Answer:
t
Explanation:
Answer: true
Explanation:
A teenager received a ticket for driving 80 miles per hour. This information describes the teenager's
Answer:
Speed
Explanation:
Ii is given that, "A teenager received a ticket for driving 80 miles per hour.". It doesn't give any information about the direction of motion. It means it represents the speed of teenager. Speed is a scalar quantity. It doesn't have direction.
Hence, the given information describes the teenager's speed.
Answer:
Speed! :)
Explanation:
There is no reference to the direction, which cancels out velocity and direction. In addition, they don't mention the initial speed and the time, so acceleration is out, leaving your answer... SPEED:)
Hope this helps, have a marvelous day!
An object is accelerating uniformly from 8.0 m/s to 16.0 m/s in 10 seconds. How far does the object travel in 10 seconds?
Answer:
Explanation:
Using the equation of motion to get the distance
average Speed =distance/ time
Distance = average speed * time
Distance = (v-u)t
Distance = (16-8)* 10
Distance =8*10
Distance = 80m
Hence the distance covered by the object is 80m
You take a couple of capacitors and connect them in series, to which you observe a total capacitance
of 4.8 µF. However, when you connect them in parallel, their combined capacitance is 35 µF.
Determine the value of each capacitor
Answer:
Approximately [tex]\rm 5.7\; \mu F[/tex] and approximately [tex]29\; \rm \mu F[/tex].
Explanation:
Let [tex]C_1[/tex] and [tex]C_2[/tex] denote the capacitance of these two capacitors.
When these two capacitors are connected in parallel, the combined capacitance will be the sum of [tex]C_1[/tex] and [tex]C_2[/tex]. (Think about how connecting these two capacitors in parallel is like adding to the total area of the capacitor plates. That would allow a greater amount of charge to be stored.)
[tex]C(\text{parallel}) = C_1 + C_2[/tex].
On the other hand, when these two capacitors are connected in series, the combined capacitance should satisfy:
[tex]\displaystyle \frac{1}{C(\text{series})} = \frac{1}{C_1} + \frac{1}{C_2}[/tex].
(Consider how connecting these two capacitors in series is similar to increasing the distance between the capacitor plates. The strength of the electric field ([tex]V[/tex]) between these plates will become smaller. That translates to a smaller capacitance if the amount of charge stored [tex](Q)[/tex] stays the same.)
The question states that:
[tex]C(\text{parallel}) = 35\; \rm \mu F[/tex], and[tex]C(\text{series}) = 4.8\; \rm \mu F[/tex].Let the capacitance of these two capacitors be [tex]x\; \rm \mu F[/tex] and [tex]y\; \rm \mu F[/tex]. The two equations will become:
[tex]\displaystyle \left\lbrace \begin{aligned}& x + y = 35 \\ & \frac{1}{x} + \frac{1}{y} = \frac{1}{4.8}\end{aligned}\right.[/tex].
From the first equation:
[tex]y = 35 - x[/tex].
Hence, the [tex]y[/tex] in the second equation here can be replaced with [tex](35 - x)[/tex]. That equation would then become:
[tex]\displaystyle \frac{1}{x} + \frac{1}{35 - x} = \frac{1}{4.8}[/tex].
Solve for [tex]x[/tex]:
[tex]\displaystyle \frac{x + (35 - x)}{x \, (35 - x)} = \frac{1}{4.8}[/tex].
[tex]x\, (35 - x) = 4.8[/tex].
[tex]x^2 - 35 \, x + 168 = 0[/tex].
Solve this quadratic equation for [tex]x[/tex]:
[tex]x \approx 5.7[/tex] or [tex]x \approx 29.3[/tex].
Substitute back into the equation [tex]y = 35 - x[/tex] for [tex]y[/tex]:
[tex]x \approx 5.7[/tex] and [tex]y \approx 29.3[/tex], or[tex]x \approx 29.3[/tex] and [tex]x \approx 5.7[/tex].In other words, these two capacitors have only one possible set of capacitances (even though the previous quadratic equation gave two distinct real roots.) The capacitances of the two capacitors would be approximately [tex]5.7\; \rm \mu F[/tex] and approximately [tex]29\; \rm \mu F[/tex] (both values are rounded to two significant digits.)
À A car moves with an initial velocity of 18 m/s due north. Find the velocity of the car after 7 Os if
(a) its acceleration is 1.5 m/s2 due north. (b) its acceleration is 1.5 m/s2 due south
Answer:
(a) [tex]v_f=28.5m/s[/tex]
(b) [tex]v_f=7.5m/s[/tex]
Explanation:
Hello.
(a) In this case since the car is moving at an initial velocity of 18 m/s due north, the final velocity is computed considering the acceleration as positive since it is due north as well:
[tex]v_f=v_0+at=18m/s+1.5m/s^2*7s\\\\v_f=28.5m/s[/tex]
(b) In this case, since the car is moving due north by the acceleration is due south it is undergoing a slowing down process, thereby the acceleration is negative therefore the final velocity turns out:
[tex]v_f=v_0+at=18m/s-1.5m/s^2*7s\\\\v_f=7.5m/s[/tex]
Best regards.
(a) The final velocity of car after 7.0 s for an acceleration is 1.5 m/s2 due north is 28.5 m/s.
(b) The final velocity of car after 7.0 s for an acceleration is 1.5 m/s2 due south is 7.5 m/s.
Given data:
The initial velocity of car due north is, u = 18 m/s.
The time interval is, t = 7.0 s.
(a)
For the acceleration of 1.5 m/s2 due north, the final velocity of car can be obtained from the first kinematic equation of motion as,
[tex]v = u +at[/tex]
Here, v is the magnitude of final velocity of car.
Solving as,
[tex]v = 18+(1.5)7\\\\v = 28.5 \;\rm m/s[/tex]
Thus, we can conclude that the final velocity of car after 7.0 s for an acceleration is 1.5 m/s2 due north is 28.5 m/s.
(b)
since the car is moving due north by the acceleration is due south it is undergoing a slowing down process, thereby the acceleration is negative therefore the final velocity turns out:
[tex]v'=u+(-a)t\\\\v'=18+(-1.5)7\\\\v' = 7.5 \;\rm m/s[/tex]
Thus, we can conclude that the final velocity of car after 7.0 s for an acceleration is 1.5 m/s2 due south is 7.5 m/s.
Learn more about the linear acceleration here:
https://brainly.com/question/14214161
What is the difference between environmental science and environmentalism?
Explanation:
Environmental science is the pursuit of knowledge about the workings of the environment and our interactions with it. Environmentalism is a social movement dedicated to protecting the natural world. Nature makes resources at similar speeds
a coin with a diameter of 2.1 cm with an initial angular speed of 19 rad/sec and rolls in a straight line. The rotation slows at an angular acceleration of magnitude 1.9 rad/s^2. What is the magnitude of the linear acceleration?
Answer:
the magnitude of the linear acceleration is [tex]=1.995 \,\,cm/s^2\\[/tex]
Explanation:
Recall that the linear acceleration (a) is associated with the angular acceleration vi the formula:
[tex]a=R\,\alpha[/tex]
where R stands for the radius of the rotational motion (in our case 2.1 cm/2 = 1.05 cm, and [tex]\alpha[/tex] stands for the angular acceleration in radians per units of time squared.
Then the linear acceleration in our case is:
[tex]a=R\,\alpha\\a=1.05 cm * (1.9\,\,\,rad/s^2)\\=1.995 \,\,cm/s^2[/tex]
A 75 kg doctor delivers a 4 kg baby and holds it at arm's length (0.3 m). Using the Universal Law of Gravitation formula below, identify F, G, m1, m2, r. *
Answer:
m₁ = 75 kg
m₂ = 4 kg
r = 0.3 m
G = 6.67 x 10⁻¹¹ Nm²/kg²
F = 2.223 x 10⁻⁷ N
Explanation:
Given;
mass of the doctor, m₁ = 75 kg
mass of the baby, m₂ = 4 kg
length of the doctor's arm, r = 0.3 m
universal gravitation constant, G = 6.67 x 10⁻¹¹ Nm²/kg²
The gravitational force F, is calculated as;
[tex]F = \frac{Gm_1m_2}{r^2} \\\\F = \frac{(6.67*10^{-11})(75 \ kg) (4 \ kg)}{(0.3 \ m)^2} \\\\F = 2.223 *10^{-7} \ N[/tex]
You are watching your friend play hockey. In the course of the game, he strikes the puck in such a way that, when it is at its highest point, it just clears the surrounding 2.70 m high Plexiglas wall that is 12.9 m away.
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
[tex]v_y = 5.14 \ m/s[/tex]
b
[tex]\Delta t = 0.5248 \ s [/tex]
Explanation:
From the question we are told that
The maximum height is H = 2.70
The Range is R = 12.9 m
Generally from projectile motion we have that
[tex]Range = \frac{ u^2 sin2(\theta)}{g}[/tex]
[tex]12.9 = \frac{ u^2 sin2(\theta)}{g}[/tex]
Generally from trigonometric identity
[tex]sin 2(\theta) = 2sin (\theta) cos(\theta)[/tex]
So
[tex]12.9 = \frac{ u^2 2sin(\theta) cos(\theta)}{g}[/tex]
=> [tex]u^2 * 2sin(\theta) cos(\theta) = 12.9 * g[/tex]
[tex]u^2 * 2sin(\theta) cos(\theta) = 12.9 * 9.8[/tex]
[tex]u^2 *2sin(\theta) cos(\theta) = 126.42 \ \cdots (1)[/tex]
Also the maximum height is
[tex]H = \frac{u^2 sin^2 (\theta)}{2g}[/tex]
=> [tex]2.70 = \frac{u^2 sin^2 (\theta)}{2g}[/tex]
=> [tex]u^2 sin^2 (\theta) = 2.70 * 2 * g[/tex]
=> [tex]u^2 sin^2 (\theta) = 2.70 * 2 * 9.8[/tex]
=> [tex]u^2 sin^2 (\theta) = 52.92\cdots (2)[/tex]
Dividing equation 2 by (1)
[tex]\frac{u^2 sin^2 (\theta)}{u^2 *2sin(\theta) cos(\theta)} =\frac{52.92}{126.42 }[/tex]
=> [tex]tan(\theta ) = \frac{52.92}{126.42 }[/tex]
=> [tex]\theta = tan^{-1} [0.4186][/tex]
=> [tex]\theta =22.71^o [/tex]
So
From equation 1
[tex]u^2 *2sin(22.71) cos(22.71) = 126.42 \ \cdots (1)[/tex]
=> [tex]u = 13.322 \ m/s[/tex]
Generally the vertical component of the initial velocity is mathematically evaluated as
[tex]v_y = usin (\theta)[/tex]
=> [tex]v_y = 13.322 * sin (22.71)[/tex]
=> [tex]v_y = 5.14 \ m/s[/tex]
Generally the time taken is mathematically represented as
[tex]\Delta t = \frac{u sin (\theta )}{g}[/tex]
=> [tex]\Delta t = \frac{13.322 sin (22.71 )}{9.8}[/tex]
=> [tex]\Delta t = 0.5248 \ s [/tex]
Convert 26.4 mi to km
Answer:
42.48 [km]
Explanation:
To convert miles to kilometers we must know the conversion factor which is equal to:
[tex]1.609[\frac{km}{mi} ][/tex]
We make the product of the value required by the conversion factor:
[tex]26.4[mi]*1.609[\frac{km}{mi} ]\\\\[/tex]
26.4*1.609 = 42.48 [km]
PLS I NEED HELP ASAP
A rollercoaster speeds up from rest to 100mph (45m/s) in 1.2s. (Acceleration=37.5)
The rollercoaster car then travels vertically upwards, and decelerates at 10m/s^2
How much time passes before it is stationary (for a moment)?
Answer:
5.7s
Explanation:
it is stationary when v = 0 so use the equations of motion to find t. Please see photo attached
The time passed before it is stationary (for a moment) will be 5.7s.
What is acceleration?Acceleration is defined as the rate change of velocity with time.
acceleration a = (Δv) / (Δt)
A rollercoaster speeds up from rest to 100mph (45m/s) in 1.2s. The rollercoaster car then travels vertically upwards, and decelerates at 10m/s^2
Time taken for the change in speed is t.
The acceleration is given by
-10= (45 -0)/ t
t = 4.5
Total time passed = 4.5 +1.2 = 5.7s
Thus, the time passed is 5.7s.
Learn more about acceleration.
https://brainly.com/question/12550364
#SPJ2
A radar station sends a signal to a ship which is located a distance 13.9 kilometers from the station at bearing 136° clockwise from the north. At the same moment, a helicopter is at a horizontal range of 19.6 kilometers, at bearing 152° clockwise from the north, with an elevation of 2.57 kilometers. Let east be the î direction, north be the ĵ direction, and up be the direction.
(A) What is the displacement vector (in km) from the helicopter to the ship? (Express your answer in vector form. Do not include units in your answer.)
(B) What is the distance (in km) between the helicopter and ship?
(C) The ship begins to sink at a rate of 5.40 m/s. Write the position vector (in km) of the ship relative to the helicopter as a function of time as the ship sinks. Assume that the helicopter remains hovering at its initial position and that the sinking rate remains the same even after the ship sinks under the surface. (Use the following as necessary: t. Do not include units in your answer.)
(D) Evaluate the position of the ship relative to the helicopter (in km) after 1.90 h. (Express your answer in vector form. Do not include units in your answer.)
Answer:
A) d = 7.9267 km, θ = 157.19
D) d = 35.17 km
Explanation:
For this exercise the easiest way is to decompose the vectors
Ship
X axis (North)
The angle measured from the positive side of the x axis (unit vector i^ ) counterclockwise
θ = 136- 136 = 224
cos θ = x₁ / 13.9
x₁ = 13.9 cosc 224
x₁ = - 9.9988 103 m
z axis
sin 224 = z₁ / 13.9
z₁ = 13.9 sin224
z₁ = -9.6558 m
Axis y
y₁ = 0
Helicopter
x-axis (North)
θ = 360 - 152
θ = 208
cos θ = x₂ / 19.6
x₂ = 19.6 cos 208
x₂ = -17.3058 km
z axis
sin 204 = z₂ / 19.6
z₂ = 19.6 sin 204
z₂ = -7.9720 km
Axis y
y₂ = 2.57 km
It's a bit strange the way the axes give, but having the decomposition of the vectors we can answer the questions
A) They ask the displacement vector, let's start looking for the distance
d = √ [(x₂-x₁)² + (y₂-y₁)² + (z₂-z₁)²]
we substitute
d =√[(17.3058 - 9.9988)² + (2.57 - 0)² + (7.9720 -9.6558)²]
d = √ [7.307² + 2.57² + 1.6838²]
d = 7.9267 km
the angle of this vector is with respect to North (x-axis)
cos θ = -7.307 / 7.9267
θ = cos⁻¹ (-0.9218)
θ = 157.19
Y-axis elevation angle
cos θ'= 2.57 / 7.9267
θ’= cos⁻¹ (0.3242)
θ’= 71.09
b) d = 7.9267 km
c) at this time the ship is sinking at constant speed, the sinking direction is the same vertical direction of the helicopter (y-axis)
the distance is
y₁ = v₁ t
let's reduce speed to km /h
v₁ = 5.4 m / s (1km/1000m ) (3600s/1h)= 19.44 km /h
y₁ = 19.44 t
the vector positions is
d = √ [(x₂-x₁)² + (y₂-y₁)² + (z₂-z₁)²]
d = √ [7.307² + (2.57 -19.44 t)² + 1.6838²]
in vertical angle is
cos θ'= (2.57 -19.44t) / d
At an angle to the x axis is
cos θ = -7.307 / d
d) let's evaluate the position for t = 1.90 h
distance
d = √ [7.307² + (2.57- 19.44 1.9)² + 1.6838²]
d = √ [7.307² + (-34.366)² + 1.6838²]
d = 35.17 km
If a car has a mass of 1,300 kg and is moving at a constant velocity of 20 m/s, what is the net force acting on the car?
Constant velocity means there is no acceleration in the direction of the car's movement and hence no force acting on the car in this direction.
The only forces acting on the car are due to gravity and the Earth pushing back up on the car. But the car doesn't move up or down, so the net force is 0.
Use an ideal op amp to design a differentiation circuit for which the time constant is 10‐3s usinga 10 nF capacitor. What are the gains and phase shifts found for the circuit at one‐tenth and 10times the unity‐gain frequency? A series input resistor is added to limit the gain magnitude athigh frequencies to 100 V/V. What is the associated 3‐dB frequency? What gain and phase shiftresult at 10 times the unity‐gain frequency?
Answer:
Attached below is the detailed solution
Gains at one-tenth unity gain = 0.1 v/v
Gains at 10 times unity gain = 10 v/v
phase shift at 10 times unity gain =-95.71⁰
Explanation:
a)Gain at one-tenth unity gain
w/Wc = 100/1000 = 0.1 v/v
b)Gain at 10 times unity gain
w / Wc = 10 krad/sec / 1 krad/sec = 10 v/v
3-db frequency of new differentiator = 15.915 khz
attached below is the detailed solutions
what are the chemical symbols for carbon aluminium hydrogen oxygen and sodium
El unico que se es el del oxígeno: o2
A truck is moving at 2.0 m/s accelerates at a rate of +2.00 m/s2. It does this over a distance of 400.0m. Find the final velocity.
If v is the truck's final velocity, then
v² - (2.0 m/s)² = 2 * (2.00 m/s²) * (400.0 m)
v² = 1604 m²/s²
v = 40.05 m/s ≈ 40 m/s
Help please due by 3:00
Answer:
zero
Explanation:
Acceleration is a measure of the rate of change of velocity. If the velocity is unchanging, its rate of change is zero.
The acceleration is zero.
A small, 29 gram pith balls carrying 2 nC of charge is dangling from an insulating string. Another charged pith balls carrying an unknown amount of charge is brought close to the first ball, causing it to shift away. When everything is in equilibrium, the two balls are horizontally separated by distance of 5 cm, and the string is tilted about 11 degrees away from the vertical direction. How much charge is on the second ball
Answer:
[tex]q_2=7.67\times 10^{-6}\ C[/tex]
Explanation:
Given that,
Mass of a pitch ball, m = 29 g = 0.029 kg
Charge on one pitch ball, q₁ = 2 nC
Another charged pith balls carrying an unknown amount of charge is brought close to the first ball, causing it to shift away. When everything is in equilibrium, the two balls are horizontally separated by distance of 5 cm or 0.05 m, and the string is tilted about 11 degrees away from the vertical direction.
At equilibrium,
[tex]T\cos\theta=mg\ .....(1)\\\\\text{and}\\\\T\sin\theta=\dfrac{kq_1q_2}{d^2}\ ....(2)[/tex]
Where q₂ is the change on the second ball
Dividing equation (2) by (1) we get :
[tex]\tan\theta=\dfrac{kq_1q_2}{d^2mg}[/tex]
Solving for q₂, we get :
[tex]q_2=\dfrac{\tan\theta d^2 mg}{kq_1}\\\\q_2=\dfrac{\tan(11)\times 0.05^2\times 0.029\times 9.8}{9\times 10^9\times 2\times 10^{-9}}\\\\q_2=7.67\times 10^{-6}\ C[/tex]
So, the charge on the second ball is [tex]7.67\times 10^{-6}\ C[/tex].
You have landed a summer job as the technical assistant to the director of an adventure movie shot here in Arizona. The script calls for a large package to be dropped onto the bed of a fast moving pick-up truck from a helicopter that is hovering above the road, out of view of the camera. The helicopter is 235 feet above the road, and the bed of the truck is 3 feet above the road. The truck is traveling down the road at 40 miles/hour. You must determine when to cue the assistant in the helicopter to drop the package so it lands in the truck. The director is paying $20,000 per hour for the chopper, so he wants you to do this successfully in one take. If t = 0 is the time that filming starts at and you can assume that the truck is already at speed, at what time should the helicopter release the package and how far back from the drop site should it be at t = 0?
Answer:
a
[tex]t = 3.798 \ s [/tex]
b
[tex]S = 67.91 \ m [/tex]
Explanation:
From the question we are told that
The height of the helicopter is [tex]h= 235 ft[/tex]
The height of the bed of the truck is [tex]h_b = 3 \ ft[/tex]
The speed of the truck is [tex]v = 40 \ miles / hour = \frac{40 * 1609.34}{3600} = 17.88 \ m/s[/tex]
Generally the distance between the truck bed and the helicopter is mathematically represented as
[tex]H = h - h_b[/tex]
=> [tex]H = 235 -3[/tex]
=> [tex]H = 232 \ ft [/tex]
Converting to meters
[tex]H = \frac{ 232}{3.281} = 70.7 \ m [/tex]
Generally the time at which the helicopter should drop the package is mathematically represented as
[tex]t = \sqrt{\frac{2 * H}{g} }[/tex]
[tex]t = \sqrt{\frac{2 * 70.7}{9.8} }[/tex]
[tex]t = 3.798 \ s [/tex]
Generally distance of the helicopter from the drop site at time t = 0 s is
[tex]S = v * t[/tex]
=> [tex]S = 17.88 * 3.798[/tex]
=> [tex]S = 67.91 \ m [/tex]
what are two benefits of scientific using a diagram to model the water cycle
Answer:
it can show changes that occur in many different parts of earth at the same time
it can be used to show as much detail as is present in the actual water cycle
Explanation:
apex(i hope i helped)
15. When objects are moved further apart from each other, the force of
gravity between them
Answer: Newtons First law.
Explanation: Not enough information.
Help ASAP). Draw additional masses to show how the block can be made to move toward point A. Be sure to draw the string and label the mass of the block. For full credit, draw the minimum number of blocks required to make the block move toward point A. Will Mark Brainliest
Answer:
Given that the block have two applied masses 250 g at East and 100 g at South. In order to make a situation in which block moves towards point A, we have to apply minimum number of masses to the blocks. In order to prevent block moving toward East, we have to apply a mass at West, equal to the magnitude of mass at East but opposite in direction. Therefore, mass of 250 g at West is the required additional mass that has to be added. There is already 100 g of mass acting at South, that will attract block towards South or point A. No need to add further mass in North-South direction.
In a particular area of the country, electrical energy costs $0.12 per kilowatt-hour. (Round your answers, in dollars, to at least two decimal places.) (a) How much does it cost to operate an old-style incandescent 100-W light bulb continuously for 24 hours? $ (b) A modern LED light bulb that emits as much visible light as a 100-W incandescent only draws 16.0 W of power. How much does it cost to operate this bulb for 24 hours? $ (c) A particular electric oven requires a potential difference of 220 V and draws 20.0 A of current when operating. How much does it cost to operate the oven for 5.30 hours? $
Answer:
a) cost = $ 0.29 , b) cost = $ 0.046 , c) cost = $ 2.80
Explanation:
a) Let's find the energy consumed by this bulb, which is the product of the power and time
energy = P t
energy = 100 24 = 2400 W h
as the cost of energy is given in kWh we reduce this value
Energy = 2400 Wh (1 kW / 1000W)
Energy = 2.40 kWh
Calculate the cost of energy
cost = 0.12 2.40
cost = $ 0.288
cost = $ 0.29
b) energy = 16.0 24 = 384 Wh
we reduce to kWh
energy = 0.384 kWh
cost = 0.12 0.384
cost = $ 0.0461
cost = $ 0.046
c) let's find the power consumed by the oven
P = I V
P = 20.0 220
P = 4400 W
we look for the energy consumed
energy = 4400 5.30
energy = 23320 Wh
we reduce to kWh
energy = 23.32 kWh
we calculate the cost of this energy
cost = 0.12 23.32
cost = $ 2,798
cost = $ 2.80
A wildebeest and a chicken participate in a race over a 2.10 km long course. The wildebeest travels at a speed of 19.0 m/s and the chicken can do 3.30 m/s. The wildebeest runs for 1.680 km and then stops to tease the slow-moving chicken, which eventually passes by. The wildebeest waits for a while after the chicken passes and then runs toward the finish line. Both animals cross the finish line at the exact same instant. Assume both animals, when moving, move steadily at their respective speeds.
(a) how far (in m) is the chicken from the Finish Line when the wildebeest resume the race?
(b) for how long in time (in s) was the wildebeest stationary?
Answer:
Explanation:
2.1 km = 2100 m
1.68 km = 1680 m
a ) Time taken by wild beast to travel 1680 m
= 1680 / 19 = 88.42 s
Time taken by wild beast to travel 2100 m
2100 / 19 = 110.52 s
distance travelled by chicken in 88.42 s
= 88.42 x 3.3 = 291.78 s
Its distance from the end point
= 2100 - 291.78 = 1808.22m
b ) Time taken by chicken to travel 2100 m
= 2100 / 3.3 = 636.36 s
Both reach simultaneously so , time of resting by wild beast
= 636.36 - 110.52 = 525.84 s .
Consider the Bell X-2 research aircraft, which was the first aircraft to achieve Mach 3 on September 27th , 1956. During this flight, the aircraft reached a velocity of 936 m/s at an altitude of 65,500 ft. Calculate the actual Mach number that the X-2 achieved during this flight. Now, consider two other conditions. Condition #1: Assuming the aircraft travels at the same velocity in Jupiter’s atmosphere at an altitude where the temperature is -145 °C. Also, assume that the atmosphere of Jupiter is made up of entirely hydrogen gas (H2) which has a molecular weight of 2.016 g/mol. Calculate the Mach number of the X-2 on Jupiter. Condition #2: Assuming the aircraft travels at the same velocity in Pluto’s atmosphere at an altitude where the temperature is -223 °C. Also, assume that the atmosphere of Pluto’s is made up of entirely nitrogen gas (N2) which has a molecular weight of 28.013 g/mol. Calculate the Mach number of the X-2 on Pluto.
Answer:
Explanation:
mach number is ratio of speed with respect to speed of sound .
speed of aircraft = 936 m /s
speed of sound at 65500 ft = 295 m /s
mach number = 936 / 295 = 3.17
velocity of sound at - 145 degree and in hydrogen gas .
velocity of sound
[tex]V=\sqrt{\frac{RT}{M} }[/tex]
[tex]V=\sqrt{\frac{8.3\times(273-145)}{2\times10^{-3}} }[/tex]
= 729 m /s
mach number
= 936 / 729 = 1.28
velocity of sound at - 223 degree and in nitrogen gas .
velocity of sound
[tex]V=\sqrt{\frac{RT}{M} }[/tex]
[tex]V=\sqrt{\frac{8.3\times(273-223)}{28.013\times10^{-3}} }[/tex]
= 122 m /s
mach number
= 936 / 122 = 7.67
A minerals that help in clotting of blood?
Answer:
Calcium helps in blood clotting. Thank You !
Answer: Calcium
Explanation:
Calcium is Important for healthy bones and teeth; helps muscles relax and contract; important in nerve functioning, blood clotting, blood pressure regulation, immune system health
A constant force is applied to a body that is already moving. The force is directed at an angle of 60 degrees to the direction of the body's velocity. What is most likely to happen is that: the body will stop moving. the body will move in the direction of the force. the body's velocity will increase in magnitude but not change direction. the body will gradually change direction more and more toward that of the force while speeding up. the body will first stop moving and then move in the direction of the force.
Answer:
the body will gradually change direction more and more toward that of the force while speeding up.
Explanation:
From the question we were told that constant force is applied to a body that is already moving
if the applied force is in opposite direction to the motion of the object, there would be deceleration.
Whenever a force is applied to moving body , acceleration will occur in the body if the force and the motion of the body act in the same direction.
However in case of the question since the force is directed at an angle of 60 degrees to the direction of the body's velocity then the body will gradually change direction more and more toward that of the force while speeding up.
.
A boat Is headed due north on a river that's flowing directly east. What is the general direction of travel for this boat with respect to the land?
A. southeast
B. northeast
C. northwest
D.
east
Answer:
Its northeast. Just took the exam.
Explanation:
Answer:
See image
Explanation:
Plato
The dipole moment of water is p = 6.17 x 10-30 C m. If the electric field in a microwave oven is on average 94.7 x 10-6 N/C, and water molecules start anti-parallel to the external field (180o), how much energy (in Joules) is deposited into a water sample in 2.39 seconds with 13.1 of water if the direction of this field switches every 3.42 x 108 times a second and each time the electric field flips the water molecules align themselves with the new direction?
Answer:
Explanation:
Given that:
p = 6.17 × 10⁻³⁰ Cm
Electric field E = 94.7 × 10⁻⁶ N/C
Then:
[tex]U= -p^{\to} *E^{\to}[/tex]
[tex]U_i = -pE \ cos180^0 =pE \\ \\ U_f = -pE \ cos 0^0 = -pE[/tex]
∴
[tex]\Delta U = U_i - U_f = 2pE \ \ per \ dilute/per \ switch[/tex]
This implies that one switch of dipole produces 2pE energy to be deposited in the water.
mass of water = 13.1 g
The number of water molecule = [tex]\dfrac{mass}{molar \ mass}\times N_A[/tex]
=[tex]\dfrac{13.1}{18.015}\times6.023 \times 10^{23}[/tex]
= 4.38 × 10²³ molecules of water.
∴ Number of dipoles = 4.38 × 10²³
The total number of switches in 2.39 sec = switch frequency × 2.73
Number of switches = 2.39 × 3.42 × 10⁸
Number of switches = 817380000
Number of switches = 8.174 × 10⁸
The total energy Q deposited = Energy deposited per dipole × Number of dipole × no of switches
Q = (2pE) × 4.38 × 10²³ × 8.174 × 10⁸
Q = (2 × 6.17 × 10⁻³⁰ × 94.7 × 10⁻⁶ × 4.38 × 10²³ × 8.174 × 10⁸ )
Q = 0.41838 J
Which of the following is NOT a benefit of cool down activities?
A.
reduced muscle soreness
B.
maximal lightheadedness
C.
injury prevention
D.
gradually reduced heart rate
Please select the best answer from the choices provided.
A
B
C
D
The option that is not a benefit of cool down activities from the question is
Maximal lightheadedness
Cooling down activities can be regarded as easy exercise which is carried out after an intense activity, so that the body can gradually transit to a state of resting or near-resting state. It can be carried out base on on the intensity of the exercise,Examples of this activities can involve a slow jog or walk. With lower intensities, stretching, Upper body stretch as well as light jogging.Benefits of Cooling down activities are listed as Injury prevention as well as Gradually reduced heart rate and reduced muscles soreReduced muscles sore: after intense work out, the muscle must have been so stretched so with cooling down activities muscles sore can be prevented
Maximal lightheadedness can be regarded as been dizzy and not a benefit to Cooling down activities
Therefore, Cooling down activities helps the body to move slowly to state of rest.
Learn more at: https://brainly.com/question/16712082?referrer=searchResults
In a football game, running back is at the 10-yard line and running up the field towards the 50 yard
line, and runs for 3 seconds at 8 yd/s. What is his current position (in yards)?
Answer:
34 yards or 34 yard line
Explanation:
8 × 3 = 24
24 + 10 = 34
