Answer:
Water at high temperatures
Explanation:
When heated, molecules move faster which results in the sound waves being transmitted faster.
Also sound waves travel fastest in solids. Fast in liquids, and slowest in the air.
Answer:
Sound waves will move faster in water at high temperature.
Explanation:
Sound waves are longitudinal waves.These waves travel in bilk medium.The speed of sound increases with the increase in temperature.Speed of sound increases by 4.57 meter for every 1.5 degree Fahrenheit rise in temperature.What is longitudinal wave?The waves in which particles of the medium vibrate in the direction of propagation, is called longitudinal wave.
Hence sound waves will move faster in the water at high temperature.
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What is the magnetic field strength at a point 2.5 mm radially from the center of the wire leading to the capacitor
Complete Question
A 8.0 A current is charging a 1.0 -cm-diameter parallel-plate capacitor. What is the magnetic field strength at a point 2.5 mm radially from the center of the wire leading to the capacitor?
Answer:
The magnetic field is [tex]B = 6.4*10^{-4} \ T[/tex]
Explanation:
From the question we are told that
The current is [tex]I = 8.0 \ A[/tex]
The diameter is [tex]d = \ cm = \frac{1}{100} = 0.01 m[/tex]
The position considered is [tex]d = 2.5 \ mm = 0.0025 \ m[/tex]
Generally the magnetic field is mathematically represented as
[tex]B = \frac{\mu_o * I }{ 2 \pi d}[/tex]
Here [tex]\mu_o[/tex] is permeability of free space with value
[tex]\mu_o = 4\pi * 10^{-7} \ N/A^2[/tex]
So
[tex]B = \frac{ 4\pi * 10^{-7} * 8 }{ 2 \pi * 0.0025 }[/tex]
=> [tex]B = \frac{ 2 * 10^{-7} * 8 }{ * 0.0025 }[/tex]
=> [tex]B = 6.4*10^{-4} \ T[/tex]
Joffrey talks and moves slowly. When asked a question, he answers slowly in monotone monosyllables, if he answers at all. Joffrey is experiencing psychomotor________
Answer:
R.E.T.A.R.D.A.T.I.O.N
Explanation:
It won't let me spell it normal
Joffrey talks and moves slowly. When asked a question, he answers slowly in monotone monosyllables, if he answers at all then it means that he is experiencing R.E.T.A.R.D.A.T.I.O.N .
What is acceleration?The rate of change in an object's velocity with respect to time is known as acceleration in mechanics. The vector quantity of accelerations. The direction of the net force that is acting on an object determines its acceleration.
Since acceleration has both a magnitude and a direction, it is a vector quantity. Velocity is a vector quantity as well. The definition of acceleration is the change in velocity vector over a time interval divided by the time interval.
R.E.T.A.R.D.A.T.I.O.N is the process of inhibiting something's growth. However, negative acceleration has a very different meaning in physics. The negative acceleration is just the opposite of acceleration. A shift in speed is meant by the phrase "acceleration." In general, acceleration signifies an increase in velocity; while, acceleration in the opposite denotes a reduction in velocity.
To know more about Acceleration:
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what are the conditions under which the resultant of three coplanar forces is zero?
What is the orbital velocity in km/s and period in hours of a ring particle at the outer edge of Saturn's A ring
Answer:
The orbital velocity [tex]v = 16.4 \ km/s[/tex]
The period is [tex]T = 14.8 \ hours[/tex]
Explanation:
Generally centripetal force acting ring particle is equal to the gravitational force between the ring particle and the planet , this is mathematically represented as
[tex]\frac{GM_s * m }{r^2 } = m w^2 r[/tex]
=> [tex]w = \sqrt{ \frac{GM}{r^3} }[/tex]
Here G is the gravitational constant with value [tex]G = 6.67*10^{-11}[/tex]
[tex]M_s[/tex] is the mass of with value [tex]M_s =5.683*10^{26} \ kg[/tex]
r is the is distance from the center of the to the outer edge of the A ring
i.e r = R + D
Here R is the radius of the planet with value [tex]R = 60300 \ km[/tex]
D is the distance from the equator to the outer edge of the A ring with value [tex]D = 80000 \ kg[/tex]
So
[tex]r =80000 + 60300[/tex]
=> [tex]r =140300 \ km = 1.4*10^{8} \ m[/tex]
So
=> [tex]w = \sqrt{ \frac{ 6.67*10^{-11}* 5.683*10^{26}}{[1.4*10^{8}]^3} }[/tex]
=> [tex]w = 1.175*10^{-4} \ rad/s[/tex]
Generally the orbital velocity is mathematically represented as
[tex]v = w * r[/tex]
=> [tex]v = 1.175*10^{-4} * 1.4*10^{8}[/tex]
=> [tex]v = 1.64*10^{4} \ m /s = 16.4 \ km/s[/tex]
Generally the period is mathematically represented as
[tex]T = \frac{2 \pi }{w }[/tex]
=> [tex]T = \frac{2 * 3.142 }{ 1.175 *10^{-4} }[/tex]
=> [tex]T = 53473 \ second = 14.8 \ hours[/tex]
Answer:
The orbital velocity [tex]v = 16.4 \ km/s[/tex]
The period is [tex]T = 14.8 \ hours[/tex]
Explanation:
Generally centripetal force acting ring particle is equal to the gravitational force between the ring particle and the , this is mathematically represented as
[tex]\frac{GM_s * m }{r^2 } = m w^2 r[/tex]
Phil is riding a scooter and pushes off the ground with his foot. this causes him to accelerate at 12 m /s. Phil weighs 600 N. how strong was his push off the ground?
Answer:
734.16 kg m/[tex]s^{2}[/tex]
Explanation:
The problem is asking for the Force of pushing off the ground.
The formula of Force is: F = mass x accelerationGiven = Mass: 600 newtons (N)
Acceleration: 12 m/[tex]s^{2}[/tex]
We have to convert the mass into kg first. Remember that 1 kg is equal to 9.80665 newtons.
Let x be the mass in newtons.
Let's convert: [tex]\frac{1 kg}{9.80665 N}[/tex] x [tex]\frac{x}{600 N}[/tex] = [tex]\frac{600}{9.80665}[/tex] = 61.18 kg
Phil's weight is 61.18 kg
Let's go back to finding the force.
F = m x a
F = 61.18 kg x 12 m/[tex]s^{2}[/tex]
F = 734.16 kg m/[tex]s^{2}[/tex]
3. Your friend says your body is made up of more than 99.9999% empty space. What do you think?
Answer:
I would agree with the statement. it's not just the body, but everything that we see is almost 99.9999% empty space
Resistors examples.
Three resistors are connected in series at a common voltage of 300V: R1 = 100ohm, R2 = 200ohm, R3 = 300ohm.
a) calculate the current I in the circuit
b) calculate the ratio of the individual voltages on the resistors, ie: UR1: UR2: UR3
c) verify that: UR1: UR2: UR3 = R1: R2: R3
I will be very happy if someone writes it to me here with an explanation of how they did it.
thank you in advance.
Answer:
Multiply the resistances. Example: Two resistors in parallel, 100 and 200 ohms. 100 x 200 = 20,000
Add the resistances. Example: 100 + 200 = 300
Divide the result in Step 1 by the result in Step 2. This gives you the total resistance. Example: 20,000 / 300 = 66.7 ohms.
Explanation:
Multiply the resistances. Example: Two resistors in parallel, 100 and 200 ohms. 100 x 200 = 20,000
Add the resistances. Example: 100 + 200 = 300
Divide the result in Step 1 by the result in Step 2. This gives you the total resistance. Example: 20,000 / 300 = 66.7 ohms.
The weight of a person can be represented by a vector that acts...
Towards the end of a 400m race, Faisal and Edward are leading and are both running at 6m/s. While Faisal is 72m from the finish line Edward is 100m from the finish line. Realising this and to beat Faisal, Edward decides to accelerate uniformly at 0.2 m/s2 until the end of the race while Faisal keeps on the same constant speed. Does Edward succeed in beating Faisal
Answer:
NO
Explanation:
To determine this, we have to firstly determine the time it took Faisal to complete the race with 72 meters left and then the speed Edward used for the final 100 meters (with both distance occurring at the same point in time).
To determine the time it took Faisal from that onward, we use the formula
Speed = distance/time
Since Faisal maintained his speed at the end of the race, the speed will be 6 m/s while distance at the end to be covered his 72 m. Thus
6 = 72/time
time = 72/6
time = 12 seconds; It will take Faisal 12 seconds to complete the race from that point.
For Edward, he accelerated uniformly (for 0.2 m/s²) after running at a constant speed of 6 m/s. Thus, the time it would have taken him to complete (at a speed of 6 m/s) the final 100 m would be
speed = distance/time
6 = 100/time
time = 100/6
time = 16.67 s.
However, he accelerated uniformly at 0.2m/s², hence to get the speed, the formula; speed = acceleration × time will be used
speed = 0.2 × 16.67
speed = 3.334 m/s
To determine the time it took Edward from 100 meters away,
speed = distance/time
3.334 = 100/time
time = 100/3.334
time = 29.94 seconds
It would have taken Edward 29.94 seconds to complete the race, hence he would not have succeeded in defeating Faisal
16. Explain the following observations:
i. Water wets glass surface but does not wet the waxed glass surface.
Answer:
because the cohesive forces within the drops are stronger than the adhesive forces between the drops and the wax. Water wets glass and spreads out on it because the adhesive forces between the liquid and the glass are stronger than the cohesive forces within the water.
Answer:
the adhesive forces between the drops are stronger than cohesive force between the liquid
Which of the remaining designs has the highest thermal efficiency? Which of the remaining designs has the highest thermal efficiency?
Answer:
DEVICE E
Explanation:
when a car is heated , say by taking it to a desert, it expands. Is the increase in length of the car greater than, less than, or equal to its increase in height?
Answer:
ΔL = [tex]\frac{L_{o} }{h_{o} }[/tex] Δh
since the length of the carriages is greater than their height, the length expansion is greater than the height expansion
Explanation:
This is an exercise in thermal expansion, which is described by the expression for one dimension
ΔL = α L₀ ΔT
For the analysis of this exercise we will assume that the sides are independent
Let's look for the condition of the length of the car
ΔL / L₀ = α ΔT
The height delay (h) is
Δh / h₀ = α ΔT
we can match the two expressions
ΔL / L₀ = Δh / h₀
ΔL = [tex]\frac{L_{o} }{h_{o} }[/tex] Δh
since the length of the carriages is greater than their height, the length expansion is greater than the height expansion
I would like to know why this is the correct answer
-Three objects are released to the ground while the mass and net force of each is recorded. Air resistance is assumed to be negligible. Which statement is correct about all three objects?
*The ratio of net force to mass is constant across all objects.
Answer:
The correct answer is the ratio of net force to mass is constant across all objects.
A penny rides on top of a piston as it undergoes vertical simple harmonic motion with an amplitude of 4.0cm. If the frequency is low, the penny rides up and down without difficulty. If the frequency is steadily increased, there comes a point at which the penny leaves the surface. Part A At what point in the cycle does the penny first lose contact with the piston
Answer:
in the downward movement of the movement when the constant is lost
Explanation:
When the coin is on the piston it has a relationship given by
a = d²x / dt²
the piston position is
x = A cos wt
a = - A w² cos wt
the maximum acceleration is
a = - A w²
When the piston raises the acceleration of gravity and that of the piston go in the same direction, when the piston descends they relate it is contrary to gravity, therefore when the frequency increases, the point where the acceleration of the piston is greater than gravity arrives and the coin loses contact.
The point where you lose contact is
a = g
g = A w²
In short, in the downward movement of the movement when the constant is lost
Which type of change is freezing water an example of?
Answer:
For example, a physical change does not result in the formation of new substances. Physical changes alter only the size, shape, form or matter state of a material. Water boiling, melting ice, tearing paper, freezing water and crushing a can are all examples of physical changes.
Explanation:
A train is traveling away from you at 120 km/h. It blows its whistle, and you hear a tone of 0.400 kHz. Take the speed of sound to be 340 m/s. What frequency does the whistle actually produce
Answer:
The actual frequency produced by the train whistle is 444 Hz.
Explanation:
Given;
speed of the train, Vs = 120 km/h = 33.33 m/s
observed frequency, Fo = 0.4 kHz = 400 Hz
speed of sound in air, V = 340 m/s
Note: as the train moves away, the observed frequency will be smaller than the source frequency. Thus, the source frequency which is frequency of the train whistle will be greater than 400 Hz.
The source frequency is given by Doppler effect formula;
[tex]F_s = F_o [\frac{V}{V-V_s} ]\\\\F_s = 400[\frac{340}{340-33.33} ]\\\\F_s = 400(1.109)\\\\F_s = 443.6 \ Hz[/tex]
Fs = 444 Hz
Therefore, the actual frequency produced by the train whistle is 444 Hz.
Ganymede is a moon of Jupiter (mass = 1.90 x 1027 kg). It orbits Jupiter in a circle of radius 1.07 x 109 m. What is Ganymede's period in hours)?
Answer:
T = 171.59 hours
Explanation:
Mass of Ganymede, [tex]M=1.9\times 10^{27}\ kg[/tex]
Radius of the orbit, [tex]R=1.07\times 10^9\ m[/tex]
We need to find Ganymede's period. Let time is T. Using Kepler's third law of motion.
[tex]T^2=\dfrac{4\pi^2}{GM}r^3\\\\T^2=\dfrac{4\pi^2}{6.67\times 10^{-11}\times 1.9\times 10^{27}}\times (1.07\times 10^9)^3\\\\T=617754.35\ s[/tex]
or
T = 171.59 hours
Hence, Ganymede's period is 171.59 hours.
A motorcycle moves from rest and accelerates uniformly on a straight road, reaching a speed of 25 ms in 20 s and then moves at a constant speed of 25 ms1 for a distance of 300 m. Determine the total displacement for the entire trip.
Answer:total displacement is 550m.
Explanation:
Two carts with masses 10.0kg and 2.5 kg move in opposite directions on a frictionless horizontal track with speeds of 6.0m/s and 3.0 m/a respectively. The carts stick together after colliding head on. Find the final speed.
Please help!!
Answer:
4.2
Explanation:
What part of the atom is the arrow pointing to?
electron
electron shell
nucleus
proton
Answer:
electron shell
Explanation:
the proton and nucleus are inside the electron shell so the arrow is point on the outer shell which is the electron shell.
A 1,100 kg car comes uniformly to a stop. If the vehicle is accelerating at -1.2 m/s2 , which force is closest to the net force acting on the vehicle?
Answer:
The answer would be 1320 N.
Answer:
the answer would be 1320 , but since it said closet .. its gonne be 1300 N !
Explanation:
The coldest and hottest temperatures ever recorded in Switzerland are −43.2°F (231 K) and 106.7°F (315 K), respectively. What is the speed of sound in air at each temperature?
Answer:
v₂₃₁ = 304.4 m/s
v₃₅₁ = 355.5 m/s
Explanation:
The formula used to find the speed of sound in air, at different temperatures is given as follows:
v = v₀ √(T/273)
where,
v = speed of sound at given temperature
v₀ = speed of sound at 0°C = 331 m/s
T = temperature in K
For T = 231 K:
v₂₃₁ = (331 m/s)√(231 K/273 K)
v₂₃₁ = 304.4 m/s
For T = 315 K:
v₃₅₁ = (331 m/s)√(315 K/273 K)
v₃₅₁ = 355.5 m/s
An industrious beaver manages to chew through the base of a wooden tree trunk 18 m tall, causing it to fall over. If the base of the trunk does not slide while it falls over, how fast is the other end of the trunk moving right before it hits the ground
Answer:
Vf = 18.78 m/s
Explanation:
As, the block does not trunk does not slide while falling. hence, we can use third equation of motion to find its velocity before it hits the ground:
2gh = Vf² - Vi²
where,
g = acceleration due to gravity = 9.8 m/s²
h = Height of Trunk = 18 m
Vf = Velocity of trunk just before it hits the ground = ?
Vi = Initial Velocity of the trunk = 0 m/s
Therefore, using these values in the equation, we get:
(2)(9.8 m/s²)(18 m) = Vf² - (0 m/s)²
Vf = √(352.8 m²/s²)
Vf = 18.78 m/s
A thin cylindrical shell is released from rest and rolls without slipping down an inclined ramp that makes an angle of 30° with the horizontal. How long does it take it to travel the first 3.1 m?A) 1.4 sB) 1.1 sC) 2.1 sD) 1.6 sE) 1.8 s
Answer:
B ( 1.1 s )
Explanation:
Given that a thin cylindrical shell is released from rest and rolls without slipping down an inclined ramp that makes an angle of 30° with the horizontal.
Let the height = h
Sin 30 = h / 3.1
h = 3.1 Sin 30
The P.E at the top = mgh
P.E = 9.8 × 3.1 Sin 30 × m
P.E = 15.19m
The K.E = P.E
K.E = 1/2mv^2
1/2 × V^2 × m = 15.19m
The mass m will cancel out.
V^2 = 30.38
V = 5.51 m/s
Using third equation of motion to find acceleration
V^2 = U^2 + 2as
Since it starts from rest, initial velocity u = 0
30.38 = 2 × 3.1 × a
30.38 = 6.2a
a = 30.38 / 6.2
a = 4.9 m/s^2
Using equation one of linear motion to calculate time t
V = U + at
5.51 = 4.9t
t = 5.51 / 4.9
t = 1.12 s
Therefore, it will take approximately 1.1 s to travel the first 3.1 m
The correct option is B
A teacher bangs his ruler on his desk with a force of 15 N breaking it into pieces. If the ruler has a mass of 0.25 kg, how much force did the desk apply back to the ruler when it broke into pieces?
Answer:
Well, this teacher is pretty dumb if you ask me.
Explanation:
5 N, i think this is right.
A student measures the stiffness of a spring by observing how far it stretches with different masses hanging from it. She tries six different masses: 10, 20, 30, 40, 50, 60 grams; and she finds that the spring stretches: 3.1, 6.5, 10.2, 11.1, 16.2, 18.5 centimeters.
a. Based on these observations, what is the best estimate for the spring constant of this spring?
b. With the 60 gram mass attached, the student observes an oscillatory period of 0.886±0.003 seconds. Explain whether this observation is consistent with your answer from part (a).
Answer:
a) k = 3.2 N / m
b) T = 0.27 s
some problem measuring the time of the oscillation.
Explanation:
a) With the student's observations we can make a graph of elongation against applied weight, see attached, with this graph, Hooke's law must comply
F = -k x
where force is the applied weight
F = W = mg
substituting
W = k x
x = 1 / k W (1)
the linear regression of the graph gives
x = 31.2 w + 0.23
the slope of the graph is
m = 31.2 cm/N
if we relate this value with equation 1
1 / k = 131.2
k = 0.032 N / cm
Let's reduce to the SI system
k = 0.032 N / cm (100cm / 1m)
k = 3.2 N / m
This is the best value we can obtain from the spring constant with these experiential data
b) When the student oscillates the system, he has a simple harmonic motion whose angular velocity is
w =[tex]\sqrt\frac{k}{m} {}[/tex]
for the masses of m = 60 gr = 60 10-3 kg = 0.060 kg
w = √ (3.2 / 0.060)
w = 22.82 rad/s
angular velocity is related to frequency and period
w = 2π f = 2π / T
T = 2π / w
T = 2π / 22.82
T = 0.27 s
A great discrepancy is observed between the theoretical value and the experimental value, it is not common erorr so high it can be due to some problem measuring the time of the oscillation.
True or False: The negative oxygen end of one water molecule is attracted
to the positive hydrogen end of another water molecule to form a
hydrogen bond.
Answer: I believe that it is true
Explanation:
For what angle of incidence at the first mirror will this ray strike the midpoint of the second mirror (which is 28.0 cmcm long) after reflecting from the first mirror
This question is incomplete, the complete question is;
Two plane mirrors intersect at right angles. A laser beam strikes the first of them at a point 11.5 cm from their point of intersection, as shown in the figure.
For what angle of incidence at the first mirror will this ray strike the midpoint of the second mirror (which is 28.0 cmcm long) after reflecting from the first mirror
Answer: angle of incidence is 39.4°
Explanation:
Given that;
two plain mirrors intersect at right angle (90°)
distance d = 11.5 cm
S = 28.0 cm
Now the angle that the reflection ray males with first the mirror equal theta (∅)
so
tan∅ = (S/2) / d
tan∅ = (28/2) / 11.5
tan∅ = 14 / 11.5
tan∅ = 1.2173
∅ = tan⁻¹ (1.2173)
∅ = 50.6°
so angle of incidence = 90° - ∅
= 90° - 50.6°
= 39.4°
Therefore angle of incidence is 39.4°
A motor exerts a 280 N force and does 1220 J
of work while lifting a box. How far did the
motor lift the box?
We know that:
Work = Force × DistanceSolving for Distance:
Distance = Work / ForceDistance = 1220 J / 280 N Distance = 4.36 mHow is it possible for man made things to move?
Explanation:
Natural things are all the elements present in the world. Whatever is there because of nature, like petrolium and coal which is developed over thousands and millions of year process. There are many more, like even living things do come inside the circle of natural things, because man can not make life we can alter it examples can be found on your dining table, fruits and vegetables. Over the period of time humans have altered the genes of fruits and vegetables to grow the way they want example seedless grapes, seedless banana etc.
