The four consecutive odd integers
If the first integer is given to be x
Then the next three are:
x + 2, x+ 4 and x+ 6
The sum of the second and forth integers :
x+2 + x+ 6 = 2x + 8
Hence, the sum of the second and forth integers are: 2x+8
find the first term when the 31st 32nd and 33rd are 1.40, 1.55, and 1.70
jadeymae06, this is the solution:
This is an arithmetic sequence, where d (common difference) = 0.15
(1.70 - 1.55) or (1.55 - 1.40)
•
,• a + 30d = 1.40
,• a + 30(0.15) = 1.4
,• a + 4.5 = 1.4
,• a = 1.4 - 4.5
,• a = -3.1
Jade, the first term is -3.1
Where can I find L1 and L4 for a missing vertical angles?
The vertical angle theorem states that the opposite angles formed by two lines that intersect each other are always equal to each other.
Then, if we apply this to the figure shown we can say that by the vertical angle theorem
[tex]\begin{gathered} L1=L3 \\ L2=L4 \\ Meaning\colon \\ L1=45.5 \\ L4=134.5 \end{gathered}[/tex]John recently purchased $4,106.00 worth of a stock that is expected to grow in value by 8% each year for the next ten years.Assuming this growth forecast holds, which function will show the value of John's stock in tyears?A(t) = 1.08(54,106)A(O) = 54,106(1.1)A(0) = 54,106(1.08)A(t) = $4,106(1.08)
The exponential growth formula:
[tex]A(t)=A_0(1+r)^t[/tex]Given:
[tex]\begin{gathered} A_0=\text{ \$4106} \\ t=10yrs \\ r=8\%=\frac{8}{100}=0.08 \end{gathered}[/tex]Therefore,
[tex]A(t)=4106(1+0.08)^t=4106(1.08)^t[/tex]Hence, the answer is
[tex]A(t)=\text{ \$}4106(1.08)^t[/tex]what number is divisible by 5 ? 86,764,670,or27
The number divisible by 5 is 670.
Numbers divisible by 5 have their last digits as 0 or 5
Answer : 670
What is the answer to 3/8 + 7 5/8
Given the Addition:
[tex]\frac{3}{8}+7\frac{5}{8}[/tex]You can find the sum as follows:
1. Covert the Mixed Number to an Improper Fraction:
- Multiply the Whole Number part by the denominator of the fraction.
- Add the result to the numerator.
- The denominator does not change.
Then:
[tex]7\frac{5}{8}=\frac{5+(7\cdot8)}{8}=\frac{5+56}{8}=\frac{61}{8}[/tex]2. Rewrite the Addition:
[tex]=\frac{3}{8}+\frac{61}{8}[/tex]3. Since the denominators are equal, you only need to add the numerators:
[tex]=\frac{3+61}{8}=\frac{64}{8}[/tex]4. Simplifying the fraction, you get:
[tex]=8[/tex]Hence, the answer is:
[tex]=8[/tex]One Sunday night, the Celluloid Cinema sold $ 1,585.75 in tickets. If the theater sold a children's ticket for $ 7.7S and an adult ticket for $ 10.25, a) write an equation to represent this situation. b) If the theater sold 75 children's tickets, solve your equation to find the number of adult tickets.
Answer:
98 adult tickets
Explanation:
Part A
Let the number of children's ticket sold = c
Let the number of adult's ticket sold = a
Cost of a children's ticket = $7.75
Cost of an adult's ticket = $10.25
Total income from ticket sales = $1,585.75
An equation to represent this situation is:
[tex]7.75c+10.25a=1585.75[/tex]Part B
If the number of children's ticket sold, c = 75
Then:
[tex]\begin{gathered} 7.75c+10.25a=1585.75 \\ 7.75(75)+10.25a=1585.75 \\ 581.25+10.25a=1585.75 \\ 10.25a=1585.75-581.25 \\ 10.25a=1004.50 \\ \frac{10.25a}{10.25}=\frac{1004.50}{10.25} \\ a=98 \end{gathered}[/tex]The number of adult tickets sold by the cinema is 98.
Zales sells diamonds for $1,100 that cost $800. What is Zales’s percent markup on selling price? Check the selling price.
Zales's percent markup on the selling price as required in the task content is; 37.5%.
Percentages and markup priceIt follows from the task content that the percent markup on the selling price be determined according to the given data.
Since the cost of diamonds is; $800 while the diamonds sell for $1,100. It follows that the markup on the selling price of the diamonds is;
Markup = Selling price - Cost price.
Hence, we have;
Markup = 1,100 - 800.
Therefore, the markup is; $300.
On this note, the percent markup can be determined as follows;
= (300/800) × 100%.
= 37.5%.
Ultimately, the percent markup on the diamonds is: 37.5%.
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11. Jarrod's favorite movie is now on video at 15% off the originalprice. If he pays $17, what was the original price?
original price = x
discount = 15%
price after discount = $17
Write an equation:
x (1-15/100) = 17
x (1-0.15 ) = 17
0.85x = 17
Solve for x:
x = 17/0.85
x = $20
write the expression using exponents 7•7•7•7•7•7• (–3)•(–3)•(–3)•(–3)
We have the number 7 multiplying itself 6 times, and the number (-3) multiplying itself 5 times, so writing the expression using exponents, we have:
[tex]\begin{gathered} 7\cdot7\cdot7\cdot7\cdot7\cdot7=7^6 \\ (-3)\cdot(-3)\cdot(-3)\cdot(-3)\cdot(-3)=(-3)^5 \\ \\ 7\cdot7\cdot7\cdot7\cdot7\cdot7\cdot(-3)\cdot(-3)\cdot(-3)\cdot(-3)\cdot(-3)=7^6\cdot(-3)^5 \end{gathered}[/tex]So the final expression is 7^6 * (-3)^5
Greg is ordering tile for a floor he is installing. The owner picks out tile that is 16in by 16in including the grout . The floor is 350 sq ft . (part 1) How many tile must Greg order for the floor ( assume no waste)(part 2) Each tile cost $ 1.75 plus 8% sales tax . How will the tile cost ?
ANSWER
(part 1) 196 tiles
(part 2) $ 1.89
EXPLANATION
(part 1)
First we have to find the area of each tile, that is the product of the dimensions because it is a rectangle,
[tex]A_{\text{tile}}=16in\cdot16in=256in^2[/tex]To compare it to the floor's area, we have to transform it into square feet. Knowing that 1 ft² = 144 in²,
[tex]256in^2\cdot\frac{1ft^2}{144in^2}=\frac{16}{9}ft^2[/tex]This is a partial result, so it is best if we leave it as a fraction so we don't miss any decimals.
Now, the area of the floor is 350 ft². To find how many tiles Greg has to order, we have to divide the area of the floor by the area of each tile,
[tex]\#tiles=\frac{A_{\text{floor}}}{A_{\text{tile}}}=\frac{350ft^2}{\frac{16}{9}ft^2}=196.875[/tex]But the number of tiles has to be an integer. If Greg buys 197 tiles they will have to cut some (waste). If he buys 196 there will be some of the floor not covered. However we were asked to assume no waste, so Greg will have to order 196 tiles.
(part 2)
To answer this question we have to add 8% to the cost of the tile. The 8% of 1.75 is,
[tex]1.75\cdot\frac{8}{100}=0.14[/tex]So the cost of each tile is,
[tex]1.75+0.14=1.89[/tex]use the second derivative test to classify the relative extrema if the test applies
Answer
The answer is:
[tex](x,f(x))=(0,256)[/tex]SOLUTION
Problem Statement
The question gives us a polynomial expression and we are asked to find the relative maxima using the second derivative test.
The function given is:
[tex](3x^2+16)^2[/tex]Method
To find the relative maxima, there are some steps to perform.
1. Find the first derivative of the function
2. Equate the first derivative to zero and solve for x.
3. Find the second derivative of the function.
4. Apply the second derivative test:
This test says:
[tex]\begin{gathered} \text{ If }a\text{ is one of the roots of the equation from the first derivative, then,} \\ f^{\doubleprime}(a)>0\to\text{There is a relative minimum} \\ f^{\doubleprime}(a)<0\to\text{There is a relative maximum} \end{gathered}[/tex]5. Find the Relative Minimum
Implementation
1. Find the first derivative of the function
[tex]\begin{gathered} f(x)=(3x^2+16)^2 \\ \text{Taking the first derivative of both sides, we have:} \\ f^{\prime}(x)=6x\times2(3x^2+16) \\ f^{\prime}(x)=12x(3x^2+16) \end{gathered}[/tex]2. Equate the first derivative to zero and solve for x.
[tex]\begin{gathered} f^{\prime}(x)=12x(3x^2+16)=0 \\ \text{This implies that,} \\ 12x=0\text{ OR }3x^2+16=0 \\ \therefore x=0\text{ ONLY} \\ \\ \text{Because }3x^2+16=0\text{ has NO REAL Solutions} \end{gathered}[/tex]This implies that there is ONLY ONE turning point/stationary point at x = 0
3. Find the second derivative of the function:
[tex]\begin{gathered} f^{\prime}(x)=12x(3x^2+16) \\ f^{\doubleprime}(x)=12(3x^2+16)+12x(6x) \\ f^{\doubleprime}(x)=36x^2+192+72x^2 \\ \therefore f^{\doubleprime}(x)=108x^2+192 \end{gathered}[/tex]4. Apply the second derivative test:
[tex]\begin{gathered} f^{\doubleprime}(x)=108x^2+192 \\ a=0,\text{ which is the root of the first derivative }f^{\prime}(x) \\ f^{\doubleprime}(a)=f^{\doubleprime}(0)=108(0)^2+192 \\ f^{\doubleprime}(0)=192>0 \\ \\ By\text{ the second derivative test,} \\ f^{\doubleprime}(0)>0,\text{ thus, there exists a relative minimum at }x=0\text{ } \\ \\ \text{ Thus, we can find the relative minimum when we substitute }x=0\text{ into the function }f(x) \end{gathered}[/tex]5. Find the Relative Minimum:
[tex]\begin{gathered} f(x)=(3x^2+16)^2 \\ \text{substitute }x=0\text{ into the function} \\ f(0)=(3(0)^2+16)^2 \\ f(0)=16^2=256 \\ \\ \text{Thus, the minimum value of the function }f(x)\text{ is }256 \\ \\ \text{The coordinate for the relative minimum for the function }(3x^2+16)^2\text{ is:} \\ \mleft(x,f\mleft(x\mright)\mright)=\mleft(0,f\mleft(0\mright)\mright) \\ \text{But }f(0)=256 \\ \\ \therefore(x,f(x))=(0,256) \end{gathered}[/tex]Since the function has ONLY ONE turning point, and the turning point is a minimum value, then THERE EXISTS NO MAXIMUM VALUE
Final Answer
The answer is:
[tex](x,f(x))=(0,256)[/tex]
Charlie buys a new car with a sticker price of $9,684. For the down payment,he trades in his old car for $1,400. He finances the balance and makes36 monthly car payments of $253. What is the total amount paid for thecar, including interest?
The total amount = 36 x 253 + 1400 = 9108 + 1400 = $10508
Therefore,
the total amount paid with interest $10508
what is the simplified ratio of 32:24
Answer:
4/3
Step-by-step explanation:
The simplest form of
32: 24
is 43
Steps to simplifying fractions
Find the GCD (or HCF) of numerator and denominator
GCD of 32 and 24 is 8
Divide both the numerator and denominator by the GCD
32 ÷ 8
24 ÷ 8
Reduced fraction:
4/3
Therefore, 32/24 simplified to lowest terms is 4/3.
Hey I need help with my homework help me find the points on the graph too please Thankyouu
Given the function:
g(x) = 3^x + 1
we are asked to plot the graph of the function.
Using the table:
x y
-2 10/9
-1 4/3
0 2
1 4
2 10
The graph:
The expomential functions have a horizontal asymptote.
The equation of the horizontal asymptote is y = 1
Horizontal Asymptote: y = 1
To find the domain is finding where the question is defined.
The range is the set of values that correspond with the domain.
Domain: (-infinity, infinity), {x|x E R}
Range: (1, infinity0, {y|y > 1}.
are f(x) and g(x) inverse functions across the domain (5, + infinity)
Given:
[tex]\begin{gathered} F(x)=\sqrt{x-5}+4 \\ G(x)=(x-4)^2+5 \end{gathered}[/tex]Required:
Find F(x) and G(x) are inverse functions or not.
Explanation:
Given that
[tex]\begin{gathered} F(x)=\sqrt{x-5}+4 \\ G(x)=(x-4)^{2}+5 \end{gathered}[/tex]Let
[tex]F(x)=y[/tex][tex]\begin{gathered} y=\sqrt{x-5}+4 \\ y-4=\sqrt{x-5} \end{gathered}[/tex]Take the square on both sides.
[tex](y-4)^2=x-5[/tex]Interchange x and y as:
[tex]\begin{gathered} (x-4)^2=y-5 \\ y=(x-4)^2+5 \end{gathered}[/tex]Substitute y = G(x)
[tex]G(x)=(x-4)^2+5[/tex]This is the G(x) function.
So F(x) and G(x) are inverse functions.
[tex]\begin{gathered} G(x)-5=(x-4)^2 \\ \sqrt{G(x)-5}=x-4 \\ x=\sqrt{G(x)-5}+4 \end{gathered}[/tex]Final Answer:
Option A is the correct answer.
andrews family spent 410 on 2 adult tickets to go to the concert. maxs family spent 375 on 3 tickets and 2 child tickets 3 how much is the adult ticket how much is a child ticket
Let 'x' represents the cost of the ticket for an adult, and 'y' be the cost of a child's ticket.
Andrew's family spend 410 on two adult tickets.
[tex]2x=410[/tex]From the above expression,
[tex]\begin{gathered} x=\frac{410}{2} \\ =205 \end{gathered}[/tex]Thus, the cost of an adult ticket is 205.
Given that the Max's family spend 375 for 3 tickes, and two of them is for childrens.
[tex]\begin{gathered} x+2y=375 \\ 205+2y=375 \\ 2y=375-205 \\ 2y=170 \\ y=\frac{170}{2} \\ y=85 \end{gathered}[/tex]Thus, the cost for tickets for the childrens is 85.
You start driving north for 5 miles, turn right, and drive east for another 12 miles. At the end of driving, what is your straight line dissonance from you r starting point?
You start driving north for 5 miles, turn right, and drive east for another 12 miles
The angle between north and east = 90
So, x is the hypotenuse of the triangle
[tex]x=\sqrt[]{5^2+12^2}=\sqrt[]{25+144}=\sqrt[]{169}=13[/tex]so, the length = 13 miles
A ball is thrown from an initial height of 6 feet with an initial upward velocity of 21 ft/s. The ball's heighth (in feet) after t seconds is given by the following,6+21 167Find all values of t for which the ball's height is 12 feet.Round your answer(s) to the hearest hundredth(If there is more than one answer, use the "or" button.)
The given expression in the question is
[tex]h=6+21t-16t^2[/tex]with the value of h given as
[tex]h=12ft[/tex]By equating both equations, we will have
[tex]\begin{gathered} 12=6+21t-16t^2 \\ 12-6-21t+16t^2=0 \\ 6-21t+16t^2=0 \\ 16t^2-21t+6=0 \end{gathered}[/tex]To find the value of t we will use the quadratic formula of
[tex]ax^2+bx+c=0[/tex]which is
[tex]\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{where} \\ a=16 \\ b=-21 \\ c=6 \end{gathered}[/tex]By substitution, we will have
[tex]\begin{gathered} t=\frac{-(-21)\pm\sqrt[]{(-21)^2-4\times16\times6}}{2\times16} \\ t=\frac{21\pm\sqrt[]{441-384}}{32} \\ t=\frac{21\pm\sqrt[]{57}}{32} \\ t=\frac{21\pm7.5498}{32} \\ t=\frac{21+7.5498}{32}\text{ or t=}\frac{21-7.5498}{32} \\ t=\frac{28.5498}{32\text{ }}\text{ or }t=\frac{13.4502}{32\text{ }} \\ t=0.89\text{ or t=0.42} \end{gathered}[/tex]Alternatively, Solving the equation graphically we will have
Therefore,
The values of t( to the nearest hundredth) t= 0.89sec or 0.42sec
Find the sum of the first nine terms of the geometric series 1 – 3 + 9 - 27+....
Hello there. To solve this question, we'll have to remember some properties about geometric series.
Given that we want the sum of
[tex]1-3+9-27...[/tex]First, we find the general term of this series:
Notice they are all powers of 3, namely
[tex]\begin{gathered} 1=3^0 \\ 3=3^1 \\ 9=3^2 \\ 27=3^3 \\ \vdots \end{gathered}[/tex]But this is an alternating series, hence the general term is given by:
[tex]a_n=\left(-3\right)^{n-1}[/tex]Since we just want the sum of the first 9 terms of this geometric series, we apply the formula:
[tex]S_n=\frac{a_1\cdot\left(1-q^n\right?}{1-q}[/tex]Where q is the ratio between two consecutive terms of the series.
We find q as follows:
[tex]q=\frac{a_2}{a_1}=\frac{\left(-3\right)^{2-1}}{\left(-3\right)^{1-1}}=\frac{-3}{1}=-3[/tex]Then we plug n = 9 in the formula, such that:
[tex]S_9=\frac{1\cdot\left(1-\left(-3\right)^9\right?}{1-\left(-3\right)}=\frac{1-\left(-19683\right)}{1+3}=\frac{19684}{4}[/tex]Simplify the fraction by a factor of 4
[tex]S_9=4921[/tex]This is the sum of the nine first terms of this geometric series and it is the answer contained in the second option.
How do I find the selling price if a store pays 3$ for a magazine. The markup is 5%
We need to find the selling price of a magazine. We know that the store pays $3 for it, and the markup is 5%.
So, we need to add 5% of the initial price to that initial price.
First, let's find:
[tex]5\%\text{ of }\$3=5\%\cdot\$3=\frac{5}{100}\cdot\$3=\frac{\$15}{100}=\$0.15[/tex]Now, adding the previous result to the initial price, we obtain:
[tex]\$3+\$0.15=\$3.15[/tex]Therefore, the selling price is $3.15.
Help me please I paid for the tutor Version of this app and it can’t fine me a tutor like I just paid 100 dollars for nothing
The Solution.
The function is increasing on the interval below:
[tex](-2.5,1)[/tex]The function is decreasing on the intervals below:
[tex](-\infty,-2.5)\cup(1,\infty)[/tex]If A and B are two random events with probabilities of P(A) = 4/9, P(B) = 2/9, P(A ∩ B) = 1/9, calculate P(B|A).a.1/4b.3/4c. 1/2d.1
Answer:
A. 1/4.
Explanation:
Given two random events A and B:
[tex]\begin{gathered} P(B|A)=\frac{P(B\cap A)}{P(A)} \\ P(B\cap A)=P(A\cap B) \end{gathered}[/tex]Substitute the given values:
[tex]P(B|A)=\frac{\frac{1}{9}}{\frac{4}{9}}=\frac{1}{9}\div\frac{4}{9}=\frac{1}{9}\times\frac{9}{4}=\frac{1}{4}[/tex]The value of P(B|A) is 1/4.
What is the distance from 7 to 0? O A. 7, because 171 = 7 Jurid O B. 7, because 171 = 7 O c. 7, because |-71 = -7 O D. -7, because [7] = -7
The distance from 7 to 0 is 7 because the absolute value of 7 is 7.
Correct Answer: A
2) A seat has a speed of 15 mph in seicher travels downstream from Greentown to Glenevon in 2/5 of an hour. It then goes back upstream from Glenevon to Colombia, which is 2 miles downstream, in 3/5 of an hour. Find the rate of the current.
Rate of the current = 5 mph
Explanations:The time taken to travel downstream from Greentown to Glenevon = 2/5 hours
The time taken to travel upstream from Glenevon to Columbia = 3/5 hours
Rate = Distance /time
Let the distance traveled = y miles
Rate of the downstream travel:
Rate = y ÷ 2/5
Rate = y x 5/2
Rate = 5y / 2
Rate of the upstream travel
Since the travel upstream from Glenevon to Columbia is 2 meters downstream:
Distance = y - 2
Rate = (y-2) ÷ 3/5
Rate = (y-2) x 5/3
Rate = 5(y-2)/3
Let the current rate be represented by k
The rate of the downstream travel will be:
15 + k = 5y/2...........(1)
The rate of the upstream movement will be:
15 - k = 5(y-2)/3............(2)
Add equations (1) and (2)
(15 + k) + (15 - k) = [5y/3] + [5(y-2)/3]
[tex]\begin{gathered} 30\text{ = }\frac{5y}{2}+\text{ }\frac{5y-10}{3} \\ 30\text{ = }\frac{15y+10y-20}{6} \\ 30(6)\text{ = 15y + 10y - 20} \\ 180\text{ = 25y - 20} \\ 180\text{ + 20 = 25y} \\ 25y\text{ = 200} \\ y\text{ = 200/25} \\ y\text{ = 8} \end{gathered}[/tex]Substitute the value of y into equation (1)
[tex]\begin{gathered} 15\text{ + k = }\frac{5y}{2} \\ 15\text{ + k = }\frac{5(8)}{2} \\ 15\text{ + k = }\frac{40}{2} \\ 15\text{ + k = 20} \\ k\text{ = 20 - 15} \\ k\text{ = 5} \end{gathered}[/tex]The rate of the current = 5 mph
Function g is a transformation of the parent function exponential function. Which statements are true about function g?
For the given function, The following are true statements:
Four units separate function g from function f.There is a y-intercept for function g. (0,4)Function g has a range of (3,∞ ).Over the range (-, ∞), function g is positive.It may be seen from the graph below that
The g function's graph is 4 units higher than the parent exponential function's graph.
All of the input values for which the function is defined are referred to as the function's domain. The domain of the function is (-, ∞ ) according to the graph of function g.
The location where a function's graph crosses the y-axis is known as the y-intercept. G's graph crosses the y-axis at (0, 4). As a result, the Function g's y-intercept is (0,4).
growing function g across the range (- ∞, 0).
Function output values are referred to as the function's range. It can be seen from the graph that the range of function g is (3, ∞ ).
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Kepler's third law of planetary motion states that the square of the time required for a planet to make one revolution about the sun varies directly as the cube of the average distance of the planet from the sun. If you assume that Jupiter is 5.2 times as far from the sun as is the earth, find the approximate revolution time for Jupiter in years.
Show work pls ;-;
By applying Kepler's third law of planetary motion, the approximate revolution time for Jupiter is equal to 12 years.
What is Kepler's third law?Mathematically, Kepler's third law of planetary motion is given by this mathematical expression:
T² = a³
Where:
T represents the orbital period.a represents the semi-major axis.Note: Earth has 1 astronomical unit (AU) in 1 year of time.
For this direct variation, the value of the constant of proportionality (k) is given by:
T² = ka³
k = T²/a³
k = 1²/1³
k = 1.
When the semi-major axis or the distance of Jupiter from Sun is 5.2, we have;
T² = ka³
T² = 1 × 5.2³
T² = 140.608
T = √140.608
T = 11.858 ≈ 12 years.
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Given the conversion factor which cube has the larger surface area?
Given the surface area of a cube as
[tex]\begin{gathered} SA=6l^2 \\ \text{where l is the length} \end{gathered}[/tex]Given Cubes A and B
[tex]\begin{gathered} \text{Cube A} \\ l=19.5ft \end{gathered}[/tex][tex]\begin{gathered} \text{Cube B } \\ l=6m\text{ } \\ \text{ in ft}\Rightarrow\text{ 1m =3.28ft} \\ l=6\times3.28ft=19.68ft \end{gathered}[/tex]Find the surface area of the cubes and compare them to know which one is larger
[tex]\begin{gathered} \text{Cube A} \\ SA=6\times19.5^2=6\times380.25=2281.5ft^2 \end{gathered}[/tex][tex]\begin{gathered} \text{Cube B} \\ SA=6\times19.68^2=6\times387.3024=2323.8144ft^2 \end{gathered}[/tex]Hence, from the surface area gotten above, Cube B has a larger surface area than Cube A
Solve p3 = −512.
p = ±8
p = −8
p = ±23
p = −23
Answer:
B. p = −8
Step-by-step explanation:
Hope this helps you on whatever your doing. :))
if its incorrect, please let me know.
The solution is, the value is, p = −8.
What is multiplication?In mathematics, multiplication is a method of finding the product of two or more numbers. It is one of the basic arithmetic operations, that we use in everyday life.
here, we have,
given that,
p^3 = −512.
so, we know, p^3 = p*p*p
and, 512 = 8*8*8
now, we get,
p^3 = - 8*8*8
so, solving we get,
p = -8
Hence, The solution is, the value is, p = −8.
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i need help with this question
Answer:
8%.
Step-by-step explanation:
The perimeter = 2(20 + 30)
= 100 cm.
The new perimeter = 2(20 + 0.05*20 + 30 + 30*0.10)
= 2(21 + 33)
= 2*54
= 108 cm.
Percent increases = 8%.
the output is 9 less than 5 times the input"
Let the output is y and the input is x, then
output is means y =
9 less than 5 times input means 9 less than 5x
Then
y = 5x - 9
