Q3) Salman walks to the mosque with speed 2.4 m/s. If it takes him 3 min to
reach the mosque. Find the distance.​

Answer:

D. Constructive Interference of waves

Explanation:

Rogue waves occur when wave forms arrive suddenly in oceans, thus causing ships to sink within a very short time. The explanation scientists have for this is constructive interference magnified by second-order bound non-linearities. Waves are meant to arrive in a particular direction. During constructive interference, these waves arrive from different directions and in an organized way thus increasing the height of the wave.

This increased height is as a result of the waves not being in a linear form and having sharp peaks. There is also a significant difference between the crests and troughs. Scientists arrived at this explanation for the rogue waves though three experiments conducted in 1997, 2007, and 2015.

The force acts on this bullet : 4.8456 N

Given

m=0.09 kg

Δt=0.025 s

vo=0(from rest)

vt=1.346 m/s

Required

Force

Solution

Impulse is a change in momentum

I=ΔP

F.Δt=m(vt-vo)

Input the value

F x 0.025 = 0.09(1.346-0)

F=4.8456 N

Answer:

6.45×10¯²⁶ J

Explanation:

From the question given above, the following data were obtained:

Frequency (f) = 97.3 MHz

Energy (E) =?

Next, we shall convert 97.3 MHz to Hz. This can be obtained as follow:

1 MHz = 1×10⁶ Hz

Therefore,

97.3 MHz = 97.3 MHz × 1×10⁶ Hz / 1 MHz

97.3 MHz = 9.73×10⁷ Hz

Thus, 97.3 MHz is equivalent to 9.73×10⁷ Hz.

Finally, we shall determine the energy at which the frequency is broadcasting. This can be obtained as follow:

Frequency (f) = 9.73×10⁷ Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =?

E = hf

E = 6.63×10¯³⁴ × 9.73×10⁷

E = 6.45×10¯²⁶ J

Therefore, the energy at which the frequency is broadcasting is 6.45×10¯²⁶ J

Answer:

12 N/cm²

Explanation:

From the question given above, the following data were obtained:

Weight (W) of block = 240 N

Area (A) = 20 cm²

Pressure (P) =?

Next, we shall determine the force exerted by the block. This can be obtained as follow:

Weight (W) of block = 240 N

Force (F) =.?

Weight and force has the same unit of measurement. Thus, we force applied is equivalent to the weight of the block. Thus,

Force (F) = Weight (W) of block = 240 N

Force (F) = 240 N

Finally, we shall determine the pressure on the floor as follow:

Force (F) = 240 N

Area (A) = 20 cm²

Pressure (P) =?

P = F/A

P = 240 / 20

P = 12 N/cm²

Therefore, the pressure on the floor is 12 N/cm².

Answer:

45kw45_32+675&453try to get it done

Answer:

A: 9 kg

Explanation:

on edge! hope this helps!!~ ∩(︶▽︶)∩

Answer:

Unit of precision for force is the Newton.

Explanation:

It is the official unit used to describe force in science and mostly abbreviated with the symbol N.

Answer:

pendulum

hope it helps! please mark me brainliest..

Thank you! have a good day ahead

Answer:

F = 318.88[N]

Explanation:

This problem can be solved by the principle of momentum conservation, which tells us that momentum is preserved before and after kicking the ball.

In this way, we can construct the following equation.

[tex]F*t=m*v[/tex]

where:

F = force [N]

t = time = 0.08 [s]

m = mass = 0.41 [kg]

v = velocity [m/s]

[tex]F*0.045=0.41*35\\F=318.88[N][/tex]

Answer:

a)   w = 0.4726 rad / s,     b)  w_{f} = 4.56 rad / s

Explanation:

a) the two skaters have an angular momentum, for which we will form a system formed by the two of them, in this case when they collide the forces are internal and the moment is conserved.

Initial instant. When the skaters approach, just before touching

        L₀ = r p = r m v

in this case the result is the same if we take the reference system at the midpoint or on one of the skaters.    We place the reference system on one of the skaters

Final moment. After being joined by the pole

         [tex]L_{f}[/tex] = I w

as the forces are internal, the ngualr moment is conserved

         L₀ = L_{f}

         r m v = I w

suppose we approximate the skaters as particles

         I = m r²

we substitute

        r m v = m r² w

        w = v /r

we calculate

        w = 1.38 /2.92

         w = 0.4726 rad / s

What happens is that when the two skaters lower the pole, their velocity acts as a torque, creating a rotational movement with angular velocity w.

b) When the skaters who are at r₀ = 2.92 m approach [tex]r_{f}[/tex] = 0.940 m as the system is isolated, the angular momentum is conserved

initial instant. r₀ = 2.92

       L₀ = I w

final instant r_{f} = 0.940 m

       L_{f} = I_{f}  w_{f}

       L₀ = L_{f}

       I w = I_{f} w_{f}

let's approximate skaters as particles

       I = m r²

we substitute

     m r² w = m r_{f}² wf

     [tex]w_{f}[/tex] = [tex]\frac{r^{2} }{r_{f}^{2} } w[/tex]

we calculate

     w_{f} = [tex]\frac{2.92^{2} }{ 0.940^{2} }[/tex] 0.4726

     w_{f} = 4.56 rad / s

we see that the angular velocity increases

Answer:

The time it will take the mega-ray blaster to hit the ground is 2.57 s.

Explanation:

Given;

initial velocity of Optimus Prime, u = 24 m/s

height of fall of the mega-ray blaster, h = 94 m

The time of fall of the mega-ray blaster is calculated using the following kinematic equation;

[tex]h = ut + \frac{1}{2}gt^2\\\\94 = 24t + \frac{1}{2}(9.8)t^2\\\\94 = 24t + 4.9t^2\\\\4.9t^2 +24t -94 = 0\\\\Use \ formula \ method \ to \ solve \ for \ "t"\\\\a = 4.9 , b = 24, c = -94\\\\t = \frac{-b \ +/- \ \sqrt{b^2 -4ac} }{2a} \\\\t = \frac{-24 \ +/- \ \sqrt{(24)^2 -4(-94 \times4.9)} }{2(4.9)} \\\\t = \frac{-24 \ +/- \ \sqrt{2418.4} }{9.8}\\\\t = \frac{-24 \ +/- \ 49.177 }{9.8}\\\\t = \frac{-24 \ +\ 49.177 }{9.8} \ \ or \ \ t = \frac{-24 \ -\ 49.177 }{9.8} \\\\[/tex]

[tex]t = 2.57 \ s \ \ or \ \ t = -7.47 \ s[/tex]

t = 2.57 s

Therefore, the time it will take the mega-ray blaster to hit the ground is 2.57 s.

Answer:

=101343.62N/m^2

Explanation:

absolute pressure on the bottom of a swimming pool= atmospheric pressure +( 2 ×ρ ×g)

( 2 ×ρ ×g)= guage pressure

atmospheric pressure= 101325pa

h= height= 1.9 mm = 1.9×10^-3m

ρ = density of water

= 1000kg/m^3

g= acceleration due to gravity= 9.8m/s^2

Then substitute, we have

absolute pressure on the bottom of a swimming pool= 101325+ [0.0019 ×1000 × 9.8)]

=101343.62N/m^2

Hence, the absolute pressure on the bottom of a swimming pool is =101343.62N/m^2

Explanation:

Given that,

Number of turns in the coil, N = 100

Area of the coil, A = 100 cm² = 0.01 m²

It is placed at an angle of 70°.

Magnetic field, B = 0.1 Wb/m²

We need to find the magnetic flux through the coil and the emf is induced in the coil after 10⁻³ s.

Magnetic flux is given by :

[tex]\phi =BA\cos\theta\\\\\text{For N turns},\\\phi =NBA\cos\theta \\\\\phi=100\times 0.1\times 0.01\times \cos(70)\\\\=0.034\ Wb[/tex]

So, the magnetic flux through the coil is 0.1 Wb.

Emf induced in the coil is :

[tex]\epsilon=\dfrac{-d\phi}{dt}\\\\=\dfrac{0.034}{10^{-3}}\\\\=34\ V[/tex]

So, 34V of emf is induced in the coil.

Answer:

The building is 176.4 meters high.

Explanation:

We use the formula for kinematics of an accelerated object (in this case acceleration of gravity):

Distance travelled = 1/2 g  t^2

Distance travelled = 1/2 9.8  (6)^2 = 176.4 meters

Answer:

Noise does not affect the digital signal, making it more reliable.                               This information is transmitted digitally, making it more reliable

Explanation:

Just did it on Ape.x

This information is transmitted digitally, making it more reliable. Noise does not affect the digital signal, making it more reliable. The correct options are B and D.

The transfer and reception of data in the form of a digital bitstream or a digitized analogue signal transmitted through a point-to-point or point-to-multipoint communication channel is known as data transmission and reception, or, more broadly, data communication or digital communications.

Because digital switching systems are substantially less expensive than analogue switching systems, digital transmission is used to achieve high reliability.

However, the analogue signals that make up the majority of speech, radio, and television must be used for digital transmission.

This information is more dependable because it is conveyed digitally. The digital signal is unaffected by noise, increasing its dependability.

Thus, B and D are the correct options.

For more details regarding digital transmission, visit:

https://brainly.com/question/29393615

#SPJ5

Answer:

v= 17.15 m/s

Explanation:

mass of the book=0.1 Kg

height above ground, h= 15 m

Using conservation of energy

Potential energy is converted into kinetic energy

[tex]mgh = \frac{1}{2}mv^2[/tex]

[tex]v=\sqrt{2gh}[/tex]

[tex]v=\sqrt{2\times 9.8\times 15}[/tex]

[tex]v=\sqrt{294}[/tex]

v= 17.15 m/s

Hence, the book will hit the ground at the speed of 17.15 m/s.

Answer:

98.0665 newtons

have a good day :]

Explanation:

Such spheres are intimately connected. Many animals (biosphere), for example, migrate through to the sky, while groundwater (hydrosphere) also flows through the ground (lithosphere). The domains are actually so closely related that a shift in one globe always results in a shift in one or both of some other spheres.

Answer:

See the answer below

Explanation:

To solve this problem we must use the definition of power and work in physics.

a)

The function of the conveyor belt is to carry the boxes from an initial point that is at low altitude to an end point that is at high altitude. In this way the conveyor belt prints a speed to the box to be able to raise it to the required vertical distance.

Since we have a velocity at the beginning and then we place the box at a high position, where then the box remains at rest, we can say that it converts kinetic energy to potential energy.

b)

Power is defined as the relationship of work over time. Therefore we have:

[tex]P=W/t[/tex]

where:

P = power = 3.8 [kW] = 3800 [W]

W = work [J]

t = time = 14 [s]

[tex]W=P*t\\W=3800*14\\W= 53200[J] = 53.2[kJ][/tex]

c)

Since the given time is equal to the given time at Point b, we can use the same work calculated.

We know that work is defined as the product of force by the distance traveled.

[tex]W =F*d[/tex]

So, the force is equal to:

[tex]F=W/d\\F=53200/5.3\\F=10037.73[N][/tex]

Now we know that force is defined as the product of mass by gravitation acceleration.

[tex]F =m*g[/tex]

where:

F = force or weight = 10037.73 [N]

g = gravity acceleration = 9.81 [m/s²]

m = mass [kg]

[tex]m=F/g\\m = 10037.73/9.81\\m = 1023.2 [kg][/tex]

d)

This part can be solved by means of the energy conservation theorem, where the potential energy is transformed into kinetic energy or vice versa.

[tex]E_{pot}=m*g*h = E_{kin}=0.5*m*v^{2}[/tex]

where:

h = elevation = 4.7 [m]

v = velocity [m/s]

[tex]m*g*h=0.5*m*v^{2}\\g*h=0.5*v^{2} \\v=\sqrt{\frac{g*h}{0.5} } \\v=\sqrt{\frac{9.81*4.7}{0.5} } \\v = 9.6 [m/s][/tex]

Answer:

When i do exercise i feel great and happy afterwards ( there is a proven fact that after you go on a run, play a sport, or exercise you are proven to be more upbeat )

When i don't exercise i feel kinda lazy and tired mostly bored.

Answer:

This is very true

Explanation:

The force from impact can easily change it to expanse in a different direction.

I hope this helped you very much :)

Answer:

5 newtons

Explanation:

Just divide them

Answer:

ok followed!

Explanation:

Answer:

 Q = 4 Q₀

Explanation:

This is an exercise on capacitors, where the capacitance is

         C =  [tex]\epsilon_{o} \ \frac{A}{d}[/tex]

if we apply the given conditions

         C = \epsilon_{o} \    \frac{2A}{0.5d}

         C = 4 \epsilon_{o} \    \frac{A}{d}

let's call the capacitance Co with the initial values

         C₀ = \epsilon_{o} \    \frac{A}{d}

         C = 4 C₀

The charge on each plate of a capacitor is

           Q = C ΔV

If the potential difference is maintained, the new charge is

       Q = 4 C₀ ΔV

let's call

        Q₀ = C₀ ΔV

we substitute

        Q = 4 Q₀

Answer:

i think b

Explanation:

Answer:

Explanation:

Step one:

Given data

work-done in dragging the trash= 236J

applied force= 18.9N

distance moved= 24.4m

Required

The angle of the applied force

Step two:

We know that work done is

WD= F * distance

The work is the product of the horizontal component of the force and the distance.

Horizontal force = 236 ÷ 24.4

= 9.67 N

Cos θ = Horizontal force ÷ Actual force

Cos θ = (236 ÷ 24.4) ÷ 18.9 = 236 ÷ 461.16

The angle is approximately 59˚

Answer:

85.77 m

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 41 m/s

Final velocity (v) = 0 m/s (at maximum height)

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (h) =?

The maximum height reached by the ball can be obtained as follow:

v² = u² – 2gh (since the ball is going against gravity)

0² = 41² – (2 × 9.8 × h)

0 = 1681 – 19.6h

Collect like terms

0 – 1681 = –19.6h

–1681 = –19.6h

Divide both side by –19.6

h = –1681 / –19.6

h = 85.77 m

Thus, the maximum height reached by the ball is 85.77 m