Sounds waves are an example of which type of wave? Longitudinal Transverse O Electromagnetic​

Answer:

the answer is B the second one

Complete Question

The complete question is shown on the first uploaded image

Answer:

The mass of the other block is  [tex]m_1 = 81.14 \ kg[/tex]

Explanation:

From the question we are told that

   Mass of the first block is  [tex]m_1 = 100 \ kg[/tex]

   The height is  [tex]s = 1.0 \ m[/tex]

   The time it takes it is  [tex]t = 1.40 \ s[/tex]

 Generally from kinematic equation

       [tex]s = ut + \frac{1}{2} at^2[/tex]

Here u  is the initial velocity which zero given that it was at rest initially

So

     [tex]s = 0 * t + \frac{1}{2} at^2[/tex]

=>  [tex]s = \frac{1}{2} at^2[/tex]

=> [tex]1 = \frac{1}{2}* a * (1.40 )^2[/tex]

=>  [tex]a = 1.0204 \ m/s^2[/tex]

Generally from the diagram the resultant force due to the weight of the first object and the tension on the string is  mathematically represented as

      [tex]mg - T = ma[/tex]

=>   [tex]T = m g - ma[/tex]

=>   [tex]T = m(g - a)[/tex]

=>   [tex]T = 877.96 \ N[/tex]

Generally from the diagram the resultant force due to the weight of the second object and the tension on the string is  mathematically represented as  

     [tex]T - m_1g = m_1 a[/tex]

=>   [tex]877.96 = m_1 (a + g)[/tex]

=>   [tex]877.96 = m_1 (1.0204 + 9.8 )[/tex]

=>   [tex]m_1 = 81.14 \ kg[/tex]

Answer:

newton's first law (sorry its really late i know you prob don't need it anymore

Explanation:

Answer:

Both are subject to a persons interpretation

Explanation:

We hear people describe this when somebody is making an irresistible sound. usually people say the baby has a pitch scream.

Answer:

1) aser 1 has the maximum closest to the center

2)  Δy = 0.0866 m ,   3)   Δy = 0.693 m

Explanation:

The interference phenomenon is described by the expression

         d sin θ = m λ                    for constructive interference

         d sin θ = (m + ½) λ           for destructive interference

We can use trigonometry to find the angle

        tan θ = y / L

in trigonometry experiments the angles are small

        tam θ = [tex]\frac{sin \theta}{cos \theta} = sin \theta[/tex]

        sin θ = y / L

we substitute

         d y / L = m λ       (1)

1) Let's find the first maximum that corresponds to m = 1 for each laser

   laser 1    λ = d / 20

        d y₁ / L = 1 d / 20

        y₁ = L / 20

        y₁ = 5.20 / 20

        y₁ = 0.26 m

Laser 2      λ= d / 15

         d y₂ / L = 1 d / 15

         y₂ = d / 15

         y₂ = 5.20 / 15

         y₂ = 0.346 m

Therefore laser 1 has the maximum closest to the center

2) the difference between these maxima

       Δy = y₂ - y₁

       Δy = 0.3466 - 0.26

       Δy = 0.0866 m

3) we look for the second maximum m = 2 of laser 1, we substitute in equation 1

         y₃ = 2 5.20 / 20

         y₃ = 0.52 m

now let's find the third minimum m = 3 of laser 2

         d y₄ / L = (m + ½) λ

         d y₄ / 5.20 = (3 + ½) d / 15

         y₄ = 3.5 5.20 / 15

         y₄ = 1.213 m

        Δy = y₄ -y₃

        Δy = 1.213 - 0.52

        Δy = 0.693 m

Answer:

half the weight depending on planet gravitational force. weight wouldn't change though if gravitational force is strong

Explanation:

This question is incomplete, the complete question is;

In the Manometer tube in the figure below, the oil in the right-hand arm is olive oil of density 916 kg/m³

If the top of the oil is 25.0 cm above the bottom of the tube, what is the height of the top of the water above the bottom of the tube?

Answer:

the height of the top of the water above the bottom of the tube is  22.9 cm

Explanation:

from the diagram

P_oil = 916 kg/m³

h_oil = 25 cm = 0.25 m

p_water = 1000 kg/m³

Now, in equilibrium;

pressure at  p due to water = pressure at p due to oil

⇒h_water × p_water × g = h_oil × p_oil × g

h_water = h_oil × p_oil × g / p_water × g

h_water = (0.25 × 916) / 1000

h_water = 0.229 m ≈ 22.9 cm

Therefore the height of the top of the water above the bottom of the tube is  22.9 cm

Answer:

one has a k and one has a s

Explanation:

Answer:

the uk refers to the indians and the us refers to the state, (i think srry if its wrong)

Answer:

Controlled braking

Explanation:

CONTROLLED BRAKING occur in a situation where a person or an individual driving a vehicle releases the brake and slowly apply smooth as well as firmly pressure on the brake without the wheels been locked which is why CONTROLLED BRAKING are often used for emergency stops by drivers reason been that it helps to reduce speed when driving as fast as possible while the driver maintain the steering control of the vehicle.

Therefore the form of braking which is used to bring a vehicle to a smooth stop by applying smooth,steady pressure to the brake is called CONTROLLED BRAKING.

Answer: Wet barometer - The tool works by measuring atmospheric pressure to predict incoming weather. Since the glass is only filled halfway with water, the other half is exposed to the atmosphere. When the outdoor atmospheric pressure rises, the pressure in the glass decreases, and causes the water to move down the spout.

Dry barometer - A Torricellian barometer (sometimes called a mercury barometer) is an inverted (upside-down) glass tube standing in a bath of mercury. Air pressure pushes down on the surface of the mercury, making some rise up the tube. The greater the air pressure, the higher the mercury rises.

I hope this helps!

The wet barometer can be used to measure the pressure of incoming weather where as dry barometer was used to measure the air pressure for sealed bellows.

Barometer

The instrument barometer can be used to measure the pressure in the atmosphere or the environment. Thus, this pressure can be also known to be Barometric pressure.

Wet barometer

A water barometer or a wet barometer is a device that are used measure barometric pressure. This device can be used with the force of gravity, combined with pressure in the air, to create a vacuum, to have a value of the pressure that can be described as with the barometric pressure. The procedure of the wet barometer can be, the glass is only filled halfway with water, the other half is exposed to the atmosphere. When the outdoor atmospheric pressure rises, the pressure in the glass decreases, and causes the water to move down the spout.

Dry barometer

A Dry barometer or a Torricellian barometer or a mercury barometer which can be the inverted glass tube standing in a bath of mercury not the water. Air pressure will pushes down on the surface of the mercury, and makes some rise up the tube. If we give more pressure on the barometer, the mercury will gets increased. Only by this way the value of pressure in the dry barometer can be determined.

Learn more about Barometer,

https://brainly.com/question/26741242

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Answer:

Explanation:

D

The net force acting on the car is -1320 N. Option B is the closest force that is acting on the car.

Given that the mass m of the car is 1100 kg and its acceleration a is -1.2 m/s2. The force on the car is calculated by Newton's second law of motion.

Newton's second law states that the force on an object is equal to the products of its mass and acceleration.

[tex]F = ma[/tex]

Substituting the values, we get the force on the car.

[tex]F = 1100 \times -1.2[/tex]

[tex]F = -1320 \;\rm N[/tex]

Hence we can conclude that the net force acting on the car is -1320 N. Option B is the closest force that is acting on the car.

To know more about Newton's second law of motion, follow the link given below.

https://brainly.com/question/8898885.

Answer:

(a) m = 0.141 kg/s

(b) t = 47.343 s

(c) t = 143.745 s

Explanation:

Given that:

The volume of air in the tank V = 1.5 m³

The initial temperature in the tank is supposed to be 20° C and not 208 C;

So  [tex]T_o = 20^0 C = ( 20 +273) K = 293K[/tex]

The initial pressure in the tank [tex]P_o= 800 \ kPa[/tex]

The throat area [tex]A_t[/tex] = 0.75 cm²

To find the initial mass flow in kg/s.

Lets first recall that:

Provided that [tex]\dfrac{P_{amb}}{P_{tank}}< 0.528[/tex], then the flow is choked.

Then;

[tex]\dfrac{P_{amb}}{P_{tank}}= \dfrac{101.35}{800}[/tex]

[tex]\dfrac{P_{amb}}{P_{tank}}= 0.1266[/tex]

From what we see above, it is obvious that the ratio is lesser than 0.528, therefore, the flow is choked.

Now, for a choked nozzle, the initial mass flow rate is determined by using the formula:

[tex]m = \rho \times A \times V[/tex]

where;

[tex]\rho = \rho_o \bigg ( \dfrac{2}{k+1} \bigg) ^{\dfrac{1}{k-1}}[/tex]

[tex]\rho =\dfrac{P_o}{RT_o} \bigg ( \dfrac{2}{k+1} \bigg) ^{\dfrac{1}{k-1}}[/tex]

[tex]\rho =\dfrac{800 \times 10^3}{287 \times 293} \bigg ( \dfrac{2}{1.4+1} \bigg) ^{\dfrac{1}{1.4-1}}[/tex]

[tex]\rho =9.51350( 0.8333 ) ^{2.5}[/tex]

[tex]\rho =6.03 \ kg/m^3[/tex]

[tex]T = T_o \bigg ( \dfrac{2}{k+1}\bigg)[/tex]

where;

[tex]T_o = 293 \ K[/tex]

[tex]T = 293 \bigg ( \dfrac{2}{1.4+1}\bigg)[/tex]

[tex]T = 293 \bigg ( \dfrac{2}{2.4}\bigg)[/tex]

[tex]T = 293 ( 0.8333)[/tex]

T = 244.16 K

During a critical condition when Mach No. is equal to one;

[tex]V = a = \sqrt{kRT}[/tex]

[tex]V = \sqrt{1.4 \times 287 \times 244.16}[/tex]

[tex]V = \sqrt{98103.488}[/tex]

V = 313.214  m/s

Thus, the initial mass flow rate [tex]m = \rho \times A \times V[/tex]

m = 6.03 × 0.75 × 10⁻⁴ × 313.214

m = 0.141 kg/s

(b)

The mass balance formula for the control volume surrounding the tank can be expressed as:

[tex]\dfrac{d}{dt}(\rho_o V) = \dfrac{d}{dt} \bigg ( \dfrac{P_o}{RT_o} V\bigg)[/tex]

[tex]= \dfrac{V}{RT_o}\dfrac{dP_o}{dt}= -m[/tex]

When the air mass flow rate is:

[tex]m = 0.6847 \dfrac{P_oA}{\sqrt{RT_o}}[/tex]

Thus; replacing [tex]m = 0.6847 \dfrac{P_oA}{\sqrt{RT_o}}[/tex] in the previous equation; we have:

[tex]\dfrac{V}{RT_o}\dfrac{dP_o}{dt}= - 0.6847 \dfrac{P_oA}{\sqrt{RT_o}}[/tex]

[tex]\dfrac{dP_o}{P_o}= -0.6847 \dfrac{A\sqrt{RT_o}}{V} \ dt[/tex]

Taking the differential of both sides  from 0 → t

[tex]In(P_o)^t_o = -0.6847 \dfrac{A\sqrt{RT}}{V} \times t[/tex]

[tex]In \bigg ( \dfrac{P(t)}{P(0)} \bigg) = -0.6847 \dfrac{A\sqrt{RT_o}}{V}\times t[/tex]

[tex]\dfrac{P(t)}{P(0)} =exp \bigg ( -0.6847 \dfrac{A\sqrt{RT_o}}{V}\times t \bigg )[/tex]

So, when the pressure P = 500 kPa, the time required is:

[tex]\dfrac{500}{800} =exp \bigg ( -0.6847 \dfrac{0.75 \times 10^{-4}\sqrt{287 \times 293}}{1.5}\times t \bigg )[/tex]

t = 47.343 s

(c)

Let us recall that:

The choking on the nozzle occurred when [tex]\dfrac{P_{amb}}{P_{tank}} = 0.528[/tex]

[tex]\dfrac{P_{amb}}{0.528} = P_{tank}[/tex]

[tex]\dfrac{101.35}{0.528} = P_{tank}[/tex]

[tex]P_{tank}= 191.95 \ kPa \\ \\ P_{tank} \simeq 192 \ kPa[/tex]

From [tex]\dfrac{P(t)}{P(0)} =exp \bigg ( -0.6847 \dfrac{A\sqrt{RT_o}}{V}\times t \bigg )[/tex]; the time required for [tex]P_{tank} \simeq 192 \ kPa[/tex] is:

[tex]\dfrac{192}{800} =exp \bigg ( -0.6847 \dfrac{0.75 \times 10^{-4}\sqrt{287 \times 293}}{1.5}\times t \bigg )[/tex]

By solving:

t = 143.745 s

Answer: A red supergiant

Explanation:

Red supergiants are the stars that have a supergiant luminosity which has a class of either K or M spectral type. In terms of volume, they are regarded as the largest stars on Earth even though they are not the most luminous.

Red supergiants are formed when a star collapses after the hydrogen fuel that the star has in its core runs out and

then fusion begins when the outer shells of hydrogen gets hot.

Answer:

i need a girlfreind

Explanation:

Answer:

20x120=2400m equivalent to 2km

15x120 =1800 m = 1.8km

2km +1.8 km = 3.8 km

Answer:

Explanation:

Sure!

Cars do it all the time. Do you mean without some sort of guidance system, or some sort of computerized brain? That's getting a little tougher. It's possible I think, if you let some sort of timer turn it on.

Answer: chemical energy

Explanation:

Answer:

A

Explanation:

Answer:

C

Explanation:

The radius of its orbit = 8.27 x 10¹³ m

Given

mass Jupiter=1.9 x 10²⁷ kg

T = 16.9 days=1.46 x 10⁶ s

Required

the radius =r

Solution

To hold the moon in its orbit, the gravitational force between two objects (jupiter and moon) will be equal to the centripetal force

[tex]\tt G\dfrac{M.m}{r^2}=m.\dfrac{v^2}{r}\rightarrow v=\dfrac{2.\pi.r}{T}\\\\M=\dfrac{r^3.4\pi^2}{T^2.G}\rightarrow r^3=\dfrac{GMT^2}{4\pi^2}[/tex]

G = 6.67 x 10⁻¹¹ N/m²kg²

Input the value :

[tex]\tt r^3=\dfrac{6.67\times 10^{-11}\times 1.9\times 10^{27}\times (1.46\times 10^6)^2}{4\pi^2}\\\\r^3=6.85\times 10^{27}\rightarrow r=8.27\times 10^{13}[/tex]

Answer:

electric field formed we see that the field is uniform only for a sheet of uniform charge, so the correct answer is b

Explanation:

Let's analyze the shape of the electro field in each given configuration

i) a charge line.

   Using Gauss's law the field varies inversely with the distance

          E = 2K λ / r

ii) an infinite leaf. the electric field is

         E = σ / 2ε₀

iii) two spherical shells

in this case the charge can be considered centered in the center of each shell and the electric field is

         E = k q / r²

for each shel linterior

The outer shell does not create an electric field in the space between them

When examining each electric field formed we see that the field is uniform only for a sheet of uniform charge, so the correct answer is b

Answer:

A and E.

Explanation:

Physical properties have to do with things that are not done chemically.

A has to do with light that you can see.

B has to do with Ph (If not A this is your next answer)

C mentions a Patina which is a chemical reaction known as oxidation

D has to do with chemical reactions

E is always correct.  One of the fundamental laws about matter is that it must always have mass.

I am 99% confident in A and E as your answer, but if it is wrong go with B and E.

Hope this helps!

Answer:

the principal energy level is d because electrons are 2 times more

Answer:

The moon is like a mirror. It reflects light produced by the Sun

Explanation:

Answer:

B. The moon is like a mirror. It reflects light produced by the Sun.

Explanation:

Answer:

The submerge iron has a greater buoyant force on it

Explanation:

Buoyant force is regarded as the force which is exerted on an object when the object is partly or wholly immersed in a fluid. It can be regarded as that force that is responsible for floating of an object. Buoyant force is one as a result of the differences in pressure that is acting on opposite sides of an object when immersed in a static fluid.

According to Archimedes' principle which states that when a body is fully or partially immersed in fluid, the upward buoyant force that is exerted on that body is proportional to the weight of the fluid that is been displaced by the object

FB= -ρgv

Where FB= buoyant force

ρ= density of fluid

V= volume of fluid

g= acceleration due to gravity

NOTE: from this principle, the magnitude of the buoyant force is proportional to weight of the displaced fluid

✓Volume of both wood and iron=31.0 cm^3

✓the piece of the iron is submerged totally

✓the piece of wood is partially submerged

ANSWER:

The buoyant force that is exerted on the body depends on both the volume of the fluid displaced and the density, but we know that both piece of iron and the wood posses the same volume of 31.0 cm^3 and we also know that the piece of iron displaces more water compare to the wood , simply because the iron is totally submerged, Hence the piece of iron has a greater buoyant force on it.

Answer:

[tex]m = 180 \ bright \ fringes[/tex]

Explanation:

From the question we are told that

    The  wavelength is  [tex]\lambda = 510 \ nm = 510 *10^{-9} \ m[/tex]

    The length of the of the plate is  [tex]l = 24.3 \ cm = 0.243 \ m[/tex]

    The radius of the wire  is [tex]r= 0.023 \ mm = 2.3 *10^{-5} \ m[/tex]

Generally the diameter of the wire which is the distance between the glass  plates is mathematically represented as

             [tex]d = 2 * r[/tex]

=>          [tex]d = 2 * 2.3 *10^{-5}[/tex]

=>          [tex]d = 4.6 *10^{-5} \ m[/tex]

 Generally the condition for constructive interference is mathematically represented as

           [tex]2 *d = m \lambda[/tex]

=>        [tex]m = \frac{2d}{\lambda}[/tex]

=>        [tex]m = \frac{2 * (4.6* 10^{-5})}{ 510 *10^{-9} }[/tex]

=>        [tex]m = 180 \ bright \ fringes[/tex]

Answer:Which type of wave vibrates parallel to the direction the energy travels, like a slinky ... ex: Rainbow is composed of different frequencies of visible light ... ex: sledding down a hill - potential energy TRANSFORMS into kinetic energy ... C mechanical. D heat. B Chemical energy is energy stored in the bonds of a chemical ...

Explanation:

Answer:

Explanation:

Let acceleration of fall be a .

v² = u² + 2as

v = 3.8 m /s

u = 0

s = 3.5 m

3.8² = 0 + 2 x a x 3.5

a = 2.06 m /s²

Since this acceleration is less than g , an upward force is acting on the firefighter in the form of friction . Let this force be F . Let mass of the firefighter be m .

m = 765 / 9.8

= 78.06 kg

mg - F = ma

765 - F = 78.06 x 2.06

765 - F = 160.8

F = 604.2 N .

Answer:

[tex]Specific\ Gravity = 2[/tex]

Explanation:

The volume can't be 2g but 2mL

So, the given parameters are:

[tex]Mass = 4g[/tex]

[tex]Volume = 2mL[/tex]

Required

Determine the specific gravity

First, we calculate the gravity of the quartz

[tex]Density= \frac{Mass}{Volume}[/tex]

[tex]Density = \frac{4g}{2mL}[/tex]

[tex]Density = 2g/mL[/tex]

The specific gravity is then calculated using:

[tex]Specific\ Gravity = \frac{Density\ of\ object}{Density\ of\ Water}[/tex]

[tex]Density\ of\ water = 1g/mL[/tex]

So, the expression becomes:

[tex]Specific\ Gravity = \frac{2g/mL}{1g/mL}[/tex]

[tex]Specific\ Gravity = 2[/tex]