Answer:
y - 1 = -8/3(x - 10)
also valid:
y - 9 = -8/3(x - 7)
Step-by-step explanation:
Point-slope equation is a fill-in-the-blank formula that is sort of a shortcut for writing the equation of a line. Point-slope is named that bc you fill in a point and the slope.
Point-slope Eq:
y - Y = m(x - X)
fill in the slope for the m and fill in any point on the line for the X,Y.
First slope:
Slope is y-y over x-x
9-1 / 7-10
= 8/ -3
= -8/3
So slope is -8/3 fill that in for the m.
y -Y = -8/3(x-X)
Pick one of the points (either one it totally doesn't matter)
Let's use (10,1)
fill in 10 for X and 1 in place of Y.
the y in the very front stays a y and the first x in the parentheses stays an x, so there will be two variables in your completed answer.
y - 1 = -8/3(x - 10)
make sure the parentheses on the right is beside the -8/3 fraction and is NOT written on the bottom, beside the 3 only.
The director of an alumni association for a small college wants to determine whether there is any type of relationship between an alum’s contribution (in dollars) and the number of years the alum has been out of school. The data follow.
----------------------------
b)
[tex]\begin{gathered} X=4 \\ \hat{y}(4)=-50.43919(4)+453.17568 \\ \hat{y}(4)=-201.75676+453.17568 \\ \hat{y}(4)=251.41892 \end{gathered}[/tex]There are 3 consecutive even integers that have a sum of 6. What is the value of the least integer?
We can express this question as follows:
[tex]n+(n+2)+(n+4)=6[/tex]Now, we can sum the like terms (n's) and the integers in the previous expression. Then, we have:
[tex](n+n+n)+(2+4)=6=3n+6\Rightarrow3n+6=6[/tex]Then, to solve the equation for n, we need to subtract 6 to both sides of the equation, and then divide by 3 to both sides too:
[tex]3n+6-6=6-6\Rightarrow3n=0\Rightarrow n=\frac{3}{3}n=\frac{0}{3}\Rightarrow n=0_{}[/tex]Then, we have that the three consecutive even integers are:
[tex]0+2+4=6[/tex]Therefore, the least integer is 0.
(spanish only) (Foto)
Respuesta:
Rectángulo.
Explicación paso a paso:
Cuando un triangulo isósceles (ángulos de la base de igual magnitud) miden 45°, significa que el ángulo que no conocemos será de 90 grados por el teorema de los ángulos internos de un triángulo.
180-(45+45)=90.
Por lo tanto, se forma un triangulo rectángulo, significa que tiene un ángulo recto de 90°.
Newton's law of cooling is T = A * e ^ (- d * t) + C where is the temperature of the object at time and C is the constant temperature of the surrounding mediumSuppose that the room temperature is 71^ + and the temperature of a cup of tea 160when it is placed on the table. How long will it take for the tea to cool to 120 degrees for k = 0.0595943 Round your answer to two decimal places.
Solution
Given
[tex]\begin{gathered} T=Ae^{-kt}+C\text{ --------\lparen1\rparen} \\ \\ C=71 \\ \\ A=160-71 \\ \\ T=120 \\ \\ k=0.0595943 \end{gathered}[/tex]To find the time, we nee to substitute the C, A, T, and k in (1) and then determine (t
[tex]\begin{gathered} 120=(160-71)e^{-0.0595943t}+71 \\ \\ \Rightarrow\frac{120-71}{160-71}=e^{-0.0595943t} \\ \\ \Rightarrow\frac{49}{89}=e^{-0.0595943t} \\ \\ \Rightarrow-0.0595943t=\ln(\frac{49}{89}) \\ \\ \Rightarrow t=\frac{1}{-0.0595943}\ln(\frac{49}{89})=10.01456\text{ s} \end{gathered}[/tex][tex]t=\frac{10.01465}{60}\text{ mins}=0.17\text{ mins}[/tex]Choose an equation that models the verbal scenario. The cost of a phone call is 7 cents to connect and an additional 6 cents per minute (m).
"The cost of a phone call is 7 cents to connect and an additional 6 cents per minute (m)"
If "C" indicates the total cost of a phone call and "m" corresponds to the number of minutes the phone call lasted.
The phone call costs 7 cents to connect, this means that regardless of the duration of the call, you will always pay this fee. This value corresponds to the y-intercept of the equation.
Then, the phone call costs 6 cents per minute, you can express this as "6m"
The total cost of the call can be calculated by adding the cost per minute and the fixed cost:
[tex]C=6m+7[/tex]These figures are similar. Thearea of one is given. Find thearea of the other.area=32 in?9 in12 in[ ? Jina
To find the area of similar figures whe you know the area of one of the figures and the length of corresponding sides:
1. Find the scale factor: in this case as you have the area of the largest figure find the scale factor for a reduction:
[tex]SF=\frac{small}{\text{big}}=\frac{9}{12}=\frac{3}{4}[/tex]2. Find the missing area: the area in similar figures is equal to the scale factor squared multiplied by the given area.
[tex]\begin{gathered} A=(\frac{3}{4})^2\cdot32in^2 \\ \\ A=(\frac{9}{16})\cdot32in^2 \\ \\ A=\frac{288}{16}in^2 \\ \\ A=18in^2 \end{gathered}[/tex]Then, the missing area is 18 square inchesFind the derivatives of the following using the different rules.1. f(x) = -67x
To derive f(x) = -67x, we can use the Power Rule.
[tex]x^n\Rightarrow nx^{n-1}[/tex]In the given term, our n = 1 since x¹ = x. So, following the power rule, we will multiply the exponent 1 to the constant term -67, then subtract 1 from the exponent 1, hence x¹ will become x⁰.
[tex]-67x^1\Rightarrow1(-67)(x^{1-1})[/tex]Then, simplify.
[tex]-67x^0\Rightarrow-67(1)=-67[/tex]Therefore, the first derivative of f(x) = -67x is -67.
[tex]f^{\prime}(x)=-67[/tex]In AOPQ, mZO = (6x – 14)°, mZP = (2x + 16)°, and mZQ = (2x + 8)°. Find mZQ.
Explanation
Step 1
the sum of the internal angles in a triangle equals 18o, so
[tex]\begin{gathered} (2x+16)+(6x-14)+(2x+8)=180 \\ 2x+16+6x-14+2x+8=180 \\ \text{add similar terms} \\ 10x+10=180 \\ \text{subtract 10 in both sides} \\ 10x+10-10=180-10 \\ 10x=170 \\ \text{divide both sides by 10} \\ \frac{10x}{10}=\frac{170}{10} \\ x=17 \end{gathered}[/tex]Step 2
now, replace the value of x in angle Q to find it
[tex]\begin{gathered} \measuredangle Q=(2x+8) \\ \measuredangle Q=(2\cdot17+8) \\ \measuredangle Q=(34+8) \\ \measuredangle Q=42 \end{gathered}[/tex]I hope this helps you
Which statement correctly describes the relationship between the graph of f(x) and g(x)=f(x+2)? Responses The graph of g(x) is the graph of f(x) translated 2 units right. The graph of , g begin argument x end argument, is the graph of , , f open argument x close argument, , translated 2 units right. The graph of g(x) is the graph of f(x) translated 2 units down. The graph of , g begin argument x end argument, is the graph of , , f open argument x close argument, , translated 2 units down. The graph of g(x) is the graph of f(x) translated 2 units up. The graph of , g begin argument x end argument, is the graph of , , f open argument x close argument, , translated 2 units up. The graph of g(x) is the graph of f(x) translated 2 units left.
The graph of g(x) is the graph of f(x) translated 2 units left by the operation g(x)=f(x+2) so option (D) is correct.
What is the transformation of a graph?Transformation is rearranging a graph by a given rule it could be either increment of coordinate or decrement or reflection.
If we reflect any graph about y = x then the coordinate will interchange it that (x,y) → (y,x).
If a function f(x) is transformed by funciton g(x) as shown,
g(x) = f(x+a)
For a>0, then the graph of f(x) shifts left by "a" unit, while if a<0, then the graph of f(x) shifts right side by "a"units.
As per the given function,
g(x) = f(x + 2)
Since 2 > 0 therefore the function will shift 2 units left.
Hence "The graph of g(x) is the graph of f(x) translated 2 units left by the operation g(x)=f(x+2)".
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The figure ABCD is a rectangle. AB = 2 units, AD = 4 units, and AE = FC = 1 unit.Find the area of triangle ABE.
Area of triangle ABE can be calculated using the formula 1/2 x b xh
From the question,
base b = AE = 1
height h =AB = 2
substitute the values into the formula
[tex]A=\frac{1}{2}\times1\times2[/tex]Area = 1 square unit
A gift wrapping store has 8shapes of boxes, 14types of wrapping paper, and 12 different bows. How many different options are available at this store?
If a gift wrapping store has 8shapes of boxes, 14types of wrapping paper, and 12 different bows. The number of different options that are available at this store is 1344.
How to find the different options?Using this formula to determine the number of different options
Number of different options available = Number of shapes of boxes × Number of wrapping paper × Number of different bowl
Let plug in the formula
Number of different options available = 8 × 14 × 12
Number of different options available = 1,344
Therefore we can conclude that 1,344 different options are available.
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There are 120 teachers. Select a sample of 40 teachers by using the systematic sampling technique.
Given:
Total number of teachers = 120
To select a number of teachers = 40
Required:
To find a sample of 40 teachers by using the systematic sampling technique.
Explanation:
The probability formula is given as:
[tex]\begin{gathered} P=\frac{number\text{ of favourable outcomes}}{Total\text{ number of outcomes}} \\ P=\frac{40}{120} \\ P=\frac{1}{3} \end{gathered}[/tex]Final Answer:
[tex]undefined[/tex]Geometric mean of36 and 21
The Geometric Mean is:
[tex]6\sqrt[]{21}[/tex]Explanation:Given 36 and 21, the Geometric Mean is given as:
[tex]\begin{gathered} m=\sqrt[]{36\times21} \\ =\sqrt[]{6^2\times21} \\ =6\sqrt[]{21} \end{gathered}[/tex]Eighth grade 0.12 Exterior Angle Theorem FMP What is m_1? 1 470 670 Q m21 =
we know that
An exterior angle of a triangle is equal to the sum of the two opposite interior angles.
so
Applying the Exterior Angle Theorem
m<1=67+47
m<1=114 degreesBased on the degree of the polynomial f(x) given below, what is the maximum number of turning points the graph of f(x)
can have?
f(x) = -3+x²-3x - 3x³ + 2x² + 4x4
The maximum number of turning points based on the degree of the polynomial is 2.
What is the turning point?A polynomial function is a function that can be expressed in the form of a polynomial. The definition can be derived from the definition of a polynomial equation. A polynomial is generally represented as P(x). The highest power of the variable of P(x) is known as its degree.A turning point is a point in the graph where the graph changes from increasing to decreasing or decreasing to increasing.Turning point = n-1, where n is the degree of the polynomial.
The highest order of the polynomial is 3.n = 3Turning point = 3 - 1 = 2Therefore, the maximum number of turning points based on the degree of the polynomial is 2.
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Simplify by writing the expression with positive exponents. Assume that all variables represent nonzero real numbers
Explanation
Let's remember some properties ofthe fractions ans exponents,
[tex]\begin{gathered} a^{-n}=\frac{1}{a^n} \\ (\frac{a}{b})^n=\frac{a^n}{b^n} \\ (ab)^n=a^nb^n \\ (a^n)^m=a^{m\cdot n} \end{gathered}[/tex]so
Step 1
[tex]\lbrack\frac{4p^{-2}q}{3^{-1}m^3}\rbrack^2[/tex]reduce by using the properties
[tex]\begin{gathered} \lbrack\frac{4p^{-2}q}{3^{-1}m^3}\rbrack^2 \\ \lbrack\frac{4q}{3^{-1}m^3p^2}\rbrack^2 \\ \lbrack\frac{3^1\cdot4q}{m^3p^2}\rbrack^2 \\ \lbrack\frac{12q}{m^3p^2}\rbrack^2 \\ \lbrack\frac{144q^2}{m^{3\cdot2}p^{2\cdot2}}\rbrack^{} \\ \lbrack\frac{144q^2}{m^6p^4}\rbrack^{} \end{gathered}[/tex]therefore, the answer is
[tex]\lbrack\frac{144q^2}{m^6p^4}\rbrack^{}[/tex]I hope this helps you
help meeeeeeeeee pleaseee !!!!!
The value of the composite function is: (f o g)(2) = 33.
How to Find the Value of a Composite Function?To evaluate a composite function, take the following steps:
Step 1: Find the value of the inner function by substituting the value of x into the equation of the functionStep 2: Use the value of the output of the inner function as the input for the outer function and simplify to get the value of the composite function.Given the following:
f(x) = x² - 3x + 5
g(x) = -2x
Therefore,
(f o g)(2) = f(g(2))
Find the value of the inner function g(2):
g(2) = -2(2)
g(2) = -4
Find f(g(2)) by substituting x = -4 into the function f(x) = x² - 3x + 5:
(f o g)(2) = f(g(2)) = (-4)² - 3(-4) + 5
= 16 + 12 + 5
(f o g)(2) = 33
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This question has two parts. First, answer Part A. Then, answer Part B. Part A Conjecture: A quadrilateral with one pair of sides both congruent and parallel is a parallelogram. Which of the following shows the marked diagram of the situation?restate the conjecture as a specific statement using the diagram you chose from part AIn quadrilateral ABCD, AB is congruent to___ and ____ is parallel to CD. show that ABCD is a ____
We have the following:
We can know when they are congruent, since being congruent they are equal sides.
By notation we know that " ' " means that they are the same, therefore
[tex]AB=DC[/tex]And the parallel lines are:
[tex]BA\parallel CD[/tex]Therefore, the answer is B.
In quadrilateral ABCD, AB is congruent to CD and AB is parallel to CD. show that ABCD is a parallelogram
if you halved a recipe that calls for 5 c. chicken broth how much broth would you use
If halved a recipe that calls for 5 c chicken broth, then you would end up using 2.5 c chicken broth (that is two and half c of chicken broth).
A $40,000 is placed in a scholarship fund that earns an annual interest rate of 4.25% compounded daily find the value in dollars of the account after 2 years assume years have 365 days round your answer to the nearest cent
SOLUTION
From the question, we want to find the value in dollars of the account after 2 years.
We will usethe formula
[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ Where\text{ A = value of the account, amount in dollars = ?} \\ P=principal\text{ money invested = 40,000 dollars } \\ r=annual\text{ interest rate = 4.25\% = }\frac{4.25}{100}=0.0425 \\ n=number\text{ of times compounded = daily = 365} \\ t=time\text{ in years = 2 years } \end{gathered}[/tex]Applying this, we have
[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ A=40,000(1+\frac{0.0425}{365})^{365\times2} \\ A=40,000(1.000116438)^{730} \\ A=40,000\times1.0887116 \\ A=43,548.467179 \\ A=43,548.47\text{ dollars } \end{gathered}[/tex]Hence the answer is 43,548.47 to the nearest cent
write an equation if a circle has a center of (3,-1) and the diameter 8
Answer:
[tex](x-3)^2+(y+1)^2=16[/tex]Explanation:
The equation of a circle with center (h, k) and radius of r is generally given as;
[tex](x-h)^2+(y-k)^2=r^2[/tex]Given the center of the circle as (3, -1) and the diameter of 8 (r = d/2 = 8/2 = 4), the equation of the circle can then be written as shown below;
[tex]\begin{gathered} (x-3)^2+\lbrack y-(-1)\rbrack^2=4^2 \\ (x-3)^2+(y+1)^2=16 \end{gathered}[/tex]Help in solving for y. Need to know the slope and y-intercept in the equation
Given the following equation:
8x - 5y = 10
then, we can solve it for y as follows:
5y = 8x -10
y = (8/5)x - (10/5)
y = (8/5)x - 2
So, the slope is m = 8/5 and the y-intercept is yo = -2.
Identify the vertex, axis of symmetry, and if the graph has a maximum or minimum. Then write the function for the graph shown
Answer:
Step-by-step explanation:
n b
Eliza had $14 and Emma had $64 more than Eliza how much did Emma have?
Given
Eliza had $14
Emma had $64 more than Eliza
Find
how much did Emma have
Explanation
as we have given
Eliza has $14
so , Emma = $64 + $14 = $78
Final Answer
Therefore , the Emma had $78
The length of a wire was measured using two different rulers. How many significant figures are in each measurement?
We will have the following
In the first image we can see that the maximum you will measure with a good degree of certainty is the unit, and in the next one we wil have that is the unit and a fraction of it, so:
Top: 1 significative figure.
Bottom: 2 significative figures.
3 2 — · — = _____ 8 5 2 9· — = _____ 3 7 8 — · — = _____ 8 7 x — · y = _____ y a b —— · — = _____ 2b c m n2 —- · —— = _____ 3n mGive the product in simplest form: 1 2 · 2— = _____ 2Give the product in simplest form: 1 2 — · 3 = _____ 4 Give the product in simplest form: 1 1 1— · 1— = _____ 2 2 Give the product in simplest form: 1 2 3— · 2— = _____ 4 3
Given:
[tex]\frac{3}{8}\cdot\frac{2}{5}[/tex]Required:
We need to multiply the given rational numbers.
Explanation:
Cancel out the common terms.
[tex]\frac{3}{8}\cdot\frac{2}{5}=\frac{3}{4}\cdot\frac{1}{5}[/tex][tex]Use\text{ }\frac{a}{b}\cdot\frac{c}{d}=\frac{a\cdot c}{b\cdot d}.[/tex][tex]\frac{3}{8}\cdot\frac{2}{5}=\frac{3}{20}[/tex]Consider the number.
[tex]\frac{7}{8}\cdot\frac{8}{7}=\frac{1}{1}\cdot\frac{1}{1}[/tex]Cancel out the common multiples
[tex]9\cdot\frac{2}{3}[/tex][tex]9\cdot\frac{2}{3}=3\cdot2=6[/tex]Consider the number
[tex]\frac{7}{8}\cdot\frac{8}{7}[/tex]Cancel out the common multiples.
[tex]\frac{7}{8}\cdot\frac{8}{7}=\frac{1}{1}\cdot\frac{1}{1}[/tex][tex]\frac{7}{8}\cdot\frac{8}{7}=1[/tex]Consider the number
[tex]\frac{x}{y}\cdot y=x[/tex][tex]\frac{a}{2b}\cdot\frac{b}{c}=\frac{a}{2}\cdot\frac{1}{c}=\frac{a}{2c}[/tex][tex]\frac{m}{3n}\cdot\frac{n^2}{m}=\frac{1}{3}\cdot\frac{n}{m}=\frac{n}{3m}[/tex]Final answer:
[tex]\frac{3}{8}\cdot\frac{2}{5}=\frac{3}{20}[/tex][tex]9\cdot\frac{2}{3}=6[/tex][tex]\frac{7}{8}\cdot\frac{8}{7}=1[/tex][tex]\frac{x}{y}\cdot y=x[/tex][tex]\frac{a}{2b}\cdot\frac{b}{c}=\frac{a}{2c}[/tex][tex]\frac{m}{3n}\cdot\frac{n^2}{m}=\frac{n}{3m}[/tex]The residence of a city voted on whether to raise property taxes the ratio of yes votes to no votes was 5 to 8 if there were 4275 yes both what was the total number of votes
The ratio of votes has been given as;
[tex]Yes\colon No\Rightarrow5\colon8[/tex]This means the ratios can be expressed mathematically as;
[tex]\begin{gathered} \text{Yes}=\frac{5}{5+8}\Rightarrow\frac{5}{13} \\ No=\frac{8}{5+8}\Rightarrow\frac{8}{13} \end{gathered}[/tex]If there were 4275 YES votes, then this means the number 4275 represents 5/13.
Therefore,
[tex]\frac{5}{13}=\frac{4275}{x}[/tex]Where x represents the total number of votes. Therefore,
[tex]undefined[/tex]I need help solving this I’m having trouble with it is from my trigonometry prep bookIf you can **** use Desmos to graph the function that is provided in the picture
So we have to graph the function:
[tex]f(x)=\cot (x+\frac{\pi}{6})[/tex]First is important to note that the cotangent can be defined by the quotient between the cosine and the sine:
[tex]\cot (x+\frac{\pi}{6})=\frac{\cos(x+\frac{\pi}{6})}{\sin(x+\frac{\pi}{6})}[/tex]By looking at this new expression we can infer a few things about the graph. First of all, we have a sine in the denominator which means that the denominator can be equal to 0. Let's assume that the denominator is 0 at x=a. Then the graph has a vertical asymptote at x=a. What's more, the sine is a periodic funtion that is equal to zero for an infinite amount of x values so the graph of the cotangent has infinite vertical asymptotes. The good part is that we just need to graph one full period and in the case of the cotangent one full period is completed between two consecutive vertical asymptote. So basically we have to find two consecutive vertical asymptote and graph the function between them.
So let's begin by finding two x values that makes the denominator equal to 0. The sine is equal to 0 when its argument is equal to 0 and the next value at which the sine is equal to zero is pi so:
[tex]\sin 0=0=\sin \pi[/tex]Then we can construct two equations:
[tex]\begin{gathered} \sin (x+\frac{\pi}{6})=0=\sin 0 \\ \sin (x+\frac{\pi}{6})=0=\sin \pi \end{gathered}[/tex]The equations are:
[tex]\begin{gathered} x+\frac{\pi}{6}=0 \\ x+\frac{\pi}{6}=\pi \end{gathered}[/tex]We can substract π/6 from both sides of both equations:
[tex]\begin{gathered} x+\frac{\pi}{6}-\frac{\pi}{6}=0-\frac{\pi}{6} \\ x=-\frac{\pi}{6} \\ x+\frac{\pi}{6}-\frac{\pi}{6}=\pi-\frac{\pi}{6} \\ x=\frac{5\pi}{6} \end{gathered}[/tex]So we have a vertical asymptote at x=-π/6 and another one at x=5π/6. This means that we just need to graph f(x) between these two vertical lines. It is also important to note that f(x) reaches positive or negative values when the value of x approaches to -π/6 or 5π/6.
Now that we have the asymptotes let's find the x-intercept i.e. the point where f(x) meets with the x-axis. This happens when f(x)=0 which happens when the numerator is equal to 0. Then we get:
[tex]\cos (x+\frac{\pi}{6})=0[/tex]The cosine is equal to zero at π/2 so we have:
[tex]\begin{gathered} \cos (x+\frac{\pi}{6})=0=\cos \frac{\pi}{2} \\ x+\frac{\pi}{6}=\frac{\pi}{2} \end{gathered}[/tex]We can substract π/6 from both sides:
[tex]\begin{gathered} x+\frac{\pi}{6}-\frac{\pi}{6}=\frac{\pi}{2}-\frac{\pi}{6} \\ x=\frac{\pi}{3} \end{gathered}[/tex]So the x-intercept is located at x=π/3. So for now we have the x-intercept and two vertical asymptotes so at the moment we have the following:
The black dot is the x-intercept at (π/3,0) and the dashed lines are the asymptotes. Our function passes through the black dot and is limited by the asymptotes.
We still need to find if it reaches positive or negative infinite values when approaching to the asymptotes. As we saw the function is equal to zero at x=π/3. This means that between the first asymptote and x=π/3 the function is either entirely positive or entirely negative. The same happens with the interval between x=π/3 and the second asymptote. So we have two intervals where the function mantains its sign: (-π/6,π/3) and (π/3,5π/6). Let's evaluate f(x) in one value of each interval and see if it's positive or negative there. For example, x=0 is inside the first interval and x=2 is inside the second interval:
[tex]\begin{gathered} f(0)=1.73205>0 \\ f(2)=-1.4067<0 \end{gathered}[/tex]So f(x) is positive at (-π/6,π/3) which means that as x approaches to -π/6 from the right it reaches positive infinite values. We also have that f(x) is negative at (π/3,5π/6) so as x approaches 5π/6 from the left the function reaches negative infinite values.
Using this information and the fact that the graph must pass throug the x-intercept we can graph the function. It should look like this:
And that's the graph of f(x).
A father is 42 years old and his son is y years old. If the difference of their ages 28 years, what is the value of y?
Answer:
Son's age (y) = 14 years
Step-by-step explanation:
According to the question,
Father's age = 42 years
Son's age = y years
Difference between father's & son's age is 28 years. i.e.
Father's age - son's age = 28
42 - y = 28
42 - 28 = y
y = 42 - 28
y = 14
Find the y-coordinate of point P that lies 1/3 along segment CD, closer to C, where C (6, -5) and D (-3, 4).
SOLUTION:
The given ratio is:
[tex]1:3[/tex]• The given points are ,C(6, -5) and D (-3, 4).
Using the section formula, the coordinate of P is:
[tex]\begin{gathered} P=(\frac{1(-3)+3(6)}{1+3},\frac{1(4)+3(-5)}{1+3}) \\ P=(\frac{-3+18}{4},\frac{4-15}{4}) \\ P=(\frac{15}{4},\frac{-11}{4}) \end{gathered}[/tex]Therefore the coordiantes of P
[tex]P=(\frac{15}{4},\frac{-11}{4})[/tex]