Sophia codes 1/5 of her game in 1/4 of an hour

At this rate how much of her game can she code in 1 hour?

1. Show your thinking step-by-step on how you saw this problem

2. Don’t forget to add the final answer

Giveing Brainly and worth 50 points!!!


(Please actually answer or don’t comment)

Answer:

circumference=2πr

2×3.14×5

10×3.14

=31.4cm

Answer: Area=78.54

circumference=31.42

Step-by-step explanation:

For function 1

p=r+7

On comparing to y=mx+b

For function 2

y intercept is 8

Function 2 has greater intercept

[tex]\textit{internal division of a line segment using ratios} \\\\\\ A(-7,2)\qquad B(1,-6)\qquad \qquad \stackrel{\textit{ratio from A to B}}{5:3} \\\\\\ \cfrac{A\underline{P}}{\underline{P} B} = \cfrac{5}{3}\implies \cfrac{A}{B} = \cfrac{5}{3}\implies 3A=5B\implies 3(-7,2)=5(1,-6)[/tex]

[tex](\stackrel{x}{-21}~~,~~ \stackrel{y}{6})=(\stackrel{x}{5}~~,~~ \stackrel{y}{-30})\implies P=\underset{\textit{sum of the ratios}}{\left( \cfrac{\stackrel{\textit{sum of x's}}{-21+5}}{5+3}~~,~~\cfrac{\stackrel{\textit{sum of y's}}{6-30}}{5+3} \right)} \\\\\\ P=\left( \cfrac{-16}{8}~~,~~\cfrac{-24}{8} \right)\implies P=(-2~~,~~-3)[/tex]

Answer  B. $168.75

Step-by-step explanation:

I took the test and I got it correct and I will tell you guys the other answers if you have these same questions.

1) Scott invests $1000 at a bank that offers 6% compounded annually. Write an equation to model the growth of the investment.

Answer: D) A = 1000(1.06)t

2) Find the maturity value of a loan of $2500 at simple interest that is to be repaid in 8 months. The interest rate is 4.3%.

Answer: B) $2571.67

3) Owen has a loan for $3700 at a rate of 5% annually. If the interest is not compounded, what is the total amount of repayment if the loan is for 7 years?

Answer: D) $4995.00

4) Davis puts $5,000 each year in an account that earns 5% annual interest, compounded annually. His brother Mike puts $5,000 each year in a safe in his bedroom. After the first 10 years of doing this, how much more money does Davis have than Mike? Round your answer to the nearest dollar.

Answer: A) $20,524

5) Ally is buying a speed boat for $10,000 with a down payment of $2,500. The bank approved a simple interest flat rate loan for 5 years at 7% APR. How much are the monthly loan payments? (round to the nearest cent)

Answer: B) $168.75

The monthly loan payments should be [tex]\$168.75[/tex].

Option B is correct.

Given that, Ally is buying a speed boat for $10,000 with a down payment of $2,500.

Remaining amount Ally have to pay,

                                      [tex]=10000-2500=7500[/tex]

Rate of interest [tex]r=7\%[/tex] , time [tex]t=5[/tex] years and Principal [tex]P=7500[/tex]

          Simple interest,  [tex]S.I=\frac{P*r*t}{100}[/tex]

                          [tex]S.I=\frac{7500*7*5}{100} \\\\S.I=2625[/tex]

In 5 years, Ally have to pay,

                                 [tex]=7500+2625=10125[/tex]

In one month, Ally have to pay [tex]=\frac{10125}{60}=\$168.75[/tex]

Learn more about the simple interest here:

https://brainly.com/question/2294792

It looks like the integral might be

[tex]\displaystyle \int (9 - x^2)^{3/2} \, dx[/tex]

or perhaps

[tex]\displaystyle \int \frac1{(9 - x^2)^{3/2}} \, dx[/tex]

Take note of the fact that both integrands are defined only over the interval -3 < x < 3.

For either integral, we substitute x = 3 sin(θ) and dx = 3 cos(θ) dθ.

Note that we want this substitution to be reversible, so we must restrict -π/2 ≤ θ ≤ π/2, an interval over which sine has an inverse. Then θ = arcsin(x/3).

The first case then reduces to

[tex]\displaystyle \int (9 - (3\sin(\theta))^2)^{3/2} (3 \cos(\theta) \, d\theta) = 3 \times 9^{3/2} \int (1 - \sin^2(\theta))^{3/2} \cos(\theta) \, d\theta \\\\ = 81 \int (\cos^2(\theta))^{3/2} \cos(\theta) \, d\theta \\\\ = 81 \int |\cos^3(\theta)| \cos(\theta) \, d\theta[/tex]

By definition of absolute value,

[tex]\displaystyle 81 \int |\cos^3(\theta)| \cos(\theta) \, d\theta = \begin{cases}\displaystyle 81 \int \cos^4(\theta) \, d\theta & \text{if }\cos(\theta) \ge 0 \\ \displaystyle -81 \int \cos^4(\theta) \, d\theta & \text{if }\cos(\theta) < 0\end{cases}[/tex]

and these cases correspond to 0 ≤ θ < π/2 and π/2 < θ ≤ π, respectively. But we are assuming -π/2 ≤ θ ≤ π/2, so the negative case doesn't matter to us.

You can compute the remaining antiderivative by exploiting the half-angle identity for cosine,

[tex]\cos^2(\theta) = \dfrac{1 + \cos(2\theta)}2[/tex]

Then

[tex]\cos^4(\theta) = \left(\cos^2(\theta)\right)^2 = \dfrac{1 + 2\cos(2\theta) + \cos^2(2\theta)}4 = \dfrac{3 + 4\cos(2\theta) + \cos(4\theta)}8[/tex]

and so

[tex]\displaystyle \int \cos^4(\theta) \, d\theta = \dfrac{12\theta + 8\sin(2\theta) + \sin(4\theta)}{32} + C[/tex]

We can simplify this using the double angle identity for (co)sine,

sin(2θ) = 2 sin(θ) cos(θ)

cos(2θ) = 1 - 2 sin²(θ)

as well as the relations,

sin(arcsin(x/3)) = x/3

cos(arcsin(x/3)) = √(9 - x²)/3

which gives us

[tex]\displaystyle \int \cos^4(\theta) \, d\theta = \dfrac{12\theta + 16 \sin(\theta) \cos(\theta) + 4 \sin(\theta) \cos(\theta) (1 - 2\sin^2(\theta))}{32} + C[/tex]

Putting this in terms of x, we get

[tex]\displaystyle \int (9 - x^2)^{3/2} \, dx \\ = 81 \times \dfrac{12\arcsin\left(\frac x3\right) + 16 \times \frac x3 \times \frac{\sqrt{9-x^2}}3 + 4\times\frac x3\times\frac{\sqrt{9-x^2}}3 \left(1 - 2\left(\frac x3\right)^2\right)}{32} + C[/tex]

[tex]\displaystyle \int (9 - x^2)^{3/2} \, dx = 81 \times \dfrac{12\arcsin\left(\frac x3\right) + \frac{16x\sqrt{9-x^2}}9 + \frac{4x(9-2x^2)\sqrt{9-x^2}}{81}}{32} + C[/tex]

[tex]\boxed{\displaystyle \int (9 - x^2)^{3/2} \, dx = \dfrac{12\arcsin\left(\frac x3\right) + (180x-8x^3)\sqrt{9-x^2}}{32} + C}[/tex]

If you were asking about the other integral, the first few steps are similar and you end up with the far more trivial integral and antiderivative

[tex]\displaystyle \frac19 \int \frac{d\theta}{\cos^2(\theta)} = \frac19 \int \sec^2(\theta) \, d\theta = \frac19 \tan(\theta) + C[/tex]

Putting it back in terms of x, we get

[tex]\displaystyle \int \frac1{(9 - x^2)^{3/2}} \, dx = \frac19 \tan\left(\arcsin\left(\frac x3\right)\right) + C[/tex]

Recall that tan(θ) = sin(θ)/cos(θ), so

[tex]\displaystyle \int \frac1{(9 - x^2)^{3/2}} \, dx = \frac19 \times \frac{\frac x3}{\frac{\sqrt{9-x^2}}3} + C[/tex]

[tex]\boxed{\displaystyle \int \frac1{(9 - x^2)^{3/2}} \, dx = \frac{x}{9\sqrt{9-x^2}} + C}[/tex]

Answer:

The cost of one ticket will be £8.20

Answer:

Andy basically has two stickers

Answer:

AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA

Step-by-step explanation:

Answer:

C+3

Step-by-step explanation:

[tex]\qquad \qquad\huge \underline{\boxed{\sf Answer}}[/tex]

For the first figure ~

The diagonals of a kite intersect each other at 90°

So, we can apply Pythagoras theorem here :

[tex]\qquad \sf  \dashrightarrow \: CD² = OC² + OD²[/tex]

[tex]\qquad \sf  \dashrightarrow \: CD² = {7}^{2} + {9}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \: CD² = 49 + 81[/tex]

[tex]\qquad \sf  \dashrightarrow \: CD² = 130[/tex]

[tex]\qquad \sf  \dashrightarrow \: CD=x = \sqrt{ 130}[/tex]

For the second figure ;

we have same concept of kite, and use of Pythagoras theorem !

Also, the diagonal QS bisects diagonal PR

Hence,

[tex]\qquad \sf  \dashrightarrow \: PR = 2 \times OR [/tex]

[tex]\qquad \sf  \dashrightarrow \: 10 = 2 \times OR [/tex]

[tex]\qquad \sf  \dashrightarrow \: OR = 10 \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \: OR = 5 \: mm[/tex]

now, apply pythagoras theorem ~

[tex]\qquad \sf  \dashrightarrow \: QR² = OR² + OQ²[/tex]

[tex]\qquad \sf  \dashrightarrow \: QR² = {5}^{2} + {6}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \: QR² = 25 + 36[/tex]

[tex]\qquad \sf  \dashrightarrow \: QR² = 61[/tex]

[tex]\qquad \sf  \dashrightarrow \: QR=x = \sqrt{61} \: mm[/tex]

here, 2 OR = 2 OP = PR

so, similarly OP = 5 mm

Applying pythagoras theorem again ;

[tex]\qquad \sf  \dashrightarrow \: SP² = OS² + OP²[/tex]

[tex]\qquad \sf  \dashrightarrow \: SP² = {10}^{2} + {5}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \: SP² = {100}^{} + 25[/tex]

[tex]\qquad \sf  \dashrightarrow \: SP² = 125[/tex]

[tex]\qquad \sf  \dashrightarrow \: SP = \sqrt{125}[/tex]

[tex]\qquad \sf  \dashrightarrow \: SP = y = 5\sqrt{5} \: mm[/tex]

Answer: 2/4 simplified to 1/2

Step-by-step explanation:

Answer:

-1/2

Step-by-step explanation:

A(-3, 4)

B(1, 2)

slope = (y2 - y1)/(x2 - x1)

slope = (4 - 2)/(-3 - 1)

slope = 2/(-4)

slope = -1/2

Answer:

x=35

Step-by-step explanation:

180-147=33 (angles in a straight line)

33+3x+42=180 (angles in a triangle)

3x+42=147

147-42=105

105/3=35

Answer:

0.78

Step-by-step explanation:

To know which one is the greatest, convert all of them into decimals.

3/4 is the same as 0.75

50% is the same as 0.50

0.78 doesn't needs to be changed

We now have 0.75, 0.50 and 0.78.

Out of all these numbers, 0.78 is the greatest number.

Hope this helps.

Answer:

2

Step-by-step explanation:

Degree of the polynomial is the highest power of the term.

As degree of the polynomial is 3, m value should be 2

Answer: its b.) 2

Step-by-step explanation:

I got it right om test

SOLUTION:

=) 49/64 is the answer I think

Answer:

one has (_) and another has (+)

Answer:

from the figure find the length unknown side

Answer:

B

Step-by-step explanation:

The equation a/b x b/a = 1 is a product equation

It is true that a/b x b/a = 1

The product expression is given as:

a/b x b/a = 1

Rewrite the product expression properly as follows:

[tex]\frac ab * \frac ba = 1[/tex]

Multiply the numerator of the fractions

[tex]\frac {ab}b * \frac 1a = 1[/tex]

Multiply the denominator of the fractions

[tex]\frac {ab}{ab} = 1[/tex]

Evaluate the quotient

[tex]1= 1[/tex]

Hence, it is true that a/b x b/a = 1

Read more about mathematical proofs at:

https://brainly.com/question/1788884

Answer:

V =2860 in ^3

Step-by-step explanation:

The volume of a rectangular prism is given by

V = l*w*h  where l is the length, w is the width and h is the height.

V = 20 * 11 * 13

V =2860 in ^3

[tex]\qquad \qquad\huge \underline{\boxed{\sf Answer}}[/tex]

In the given question, the two angles are complementary Angle pair, so the sum of their values will add up to 90°

that is ~

[tex]\qquad \sf  \dashrightarrow \: (3x + 30) \degree + x \degree = 90 \degree[/tex]

[tex]\qquad \sf  \dashrightarrow \: 3x + x + 30 \degree = 90 \degree[/tex]

[tex]\qquad \sf  \dashrightarrow \: 4x = 90 \degree - 30 \degree[/tex]

[tex]\qquad \sf  \dashrightarrow \: 4x = 60 \degree[/tex]

[tex]\qquad \sf  \dashrightarrow \: x = 60 \div 4[/tex]

[tex]\qquad \sf  \dashrightarrow \: x = 15 \degree[/tex]

Answer:

x = 15 (third option)

Step-by-step explanation:

Complementary angles sum up to 90°.

∠1 + ∠2 = 90°

x° + (3x + 30)° = 90°

x + 3x + 30 = 90

4x = 90 - 30

4x = 60

x = 60/4

x = 15

Hope it helps ⚜

We need x and y

JKLM is a rectangle not triangle

Opposite sides of rectangle are equal

Now

[tex]\\ \rm\Rrightarrow 4y+5=2y+35[/tex]

[tex]\\ \rm\Rrightarrow -2y=-30[/tex]

[tex]\\ \rm\Rrightarrow y=-30/-2[/tex]

[tex]\\ \rm\Rrightarrow y=15[/tex]

And

[tex]\\ \rm\Rrightarrow x+31=5x-9[/tex]

[tex]\\ \rm\Rrightarrow -4x=-40[/tex]

[tex]\\ \rm\Rrightarrow x=10[/tex]

Answer:

b

Step-by-step explanation:

Answer:

10.5

Step-by-step explanation:

8.4^2 = 70.56

6.3^2 = 39.69

110.25 = c^2

c = 10.5

Answer:

4.5 L

Step-by-step explanation:

4500/1000 =4.5

Have an amazing day!

Please mark brainliest!

Answer:

  (c)  $63.75

Step-by-step explanation:

The discounted price will be 100% -25% = 75% of the marked price. Mike's final price will be ...

  ($80 +5)×0.75 = $63.75