Answers
The equation is given as,
[tex]3e^{5x}=1977[/tex]Transpose the term,
[tex]\begin{gathered} e^{5x}=\frac{1977}{3} \\ e^{5x}=659 \end{gathered}[/tex]Taking logarithm on both sides,
[tex]\ln (e^{5x})=\ln (659)[/tex]Consider the formula,
[tex]\ln (e^m)=e^{\ln (m)}=m[/tex]Applying the formula,
[tex]\begin{gathered} 5x=\ln (659) \\ x=\frac{1}{5}\cdot\ln (659) \\ x\approx1.30 \end{gathered}[/tex]Thus, the solution of the given exponential equation is approximately equal to,
[tex]1.30[/tex]Related Questions
hector recorded the amount of rainfall in the desert each month over a period of two years. the list shows the number of inches fell for each month for year 1 and year 2 year 1: 2,2,0,0,0,1,2,2,3,2,2,2year 2:1,1,0,0,0,0,2,2,2,1,2,1 whats the difference in rain fall between the mean of the rain fall in two years hurry its a test
Answers
ANSWER
The difference is 0.5
EXPLANATION
We have to find the mean of the rain fall for each year. To do this we have to add all the data and then divide by the total number of data.
Year 1: number of data = 12:
[tex]\bar{x_1}=\frac{2+2+0+0+0+1+2+2+3+2+2+2}{12}=\frac{18}{12}=\frac{3}{2}=1.5[/tex]Year 2: number of data = 12:
[tex]\bar{x_2}=\frac{1+1+0+0+0+0+2+2+2+1+2+1}{12}=\frac{12}{12}=1[/tex]The difference is:
[tex]\bar{x}_1-\bar{x}_2=1.5-1=0.5[/tex]Find all x-intercepts of the following function. Write your answer or answers as
coordinate points. Be sure to select the appropriate number of x-intercepts.
f(x)
3x + 30
25x2 - 49
Answers
Given: The function below
[tex]f(x)=\frac{3x+30}{25x^2-49}[/tex]To determine: All x-intercepts of the given function
The x-intercept is a point where the graph crosses the x-axis
We would substitute the function equal to zero and find the value of x
[tex]\begin{gathered} f(x)=\frac{3x+30}{25x^2-49},f(x)=0 \\ \text{Therefore} \\ \frac{3x+30}{25x^2-49}=0 \\ \text{cross}-\text{ multiply} \\ 3x+30=0 \end{gathered}[/tex][tex]\begin{gathered} 3x=-30 \\ \frac{3x}{3}=\frac{-30}{3} \\ x=-10 \end{gathered}[/tex]Therefore, the coordinate of the x-intercept is (-10, 0)
Solve for x: 3x + 2 = 11 A : 11/5 B: 3. C : 11/3. D : 13/3. E : 6
Answers
Explanation:
The equation is given as:
3x + 2 = 11
The first step is to collect like terms ( Note that if 2 crosses to the other side of the equality sign, it becomes -2)
3x = 11 - 2
3x = 9
The next step is to divide both sides by 3:
3x/3 = 9/3
x = 3
Other than no solutions to use interval notation to Express the solution set and then graph the solution set on the number line
Answers
Answer
[tex]7(4x-4)-12x<4(1+4x)-3[/tex]Open the bracket
[tex]\begin{gathered} 28x-28-12x<4+16x-3 \\ collect\text{ the like terms} \\ 28x-12x_{}-16x<4-3+28 \\ 16x-16x<1+28 \\ 0<29 \end{gathered}[/tex]True for all x
[tex](-\infty,\infty)[/tex]Determine the rate of change of a line that passes through the coordinates G (-13, -4) andB (7, -12). Reduce when necessary. (Show all work)
Answers
EXPLANATION:
-We must first identify the points that correspond to the x-axis and the points that correspond to the y-axis.
-To calculate the slope, then we apply the formula of the slope or rate of change which is the following:
[tex]\begin{gathered} \text{the rate of change :} \\ m=\frac{y2-y1}{x2-x1}\text{ } \end{gathered}[/tex]-now we must correctly locate the points in the formula.
[tex]\begin{gathered} G\text{ }(-13,-4),\text{ X1}=-13\text{ and y1}=-4 \\ B(7,-12);\text{ X2}=7\text{ and y2}=-12 \\ m=\frac{-12-(-4)}{7-(-13)}\text{ }=\frac{-12+4}{7+13}=\frac{-8}{20}=\frac{-4}{10} \\ simplify;\text{ }\frac{-4}{10}=\frac{-2}{5} \end{gathered}[/tex]-
Louis borrowed $500 from his bank. His bank will charge Louis 8% simple interest per year to loan him the money. If he paid back the total amount he owed the bank, including interest, in 6 months, how much should he have paid?
Answers
The amount that he owed the bank and paid is $520.
What will the interest be?The simple interest is calculated as:
= Principal × Rate × Time / 100
Principal = $500
Rate = 8%
Time = 6 months = 6/12 = 0.5 years
The interest will be:
= PRT / 100
= (500 × 8 × 0.5)/100
= 2000/100
= $20
The amount paid back will be:
= Principal + Interest
= $500 + $20
= $520
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Explain how rays AB and AC form both a line and an angle.
Answers
Answer:
The point from C goes straight until it reaches A and stull continues till it gets ti B and stops. The angle is then given as 180°
which system of equations can be used to determine how many quarters, x, and how many nickels, y, he has?
Answers
Given: Alfred has 12 coins in his piggy bank. Some of the coins are quarters, some are nickels, and have a total of $3.15.
Required: To determine the system of linear equations for the given situation.:
Solve for x: 4 open parentheses 2 x minus 1 close parentheses plus 8 minus 14 x equals negative 8 x plus 4 plus 2 x The solution is X = _________
Answers
Answer:
x = 1
Step-by-step explanation:
4(2x-1)+8-14= -8x+ 4+ 2x
Part of a manufacturing plant packages tissues in boxes. Each box contains 250 tissues. Part A: Write an algebraic expression that can be used to find the total number of tissues packaged one day. Describe what the variable stands for in your expression. Part B: In one hour, 87,500 tissues are packaged into boxes. How many boxes of tissues are packaged? Show your work. Answer: boxes
Answers
Given
A manufacturing plant packages tissues in boxes and each box contains 250 tissues.
Required
We need to find an algebraic expression that illustrates the number of tissues packed per day.
Explanation
Let x be the number of boxes manufactured in one day
Then total number of tissues manufactured on that day is 250x
This answers our first part.
Now in one hour 87500 tissues are manufactured
Let the number of boxes packed in one hour be y
Then
[tex]y=\frac{number\text{ }of\text{ }tissues\text{ }in\text{ }one\text{ }hour}{number\text{ }of\text{ }tissues\text{ }in\text{ }each\text{ }box}=\frac{87500}{250}=350\text{ boxes}[/tex]So the answer to second part is 350 boxes.
please help! prove by bubble proof. please show you work
Answers
Statement | Reason
Points M and N are on AB | Given
AM ≅ NB | Given
AM + MN ≅ NB + MN | Addition Property of Equality
AM + MN = AN | Segment Addition Postulate
NB + MN = MB | Segment Addition Postulate
AN ≅ MB | Substitution Property of Equality
can you help me please
Answers
Draw a line connecting each sphere to its volume in terms of π and round it to the nearest tenth. (Not all of the values will be used.)
Answers
Remember that
The volume of a sphere is equal to
[tex]V=\frac{4}{3}\pi r^3[/tex]N 1
we have
D=9 units
r=9/2=4.5 units
substitute
[tex]\begin{gathered} V=\frac{4}{3}\pi(4.5)^3 \\ V=121.5\pi\text{ unit3} \\ V=381.5\text{ unit3} \end{gathered}[/tex]N 2
we have
r=2 units
[tex]\begin{gathered} V=\frac{4}{3}\pi2^3 \\ V=10.6\pi\text{ unit3} \\ V=33.5\text{ unit3} \end{gathered}[/tex]N 3
we have
D=14 units
r=14/2=7 units
[tex]\begin{gathered} V=\frac{4}{3}\pi7^3 \\ V=457.3\pi\text{ unit3} \\ V=1,436\text{ unit3} \end{gathered}[/tex]N 4
we have
r=9 units
[tex]\begin{gathered} V=\frac{4}{3}\pi9^3 \\ V=972\pi\text{ unit3} \\ V=3,052.1\text{ unit3} \end{gathered}[/tex]For each ordered pair, determine whether it is a solution to 3x + 5y=-17. Is it a solution? X 6 ? No (-8,3) (-4, -1) (6, 7) (7,2)
Answers
Determine whether is a solution for:
[tex]\begin{gathered} 3x+5y=-17 \\ To\text{ determine if it's a solution, we can isolate y and see if the statement} \\ is\text{ true:} \\ 5y=-17-3x \\ y=-\frac{17}{5}-\frac{3}{5}x \end{gathered}[/tex]For, x=-8, y has to be 3:
[tex]\begin{gathered} y=-\frac{17}{5}-\frac{3}{5}(-8) \\ y=\frac{7}{5}=1.4 \end{gathered}[/tex](-8, 3) is not a solution for the equation.
For x=-4, y has to be -1:
[tex]\begin{gathered} y=-\frac{17}{5}-\frac{3}{5}(-4) \\ y=-1 \end{gathered}[/tex](-4, -1) is a solution for the equation.
For x=6, y has to be -7:
[tex]\begin{gathered} y=-\frac{17}{5}-\frac{3}{5}(6) \\ y=-7 \end{gathered}[/tex](6, -7) is a solution for the equation.
For x=7, y has to be 2
[tex]\begin{gathered} y=-\frac{17}{5}-\frac{3}{5}(7) \\ y=-\frac{38}{5}=-7.6 \end{gathered}[/tex](7, 2) is not a solution for the equation.
Angle RQT is a straight angle. What are m angle RQS and m angle TQS? Show your work.
Answers
11x + 5 + 8x + 4 = 180
Simplifying like terms
11x + 8x = 180 - 5 - 4
19x = 171
x = 171/19
x = 9
RQS = 11(9) + 5
= 99 + 5
= 104°
TQS = 8(9) + 4
= 72 + 4
= 76°
what is an equation of the line that passes through the point -6 and -7 and is perpendicular to the line 6x+5y=30I got y=5/6-2 but apparently its wrong
Answers
First we can find the slope. The standard form of the equation of a line is:
[tex]y=ax+b[/tex]Where a is the slope and b is the intercept.
When 2 lines are perpendicular, the slopes are reciprocal and opposite to each other. If we write the given equation of the perpendicular line in the standard form we have:
[tex]6x+5y=30\rightarrow y=-\frac{6}{5}x+\frac{30}{5}\rightarrow y=-\frac{6}{5}x+6[/tex]So you got the slope right, it's 5/6.
Now, with the given point we find the intercept. The point is x = -6 and y = -7, so we replace these values into the expression we have until now:
[tex]y=\frac{5}{6}x+b[/tex][tex]-7=\frac{5}{6}(-6)+b[/tex]And solve for b
[tex]-7=-5+b\rightarrow b=-7+5=-2[/tex]So the equation of the line is:
[tex]y=\frac{5}{6}x-2[/tex]Tan (a) cos (a)= sin (a)Trig: use trigonometric identities to transform the left side of the equation into the right side
Answers
hello
the question here relates to trionometric identies and we can easily solve this once we know some of the identities
for example
[tex]undefined[/tex]A number multiplied by 2/5 is 3/20, Find the number
Answers
Answer:
3/8
Explanation:
Let the number be x.
A number multiplied by 2/5 = (2/5)x
Therefore:
[tex]\frac{2}{5}x=\frac{3}{20}[/tex]To solve for x, first, we cross-multiply.
[tex]\begin{gathered} 2x\times20=3\times5 \\ 40x=15 \end{gathered}[/tex]Next, we divide both sides of the equation by 40.
[tex]\begin{gathered} \frac{40x}{40}=\frac{15}{40} \\ x=\frac{3}{8} \end{gathered}[/tex]The number is 3/8.
Jordan’s of Boston sold Lee Company of New York computer equipment with a $7,000 list price. Sale terms were 4/10, n/30 FOB Boston. Jordan’s agreed to pay the $400 freight. Lee pays the invoice within the discount period. What does Lee pay Jordan’s?
Answers
If Sale terms were 4/10, n/30 FOB Boston and Jordan’s agreed to prepay the $400 freight. Lee pays the invoice within the discount period. The amount that Lee pay Jordan’ s is $7,120.
What is the amount received?Using this formula
Amount received = [ ( Cost of computer equipment × ( 1 - rate )] + Freight
Let plug in the formula
Amount received = [ $7,000 × ( 1 - 0.04) ] +$400
Amount received = ( $7,000 x .96 ) + $400
Amount received = $6,720 + 400
Amount received = $7,120
Therefore Lee pay Jordan the amount of $7,120.
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please help me with this. four potential solutions.450, 780, 647, 354
Answers
So first of all let's take:
[tex]x_1=x\text{ and }x_2=y[/tex]Then we get:
[tex]\begin{gathered} \text{Min}z=1.5x+2y \\ x+y\ge300 \\ 2x+y\ge400 \\ 2x+5y\leq750 \\ x,y\ge0 \end{gathered}[/tex]The next step would be operate with the inequalities and the equation so we end up having only the term y at the left side of each:
[tex]\begin{gathered} \text{Min}z=1.5x+2y \\ 1.5x+2y=\text{Min}z \\ 2y=\text{Min}z-1.5x \\ y=\frac{\text{Min}z}{2}-0.75x \end{gathered}[/tex][tex]\begin{gathered} x+y\ge300 \\ y\ge300-x \end{gathered}[/tex][tex]\begin{gathered} 2x+y\ge400 \\ y\ge400-2x \end{gathered}[/tex][tex]\begin{gathered} 2x+5y\leq750 \\ y\leq150-\frac{2}{5}x \end{gathered}[/tex]So now we have the following inequalities and equality:
[tex]\begin{gathered} y=\frac{\text{Min}z}{2}-0.75x \\ y\ge300-x \\ y\ge400-2x \\ y\leq150-\frac{2}{5}x \end{gathered}[/tex]If we take the three inequalities and replace their symbols by "=' we'll have three equations of a line:
[tex]\begin{gathered} y=300-x \\ y=400-2x \\ y=150-\frac{2}{5}x \end{gathered}[/tex]The following step is graphing these three lines and delimitating a zone in the grid that meets the inequalities:
Where the blue area is under the graph of y=150-(2/5)x which means that it meets:
[tex]y\leq150-\frac{2}{5}x[/tex]And it is also above the x-axis, y=400-2x and y=300-x which means that it also meets:
[tex]\begin{gathered} x\ge0 \\ y\ge0 \\ y\ge400-2x \\ y\ge300-x \end{gathered}[/tex]All of this means that the values of x and y that give us the correct minimum of z are given by the coordinates of a point inside the blue area. The next thing to do is take the four possible values for Min(z) and use them to graph four lines using this equation:
[tex]y=\frac{\text{Min}z}{2}-0.75x[/tex]Then we have four equations of a line:
[tex]\begin{gathered} y=\frac{450}{2}-0.75x \\ y=\frac{780}{2}-0.75x \\ y=\frac{647}{2}-0.75x \\ y=\frac{354}{2}-0.75x \end{gathered}[/tex]The line that has more points inside the blue area is the one made with the closest value to Min(z). Then we have the following graph:
As you can see there are two lines that have points inside the blue area. These are:
[tex]\begin{gathered} y=-\frac{3}{4}x+\frac{450}{2} \\ y=-\frac{3}{4}x+\frac{354}{2} \end{gathered}[/tex]That where made using:
[tex]\begin{gathered} \text{Min }z=450 \\ \text{Min }z=354 \end{gathered}[/tex]Taking a closer look you can see that the part of the orange line inside the blue area is larger than that of the red line. Then the value used to make the orange line would be a better aproximation for the Min z. The orange line is -(3/4)x+450/2 which means that the answer to this problem is the first option, 450.
Assume that each circle shown below represents one unit. Express the sha amount as a single fraction and as a mixed number. One Fraction: Mixed Number:
Answers
The shaded portions for the first three circles are a total of 15 while for the fourth one is 1. As a fraction it is therefore,
[tex]\frac{16}{5}[/tex]As mixed numbers it is;
[tex]3\frac{1}{5}[/tex]Write the following equation in standard form: x + x4 + 6x +1
Answers
To answer this question, we need to know that the standard form of an equation of this type is written as follows:
[tex]ax^5+bx^4+cx^3\ldots[/tex]We have that the polynomial given is:
[tex]\frac{8}{7}x^3+x^4+6x+1[/tex]In the standard form, we need to write it as follows:
[tex]x^4+\frac{8}{7}x^3+0x^2+6x+1=x^4+\frac{8}{7}x^3+6x+1[/tex]Therefore, the correct answer is option C. This is the standard form for this fourth-degree polynomial.
in slope intercept form what is the line perpendicular to y=2x -5 that passes through the (2, -5) point
Answers
The most appropriate choice for equation of line in slope intercept form will be given by-
[tex]y = -\frac{1}{2}x - 4[/tex] is the required equation of line
What is equation of line in slope intercept form?
The most general form of equation of line in slope intercept form is given by y = mx + c
Where m is the slope of the line and c is the y intercept of the line.
Slope of a line is the tangent of the angle that the line makes with the positive direction of x axis.
If [tex]\theta[/tex] is the angle that the line makes with the positive direction of x axis, then slope (m) is given by
m = [tex]tan\theta[/tex]
The distance from the origin to the point where the line cuts the x axis is the x intercept of the line.
The distance from the origin to the point where the line cuts the y axis is the y intercept of the line.
Here,
The given equation of line is y = 2x-5
Slope of this line = 2
Slope of the line perpendicular to this line = [tex]-\frac{1}{2}[/tex]
The line passes through (2 , -5)
Equation of the required line = [tex]y - (-5) = \frac{1}{2}(x - 2)[/tex]
[tex]y +5=-\frac{1}{2}x+1\\y = -\frac{1}{2}x +1 -5\\y = -\frac{1}{2}x -4[/tex]
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Elsa drove 14 laps on a race track. Each lap was the same length. If she drove atotal of 30.8 mi what was the length of each lap? Write your answer in yards.Use the table of conversion facts as necessary, and do not round your answer.Conversion facts for length12 inches (in) = 1 foot (ft)3 feet (ft) = 1 yard (yd)36 inches (in) = 1 yard (yd)5280 feet (ft) = 1 mile (mi)1760 yards (yd) = 1 mile (mi)|0ydGХ?
Answers
Givens.
• The total number of laps is 14.
,• The total distance is 30.8 miles.
First, divide the total distance by the number of laps.
[tex]\frac{30.8mi}{14}=2.2mi[/tex]Each lap length is 2.2 miles.
Let's transform it to yards using the conversion factor 1 mile = 1760 yards.
[tex]2.2mi\cdot\frac{1760yd}{1mi}=3872yd[/tex]Therefore, each lap length is 3872 yards.
Consider the following expression:3Step 2 of 2: Determine the degree and the leading coefficient of the polynomial.AnswerHow to enter your answer (opens in new window)KeybcPreviouDegree:Leading Coefficient:
Answers
Solution
We are given the expression
[tex]3[/tex]The image below shows the definition of a polynomial and some examples as well
Thus, given
[tex]3[/tex]Here;
Degree = 0
Leading coefficient = 3
Calculate Sy for the arithmetic sequence in which ag = 17 and the common difference is d =-21.O A -46O B.-29.2O C. 32.7O D. 71.3
Answers
Given: An arithmetic sequaence has the following parameters
[tex]\begin{gathered} a_9=17 \\ d=-2.1 \end{gathered}[/tex]To Determine: The sum of the first 31st term.
Please note that the sum of the first 31st term is represented as
[tex]S_{31}=\text{ sum of the first 31st term}[/tex]The formula for the finding the n-term of an arithmetic sequence (AP) is
[tex]\begin{gathered} a_n=a+(n-1)d \\ \text{Where} \\ a_n=n-\text{term} \\ a=\text{first term} \\ d=\text{common difference} \end{gathered}[/tex]Since, we are given the 9th term as 17, we can calculate the first term a, as shown below:
[tex]\begin{gathered} a_9=17 \\ \text{Substituting into the formula} \\ a_9=a+(9-1)d \\ a_9=a+8d \\ \text{Therefore:} \\ a+8d=17 \\ d=-2.1 \\ a+8(-2.1)=17 \\ a-16.8=17 \\ a=17+16.8 \\ a=33.8 \end{gathered}[/tex]Calculate the sum of the first 31st term.
The formula for finding the first n-terms of an arithmetic series is given as
[tex]S_n=\frac{n}{2}(2a+(n-1)d)[/tex]We are given the following:
[tex]a=33.8,n=31,d=-2.1[/tex]Substitute the given into the formula:
[tex]\begin{gathered} S_{31}=\frac{31}{2}(2(33.8)+(31-1)-2.1) \\ S_{31}=15.5(67.6)+(30)-2.1) \\ S_{31}=15.5(67.6-63) \end{gathered}[/tex][tex]\begin{gathered} S_{31}=15.5(4.6) \\ S_{31}=71.3 \end{gathered}[/tex]Hence, the sum of the first 31st term of the A.P is 71.3, OPTION D
What is the slope and y-intercept?
Answers
Answer/Step-by-step explanation:
y = mx + b
Slope = m
y₂ - y₁
---------- = m
x₂ - x₁
----------------------------------------------------------------------------------------------------------
y - intercept = b
y - y₁ = m(x - x₁)
If there's an equation I can solve it, but I hope this helps!
When looking at a graph of a line, there are two things you should look for straight off the bat. First, the y-intercept. And second, the slope.
The equation of a line is y = mx + b, where m is the slope, b is the y-intercept, and x is the input.
What is slope?
Slope is a number that determines how the line changes. It is often referred to as the "rate of change" because it represents how much the y-value of the line changes when the input (x) changes. The formula for slope is:
[tex]m = \frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex]
Breakdown: This formula represents the change in the line, typically left to right. It shows the change in x-value over the change in corresponding y-value. This is also known as "rise over run," because the y-value is how much the line changes vertically, while the x-value is how much it changes horizontally.
Example: Let's say our line has a slope of 4, or m = 4/1. This means the y-value will change 4 units when the x-value changes by 1.
What is y-intercept?
Y-intercept is a value that determines the location of the line. When x = 0, the value of b will be the y-value. Essentially, when the line crosses the y-axis, that will be the y-value of the line.
HELP PLS A line includes the points (9,10) and (6,9). What is its equation in point-slope form?
Use one of the specified points in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.
Answers
Answer:
[tex]y-10=\dfrac{1}{3}(x-9)[/tex]
Step-by-step explanation:
[tex]\boxed{\begin{minipage}{4.4cm}\underline{Slope Formula}\\\\Slope $(m)=\dfrac{y_2-y_1}{x_2-x_1}$\\\\where $(x_1,y_1)$ and $(x_2,y_2)$ \\are two points on the line.\\\end{minipage}}[/tex]
To find the equation of a line that passes through two given points, first find its slope by substituting the given points into the slope formula.
Define the points:
(x₁, y₁) = (9, 10)(x₂, y₂) = (6, 9)Substitute the points into the slope formula:
[tex]\implies m=\dfrac{9-10}{6-9}=\dfrac{-1}{-3}=\dfrac{1}{3}[/tex]
Therefore, the slope of the line is ¹/₃.
[tex]\boxed{\begin{minipage}{5.8 cm}\underline{Point-slope form of a linear equation}\\\\$y-y_1=m(x-x_1)$\\\\where:\\ \phantom{ww}$\bullet$ $m$ is the slope. \\ \phantom{ww}$\bullet$ $(x_1,y_1)$ is a point on the line.\\\end{minipage}}[/tex]
To find the equation in point-slope form, simply substitute the found slope and one of the given points into the point-slope formula:
[tex]\implies y-10=\dfrac{1}{3}(x-9)[/tex]
can (x^4y)^(2/3) be simplified yes or no
Answers
Answer:
yes
we are need multiple the exponents in (x^4y)^(2/3).
[tex]x \frac{8y}{3} [/tex]
so hope it help
Answer:
[tex]x^\frac{8}{3} y^\frac{2}{3}[/tex]
Step-by-step explanation:
I'm not sure if you mean
[tex](x^4y)^\frac{2}{3}[/tex]
or
[tex](x^{4y})^\frac{2}{3}[/tex]
but I'll go with the first one
[tex](x^4y)^\frac{2}{3}[/tex]
(distribute the 2/3) (if the y is by it self, it basically is [tex]y^1[/tex])
[tex]x^\frac{8}{3} y^\frac{2}{3}[/tex]
done
1. Write the value of the digit in the hundreds place and the value of the digit in the tens place in 440. What is the relationship between the values of those two digits? The ___ in the in the hundreds place has a value _____ times as great as the____in the ____ place.
Answers
The ___ in the in the hundreds place has a value _____ times as great as the____in the ____ place.
• We have 440
,• 400 + 40
,• Four hundreds + four tens
The relationship between the values of these two digits is that they are the same, but the four in the hundreds place has a value ten times as great as the four in the tens place.
