Answer:
Step 1 of 2:
-26x - 5 = x - 56
Step 2 of 2:
17/9 or 1.89
Step-by-step explanation:
1. Putting word statement in algebraic form
Step 1:
Let x be the unknown number ==> x is the unknown variable to be used in the equation and to be solved for
Step 2:
-26 times a number minus 5 ==> -26x - 5
Step 3:
is equal to 56 less than the number ==> = x - 56
Putting it all together:
-26x - 5 = x - 56
2. Solving the equation
-26x - 5 = x - 56
1. Subtract x from both sides:
-26x - 5 - x = x - x -56
-26x -x - 5 = -56
-27x - 5 = -56
2. Add 5 to both sides
-27x - 5 + 5 = -56+ 5
-27x = -51
x = -51/-27 (dividing both sides by -27)
x = 51/27 (negative divide by negative results in positive)
Reduce 51/27 by dividing numerator and denominator by 3
x = (51 ÷ 3)/(27 ÷ 3) = 17/9
= 1.88888.... = 1.89 rounded to two decimal places
Determine the shaded area. This figure is not drawn to scale.
To find:
The area of the shaded region.
Solution:
From the figure, it is clear that the length and width of the rectangle inside the circle are 75m and 40m. The diameter of the circle is 85m. The radius of the circle is 85/2m.
The shaded region is equals (area of the circle - area of the rectangle).
So, the area of the shaded region is:
[tex]\begin{gathered} A=\pi r^2-l\times w \\ A=\pi(\frac{85}{2})^2-75\times40 \\ A=\frac{22}{7}\times\frac{7225}{4}-3000 \\ A=\frac{158950}{28}-3000 \\ A=5676.79-3000 \\ A=2676.79m^2 \end{gathered}[/tex]Thus, the area of the shaded region is 2676.79 m^2.
Been out of school for health issues trying to catch up work thanks!!
DEFINITIONS
The union of two sets contains all the elements contained in either set (or both sets). The union is notated A ⋃ B.
The intersection of two sets contains only the elements that are in both sets. The intersection is notated A ⋂ B.
Using a Venn Diagram, the union and intersection of two sets can be seen below:
GIVEN
The sets are given to be:
[tex]\begin{gathered} S=\mleft\lbrace1,2,3,\ldots,18,19,20\mright\rbrace \\ A=\mleft\lbrace3,4,8,9,11,13,14,15,20\mright\rbrace \\ B=\mleft\lbrace4,7,13,14,16,18,19\mright\rbrace \end{gathered}[/tex]QUESTION
1) (A ∪ B): The terms of the two sets contained in either set or the two sets are
[tex](A\cup B)=\mleft\lbrace3,4,7,8,9,11,13,14,15,16,18,19,20\mright\rbrace[/tex]2) (A ∩ B): The elements that are in both sets are
[tex](A\cap B)=\mleft\lbrace4,13,14\mright\rbrace[/tex]A population of values has a normal distribution with u = 203.6 and o = 35.5. You intend to draw a randomsample of size n = 16.Find the probability that a single randomly selected value is greater than 231.1.PIX > 231.1) =Find the probability that a sample of size n = 16 is randomly selected with a mean greater than 231.1.P(M > 231.1) =Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or Z-scores rounded to 3 decimal places are accepted.
Part 1:
The probability that a single randomly selected value is greater than 231.1 equals one minus the probability that it is less or equal to 231.1:
P(x > 231.1) = 1 - P(x ≤ 231.1)
Now, to find P(x ≤ 231.1), we can transform x in its correspondent z-score, and then use a z-score table to find the probability:
x ≤ 231.1 => z ≤ (231.1 - 203.6)/35.5, because z = (x - mean)/(standard deviation)
z ≤ 0.775 (rounding to 3 decimal places)
Then we have:
P(x ≤ 231.1) = P( z ≤ 0.775)
Now, using a table, we find:
P( z ≤ 0.775) ≅ 0.7808
Then, we have:
P(x > 231.1) ≅ 1 - 0.7808 = 0.2192
Therefore, the asked probability is approximately 0.2192.
Part 2
For the next part, since we will select a sample out of other samples with size n = 16, we need to use the formula:
z = (x - mean)/(standard deviation/√n)
Now, x represents the mean of the selected sample, which we want to be greater than 231.1. Then, we have:
z = (231.1 - 203.6)/(35.5/√16) = 27.5/(35.5/4) = 3.099
P(x > 231.1) = 1 - P(x ≤ 231.1) = 1 - P(x ≤ 231.1) = 1 - P( z ≤ 3.099) = 1 - 0.9990 = 0.0010
Therefore, the asked probability is approximately 0.0010.
Rationalize the denominator and simplify the expression below. Show all steps and calculations to earn full credit. You may want to do this work by hand and upload an image of that written work rather than try to type it all out. \frac{8}{1- \sqrt[]{17} }
The Solution:
The given expression is
[tex]\frac{8}{1-\sqrt[]{17}}[/tex]Rationalizing the expression with the conjugate of the denominator, we have
[tex]\frac{8}{1-\sqrt[]{17}}\times\frac{1+\sqrt[]{17}}{1+\sqrt[]{17}}[/tex]This becomes
[tex]\frac{8(1+\sqrt[]{17})}{1^2-\sqrt[]{17^2}}[/tex][tex]\frac{8+8\sqrt[]{17}}{1-17}=\frac{8(1+\sqrt[]{17})}{-16}=-\frac{1+\sqrt[]{17}}{2}[/tex]Thus, the correct answer is
[tex]-\frac{1+\sqrt[]{17}}{2}[/tex]And if you can step by step on how to do it
The radius of the cylinder is r=3 cm.
The height of the cylinder is h=7 cm.
The expression for the volume of the cylinder is,
[tex]V=\pi r^2h[/tex]Substituting the given values in the above equation,
[tex]\begin{gathered} V=\pi(3\operatorname{cm})^2(7\operatorname{cm}) \\ =\frac{22}{7}\times9cm^2\times7\operatorname{cm} \\ =198cm^3 \end{gathered}[/tex]Thus, option (C) is the correct solution.
Find the perimeter of the rectangle. Write your answer in scientific notation.Area = 5.612 times 10^14 cm squared9.2 times 10^7cm is one side of the perimeter
Answer: Perimeter = 1.962 x 10^8 cm
Explanation:
The first step is to calculate the width of the rectangle. Recall,
Area = length x width
width = Area /length
From the information given,
Area = 5.612 times 10^14 cm squared
Length = 9.2 times 10^7cm
Thus,
width = 5.612 times 10^14 /9.2 times 10^7
width = 6.1 x 10^6
The formula for calculating the perimeter is
Perimeter = 2(length + width)
Thus,
Perimeter = 2(9.2 x 10^7 + 6.1 x 10^6)
Perimeter = 1.962 x 10^8 cm
what is the domain of this exponential function y=2x-8+2
The given function is
[tex]y=2^{x-8}+2[/tex]The domain is all real numbers, but the range would be all the real numbers greater than 2 because the function approximates to y = 2.
Hence, the answer is the first option.Use the Distributive Property and partial
products to find 5 × 727
The required product of the given expression [tex]5\times727[/tex] is [tex]3635[/tex].
Distributive property is defined as sum of two or more addends is multiplied by a number gives the same result by multiplying each addends separately and add the products.
For example:
[tex]a\times (b+c)=a\times b + a\times c[/tex]
Partial product is defined as the product of each digit of a number is multiplied by each digit of other number separately.
Solving the expression using Distributive property and partial products:
[tex]5 \times 727 = 5 \times ( 700 + 27 )\\[/tex] {∵ [tex]727=700+27[/tex]}
Here, Applying the distributive property we get:
[tex]= 5 \times700 + 5 \times27\\ = 3500 + 135\\ = 3635[/tex]
Hence, the required value of the expression [tex]5\times727[/tex] is [tex]3635[/tex].
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The product of the 5×727 is 3635.
The definition of a distributive property states that when the sum of two or more addends is multiplied by a number, the results are the same whether the addends are multiplied individually or all at once. Like a×(b+c) = a × b + a × c.
The definition of a partial product is the result of multiplying each digit of one integer by each digit of the other number separately.
Given in question, 5 × 727
Using distributive property and partial product,
5 × 727 = 5 × (700 + 27)
= 5 × 700 + 5 × 27
= 3500 + 135
= 3635
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a rectangular prisim has a volume of 80cm cubed it has a length of 2cm and a width of 5cm. What is the prisms height?
rectangular prism volume is ,
[tex]\begin{gathered} V=l\times b\times h \\ 80=2\times5\times h \\ h=\frac{80}{10} \\ h=8\text{ cm } \end{gathered}[/tex]The Jones family took a 12-mile canoe ride down the Indian River in 2 hours. After lunch, the return trip back up the river took 3 hours. Find the rate of the canoe in still water and the rate of the current.
Answer:
Step-by-step explanation:
As per the distance formula, the rate of the canoe in still water is 5 mph; the rate of the current is 1 mph.
Distance formula:
Distance is defined as the total movement of an object without any regard to direction. So, it is defined as the distance that covers how much ground an object despite its starting or ending point.
Distance = Speed x time
Given,
The Jones family took a 12-mile canoe ride down the Indian River in 2 hours. After lunch, the return trip back up the river took 3 hours.
Here we need to find the rate of the canoe in still water and the rate of the current.
According to the given question we know that,
Speed downriver = (12 mi)/(2 h) = 6 mph.
Speed upriver = (12 mi)/(3 h) = 4 mph.
Now, we need to find the canoe's rate in still water is the average of these speeds:
=> (6+4)/2 = 5 miles per hour.
Then the current's rate is calculated as the difference between the actual rate and the canoe's rate:
=> 6 - 5 = 1 miles per hour.
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The padlock for your gym locker uses a 3 number sequence to open the lock. If the numbers go from 1 to 27, how many different sequences are there on the dial without repeating a number?A. 17,550B. 33,696C. 16,848D. 8,775
SOLUTION:
We want to the different sequences possible without repeating a number.
For the first number, there are 27 ways to select it.
Since we aren't allowed to repeat numbers;
There are 26 ways to select the second number.
There are also 25 ways to select the third number.
Therefore, the different sequences possible are;
[tex]No\text{. of ways =}27\times26\times25=17550\text{ ways}[/tex]What is special about a unit circle? How does this help us when finding the six trigonometric ratios?
Answer:
A circle is a closed geometric figure without any sides or angles. The unit circle has all the properties of a circle, and its equation is also derived from the equation of a circle. Further, a unit circle is useful to derive the standard angle values of all the trigonometric ratios.
Step-by-step explanation:
I need answer for this word problems you have to shown that you can make several lattes then you add milk and begin to stirring. you use a total of 30 ounces of liquid. write an equation that represents the situation and explain what the variable represents.
hello
the question here is a word problem and we can either use alphabhets to represent the variables.
let lattes be represented by x and milk be represented by y
[tex]x+y=30[/tex]since the total ounce of liquid is equals to 30, we equate the whole sentence to 30.
I don't understand please explain in simple words the transformation that is happeningwhat is the function notation
We have the next functions
[tex]f(x)=5^x^{}[/tex][tex]g(x)=2(5)^x+1[/tex]Function notation
[tex]g(x)=2(f(x))+1[/tex]Describe the transformation in words
we have 2 transformations, the 2 that multiplies the function f(x) means that we will have an expansion in the y axis by 2, the one means that we will have a shift up by one unit
a blu ray player costs $80.99 in the store. what would your total cost be if the sales tax is 5.5%
ANSWER:
$ 85.44
STEP-BY-STEP EXPLANATION:
We have the value after tax, we must calculate the sum between the original value and the value equivalent to the established percentage, therefore, we calculate it like this:
[tex]\begin{gathered} p=80.99+80.99\cdot\frac{5.5}{100} \\ p=80.99+4.45 \\ p=\text{ \$85.44} \end{gathered}[/tex]The final price is $ 85.44
Tickets numbered 1 - 10 are drawn at random and placed back in the pile. Find the probability that at least one ticketnumbered with a 6 is drawn if there are 4 drawings that occur. Round your answer to two decimal places.
The probability of a 6 being drawn in one pick is
[tex]\frac{1}{10}[/tex]For 4 drawings, the probability would be
[tex]\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+\frac{1}{10}=\frac{4}{10}=\frac{2}{5}=0.40[/tex]The graph of y = 2x2 - 4x + 2 opens downward.true or false
The equation for the graph is :
[tex]y=2x^2-4x+2[/tex]You can graph the equation on a graph tool and view the graph as below:
From the graph, you can see that it opens upwards, so the statement is False.
Correct answer is that the graph opens upwards.
Answer choice : False
13х-17y+16z= 73
-11x + 15y + 17z= 61
46x+10y-30z = -18
The solution of the linear system of three simultaneous equations is presented as follows; x = 2, y = 1 and z = 4
What is a set of simultaneous equation?Simultaneous system of equations consists of a finite set of equations for which a solution to the equation system is required.
The linear system of three equations can be presented as follows;
13•x - 17•y + 16•z = 73...(1)
-11•x + 15•y + 17•z = 61...(2)
46•x + 10•y - 30•z = -18...(3)
The above system of equations can be solved using common multiples of the coefficients as follows;
Multiply equation (2) by 2 and equation (3) by 3 to get;
2 × (-11•x + 15•y + 17•z) = 2 × 61 = 122
-22•x + 30•y + 34•z = 122...(4)3 × (46•x + 10•y - 30•z) = 3 × (-18) = -54
138•x + 30•y - 90•y = -54...(5)Subtracting equation (4) from equation (5) gives;
138•x + 30•y - 90•z - (-22•x + 30•y + 34•z) = -54 - 122 = -176
138•x - (-22•x) + 30•y - 30•y - 90•z - 34•z = -176
160•x - 124•z = -176
40•x - 31•z = 44
[tex] \displaystyle {z = \frac{(44 + 40\cdot x)}{31}}[/tex]
Plugging in the value of z in equation (1) and (2) gives;
1043•x - 527•y + 704 = 73 × 31 = 2236...(6)
Which gives;
[tex] \displaystyle {y = \frac{(1043\cdot x - 1559)}{527}}[/tex]
339•x + 465•y + 748 = 61 × 31 = 1891...(7)
Which gives; [tex] \displaystyle {y = \frac{(381 - 113\cdot x )}{155}}[/tex] which gives;
[tex] \displaystyle { \frac{(1043\cdot x - 1559)}{527}= \frac{(381 - 113\cdot x )}{155}}[/tex]
Therefore; 221216•x - 442432 = 0
x = 442432 ÷ 221216 = 2
x = 2
y = (1043×2 - 1559)÷527 = 1
y = 1
z = (44 + 40×2) ÷ 31 = 4
z = 4
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Multiply. (−5 2/5)⋅3 7/10. −19 49/50. −15 7/25. −9 1/10. -1 7/10
To perform this multiplication, first, we have to transform the mixed numbers into fractions as follows:
[tex]-5\frac{2}{5}=-\frac{5\cdot5+2}{5}=-\frac{27}{5}[/tex][tex]3\frac{7}{10}=\frac{3\cdot10+7}{10}=\frac{37}{10}[/tex]Substituting these values into the multiplication, we get:
[tex]\begin{gathered} (-5\frac{2}{5})\cdot3\frac{7}{10}= \\ =(-\frac{27}{5})\cdot\frac{37}{10}= \\ =-\frac{27\cdot37}{5\cdot10}= \\ =-\frac{999}{50} \end{gathered}[/tex]This result can be expressed as a mixed number as follows:
[tex]-\frac{999}{50}=-\frac{950+49}{50}=-(\frac{950}{50}+\frac{49}{50})=-(19+\frac{49}{50})=-19\frac{49}{50}[/tex]
Find the equation (in slope-intercept form) of the line passing through the points with the given coordinates.(3,-5) , (4,5)
We will determine th equation in slope-intercept from of the line as follows:
First, we find the slope:
[tex]m=\frac{5-(-5)}{4-(3)}\Rightarrow m=10[/tex]Then:
[tex]y-5=10(x-4)\Rightarrow y-5=10x-40[/tex][tex]\Rightarrow y=10x-35[/tex]So, the equation of the line in slope-intercept form is:
[tex]y=10x-35[/tex]which are thrwe ordered pairs that make the equation y=7-x true? A (0,7) (1.8), (3,10) B (0,7) (2,5),(-1,8) C (1,8) (2,5),(3,10)D (2,9),(4,11),(5,12)
In order to corroborate that the points belong to the equation, we must subtitute the points into the equation.
If we substitute the points from option A, we get
[tex]\begin{gathered} 7=7-0 \\ 7=7 \end{gathered}[/tex]for (1,8), we have
[tex]\begin{gathered} 8=7-1 \\ 8=6\text{ !!!} \end{gathered}[/tex]then, option A is false.
Now, if we substitute the points in option B, for point (2,5), we have
[tex]\begin{gathered} 5=7-2 \\ 5=5 \end{gathered}[/tex]which is correct. Now, for point (-1.8) we obtain
[tex]\begin{gathered} 8=7-(-1) \\ 8=8 \end{gathered}[/tex]Since all the points fulfil the equation, then option B is an answer.
Lets continue with option C and D.
If we substitute point (1,8) from option C, we have
[tex]\begin{gathered} 8=7-1 \\ 8=6\text{ !!!} \end{gathered}[/tex]then, option C is false.
If we substite point (4,11) from option D, we get
[tex]\begin{gathered} 11=7-4 \\ 11=2\text{ !!!} \end{gathered}[/tex]then, option D is false.
Therefore, the answer is option B.
A coin is tossed an eight sided die numbered 1 through 8 is rolled find the probability of tossing a head and then rolling a number greater than 6. Round to three decimal places if needed
We are given that a coin is tossed and a die numbered from 1 through 8 is rolled. To determine the probability of tossing head and then rolling a number greater than 6 is given by the following formula:
[tex]P(\text{head and n>6)=p(head)}\cdot p(n>6)[/tex]This is because we are trying to determine the probability of two independent events. The probability of getting heads is given by:
[tex]P(\text{heads})=\frac{1}{2}[/tex]This is because there are two possible outcomes, heads or tails and we are interested in one of the outcomes.
Now we determine the probability of getting a number greater than 6 when rolling the dice. For this, there are 8 possible outcomes and we are interested in two of them, these are the numbers greater than 6 on the die (7, 8). Therefore, the probability is:
[tex]P(n>6)=\frac{2}{8}=\frac{1}{4}[/tex]Now we determine the product of both probabilities:
[tex]P(\text{head and n>6)=}\frac{1}{2}\times\frac{1}{4}=\frac{1}{8}[/tex]Now we rewrite the answer as a decimal:
[tex]P(\text{head and n>6)=}0.125[/tex]Therefore, the probability is 0.125.
Which statements are true about the result of simplifying this polynomial?
To answer the question, we must simplify the following expression:
[tex]t^3(8+9t)-(t^2+4)(t^2-3t)[/tex]We expand the terms in the polynomial using the distributive property for the multiplication:
[tex]8t^3+9t^4-(t^4-3t^3+4t^2-12t)[/tex]Simplifying the last expression we have:
[tex]^{}^{}8t^4+11t^3-4t^2+12t[/tex]We see that the simplified expression:
• is quartic,
,• doesn't have a constant term,
,• has four terms,
,• is a polynomial,
,• it is not a trinomial.
Answer
The correct answers are:
• The simplified expression has four terms.
,• The simplified expression is a polynomial.
In a class of 10 boys and 12 girls, a committee of 4 members is to be formed. What is the probability to form a committee consisting of 2 boys and 2 girls?0.30400.40600.50600.2060
Consider all the different possible combinations of 4 members of the committee (b,b,b,b), (b,b,b,g),...(g,g,g,g). We need to use the binomial distribution given below
[tex]P(k)=(nbinomialk)p^k(1-p)^{n-k}[/tex]In our case
[tex]k=2,n=4,p=\frac{10}{10+12}=\frac{10}{22}=\frac{5}{11}[/tex]Then,
[tex]\begin{gathered} P(2)=(\frac{4!}{2!(4-2)!})(\frac{5}{11})^2(\frac{6}{11})^2 \\ \Rightarrow P(2)=6\cdot\frac{900}{14641} \\ \Rightarrow P(2)=0. \end{gathered}[/tex]The same set of data has been fit using two different functions. The following images show the residual plots of each function.
We have the residuals of each function graphed.
They represent the distance, taking into account the sign, of each data point to the line of best fit.
A good fit will have residuals that are close to the x-axis. Also, the distribution for the residuals should not have too much spread, meaning that all the points should have approximately the same residual in ideal conditions.
In this case, we see that Function A has most residuals around the horizontal axis. Except for one of the points, that may be considered an outliert.
In the case of Function B there is a clear pattern (a quadratic relation between x and the residual) that shows that the degree of the best fit function is not the adequate (maybe two degrees lower than what should be).
This results in residuals that have a wide spread depending on the value of x.
Then, we can conclude that Function A has a better fit because the points are clustered around the x-axis.
Answer: Function A has a better fit because the points are clustered around the x-axis [Third option]
cube A has a volume of 125 cubic inches The Edge length of cube B measures 4.8 inches. which group is larger and why?select the corrects responses1. Cube A, because it's volume is greater than the volume of cube B 2. Cube A, because its surface area is greater than the volume of cube B 3. Cube B, because it's volume is greater than the volume of cube A4. Cube B, because its side length is greater than the side length of cube A
Answer:
1. Cube A, because it's volume is greater than the volume of cube B
Explanation:
Cube A
Volume = 125 cubic inches
[tex]\begin{gathered} \text{Volume}=s^3(s=\text{side length)} \\ 125=s^3 \\ s^3=125 \\ s^3=5^3 \\ s=5\text{ inches} \end{gathered}[/tex]Therefore:
[tex]\begin{gathered} \text{Surface Area=}6s^2 \\ =6(5)^2 \\ =6\times25 \\ =150\text{ square inches} \end{gathered}[/tex]Cube B
The edge length, s = 4.8 inches.
[tex]\begin{gathered} \text{Volume}=4.8^3=110.592\text{ cubic inches} \\ \text{Surface Area=}6(4.8)^2=138.24\text{ cubic inches} \end{gathered}[/tex]We see that Cube A is the larger group because it's volume is greater than the volume of cube B.
Explain the behavior of f(x)= ln (x-a) when x=a. Give values to x and a such that x-a=0
SOLUTION:
Step 1:
In this question, we are given the following:
Explain the behavior of :
[tex]f(x)\text{ = ln\lparen x-a\rparen}[/tex]when x=a.
Give values to x and a such that:
[tex](x-a)\text{ = 0}[/tex]Step 2:
The graph of the function:
[tex]f(x)\text{ = In \lparen x- a \rparen}[/tex]are as follows:
Explanation:
From the graph, we can see that the function:
[tex]f(x)\text{ = ln\lparen x-a\rparen}[/tex]is a horizontal translation, shift to the right of its parent function,
[tex]f(x)\text{ = In x}[/tex]Graph the function. Plot five points on the graph of the function as follows.
Write an expression to represent the area for figure in #4.Simplify the expression.Find the area when x=2.
Given: A figure is given.
Required: to determine the expression for the area of the figure. Also, determine the area when x=2.
Explanation: The area of the figure can be determined by dividing the figure as shown below-
Now, DEFG and ABCG represent rectangles. The dimensions of the rectangle DEFG is (2x+4) by (7x+2), and of the rectangle, ABCG is (4x+2) by BC where BC is-
[tex]\begin{gathered} BC=(3x+5)-(2x+4) \\ =x+1 \end{gathered}[/tex]Hence, the expression for the area is-
[tex]\begin{gathered} A=(2x+4)(7x+2)+(4x+2)(x+1) \\ A=(14x^2+4x+28x+8)+(4x^2+4x+2x+2) \end{gathered}[/tex]Further solving-
[tex]\begin{gathered} A=14x^2+32x+8+4x^2+6x+2 \\ =18x^2+38x+10\text{ sq units} \end{gathered}[/tex]Substituting x=2 as follows-
[tex]\begin{gathered} A=18(2^2)+38(2)+10 \\ =72+76+10 \\ =158\text{ sq units} \end{gathered}[/tex]Final Answer: The expression for the area of the figure is-
[tex]A=18x^2+38x+10\text{ sq un}\imaginaryI\text{ts}[/tex]The area when x=2 is 158 sq units.
Question 2.Draw diagrams to represent the following situations.a. The amount of flour that the bakery used this month was a 50% increase relative to last month.b. The amount of milk that the bakery used this month was a 75% decrease relative to last month.
Given:
a. The amount of flour that the bakery used this month was a 50% increase relative to last month.
So, we will draw a diagram that represents the situation
As shown, for last month, we have drawn a rectangle divided into two equal areas, each one represents 50%
this month was a 50% increase, so, we have drawn 3 areas which represent 50% increase
b. The amount of milk that the bakery used this month was a 75% decrease relative to last month.
As shown, for last month, we have drawn a rectangle with four equal areas
75% decrease, so, we have to remove 3 areas to make the remaining = 25%
So, the difference will give a 75% decrease
