R 1 = 4 Ω, R 2 = 4 Ω и R 3 = 6 Ω?

25.006m

Hope it helps! :3

Answer:

2,8,8

Explanation:

im not sure really what you asking but is it this the shells

Answer:

Explanation:

The answer is B. He needs to count backwards. So if it’s 800,700,600, and 500, you might get the answer right.

Answer:

Actually the object with more mass with the same acceleration will need more force added on to it because it has more mass and more than likely more weight so will need that extra force to push it down the object with the least mass will go faster with the same force added

Explanation:

Electric field and magnetic field has both the attractive and repulsive character.

Electric field is defined as the region surrounding a charged particle, in which it experiences an electric force.

Here,

Electric field and magnetic field has both the attractive and repulsive character.

Both electric and magnetic fields obey the inverse square law.

Stationary charges produce electric field, whereas moving charges produce magnetic field.

Electric field is associated with two kind of charges, positive and negative, whereas magnetic field is associated with two magnetic poles, north and south.

Both electric field and magnetic field are associated with principle of superposition.

Hence,

Electric field and magnetic field has both the attractive and repulsive character.

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Answer:

The velocity of the boy and the skateboard is 24

Answer:

SeC14

Explanation:

sec14>C12-O

but since you can't subtract o from c , you get this

Answer:

c

Explanation:

Answer:

hi poop

Explanation:

"Hi"

its spelled with an H & an I :^

Answer:

Dry-strength additives, or dry-strengthening agents, are chemicals that improve paper strength normal conditions. These improve the paper's compression strength, bursting strength, tensile breaking strength, and delamination resistance. Typical chemicals used include cationic starch and polyacrylamide derivatives.

Answer:

C

Explanation:

I took the asssinghment and got an 100

Your answer is: earthquakes.

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Have a good day and God bless! :D

Answer:

C

Explanation:

The distance that the pig moves up will be less than the distance that the strongman pulls down.

Explanation: The strongman is further from the fulcrum than the pig is, so the distance that he pulls down will be greater than the distance that the pig moves up.

The distance that the pig moves up will be less than the distance that the strongman pulls down. Hence, option (C) is correct.

The given problem is based on the work done by the applied force. When some magnitude of force is applied on any object, then there will be some obvious displacement of object. This is known as work done by the object. The expression for the work done by the object is,

w = Fd

here, F is the applied force and d is the displacement.

In the given problem, the applied force will be due to the weight of man and pig. So, the modified form of work done is,

work = Wd

W = work/d

here, W is the weight.

Clearly, more the weight, less will be the displacement and vice versa. So due to heavy weight of man, he will pull the pig easily. Such that the upward distance covered by pig will be less than the distance that the strongman pulls down.

Thus, we can conclude that the distance that the pig moves up will be less than the distance that the strongman pulls down. Hence, option (C) is correct.

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Answer:

I think the answer is c

Explanation:

I had this problem once

Answer:

W = 56J

Explanation:

in physics, Work is equal to F*s

then

W = 8N*7m

W = 56J

Answer:

Ribosomes are the protein factories of the cell. Composed of two subunits, they can be found floating freely in the cell’s cytoplasm or embedded within the endoplasmic reticulum. Using the templates and instructions provided by two different types of RNA, ribosomes synthesize a variety of proteins that are essential to the survival of the cell.

Hopefully, this helped! :D

Answer:

it would dry your hair lol

Answer:

there are two way to get mate  and i gave them sepaert explation

Explanation:

55

N

Explanation:

Using Newton's second law of motion:

F

=

m

a

Force=mass

×

acceleration

F

=

25

×

2.2

F

=

55

N

So 55 Newtons are needed.

Answer link

Nam D.

Apr 6, 2018

55

N

Explanation:

We use Newton's second law of motion here, which states that,

F

=

m

a

m

is the mass of the object in kilograms

a

is the acceleration of the object in meters per second

F

=

25

kg

⋅

2.2

m/s

2

=

55

N

The net external force which is required to give a 25kg suitcase an acceleration of 2.2 m/s² to the right is 55N (Newton).

The net external force is the vector sum of all the forces which is acting on a system from outside of the system. There may be multiple external forces which are acting on a body or a system of bodies however there will be only one net external force which is the result of all those external forces which are acting on that body or system.

The net external force on the suitcase can be calculated with the formula:

f = m × a

where, f = net external force on the object,

m = mass of the object,

a = acceleration of the object

m = 25 kg

a = 2.2m/s²

f = 25 kg × 2.2 m/s²

F = 55N (Newton)

The net external force is required to have 55N.

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Answer:

61.3kgm/s

Explanation:

Given parameters:

Velocity of object  = 27m/s

Weight  = 5lbs

Unknown:

Momentum of the object = ?

Solution:

The momentum of a body can be derived from the product of its mass and velocity.

Momentum is the amount of motion a body possesses.

   Momentum  = mass x velocity

Now, let us convert the weight in pounds to mass in kg

             1lbs  = 0.454kg

             5lb  = 5 x 0.454  = 2.27kg

So,

   Momentum  = 2.27 x 27  = 61.3kgm/s

Hello! For this excersice let's applicate the formula:

[tex]\boxed{\boxed{d=vt}}[/tex]

Data:

d = Distance = 150 m

v = Velocity = ¿?

t = Time = 0,9 s

Now, let's replace according the formula:

[tex]\boxed{150 \ m = v * 0,9 \ s}[/tex]

[tex]\boxed{\dfrac{150 \ m}{0,9 \ s} = v}[/tex]

[tex]\boxed{166,67 \ m/s = v}[/tex]

The velocity is 166,67 meters per second.

The speed of the sound will be "16.67 m/s".

The given values are:

Distance,

Time,

As we know,

→ [tex]Distance = Speed\times Time[/tex]

or,

→ [tex]Time = \frac{Distance}{Speed}[/tex]

By substituting the values, we get

→           [tex]= \frac{150}{0.9}[/tex]

→           [tex]= 16.67 \ m/s[/tex]

Thus the above is the appropriate answer.

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Answer:

(c) 1.5 x 10^4 C

Explanation:

we have,

P=1kW=1000w

V=240V

therefore,

P=V *I

1000=240*I

I=1000/240

I=25/6A

now,we know that

I =Q/T

Q=IT

Q=25/6*60*60. [since time =1hour i.e 60*60sec]

Q=15000C

Q=1.5 x 10^4C

The required amount of energy passes through the fire is of [tex]1.5 \times 10^{4} \;\rm C[/tex]. Hence, option (C) is correct.

Given data:

The voltage supply of the electric fire is, V' = 240 V.

The rate of energy transfer is, E' = 1.0 kW = 1000 W.

The time interval is, t = 1 h = 60 × 60 = 3600 s.

In this problem, the energy passes through the fire is nothing but the electric charges. For that we need to calculate the value of charge. So, first calculate the current flow as,

E' = V × I

Solving as,

1000 = 240 × I

I = 1000/240

I = 4.167 A

Now, the energy passes through the fire is obtained as,

Q = I × t

Q = 4.167 × 3600

[tex]Q = 1.5 \times 10^{4} \;\rm C[/tex]

Thus, we can conclude that the required amount of energy passes through the fire is of [tex]1.5 \times 10^{4} \;\rm C[/tex]. Hence, option (C) is correct.

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Answer:

Option C

Explanation:

Centripetal acceleration formula regarding velocity and radius is,

[tex]a_c=\frac{v^2}{r}[/tex]

now we know the centripetal acceleration is 9 and the radius is 16 so we plug these values into our formula,

[tex]a_c=\frac{v^2}{r}\\\\9=\frac{v^2}{16} \\\\144=v^2\\\\\sqrt{144}=v \\\\v=12\ m/s[/tex]

so velocity is 12 m/s

Now for the angular velocity, the formula of centripetal acceleration regarding angular velocity and radius is,

[tex]a_c=rw^2[/tex]

we know the centripetal acceleration is 9 and the radius is 16 so plug these values into the formula,

[tex]a_c=rw^2\\\\9=16w^2\\\\0.5625=w^2\\\\\sqrt{0.5625}=w \\\\0.75\ rad/s=w\\[/tex]

so angular velocity is 0.75 rad/s

23×45=1035

Explanation:

first you multiply 5 and 3 you would get 15 tou drop the 5 and bring the 1 on top of 2 then you multiply 5 by 2 you get 10 then add 1 you get 11. once your Don's you would get 115. once your done with that cross out the five and then multiply 4 by 3 wich equals 12 drop the 2 under five and then bring 1 on top of 2 and then multiply 4 by 2 wich equals 8 and then add one and you get 9.

Answer:

a. 5.23 m/s² b. 44.23 N

Explanation:

a. What is the centripetal acceleration of the  hammer?  

The centripetal acceleration a = rω² where r = radius of circle and ω = angular speed.

Now r = length of chain = 1.4 m and ω = 0.595 rev/s = 0.595 × 2π/s = 3.74 rad/s.

So a = rω²

= 1.4 m × (3.74 rad/s)²

= 5.23 m/s²

b. What is the tension in the chain?

The tension in the chain, T = ma where m = mass of hammer = 8.45 kg and a = centripetal acceleration of hammer = 5.23 m/s². This tension is the centripetal force on the hammer.

So, T = 8.45 kg × 5.23 m/s²

= 44.23 N

The electromotive force (∈) = 2 V

Given

I=2 A

t = 30 s

E = 120 J

Required

The electromotive force (∈)

Solution

The electromotive force : the potential difference between two electrodes in galvanic cell

Can be formulated :

[tex]\tt \epsilon=\dfrac{E}{Q}[/tex]

E = energy, J

Q = charge , Coulomb = i.t

[tex]\tt \epsilon=\dfrac{120~J}{2~A\times 30~s}\\\\\epsilon=2~V[/tex]

Answer:

The electromotive force (∈) = 2 V

Further explanation

Given

I=2 A

t = 30 s

E = 120 J

Required

The electromotive force (∈)

Solution

The electromotive force : the potential difference between two electrodes in galvanic cell

Can be formulated :

E = energy, J

Q = charge , Coulomb = i.t

Explanation:

Answer: b. 420 m/s

Explanation: ap3x

The frequency of the wave with the speed of 345 m/s and wavelength of 23 m is 15 Hz. With the same frequency the speed of wave t 28 m wavelength will be 420 m/s.

Frequency of a wave is the number of wave cycles per unit volume. It is the inverse of time period thus have the unit of s⁻¹ which is equivalent to one Hz. Frequency is inversely proportional to the wavelength.

The relation between frequency, wavelength and speed of a wave is written as follows:

c = νλ

Given that, speed of the wave = 345 m/s

wavelength =23 m

frequency = speed/wavelength

v = 345 m/s /23 m = 15 Hz.

New wavelength = 28 m

frequency = 15 Hz

then speed = 15 Hz × 28 m = 420 m/s.

Hence, the speed of the wave become 420 m/s. Option B is correct.

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Answer:

Joule

Explanation:

Joule is the SI unit of work or energy.

Answer:

joule

Explanation:

edge2020

Answer:

The tangential velocity of a rotating object is:

v = r*w

where r is the radius, and w is the angular velocity.

w = 2*pi*f

where f is the frequency.

We know that the record plater does 11 revolutions in 20 seconds, then it does:

11 rev/20s = 0.55 rev/s = f

then we have:

w = 2*pi*0.55 s^-1 = 2*3.14*0.55 s^-1 = 3.454 s^-1

The radius of a record player is really variable, it is around 10 inches, so i will use r = 10in, which is the rotating part of the record player.

then the tangential velocity is:

v = 10in*3.454 s^-1 = 34.54 in/s

Answer:

speed is equal to distance/time

so 2m/40s

=0.05