solve for x. then find the missing piece(s) of the parallelogram for #7

Solve For X. Then Find The Missing Piece(s) Of The Parallelogram For #7

Answers

Answer 1

[tex]\begin{gathered} 2x+30+2x-10=180 \\ 2x+2x+30-10=180 \\ 4x+20=180 \\ 4x=160 \\ x=\frac{160}{4} \\ x=40^0 \end{gathered}[/tex]

Let us find the angles of the parallelogram below

[tex]\begin{gathered} 2x+30 \\ x=40 \\ 2(40)+30 \\ 80+30 \\ 110^0 \end{gathered}[/tex][tex]\begin{gathered} 2x-10 \\ 2(40)-10 \\ 80-10 \\ 70^0 \end{gathered}[/tex]

Theorem+: opposite angles of a parallelogram are the same

Hence the angles of the parallelogram are 110, 70, 110, and 70

Solve For X. Then Find The Missing Piece(s) Of The Parallelogram For #7

Related Questions

Is r = 3 + 3sin θ symmetrical along the y axis?

Answers

Answer:

Yes.  r = 3 + 3sin θ is symmetrical along the y axis

Step-by-step explanation:

Original polar equation is

r = 3 + 3sinθ

If this plot is to be symmetrical about the y axis then replacing Θ with (π-θ) in the original equation should not change the equation and thereby should not change the plot

r = 3 + 3sinθ

Replace θ with π-θ:

==>  3 + 3sin(π-θ)

But sin(π-θ) = sinθ

So the equation is unchanged at 3 + 3sin(π-θ) from the original equation r = 3 + 3sinθ

Hence the equation is symmetrical along the y-axis

This can be also be clearly seen if you plot both the equations, you will see the plot does not change

Approximately how old would you be in the years if you lived 1,000,000 hours? round your answer to the nearest whole number.

Answers

First let's see how many hours are in a year:

[tex]\begin{gathered} 1\text{ year }\rightarrow\text{ 365 days} \\ 1\text{ day }\rightarrow\text{ 24 hours} \\ \Rightarrow1\text{ year }\rightarrow365\cdot24=8760\text{ hours} \end{gathered}[/tex]

We found that 1 year has 8769 hours, then if we lived 1,000,000 hours, we have to divide it by 8760 to know the number of years lived:

[tex]\frac{1000000}{8760}=114.15[/tex]

therefore, you would have lived 114.15 years

A bee produce 0,05 ml of honey per day, how many litres of honey can the bee produce in its lifetime if they live for 28 days?

Answers

Given:

A bee produce 0.05 ml of honey per day

We will find how many liters of honey can the bee produce in its lifetime if they live for 28 days

Let it produces x ml

So, using the ratio and proportions

[tex]\frac{0.05}{1}=\frac{x}{28}[/tex]

Solve for x:

[tex]x=0.05\times28=1.4ml[/tex]

Convert ml to liters

1 liter = 1000 ml

So, 1.4 ml = 0.0014 liters

So, the answer will be

The bee can produce honey in its lifetime = 0.0014 liters

For which equation would x = 12 not be a solution?96 ÷ x = 89 x - 7 = 101x + 4 = 105 + 4 x = 53

Answers

Notice that:

1)

[tex]\frac{96}{12}=8.[/tex]

Therefore x=12 is a solution to

[tex]96\div x=8.[/tex]

2)

[tex]9*12-7=108-7=101.[/tex]

Therefore x=12 is a solution to:

[tex]9x-7=101.[/tex]

3)

[tex]12+4=16\ne10.[/tex]

Therefore x=12 is not a solution to:

[tex]x+4=10.[/tex]

4)

[tex]5+4*12=5+48=53.[/tex]

Therefore x=12 is a solution to:

[tex]5+4x=53.[/tex]

Answer: Third option:

[tex]x+4=10.[/tex]

What is the volume of this triangle right prism 8 cm 15 cm 12 cm

Answers

The volume of a triangle right prism is given by the formula

Solve the following inequality for t. Write your answer in the simplest form.6t + 3 < 7t + 10

Answers

[tex]\begin{gathered} \text{Given} \\ 6t+3<7t+10 \end{gathered}[/tex]

[tex]\begin{gathered} \text{Subtract both sides by }10 \\ 6t+3<7t+10 \\ 6t+3-10<7t+10-10 \\ 6t-7<7t\cancel{+10-10} \\ 6t-7<7t \\ \\ \text{Then subtract both sides by }6t \\ 6t-7<7t \\ 6t-6t-7<7t-6t \\ \cancel{6t-6t}-7-7 \end{gathered}[/tex]

Therefore, the solution is t > -7.

I'm attempting to solve and linear equation out of ordered pairs in slopes attached

Answers

Line equationInitial explanation

We know that the equation of a line is given by

y = mx + b,

where m and b are numbers: m is its slope (shows its inclination) and b is its y-intercept.

In order to find the equation we must find m and b.

In all cases, m is given, so we must find b.

We use the equation to find b:

y = mx + b,

↓ taking mx to the left side

y - mx = b

We use this equation to find b.

1

We have that the line passes through

(x, y) = (-10, 8)

and m = -1/2

Using this information we replace in the equation we found:

y - mx = b

↓ replacing x = -10, y = 8 and m = -1/2

[tex]\begin{gathered} 8-(-\frac{1}{2})\mleft(-10\mright)=b \\ \downarrow(-\frac{1}{2})(-10)=5 \\ 8-5=b \\ 3=b \end{gathered}[/tex]

Then, the equation of this line is:

y = mx + b,

y = -1/2x + 3

Equation 1: y = -1/2x + 3

2

Similarly as before, we have that the line passes through

(x, y) = (-1, -10)

and m = 0

we replace in the equation for b,

y - mx = b

↓ replacing x = -1, y = -10 and m = 0

-10 - 0 · (-1) = b

↓ 0 · (-1) = 0

-10 - 0 = b

-10 = b

Then, the equation of this line is:

y = mx + b,

y = 0x - 10

y = -10

Equation 2: y = -10

3

Similarly as before, we have that the line passes through

(x, y) = (-6, -9)

and m = 7/6

we replace in the equation for b,

y - mx = b

↓ replacing x = -6, y = -9 and m = 7/6

[tex]\begin{gathered} -9-\frac{7}{6}(-6)=b \\ \downarrow\frac{7}{6}(-6)=-7 \\ -9-(-7)=b \\ -9+7=b \\ -2=b \end{gathered}[/tex]

Then, the equation of this line is:

y = mx + b,

y = 7/6x - 2

Equation 3: y = 7/6x - 2

4

The line passes through

(x, y) = (6, -4)

and m = does not exist

When m does not exist it means that the line is vertical, and the equation looks like:

x = c

In this case

(x, y) = (6, -4)

then x = 6

Then

Equation 4: x = 6

5

The line passes through

(x, y) = (6, -6)

and m = 1/6

we replace in the equation for b,

y - mx = b

↓ replacing x = 6, y = -6 and m = 1/6

[tex]\begin{gathered} -6-\frac{1}{6}(6)=b \\ \downarrow\frac{1}{6}(6)=1 \\ -6-(1)=b \\ -7=b \end{gathered}[/tex]

Then, the equation of this line is:

y = mx + b,

y = 1/6x - 7

Equation 5: y = 1/6x - 7

solve the equation 3x^2 - 5x + 1 = 0 expressing your answer correct to two decimal places

Answers

You have th following equation;

[tex]3x^2-5x+1=0[/tex]

In order to find the solution to the previous equation, use the quadratic formula:

[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]

In this case, a = 3, b = -5 and c = 1. By replacing these values into the quadratic formula, you obtain:

[tex]\begin{gathered} x=\frac{-(-5)\pm\sqrt[]{(-5)^2-4(3)(1)}}{2(1)} \\ x=\frac{5\pm\sqrt[]{25-12}}{2}=\frac{5\pm\sqrt[]{13}}{2} \\ x=\frac{5\pm3.60}{2}=2.5\pm1.80 \end{gathered}[/tex]

Hence, the solutions are:

x = 2.5 + 1.80 = 4.30

x = 2.5 - 1.80 = 0.70

I child drinks 1 1/2 cups of milk twice a day.If a container of milk has 15 cups of milk remaining for the child to drink ,in how many days will the container be empty?

Answers

Data

Milk drank = 1 1/2 twice a day

Volume in a container = 15 cups

Number of days the contaier will be empty = ?

Procedure

To solve this problem just divide the volume of the container by the milk drank by the child.

As the child drinks 1 1/2 twice a day, the total milk drank in a day will be = 2 x 1 1/2 = 3

Division 15/3 = 5

Solution: The container will be empty in 5 days

10. (01.04 LC)
Your first six-month auto insurance premium was $658.00. Based on your driving record, your renewal premium is $756.70. What percent increase did you see in your premium? (1
12%
15%
28%
35%

Answers

There is 15% in the premium.

How take out percentage?

From the Latin word "per centum," which meaning "by the hundred," the word "percentage" was borrowed. The denominator of percent's is 100, making them fractions. In other words, it is the relationship between a component and a whole in which the value of the entire is consistently set to 100. The value of the entire is always 100 in a percentage, which is a ratio or fraction. Sam, for instance, would have received a score of 30 out of 100 on his arithmetic test if he received a 30%. When expressed as a ratio, it is written as 030:10 and as a fraction, 30/100. An quantity or part that is contained in each hundred is known as a percentage. The symbol "%" signifies that it is a fraction with 100 as the denominator.

First six-month auto insurance = $658

Renewal premium = $756

Change in the insurance = $98

percentage of $98 from $658

= 15%

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find the surface area of the figure and round to the nearest

Answers

The figure in the image is a Hemisphere.

The surface area of a hemisphere is given as:

[tex]3\text{ }\times\text{ }\pi\text{ }\times r^2[/tex]

Thus, the surface area is:

[tex]\begin{gathered} 3\text{ }\times\text{ 3.142 }\times8.6^2 \\ 697.15ft^2 \end{gathered}[/tex]

Hence, the surface area of the figure, to the nearest whole number is 697 square feet.

How can I know how many students scored 5 in their test?

Answers

Based on the given table, consider that the value in the column frequency specifies the number of times that a certain score (first column) is repeated in a given data.

In this case, the value of the frequency for a specific score determines the number of students with such a score in their tests.

As you can notice, for the value of the frequency equal to 3, the corresponding value of the score is 5. It means that 3 student get 5 scores in their tests.

what is the volume of a right triangular pyramid whose base is 5 meters on each side and whose altitude is 4 meters? round to the nearest hundred

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

Right triangular pyramid

base = 5 meters

altitude = 4 meters

Volume = ?

Step 02:

The volume of a right triangular pyramid

V = 1/3 B * h

B = 1/2 b * h

[tex]\begin{gathered} B\text{ = }\frac{1}{2}\cdot5m\cdot4m \\ B=\text{ }10m^2 \end{gathered}[/tex][tex]V\text{ = }\frac{1}{3}\cdot10m^2\cdot4m=\text{ }13.3333m^3[/tex]

The answer is:

The volume of the pyramid is 13.33 m³.

HeyI need help with this, having trouble solvingIt is from my ACT prep guide

Answers

We will determine the height of the building as follows:

First, we determine the height above her window, that is:

[tex]\tan (56)=\frac{h_u}{150ft}\Rightarrow h_u=(150ft)\tan (56)[/tex][tex]\Rightarrow h_u=222.3841453\ldots ft[/tex]

Now, we calculate the height below her window:

[tex]\tan (32)=\frac{h_l}{150ft}\Rightarrow h_l=(150ft)\tan (32)[/tex][tex]\Rightarrow h_l=93.73040279\ldots ft[/tex]

Then, we will have that:

[tex]h_T=h_l+h_l\Rightarrow h_T=150(\tan (56)+\tan (32))[/tex][tex]\Rightarrow h_T=316.1145581\ldots ft\Rightarrow h_T\approx316.1ft[/tex]

So, the height of the building is approximately 316.1 ft tall.

Robin is saving money to buy a 720$ phone. she has 105$ saved, and each week she adds 30$ to her savings. write an equation to find the number of weeks (w) until she has enough savings to buy the phone.

Answers

Let call w the number of weeks she has been saving.

Then, we can write the expression for her saving in function of the number of weeks as:

[tex]S(w)=105+30\cdot w[/tex]

We now have to find the number of weeks it will take for her savings to reach $720.

We can find it by calculating w for S(w)=720:

[tex]\begin{gathered} S(w)-105+30w=720 \\ 105+30w=720 \\ 30w=720-105 \\ 30w=615 \\ w=\frac{615}{30} \\ w=20.5\approx21 \end{gathered}[/tex]

Answer: it will take her 21 weeks to have enough savings.

Identify the segments that are parallel, if any, if ∠ADH≅∠ECK.A. AD¯¯¯¯¯¯¯¯ || CB¯¯¯¯¯¯¯¯B. AC¯¯¯¯¯¯¯¯ || CD¯¯¯¯¯¯¯¯C. AE¯¯¯¯¯¯¯¯ || CB¯¯¯¯¯¯¯¯D. none of these

Answers

Hi there. To solve this question, we have to remember some properties about similar triangle and congruency.

Given the triangles ADH and ECK,

We know that

[tex]\angle ADH\cong\angle ECK[/tex]

That is, the angle at D is congruent to the angle at C in the respective triangles.

In this case, we can think of the congruency between the triangles in the following diagram:

Notice that ADCB is a parallelogram and the angles given show that the angles at D and at C are congruent, hence the other angles in the parallelogram must be congruent as well.

This means that opposite sides are parallel and have the same measure (length).

The opposite sides are AD and CB and DC and AB.

In this case, we find that only AD and CB are an option to this question, therefore the correct answer.

In fact, AC is the diagonal of the parallelogram and is not parallel to any segment of the figure.

AE isn't a segment drawn and hence not parallel to any other segment.

The correct answer is the option A).

10Estimate the solution to the following system of equations by graphingOA (1,7)OB. (-1,1)OC.OD. (-1,-1)

Answers

we have the system of equations

-4x + 5y =8

6x - y = 11

Using a graphing tool

Remember that

the solution is the intersection point of both lines

The answer is the option A

Write a situation for this equation

1.5 < 1.67

Answers

The inequality equation is correct the way it is in the form 1.5 < 1.67 and will continue to be correct if 1.5x < 1.67 where x is

negative numberx less than or equal to 1

What are inequalities?

Inequalities as used in mathematics refers to the symbol that is used to related the values in the left hand side and the values at the right hand side of the expression

The symbol used in the inequality expression are

less than or equal togreater than or equal toless thangreater than

The given expression is less than and read as 1.5 is less than 1.67

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geometry extra credit- 25 questions

Answers

Given that the triangles are similar, then their corresponding sides are in proportion, that is,

[tex]\frac{AB}{JK}=\frac{BX}{KY}[/tex]

Substituting with data and solving for BX:

[tex]\begin{gathered} \frac{32}{10}=\frac{BX}{6} \\ 3.2=\frac{BX}{6} \\ \text{3}.2\cdot6=BX \\ 19.2=BX \end{gathered}[/tex]

I’m trying to make a study guide and need step by step explanation on how to solve this question please

Answers

Given:

The dimension of square shape floor is 200 feet by 200 feet.

The area of the square is calculated as,

[tex]\begin{gathered} A=side^2 \\ A=200^2=40000 \end{gathered}[/tex]

Now, given that the 1/2 bottle will cover approximately 2000 quare feet.

It gives,

[tex]\begin{gathered} \frac{1}{2}\text{ bottle=2000 square f}ee\text{t} \\ 1\text{ bottle=4000 square fe}et \end{gathered}[/tex]

So, the number of bottles required are,

[tex]\frac{A}{4000}=\frac{40000}{4000}=10\text{ bottles}[/tex]

Answer: option B)

find the coordinates of the midpoint of the line joining the points and show your work.

Answers

formula of midpoint

[tex](\frac{x1+x2}{2},\frac{y1+y2}{2})[/tex]

the we replace (7,1) and (-1,3)

[tex](\frac{7+(-1)}{2},\frac{1+3}{2})[/tex]

simplify to solve

[tex]\begin{gathered} (\frac{7+1}{2},\frac{4}{2}) \\ \\ (\frac{8}{2},\frac{4}{2}) \\ \\ (4,2) \end{gathered}[/tex]

Midpoint is (4,2)

Graph

help I'm practicing

Answers

We have the next formula to find the volume of a triangular prism-

[tex]V=B\times h[/tex]

where

B= area of the base

h= height

in our case

B=18 square inches

H= 5 inches

[tex]V=18\times5=90in^3[/tex]

the volume of the triangular prism is 90 cubic inches

Kyle has a container of flour in the shape of a cylinder.

Answers

Answer:

Part A:

The volume of a cylinder is given below as

[tex]\begin{gathered} V_{cylinder}=\pi\times r^2\times h \\ r=\frac{d}{2}=\frac{10in}{2}=5in \\ h=8in \end{gathered}[/tex]

By substituting the values , we will have

[tex]\begin{gathered} V_{cyl\imaginaryI nder}=\pi r^2h \\ V_{cyl\mathrm{i}nder}=\pi\times5^2\times8 \\ V_{cyl\mathrm{i}nder}=\pi\times200 \\ V_{cyl\mathrm{i}nder}=628.3in^3 \end{gathered}[/tex]

Hence,

The volume = 628.3in³

Part B:

To determine the weight of the flour in ounces, we will use the relation below

[tex]\begin{gathered} 0.13ounce=1in^3 \\ x=628.3in^3 \\ cross\text{ multiply, we will have} \\ x=0.13\times628.3 \\ x=81.679 \\ x\approx81.7ounces \end{gathered}[/tex]

Hence,

The weight = 81.7 ounces

Evaluate h(x) at x = 6, x = 8, and x= 12. h(x)=1.31^×

Answers

Answer : h(6) = 5.054

h(8) = 8.673

h(12) = 25.542

Given that h(x) = 1.31^x

[tex]\begin{gathered} h(x)=1.31^x \\ \text{ find the value of h(6) when x = 6} \\ h(6)=1.31^6 \\ h(6)\text{ = 5.05}4 \\ \text{when x = 8} \\ h(8)=1.31^8 \\ h(8)\text{ = 8.67}3 \\ \text{when x = 12} \\ h(12)=1.31^{12} \\ h(12)\text{ = 25.54}2 \end{gathered}[/tex]

Therefore,

h(6) = 5.054

h(8) = 8.673

h(12) = 25.542

Express your answer as a polynomial in standard form.f(x) = x^2 + 6x +7g(x) = x + 2Find: g(f(x)

Answers

[tex]y=x^2+6x+9[/tex]

1) Firstly, let's find the composite function g(f(x)) plugging into the x variable in g(x) the function f(x):

[tex]\begin{gathered} g(f(x))=(x^2+6x+7)+2 \\ g(f(x))=x^{2}+6x+9 \end{gathered}[/tex]

2) To write that as the standard form, let's replace g(f(x)) with "y" and write the polynomial orderly to the greatest coefficient to the least one.

[tex]y=x^2+6x+9[/tex]

Find the distance between the two points. Write your answer as a decimal rounded to the hundredths place if needed.

Answers

We need to find the distance between the two points given. Use the distance formula:

[tex]d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Replace using P1(3,-9) and P2(-2,4):

[tex]d=\sqrt[]{((-2)_{}-3_{})^2+(4_{}-(-9)_{})^2}[/tex]

[tex]d=\sqrt[]{(-5)^2+(13)^2}[/tex][tex]d=13.9283[/tex]

Rounded to the hundredths:

[tex]d=13.93[/tex]

Hey I need help on this math problem thank you

Answers

Answer:

From the image below we will bring out two coordinates we are going to use to calculate the rate of change of the graph

The coordinates are given below as

[tex]\begin{gathered} (x_1,y_1)\Rightarrow(2,4) \\ (x_2,y_2)\Rightarrow(-2,0) \end{gathered}[/tex]

Concept:

The rate of change will be calculated using the formula below

[tex]\begin{gathered} \text{rate of change =}\frac{change\text{ in y}}{\text{change in x}} \\ \text{rate of change}=\frac{y_2-y_1}{x_2-x_1} \end{gathered}[/tex]

By substituting the values, we will have

[tex]\begin{gathered} \text{rate of change}=\frac{y_2-y_1}{x_2-x_1} \\ \text{rate of change}=\frac{_{}0-4_{}}{-2_{}-2_{}} \\ \text{rate of change}=\frac{-4}{-4} \\ \text{rate of change}=1 \end{gathered}[/tex]

Hence,

The rate of change = 1

Apply the product rule to rewrite the product below using a single base and exponent then simplify: 3^2 *3^3 our base is Answerour exponent is Answerthis simplifies to Answer

Answers

[tex]undefined[/tex]

Explanation:

[tex]3^2\text{ }\times3^3[/tex][tex]\begin{gathered} \text{The expression has same base.} \\ \text{Base = 3} \\ We\text{ take one base and bring the exponents together} \\ \text{The sign betw}en\text{ them changes from multiplication to addition} \end{gathered}[/tex][tex]\begin{gathered} 3^2\text{ }\times3^3\text{ = }3^{2\text{ + 3}} \\ \text{Exponent = 2 + 3} \\ \text{Exponent = 5} \end{gathered}[/tex][tex]\begin{gathered} \text{Simplifying:} \\ 3^{2+3}=3^5 \\ 3^5\text{ = 243} \end{gathered}[/tex]

Find the measure of angle CDB. Explain your reasoning, including the theorem or postulate you used. (2 pts.) b) Find the measure of angle. (1 pt.)

Answers

The triangle is isosceles, since two of its sides are equal. Besides, the little triangles ABD and CBD are congruent and this can be concluding using the criterion SSS , since they share one side, and the other sides are equal. Then the angles are congruent, and the angles ADB and CDB are congruent and have the same measure. Then

[tex]\begin{gathered} m\angle ADB+m\angle CDB=m\angle ADC \\ 2m\angle CDB=m\angle ADC \\ m\angle CDB=\frac{72}{2} \\ m\angle CDB=32 \end{gathered}[/tex]

Then, the measure of angle CDB is 32 degrees.

2. Find the equation ofthe line:through (-5,1) parallel to2y = 2x - 4

Answers

Given data:

The given point is (a,b)=(-5,1).

The given line is 2y=2x-4.

The given line can be written as,

2y=2(x-2)

y=x-2

The standard equation of the line is,

y=mx+c

comapre the given line with the standard form.

m=1

The slope of two parallel lines are always equal.

m'=m

=1

The expression of the line which is parallel to the given line is,

y-b=m'(x-a)

Substitue the given values in the expression.

y-1=1(x-(-5))

y-1=x+5

y=x+6.

Thus, the equation of the line parallel to the given line is y=x+6.

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