The amount Rebecca has put into fixed savings each month to cover her annual expenses for life insurance, auto insurance and real estate taxes is $ 194.
Given that:-
Amount invested in life insurance = $ 255
Number of payments in life insurance = 4
Amount invested in real estate taxes = $ 455.35
Number of payments in real estate taxes = 2
Amount invested in auto insurance = $ 66.21
Number of payments in auto insurance = 6
We have to find the amount Rebecca has put into fixed savings each month to cover her annual expenses for life insurance, auto insurance and real estate taxes.
Hence,
Total amount put by Rebecca in a year = 255*4 + 455.35*2 + 66.21*6 = 1020 + 910.70 + 397.26 = $ 2,327.96
Amount put by Rebecca in a month = 2327.96/12 = $ 193.997 ≈ $ 194
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flying against the wind, an airplane travels 7840 kilometers in 8 hours. flying with the wind, the same plane travels 5280 kilometers in 4 hours. what is the rate of the plane in still air and what is the rate of the wind?
The rate of the plane in still air is 1150km/hr and the rate of the plane in the wind is 170km/hr.
Explanations:The formula for calculating distance is expressed as:
[tex]\begin{gathered} dis\tan ce=\text{speed}\times\text{time} \\ d=st \end{gathered}[/tex]Let the rate of the plane in still air be "x"
Let the rate of the plane in the wind be "y"
if flying against the wind, an airplane travels 7840 kilometers in 8 hours, then;
8 (x - y) = 7840
x - y = 980 ........................ 1
If flying with the wind, the same plane travels 5280 kilometers in 4 hours
4 (x + y) = 5280
x + y = 1,320 ......................2
Add both equations:
x + x = 980 + 1320
2x = 2,300
x = 2300/2
x = 1150 km/hr
Substract x = 1150km/hr into equation 1.
x - y = 1320
1150 + y = 1320
y = 1320 - 1150
y = 170km/hr
Hence the rate of the plane in still air is 1150km/hr and the rate of the plane in the wind is 170km/hr
Watch the video and then solve the problem given below.Click here to watch the video.Solve the inequality both algebraically and graphically. Give the solution in interval notation and draw it on a number line graph.x−54
Given the inequality below:
[tex]\frac{x-5}{4}<\frac{9}{5}[/tex]Solving algebraically as shown below:
[tex]\begin{gathered} \frac{x-5}{4}<\frac{9}{5} \\ \text{Lcm of the denominator(4 and 5) is 20} \\ \text{mltiply through by the Lcm(20)} \\ 20\times\frac{(x-5)}{4}<20\times\frac{9}{5} \end{gathered}[/tex][tex]\begin{gathered} 5(x-5)<4\times9 \\ 5x-25<36 \\ 5x<36+25 \\ 5x<61 \\ x<\frac{61}{5} \\ x<12.2 \end{gathered}[/tex]Solving graphically as shown below the plotting of x < 12.2
The number line graph is the number line showing x < 61/5, as shown below:
The interval notation of the solution is (- ∞, 61/5) or (- ∞, 12.2)
Question 1
Is the sequence arithmetic: 78, 785, 7855, 78555, ...
O No
5 pts
Yes
Next >
The sequence is not arithmetic
What is a sequence?
A sequence in mathematics is an enumerated collection of items in which repetitions are permitted and order is important. It, like a set, has members (also called elements, or terms). The length of the series is defined as the number of items (which might be infinite). Unlike a set, the same components can occur numerous times in a sequence at various points, and the order does important. Formally, a sequence may be defined as a function from natural numbers (the sequence's places) to the items at each point. The concept of a sequence may be extended to include an indexed family, which is defined as a function from an arbitrary index set.
The given sequence 78, 785, 7855, 78555, ... is not arithmetic.
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I’m a parent and I’m not sure I’m understanding this question the practice test question says “How would you take apart 14 to solve 28 - 14? The choices are 7 and 710 and 4 12 and 220 and 8. I said 7 and 7
There are several ways of taking apart the number 14:
1 and 13
2 and 12
3 and 11
4 and 10
5 and 9
6 and 8
7 and 7
Nevertheless, as we can see by the note below that exercise,
"Have your child take apart 16 to make a ten to find 87 - 16",
we can conclude that the exercise is asking how to take apart 14 to make a ten. By doing so, the subtraction operation (28 - 14) gets simpler since you could subtract 4, and then subtract the ten:
14 = 10 + 4 (1 ten and 4 units)
So, when we do 28 - 14, we can do that in two steps:
• 28 - 4 = ,24
,• 24, - 10 = 14
Therefore, based on the note below exercise 6, the expected answer is
10 and 4
You have 1/5 of a box of erasers and you need to share them with 3 total people, including yourself. What fraction of the box should each person get?
You have 1/5 of a box of erasers
Number of box of erasers = 1/5.
you need to share them with 3 total people, including yourself
Total number of people = 3 + 1( yourself)
Total number of people = 4
Since, we have to distribute the box of erasers to 4 people
So, divide 1/5 by 4:
[tex]\begin{gathered} \frac{1}{5}\text{ }\div4=\frac{\frac{1}{5}}{4} \\ \frac{1}{5}\text{ }\div4=\frac{1}{5}\times\frac{1}{4} \\ \frac{1}{5}\text{ }\div4=\frac{1}{5\times4} \\ \frac{1}{5}\text{ }\div4=\frac{1}{20} \end{gathered}[/tex]The fraction of the box that each person will get is 1/20
Answer: 1/20
Jenna bought a package of 2 chicken drumsticks. If the package weighed 0.232 kg, what is the average weight of
each drumstick?
Answer:
0.116
Step-by-step explanation:
[tex]\frac{0.232}{2}[/tex] = 0.116
Given the set of all even integers between and including -18 to -6 , what is the probability of choosing a multiple of -6 from this set?1/93/74/9
TheseGiven the set: {-18, -16, -14, -12, -10, -8, -6}
This is 7 numbers
Multiplies of -6 are:
[tex]\begin{gathered} -6\times1=-6 \\ -6\times2=-12 \\ -6\times3=-18 \end{gathered}[/tex]This is 3 numbers
Therefore, the probability is given by:
[tex]P=\frac{multiplies\text{ of }-6}{total\text{ set }}[/tex]So:
[tex]P=\frac{3}{7}[/tex]Answer: 3/7
A governor has been working to decrease the unemployment rate but it has gone up by 3%. In an effort to undermine the governor, a media outlet releases a bar graph comparing the unemployment rate before and after the governor took office.Which of the following tactics did the media outlet use to create this graph?A. Comparison chartsB. SizingC. Missing informationD. Axis and scaling manipulation
From the given graph, let's determine the tactics which the media outlet used to create the graph.
From the graph, we can see that the scaling of the y-axis was manipulated.
The numbers in the y-axis starts from 8%, while a normal graph is suposed to start from 0%.
Although the graph is correct, but the scaling of the y-axis is misleading. This is because when you look at the graph, you will think there is a major difference between unnemployment before and unemployment after.
Therefore, the tactics the media outlet used to create this graph can be said to be Axis and Scaling manipulation.
Axis and scaling manipulation is a method used in producing misleading graphs to make the data look worse or better than it actually is. This method leads to incorrect conclusions,
ANSWER:
D. Axis and Scaling manipulation.
if (x + y) +61 = 2, what is x + y?
The question is given as
[tex](x+yi)+6i=2[/tex]To solve, we need to make (x + yi) the subject of the formula.
To do so, we move 6i to the right-hand side of the equation:
[tex]x+yi=2-6i[/tex]Therefore, OPTION A is correct.
Answer:
(x + yi)= 2-6i
Step-by-step explanation:
Complex numbers
(x + yi) +6i = 2
Subtract 6i from each side
(x + yi) +6i -6i = 2-6i
(x + yi)= 2-6i
Determine (Freshman) Small Cafeteria). Interpret this answer in the context of the situation.
Step 1:
[tex]\text{Probability = }\frac{N\text{umber of required outcomes}}{N\text{umber of total possible outcome}}[/tex]Step 2:
a)
Total possible outcome = 2640
Total number of freshman = 625
[tex]\begin{gathered} P(\text{Freshman) = }\frac{625}{2640} \\ \text{= }\frac{125}{528} \\ \text{= 0.237} \end{gathered}[/tex]Step 3:
b)
Total number of senior and large cafeteria = 350
[tex]\begin{gathered} P(\text{senior and large cafeteria) = }\frac{350}{2640} \\ =\text{ }\frac{70}{528} \\ =\text{ }\frac{35}{264} \\ =\text{ 0.132} \end{gathered}[/tex]Step 4:
c)
Number of Sophomore or student center = 650 + 595 - 125 = 1120
[tex]\begin{gathered} P(\text{Sophomore or student center) = }\frac{1120}{2640} \\ =\text{ }\frac{112}{264} \\ =\text{ 0}.424 \end{gathered}[/tex]Step 5:
d)
[tex]\begin{gathered} p(\text{freshman}|\text{small cafeteria) = }\frac{n(freahman\text{ and small cafeteria)}}{n(small\text{cafeteria)}} \\ =\frac{435}{860}\text{ } \\ =\text{ }\frac{87}{172} \\ =\text{ 0.506} \end{gathered}[/tex]Refer to the rectangle ABCD, shown below, where m(<4)=10degrees. Need help.
From the statement of the problem, we know that:
[tex]m(\angle4)=18^{\circ}\text{.}[/tex]From the diagram, we see that:
1) ∠1 and ∠4 are complementary angles, so they sum up 90°:
[tex]\begin{gathered} m\mleft(\angle1\mright)+m\mleft(\angle4\mright)=90\degree \\ m\mleft(\angle1\mright)=90\degree-m\mleft(\angle4\mright), \\ m(\angle1)=90\degree-18^{\circ}=72^{\circ}\text{.} \end{gathered}[/tex]2) ∠4, ∠3 and a right angle are inner angles of a triangle, so they must sump up 180°:
[tex]\begin{gathered} m(\angle4)+m(\angle3)+90^{\circ}=180^{\circ}\text{.} \\ m(\angle3)=180^{\circ}-90^{\circ}-m(\angle4), \\ m(\angle3)=180^{\circ}-90^{\circ}-18^{\circ}=72^{\circ}\text{.} \end{gathered}[/tex]3) ∠3 and ∠2 are complementary angles, so they sum up 90°:
[tex]\begin{gathered} m(\angle3)+m(\angle2)=90^{\circ}, \\ m(\angle2)=90^{\circ}-m(\angle3), \\ m(\angle2)=90^{\circ}-72^{\circ}=18^{\circ}\text{.} \end{gathered}[/tex]Answer
c. m(∠1) = 72°, m(∠2) = 18°, m(∠3) = 72°.
Can you please help me out with the a question
Arc XY = 2π • (PX)/ 4
. = 2π • 5/4
. = 6.28 • 5/4= 31.40/4 = 7.85
Then answer is
Option G) 7.854
it says find x 110° x and 25° in a triangle
There are two known angles in such a manner:
We know that the sum of internal angles of a triangle is equal to 180 degrees. This means that we can find the missing angle by adding all the internal angles and making it equal to 180
[tex]\begin{gathered} 25+110+x=180 \\ 135+x=180 \\ x=180-135 \\ x=45 \end{gathered}[/tex]The missing angle is 45 degrees.
Given the equations and the table below, what is the first x-value when the y-value of equation 2 is greater than the y-value of equation 1 after the functions first intersect?Equation 1: f(x)=5x^3Equation 2: f(x)=2x+3
the first x value, when the y-value of the equation is greater than the y value of equation one, is x=15
Because the y-value of equation 2 with x=15 is 32771, while the y-value of equation 1 is 16875
Match each expression on the left with its sum on the right. Some answer options on the right will not be used.
To match the expression with the sum, what you have to do is solve each sum.
Remember that to sum/subtract two fractions, both of them should be expressed using the same denominator,
1)
[tex]-\frac{2}{3}+\frac{5}{6}[/tex]The denominators of these fractions are "3" and "6", the least common denominator between both values is 6. To express the first fraction as its equivalent with denominator 6, you have to multiply it by 2:
[tex]-\frac{2\cdot2}{3\cdot2}+\frac{5}{6}=-\frac{4}{6}+\frac{5}{6}[/tex]Now you can proceed to add both fractions:
[tex]-\frac{4}{6}+\frac{5}{6}=\frac{-4+5}{6}=\frac{1}{6}[/tex]The result for this sum is 1/6
2)
[tex]\frac{7}{12}+(-\frac{3}{4})[/tex]First, simplify both symbols, when a plus symbol and a minus symbol and next to each other, the plus sign gets canceled:
[tex]\frac{7}{12}+(-\frac{3}{4})=\frac{7}{12}-\frac{3}{4}[/tex]To subtract both fractions the first step is to express them using the same denominator. The least common denominator between 12 and 4 is 12, to express -3/4 as its equivalent with denominator 12, you have to multiply the fraction by 3:
[tex]\frac{7}{12}-\frac{3\cdot3}{4\cdot3}=\frac{7}{12}-\frac{9}{12}[/tex]Next, subtract both fractions:
[tex]\frac{7}{12}-\frac{9}{12}=\frac{7-9}{12}=-\frac{2}{12}[/tex]The result is no in its simplest form, 2 and 12 are divisible by 2, so to simplify the fraction you have to divide the numerator and denominator by 2:
[tex]-\frac{2\div2}{12\div2}=-\frac{1}{6}[/tex]The result for this expression is -1/6
3)
[tex]-\frac{1}{4}+\frac{3}{8}[/tex]Same as before, the first step is to express both fractions with the same denominator. the least common denominator for both fractions is 8. To express -1/4 as its equivalent with denominator 8, you have to multiply the fraction by 2
[tex]-\frac{1\cdot2}{4\cdot2}+\frac{3}{8}=-\frac{2}{8}+\frac{3}{8}[/tex]Next, add both fractions:
[tex]-\frac{2}{8}+\frac{3}{8}=\frac{-2+3}{8}=\frac{1}{8}[/tex]The result for this sum is 1/8
So the corresponding matches are:
[tex]\begin{gathered} 1)-\frac{2}{3}+\frac{5}{6}=\frac{1}{6} \\ 2)\frac{7}{12}+(-\frac{3}{4})=-\frac{1}{6} \\ 3)-\frac{1}{4}+\frac{3}{8}=\frac{1}{8} \end{gathered}[/tex]Sergio believes he is five years younger than double the age of Chloe and Chloe believes she is five yearsolder than half of Sergio's age. Are they both right?
Let S represent Sergio's age
Let C represent Chloe's age
Sergio believes he is five years younger than double the age of Chloe. This would be expressed as
S = 2C - 5
Chloe believes she is five years older than half of Sergio's age. This means that
C = 5 + S/2
If we multiply the second equation by 2, it becomes
2C = 10 + S
This means that both equations are not the same. Therefore, they are not right
what times what equals 38
To make an open box from a 175cm by 100cm piece of cardboard, equal-sized squares will be cut from each of the four corners and then the sides will be folded up. What is the approximate volume of the largest possible box that can be made?Group of answer choices:A) 324,146 cm^3B)162,073cm^3C) 251,707cm^3D)189,640cm^3
Given that dimensions of the piece of cardboard are:
[tex]\begin{gathered} l=175\text{ }cm \\ w=100\text{ }cm \end{gathered}[/tex]Where "l" is the length and "w" is the width, you can determine that it has the shape of a rectangle.
You know that equal-sized squares will be cut from each of the four corners and then the sides will be folded up. Then, you can make the following drawing:
By definition, the volume of a rectangle is:
[tex]Volume=length\cdot width\cdot height[/tex]In this case, you can set up that:
[tex]\begin{gathered} length=175-2x \\ width=100-2x \\ height=x \end{gathered}[/tex]Therefore, you can write this equation:
[tex]V=(175-2x)(100-2x)(x)[/tex]Expand it:
[tex]V=(175-2x)(100x-2x^2)[/tex][tex]V=(175)(100x)-(175)(2x)-(2x)(100x+(2x)(2x^2)[/tex][tex]V=4x^3-550x^2+17500x[/tex]Now you need to derivate it using the Power Derivative Rule:
[tex]\frac{d}{dx}(x^n)=nx^{n-1}[/tex]Then:
[tex]V^{\prime}=(4)(3)x^2-(550)(2)x+17500[/tex][tex]V^{\prime}=12x^2-1100x+17500[/tex]Make the equation equal to zero and sove for "x":
[tex]12x^2-1100x+17500=0[/tex]Use the Quadratic Formula:
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]Substituting:
[tex]\begin{gathered} a=12 \\ b=-1100 \\ c=17500 \end{gathered}[/tex]You get:
[tex]\begin{gathered} x_1\approx20.49 \\ x_2\approx71.18 \end{gathered}[/tex]Therefore, you can make the following Sign Chart:
Then, you can substitute these:
[tex]\begin{gathered} x=20 \\ x=50 \\ x=72 \end{gathered}[/tex]Into the factorize form of the derivated function:
[tex]V=(x+\frac{275-25\sqrt{37}}{6})(x-\frac{275+25\sqrt{37}}{6})[/tex][tex]V=(x+\frac{275-25\sqrt{37}}{6})(x-\frac{275+25\sqrt{37}}{6})[/tex]Araceli filled a cone-shaped container with a variety of colored sand to give as a gift to a friend. The volume of a cone is represented by the expression below, where r is the radius of the base of the cone and h is the height of the cone.radius = 3 1/23 5/3 is the height
The volume of the cone is 45.28 cubic inches.
The amount of sand inside the cone is measured by its volume.
Based on the numbers for the radius and height, the cone's volume is 45.28 cubic inches.
The volume of a cone is the measure of how much space a cone takes up. Cone height and base radius both affect how much space the cone takes up.
The volume of the cone is given by V = [tex]\frac{1}{3}\pi r^{2} h[/tex]
The value of the radius is r = [tex]3\frac{1}{23} = \frac{70}{23}[/tex]
The value of Height is h = [tex]3\frac{5}{3} = \frac{14}{3}[/tex]
So, the Volume of the cone =[tex]V =\frac{1}{3}\pi r^{2} h[/tex]
[tex]V =\frac{1}{3}\pi r^{2} h\\\\V = \frac{1}{3}\pi (\frac{70}{23}) ^{2} \frac{14}{3} \\\\V = 45.28[/tex]
The volume of the cone is 45.28 cubic. inches
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Endpoint: (1,3) Midpoint: (-2,5) Please I need help ASAP
How to solve this problem? (the answer is 262 Hz). i want to know the step by step on how to solve the equation given. if it helps, i am a grade 10 student. (YES, this is a MATH problem)
The frequency of middle C = 262 Hz
Explanation:The formula for calculating the frequency, F hertz, of a note n seminotes above the concert pitch is:
[tex]F\text{ = 440(}\sqrt[12]{2})^n[/tex]This can be re-written as:
[tex]F=440(2^{\frac{n}{12}})[/tex]Middle C is 9 semitones below the concert pitch
That is, n = -9
To find the frequency of middle C, substitute n = -9 into the equation for F
[tex]\begin{gathered} F=440(2^{\frac{-9}{12}}) \\ F\text{ = 440(}0.5946) \\ F\text{ = }261.62\text{ Hz} \\ F\text{ = 262 Hz (to the nearest hertz)} \end{gathered}[/tex]The frequency of middle C = 262 Hz
Question 2 Multiple Choice Worth 2 points)(08.07 LC)Two friends are reading books. Jimmy reads a book with 21,356 words. His friend Bob reads a book with one-and-a-half times as many words. Which expressionrepresents the number of words Bob reads?O 21,356 x 2O 21,356 x6 x 1nents1adesO 21,356 xO 21.356 x112Question 3 Multiple Choice Worth 2 points)(08.07 LC)Question 1 (Answered)OVIOUS QuestionNexd Quest
The number of words of the book Jimmy reads os 21,356, and the number of words of the book Bob reads is one-and-a-half times (that is, 1.5x) as many words, so to find the number of words Bob reads, we just need to multiply the number of words of Jimmy's book by the factor of 1.5:
[tex]21356\cdot1.5=32034[/tex]In one year, the CPI increased from 106.3 to 108.9. How much money was required at the end of the year in order to have the same purchasing power as $1,000 at the beginning?
Based on the increase in CPI, the amount that would be required at year end to have the same purchasing power at the beginning of the year is $1,024.46.
How to find the change in purchasing power?First, find the inflation rate:
= (Current CPI - Beginning CPI) / Beginning CPI
= (108.9 - 106.3) / 106.3
= 2.446%
This means that the amount of money at the beginning of the year has lost a value of 2.446%.
In order to remain the same as the value of $1,000, a person would need:
= 1,000 x (1 + 2.446%)
= $1,024.46
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in health class, the students were asked what grain they prefered in their breakfast cereal. The results are shown in the table. what's the probability that a randomly chosen student in the health class listed oats as their favorite grain?A. 20%B. 25%C. 35%D. 14%
To find the probability of a randomly choosen student listing oats as its favorite grain, divide the number of students that chose oats by the total number of students and multiply the fraction by 100%.
To find the total number of students, add the numbers under each cereal:
[tex]12+14+8+6=40[/tex]The number of students who chose oats, is 14. Then, the requested probability, is:
[tex]\frac{14}{40}\times100=35\text{ \%}[/tex]From the diagram below, given the side lengths marked, and if we know that < C is congruent to < F, we can say that ___
SAS Similarity Theorem: If two sides in one triangle are proportional to two sides in another triangle and the included angle in both are congruent, then the two triangles are similar.
AC is proportional to DE while BC is proportional to FE, but F is not the included angle between those sides, therefore, those triangles are not similar by SAS.
The Angle-Side-Angle Postulate (ASA) states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent. Since we have information only about one of the angles, ASA also doesn't apply.
For two triangles to be congruent, all of their measures must be congruent, which is not the case of our triangles.
The answer is option d. The two cannot be proven to be similar.
I got the picture and will send it to you show the coordinates of the points that create the shape of the image
We have the following:
[tex]\begin{gathered} P(1-1,-3+3)\rightarrow P^{\prime}(0,0) \\ Q(3-1,-1+3)\rightarrow Q^{\prime}(2,2) \\ R(4-1,-3+3)\rightarrow R^{\prime}(3,0) \end{gathered}[/tex]now,
The answer is:
8. In order to reach the top of a hill which is 250 feet high, one must travel 2000 feet straight up a road
which leads to the top. Find the number of degrees contained in the angle which the road makes with the
horizontal.
7.18° the angle which the road makes with the horizontal.
Define Trigonometric functions
The trigonometric functions are real functions which relate an angle of a right-angled triangle to ratios of two side lengths.
Given,
Height of hill = 250 feet
Length of the slope = 2000 feet
find the angle,
we know, sin(x) = perpendicular / hypotenuse
sin(x) = 250 / 2000
x = sin^-1 (0.125)
x = 7.18°
Hence, 7.18° the angle which the road makes with the horizontal.
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3. The function f(x) has the coordinates below. State the changes made to f(x) which result in the function g(x). Write the (x,y) rule that would transform the coordinates of f(x) to the coordinates of g(x). g(x) = -2f(x + 1) - 4
Problem
The function f(x) has the coordinates below. State the changes made to f(x) which result in the function g(x). Write the (x,y) rule that would transform the coordinates of f(x) to the coordinates of g(x). g(x) = -2f(x + 1) - 4
Solution
From this table we know that
f(-1) = 5, f(2) = 1, f(6)=0
The rule for this case would be:
y= 13/84x^2 -125/84x +47/14
We also know that we have the following transformation
g(x) = -2f(x + 1) - 4
The corresponding coordinates of x on g(x) are:
0, 3, 7
So we have this:
f(0) = 47/14
f(3)= 2/7
f(7) = 11/21
And the corresponding y coordinates are:
-2(47/14) -4=-75/7
-2(2/7) -4=-3277
-2(11/21) -4=-106/21
I attached the questions as images. The first image is actually the second.You can send in the work on paper like the graphing part.The questions can be typed on the solution tab or messages whichever is easier for you.Thanks again for the help :)
SOLUTION
Consider the image below,
The lenght of the compass is the radius, using a lenght of 5 unit, we have circle below as the sphere .
Where
[tex]\begin{gathered} r=\text{ radius, O= origin } \\ And \\ r=5\text{unit } \end{gathered}[/tex]Using the formula, we have
[tex]\begin{gathered} \text{Volume of sphere} \\ =\frac{4}{3}\pi r^3 \\ \text{where} \\ \pi=3.14,\text{ r=}5 \end{gathered}[/tex]Substitute into the formula, we have
[tex]\begin{gathered} \text{Volume of the sphere is } \\ =\frac{4}{3}\times3.14\times5^3 \\ \text{Hence } \\ 523.33\text{ cubic unit} \end{gathered}[/tex]Therefore
The volume of the sphere is 523.33 cubic unit
Lines AD and BC are parallel. What is the angle measurement of Angle DAE(Point A)?D150°45°BсFYour answer
Solution
For this case we can find the angle:
m < ECB = 30º
And we can find the angle CEB and we got:
m < CEB = 180 -30 - 45 = 105
And then the angle DAE would be:
m < DAE = 30º
