Seth earns $25 a day and also she earns $3 for each ticket he sells at the local theatre.
Therefore $25 is the independent value and $3 is the dependent value because it depends on how many tickets are sold.
We can write the next expression:
[tex]25+3x[/tex]Now, we need to make an inequality about he must sell at least $115 in a day.
The word "at least" means greater than or equal to, therefore:
[tex]25+3x\ge115[/tex]Now, let's solve the inequality:
Subtract both sides by 25:
[tex]25-25+3x\ge115-25[/tex][tex]3x\ge90[/tex]Then, divide both sides by 3:
[tex]\frac{3x}{3}\ge\frac{90}{3}[/tex]Simplify:
[tex]x\ge30[/tex]I need some help with this
The product is:
(7*10⁵)*(3*10²) = 2.1*10⁸
So the correct option is D
The quotient is:
(2*10⁵)/(4*10²) = 5*10²
So the correct option is B.
How to get the products?
Here we want to get the product between numbers in scientific notation, the first one is:
a) (7*10⁵)*(3*10²)
We can rewrite this as:
(7*10⁵)*(3*10²) = (7*3)*(10⁵*10²) = (21)*(10⁵⁺²) = 21*10⁷
In scientific notation we can have only one digit at the left of the decimal point, so we can rewrite:
21*10⁷ = 2.1*10⁸
So the correct option is D.
b) Now the quotient is:
(2*10⁵)/(4*10²) = (2/4)*(10⁵*10²) = 0.5*10⁵⁻² = 0.5*10³
Again, we need to have a single digit in the left of the decimal point:
0.5*10³ = 5*10²
The correct option is B.
Learn more about scientific notation:
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Danica made $319 babysitting last month in that might she babysitted for total of 29 hours how much money did Danica make per hour
Answer:
Explanation:
From the question, we are told that Danica
The slope of the line containing the points (-2, 3) and (-3, 1) is
Hey :)
[tex]\star\sim\star\sim\star\sim\star\sim\star\sim[/tex]
Apply the little slope equation. By doing that successfully, we should get our correct slope.
[tex]\large\boldsymbol{\frac{y2-y1}{x2-x1}}[/tex]
[tex]\large\boldsymbol{\frac{1-3}{-3-(-2)}}[/tex]
[tex]\large\boldsymbol{\frac{-2}{-3+2}}[/tex]
[tex]\large\boldsymbol{\frac{-2}{-1}}[/tex]
[tex]\large\boldsymbol{-2}}[/tex]
So, the calculations showed that the slope is -2. I hope i could provide a good explanation and a correct answer to you. Thank you for taking the time to read my answer.
here for further service,
silennia[tex]\star\sim\star\sim\star\sim\star\sim\star\sim[/tex]
Choose all true inequalities from the list below.3 < 8-8 < -3-5 < -2118 > 4
ANSWER and EXPLANATION
We want to identify which of the inequalities are correct.
For the inequality to be correct, the left and right-hand sides of the inequality must agree with
(4, 2); slope = 3 writing linear equations given point and slope
The standard equation of a line in point-slope form is expressed as;
y-y0 = m(x-x0) where;
m is the slope
(x0, y0) is the point on the line
Given
(x0, y0) = (4, 2)
From the coordinate;
x0 = 4 and y0 =2
slope m = 3
Substitute the given parameters into the equation as shown;
y-2 = 3(x-4)
Hence the linear equations given the point and slope id expressed as y-2 = 3(x-4)
Debra is playing a role-playing game with her friends. She will roll dice to determine if her character unlocks a treasure chest. The probability of her unlocking the treasure chest is 3/10. Find the odds in favor of her character unlocking the treasure chest.
Probability of Debra unlocking the treasure chest, P(unlocking) = 3/10
Probability of Debra not unlocking the treasure chest,
P( not unlocking) = 1 - 3/10
P( not unlocking) = 7/10
[tex]undefined[/tex]Suppose that $2000 is invested at a rate of 2.8%, compounded quarterly. Assuming that no withdrawals are made, find the total amount after 5 years.Do not round any intermediate computations, and round your answer to the nearest cent.
Solution:
Given the amount invested, P; the rate, r, at which it was invested and the time, t, it was invested.
Thus,
[tex]\begin{gathered} p=2000, \\ \\ r=2.8\text{ \%}=0.028 \\ \\ t=5 \end{gathered}[/tex]Then, we would solve for the total amount, A, using the formula;
[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ \\ Where; \\ n=4 \end{gathered}[/tex]Thus;
[tex]\begin{gathered} A=2000(1+\frac{0.028}{4})^{(4)(5)} \\ \\ A=2000(1.007)^{20} \\ \\ A=2299.43 \end{gathered}[/tex]ANSWER: $2,299.43
Hi, I’m really confused with this question and I’m not sure how to solve it!
SOLUTION
The figure below would help in answering the question
Let's get the slopes of the line for company G and company H
Slope m is given as
[tex]m=\frac{rise}{run}[/tex]For company G, we have slope as
[tex]m=\frac{5}{1}=5[/tex]For Company H, we have
[tex]m=\frac{4}{1}=4[/tex]From the graph
Cab fare for 1 mile with company G is $7
Cab fare for 10 miles with company H is?
To get this we need to get the equation of the line H
From
[tex]\begin{gathered} y=mx+b \\ where\text{ m is slope and b is the y-intercept, we have } \\ y=4x+2 \end{gathered}[/tex]Now substituting x for 10 in the equation, we have
[tex]\begin{gathered} y=4x+2 \\ y=4(10)+2 \\ y=40+2 \\ y=42 \end{gathered}[/tex]Hence the cab fare for 10 miles with Company H is $42
The rate charge per mile by Company G is the slope we got as 5.
Hence the answer is $5 per mile
The rate charge per mile by Company H is the slope we got as 4.
Hence the answer is $4 per mile
Amelia used 6 liters of gasoline to drive 48 kilometers.How many kilometers did Amelia drive per liter?kilometers =At that rate, how many liters does it take to drive 1 kilometer?liters =
Answer:
8km /hr
1/ 8 of a litre.
Explanation:
We are told that Amelia drives 48 kilometres in 6 hours, this means the number of kilometres she drives per litre is
[tex]48\operatorname{km}\div6\text{litres}[/tex][tex]\frac{8\operatorname{km}}{\text{litre}}[/tex]Hence, Amelia drives 8 kilometres per litre.
The next question can be rephrased as, given that Amelia drives 8 km per litre, how many litres will it take to drive one kilometre?
To answer this question, we make use of the equation
[tex]\operatorname{km}\text{ travelled = 8km/litre }\cdot\text{ litres}[/tex]Now, we want
km travelled = 1 km
and the above equation gives
[tex]\begin{gathered} 1=\frac{8\operatorname{km}}{\text{litre}}\cdot\text{litres} \\ 1=8\cdot\text{litres} \end{gathered}[/tex]Dividing both sides by 8 gives
[tex]\text{litres}=\frac{1}{8}[/tex]Hence, it takes 1/8 of a litre to drive 1 kilometre.
karen recorded her walking pace in the table below. what equation best represents this relationship
Given Data:
The table given here shows time taken in the first column and the distance travelled in the second column.
First check the ration of distance /time to verify if the speed of the man is constant or not.
[tex]\begin{gathered} \frac{8.75\text{ m}}{2.5\text{ h}}=3.5\text{ m/h} \\ \frac{14\text{ m}}{4\text{ h}}=3.5\text{ m/h} \end{gathered}[/tex]As both ratios are same it means the speed of the man is constant and the distance travelled is directly proportional to the time taken and varies linealy with the time.
Now to determine the relationship between m and h we will use the same ratio of m and h which comes in the previous step.
[tex]\begin{gathered} \frac{m}{h}=3.5 \\ m=3.5h \end{gathered}[/tex]Thus, option (D) is the required solution.
In the expression 9+2z what is the variable?
To answer this question, we will define some things first.
For every mathematical expression or term, it consist of three parts:
1) Coefficient
2) Variable: a symbol that stands in for an unknown value in a mathematical expression
3) Constant
In the expression given:
[tex]\begin{gathered} 9+2z \\ 9\text{ is the constant} \\ 2\text{ is the coefficient} \\ z\text{ is the variable} \end{gathered}[/tex]So the variable in the expression is z.
Write an equation of each circle described below. Show work! (Hint: find the coordinates of the center first)Given a circle with (5, 1) and (3,-1) as the endpoints of the diameter.(x − B1)² + (y - B2)² = (B3)²B1=B2=B3=Blank 1:Blank 2:Blank 3:Submit
Given:
It is given that a circle is represented by two end points (5,1) and (3,-1).
Find:
we have to find the equation of the circle, radius and center of the circle using end points.
Explanation:
The circle represented by two end points (5,1) and (3,-1) is drawn as
The diameter of the circle is
[tex]d=\sqrt{(5-3)^2+(1-(-1))^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}[/tex]Therefore radius of the circle is
[tex]B3=\frac{d}{2}=\frac{2\sqrt{2}}{2}=\sqrt{2}[/tex]The center of the circle is
[tex](B1,B2)=(\frac{5+3}{2},\frac{1-1}{2})=(\frac{8}{2},\frac{0}{2})=(4,0)[/tex]Therefore, the equation of the circle is
[tex](x-4)^2+(y-0)^2=(\sqrt{2})^2[/tex]where,
[tex]\begin{gathered} B1=4 \\ B2=0 \\ B3=\sqrt{2} \end{gathered}[/tex]Two balls are drawn in succession without replacement from an urn containing 5 red balls and 6 blue balls. Let Z be the random variable representing the number of blue balls. Construct the probability distribution and histogram of the random variable Z.
ANSWER and EXPLANATION
Let R represent the number of red balls.
Let B represent the number of blue balls.
There are four possible outcomes when the balls are picked:
[tex]\lbrace RR,RB,BR,BB\rbrace[/tex]We have that Z is the random variable that represents the number of blue balls.
This implies that the possible values of Z are:
To construct the probability distribution, we have to find the probabilities of each of the outcomes:
[tex]\begin{gathered} P(RR)=\frac{5}{11}*\frac{4}{10}=\frac{2}{11} \\ P(RB)=\frac{5}{11}*\frac{6}{10}=\frac{3}{11} \\ P(BR)=\frac{5}{11}*\frac{6}{10}=\frac{3}{11} \\ P(BB)=\frac{6}{11}*\frac{5}{10}=\frac{3}{11} \end{gathered}[/tex]Hence, the probabilities for the possible outcomes of the random variable are:
[tex]\begin{gathered} P(Z=0)=\frac{2}{11} \\ P(Z=1)=\frac{3}{11}+\frac{3}{11}=\frac{6}{11} \\ P(Z=2)=\frac{3}{11} \end{gathered}[/tex]Therefore, the probability distribution is:
Now, let us plot the histogram:
That is the answer.
Find the center, vertices, foci, endpoints of the latera recta and equations of the directrices. Then sketch the graph of the ellipse.
The given equation of ellipse is,
[tex]\frac{(x-2)^2}{16}+\frac{y^2}{4}=1\text{ ---(1)}[/tex]The above equation can be rewritten as,
[tex]\frac{(x-2)^2}{4^2}+\frac{y^2}{2^2}=1\text{ ----(2)}[/tex]The above equation is similar to the standard form of the ellipse with center (h, k) and major axis parallel to x axis given by,
[tex]\frac{(x-h)^2}{a^2}+\frac{y^2}{b^2}=1\text{ ----(3)}[/tex]where a>b.
Comparing equations (2) and (3), h=2, k=0, a=4 and b= 2.
Hence, the center of the ellipse is (h, k)=(2, 0).
The coordinates of the vertices are given by,
[tex]\begin{gathered} (h+a,\text{ k)=(2+}4,\text{ }0)=(6,\text{ 0)} \\ (h-a,\text{ k)=(2-}4,\text{ }0)=(-2,\text{ 0)} \end{gathered}[/tex]Hence, the coordinates of the vertices are (6, 0) and (-2,0).
The coordinates of the co-vertices are given by,
[tex]\begin{gathered} (h,\text{ k+}b)=(2,\text{ }0+2)=(2,\text{ 2)} \\ (h,\text{ k-}b)=(2,\text{ }0-2)=(2,\text{ -2)} \end{gathered}[/tex]Hence, the coordinates of the co-vertices are (2, 2) and (2, -2).
The coordinates of the foci are (h±c, k).
[tex]\begin{gathered} c^2=a^2-b^2 \\ c^2=4^2-2^2 \\ c^2=16-4 \\ c^2=12 \\ c=2\sqrt[]{3} \end{gathered}[/tex]Using the value of c, the coordinates of the foci are,
[tex]\begin{gathered} \mleft(h+c,k\mright)=(2+2\sqrt[]{3},\text{ 0)} \\ (h-c,k)=(2-2\sqrt[]{3},\text{ 0)} \end{gathered}[/tex]Therefore, the coordinates of the foci are,
[tex](2+2\sqrt[]{3},\text{ 0) and }(2-2\sqrt[]{3},\text{ 0)}[/tex]The endpoints of the latus rectum is,
[tex]\begin{gathered} (h+c,\text{ k}+\frac{b^2}{a})=(2+2\sqrt[]{3},\text{ 0+}\frac{2^2}{4^{}}) \\ =(2+2\sqrt[]{3},\text{ 1)}^{} \\ (h-c,\text{ k}+\frac{b^2}{a})=2-2\sqrt[]{3},\text{ 0+}\frac{2^2}{4^{}}) \\ =(2-2\sqrt[]{3},\text{ 1}^{}) \\ (h+c,\text{ k-}\frac{b^2}{a})=(2+2\sqrt[]{3},\text{ 0-}\frac{2^2}{4^{}}) \\ =(2+2\sqrt[]{3},\text{ -1}^{}) \\ (h-c,\text{ k-}\frac{b^2}{a})=(2-2\sqrt[]{3},\text{ 0-}\frac{2^2}{4^{}}) \\ =(2-2\sqrt[]{3},\text{ -1}^{}) \end{gathered}[/tex]Therefore, the coordinates of the end points of the latus recta is,
[tex](2+2\sqrt[]{3},\text{ 1)},\text{ }(2-2\sqrt[]{3},\text{ 1}^{}),\text{ }(2+2\sqrt[]{3},\text{ -1}^{})\text{ and }(2-2\sqrt[]{3},\text{ -1}^{})[/tex]Now, the equations of the directrices is,
[tex]\begin{gathered} x=h\pm\frac{a}{e} \\ x=\pm\frac{a}{\sqrt[]{1-\frac{b^2}{a^2}}} \\ x=2\pm\frac{4}{\sqrt[]{1-\frac{2^2}{4^2}}} \\ x=2\pm\frac{4}{\sqrt[]{1-\frac{1^{}}{4^{}}}} \\ x=2\pm\frac{4}{\sqrt[]{\frac{3}{4}^{}}} \\ x=2\pm4\sqrt[]{\frac{4}{3}} \end{gathered}[/tex]Here, e is the eccentricity of the ellipse.
Therefore, the directrices of the ellipse is
[tex]x=2\pm4\sqrt[]{\frac{4}{3}}[/tex]Now, the graph of the ellipse is given by,
URGENT!! ILL GIVE
BRAINLIEST!!!!! AND 100
POINTS!!!!!
Equation of the line that passes through points (8,7) and (0,0)
Equation of the line:
y = mx+b
where:
m= slope
b= y-intercept
First, we have to find the slope:
m = (y2-y1) / (x2-x1)
Since we have:
(x1,y1) = (8,7)
(x2,y2)= (0,0)
Replacing:
m = (0-7)/ (0-8) = -7/-8 = 7/8
Now, that we have the slope:
y = 7/8 x +b
We can place the point (8,7) in the equation and solve for b:
7 = 7/8 (8) +b
7=7 +b
7-7=b
b=0
Since the y-intercept=0
The final equation is:
y= 7/8x
3t^2-2t+5; find the company revenues last month if t=-1
Given revenue function is:
[tex]R=3t^2-2t+5[/tex]Now revenue at t=(-1)
[tex]\begin{gathered} R=3(-1)^2-2(-1)+5 \\ R=3+2+5 \\ R=10 \end{gathered}[/tex]So the revenue at t=-1 is 10.
9.5.35 Assigned Media An architect designs a rectangular flower garden such that the width is exactly two-thirds of the length. If 300 feet of antique picket fencing are to be used to enclose the garden, find the dimensions of the garden What is the length of the garden? The length of the garden is
Answer:
• The dimensions of the garden are 90 feet by 60 feet.
,• The length of the garden is 90 feet.
Explanation:
Let the length of the garden = l
The width is exactly two-thirds of the length, Width = (2/3)l
If 300 feet of antique picket fencing are to be used to enclose the garden, this means that the perimeter of the proposed garden is 300 feet.
[tex]\begin{gathered} \text{Perimeter}=2(\text{Length}+\text{Width)} \\ 300=2(l+\frac{2}{3}l) \end{gathered}[/tex]Next, solve the equation for the length, l:
[tex]\begin{gathered} \frac{300}{2}=l+\frac{2}{3}l \\ 150=\frac{5l}{3} \\ l=150\times\frac{3}{5} \\ l=90\text{ feet} \end{gathered}[/tex]The length of the garden is 90 feet.
Next, we determine the width.
[tex]\begin{gathered} \text{Width}=\frac{2}{3}l \\ =\frac{2}{3}\times90 \\ =2\times30 \\ =60\text{ feet} \end{gathered}[/tex]The dimensions of the garden are 90 feet by 60 feet.
Find the zeros by using the quadratic formula and tell whether the solutions are real or imaginary. F(x)=x^2–8x+2
We have to calculate the zeros of the function with the quadratic formula.
[tex]f(x)=x^2-8x+2[/tex][tex]\begin{gathered} x=\frac{-(-8)}{2\cdot1}\pm\frac{\sqrt[]{(-8)^2-4\cdot1\cdot2}}{2\cdot1}=\frac{8}{2}\pm\frac{\sqrt[]{64-8}}{2}=4\pm\frac{\sqrt[]{56}}{2}=4\pm\sqrt[]{\frac{56}{4}}=4\pm\sqrt[]{14} \\ \\ x_1=4+\sqrt[]{14}\approx4+3.742=7.742 \\ x_2=4-\sqrt[]{14}\approx4-3.742=0.258 \end{gathered}[/tex]The roots are x1=7.742 and x2=0.258, both reals., both
Which number line shows the solutions to x > 5? O A. A. 3642 8 2 4 6 8 B. 8 -6 -4 -2 0 2 4 6 8 c. -6-4 2 0 2 4 6 8 D. 8 8 4 2 0 2 4 6 8
The answer is option C.
thats where there are intergers greater than 5.
The area of this figure 20 in. is square inches. 28 in. 30 in. 7 in. 25 in.
The shape can be broken into two separate rectangles of the forms below.
Bothe shapes give a rectangle, therefore the area of the shape is
Area of Shape = Area of rectangle A + Area of rectangle B
Since Area of rectangle = LENGTH X BREADTH, we then have below
[tex]\begin{gathered} \text{Area of shape = (28 x 7)}+(25\times30) \\ =196+750 \\ =946\text{ square inches} \end{gathered}[/tex]In conclusion, the answer is 946 square inches
Hello,Can you help me with the following word problem?A medical researcher needs 6 people to test the effectiveness of an experimental drug. If 13 people have volunteered for the test, in how many ways can 6 people be selected?This might be using the nCr formula
Solution:
Given that a medical researcher needs 6 people to test the effectiveness of an experimental drug. If 13 people have volunteered for the test, this implies that
[tex]\begin{gathered} total\text{ number of options in the set = 13} \\ number\text{ of oprions to be chosen = 6} \end{gathered}[/tex]To evaluate the number of people that can be selected, we use the combination formula expressed as
In this case,
[tex]\begin{gathered} n=13 \\ r=6 \end{gathered}[/tex]Thus, the question involves combination.
Answer the questions below about the quadratic function.g(×)=2×^2-12×+19Does the function have a minimum or maximum? minimum or maximum what is the functions minimum or maximum value?Where does the minimum or maximum value occur?x=?
Given the function:
[tex]g(x)=2x^2-12x+19[/tex]Let's determine if the function has a minimum or maximum.
The minimum and maximum of a function are the smallest and largest value of a function in a given range or domain
The given function has a minimum.
Apply the general equation of a quadratic function:
[tex]y=ax^2+bx+c[/tex]To find the minimum value, apply the formula:
[tex]x=-\frac{b}{2a}[/tex]Where:
b = -12
a = 2
Thus, we have:
[tex]\begin{gathered} x=-\frac{-12}{2(2)} \\ \\ x=-\frac{-12}{4} \\ \\ x=3 \end{gathered}[/tex]To find the function's minimum value, find f(3).
Substitute 3 for x in the function and evaluate:
[tex]\begin{gathered} f(x)=2x^2-12x+19 \\ \\ f(3)=2(3)^2-12(3)+19 \\ \\ f(3)=2(9)-36+19 \\ \\ f(3)=18-36+19 \\ \\ f(3)=1 \end{gathered}[/tex]Therefore, the function's minimum value is 1
Therefore, the functions minimum value occurs at:
x = 3
ANSWER:
• The function has a minimum
• Minimum value: 1
• The minimum occurs at: x = 3
p(x) = x + 4; Find p(2) evaluate function
Given:
The function is,
[tex]p(x)=x+4[/tex]Explanation:
Substitute 2 for x in the function to determine the value of p(2).
[tex]\begin{gathered} p(2)=2+4 \\ =6 \end{gathered}[/tex]So answer is p(2) = 6
in the lab Dale has two solutions that contain alcohol and is mixing them each other.she uses four times as much solution A as solution B.solution a is 20% of alcohol and solution B is 15% of alcohol. how many milliliters of solution B does he use, if the was resulting mixtures has 570 milliliter of pure alchohol.number of milliliters of solution B__?
Let:
• A ,be the number of millilitres (mL) of solution A used.
,• B ,be the number of mL of solution B used.
We know that Dale uses four times as much solution A as solution B, meaning
[tex]A=4B[/tex]Now, we know that we will end up with 570 mL of pure alcohol in the final solution. Using the dilution of both A and B (20% means 0.2 and 15% is 0.15) we would have that:
[tex]0.2A+0.15B=570[/tex]We would have the following system of equations:
[tex]\begin{cases}A=4B \\ 0.2A+0.15B=570\end{cases}[/tex]Substituting equation 1 in equation 2 and solving for B :
[tex]\begin{gathered} 0.2A+0.15B=570 \\ \rightarrow0.2(4B)+0.15B=570 \\ \rightarrow0.8B+0.15B=570 \\ \rightarrow0.95B=570\rightarrow B=\frac{570}{0.95} \\ \Rightarrow B=600 \end{gathered}[/tex]Substituting in equation 1 and solving for A:
[tex]\begin{gathered} A=4B \\ \rightarrow A=4(600) \\ \Rightarrow A=2400 \end{gathered}[/tex]This way, we can conclude that 2400 mL of solution A and 600mL of solution B were used.
I would like to know how to solve this answer.
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
k > 0
k * v
Step 02:
Scalars and Vectors:
k = scalar
v = vector
Scalar multiplication of a real vector by a positive real number multiplies the vector's magnitude, without changing its direction.
k * v
The answer is:
k v is parallel and has same direction as v
A recipe uses 6 cups of flour to 1 1/10 cups of milk. If you have 2 cups of flour, how much milk should you use?
We were told that the recipe uses 6 cups of flour to 1 1/10 cups of milk. Converting 1 1/10 to improper fraction, it becomes 11/10
Let x represent the number of cups of milk that would be used for 2 cups of flour. The equations would be as shown below
11/10 = 6
x = 2
By cross multiplying, we have
2 * 11/10 = 6 * x
6x = 22/10 = 11/5
x = (11/5) / 6
If we flip 6 such that it becomes 1/6, the division sign changes to multiplication. Thus, we have
x = 11/5 * 1/6 = 11/30
Thus, 11/30 cup of milk should be used
The scatter plot shows the number of CDs in millions that were sold from 1999 to 2005. Use the points (1999,940) and (2002,805) to find a line of fit for the data. Then use the line of fit to estimate the number of CDs that were sold in 2008
Based on the given points from the scatter plot on the number of CDs sold in millions, the line of best fit for the data is y = -45x + 90,895
The estimated number of CDs sold in 2008 was 535 CDs.
How to find the line of best fit?The line of best fit will take the form:
y = Slope(x) + y intercept
The value of x will be assumed to be the number of years since 1999.
The slope is:
= Change in y / Change in x
= (805 - 940) / (2002 - 1999)
= -45
The y intercept is:
940 = -45(3) + y
y = 90,895
The line of best fit is:
y = -45x + 90,895
This means that the number of CDs sold in 2008:
= -45(2008) + 90,895
= 535 CDs
Find out more on the line of best fit at https://brainly.com/question/17013321
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Malachi is making a fruit smoothie. In addition to a frozen banana, he wants to add one other fruit and one small container of yogurt.
If he has four different options for fruit (blueberries, strawberries, peaches, and raspberries) and three different options for yogurt flavors (plain, vanilla, and lemon), how many fruit smoothie combinations are possible?
There are
possible fruit smoothie combinations.
Answer:
12 different combinations are possible (I think)
Step-by-step explanation:
Let's try to understand,
1. Blueberries + Plain Yogurt
2. Strawberries + Plain Yogurt
3. Peaches+ Plain Yogurt
4. Raspberries + Plain Yogurt
5. Blueberries + Vanilla Yogurt
6. Strawberries +VanillaYogurt
7. Peaches+ VanillaYogurt
8. Raspberries + VanillaYogurt
9. Blueberries + Lemon Yogurt
10. Strawberries + Lemon Yogurt
11. Peaches+ Lemon Yogurt
12. Raspberries + LemonYogurt
I hope this is the right answer and if not please forgive.
18. The surface area of a cone is 12611 square meters. The diameter of the 5 points cone's circular base is 22 meters. What is the lateral area of the cone? Round your answer to the hundredths place value. * A 1 5 7 1 +/- B 5 -- C С 3 2 6 7 3 +/- D 1 4 7 0 2 7 +/-
data
Area = 126pi m^2
diameter = 22
TA = pi r h + pir^2
126pi = LA + pi(11)^2
LA = 126pi - 121pi
LA = 5pi
Letter B.
