the initial equation is:
[tex]\frac{p}{r}+s=q[/tex]To solve for p we can rest s in bout sides so:
[tex]\begin{gathered} \frac{p}{r}+s-s=q-s \\ \frac{p}{r}=q-s \end{gathered}[/tex]Now we can multiply by r so:
[tex]\begin{gathered} \frac{p\cdot r}{r}=(q-s)\cdot r \\ p=(q-s)\cdot r \end{gathered}[/tex]The marching band director is standing on a platformoverlooking the band practice. The pit section is located 8feet from the base of the platform. If the angle ofdepression from the band director to the pit section is 67°find the height of the platform.
Through trigonometry, we calculated that the height of the platform is 18.8 feet.
The director of the marching band is observing the band practice from a platform. 8 feet separate the base of the platform from the pit area. If the pit section's angle of depression is 67 degrees from the band director,
The angle formed by the horizontal line and the item as seen from the horizontal line is known as the angle of depression. When the angles and the separation of an object from the ground are known, it is mostly used to calculate the distance between the two objects.
We have,
So, the Angle of Depression = [tex]\alpha[/tex] = 67
Let x be the height of the platform,
Tan [tex]\alpha = \frac{x}{8}[/tex]
[tex]Tan 67 = \frac{x}{8} \\\\2.35 =\frac{x}{8} \\x = 2.35 *8 = 18.8[/tex]
Hence, The height of the platform is 18.8 feet.
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Home Liquidators marks up its merchandise 35% on cost. What is the company’s equivalent markup on selling price?
Home Liquidators marks up its merchandise 35% on cost, the company's equivalent markup on the selling price is 25.9%.
What is an equivalent value?An equivalent value represents equality.
Equivalent values show that two paired mathematical expressions are equal.
How is the markup on the selling price determined?The markup on the selling price can be derived by equating the markup on cost with the markup on the selling price as follows:
Markup on cost = 35%
Cost = 100%
Selling price = 135%
Markup on selling price = 25.9% (0.35/1.35 x 100)
Thus, we can describe Home Liquidators' markup on the selling price as equivalent to 25.9% or simply 26%.
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Trying to solve this problem kind of having a hard time
Future Value of an Investment
The formula to calculate the future value (FV) of an investment P for t years at a rate r is:
[tex]FV=P\mleft(1+\frac{r}{m}\mright)^{m\cdot t}[/tex]Where m is the number of compounding periods per year.
Leyla needs FV = $7000 for a future project. She can invest P = $5000 now at an annual rate of r = 10.5% = 0.105 compunded monthly. This means m = 12.
It's required to find the time required for her to have enough money for her project.
Substituting:
[tex]\begin{gathered} 7000=5000(1+\frac{0.105}{12})^{12t} \\ \text{Calculating:} \\ 7000=5000(1.00875)^{12t} \end{gathered}[/tex]Dividing by 5000:
[tex]\frac{7000}{5000}=(1.00875)^{12t}=1.4[/tex]Taking natural logarithms:
[tex]\begin{gathered} \ln (1.00875)^{12t}=\ln 1.4 \\ \text{Operating:} \\ 12t\ln (1.00875)^{}=\ln 1.4 \\ \text{Solving for t:} \\ t=\frac{\ln 1.4}{12\ln (1.00875)^{}} \\ t=3.22 \end{gathered}[/tex]It will take 3.22 years for Leila to have $7000
whats the simplest term of 9m-2(3m-1)
Answer:
[tex]3m+2[/tex]
Step-by-step explanation:
I'm assuming you mean: [tex]9m-2(3m-1)[/tex] and not: [tex](9m-2)(3m-1)[/tex]
So you simply need to know the Distributive Property, which allows you to expand out values being multiplied within parenthesis without adding the values first as such: [tex]A(B+C)=AB+AC[/tex]
Applying this to distribute the -2, we get: [tex]9m-6m+2[/tex]
Adding like terms we get: [tex]3m+2[/tex]
two ships leave a port at the same time. the first ship sails on a bearing of 55° at 12 knots (natural miles per hour) and the second on a bearing of 145° at 22 knots. how far apart are they after 1.5 hours (round to the nearest nautical mile)
Given that one of the ships travels at 12 nautical miles per hour, then after 1.5 hours, it will travel 12*1.5 = 18 miles
The other ship will travel 22*1.5 = 33 miles
The angle of 145° is measured with respect to the positive x-axis. Then, respect the negative x-axis, its measure is 180° - 145° = 35°
We have to use trigonometric functions to find x1, y1, x2, and y2, as follows:
sin(55°) = y1/18
sin(55°) *18 = y1
14.7 = y1
cos(55°) = x1/18
cos(55°)*18 = x1
10.3 = x1
sin(35°) = y2/33
sin(35°)*33 = y2
18.9 = y2
cos(35°) = x2/33
cos(35°)*33 = x
-27 = x2 (the minus sign comes from the graph)
The distance between two points (x1, y1) and (x2, y2) is computed as follows:
[tex]d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]Substituting with the values found,
[tex]\begin{gathered} d=\sqrt[]{(-27-10.3)^2+(18.9-14.7)^2} \\ d=\sqrt[]{(-37.3)^2+4.2^2} \\ d=\sqrt[]{1391.29+17.64} \\ d\approx38\text{ miles} \end{gathered}[/tex]Geometry ? What is the coordinate of G if triangle E’F’G’ is created by dilating EFG with a scale factor of 4 about the origin
In order to dilate the figure around the origin by a scale of 4, we need to multiply the coordinates of each point by 4. This is done below:
[tex]\begin{gathered} F^{\prime}=(4\cdot-1,4\cdot2)=(-4,8) \\ G^{\prime}=(4\cdot2,4\cdot-2)=(8,-8) \\ E^{\prime}^{}=(4\cdot-2,,4\cdot0)=(-8,0) \end{gathered}[/tex]The coordinates are: F'(-4, 8), G'(8,-8) and E'(-8,0).
Using the Smith's BBQ Report, all of your hourly personnel are getting a promotion this week. As a result, your hourly wages for next week will be 8% more than the current week. What will be the approximate Total Payroll Variance from the current week to next week if all other factors remain the same?A 156B 9265C 842D 686
Given:
The current week hour wage is 8579
Total payroll =14081.
The hourly wage will be increased 8 %.
The 8% of 8579 is
[tex]=\frac{8}{100}\times8579=686.32[/tex]The hourly wage will be increased by 686 next week.
The total payroll also will be increased by 686.
So the total Payroll Variance from the current week to next week is 686.
Hence option D is correct.
What does the y-intercept mean? What does the x-intercept mean? Explain what each intercept means and then Identify the x-intercept and y-intercept from each equation.A. y=7/2x -2B. x=-3
x intercept = where the function crosses the x axis (x,0)
y intercept = where the function crosses the y-axis (0,y)
A. y=7/2x-2
x intercept , replace y by 0 and solve for x:
0 =7/2x-2
2= 7/2 x
2 / (7/2) = x
x= 4/7
y-intercept, replace x by 0 and solve for y
y= 7/2x-2
y= 7/2 (0) -2
y=-2
B.
x-intercept:
x=-3
y-intercept
0=-3
It doesn't have a y-intercept.
Which transformations can be used to carry ABCD onto itself? The point ofrotation is (3,2). Check all that apply.у5DС321АВ012345
The point of rotation is (3, 2). We would subtract this origin from each vertex. Let us consider vertex D(1, 3). Subtracting, we have (1 - 3, 3 - 2) = (- 2, 1).
if we rotate it 180 degrees, we have (- - 2, - 1) = (2, - 1). If we add the vertex again, it becomes (- 2 + 3, 1 + 2) = (1, 3). If we reflect it over the line, y = 2, we have (3, 2)
The correct options are
B. Rotate 180 degrees
D) reflection over the line, y = 2
Approximate the measure in degrees of angle in a right triangle given that the side adjacent to angle is 5 and the hypotenuse of the triangle is 9 units. (Round your answer to one decimal place.)
Measure of perpendicular side for the given right triangle with adjacent side 5units and hypotenuse 9 unit is equal to 7.5 units(Upto one decimal place).
As given in the question,
In a right triangle,
Measure of a adjacent side = 5units
Measure of a hypotenuse = 9units
Let x be the measure of the perpendicular side
Using Pythagoras theorem we get,
(Hypotenuse)² = (Adjacent side)² +(perpendicular side)²
⇒ (9)² = (5)² + (x)²
⇒ (x)² = (9)² - (5)²
⇒x² = 81 -25
⇒ x = √56
⇒ x= 7.4833..
⇒x = 7.5 units(round upto one decimal)
Therefore, measure of perpendicular side for the given right triangle with adjacent side 5units and hypotenuse 9 unit is equal to 7.5 units(Upto one decimal place).
The complete question is :
Approximate the measure in degrees of angle in a right triangle given that the side adjacent to angle is 5 and the hypotenuse of the triangle is 9 units. Find the measure of perpendicular side.(Round your answer to one decimal place.)
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Wouldnt 8-4 be 8? because if u think about it your taking away the 4 so its not there anymore so then 8 is left ?
The subtraction of 4 from 8 is equal to 4 and not 8
What is subtraction of numbers?
In math, subtracting means to take away from a group or a number of things. When we subtract, the number of things in the group reduces or becomes less. The minuend, subtrahend, and difference are parts of a subtraction problem.
Now in this question, let's assume you have 8 apples in your bag. During lunchtime, you gave 4 out to your friends to share with you. If you check your bag again, you would notice that you no longer have 8 apples again in your bag because you have given 4 out and you would be left with 4 apples.
So, whenever we subtract 4 from 8 i.e. 8 - 4, the answer is and must always be equal to 4 and not 8.
Mathematically, this is written as 8 - 4 = 4.
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Two buses leave a station at the same time and travel in opposite directions. One bus travels 16(km)/(h) slower than the other. If the two buses are 1040 kilometers apart after 4 hours, what is the rate of each busSolve using a system of linear equations
Let x be the velocity (rate of change ) of one of the buses. We know that the other one travels 16 km/h slower; this means that the second velocity is:
[tex]x-16[/tex]Now the combined velocity would be:
[tex]2x-16[/tex]We know that the distance is equal to time by velocity, then we have that:
[tex]4(2x-16)=1040[/tex]Solving for x we have:
[tex]\begin{gathered} 4(2x-16)=1040 \\ 2x-16=\frac{1040}{4} \\ 2x-16=260 \\ 2x=260+16 \\ 2x=276 \\ x=\frac{276}{2} \\ x=138 \end{gathered}[/tex]Therefore the rate of the faster bus is 138 km/h and the rate for the slower bus is 122 km/h.
what is the equation of the line with x-intercept (6,0) and y-intercept (0, 2)
Answer:
3y=6-x
Explanation:
The slope-intercept form of a line is y=mx+b.
First, we determine the slope(m) of the line.
[tex]\begin{gathered} m=\frac{2-0}{0-6} \\ =-\frac{2}{6} \\ m=-\frac{1}{3} \end{gathered}[/tex]Since the y-intercept, b=2
The equation of the line is:
[tex]\begin{gathered} y=-\frac{1}{3}x+2 \\ y=\frac{-x+6}{3} \\ 3y=6-x \end{gathered}[/tex]gabriella bought two hoodies that were $15 each. The store was having a sale, everything in the store 15% off. If the sales tax on the purchase was 8%, what was the final cost of the hoodie?
Given:
The cost of each hoodie is, C = $15.
The discount percentage is, d = 15%.
The tax percentage on purchase is t = 8%.
The objective is to find the final cost of the hoodie.
The selling price of one hooie can be calculated as,
[tex]\begin{gathered} SP=c-d \\ =15-(\frac{15}{100}\times15) \\ =15-2.25 \\ =12.75 \end{gathered}[/tex]Now, by adding sales tax to the selling price the final cost will be,
[tex]\begin{gathered} FC=SP+t \\ =12.75+(\frac{8}{100}\times12.75) \\ =12.75+1.02 \\ =13.77 \end{gathered}[/tex]Cost of two hoodie can be calculated as,
[tex]\begin{gathered} C(\text{two)}=2\times13.77 \\ =27.54 \end{gathered}[/tex]Hence, the final cost of one hoodie is $13.77 and final cost of two hoodie is $27.54.
The height of the Empire State Building is 1250 feet tall. Your friend, who is 75 inches tall, is standing nearby and casts a shadow that is 33 inches long. What is the length of the shadow of the Empire State Building? Please help me draw triangles
The length of the building's shadow = 550.66 ft
Explanations:The height of the Empie State Building = 1250 feet
The friend's height = 75 inches
The length of the friend's shadow = 33 inches
[tex]\frac{Actual\text{ height of the friend}}{\text{Length of the friend's shadow}}=\text{ }\frac{Height\text{ of the building}}{\text{Length of the building's shadow}}[/tex][tex]\begin{gathered} \frac{75}{33}=\text{ }\frac{1250}{\text{Length of the building's shadow}} \\ 2.27\text{ = }\frac{1250}{\text{Length of the building's shadow}} \\ \text{Length of the building's shadow = }\frac{1250}{2.27} \\ \text{Length of the building's shadow = }550.66\text{ f}et \end{gathered}[/tex]Evaluate the expression for r = –31, s = 4, and t = –16.
Answer:
st - r = -33
Explanation:
We need to replace r by -31, s by 4 and t by -16, so the expression is equal to
st - r = 4(-16) - (-31)
st - r = - 64 + 31
st - r = -33
So, the answer is
st - r = -33
Mr. Ocana drove 15 miles to go to work last week. Due to construction on the road, this week he drove 21 miles to go to work. What is the percent increase in the number of miles he drove to work this week? О 40% 50% ООО 60% O 70%
ANSWER:
40%
STEP-BY-STEP EXPLANATION:
In this case, what we must do is calculate the percentage that represents 21 miles, assuming that 100% is 15 miles, like this
[tex]21\cdot\frac{100}{15}=140\text{\%}[/tex]Now we subtract 100% from this value, like this:
[tex]140\text{\%}-100\text{\%}=40\text{\%}[/tex]Simplify the following expression 6 + (7² - 1) + 12 ÷ 3
You have to simplify the following expression
[tex]6+(7^2-1)+12\div3[/tex]To solve this calculation you have to keep in mind the order of operations, which is:
1st: Parentheses
2nd: Exponents
3rd: Division/Multiplication
4th: Addition/Subtraction
1) The first step is to solve the calculation within the parentheses
[tex](7^2-1)[/tex]To solve it you have to follows the order of operations first, which means you have to solve the exponent first and then the subtraction:
[tex]7^2-1=49-1=48[/tex]So the whole expression with the parentheses calculated is:
[tex]6+48+12\div3[/tex]2) The second step is to solve the division:
[tex]12\div3=4[/tex]Now the expression is
[tex]6+48+4[/tex]3) Third step is to add the three values:
[tex]6+48+4=58[/tex]If the trend shown in the graph above continued into the next year, approximately how many sport utility vehicles were sold in 1999?
ANSWER :
EXPLANATION :
A family is traveling from their home to avacation resort hotel. The table below showstheir distance from home as a function of time.Time (hrs)0257Distance(mi)0140375480Determine the average rate of change betweenhour 2 and 7, including the units.
Let
x -------> the time in hours
y -------> the distance in miles
we know that
To find the average rate of change, we divide the change in the output (y) value by the change in the input value (x)
so
For x=2 h ------> y=140 mi
For x=7 h ------> y=480 mi
rate of change=(480-140)/(7-2)
rate of change=340/5=68 mi/h
The average rate of change is equal to the speed in this problem
[tex] \frac{x - 2}{x + 3} + \frac{10x}{x {}^{2 } - 9}[/tex]simplify the sum. state any restrictions on the variables.
We have
[tex]\frac{x-2}{x+3}+\frac{10x}{x{}^2-9}[/tex]first, we need to factorize the next term
[tex]x^2-9=(x+3)(x-3)[/tex]so we have
[tex]\frac{x-2}{x+3}+\frac{10x}{(x+3)(x-3)}[/tex]Remember in order to sum a fraction the denominator must be the same
[tex]\frac{(x-2)(x-3)+10x}{(x+3)(x-3)}[/tex]then we solve the multiplications (x-2)(x-3)
[tex]\frac{x^2-3x-2x+6+10x}{(x+3)(x-3)}=\frac{x^2+5x+6}{(x+3)(x-3)}[/tex]then we can factorize the numerator
[tex]x^2+5x+6=(x+3)(x+2)[/tex]so the simplification will be
[tex]\frac{x^2+5x+6}{(x+3)(x-3)}=\frac{(x+3)(x+2)}{(x+3)(x-3)}=\frac{(x+2)}{(x-3)}[/tex]the final result is
[tex]\frac{(x+2)}{(x-3)}[/tex]1.) You are buying flower bundles and have
$24 to spend. Rose bundles cost $4. Tulip bundles
cost $6. Write an equation to describe how many
types of each kind of bundle you can buy.
Answer:
[tex]4r+6t \leq 24[/tex]
Step-by-step explanation:
The cost of money spent on a rose bundle can be represented by 4r, where 4 is the cost of one rose bundle and r is the number of rose bundles purchased.
The cost of money spent on a tulip bundle can be represented by 6t, where 6 is the cost of one tulip bundle and t is the number of rose bundles purchased.
The amount spent on rose bundles added to the amount spent on tulip bundles must be equal to or less than $24, since that's all you have to spend. This can be represented using this equation:
[tex]4r + 6t \leq 24[/tex]
:)
I believe the answer to be c but I'm not the best at word problems this is a practice study guide.
In order to find the interval of values where 95% of the shoe sizes lie, let's find the values of z-score that represents 2.5% to the left and 2.5% to the right of the standard distribution curve:
Looking at the z-table for the probabilities of 0.025 and 0.975, we have z1 = -1.96 and z2 = 1.96.
Now, we can calculate the values that define the interval using the formula below:
[tex]\begin{gathered} z=\frac{x-\mu}{\sigma} \\ -1.96=\frac{x-8.1}{1.47} \\ x-8.1=-2.88 \\ x=-2.88+8.1 \\ x=5.22 \\ \\ 1.96=\frac{x-8.1}{1.47} \\ x-8.1=2.88 \\ x=2.88+8.1 \\ x=10.98 \end{gathered}[/tex]Therefore the correct option is the second one. (It's the only option with very close values to the ones calculated)
For a standard normal distribution,Find P(-1.21 < Z< 2.26)
Answer:
The range of z-score is given below as
[tex]P(-1.21Using a graphing calculator, we will have the image be[tex]\begin{gathered} P(z<-1.21)=0.11314 \\ P(z<2.26)=0.9881 \\ P(-1.21Hence,The final answer is
[tex]P(-1.21\lt z\lt2.26)=0.8750[/tex]The given pair of triangles are similar. Find X and Y.
Given that the pair of triangles are similar, then their corresponding sides are in proportion, this means that:
[tex]\frac{\text{longer leg of the triangle on the left}}{\text{shorter leg of the triangle on the left}}=\frac{\text{longer leg of the triangle on the right}}{\text{shorter leg of the triangle on the right}}[/tex]Substituting with the information of the diagram:
[tex]\frac{27}{x}=\frac{x}{9}[/tex]Cross multiplying:
[tex]\begin{gathered} 27\cdot9=x\cdot x \\ 243=x^2 \\ \sqrt[]{243}=x \\ 15.58\approx x \end{gathered}[/tex]Considering the triangle on the left, and applying the Pythagorean theorem with c = y (the hypotenuse), a = 27, and b = x (the legs), we get:
[tex]\begin{gathered} c^2=a^2+b^2 \\ y^2=27^2+x^2 \\ y^2=729+243 \\ y^2=972 \\ y=\sqrt[]{972} \\ y\approx31.18 \end{gathered}[/tex]
Question 3
If your rectangular yard is 8 feet wide and requires 160 pieces of sod that are cut into 1 foot squares. how
long is it?
The length of the rectangle yard is 2 feet.
What is a rectangle?A rectangle in Euclidean plane geometry is a quadrilateral with four right angles. It can also be explained in terms of an equiangular quadrilateral—a term that refers to a quadrilateral whose angles are all equal—or a parallelogram with a right angle. A square is an irregular shape with four equal sides.So, the length f the rectangular yard:
Width is 8 feet.Requires 160 pieces of sod.Then 160ft² is the area of the rectangular yard.
Now, calculate the length as follows:
A = l × w160 = l × 80l = 160/80l = 2 feetTherefore, the length of the rectangle yard is 2 feet.
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Write the rate as fraction in simplest form 22 gallons of pest rifles for 8 acres of crops
Since the given rate is 22 gallons of pest for 8 acres of crops, then
We need to find how many acres per gallon
Then we will divide 22 acres by 8 gallons to find the rate
[tex]rate=\frac{22}{8}[/tex]Divide up and down by 2 to simplify
[tex]\begin{gathered} rate=\frac{\frac{22}{2}}{\frac{8}{2}} \\ \\ rate=\frac{11}{4} \end{gathered}[/tex]The answer is:
The rate is 11/4 gallon per acre (2 3/4)
You deposit $5000 in an account earning 6% interest compounded continuously. How much will you have in the account in 5 years?
For us to determine how much the account will be in 5 years at compounded continuously, we will be using the following formula:
[tex]\text{ A = P}_0e^{rt}[/tex]Where,
P = Principal amount (Initial Value)
A = Final amount (Future Value)
r = interest rate (in decimal)
t = time (in years)
e = mathematical constant approximately 2.7183
Given:
P = $5,000
r = 6% = 6/100 = 0.06
t = 5 years
We get,
[tex]\text{ A = P}_0e^{rt}[/tex][tex]\text{ A = (5,000)(2.7183)}^{(0.06)(5)}[/tex][tex]\text{ A = (5,000)(2.7183)}^{0.3}[/tex][tex]\text{ A = (5,000)(}1.34986151469)[/tex][tex]\text{ A = }6,749.30757343\text{ }\approx\text{ \$6,749.30}[/tex]Therefore, in 5 years, at 6% compounded continuously, your account will be $6,749.30
how to find two consecutive whole numbers that square root 40 lies between
First, we need to identify the square root of the fisrt squared numbers:
[tex]\begin{gathered} \sqrt{1}=\text{ 1} \\ \sqrt{4}=2 \\ \sqrt{9}=3 \\ \sqrt{16}=4 \\ \sqrt{25}=5 \\ \sqrt{36}=6 \\ \sqrt{49}=7 \\ \sqrt{64}=8 \end{gathered}[/tex]Since 40 is a number between 36 and 49, we can say that the square root of 40 is between 6 and 7. So:
[tex]6<\sqrt{40\text{ }}<7[/tex]4 Use the sequence below to complete each task. -6, 1, 8, 15, ... a. Identify the common difference (a). b. Write an equation to represent the sequence. C. Find the 12th term (a) our Wilson (All Things Algebral. 2011 Enter your answer(s) here
we have
-6, 1, 8, 15, ...
so
a1=-6
a2=1
a3=8
a4=15
a2-a1=1-(-6)=7
a3-a2=8-1=7
a4-a3=15-8=7
so
the common difference is
d=7
Part 2
write an equation
we have that
The equation of a general aritmetic sequence is equal to
an=a1+(n-1)d
we have
d=7
a1=-6
substitute
an=-6+(n-1)7
an=-6+7n-7
an=7n-13
Part 3
Find 12th term
we have
n=12
a12=-7(12)-13
a12=71
