Answer:
a=10 and a=-10
Step-by-step explanation: its absolute value
Which situation represents a proportional relationship?
O Renting a movie for $2 per day
O Renting a movie for $2 per day with a coupon for $0.50 off for the first day
O Renting a movie for $2 per day along with paying a $5 membership fee
O Renting a movie for $2 for the first day and $1 for each day after the first day
The option D that is "Renting a movie for $2 for the first day and $1 for each day after the first day" shows a proportional relationship as they are in proper ratio.
What is proportional relationship?Relationships between two variables that are proportional occur when their ratios are equal. Another way to consider them is that in a proportional relationship, one variable is consistently equal to the other's constant value. The "constant of proportionality" is the name of this constant.
What is ratio?A ratio in mathematics demonstrates how many times one number is present in another. For instance, if a bowl of fruit contains eight oranges and six lemons, the ratio of oranges to lemons is eight to six. The ratio of oranges to the total amount of fruit is 8:14, and the ratio of lemons to oranges is 6:8.
As they are in the right ratio, option D, "Renting a movie for $2 for the first day and $1 for each day after the first day," demonstrates a proportional relationship.
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Use the Quotient Rule to find the derivative of the function.f(x) = x/(x − 6)f'(x)=
ANSWER
[tex]\frac{-6}{(x-6)^2}[/tex]EXPLANATION
We want to find the derivative of the function:
[tex]f(x)=\frac{x}{x-6}[/tex]The quotient rule states that:
[tex]f^{\prime}(x)=\frac{v\frac{du}{dx}-u\frac{dv}{dx}}{v^2}[/tex]where u = the numerator of the function
v = the denominator of the function
From the function, we have that:
[tex]\begin{gathered} u=x \\ v=x-6 \end{gathered}[/tex]Now, we have to differentiate both u and v:
[tex]\begin{gathered} \frac{du}{dx}=1 \\ \frac{dv}{dx}=1 \end{gathered}[/tex]Therefore, the derivative of the function is:
[tex]\begin{gathered} f^{\prime}(x)=\frac{(x-6)(1)-(x)(1)}{(x-6)^2} \\ f^{\prime}(x)=\frac{x-6-x}{(x-6)^2} \\ f^{\prime}(x)=\frac{-6}{(x-6)^2} \end{gathered}[/tex]eln(x-3) = 9what are the steps to solve? I am so confused, what is ln even??
Jenna organizes the food in her pantry. She organizes 4 cereal boxes, 6 cans, t pieces of fruit, and 2 bags of rice. How many food items does Jenna organize?
Solution:
The number of food items is given by the following expression:
4 cereal boxes + 6 cans+ t pieces of fruit+ 2 bags of rice
that is, she organizes
4+6+t+2 meals
this is equivalent to
(4+6+2)+t
this is equivalent to say
12 + t meals.
So that the correct answer is:
12 + t
How do you determine 1 and 2/5 - 6/10 =
[tex]\frac{4}{5}[/tex].
Step-by-step explanation:1. Write the expression.[tex]1+\frac{2}{5} -\frac{6}{10}[/tex]
2. Rewrite the fractions with a common denominator.A common denominator is just a number that can be used as a denominator all fractions when we convert them through multiplications. A common denominator is usually found just by multiplying all denominators of all fractions. In this case, we don't need to go that far, since 5 could be a common denominator.This is how you do it:
[tex]1=\frac{1}{1} *\frac{5}{5}=\frac{5}{5} \\ \\\frac{2}{5}= \frac{2}{5}\\\\\frac{6}{10} =\frac{6/2}{10/2}=\frac{3}{5}[/tex]
3. Take all the rewritten fractions and rewrite the operation.[tex]\frac{5}{5} +\frac{2}{5} -\frac{3}{5}[/tex]4. Solve.[tex]\frac{5}{5} +\frac{2}{5} -\frac{3}{5} =\frac{5+2-3}{5} =\frac{4}{5}[/tex]
5. Express your result.[tex]1+\frac{2}{5} -\frac{6}{10}=\frac{4}{5}[/tex].
[tex]\frac{4}{5}[/tex].
Step-by-step explanation:1. Write the expression.[tex]1+\frac{2}{5} -\frac{6}{10}[/tex]
2. Rewrite the fractions with a common denominator.A common denominator is just a number that can be used as a denominator all fractions when we convert them through multiplications. A common denominator is usually found just by multiplying all denominators of all fractions. In this case, we don't need to go that far, since 5 could be a common denominator.This is how you do it:
[tex]1=\frac{1}{1} *\frac{5}{5}=\frac{5}{5} \\ \\\frac{2}{5}= \frac{2}{5}\\\\\frac{6}{10} =\frac{6/2}{10/2}=\frac{3}{5}[/tex]
3. Take all the rewritten fractions and rewrite the operation.[tex]\frac{5}{5} +\frac{2}{5} -\frac{3}{5}[/tex]4. Solve.[tex]\frac{5}{5} +\frac{2}{5} -\frac{3}{5} =\frac{5+2-3}{5} =\frac{4}{5}[/tex]
5. Express your result.[tex]1+\frac{2}{5} -\frac{6}{10}=\frac{4}{5}[/tex].
Factor 9x^4-18x^3+36x^2
Given the expression:
[tex]9x^4-18x^3+36x^2[/tex]You can factor it by following these steps:
1. Find the Greatest Common Factors (GCF) of the terms:
- The Greatest Common Factor (GCF) of the coefficients can be found by decomposing each coefficient into their Prime Factors:
[tex]\begin{gathered} 9=3\cdot3 \\ 18=2\cdot3\cdot3 \\ 36=2\cdot2\cdot3\cdot3 \end{gathered}[/tex]Notice that all the coefficients have:
[tex]3\cdot3=9[/tex]Therefore, that is the Greatest Common Factor (GCF) of the coefficients.
- The Greatest Common Factor (GCF) of the variables is the variable with the lowest exponent:
[tex]x^2[/tex]Hence:
[tex]GCF=9x^2[/tex]2. Now you can factor it out:
[tex]=9x^2(x^2-2x+4)[/tex]Hence, the answer is:
[tex]9x^2(x^2-2x+4)[/tex]PLEASE I NEED THIS ANSWER ASAP!!!!!!
46% of employees judge their peers by the cleanliness of their workspaces. You randomly select 8 employees and ask them whether they judge their peers by the cleanliness of their workspaces. The random variable represents the number of employees who judge their peers by the cleanliness of their workspaces. Complete parts (a) through (c) below.
Using the binomial distribution, the probabilities are given by the image at the end of the answer.
Binomial distributionThe probability mass function is given as follows:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters of the function are described as follows:
n is the number of trials of the experiment.p is the probability of a success on a single trial of the experiment.x is the number of successes that we want to find the probability of.In the context of this problem, the values of these parameters are given as follows:
p = 0.46, as 46% of employees judge their peers by the cleanliness of their workspaces.n = 8, as you randomly select 8 employees and ask them whether they judge their peers by the cleanliness of their workspaces.To complete the table, we find each probability, as follows:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{8,0}.(0.46)^{0}.(0.54)^{8} = 0.0072[/tex]
[tex]P(X = 1) = C_{8,1}.(0.46)^{1}.(0.54)^{7} = 0.0493[/tex]
[tex]P(X = 2) = C_{8,2}.(0.46)^{2}.(0.54)^{6} = 0.1469[/tex]
[tex]P(X = 3) = C_{8,3}.(0.46)^{3}.(0.54)^{5} = 0.2503[/tex]
[tex]P(X = 4) = C_{8,4}.(0.46)^{4}.(0.54)^{4} = 0.2665[/tex]
[tex]P(X = 5) = C_{8,5}.(0.46)^{5}.(0.54)^{3} = 0.1816[/tex]
[tex]P(X = 6) = C_{8,6}.(0.46)^{6}.(0.54)^{2} = 0.0774[/tex]
[tex]P(X = 7) = C_{8,7}.(0.46)^{7}.(0.54)^{1} = 0.0188[/tex]
[tex]P(X = 8) = C_{8,8}.(0.46)^{8}.(0.54)^{0} = 0.0020[/tex]
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8. Kayla finds the multiplication
facts for 12
by doubling the multiplication facts for 6.
Does Kayla's strategy work?
Use words, numbers, or pictures to explain.
A strategy is a way to manipulate numbers, use connections and interactions between numbers to solve an issue. For each procedure, there are a few key tactics. The first thing you do with the statistics is frequently used to categorize, characterize, or label a technique.
What is a doubling strategy?By doubling the multiplication facts for 6, Kayla discovers the 12 multiplication facts.The participant does as instructed, multiplying the number twice or three times. Lily, for instance, rolls "4" and "DDD." She believes that double 4 is equal to 8, double 8 to 16, and double 16 to 32. Four times eight equals 32.A number is simply doubled when multiplied by two, according to the two times table. Any number plus itself is the same as any number multiplied by two.The card below depicts the mental image of two groups of six, or double six, that we want pupils to have. (Students who have been using ten-frames may interpret the amount as ten plus two extra.)To Learn more about strategy refer to:
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what is 2 3/24 simplified
2 3/24
Multiply the denominator by the whole number and add the numerator to obtain the new numerator. the denominator stays the same.
(2x24)+3 /24 = 48+3 /24 = 51/24
simplify by 3
17/8
what should the height of the container be so as to minimize cost
Lets make a picture of our problem:
where h denotes the height of the box.
We know that the volume of a rectangular prism is
[tex]\begin{gathered} V=(4x)(x)(h) \\ V=4x^2h \end{gathered}[/tex]Since the volume must be 8 cubic centimeters, we have
[tex]4x^2h=48[/tex]Then, the height function is equal to
[tex]h=\frac{48}{4x^2}=\frac{12}{x^2}[/tex]On the other hand, the function cost C is given by
[tex]C=1.80A_{\text{bottom}}+1.80A_{\text{top}}+2\times3.60A_{\text{side}1}+2\times3.60A_{\text{side}2}[/tex]that is,
[tex]\begin{gathered} C=1.80\times4x^2+1.80\times4x^2+3.60(8xh+2xh) \\ C=3.60\times4x^2+3.60\times10xh \end{gathered}[/tex]which gives
[tex]C=3.60(4x^2+10xh)[/tex]By substituting the height result from above, we have
[tex]C=3.60(4x^2+10x(\frac{12}{x^2}))[/tex]which gives
[tex]C=3.60(4x^2+\frac{120}{x})[/tex]Now, in order to find minum cost, we need to find the first derivative of the function cost and equate it to zero. It yields,
[tex]\frac{dC}{dx}=3.60(8x-\frac{120}{x^2})=0[/tex]which is equivalent to
[tex]\begin{gathered} 8x-\frac{120}{x^2}=0 \\ \text{then} \\ 8x=\frac{120}{x^2} \end{gathered}[/tex]by moving x squared to the left hand side and the number 8 to the right hand side, we have
[tex]\begin{gathered} x^3=\frac{120}{8} \\ x^3=15 \\ \text{then} \\ x=\sqrt[3]{15} \\ x=2.4662 \end{gathered}[/tex]Therefore, by substituting this value in the height function, we get
[tex]h=\frac{12}{2.4662^2}=1.9729[/tex]therefore, by rounding to the neastest hundredth, the height which minimize the cost is equal to 1.97 cm
helpppppppppppppppppppppppppppppp
Step-by-step explanation:
im still working on the 2nd part
What is 2 2/3 - 3/5? 7/154 4/152 1/15 1 2/5
Hi, can you help me to solve this exercise please, it’s about Function Evaluation & Applications!
Given
[tex]f(x)=\lvert x\rvert+4[/tex]Part A
[tex]\begin{gathered} we\text{ want to find f(4)} \\ we\text{ only n}eed\text{ to substitute the value of 4 to x in the given function} \\ f(4)=\lvert4\rvert+4 \\ f(4)=4+4_{} \\ f(4)=8 \end{gathered}[/tex]Part B
[tex]\begin{gathered} we\text{ want to evaluate f(-4)} \\ \text{note that the absolute value returns postive values} \\ \text{thus, }\lvert-4\rvert=4 \\ f(-4)=\lvert-4\rvert+4 \\ f(-4)=4+4 \\ f(-4)=8 \end{gathered}[/tex]Part C
[tex]\begin{gathered} To\text{ find f(t), we only n}eed\text{ to replace t with x} \\ f(t)=\lvert t\rvert+4 \end{gathered}[/tex]Write an equation of a circle with diameter AB.A(1,1), B(11,11)Choose the correct answer below.A. (X-6)2 + (y-6)2 = 11C. (x-6)2 – (y+6)2 = 50E. (X+6)2 + (y-6)2 = 50G. (X+6)2 – (y + 6)2 = 50
The question asks us to find the equation of a circle with diameter AB with coordinates:
A = (1, 1), B = (11, 11)
In order to solve this, we need to know the general form of the equation of a circle.
The general form of the equation of a circle is given by:
[tex]\begin{gathered} (x-a)^2+(y-b)^2=r^2 \\ \text{where,} \\ (a,b)=\text{ coordinates of the center of the circle} \\ r=\text{radius of the circle} \end{gathered}[/tex]We have been given the coordinates of the diameter. This means that finding the midpoint of the diameter
will give us the center coordinates of the circle, which is (a, b).
The formula for finding the midpoint of a line is given below:
[tex]\begin{gathered} (x,y)=\frac{x_2+x_1}{2},\frac{y_2+y_1}{2} \\ \text{where,} \\ x_2,y_2=\text{ second coordinate} \\ x_1,y_1=\text{first coordinate} \end{gathered}[/tex]For better understanding, a sketch is made below:
Therefore, let us find the coordinates of the center of the circle using the midpoint formula given above:
[tex]\begin{gathered} a,b=\frac{x_2+x_1}{2},\frac{y_2+y_1}{2} \\ x_2=11,y_2=11 \\ x_1=1,y_1=1 \\ \\ \therefore(a,b)=\frac{11+1}{2},\frac{11+1}{2} \\ \\ (a,b)=6,6 \\ Thus, \\ a=6,b=6 \end{gathered}[/tex]Now that we have the coordinates of the center, we now need to find the value of the radius of the circle.
This is done by finding the length from the center of the circle to any side of the diameter.
Let us use from point (6,6) which is the center to the point (11, 11) which is one side of the diameter.
The formula for finding the distance between two points is given by:
[tex]\begin{gathered} |\text{distance}|^2=(y_2-y^{}_1)^2+(x_2-x_1)^2_{} \\ \text{where,} \\ x_2,y_2=\text{second point} \\ x_1,y_1=\text{first point} \end{gathered}[/tex]hence, we can now find the square of the radius as:
[tex]\begin{gathered} r^2=(y_2-y^{}_1)^2+(x_2-x_1)^2_{} \\ x_2,y_2=11,11_{} \\ x_1,y_1=6,6 \\ \\ \therefore r^2=(11-6)^2+(11-6)^2 \\ r^2=5^2+5^2 \\ r^2=25+25 \\ \therefore r^2=50 \end{gathered}[/tex]Now that we have the radius, we can now compute the equation of the circle as:
[tex]\begin{gathered} (x-a)^2+(y-b)^2=r^2 \\ a=6,b=6,r^2=50 \\ \\ \therefore(x-6)^2+(y-6)^2=50\text{ (Option B)} \end{gathered}[/tex]A graph of the circle is given below:
A ball is kicked up in the air from the ground. The height of the ball can be modeled as a function of time in seconds. This function is represented on the graph below. Enter the average rate of change for the height of the ball, measured as feet per second, between 0 seconds and 2 seconds._[blank]_ feet per secondEnter your answer as a number, like this: 42
ANSWER:
2
STEP-BY-STEP EXPLANATION:
The average rate of change is given by the following formula:
[tex]r=\frac{f(b)-f(a)}{b-a}[/tex]Since it is between 0 and 2 seconds, the values of a and b will be these respectively, the evaluated values can be determined by the graph, therefore:
[tex]\begin{gathered} r=\frac{4-0}{2-0}=\frac{4}{2} \\ \\ r=2\text{ feet pe second } \end{gathered}[/tex]The average rate of change is equal to 2 feet per second
Help me please Circle describe and correct each error -2=-3+x/4-2(4)-3+x/4•48=-3+x+3X=11
Answer
The error in the solution is circled (red) in the picture below.
The equation can be solved correctly as follows
[tex]\begin{gathered} -2=\frac{-3+x}{4} \\ \\ Multiply\text{ }both\text{ }sides\text{ }by\text{ }4 \\ \\ -2(4)=\frac{-3+x}{4}\cdot4 \\ \\ -8=-3+x \\ \\ Add\text{ }3\text{ }to\text{ }both\text{ }sides \\ \\ -8+3=-3+x+3 \\ \\ x=-5 \end{gathered}[/tex]Hi hope you are well!!I have a question: When Debbie baby-sits she charges $5 to go the house plus $8 for every hour she is there. The expression 5+8h gives the amount in dollars she charges. How much will she charge to baby-sit for 5 hours? Please help me with this questionHave a nice day,Thanks
5 + 8h
h= number of hours
Replace h by 5 and solve
5 + 8(5)
5 +40
45
She will charge $45
Drag the factors to the correct locations on the image. Not all factors will be used.What is the factored form of this expression?27 m 3 + 125n39m + 25n9m2 - 15mn + 25n23m + 5n9m2 + 15mn + 2523m2 – 8mn + 5123m - 5n
What is the average rate of change from g(1) to g(3)?Type the numerical value for your answer as a whole number, decimal or fractionMake sure answers are completely simplified
The average rate of change from g(1) to g(3)
[tex]\frac{g(x)_3-g(x)_1}{X_3-X_1}_{}[/tex]where
[tex]g(x)_3=-20,g(x)_1=-8,x_3=3,x_1=\text{ 1}[/tex][tex]\begin{gathered} =\frac{-20\text{ --8}}{3-1}\text{ = }\frac{-20\text{ +8}}{2} \\ =\frac{-12}{2} \\ -6 \end{gathered}[/tex]Hence the average rate of change is -6
7. Find the slope of a line which passes through the origin and point (2,4).A 0.5B -0.5C 2D 4
Answer:
C
Step-by-step explanation:
the slope of a line is the ratio (y coordinate change / x coordinate change) when going from one point on the line to another.
in our case here we are going e.g. from the origin (0, 0) to (2, 4).
so, x changes by +2 (from 0 to 2).
y changes by +4 (from 0 to 4).
therefore, the slope is
+4/+2 = 2
FYI - the direction is not important. it works the same way in the other direction. but what is important : once you pick a direction for one coordinate, you have to use the same direction for the second one. you cannot go e.g. for x in one direction and for y in the other.
Is P(A and B) ≠ 0? Explain.
A.) No. P(A and B) = 0.
B.) Yes. Even if P(A) = 0 or P(B) = 0, P(A and B) will always be non-zero.
C.) No. Because both P(A) and P(B) are not equal to 0, P(A and B) = 0.
D.) Yes. Because both P(A) and P(B) are not equal to 0, P(A and B) ≠ 0. (b)
The right option is D as P(A and B) ≠ 0 only for the independent probability events for A and B.
What is an independent event in probability?Two events say A and B are said to be independent if the probability of the intersection of A and B is equal to the product of their respective probability, But same events are said to be mutually exclusive if the probability of the intersection of A and B is equal to zero(0).
In the given question, P(A and B) ≠ 0 can only be true if A and B are independent event and P(A) and P(B) are not equal to zero such that
P(A and B)=P(A)× P(B)≠ 0.
Hence, we can deduce from the axiom of independent events of probability that because both P(A) and P(B) are not equal to 0, P(A and B) ≠ 0.
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Given rectangle BCDE below. If BF = 22, find EF.
Okay, here we have this:
Considering the provided graph, we are going to find the requested measure, so we obtain the following:
Let us remember that a rectangle besides having the properties of a parallelogram also stands out because it has congruent diagonals. So considering this we have:
BD=EC
EF=BF
EF=22
Finally we obtain that EF is equal to 22 units.
What is the low end value, high end value, and does it have an outlier
Solution;
Given the results:
From the above data:
A) The low-end value is
[tex]0[/tex]B) The high end value is
[tex]95[/tex]C) Does this data set have outlier?
[tex]Yes[/tex]D) Outlier:
[tex]95[/tex]Hurry and answer this pls Bc this have to be turned in
Please help me solve. I also need help on what ratios to put in the two boxes before the answer. Do I just choose any of them?
Explanation
By metric conversion
[tex]\begin{gathered} 1\text{ mile =}1.61km \\ 1\text{ hour = 60 mins} \end{gathered}[/tex]Therefore;
[tex]\frac{57mi}{1hr}\times\frac{1.61}{1}\times\frac{1}{60}=1.5295\frac{km}{\min }[/tex]Answer:
[tex]\begin{gathered} \text{Box 1= }\frac{\text{1.61}}{1} \\ \text{Box 2=}\frac{1}{60} \\ \text{Box 3=}1.53 \end{gathered}[/tex]1 B 0 A C If the distance from point A to point C is 7.5 units and O=40°, find the distance from point A to point B to the nearest tenth. (1 Point) a. 8.9 b. 4.7 C. 6.3 d. 2.5
Answer
Option C is correct.
AB = 6.3 units
Explanation
In a right angle triangle, the side opposite the right angle is the Hypotenuse, the side opposite the given angle that is non-right angle is the Opposite and the remaining side is the Adjacent.
Using trignometric relations, we can see that TOA wil work for this
Tan θ = (Opp/Adj)
θ = 40°
Opp = AB = ?
Adj = AC = 7.5 units
Tan 40° = (Opp/7.5)
Opp = AB = 7.5 (Tan 40°) = 6.3 units
Hope this Helps!!!
Find the vertical and horizontal lines that passes through the point (3,6).
We have to find the vertical and horizontal lines that passes through the point (3,6).
A vertical line will be defined as x = constant. If it passes trough a point (x,1,y1), the line will be defined as a x=x1, so the point (x1,y1) belongs to the line.
The same goes for horizontal lines, but in this case the line is defined as y = constant.
For a point (x1,y1), the horizontal line that pass through the point will be y = y1.
Then, for point (x,y)=(3,6), the vertical and horizontal lines as:
x=3 and y=6.
Answer:
Vertical line: x = 3
Horizontal line: y = 6.
A company estimates that that sales will grow continuously at a rate given by the functions S’(t)=15e^t where S’(t) Is the rate at which cells are increasing, in dollars per day, on day t. find the sales from the 2nd day through the 6th day (this is the integral from one to six)
Given the function:
[tex]S^{\prime}(t)=15e^t[/tex]Where S’(t) Is the rate at which sales are increasing (in dollars per day). To find the sales from the second day through the 6th day, we need to integrate this function from t = 1 to t = 6:
[tex]\int_1^6S^{\prime}(t)dt=\int_1^615e^tdt=15\int_1^6e^tdt[/tex]We know that:
[tex]\int e^tdt=e^t+C[/tex]Then:
[tex]15\int_1^6e^tdt=15(e^6-e^1)\approx\text{\$}6010.66[/tex]The sales from the 2nd day through the 6th day are $6,010.66
Leila triples her recipe that calls for 2/5 of a cup of flour. Leila has 1 cup of flour. Does she have enough to triple her recipe?
no
yes
Answer:
No
Step-by-step explanation:
3 × [tex]\frac{2}{5}[/tex] = [tex]\frac{6}{5}[/tex] = 1 [tex]\frac{1}{5}[/tex] cups required to triple her recipe
she only has 1 cup
so does not have enough to triple her recipe
Answer:
No
Step-by-step explanation:
If she triples it that means you need to triple the 2/5 so she would neew 6/5 of flour which is 1/5 more than what she has.
^3square root of 1000
Given the following question:
[tex]\sqrt[3]{1000}[/tex][tex]\begin{gathered} \sqrt[3]{1000} \\ \sqrt[3]{1000}=\sqrt[3]{10^3} \\ 10^3=1000 \\ \sqrt[3]{10^3} \\ \sqrt[n]{a^n}=a \\ \sqrt[3]{10^3}=10 \\ =10 \end{gathered}[/tex]Your answer is 10.