let the required number be x then
[tex]\begin{gathered} \frac{60}{x}\times100=40 \\ x=\frac{60}{40}\times100 \\ x=150 \end{gathered}[/tex]So 60 is 40% of 150.
What is the missing coefficient of the x-term of the product (−x−5)^2 after it has been simplified?−25−101025
Given:
The terms is
[tex](-x-5)^2[/tex]Required:
What is the missing coefficient of the x-term of the product after it has been simplified?
Explanation:
We have to find the missing coefficient of the x term of the given product
We know
[tex](a-b)^2=a^2-2ab+b^2[/tex]So,
[tex](-x-5)^2=x^2+10x+25[/tex]Therefore, the missing coefficient of the x-term is 10.
Answer:
Therefore, the missing coefficient of the x-term is 10.
Palge counted the number of items in other people's shopping carts while waiting in line at the grocery store. Palge counted the following items in seven carts: 13, 24, 17, 43, 38, 22, and 35. What is the median number of items in the shopping carts? items
ANSWER
24
EXPLANATION
The median of a data set is the middle number of the set - when they are arranged from least to greatest. If the amount of numbers in the data set is even, the median is the average of the two middle numbers.
In this case, there are 7 charts. To find the middle number we have to arrage the set from least to greatest: 13, 17, 22, 24, 35, 38, 43
The middle number is 24. This is the median.
the cone has a height of 19 mm and the radius of 15 mm what is its volume use pie and round your answer to the nearest hundredth
Answer
Volume = 4,478.57 mm³
Explanation
The volume of a cone is given as
Volume = ⅓ (πr²h)
where
π = pi = 3.142
r = radius of the cone = 15 mm
h = height of the cone = 19 mm
Volume = ?
Volume = ⅓ (πr²h)
Volume = ⅓ (3.142 × 15² × 19) = 4,478.57 mm³
Hope this Helps!!!
You are dealt one card from a 52-card deck. Find the probability that you are not dealt a card with number from 2 to 9.
The probability that we do not dealt a card with number 2 to 9 is 5/13
What is Probability?
The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty.
Given,
A pack of card = 52 cards
The Cards having Hearts = 13
The Cards having Spade = 13
The Cards having Diamond = 13
The Cards having Clubs = 13
According to question
The cards numbered from 2 to 9 are 8 cards, specifically 2, 3, 4, 5, 6, 7, 8, and 9.
But there are four suits: diamonds, hearts, spades, and clubs.
Therefore you multiply 8 by 4 to get 32
The probability of getting dealt one of those cards would be:
32/52, or
8/13
But we have to find the probability of not getting such cards
Thus,
1 - 8/13 = 5/13
Hence, the probability that you are not dealt a card with number from 2 to 9 will be 5/13
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24. How many gallons of ethanol are in a 100 gal mixture that is 10%
ethanol?
By working with percentages, we will see that there are 10 gallons of ethanol in the mixture.
How many gallons of ethanol are in the mixture?We know that we have a mixture with a volume of 100 gallons, and 10% of that mixture is ethanol, so we just need to find the 10% of 100 gallons.
To work with percentages, we will use the equation:
Volume of ethanol = total volume*ratio of ethanol.
V = 100gal*(10%/100%)
V = 100gal*0.10 = 10 gal
There are 10 gallons in the mixture.
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FIRST OPTIONS ARE THE NUMBER OF CONVERTIBLES SOLD BY PLATO CARSTHE REVENUE FROM SALES OF CONVERTIBLE CARS BY PLATO CARSTHE REVENUE FROM SALES OF SEDANS BY PLATO CARSTHE TOTAL SALES REVENUE OF PLATO CARS SECOND OPTIONS 0.1070.2250.290.33
Given:
The number in the highlighted cell is 18.
The total sales revenue of pluto cars is 80.
To find the relative frequency from the sales of sedans by Plato cars to the total sales revenue of Plato cars:
The formula for relative frequency is,
[tex]\begin{gathered} RF=\frac{subgroup\text{ fr}equency}{\text{Total frequency}} \\ =\frac{18}{80} \\ =0.225 \end{gathered}[/tex]So, the relative frequency is 0.225.
Hence, the answer is,
The number in the highlighted cell is 18. The relative frequency from the sales of sedans by Plato cars to the total sales revenue of Plato cars is 0.225
What is the slope of the line with points (3,7) and (3,-2)
Answer:
slope = 0
Given:
(3, 7)
(3, -2)
The formula for the slope is solved by the following formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]From the given, we know that:
x₁ = 3
x₂ = 3
y₁ = 7
y₂ = -2
Substituting these values to the formula, we will get:
[tex]\begin{gathered} m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ m=\frac{-2-7}{3-3} \\ m=\frac{-9}{0} \\ m=0 \end{gathered}[/tex]Therefore, the slope would be 0.
Convert the function p(x) = 2(x – 4)(x + 3)
Expanding the expression,
[tex]\begin{gathered} p(x)=2(x-4)(x+3) \\ \rightarrow p(x)=2(x^2+3x-4x-12) \\ \rightarrow p(x)=2(x^2-x-12) \\ \rightarrow p(x)=2x^2-2x-24 \end{gathered}[/tex]We get that:
[tex]p(x)=2x^2-2x-24[/tex]Use the number line to video to find two other solutions to the inequality 7 + m < 20.
Answer:
m = 2 and m = 3
Explanation:
To find the solutions to the inequality, we need to isolate m. So, we can subtract 7 from both sides as:
7 + m < 20
7 + m - 7 < 20 - 7
m < 13
Therefore, any number that is less than 13, is a solution of the inequality.
For example: 2 and 3 are solutions of the inequality.
Find the equation of the line passing through point (3,5) and with a slope ⅓
hello
we are given 1 point with x and y co-ordinate and a slope, we can easily write down the equation of the line
standard equation of a straight line is
[tex]\begin{gathered} y=mx+c \\ m=\text{slope} \\ c=\text{intercept} \end{gathered}[/tex]to solve this problem, we need to find the intercept first
substitute the x and y co-ordinates in the equation
[tex]\begin{gathered} y=mx+c \\ m=\frac{1}{3} \\ y=5 \\ x=3 \\ 5=\frac{1}{3}(3)+c \\ 5=1+c \\ c=4 \end{gathered}[/tex]we know our intercept is equal to 4 and we can proceed to write out our equation
[tex]y=\frac{1}{3}x+4[/tex]we can leave it this way or multiply through by 3
[tex]3y=x+12[/tex]3 ftFind the outer perimeter ofthis figure. Round youranswer to the nearesthundredth. Use 3.14 toapproximate .4 ft5 ft5 ftP = [ ? ] ftNotice that only half of the circle is included in the figure!Enter
Perimeter = sum of outer lengths
Lenght of the triangle sides = 5ft
perimeter of a semicircle = π d; half = π d / 2
5 ft + 5ft + π r
5 + 5 + (3.14*3) = 19.42 ft
Question 23A company's logo was designed using circles of 3 different sizes. The diameters of two of the circles are shown6 cm12 cmWhich measurement is closest to the area of the largest circle in square centimeters?D2021 Illuminate Education Inc.
SOLUTION
A company's logo was designed using circles of 3 different sizes. The diameters of two of the circles are shown:
6 cm
12 cm
Which measurement is closest to the area of the largest circle in square centimeters?
The measurement is closest to the area of the largest circle in square centimeters is
12 cm since it has a radius of 6 cm with 36 pi square centimetres; unlike the diameter
of 6 cm which has 3 cm radius and 9 pi square centimetres.
The correct answer is 12 cm.
Consider the function f (x) = x2 – 3x + 10. Find f (6).
The given function is f(x) = x^2 - 3x + 10
this means that the expression is a function of x
f(6) means replace x with 6
f(6) = (6)^2 - 3(6) + 10
f(6) = 36 - 18 + 10
f(6) = 18 + 10
f(6) = 28
The answer is 28
I got stuck and I need help on this I would appreciate the help:0
1) In this problem, we can see that this is an isosceles right triangle.
2) So, one way of solving it is to make use of the Pythagorean theorem. Note that an isosceles triangle has two congruent sides, so we can write out:
[tex]\begin{gathered} a^2=b^2+c^2 \\ b=c \\ 9^2=x^2+x^2 \\ 81=2x^2 \\ 2x^2=81 \\ \frac{2x^2}{2}=\frac{81}{2} \\ x^2=\frac{81}{2} \\ \sqrt[]{x^2}=\sqrt[]{\frac{81}{2}} \\ x=\frac{9}{\sqrt[]{2}} \end{gathered}[/tex]Usually, we rationalize it. But since the question requests the denominator to be a rational one, so this is the answer.
(2-5). (6.0)Find the midpoint
Let:
(x1,y1)=(2,-5)
(x2,y2)=(6,0)
The midpoint is given by:
[tex]\begin{gathered} xm=\frac{x1+x2}{2} \\ xm=\frac{2+6}{2} \\ xm=\frac{8}{2}=4 \\ ym=\frac{-5+0}{2}=-\frac{5}{2}=-2.5 \end{gathered}[/tex]Therefore the midpoint is:
M = (4 , -5/2) or M = (4, -2.5)
The rotation of the smaller wheel in the figure causes the larger wheel to rotate. Find the radius of the largerwheel in the figure if the smaller wheel rotates 70.0° when the larger wheel rotates 40.0°The radius of the large wheel is approximately ____ cm.
Let's begin by listing out the information given to us:
r (1) = 11.4 cm, θ (1) = 70°, θ (2) = 40°, r(2) = ?
The arc length is the same for the 2 circles
r (1) * θ (1) = r (2) * θ (2)
11.4 * 70° = r (2) * 40°
r (2) = 11.4 * 70 ÷ 40
r (2) = 19.95 cm
Hence, the radius of the larger circle is 19.95 cm
what is the line that passes through points(-6,-10)(-2,-10)
The line passes through the points, (-6,-10) and (-2,-10)
We know equation of the line passing through points (x',y') and (x'',y'') is given by:
[tex]y-y^{\prime}=\frac{y^{\prime}^{\prime^{}}-y^{\prime}}{x^{\prime}^{\prime}-x^{\prime}}(x-x^{\prime})[/tex]So the equation of the line is:
[tex]\begin{gathered} y-(-10)=\frac{-10-(-10)}{-2-(-6)_{}}(x-(-6)) \\ \Rightarrow y+10=0 \\ \Rightarrow y=-10 \end{gathered}[/tex]The equation of the line is y=-10
the sum of interior angle measures of a polygon with n sides is 2340 degrees. find n15
the measure of each angle will be 2340/n then if n=15 the measure of each one of the angles will be 2340/15=156 degrees
i invest $250 in a simple account that earns 10% annually. After 6 years, how much money have i earned? Hint round to the nearest cent.
We have to use the simple interest formula
[tex]A=P(1+rt)[/tex]Where P = 250; r = 0.10 (10%); t = 6. Replacing these values, we have
[tex]A=250(1+0.10\cdot6)=250(1+0.6)=250(1.6)=400[/tex]Hence, after 6 years, you have $400.
If we subtract this amount from the investment, we get the profits.
[tex]400-250=150[/tex]Hence, the earnings are $150.Show the steps needed to Evaluate (2)^-2
Answer:
[tex]\dfrac{1}{4}[/tex]
Step-by-step explanation:
Given expression:
[tex]2^{-2}[/tex]
[tex]\boxed{\textsf{Exponent rule}: \quad a^{-n}=\dfrac{1}{a^n}}[/tex]
Apply the exponent rule to the given expression:
[tex]\implies 2^{-2}=\dfrac{1}{2^2}[/tex]
Two squared is the same as multiplying 2 by itself, therefore:
[tex]\begin{aligned}\implies 2^{-2}&=\dfrac{1}{2^2}\\\\&=\dfrac{1}{2 \times 2}\\\\&=\dfrac{1}{4}\end{aligned}[/tex]
Solution
[tex]2^{-2}=\dfrac{1}{4}[/tex]
Answer:
1/4
Step-by-step explanation:
Now we have to,
→ find the required value of (2)^-2.
Let's solve the problem,
→ (2)^-2
→ (1/2)² = 1/4
Therefore, the value is 1/4.
what would be an equation for a decrease of 75% using the y=kx format?
Input data
75% = 0.75
format
y = kx
Procedure
The k factor would be equal to 0.25
The answer would be
[tex]y=0.25x[/tex]Determine the solution to the given equation.4 + 3y = 6y – 5
Answer:
[tex]y=3[/tex]Explanation:
Step 1. The expression we have is:
[tex]4+3y=6y-5[/tex]And we are required to find the solution; the value of y.
Step 2. To find the value of y, we need to have all of the terms that contain the variable on the same side of the equation. For this, we subtract 6y to both sides:
[tex]4+3y-6y=-5[/tex]Step 3. Also, we need all of the numbers on the opposite side that the variables are, so we subtract 4 to both sides:
[tex]3y-6y=-5-4[/tex]Step 4. Combine the like terms.
We combine the terms that contain y on the left side of the equation, and the numbers on the right side of the equation:
[tex]-3y=-9[/tex]Step 5. The last step will be to divide both sides of the equation by -3 in order to have only ''y'' on the left side:
[tex]\begin{gathered} \frac{-3y}{-3}=\frac{-9}{-3} \\ \downarrow\downarrow \\ y=3 \end{gathered}[/tex]The value of y is 3.
Answer:
[tex]y=3[/tex]The following are all 5 quiz scores of a student in a statistics course. Each quiz was graded on a 10-point scale.6, 8, 9, 6, 5,Assuming that these scores constitute an entire population, find the standard deviation of the population. Round your answer to two decimal places.
For this type of problem we use the following formula:
[tex]\begin{gathered} \sigma=\sqrt[]{\frac{\sum^{}_{}(x_i-\mu)^2}{N},} \\ \\ \end{gathered}[/tex]where μ is the population mean, xi is each value from the population, and N is the size of the population.
First, we compute the population mean in order to do that we use the following formula:
[tex]\mu=\frac{\Sigma x_i}{N}\text{.}[/tex]Substituting each value of x_i in the above formula we get:
[tex]\mu=\frac{6+8+9+6+5}{5}=\frac{34}{5}=6.8.[/tex]Now, we compute the difference of each x_i with the mean:
[tex]\begin{gathered} 6-6.8=-0.8, \\ 8-6.8=1.2, \\ 9-6.8=2.2, \\ 6-6.8=-0.8, \\ 5-6.8=-1.8. \end{gathered}[/tex]Squaring each result we get:
[tex]\begin{gathered} (-0.8)^2=0.64, \\ (1.2)^2=1.44, \\ (2.2)^2=4.84, \\ (-0.8)^2=0.64, \\ (-1.8)^2=3.24. \end{gathered}[/tex]Now, we add the above results:
[tex]0.64+1.44+4.84+0.64+3.24=10.8.[/tex]Dividing by N=5 we get:
[tex]\frac{10.8}{5}=2.16.[/tex]Finally, taking the square root of 2.16 we obtain the standard deviation,
[tex]\sigma=\sqrt[]{2.16}\approx1.47.[/tex]Answer:
[tex]\sigma=1.47.[/tex]A bicycle wheel is 63 centimeters from top to bottom . When the wheel goes all the way around one time , the bicycle travels 198 centimeters . How can this information be used to estimate the value of pi
Given :
A bicycle wheel is 63 centimeters from top to bottom .
So, the diameter of the wheel = 63 cm
When the wheel goes all the way around one time , the bicycle travels 198 centimeters .
So, the circumference of the circle = 198 cm
The circumference of the circle of diameter = d will be :
[tex]\pi\cdot d[/tex]So,
[tex]\begin{gathered} \pi\cdot63=198 \\ \\ \pi=\frac{198}{63}=\frac{22}{7} \end{gathered}[/tex]Hi! I was absent today and did not understand this lesson please I will be really grateful if you help me ! I appreciate it this is classwork assignment does not count as a test
Answer:
Given:
[tex]\begin{gathered} \sin \alpha=\frac{40}{41}first\text{ quadrant} \\ \sin \beta=\frac{4}{5},\sec ondquadrant \end{gathered}[/tex]Step 1:
Figure out the value of cos alpha
We will use the Pythagoras theorem below
[tex]\begin{gathered} \text{hyp}^2=\text{opp}^2+\text{adj}^2 \\ \text{hyp}=41,\text{opp}=40,\text{adj}=x \\ 41^2=40^2+x^2 \\ 1681=1600+x^2 \\ x^2=1681-1600 \\ x^2=81 \\ x=\sqrt[]{81} \\ x=9 \end{gathered}[/tex]Hence,
[tex]\begin{gathered} \cos \alpha=\frac{\text{adjacent}}{\text{hypotenus}} \\ \cos \alpha=\frac{9}{41} \end{gathered}[/tex]Step 2:
Figure out the value of cos beta
To figure this out, we will use the Pythagoras theorem below
[tex]\begin{gathered} \text{hyp}^2=\text{opp}^2+\text{adj}^2 \\ \text{hyp}=5,\text{opp}=4,\text{adj}=y \\ 5^2=4^2+y^2 \\ 25=16+y^2 \\ y^2=25-16 \\ y^2=9 \\ y=\sqrt[]{9} \\ y=3 \end{gathered}[/tex]Hence,
[tex]\begin{gathered} \cos \beta=\frac{\text{adjacent}}{\text{hypotenus}} \\ \cos \beta=-\frac{3}{5}(\cos \text{ is negative on the second quadrant)} \end{gathered}[/tex]Step 3:
[tex]\cos (\alpha+\beta)=\cos \alpha\cos \beta-\sin \alpha\sin \beta[/tex]By substituting the values, we will have
[tex]\begin{gathered} \cos (\alpha+\beta)=\cos \alpha\cos \beta-\sin \alpha\sin \beta \\ \cos (\alpha+\beta)=\frac{9}{41}\times-\frac{3}{5}-\frac{40}{41}\times\frac{4}{5} \\ \cos (\alpha+\beta)=-\frac{27}{205}-\frac{160}{205} \\ \cos (\alpha+\beta)=-\frac{187}{205} \end{gathered}[/tex]Hence,
The final answer = -187/205
A football team is losing by 14 points near the end of a game. The team scores two touchdowns (worth 6 points each) before the end of the game. After each touchdown, the coach must decide whether to go for 1 point with a kick (which is successful 99% of the time) or 2 points with a run or pass (which is successful 45% of the time). If the team goes for 1 point after each touchdown, what is the probability that the coach’s team wins? loses? ties? If the team goes for 2 points after each touchdown, what is the probability that the coach’s team wins? loses? ties? Can you develop a strategy so that the coach’s team has a probability of winning the game that is greater than the probability of losing
His football team is losing 14 points near the end of the game. The team scores two touchdowns with each worth 6 points (total = 12 points).
After each touchdown, the coach must decide whether to go for 1 point with each kick(99% successful) or 2 points with a run or pass(45% successful).
Note
Two touchdown = 12 points
So, it remaining 2 point to level up and more than 2 points to win the game
a.
If the team goes for 1 point after each touchdown, the probability that the coach's team loses? wins? ties? can be computed below
[tex]undefined[/tex]Consider the following graph. Determine the domain and range of the graph? Is the domain and range all real numbers?
ANSWER
Domain = [-10, 10]
Range = [4]
EXPLANATION
Domain of a graph is the set of all input values on x-axis; while
Range is the set of all possible output values on y-axis.
Determining the Domain from the given graph,
The set of all INPUT values on x-axis are -10, -9, -8,....0......5,6,7,8,9,10.
So the Domain = [-10, 10].
Determining the Range from the given graph,
For the set of all possible OUTPUT values on y-axis, we only have 4,
So the Range = [4]
Hence, Domain = [-10, 10] and Range = [4]
Solve each equation for the given variable.-2x + 5y = 12 for ySolve each equation for y. Then find the value of y for each value if x.y + 2x = 5; x = -1, 0, 3
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
-2x + 5y = 12
y = ?
Step 02:
We must apply algebraic rules to find the solution.
-2x + 5y = 12
5y = 12 + 2x
y = 12 / 5 + 2x / 5
[tex]y\text{ =}\frac{12}{5}\text{ + }\frac{2x}{5}[/tex]The answer is:
y = 12 / 5 + 2x / 5
Draw the graph of the line that is parallel to Y -3 = 1/3(x+2) and goes through the point (1, 7)
Explanation:
We are required to draw the graph of the line that is parallel to y-3=1/3(x+2) and goes through the point (1, 7).
Given the equation of the line:
[tex]y-3=\frac{1}{3}(x+2)[/tex]Compare the equation with the slope-point form of a line:
[tex]$$y-y_1=m(x-x_1)$$[/tex]• The slope of the line, m=1/3
,• In addition, the line goes through the point (1,7)
Substitute these values into the point-slope form given above:
[tex]y-7=\frac{1}{3}(x-1)[/tex]Finally, graph the line by looking for another point in addition to point (1,7):
When x=-2
[tex]\begin{gathered} y-7=\frac{1}{3}(x-1) \\ y-7=\frac{1}{3}(-2-1) \\ y-7=\frac{1}{3}(-3) \\ y-7=-1 \\ y=-1+7 \\ y=6 \\ \implies(-2,6) \end{gathered}[/tex]Join the points (1, 7) and (-2, 6) to plot the line.
Answer:
The graph showing the two points is attached below:
Note:
For comparison purposes and to show that the two lines are parallel, the other graph is added below:
Estimate. Then find the quotient. Round to the nearest thousandth.24.752:6Estimate=Quotient =
Estimate = 4.13
Quotient = 4.12533333
To the nearest thousand 4.12533
