solvent = 1 kg

molality = 0.200 m

molality = moles of solute/(mass of solvent in kg)

0.200 m = moles of solute/1 kg

moles of solute = 0.200 m * 1 kg

moles of solute = 0.200 moles

So our solution has 0.200 moles of solute in 1 kg of solvent. The solvent is chloroform (CHCl₃). We can convert the mass of solvent into moles using the molar mass of it.

molar mass of CHCl₃ = 119.38 g/mol

mass of solvent = 1 kg = 1 kg * 1000 g/kg

mass of solvent = 1000 g

moles of solvent = 1000 g * 1 moles/(119.38 g)

moles of solvent = 8.377 moles

Our solution has 8.377 moles of solvent and 0.200 moles the non-volatile solute.

total number of moles = moles of solute + moles of solvent

total number of moles = 8.377 moles + 0.200 moles

total number of moles = 8.577 moles

Xsolvent = moles of solvent/(total number of moles)

Xsolvent = 8.377 moles/(8.577 moles)

Xsolvent = 0.977

Finally we found the mole fraction of the solvent and we can find the answer to our problem.

Psolution = Xsolvent * P°solvent

Psolution = 0.977 * 120 mmHg

Psolution = 117.2 mmHg

Answer: The vapor pressure of the solution is 117.2 mmHg.

In this question, we have to find the number of atoms in 12.5 moles of Sulfur, and the way to do it is by using the Avogadro's number, which is 6.02*10^23 atoms, this value represents how many atoms we have in 1 single mol of any element. Therefore in 12.5 moles we will have:

1 mol = 6.02*10^23 atoms

12.5 moles = x atoms

x = 7.52*10^24 atoms of Sulfur in 12.5 moles

Answer:

1.11 x 10²³ atoms O

Explanation:

To find the number of oxygen atoms in FeSO₄, you need to (1) convert FeSO₄ from grams to moles (using the molar mass), then (2) convert moles FeSO₄ to moles O (using the mole-to-mole ratio of FeSO₄), and then (3) convert moles O to atoms O (using Avogadro's Number). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs like the given number (7.00 = 3 sig figs).

Atomic Mass (Fe): 55.845 g/mol

Atomic Mass (S): 32.065 g/mol

Atomic Mass (O): 15.999 g/mol

Molar Mass (FeSO₄): 55.845 g/mol + 32.065 g/mol + 4(15.999 g/mol)

Molar Mass (FeSO₄): 151.906 g/mol

1 mole FeSO₄: 1 mole Fe, 2 mole S, 4 moles O

Avogadro's Number:

6.022 x 10²³ atoms = 1 mole

 7.00 g FeSO₄             1 mole                 4 moles O            6.022 x 10²³ atoms
-----------------------  x  -------------------  x  -----------------------  x  ----------------------------
                                   151.906 g           1 mole FeSO₄                  1 mole

=  1.11 x 10²³ atoms O

To solve this problem we can use the Ideal gas law:

The problem give us de following information:

P1= 131kPa

V1=1.82L

T1=-30°C= 243.15 K

P2= 233 kPa

V2= 1.3L

Then we just have to solve for T2 and use the information provided:

Then the answer is T2=35.76°C

Answer: the second one

Explanation:

Answer:

there's no answer choices?

Answer

A. -1305 kJ

Explanation

Given:

Equation: C2H4(g) + 302(g) ---- > 2C02(g) + 2H20(l).

Formation ΔH values:

​​for C2H4(g) = 52.30 kJ/mol,

for 02(g) = 0 kJ/mol,

for CO2(g) = -393.5 kJ/mol, and

for H20(1) = -285.8kJ/mol.

What to find:

The ΔHrxn from the ΔH of formation for the given reaction.

Step-by-step solution:

ΔHrxn = (Sum of ΔH formation for the product) - (Sum of ΔH formation for the reactants).

ΔHrxn = (ΔH for 2CO2(g) + ΔH for 2H2O(l)) + (ΔH for C2H4(g) + ΔH for 3O2(g))

ΔHrxn = [(2 x -393.5) + (2 x -285.8)] + [52.30 + (3 x 0)]

ΔHrxn =(-787.0 - 571.6) + (52.30 + 0)

ΔHrxn = -1358.6 + 52.30

ΔHrxn = -1306.3 kJ

so the closest answer is A. -1305 kJ

Answer:

Explanation:

Here, we want to get the class of lipids that the given substances belong to

These substances are formed from glycerol and fatty acids

From their make up,we know that they are simple lipids

Thus, the answer here is simple

The final pressure of the sample gas based on the new volume and temperature would be 0.245 atm.

The combined gas law is expressed as:

[tex]\frac{p_1v_1}{t_1}[/tex] = [tex]\frac{p_2v_2}{t_2}[/tex]

Where

In this case, we were given all the variables except the final pressure, [tex]p_2[/tex]:

Making p2 the subject of the formula in the combined gas equation, we have:

[tex]p_2[/tex]= [tex]p_1v_1t_2/t_1v_2[/tex]

Next, let's substitute the given variables:

[tex]p_2[/tex]= 1.2 x 6.02 x 20.2/59.5 x 10.0

     = 145.9248/595

     = 0.245 atm

In other words, the final pressure when the sample of gas is administered to a new volume of 10.0 L at 20.2℃ is 0.245 atm'

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There are only two electrons that could posses the quantum numbers as shown.

We now that it is often common to seek to describe the probability of finding the electrons in the atom. While it is know that the electron is not a given point in the atom. The probability of finding the electron in the atom is given by the help of the quantum numbers that can be used to describe the position of the electron as shown.

In tis case, we have an electron that has the quantum numbers; n = 3, l = 2, ml = -2. This describes an orbital and there are two electrons in a given orbital.

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Answer

a. 74.2

Explanation

Given that:

The initial temperature, T₁ = 63.2 °C + 273 = 336.2 K

Initial pressure, P₁ = 57.3 kPa

The final volume, V₂ = 15.56 mL

Final temperature, T₂ = 138.7°C + 273 = 411.7 K

Final pressure, P₂ = 334.6 kPa

What to find:

The initial volume, V₁.

Step-by-step solution:

The initial volume, V₁ can be calculated using the combined gas law equation.

Hence, its initial volume at 63.2 °C and 57.3 kPa is 74.2 mL

According to the concept of molar concentration,0.715 g of hydrogen iodide are dissolved in the solution.

Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.

The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.

In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.

Using the formula of M₁V₁=M₂V₂ molarity of HI is determined,that is ,M₂=0.25×22.4/15=0.373 M.

For determining the mass is determined by using the formula,mass=0.373×127.911×0.015=0.715 g

Thus, 0.715 g of hydrogen iodide are required for making the solution.

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Final Molarity of acetate ion is 0.0394 M. The number of moles of solute per liter of solution is referred to as molarity.

The amount of a substance in a given volume of solution is measured in molarity (M). Molarity is defined as the number of moles of a solute in one liter of solution. A solution's molarity is also known as its molar concentration.

Therefore,

We first assume that the reaction completes and that the volume of the reaction remains constant.

The balanced stoichiometric equation is as follows:

Ba(CH₃COO)₂ + (NH₄)₂SO₄ → BaSO₄ + 2NH₄(CH₃COO)

First, we must determine which reactant is in excess and which has been completely consumed by the reaction. To do so, we count the number of moles of each reactant at the beginning of the reaction.

For Ba(CH₃COO)₂

The number of moles = (Mass)/(Molar Mass)

Barium acetate mass = 2.68 g

Barium acetate molar mass = 255.43 g/mol

The number of moles = (2.68/255.43) = 0.0104 moles.

For (NH₄)₂SO₄,

Number of moles = (Concentration in mol/L) × (Volume in L)

Concentration of Ammonium surface in mol/L = 45 M

Volume in L = (300/1000) = 0.3 L

Number of moles = 45 × 0.3 = 13.5 moles

From the stoichiometric balance of the reaction,

1 mole of Ba(CH₃COO)₂ responds with 1 mole of (NH₄)₂SO₄

As a result, it is clear that Ba(CH₃COO)₂ is the limiting reagent; the chemical specie that is depleted during the reaction and determines the number of other reactants and products formed.

1 mole of Ba(CH₃COO)₂ provide 2 moles of NH₄(CH₃COO)

0.0591 moles of Ba(CH₃COO)₂ will give 2 × 0.0591 moles of NH₄(CH₃COO); 0.1182 moles of NH₄(CH₃COO).

The molarity of NH₄(CH₃COO) exist then provide as (number of moles) ÷ (Vol in L)

The number of moles = 0.1182 moles

L volume of the solution = 0.3 L

Molarity of NH₄(CH₃COO) = (0.01182/0.3)

= 0.0394 M

Note that 1 mole of NH₄(CH₃COO) contains 1 mole of acetate ion,

Hence, 0.0394 M of NH₄(CH₃COO) also contains 0.0394 M of acetate ion.

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Given Data:

Concentration of acid, H2SO4 = 2.59 M

For, H2SO4, n-factor = 2, i.e., the number of [tex]H^{+}[/tex] ions on dissociation

Thus, the concentration in normality, N1 = 2.59 x 2 = 5.18 N

Concentration of base, KOH = 0.827 M

For, KOH, n-factor = 1, i.e., the number of [tex]OH^{-}[/tex] ions on dissociation

Thus, the concentration in normality, N2 = 0.827 x 1 = 0.827 N

Volume of  base, V2 = 47.50 mL

Using the formula, N1 x V1 = N2 x V2, where, V1 = volume of acid

Thus, volume of acid required to neutralize, V1 = [tex]\frac{N_{2}X V_{2} }{N_{1} }[/tex] =  [tex]\frac{0.827 X 47.50}{5.18}[/tex]

                                                                               = 7.58 mL.

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Answer:

B. The percent yield is 55.9%.

Explanation:

From the balanced reaction we know that 2 moles of FePO4 produce 1 mole of Fe2(SO4)3.

1st) It necessary to convert moles into grams, using the molar mass of FePO4 (151g/mol) and the molar mass of Fe2(SO4)3 (400g/mol):

- FePO4 conversion:

- Fe2(SO4)3 conversion:

In this case, it is not necessary the conversion, because there is 1 mole, so it is equal to 400g.

Now we know that 302g of FePO4 produce 400g of Fe2(SO4)3.

2nd) Now we have to calculate the Theoretical yield of Iron (III) sulfate, that is, the amount of Iron (III) sulfate that we must produce from 25g of Iron (III) phosphate:

So, the Theoretical yield is 33.11g.

3rd) Finally, we can calculate the Percent yield using the Theoretical yield (33.11g) and the Actual yield (18.5g):

So, the percent yield is 55.9%.

The concentration of C₂H₅OH in the resulting solution is 1.332 M.

given that :

mass of C₂H₅OH = 30.7 g

molar mass =46.07 g/mol

volume =  500 ml = 0.5 L

number of moles can be calculated by the following formula :

number of moles = mass / molar mass

no. of moles = 30.7 g / 46.07 g/mol

no. of moles = 0.666 mol

now, the concentration of C₂H₅OH :

Molarity = no. of mole / volumes in l

Molarity = 0.666 / 0.5

Molarity = 1.332 M

Thus, If 30.7 g of C₂H₅OH (MM = 46.07 g/mol) are added to a 500.0 mL volumetric flask, and water is added to fill the flask, The concentration of C₂H₅OH in the resulting solution is 1.332 M.

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