Answer:
D. Newton's third law of motion
Plants in the rainforest
that was a little random
Which of the following is a correct description of an atom?
A. A very small particle that holds a positive or negative charge depending upon the element
B. A mixture of protons and electrons surrounded by neutrons in very tight orbits
C.A very small particle that's the same for every element
D. The smallest particle of an element that still keeps the properties of that element
Answer:
A it makes sense
Explanation:
The best description of an atom is that it is A very small particle that holds a positive or negative charge, depending upon the element. Hence, option A is correct.
What is an Atom?The smallest unit of matter that can be divided with releasing charged particles is the atom. It is also the smallest bit of matter with chemical substance properties. As a result, the atom is the basic building block of chemistry.
Examine the many-electron-electron arrangements in the electron shells around the atom's nucleus.
A large portion of a molecule is empty space. The remainder of the structure, which is composed of neutrons and protons, is surrounded by a cloud of negatively charged electrons, while the nucleus itself has a positive charge.
Therefore, for an atom, the best description is that it is a very small particle that hold charge depending on the element.
To know more about Atom:
https://brainly.com/question/13654549
#SPJ2
Which has bigger inertia? Why? Elephant or ant sumo fighter or toddler pickup truck or 16 wheeler.
Answer:
16 wheelerExplanation:
"Inertial mass is a measure of an object resistance to acceleration when a force is applied. the inertial is a function of the mass of a body.
Given the following
1. Elephant
2. Ant sumo fighter
3. Toddler pickup truck
4. 16 wheeler.
The body of greater mass has greater inertia.
Of all the 4 items in the list, the 16 wheeler has the largest mass, hence it also has the greater inertial
HELPPPP QUESTION IS ABOVE
Answer:
discount rate
Explanation:
i could be wrong but i believe thats what it is
Three charges are enclosed inside a spherical closed surface. The net flux through the surface is −216 N · m2/C. If two of the charges inside the closed surface are 1.74 nC and 1.16 nC, determine the value (magnitude and sign) of the third charge.
Answer:
q₃ = -4.81 nC
Explanation:
We can use the Gauss Law here:
∅ = q/∈₀
where,
∅ = Net Flux = - 216 N.m²/C
q = total charge enclosed inside sphere = ?
∈₀ = permittivity of free space = 8.85 x 10⁻¹² C/N.m²
Therefore,
- 216 N.m²/C = q / 8.85 x 10⁻¹² C²/N.m²
q = (-216 N.m²/C)(8.85 x 10⁻¹² C²/N.m²)
q = - 1.91 nC
So, the total charge will be sum of all three charges:
q = q₁ + q₂ + q₃
- 1.91 nC = 1.74 nC + 1.16 nC + q₃
q₃ = - 1.91 nC - 1.74 nC - 1.16 nC
q₃ = -4.81 nC
A transverse, sinusoidal wave travels in a string and can be described by the function: y(x,t)=0.87 sin(21x−4.9t). What is the speed of this wave?
Answer:
2.61m/s
Explanation:
Given the wave function;
y(x,t)=0.87 sin(21x−4.9t).
The general wave equation is expressed as;
[tex]y = Asin(2\pi ft + 2\pi x /\lambda)[/tex]
f is the frequency of the wave
t is the time
[tex]\lambda\\[/tex] is the wavelength
On comparing;
2πft = 4.9t
2πf= 4.9
f = 4.9/2π
f = 4.9/2(3.14)
f = 4.9/6.28
f = 0.78Hz
Get the wavelength;
2πx/[tex]\lambda[/tex] = 21x
2π/[tex]\lambda[/tex] = 21
2π = 21[tex]\lambda[/tex]
[tex]\lambda[/tex] = 21/2π
[tex]\lambda[/tex] = 21/2(3.14)
[tex]\lambda[/tex] = 21/6.28
[tex]\lambda[/tex] = 3.34m
Speed = frequency * wavelength
Speed of the wave = 0.78 * 3.34
Speed of the wave = 2.61m/s
Hence the speed of the wave is 2.61m/s
Gravitational potential energy depends on the ____________ of the object.
Answer:
Height And Mass!
Explanation:
Got It from Google! I ain't smart XDD
If a baseball is held in the air at shoulder level then dropped to the ground, does it have more energy when it is held in the air at shoulder level or just before it hits the ground?
Answer:
it should not be dropping it goes up in the air then it goes down
If you drop a rock from 700 meters high, how long will it take the hit the ground? (Remember to make height negative when solving because it is falling)
Answer:
it would be 11.95 seconds
Explanation:
sorry for saying i did not know
A cyclist is coasting at 13 m/s when she starts down a 460 m long slope that is 30 m high. The cyclist and her bicycle have a combined mass of 70 kg. A steady 15 N drag force due to air resistance acts on her as she coasts all the way to the bottom. What is her speed at the bottom of the slope?
Answer:
The value is [tex]v = 23.6 \ m/s[/tex]
Explanation:
From the question we are told that
The velocity is [tex]u = 13 \ m/s[/tex]
The length of the slope is [tex]l = 460 \ m[/tex]
The height of the slope is [tex]h = 30 \ m[/tex]
The mass of the cyclist and her bicycle is [tex]m = 70 \ kg[/tex]
The drag force is [tex]F = 15 \ N[/tex]
Generally from the law of energy conservation we have that
[tex]PE + KE_t = W * KE_b[/tex]
Here [tex]PE[/tex] is the potential energy at the top of the slope which is mathematically represented as
[tex]PE = m* g * h[/tex]
=> [tex]PE = 70 * 9.8 * 30[/tex]
=> [tex]PE = 20580 \ J[/tex]
and [tex]KE_t[/tex] is the kinetic energy at the top of the slope which is mathematically represented as
[tex]KE_t = \frac{1}{2} * m * u^2[/tex]
=> [tex]KE_t = \frac{1}{2} * 70 * 13^2[/tex]
=> [tex]KE_t = 5915 \ J[/tex]
And W is the work done by the bicycle which is mathematically represented as
[tex]W = F * l[/tex]
=> [tex]W = 15 * 460[/tex]
=> [tex]W = 6900 \ J[/tex]
and [tex]KE_b[/tex] is the kinetic energy at the bottom of the slope which is mathematically represented as
[tex]KE_b = \frac{1}{2} * m * v^2[/tex]
=> [tex]KE_b = \frac{1}{2} * 70 * v^2[/tex]
=> [tex]KE_b = 35 v^2[/tex]
So
[tex]20580 + 5915 = 6900 + 35 v^2[/tex]
=> [tex]v = 23.6 \ m/s[/tex]
Acceleration and force are proportional
Answer:
whats the question tho
20
A force of 1 N accelerates a mass of 1 kg at the rate of 1 m/s/s. The
acceleration of a mass of 2 kg acted upon by a net force of 2 N is
O half as much
twice as much.
the same.
O none of these
Answer:
Doing it right now i’ll pm once done give me 5 minutes:)
Explanation:
If an object has more mass then it will have...
A: less intertia
B: more inertia
C: more volume
D: less volume
True or False: The motion of the plates over the surface of the Earth occurs at a noticeable and fairly rapid rate.
Suppose a large housefly 3.0 m away from you makes sound with an intensity level of 40.0 dB. What would be the sound intensity level if there 1000 identical flies at that same distance?
Answer:
Explanation:
Let the intensity of the noise be represented by I
Given that
40dB = 10 log 10 ( I /I•) ........ 1
I• is the lowest or threshold intensity of sound made.
I represents the intensity of the sound/ noise
The intensity of noise of 1000flies will be
β = 10 log 10 (1000I/I•)
Open up the bracket
β = 10 log 10(1000)+ 10 log 10(I/I•)
10 log 10(10^3)+10 log 10(I/I•)
3×10(10 log 10) +10 log 10(I/I•)
Recall, 10 log 10 = 1
30×1 + 10 log 10(I/I•).........2
Put equation 1 into 2
β =30+40
= 70db
The sound intensity produced by the large housefly at a distance of 3.0 m is 10,000 times greater than the reference intensity. If there are 1000 identical flies at the same distance, the sound intensity level would be 70.0 dB.
The sound intensity level (L) in decibels (dB) follows a logarithmic scale and can be calculated using the formula:
L = 10 × log₁₀(I/I0)
40.0 dB = 10 × log₁₀(I1/I0)
4.0 = log₁₀(I1/I0)
I1/I0 = 10⁴
I1/I0 = 10,000
This means that the sound intensity produced by the large housefly at a distance of 3.0 m is 10,000 times greater than the reference intensity.
For the sound intensity level when there are 1000 flies, we need to multiply the original sound intensity by 1000:
I_total = 1000 × I₁
I_total/I0 = 1000 × 10,000
I_total/I0 = 10,000,000
L_total = 10 × log₁₀(I_total/I0)
L_total = 10 × log₁₀(10,000,000)
L_total = 10 × 7
L_total = 70 dB
Therefore, if there are 1000 identical flies at the same distance, the sound intensity level would be 70.0 dB.
To know more about the sound intensity:
https://brainly.com/question/32194259
#SPJ6
Moist air initially at 1258C, 4 bar, and 50% relative humidity is contained in a 2.5-m3 closed, rigid tank. The tank contents are cooled. Determine the heat transfer, in kJ
Here is the missing part of the question
To Determine the heat transfer, in kJ if the final temperature in the tank is 110 deg C
Answer:
Explanation:
The image attached below shows the process on T - v diagram
At State 1:
The first step is to find the vapor pressure
[tex]P_{v1} = \rho_1 P_g_1[/tex]
[tex]= \phi_1 P_{x \ at \ 125^0C}[/tex]
= 0.5 × 232 kPa
= 116 kPa
The initial specific volume of the vapor is:
[tex]P_{v_1} v_{v_1} = \dfrac{\overline R}{M_v}T_1[/tex]
[tex]116 \times 10^3 \times v_{v_1} = \dfrac{8314}{18} \times (125 + 273)[/tex]
[tex]116 \times 10^3 \times v_{v_1} = 183831.7778[/tex]
[tex]v_{v_1} = 1.584 \ m^3/kg[/tex]
At State 1:
The next step is to determine the mass of water vapor pressure.
[tex]m_{v1} = \dfrac{V}{v_{v1}}[/tex]
[tex]= \dfrac{2.5}{1.584}[/tex]
= 1.578 kg
Using the ideal gas equation to estimate the mass of the dry air [tex]m_a[/tex][tex]P_{a1} V = m_a \dfrac{\overline R}{M_a}T_1[/tex]
[tex](P_1-P_{v1}) V = m_a \dfrac{\overline R}{M_a}T_1[/tex]
[tex](4-1.16) \times 10^5 \times 2.5 = m_a \dfrac{8314}{28.97}\times ( 125 + 273)[/tex]
[tex]710000= m_a \times 114220.642[/tex]
[tex]m_a = \dfrac{710000}{114220.642}[/tex]
[tex]m_a = 6.216 \ kg[/tex]
For the specific volume [tex]v_{v_1} = 1.584 \ m^3/kg[/tex] , we get the identical value of saturation temperature
[tex]T_{sat} = 100 + (110 -100) \bigg(\dfrac{1.584-1.673}{1.210 - 1.673}\bigg)[/tex]
[tex]T_{sat} =101.92 ^0\ C[/tex]
Thus, at [tex]T_{sat} =101.92 ^0\ C[/tex], condensation needs to begin.
However, since the exit temperature tends to be higher than the saturation temperature, then there will be an absence of condensation during the process.
Heat can now be determined by using the formula
Q = ΔU + W
Recall that: For a rigid tank, W = 0
Q = ΔU + 0
Q = ΔU
Q = U₂ - U₁
Also, the mass will remain constant given that there will not be any condensation during the process from state 1 and state 2.
At State 1;
The internal energy is calculated as:
[tex]U_1 = (m_a u_a \ _{ at \ 125^0 C})+ ( m_{v1} u_v \ _{ at \ 125^0 C} )[/tex]
At [tex]T_1[/tex] = 125° C, we obtain the specific internal energy of air
SO;
[tex]U_{a \ at \ 125 ^0C } = 278.93 + ( 286.16 -278.93) (\dfrac{398-390}{400-390} )[/tex]
[tex]=278.93 + ( 7.23) (\dfrac{8}{10} )[/tex]
[tex]= 284.714 \ kJ/kg\\[/tex]
At [tex]T_1[/tex] = 125° C, we obtain the specific internal energy of water vapor
[tex]U_{v1 \ at \ 125^0C} = u_g = 2534.5 \ kJ/kg[/tex]
[tex]U_1 = (m_a u_a \ at \ _{ 125 ^0C }) + ( m_{v1} u_v \ at \ _{125^0C} )[/tex]
= 6.216 × 284.714 + 1.578 × 2534.5
= 5768.716 kJ
At State 2:
The internal energy is calculated as:
[tex]U_2 = (m_a u_a \ _{ at \ 110^0 C})+ ( m_{v1} u_v \ _{ at \ 110^0 C} )[/tex]
At temperature 110° C, we obtain the specific internal energy of air
SO;
[tex]U_{a \ at \ 110^0C } = 271.69+ ( 278.93-271.69) (\dfrac{383-380}{390-380} )[/tex]
[tex]271.69+ (7.24) (0.3)[/tex]
[tex]= 273.862 \ kJ/kg\\[/tex]
At temperature 110° C, we obtain the specific internal energy of water vapor
[tex]U_{v1 \ at \ 110^0C}= 2517.9 \ kJ/kg[/tex]
[tex]U_2 = (m_a u_a \ at \ _{ 110 ^0C }) + ( m_{v1} u_v \ at \ _{110^0C} )[/tex]
= 6.216 × 273.862 + 1.578 × 2517.9
= 5675.57 kJ
Finally, the heat transfer during the process is
Q = U₂ - U₁
Q = (5675.57 - 5768.716 ) kJ
Q = -93.146 kJ
with the negative sign, this indicates that heat is lost from the system.
Water waves are waves because the wave moves up and down. transverse longitudinal
Answer:
it is transverse because longitudinal run lengthwise rather than across
hoped this helped lmk if it did
A ball is thrown in the air at an angle of 60.0° to the ground, with an initial speed of 30m/s. How far from its original position does it land?
Answer:
A student is conducting a pendulum experiment. Which of the following pieces of safety equipment would be the most vital to conduct this test?
Explanation:bkdbjkfej jf jfekjwniorigoexhndvgkj...............aplokdiuhyfgbv ..............................................
Which equation shows the correct relationship between mechanical energy, kinetic energy, and potential energy?
ME = KE + PE
O ME + KE = PE
O ME = KE - PE
O ME + PE = KE
Answer:
ME= KE+PE
Explanation:
just took quiz
The correct relationship between mechanical energy, kinetic energy, and potential energy is ME= KE + PE, the correct option is A.
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.
The expression for total mechanical energy is as follows
[tex]ME = KE + PE[/tex]
As total mechanical energy is the sum of all the kinetic as well potential energy stored in the system.
Learn more about mechanical energy
https://brainly.com/question/12319302
#SPJ5
(question 1) A person with a mass of 50 kilograms pushes a 2000-kilogram car to the right with a force of 500 Newtons. What is the force that the car applies to the person?
(question 2) An ice skater with a mass of 50 kilograms pushes another skater (with a mass of 40 kilograms) with a force of 25 newtons. How much acceleration does the 50-kg skater have?
(question 3) Two people are moving a heavy desk. One person pulls to the right with a force of 25 newtons, while the other pushes to the right with a force of 50 newtons. There is also 29 newtons of friction pointing to the left. what is the net force on the desk?
(question 4) Two people are trying to pull 5-kilogram block in opposite directions. The first person pulls to the right with a force of 25 newtons, and the second person pulls to the left with a force of 15 newtons. What is the acceleration of the block?
IK its a lot but I need help please
Answer:
q1: 0.5m/s2
Explanation:
it was a dark and stormy night.Buffy hameard thunder exactly 6 secounds after she saw lightning , the temperature of air is 15°C . the speed light is 3×10^8 m/s
caculate the speed of sound
Answer:
υ = 345.82 m/s
Explanation:
The formula used to find the speed of sound in air, at different temperatures is given as follows:
[tex]v = v_{0}\sqrt{\frac{T}{273} }[/tex]
where,
υ = speed of sound at given temperature = ?
υ₀ = speed of sound at 0°C = 331 m/s
T = temperature in K = 15°C + 273 = 298 k
Therefore, using these values in the equation, we get:
[tex]v = (331 m/s)\sqrt{\frac{298 k}{273 k}}\\[/tex]
υ = 345.82 m/s
Solid state physics uses the. Theory to understand how the large-scale properties of solids result from their atomic scale structure
Answer:
Quantum theory
Explanation:
The scientific foundation in quantum mechanics is quantum theory, which describes the existence and behavior of mass and antimatter at the subatomic particles levels. Quantum theory and quantum theory are often related to as the existence and behavior of matter in the universe at that stage.
What is the acceleration of gravity on Earth?
Answer:
9.807 m/s²
Explanation:
PLS make me brainliest
Answer:
[tex]\huge\boxed{\sf 9.8 \ m/s^2}[/tex]
Explanation:
The acceleration due to gravity is g the value of which is 9.8 m/s².
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807Help! My homework is due in a few minutes :(
Fernando is an engineer at an amusement park who is experimenting with changes to the setup for a magnetic roller coaster ride. In one ride, there are two identical roller coaster cars (red and yellow) that start on opposite sides of a large magnet located in the center of a station. He moves both cars, so each car ends up one space farther away from the large magnet.How did the potential energy of the two cars change? Did the potential energy of one car change more than the other? Why do you think so?
Answer:
I think that the potential energy of the cars will go down because the cars are moving farther away from the big magnet. Since the pols of the cars and big magnet are opposite and not the same they would want to attract if they got close to the big magnet, but since Fernando is pulling the carts away they loose that potential energy. I also think that the red cart changed more than the yellow cart because it is closer to the magnet which can have a lot of potential energy and he is now bringing the cart away from it. In conclusion, I think the red cart had a greater change in potential energy and the two cars changed in potential energy too.
Explanation:
- i hope this helps, i tried lol :)
Which climate condition is typically found in the tropics due to the interaction of the atmosphere and hydrosphere? (3 points)
a
Dry with low humidity
b
Dry with high humidity
c
Wet with high humidity
d
Stormy with low humidity
Answer:
wet with high humidity
Explanation:
i took the test
summarize your observations about the relationships between molecular mass (heavy vs light), kinetic energy, particle speed, and temperature
Answer:
See explanation
Explanation:
Given that the kinetic energy of particles is obtained from; Ek = 1/2 mu^2. The speed of particles is given by c = [3RT/M]^1/2.
From what we can see in the graphs with heavy particles, they only have higher peaks while the lighter particles have lower peaks of kinetic energy and particle speed.
From the graphs and the temperatures used, it is evident that the shape of the graphs were almost the same. Temperature appears not to have any outstanding effect on it.
Eddie and Val observed the picture of an athlete running in a race.
A large group of runners participate in a race.
Eddie stated the picture shows potential energy being transformed to kinetic energy. Val stated that it shows chemical energy being transformed to mechanical energy. Which best explains who is correct?
Only Eddie is correct because the picture does not show a transformation that starts with chemical energy.
Only Eddie is correct because the picture does not show a transformation that ends with mechanical energy.
Both Eddie and Val are correct because chemical energy is a type of potential energy and mechanical energy includes kinetic energy.
Both Eddie and Val are correct because chemical energy is a type of kinetic energy and mechanical energy includes potential energy.
Answer:
The Answer is C.
Explanation:
Both Eddie and Val are correct because chemical energy is a type of potential energy and mechanical energy includes kinetic energy.
What is Energy?This is defined as the capacity and ability to do work. Potential energy is a type of energy by virtue of its position and chemical energy falls under this category.
Kinetic energy on the other hand is the energy by virtue of movement or motion and mechanical energy falls under this too thereby making option C most appropriate.
Read more about Energy here https://brainly.com/question/26520543
A light board, 10 m long, is supported by two sawhorses, one at one edge of the board and a second at the midpoint. A small 40-N weight is placed between the two sawhorses, 3.0 m from the edge and 2.0 m from the center. What forces are exerted by the sawhorses on the board
Answer:
8N and 32N
Explanation:
Given that a light board, 10 m long, is supported by two sawhorses, one at one edge of the board and a second at the midpoint. A small 40-N weight is placed between the two sawhorses, 3.0 m from the edge and 2.0 m from the center.
To calculate the forces that are exerted by the sawhorses on the board, we must consider the equilibrium of forces acting on the board.
Let the two upward forces produce by the saw horses be P1 and P2
Assuming that the weight is negligible
Sum of the upward forces = sum of the downward forces.
P1 + P2 = 40 ....... (1)
Also, the sum of the clockwise moment = sum of the anticlockwise moments.
Let's assume that the board is uniform. The weight will act at the centre.
Taking moment at the centre:
P1 × 5 + 40 × 2 = 0
P1 = 40 / 5
P1 = 8N
Substitute P1 into equation 1
8 + P2 = 40
P2 = 40 - 8
P2 = 32N
Answer:
56
Explanation:
A sphere of volume 1.20×10−3m3 hangs from a cable. When the sphere is completely submerged in water, the tension in the cable is 29.4 N. What is the buoyant force on the submerged sphere?
Answer:
B = 62.9 N
Explanation:
This is an exercise on Archimedes' principle, where the thrust force equals the weight of the liquid
B = ρ g V
write the equilibrium equation
T + B -W = 0
B = W- T (1)
use the density to write the weight
ρ = m / V
m = ρ V
W = ρ g V
substitute in 1
B = m g -T
B = [tex]\rho_{body}[/tex] g V - T
To finish the calculation, the density of the material must be known, suppose it is steel \rho_{body} = 7850 kg / m³
calculate
B = 7850 9.8 1.20 10⁻³ - 29.4
B = 92.3 - 29.4
B = 62.9 N
Centripetal forces are always directed toward the (center, outside) of a circle.
Answer:
Centripetal forces are directed toward the center of a circle.
Hope this helps.
Explanation:
The force needed to move a body in a curved way is understood as centripetal force. Centripetal forces are always directed toward the center of a circle.
What is centripetal force?The force needed to move a body in a curved way is understood as centripetal force. This is a force that can be sensed from both the fixed frame and the spinning body's frame of concern.
The direction of centripetal force is always in the path of the center of the course.
Hence center is the right option. Centripetal forces are always directed toward the center of a circle.
To learn more about the centripetal force refer to the link;
https://brainly.com/question/10596517
