q(v)= int 0 ^ v^ prime sqrt 4+w^ 5 dw ther; q^ prime (v)=

Q(v)= Int 0 ^ V^ Prime Sqrt 4+w^ 5 Dw Ther; Q^ Prime (v)=

Answers

Answer 1

ANSWER

[tex]q^{\prime}(v)=\sqrt{4+(v^7)^5}[/tex]

EXPLANATION

We want to find the derivative of the given function:

[tex]q(v)=\int_0^{v7}\sqrt{4+w^5}dw[/tex]

When the lower limit of an integral is a constant and the upper limit of the integral is a variable, the derivative of this is the function inside the integral in terms of the upper limit of the integral.

In other words, the derivative of the given integral function is:

[tex]q^{\prime}(v)=\sqrt{4+(v^7)^5}[/tex]

That is the answer.


Related Questions

I need help doing this it’s the homework but I need to understand it for the test

Answers

By similar triangle, we have:

[tex]\begin{gathered} Let\text{ the unknown measurement be x} \\ \text{Thus, we have:} \\ \frac{14}{x}=\frac{8}{15} \\ \text{cross}-\text{multiply} \\ 8x=210 \\ x=\frac{210}{8} \\ x=26.25\text{ f}eet \end{gathered}[/tex]

Hence, the unknown measurement of the plan is 26.25 feet

The following are all 5 quiz scores of a student in a statistics course. Each quiz was graded on a 10-point scale.6, 8, 9, 6, 5,Assuming that these scores constitute an entire population, find the standard deviation of the population. Round your answer to two decimal places.

Answers

For this type of problem we use the following formula:

[tex]\begin{gathered} \sigma=\sqrt[]{\frac{\sum^{}_{}(x_i-\mu)^2}{N},} \\ \\ \end{gathered}[/tex]

where μ is the population mean, xi is each value from the population, and N is the size of the population.

First, we compute the population mean in order to do that we use the following formula:

[tex]\mu=\frac{\Sigma x_i}{N}\text{.}[/tex]

Substituting each value of x_i in the above formula we get:

[tex]\mu=\frac{6+8+9+6+5}{5}=\frac{34}{5}=6.8.[/tex]

Now, we compute the difference of each x_i with the mean:

[tex]\begin{gathered} 6-6.8=-0.8, \\ 8-6.8=1.2, \\ 9-6.8=2.2, \\ 6-6.8=-0.8, \\ 5-6.8=-1.8. \end{gathered}[/tex]

Squaring each result we get:

[tex]\begin{gathered} (-0.8)^2=0.64, \\ (1.2)^2=1.44, \\ (2.2)^2=4.84, \\ (-0.8)^2=0.64, \\ (-1.8)^2=3.24. \end{gathered}[/tex]

Now, we add the above results:

[tex]0.64+1.44+4.84+0.64+3.24=10.8.[/tex]

Dividing by N=5 we get:

[tex]\frac{10.8}{5}=2.16.[/tex]

Finally, taking the square root of 2.16 we obtain the standard deviation,

[tex]\sigma=\sqrt[]{2.16}\approx1.47.[/tex]

Answer:

[tex]\sigma=1.47.[/tex]

FIRST OPTIONS ARE THE NUMBER OF CONVERTIBLES SOLD BY PLATO CARSTHE REVENUE FROM SALES OF CONVERTIBLE CARS BY PLATO CARSTHE REVENUE FROM SALES OF SEDANS BY PLATO CARSTHE TOTAL SALES REVENUE OF PLATO CARS SECOND OPTIONS 0.1070.2250.290.33

Answers

Given:

The number in the highlighted cell is 18.

The total sales revenue of pluto cars is 80.

To find the relative frequency from the sales of sedans by Plato cars to the total sales revenue of Plato cars:

The formula for relative frequency is,

[tex]\begin{gathered} RF=\frac{subgroup\text{ fr}equency}{\text{Total frequency}} \\ =\frac{18}{80} \\ =0.225 \end{gathered}[/tex]

So, the relative frequency is 0.225.

Hence, the answer is,

The number in the highlighted cell is 18. The relative frequency from the sales of sedans by Plato cars to the total sales revenue of Plato cars is 0.225

A hairdresser is considering ordering a certain shampoo.  Company A charges $5 per 8 ounce bottle plus a $5 handling fee per order.  Company B charges $2 per 8 ounce bottle plus a $23 handling fee per order.  How many bottles must the hairdresser buy to justify using Company B?

Answers

For the shampoo:

Company A charges $5 per ounce bottle + $5 handling fee.

Company B charges $2 per ounce bottle + $23 handling fee.

Let C represent the total cost for the shampoo and x represent the number of bottles of shampoo then you can express the total cost for both companies as equations:

[tex]\begin{gathered} C_A=5x+5 \\ C_B=8x+23 \end{gathered}[/tex]

For the hairdresser to justify using the shampoo of company C, the cost must be less than for company A, so that:

[tex]\begin{gathered} C_BNow

Complete the steps to find the value of x .

Answers

Set 128 and 2x to be equal to each other and solve for x which is 64

Basically, the question is asking to solve a problem about rectangular prisms. It says the the shape of one box, with (h) height in feet, has a volume defined by the function:V(h) = h (h-5)(h-6)It says to graph the function. What is the maximum volume for the domain 0

Answers

The function representing the volume of the rectangular prism is given to be:

[tex]V(h)=h(h-5)(h-6)[/tex]

Since we are expected to find the volume using the graph, we can prepare a table of values for the function using values of h as integers from 1 - 5, such that:

[tex]\begin{gathered} At\text{ }h=1 \\ V(1)=1(1-5)(1-6)=-4\times-5=20 \end{gathered}[/tex]

The completed table is shown below:

Hence, we can plot these points on a graph using a graphing calculator for ease of work. This is shown below:

The maximum volume of the prism is represented by the highest point on the graph. The graph's highest point is at:

[tex]h=1.811[/tex]

The corresponding value for the volume as can be seen on the graph is:

[tex]V=24.193[/tex]

This is the maximum volume of the prism.

To the nearest cubic foot, the maximum volume of the rectangular prism is 24 cubic feet.

what is the area of a triangle with the legth of 8in,12in,6in

Answers

Area is

[tex]A=\frac{1}{2}bh=\frac{1}{2}\times6\times8=\frac{48}{2}=24[/tex]

answer: 24 sq in

Find the minimum or maximum value of the function f(x)=8x2+x−5. Give your answer as a fraction.

Answers

Answer

Minimum value of the function = (-41/8)

Explanation

The minimum or maximum of a function occurs at the turning point of the graph of the function.

At this turning point, the first derivative of the function is 0.

The second derivative of the function is positive when the function is at minimum and it is negative when the function is at maximum.

f(x) = 8x² + 2x - 5

(df/dx) = 16x + 2

At minimum or maximum point,

16x + 2 = 0

16x = -2

Divide both sides by 16

(16x/16) = (-2/16)

x = (-1/8)

Second derivative

f(x) = 8x² + 2x - 5

(df/dx) = 16x + 2

(df²/d²x) = 16 > 0, that is, positive.

So, this point is a minimum point.

f(x) = 8x² + 2x - 5

f(-1/8) = 8(-1/8)² + 2(-1/8) - 5

= 8 (1/64) - (1/4) - 5

= (1/8) - (1/4) - 5

= (1/8) - (2/8) - (40/8)

= (1 - 2 - 40)/8

= (-41/8)

Hope this Helps!!!

Estimate. Then find the quotient. Round to the nearest thousandth.24.752:6Estimate=Quotient =

Answers

Estimate = 4.13

Quotient = 4.12533333

To the nearest thousand 4.12533

How do I simplify 5 8/48

Answers

Given:

[tex]5\frac{8}{48}[/tex][tex]5\frac{8}{48}=\frac{248}{48}[/tex][tex]5\frac{8}{48}=\frac{31}{6}[/tex][tex]5\frac{8}{48}=5.1667[/tex]

focus on the fraction
what can divide into 8 and 48
if you need to you can do small numbers like 2
but you can divide 4 and 8
you don’t have to worry about 5 because that a whole number so pretend that’s not that there until you break down the fraction till you can’t anymore
once you can’t break down the fraction anymore and the 5 back
hope this helped

Created by Cortin Lyons riables on Both Sides #3 2.12r – 14 = 8x + 16 12x – 14 = 6x + 16 as with Distributive Property

Answers

Problem N 2

we have

12x-14=8x+16

solve for x

subtract 8x both sides

12x-14-8x=8x+16-8x

4x-14=16

Adds 14 both sides

4x-14+14=16+14

4x=30

divide by 4 both sides

x=30/4

x=7.5

Problem N 4

we have

12x-14=6x+16

solve for x

subtract 6x both sides

12x-14-6x=6x+16-6x

6x-14=16

adds 14 both sides

6x=16+14

6x=30

divide by 6 both sides

x=30/6

x=5

Draw the graph of the line that is parallel to Y -3 = 1/3(x+2) and goes through the point (1, 7)

Answers

Explanation:

We are required to draw the graph of the line that is parallel to y-3=1/3(x+2) and goes through the point (1, 7).

Given the equation of the line:

[tex]y-3=\frac{1}{3}(x+2)[/tex]

Compare the equation with the slope-point form of a line:

[tex]$$y-y_1=m(x-x_1)$$[/tex]

• The slope of the line, m=1/3

,

• In addition, the line goes through the point (1,7)

Substitute these values into the point-slope form given above:

[tex]y-7=\frac{1}{3}(x-1)[/tex]

Finally, graph the line by looking for another point in addition to point (1,7):

When x=-2

[tex]\begin{gathered} y-7=\frac{1}{3}(x-1) \\ y-7=\frac{1}{3}(-2-1) \\ y-7=\frac{1}{3}(-3) \\ y-7=-1 \\ y=-1+7 \\ y=6 \\ \implies(-2,6) \end{gathered}[/tex]

Join the points (1, 7) and (-2, 6) to plot the line.

Answer:

The graph showing the two points is attached below:

Note:

For comparison purposes and to show that the two lines are parallel, the other graph is added below:

3 ftFind the outer perimeter ofthis figure. Round youranswer to the nearesthundredth. Use 3.14 toapproximate .4 ft5 ft5 ftP = [ ? ] ftNotice that only half of the circle is included in the figure!Enter

Answers

Perimeter = sum of outer lengths

Lenght of the triangle sides = 5ft

perimeter of a semicircle = π d; half = π d / 2

5 ft + 5ft + π r

5 + 5 + (3.14*3) = 19.42 ft

What are the first two steps to graph y=4/5x + 3?

Answers

The function y=4/5x + 3 represents a linear equation.

Let's find some points.

Where x=1, then:

[tex]y=\frac{4}{5}x+3[/tex][tex]y=\frac{4}{5}(1)+3[/tex][tex]y=\frac{19}{5}[/tex]

We find the point (1,19/5).

Where 19/5 = 3.8

Now, lest find the x-intercept and y-intercept.

To find the x-intercept, set y=0

[tex]0=\frac{4}{5}x+3[/tex]

Solve for x:

[tex]-3=\frac{4}{5}x[/tex][tex]5\cdot-3=4x[/tex][tex]-15=4x[/tex]

where

[tex]x=-\frac{15}{4}=-3.75[/tex]

So, the x-intercept is the point (-15/4, 0)

To find the y-intercept, set x=0. Then:

[tex]y=\frac{4}{5}x+3[/tex][tex]y=\frac{4}{5}(0)+3[/tex][tex]y=3[/tex]

So, the y-intercept is the point (0,3)

Use this information to graph the line.

Hence, the graph for y=4/5x + 3 is given by:

A contractor has submitted bids on three state jobs: an office building, a theater, and a parking garage. State rules do not allow a contractor to be offered more than one of these jobs. If this contractor is awarded any of these jobs, the profits earned from these contracts are: 13 million from the office building, 9 million from the theater, and 4 million from the parking garage. His profit is zero if he gets no contract. The contractor estimates that the probabilities of getting the office building contract, the theater contract, the parking garage contract, or nothing are .17, .27, .45, and .11, respectively. Let x be the random variable that represents the contractor's profits in millions of dollars. Write the probability distribution of x. Find the mean and standard deviation of x.

Answers

Answer:

Probability distribution:

x (million) P(x)

13 0.17

9 0.27

4 0.45

0 0.11

Mean: 6.44

Standard deviation: 4.04

Explanation:

The probability distribution is a table that shows the profits earned and its respective probabilities, so:

x (million) P(x)

13 0.17

9 0.27

4 0.45

0 0.11

Then, the mean can be calculated as the sum of each profit multiplied by its respective probability. Therefore, the mean E(x) is equal to:

E(x) = 13(0.17) + 9(0.27) + 4(0.45) + 0(0.11)

E(x) = 2.21 + 2.43 + 1.8 + 0

E(x) = 6.44

Finally, to calculate the standard deviation, we first need to find the differences between each value and the mean, and then find the square of these values, so:

x x - E(x) (x - E(x))²

13 13 - 6.44 = 6.56 (6.56)² = 43.03

9 9 - 6.44 = 2.56 (2.56)² = 6.55

4 4 - 6.44 = -2.44 (-2.44)² = 5.95

0 0 - 6.44 = -6.44 (-6.44)² = 41.47

Then, the standard deviation will be the square root of the sum of the values in the last column multiply by each probability:

[tex]\begin{gathered} s=\sqrt[]{43.03(0.17)+6.55(0.27)+5.95(0.45)+41.47(0.11)} \\ s=\sqrt[]{16.3264} \\ s=4.04 \end{gathered}[/tex]

Therefore, the answers are:

Probability distribution:

x (million) P(x)

13 0.17

9 0.27

4 0.45

0 0.11

Mean: 6.44

Standard deviation: 4.04

#Classify each number as a natural number, a whole number, or an integer.
If a number belongs to more than one set, list all possible sets it belongs to.
a) 1
b) -20
c) -3

Answers

(a) Whole number and integer

(b) Negative integer

(c) Negative integer

What are whole numbers an integers?

Positive, negative, and zero numbers all fall under the category of integers. The word "integer" is a Latin word that signifies "whole" or "intact." Therefore, fractions and decimals are not considered to be integers. A number line is a graphic representation of positive and negative integers. The use of integers on a number line facilitates mathematical procedures. The right-side number is always greater than the left-side number. Due to the fact that they are greater than 0, positive numbers are positioned to the right of zero. All natural numbers and 0 are included in a group of numbers known as whole numbers. They belong to the category of real numbers, which excludes fractions, decimals, and negative numbers. Numbers used for counting are also regarded as whole numbers.

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If two lines intersect and one of the angles formed has a measure of 67°, which of the following statements are true? Explain your answers.

Answers

Intersecting Lines

When two lines intersect, four angles are formed at the point of intersection.

Two pairs of angles are vertical, i.e., they have the same measure.

Two pairs of angles are complementary (or linear) therefore their sum adds up to 180°.

We are given one of the angles that has a measure of 67°.

Then, another angle also measures 67° (the vertical peer).

One of the other angles is 180° - 67° = 113°

The other angle also measures 113° (the other vertical peer).

According to the facts found above, the following statements are true:

* Vertical angles are congruent, therefore another angle must equal 67°

* The lines form linear pairs

* The lines form complementary angles

* Two of the angles formed measure 113°

* Two of the angles formed will have a sum of 180°

Note: The last statement should read "Two pairs of angles formed..."

the cone has a height of 19 mm and the radius of 15 mm what is its volume use pie and round your answer to the nearest hundredth

Answers

Answer

Volume = 4,478.57 mm³

Explanation

The volume of a cone is given as

Volume = ⅓ (πr²h)

where

π = pi = 3.142

r = radius of the cone = 15 mm

h = height of the cone = 19 mm

Volume = ?

Volume = ⅓ (πr²h)

Volume = ⅓ (3.142 × 15² × 19) = 4,478.57 mm³

Hope this Helps!!!

I got stuck and I need help on this I would appreciate the help:0

Answers

[tex]x=\frac{9}{\sqrt[]{2}}[/tex]

1) In this problem, we can see that this is an isosceles right triangle.

2) So, one way of solving it is to make use of the Pythagorean theorem. Note that an isosceles triangle has two congruent sides, so we can write out:

[tex]\begin{gathered} a^2=b^2+c^2 \\ b=c \\ 9^2=x^2+x^2 \\ 81=2x^2 \\ 2x^2=81 \\ \frac{2x^2}{2}=\frac{81}{2} \\ x^2=\frac{81}{2} \\ \sqrt[]{x^2}=\sqrt[]{\frac{81}{2}} \\ x=\frac{9}{\sqrt[]{2}} \end{gathered}[/tex]

Usually, we rationalize it. But since the question requests the denominator to be a rational one, so this is the answer.

A 6000-seat theater has tickets for sale at $24 and $40. How many tickets should be sold at each price for a sellout performance to generate a total revenue
of $168,000?
The number of tickets for sale at $24 should be ?

Answers

The number of tickets which should be sold to $24 and $40 are 4500 and 1500 respectively.

Given, A 6000-seat theater has tickets for sale at $24 and $40.

How many tickets should be sold at each price for a sellout performance to generate a total revenue of $168,000 = ?

first, assign variables:

X = # of $24 tickets,  Y = # or $40 tickets

write equations based on the data presented:

"6000 seat theater..."

   X + Y = 6000 ...equation 1

"total revenue of 168,000"

The revenue from each type of ticket is the cost times the number sold, so:

  24X + 40Y = 168,000 .....equation 2

from equation 1:

   X = 6000 - Y

substitute this into equation 2:   (replace X with 6000-Y)

   24 (6000 - Y) + 40Y = 168,000

expand:

144,000 -24Y + 40Y = 168,000

rearrange and simplify:

    16Y = 168,000 - 144,000

    y = 24000/16

     Y = 1500

from equation 1:

     X = 6000 - 1500

     X = 4500

hence the number of tickets for sale at $24 should be 4500.

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Help please I’ll give 10 points

Answers

The writing of the symbols, <, =, or > in each of the comparison (equality or inequality) statements is as follows:

1. 0.02 > 0.002

2. 0.05 < 0.5

3. 0.74 < 0.84

4. 0.74 > 0.084

5. 1.2 < 1.25

6. 5.130 = 5.13

7. 3.201 > 3.099

8. 0.159 < 1.590

9. 8.269 > 8.268

10. 4.60 > 4.060

11. 302.026 > 300.226

12. 0.237 > 0.223

13. 3.033 < 3.303

14. 9.074 < 9.47

15. 6.129 < 6.19

16. 567.45 > 564.75

17. 78.967 > 7.957

18. 5.346 < 5.4

19. 12.112 < 12.121

20. 26.2 = 26.200

21. 100.32 > 100.232

22) The strategy for solving comparison mathematical statements is to check the place values.

What is a place value?

A place value is a numerical value that a digit possesses because of its position in a number.

To find a digit's place value, discover how many places the digit is to the right or left of the decimal point in a number.

Some of the place values before the decimal place include Millions, Hundred Thousands, Ten Thousands, Thousands, Hundreds, Tens, and Units.

After the decimal place, the place values are tenths, hundredths, thousandths, ten thousandths, hundred thousandth, and millionths.

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Write a division equation that represents the equation, How many 3/4 are in 10/9?

Answers

Given:

The number of 3/4 in 10/9.

To find the division equation that represents the given problem:

That is a number that is multiplied by 3/4 to obtain 10/9.

We need to find the number.

[tex]x\times\frac{3}{4}=\frac{10}{9}[/tex]

Thus, the division equation will be,

[tex]x=\frac{10}{9}\div\frac{3}{4}[/tex]

t, Decimal, Fractions a. 100 is what percent of 80? = 125% b. What is 1/20 as a decimal? What is that decimal as a percent? –5%

Answers

Explanation

Step 1

a) 100 is what percent of 80?

you can solve this by using a rule of three

Let

x represents the percent

then

[tex]undefined[/tex]

Which of the following is equal to - 7/4w expressed as a linear combination of vectors, if W= -1/2i- 3/2j?

Answers

[tex]w=-\frac{1}{2}i-\frac{3}{2}j[/tex]

Therefore, the scalar multiplication of vector -7/4 w is given by

[tex]-\frac{7}{4}w=-\frac{7}{4}(-\frac{1}{2}i-\frac{3}{2}j)[/tex][tex]=\frac{7}{8}i+\frac{21}{8}j[/tex]

Hence, the linear combination is 7/8 i + 21/8 j

Need help with a math word problem for homework. Thank you in advance

Answers

Given:

A client is making a 10-lb bag of trail mix

The chocolates cost $4 per pound and mixed nuts cost $7 per pound

the client has a budget of $6.1 per pound

We will use the variables c and n to represent the number of pounds for chocolates and nuts

So, we have the following system of equations:

[tex]\begin{gathered} c+n=10\rightarrow(1) \\ 4c+7n=6.1\cdot10\rightarrow(2) \end{gathered}[/tex]

Solving the system by substitution method

From equation (1)

[tex]c=10-n\rightarrow(3)[/tex]

substitute with (c) from equation (3) into equation (2)

[tex]\begin{gathered} 4(10-n)+7n=6.1\cdot10 \\ \end{gathered}[/tex]

solve the equation to find (n)

[tex]\begin{gathered} 4\cdot10-4n+7n=6.1\cdot10 \\ -4n+7n=6.1\cdot10-4\cdot10 \\ 3n=21 \\ n=\frac{21}{3}=7 \end{gathered}[/tex]

Substitute with (n) into equation (3) to find (c)

[tex]c=10-7=3[/tex]

so, the answer will be:

The number of pounds of chocolates = c = 3 pounds

The number of pounds of nuts = n = 7 pounds

7. f(x) = x² + 4 (a) f(-2) (b) f(3) f) f (c) f(2) (d) f(x + bx)

Answers

[tex]\begin{gathered} a)\text{ 2}\sqrt[]{2} \\ b)\text{ }\sqrt[]{13} \\ c)\text{ 2}\sqrt[]{2} \\ d)\text{ }\sqrt[]{x^2(1+2b+b^2)+4}\text{ } \end{gathered}[/tex]Explanation:[tex]f(x)\text{ = }\sqrt[]{x^2\text{ + 4}}[/tex][tex]\begin{gathered} a)\text{ when x = -2} \\ f(-2)\text{ = }\sqrt[]{(-2)^2\text{ + 4}}\text{ = }\sqrt[]{4+4} \\ f(-2)\text{ = }\sqrt[]{8}\text{ = }\sqrt[]{2\times4} \\ f(-2)\text{ = 2}\sqrt[]{2} \end{gathered}[/tex][tex]\begin{gathered} b)\text{ }when\text{ x = 3} \\ f(3)\text{ = }\sqrt[]{(3)^2+\text{ 4}}\text{ = }\sqrt[]{9\text{ + 4}} \\ f(3)\text{ = }\sqrt[]{13} \end{gathered}[/tex][tex]\begin{gathered} c)\text{ when x = 2} \\ f(2)\text{ = }\sqrt[]{(2)^2+4}\text{ = }\sqrt[]{4+4} \\ f(2)\text{ = }\sqrt[]{8} \\ f(2)\text{ = 2}\sqrt[]{2} \end{gathered}[/tex][tex]\begin{gathered} d)\text{ when x = x + bx} \\ f(x\text{ + bx) = }\sqrt[]{(x+bx)^2+4}\text{ = }\sqrt[]{(x+bx)(x^{}+bx)+4} \\ f(x\text{ + bx) = }\sqrt[]{(x^2+bx^2+bx^2+b^2x^2)+4} \\ f(x\text{ + bx) = }\sqrt[]{(x^2+2bx^2^{}+b^2x^2)+4} \\ f(x\text{ + bx) = }\sqrt[]{x^2(1+2b+b^2)+4}\text{ } \end{gathered}[/tex]

The rotation of the smaller wheel in the figure causes the larger wheel to rotate. Find the radius of the largerwheel in the figure if the smaller wheel rotates 70.0° when the larger wheel rotates 40.0°The radius of the large wheel is approximately ____ cm.

Answers

Let's begin by listing out the information given to us:

r (1) = 11.4 cm, θ (1) = 70°, θ (2) = 40°, r(2) = ?

The arc length is the same for the 2 circles

r (1) * θ (1) = r (2) * θ (2)

11.4 * 70° = r (2) * 40°

r (2) = 11.4 * 70 ÷ 40

r (2) = 19.95 cm

Hence, the radius of the larger circle is 19.95 cm

if a triangle has side lengths of 4x + 6, 6, and 5x; what is the perimeter

Answers

[tex]\begin{gathered} \text{perimeter is the addition of the all of the sides.} \\ \text{Perimeter}=4x+6+6+5x \\ \text{Perimeter}=9x+12 \end{gathered}[/tex]

Write an equation in point slope form for the line given the slope of 4,and a point on the line (1,2)

Answers

[tex]\begin{gathered} \text{ the equation of a line in slope-point form is} \\ y=mx+b,\text{ we know that m=4, and that (1,2) is on the line, so} \\ 2=4(1)+b \\ 2=4+b \\ b=2-4 \\ b=-2 \\ \\ \text{ Thus, the equation has the form} \\ y=4x-2 \\ \end{gathered}[/tex]

Answer:

[tex]y-2=4(x-1)[/tex]

Step-by-step explanation:

Pre-Solving

We are given that a line has a slope (m) of 4, and that it contains the point (1,2).

We want to write the equation of this line in point-slope form.

Point-slope form is given as [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1, y_1)[/tex] is a point, hence the name.

Solving

Since we are already given the slope, we can immediately plug it into the formula.

Substitute 4 for m.

[tex]y-y_1=4(x-x_1)[/tex]

Now, let's label the values of (1,2) to avoid confusion while substituting.

[tex]x_1=1\\y_1=2\\[/tex]

Substitute these values into the formula.

[tex]y-2=4(x-1)[/tex]

Topic: point-slope form

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7. An antique dealer has a fund of $1,160 for investments. She spends 50%of the fund on a 1911 rocking chair. She then sells the chair for $710, all ofwhich she returns to the fund.a) What was the percent gain on the investment?b) What percent of the original value of the fund is the new value of the fund?

Answers

Given:

Total amount dealer has is $1160.

Spend 50% of the fund to buy a 1911 rocking chair and sells it for $710.

[tex]Fund\text{ she spends on chair=}1160\times\frac{50}{100}[/tex][tex]Fund\text{ she spends on chair= \$580}[/tex]

a)

[tex]\text{Fund gain on selling the chair= 710-580}[/tex][tex]\text{Fund gain on selling the chair= \$}130[/tex][tex]\text{Percent gain on the investment=}\frac{130}{580}\times100[/tex][tex]\text{Percent gain on the investment=}22.41\text{ \%}[/tex]

b)

[tex]\text{New value of the fund=1160+130}[/tex][tex]\text{New value of the fund= \$}1290[/tex][tex]\text{Percentage of original to the new value = }\frac{1290}{1160}\times100[/tex][tex]\text{Percentage of original to the new value =111.21 \%}[/tex]

111.21% of the original value of the fund is the new value of the fund.

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