Recall the postulates of kinetic-molecular theory. Read the list and check all the statements that apply to the behavior of an ideal gas:1. gas particles behave like hard spheres2. gas particles travel randomly3. gas particles are attracted to each other4. energy is lost when gas particles collide 5. average kinetic energy of a collection of gas particles depends on the temperature6. gas particles occupy most of the space within a container7. gas particles have mass and volume
Answers
Answer:
Chemistry - States of matter - Kinetic Molecular Theory
This is the theory that explains the states of the matter and is based on the idea that matter is composed of tiny particles that are always on motion.
Part 1: Check all the statements that apply to the behavior of an ideal gas
The behaviors that apply are:
1.Gas paarticles behave like hard sphares.
2.Gas particles travel randomly.
5. Average kinetic energy of a collection of gas particles depends on the temperature.
Part 2: According to kinetic-molecular theory the one that would not be considered an ideal gas is:
A gas with highly polar molecules that have very strong intermolecular forces.
This is because the theory consideres thhat there are no forces of attraction of repultion between gas particles.
Related Questions
10. When a metal atom combines with a nonmetal
atom, the nonmetal atom will
A. lose electrons and decrease in size
B. lose electrons and increase in size
C. gain electrons and decrease in size
D. gain electrons and increase in size
Answers
When a metal atom combines with a nonmetal atom, the nonmetal atom will gain electrons and decrease in size
What happen when metal react with non metal ?In a reaction between metals and non-metals, electrons are moved from the metal atoms to the non-metal atoms, resulting in the formation of ions. An ionic compound is the name given to the resulting substance.
Ions are created when metals and non-metals interact because the metal atoms' electrons are transferred to the non-metal atoms.The end result of this procedure is an ionic compound. Metal atoms provide their electrons to non-metal atoms. Metal atoms change into positive ions, whereas non-metal atoms change into negative ions.Learn more about Metals and non metal here:
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how many grams of CO2 are in 5.67 moles of CO2
Answers
The International System of Units uses the mole (symbol: mol) as the unit of substance amount.
In 5.67 moles of CO2 there exists 249.48 grams of CO2.
How to calculate grams in moles?Start by dividing the number of atoms by the atomic weight of each component of the compound to convert grams to moles. After that, tally up all of your responses to determine the compound's molar mass. The final step is to calculate the number of moles by dividing the number of grams of the compound by its molar mass.
The International System of Units uses the mole (symbol: mol) as the unit of substance amount. How many elementary entities of a particular substance are present in an object or sample is determined by the quantity of that substance.
Let the equation be
Mass = relative atomic mass × mole number
substitute the values in the above equation, we get
= 5.67 × (12 + 16 + 16)
= 249.48 g
Therefore, there exists 249.48 grams of CO2 are in 5.67 moles of CO2.
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Katarina is a forensic scientist who finds a stain at a crime scene. What is the first thing she should do?
A.
Build a small frame around the area.
B.
Scrape the substance into a plastic bag.
C.
Make a sketch of the stain in a notepad.
D.
Determine if the substance is blood.
Answers
When Katarina finds a stain at a crime scene the first thing she should do is to scrape the substance into a plastic bag. That is option B.
Who is a forensic scientist?A forensic scientist is a professionally trained individual that applies their knowledge in the field of criminology by using evidence found on the crime scene to narrow down a suspect.
When a stain is being noticed by the forensic scientist, the first step should be to secure the stain for further investigation.
To secure the stain, the scientist should scrap the stain into a plastic bag and this should be taken to the laboratory for further evaluation and investigation.
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Classify the following compounds as alkane, alkene, alkyne based on the given structure
Answers
We have the next compounds
And we must classify them as alkane, alkene, alkyne.
We need to know that
- Alkane: They are the simplest hydrocarbons, containing only carbon and hydrogen held together by single bonds.
- Alkene: Alkenes are hydrocarbons that contain a double bond.
- Alkyne: Alkynes are hydrocarbons that contain a triple bond.
1. We can see that the structure has a double bond. So, it is an Alkene.
2. We can see that the structure has a triple bond. So, it is an Alkyne.
3. We can see that the structure has a double bond. So, it is an Alkene.
4. We can see that the structure has a triple bond. So, it is an Alkyne.
ANSWER:
1. Alkene
2. Alkyne
3. Alkene
4. Alkyne
A student finds two green powders that look the same. He wants to figure out if the two powders are the same or different substances. Which of the following is
the best method to use?
I temperature of each powder
Mix the two green powders together and then test the properties.
Answers
A student finds two green powders that look the same he wants to figure out if the two powders are the same or different substances then mix the two green powders together and then test the properties
A powder is a dry bulk solid composed of many very fine particles that may flow freely when shaken or tilted and to figure out unknown two mixture powder are same or different then student want to mix the two green powders together and then test the properties because of properties student the two unknown powder are to be determined
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How many milliliters of 0.100M NaOH are required to neutralize the following solution 5.00mL of.0500M HCI
Answers
1) Set the chemical equation
[tex]\text{NaOH + HCl = NaCl + H}_2O[/tex]2) Find out how many moles of HCl react in the solution.
[tex]\text{moles of HCl = }\frac{0.0500\text{ M}}{\square}\cdot\frac{5.00\text{ mL}}{\square}\cdot\frac{1\text{ L}}{1000\text{ mL}}=\text{ 0.00025 moles of HCl}[/tex]3) Find out how many moles of NaOH reacted with HCl
[tex]\text{moles of NaOH = }\frac{0.00025\text{ moles of HCl}}{\square}\cdot\frac{1\text{ mole of NaOH}}{1\text{ mole of HCl}}=\text{ 0.00025 moles of NaOH}[/tex]4) Find out the milliliters of NaOH
[tex]mL\text{ of NaOH = }\frac{0.00025\text{ moles of NaOH}}{0.100\text{ M}}\cdot\frac{1000\text{ mL}}{1\text{ L}}\text{= 2.50 mL}[/tex]Complete the balanced dissociation equation for the compound below. If
the compound does not dissociate, write NR after the reaction arrow.
LiOH(s) →
Answers
LiOH ⇌ Li + + OH - NR
When there are too many OH ions, water dissociates fully to the left, possibly leaving only Li + and OH ions and H 2 O molecules.
IN CHEMISTRY, WHAT IS AN ION?An atom or collection of atoms that is classified as an ion as a different number of electrons than proton atoms. The particle is a positive ion, also known as a cation, if the number of electrons is smaller than the number of protons.
How do ions form?Ions are created when there are more protons in an atom than electrons, which is the case in all atoms. An atom that has gained or lost one or more electrons, and as a result has a negative or positive charge, is what is referred to as an ion. Exchanging electrons between atoms or molecules is the process of ionization.
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A 25.0 mL solution of HNO₃ is neutralized with 31.4 mL of 0.250 M Ba(OH)₂. What is the concentration of the original HNO₃ solution?
Answers
The concentration of the 25ml of original HNO₃ solution that was neutralized with 31.4 mL of 0.250 M Ba(OH)₂ is 0.628 M HNO3
The neutralization reaction involved with HNO₃ and Ba(OH)2 is
Ba(OH)₂ + 2HNO₃---> Ba(NO₃) + 2H₂O.
From the balanced equation of the reaction, we can say that to neutralize barium hydroxide (Ba(OH)₂) we would require 2 moles of Nitric acid (HNO₃)
By multiplying concentration of barium hydroxide by volume its volume, and then multiplying by 2 as twice is required we would get the moles of HNO3 that is equivalent to 2 moles based on the values
Moles of HNO₃ = 2 (0.0314 * 0.250) = 0.0157 moles
Concentration of the original HNO₃ solution = 0.0157 moles / 0.025 L = 0.628 M HNO₃
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Calculate the mass (in g) of 5.86x10^20 SO3 molecules.
Answers
Answer
0.0779 g SO₃
Procedure
To solve this question, you will need to use the Avogadro's number equivalent to 6.02214 x 10^23 molecules/ mol, and then the molecular weight in grams per mole for the SO₃.
[tex]5.86\times10^{20}\text{ molecules SO}_3\frac{1\text{ mol SO}_3}{6.02214\text{ x 10}^{23}\text{molecules SO}_3}\frac{80.06\text{ g SO}_3}{1\text{ mol SO}_3}=0.0779\text{ g SO}_3[/tex]Calculate the imperial formula of the compound. Express your answer as a chemical formula.
Answers
The empirical formula corresponds to the simplest form of expressing a compound, it indicates the proportion of atoms in the molecule.
We have two elements S and F and they give us the mass resulting from the decomposition of the molecule. We can find the moles of each element using the atomic weight of each element as follows:
[tex]\begin{gathered} \text{Moles S= Given g of S}\times\frac{1\text{ mol S}}{AtomicWeight,\text{ g S}} \\ \text{Moles S= 0.905 g of S}\times\frac{1\text{ mol S}}{32.065\text{ g S}}=0.028\text{mol S} \end{gathered}[/tex][tex]\begin{gathered} \text{Moles F= Given g of F}\times\frac{1\text{ mol F}}{AtomicWeight,\text{ g F}} \\ \text{Moles F=3.221 g of F}\times\frac{1\text{ mol F}}{18.998\text{g F}}=0.170\text{mol F} \end{gathered}[/tex]To find the ratio between the elements we divide the moles of each element by the smallest number of moles found, that is by 0.028 moles.
[tex]\begin{gathered} S\rightarrow\frac{0.028}{0.028}=1 \\ F\rightarrow\frac{0.170}{0.028}=6 \end{gathered}[/tex]Therefore the empirical formula of the compound will be:
[tex]SF_6[/tex]What is the percent mass of 42.5 g KCl dissolved in 122.5 g water?
Answers
Answer
% mass of KCl = 25.76%
Explanation
Given:
mass of KCl = 42.5 g
mass of water = 122.5 g
Required: The % mass of KCl
Solution:
Step 1: Calculate the total mass
42.5 g + 122.5 g = 165 g
Step 2: Calculate the % of KCl
%KCl = (42.5/165)*100
%KCl = 25.76%
Why is reproducibility so important to scientistis
Answers
Answer: They serve as proof that an established and documented work can be verified, repeated, and reproduced.
Explanation: Reproducibility and research integrity are essential tenets of every scientific study and discovery. They serve as proof that an established and documented work can be verified, repeated, and reproduced. New knowledge in biomedical science is built on the shoulders of established and proven principles.
Answer:
Evidence of accuracy
Explanation:
it creates new opportunities for insights and facilitates innovation in terms of scientific knowledge.
find the natural logarithm of7.56
Answers
In a graph:
The 946 mL of Gatorade bottle contains FD&C Blue I at concentration of 0.100mg/L. Molar mass of Blue I is 792.84 g/mol.
a) Calculate the molarity of Blue I in Gatorade.
b) How many molecules of Blue I would you consume by drinking the entire bottle of Gatorade.
Answers
The molarity of Blue I in Gatorade is 0.00010 mol L⁻ molecules of Blue I would you consume by drinking the entire bottle of Gatorade is 4.77 mol
Molarity is the amount of substance in certain volume of solution and also moles of solute per liter of solution
Here given data is
Volume = 946 mL
Molar mass = 792.84 g/mol
Concentration = 0.100mg/L
We have to find molarity and molecules of Blue I would you consume by drinking the entire bottle of Gatorade = ?
Molarity = number of moles of solute/volume of solution
Molarity = 0.100mg/L/946 mL
Molarity =0.00010 mol L⁻
Now we have to find molecules of Blue I = ?
Molecules of Blue I = 792.84 g/mol × avagadro number
Avagadro number = 6.022×10²³
Molecules of Blue I = 792.84 g/mol×6.022×10²³
Molecules of Blue I = 4.77 mol
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In the reaction 2H2 + O2 →2H2O if 14grams of H2 react, how many grams of water could be produced?
Answers
Answer:
Explanation:2H2 + O2 —-> 2H2O
The mole ratio of H2 to H2O is 2 : 2 = 1:1
4 moles of H2 = 4 moles of H2O
Moles of H20 = 4mol
Molar mass of H2O = 18g/mol
Mass = moles X Molar mass
= 4mol x 18g/mol
= 72g
0.650 moles of O₂(g) are added to 1.00 L flask and the internal pressure is measured at 20.00 atm. What is the temperature of the gas under these conditions (in *C)?___ °C ?
Answers
Answer:
T = 101.96 degrees
Explanation:
We are given the following
Number of moles = 0.650 mol
Volume = 1.00 L
Pressure = 20.00 atm
We are going to use the ideal gas low which is given by:
pV = nRT
Therefore:
[tex]T\text{ = }\frac{pV}{nR}[/tex]We know R = 0.08206 L.atm/Kmol
[tex]\begin{gathered} T\text{ = }\frac{20\ast1}{0.65\ast0.08206} \\ T\text{ = 374.960 K} \end{gathered}[/tex]T(in degrees) = 374.96 - 273
= 101.96 degrees
If a student did an experiment were they mixed 25 mL of HCl (0.5M) and 7.4g of sodium bicarbonate together How many moles of carbon dioxide would be generated at STP? Show your balanced equation aswell.
Answers
The first thing will be to finish the reaction that happens in the experiment to the reactional HCl and sodium bicarbonate (NaHCO3). The balanced reaction is the following:
[tex]NaH_{}CO_3+HCl\rightarrow NaCl+H_2O+CO_{2(g)}[/tex]Now, we must determine which is the limiting reactant. To do this we are going to convert all the data they give us to moles.
For HCl we are given the molarity, so the moles will be:
[tex]\begin{gathered} \text{Molarity}=\text{ }\frac{\text{Moles of solute}}{L\text{ of solution}} \\ \text{Moles of solute= Molarity}\times L\text{ of solution} \\ \text{Moles of solute=}0.5M\times(25mL\times\frac{1L}{1000mL}) \\ \text{Moles of solute=}0.0125\text{ mol HCl} \end{gathered}[/tex]Now the moles of sodium bicarbonate are found using its molar mass:
[tex]\begin{gathered} \text{Moles }NaHCO3=\text{Given g }NaHCO3\times\frac{1molNaHCO3}{Molar\text{ mass, g}NaHCO3} \\ \text{Moles }NaHCO3=7.4g\times\frac{1moNaHCO3}{84.007gNaHCO3} \\ \text{Moles }NaHCO3=0.0880\text{mol }NaHCO3 \end{gathered}[/tex]By stoichiometry, we have that one mole of NaHCO3 reacts with one mole of HCl. We have more moles of NaHCO3 than HCl. Therefore, HCl will be the limiting reactant.
So the reaction will occur according to the number of moles of HCl. Now the ratio between HCl and CO2 gas formed is 1 to 1. For one mole of HCl that reacts, 1 mole of CO2 will be formed.
so, the number
Given the following, find the number of grams 0.3672 moles SmO
Answers
Answer:
61.09 grams SmO
Explanation:
To find the number of grams SmO, you need to multiply the moles by the molar mass of SmO. The molar mass is a ratio which represents the mass of SmO per every 1 mole. It is important to arrange the ratio in a way that allows for the cancellation of units (moles should be in the denominator). The final answer should have 4 sig figs like the given value (0.3672 = 4 sig figs).
Atomic Mass (Sm): 150.36 g/mol
Atomic Mass (O): 15.999 g/mol
Molar Mass (SmO): 150.36 g/mol + 15.999 g/mol
Molar Mass (SmO): 166.359 g/mol
0.3672 moles SmO 166.359 grams
-------------------------------- x -------------------------- = 61.09 grams SmO
1 mole
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Why does an atom want to form an octet or duet?And yes I know these rules and I know that it “wants” a stable electronic configuration and a filled shell.
Answers
Answer
An atom wants to form an octet or duet because an atom always wants to be in the most stable form. For any atom, stability is achieved by following the octet rule or duet rule, which is to say all atoms (with a few exceptions) want 8 electrons (octet) or 2 electrons (duet) in their outermost electron shell just like noble gases.
a sample of a gas is at STP and it’s temperature remains constant. if the pressure decreases what will happen to the volume
Answers
Explanation
There are said to have two different conditions of a gas.
First condition is STP which means: pressure = 1 atm and temperature (absolute) = 0 °C + 273 = 273 K
-------------
It is said that the temperature remains constant, therefore we can apply Boyle's law which states that the pressure of a gas tends to decrease as the volume of the container increases.
Synthesize Information If you calculate the percent composition of elements in a compound, is there enough information to determine the empirical formula for the compound? If yes, how? If no, improve the model by identifying and explaining additional information needed to identify the compound.
Answers
If you only have the percent composition of each element in a give compound, you can't determine yet the empirical formular for the compound. The problem is, the percent composition only gives relative numbers for each element. What can be determined is the empirical stochiometry of one element relative to the others.
For example, supose you have a compound with element X and Y, with the percent composition you can determine how much X you have relative to how much Y you have. Say you determine that for each 2 X you have 3 Y, the formula can be X₂Y₃ but it can also be X₄Y₆ or even othre possibilities.
To determine the empirical formula you need to know how many of one of the elements you have in each compound. A common way of getting the empirical formula is to use the percent composition and, in addition, the molar mass of the compound, which will make it possible to get the empirical formula from the relative ratios of each element you have.
A balloon filled to 2.0 L here in Michigan (at 20°C and 752 mmHg) is taken to the top of Mt. Everest. The pressure at the top of Mt. Everest is 253 mmHg, and the balloon grows to a size of 5.1 L. What is the temperature (in °C) at the top of Mt. Everest?
Answers
tellsTo answer this question we can use the Combined Gas Law, which tell us that the pressure, volume, and temperature of one situation is equal to the second situation, now let's see how is this formula and how can we apply it to our question:
P1 * V1/T1 = P2 * V2/T2
Now in your question:
1 * 2/20 = 0.33 * 5.1/T2 (I did the transformation mmHg - atm, that makes the question easier, so 752 mmHg = roughly 1 atm and 253 mmHg = 0.33 atm)
2/20 = 1.683/T2
0.1 = 1.683/T2
T2 = 16.8°C
Classify each of the following chemical reactions as a synthesis decomposition and single displacement or double displacement reaction
Answers
1. Synthesis reaction : there is only 1 product formed from 2 or more reactant
E.g:
[tex]H_2(g)+N_2(g)\text{ }\Rightarrow2NH_3(g)\text{ }[/tex]2. Decomposition : reaction that occurs in presence of UV light and only 1 reactant that decomposes into 2 or more products.
E.g:
[tex]CH_3Br(g)+UV_{light}\Rightarrow CH_3(g)\text{ + Br (g)}[/tex]3. Single displacement : reaction that occurs when 1 reactant displaces other reactant from its compound:
E.g:
[tex]Zn(s)+CoCl_2(aq)\text{ }\Rightarrow ZnCl_2(aq)\text{ + Co(s)}[/tex]4. Double displacement : reaction that occurs when both reactant displaces each other.
E.g :
[tex]K_2S(aq)+Co(NO_3)_2\Rightarrow2KNO_3(aq)\text{ + }CoS(s)\text{ }[/tex]Please help with Chemistry I'm confused at the elements reactivity:
Question:
Which of the following combination of elements is the most reactive?
Answer options:
A: Potassium and Iodine
B: Caesium and Iodine
C: Sodium and Bromine
D: Caesium and Bromine
Answers
The combination of elements that is the most reactive would be caesium and bromine.
Reactivity of metals and non-metalsThe reactivity series of elements is a table that shows how reactive elements are, usually in descending order.
Elements are classified as metals, non-metals, and metalloids. Metals or non-metals that are at the top of the reactivity series are highly reactive and cannot be displaced in solution by metals below them.
Highly reactive non-metals are also usually at the top of the reactivity series of non-metals. They are able to form compounds with a wide variety of elements.
A typical reactivity series of metals include caesium, rubidium, potassium, sodium, lithium, etc. A reactivity series of non-metals include fluorine, chlorine, oxygen, bromine, iodine, etc.
Thus, bromine is more reactive than iodine and caesium is more reactive than potassium and sodium.
The combination of elements that are the most reactive among the options is, therefore, Caesium and Bromine.
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(The question is in the photo Sorry Lol) What volume of chlorine gas at 36.0°C and 1.74 atm is needed to react completely with12.0 g of sodium to form NaCl?Answer in units of L
Answers
3.786137931L of chlorine are needed.
1st) It is necessary to write the balanced equation of the reaction between chlorine gas (Cl2) and sodium (Na) to produce sodium chloride (NaCl):
[tex]2Na+Cl_2\text{ }\rightarrow\text{ 2 NaCl}[/tex]Now we know that 1 mol of chlorine gas is needed to react with 2 moles of sodium in the production of sodium chloride. With the molar mass of Na (23.0g/mol) and Cl2 (71.0g/mol), we can see that 71.0g of Cl2 are needed to react with 46.0g of sodium.
2nd) Knowing that 71.0g of Cl2 are needed to react with 46.0g of sodium, we can use a mathematical rule of three to calculate the amount of Cl2 that will react completely with 12.0g of sodium:
[tex]\begin{gathered} 46.0\text{gNa}-71.0gCl_2 \\ 12.0\text{gNa}-x=\frac{12.0\text{gNa}\cdot71.0Cl_2}{46.0\text{gNa}} \\ x=18.5gCl_2 \end{gathered}[/tex]3rd) Now it is necessary to convert the mass of chlorine gas into moles, so we can use it in the Ideal gas formula:
[tex]\begin{gathered} 71.0gCl_2-1mol \\ 18.5gCl_2-x=\frac{18.5gCl_2\cdot1mol}{71.0gCl_2} \\ x=0.26\text{mol} \end{gathered}[/tex]So, 0.26 moles of chlorine gas are needed.
4th) With the formula of Ideal gases and replacing the values of Pressure (P), number of moles (n) and Temperature (T, in Kelvin), we can calculate the volume of Cl2:
[tex]\begin{gathered} P\mathrm{}V=n\mathrm{}R\mathrm{}T \\ 1.74atm.V=0.26mol\cdot0.082\frac{atm\cdot L}{\text{mol}\cdot K}\cdot309K \\ V=\frac{0.26mol\cdot0.082\frac{atm\cdot L}{\text{mol}\cdot K}\cdot309K}{1.74atm} \\ V=3.786137931L \end{gathered}[/tex]Finally, 3.786137931L of chlorine are needed to react completely with 12.0g of sodiu.
What's the difference between ionization and dissociation?
Question options:
A)
Ionization breaks ionic bonds, and dissociation breaks covalent bonds.
B)
Ionization involves complete breakdown, while dissociation is only partial.
C)
Ionization breaks covalent bonds, and dissociation breaks ionic bonds.
Answers
The difference between ionization and dissociation : Ionization breaks ionic bonds, and dissociation breaks covalent bonds.
Ionization breaks the ionic bond into its constituent ions while dissociation is breaking of bond into its simple constituent. Ionization is a irreversible process and dissociation is reversible process. The bond involves in the process of ionization is ionic bond and the bond involved in the process of dissociation is the covalent bond. The compound related to ionization is ionic compound and the compounds related with dissociation is covalent compound.
Thus, The difference between ionization and dissociation :
(A) Ionization breaks ionic bonds, and dissociation breaks covalent bonds.
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2A + C + D + EDetermine the enthalpy(AH)in kJ of the above reaction using the reactions below:1B → C AH = 415.3 kJA + 1B →D AH = -95.7 kJ6A ->6E AH = 207.9 kJ
Answers
Explanations:
• We will follow Hess's Law of Constant Heat Summation:
(that states that if a reaction occurs in more than one route, then the the total enthalpy change for the reaction is the sum of all changes.)
For reaction :
[tex]\begin{gathered} B\Rightarrow C\text{ }\Delta H\text{ = 415.3 kJ }\ldots\text{.}\mathrm{}(\text{ reaction 1)} \\ A+B\text{ }\Rightarrow\text{ D }\Delta H\text{ = -95.7kJ}\ldots.(\text{ reaction 2 ) } \\ 6A\text{ }\Rightarrow6E\text{ }\Delta H\text{ = 207.9kJ }\ldots\ldots(\text{reaction 3 ) } \end{gathered}[/tex]∆H total =( reaction 3 )/6 +reaction 2 - reaction 1this can be expressed as :
[tex]\begin{gathered} \Delta H_{total\text{ }}=\text{ }\frac{207.9}{6\text{ }}+(-95.7\text{ ) - 415}.3\text{ } \\ \text{ = 34.65 -95.7 -415.3} \\ \text{ =-476.35kJ} \end{gathered}[/tex]This means that ∆H total= -476.35kJ.
I’m not sure and I’m kind of confused can anyone help?
Answers
We will reconstruct the model in the following manner :
From the above diagram we can see that :
• number of Carbon atom = 3
• number of hydrogen atom = 8
• rewrite this in an alphabetical order, you get :
[tex]\begin{gathered} C_3H_8\text{ } \\ \Rightarrow Propane\text{ } \end{gathered}[/tex]the molecule has a chemical formula = C3H8Given the equation below, how many moles of nitrogen gas (N2) areneeded to react with 7.5 moles of hydrogen gas (H2)?N2+ 3H2 —>2 NH3
Answers
Answer
2.5 moles of N₂ are needed to react with 7.5 moles of hydrogen gas
Explanation
Given:
Equation: N₂ + 3H₂ → 2NH₃
Moles of H₂ = 7.5 moles
What to find:
The moles of nitrogen gas (N₂) needed to react with 7.5 moles of hydrogen gas
Step-by-step solution:
Let the mole of N₂ needed be x.
From the given balanced chemical equation:
3 moles of H₂ react with 1 mole of N₂
Therefore, 7. 5 moles of H₂ will react with x moles of N₂
Cross multiply
[tex]\begin{gathered} x\text{ moles }N_2\times3\text{ moles H}_2=7.5\text{ moles H}_2\times1\text{ mole N}_2 \\ \text{Divide both sides by 3 moles H}_2 \\ \frac{x\text{ moles }N_2\times3\text{ moles H}_2}{3\text{ moles H}_2}=\frac{7.5\text{ moles H}_2\times1\text{ mole N}_{2}}{3\text{ moles H}_2} \\ x\text{ moles }N_2=2.5\text{ moles} \end{gathered}[/tex]Write the correct formula for the following compound:
magnesium hydroxide
Answers
The formula of magnesium hydroxide is Mg(OH)2.
How magnesium hydroxide?Magnesium hydroxide is an inorganic compound having the chemical formula of Mg(OH)2. It is present in nature as mineral brucite. It is a white solid substance with low solubility in water. Magnesium hydroxide is a component of antacids such as milk of magnesia. Extended use or overuse of this medication for constipation results in dependence on laxatives and constipation. Overuse of Magnesium hydroxide also causes diarrhea that does not go away, dehydration, and mineral imbalances. Severe nausea, vomiting, or diarrhea are the symptoms of using a high dose of magnesium hydroxide. After using a medicine such as a laxative, nausea, vomiting or diarrhea can be cured.
So we can conclude that Mg(OH)2 is the correct formula for magnesium hydroxide.
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