We have a cubic function
[tex]f(x)=x^3-3x^2-47x-87[/tex]One way to find all the zeros is by factoring, we can easily find the first zero using the divisors test if we have an independent term, at our case it's -87, one of the divisors may be a zero. The divisors of -87 is 1, 3, 29 and 87.
If we check for all of the divisors we will see that -3 is a zero. (Check with both signals).
If -3 is a zero, the D'Alembert theorem tells us that f(x) is divisible by (x+3), if we do that division we'll have a quadratic function where we can just apply the quadratic formula, then
There's a theorem that says that, if f(a) is a zero, i.e f(a) = 0, and f(x) is a polynomial, then f(x) is divisible by (x-a), in other words, we can divide f(x) by (x-a) and the rest of the division will be 0.
Therefore, let's divide our function by (x+3)
Then we can write our function as
[tex]f(x)=(x+3)(x^2-6x-29)[/tex]Look that now we have a quadratic function, and we can easily find its zeros, applying the quadratic formula
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]We have a = 1, b = -6 and c = -29. Then
[tex]\begin{gathered} x=\frac{6\pm\sqrt[]{36+4\cdot29}}{2} \\ \\ x=\frac{6\pm\sqrt[]{156}}{2} \\ \\ x=\frac{6\pm2\sqrt[]{38}}{2} \\ \\ x=3\pm\sqrt[]{38} \end{gathered}[/tex]Now we have all the zeros of f(x), it's
[tex]\begin{gathered} x=-3 \\ \\ x=3+\sqrt[]{38} \\ \\ x=3-\sqrt[]{38} \end{gathered}[/tex]As we can see there's no complex zero, all the zeros are real numbers.
The max number of complex zeros is 2 because the complex zeros always come in pairs, so if we have 1 complex zero, automatically we have another, for a 3-degree equation, there's a maximum of 2 complex zeros and 1 real zero, or all the of them are real.
Then the correct answer is A)
A rectangle is placed around a semicircle as shown below. The width of the rectangle is . Find the area of the shaded region.Use the value for , and do not round your answer. Be sure to include the correct unit in your answer.
Solution
Step 1
Write the given data:
Radius r of the semi-circle = 4 yd
Width of the rectanhle = 4 yd
Length of the rectangle = 2 x 4 = 8 yd
Step 2
Write the formula for the area of the shaded region:
[tex]\begin{gathered} Area\text{ of the shaded region} \\ =\text{ Area of a rectangle - Area of the semi-circl} \\ =\text{ W }\times\text{ L - }\frac{\pi r^2}{2} \\ =\text{ 4}\times\text{ 8 - }\frac{3.14\times4^2}{2} \\ =\text{ 32 - 25.12} \\ =\text{ 6.88 yd}^2 \end{gathered}[/tex]Final answer
6.88
according to recent study 7 out of every 500 Americans aged 13-17, years are vegetarian.in a group of 350 13 to 17- years old about how many would you expect to he vegetarian
7 out of every 500 Americans aged 13 -17 years are vegetarians
This implies that in a group of 500 Americans , 7 Americans that are within the age range of 13 - 17 years are vegetarians
7 ======== 500
x ======== 350
Introduce cross multiplication
7 x 350 = x * 500
2450 = 500x
Divide both sides by 500
2450/500 = 500x/ 500
x = 4.9
Approximately, 5
5 vegetarians aged 13 - 17 years will be present is in a group of 350 Americans
The answer is 5
What is the explicit rule for the nth term of the geometric sequence? Thanks
Solution.
Given the sequence
[tex]3,18,108,648,3888[/tex]Test which kind of sequence it is
[tex]\begin{gathered} \frac{18}{3}=6 \\ \frac{108}{18}=6 \\ The\text{ sequence has a common ratio which is 6. } \\ Thus,\text{ it is a geometric sequence} \\ \end{gathered}[/tex][tex]\begin{gathered} The\text{ nth term of a geometric sequence can be determined by the formula} \\ a_n=ar^{n-1} \\ where\text{ a = 1st term} \\ r=common\text{ ratio} \end{gathered}[/tex][tex]a_n=3(6^{n-1})[/tex][tex]The\text{ answer is a}_n=3(6^{n-1})[/tex]Solve the direct variation problemsJohn is working at a bank and receives 25 dollars an hour. a. Write an equation that relates x and y.b. what is the constant of proportionality?
Let "x" represent the number of hours that John works and "y" represent John's earnings after working x hours.
b) John receives $25/hour → this value represents the change in John's earnings for every unit increase of x, which is, the constant proportionality (k) of the relationship.
a) If x and y have a direct relationship, you can express it as follows:
[tex]y=25x[/tex]Find the length of the arc. Use 3.14 for it.270°8 cm
The radius of circle is r = 8 cm.
The arc is of angle 270 degree.
The formula for the arc length is,
[tex]l=2\pi r\cdot\frac{\theta}{360}[/tex]Determine the length of the arc.
[tex]\begin{gathered} l=2\cdot3.14\cdot8\cdot\frac{270}{360} \\ =37.68 \end{gathered}[/tex]So lenth of the arc is 37.68.
Mean player age Mean Absolute Team Three golf teams wanted to compare the ages of their players. Each team calculated their players' mean age in years and the mean absolute deviation of their ages. They displayed the results in this table. 9.5 45 Appleton Coalvale 31 15.9 Which statements are true? Summerton 43 16.1 Select each correct answer. Team Coalvale's players ages and Team Summerton's players ages vary about the same amount Team Summerton's players ages and Team Appleton's players ages vary about the same amount Team Appleton's players ages vary less than do Team Summerton's players ages. Team Appleton's players ages vary more than do Team Coalvale's players ages. a ? 7+ O i JOTE to search
Given:
• Appleton: Mean = 45; Mean Absolute deviation = 9.5
,• Coalvale: Mean = 31; Mean Absolute deviation = 15.9
,• Summerton: Mean = 43; Mean Absolute deviation = 16.1
Using the given data, let's select the correct statements.
From the data we can see the difference between the Mean Absolute Deviations of team Coalvale and Summerton is (16.1 - 15.9) = 0.2
This means the ages of team Coalvale and Summerton vary about the same about.
The Mean Absolute deviation of Appleton is far from other mean absolute deviation. This means the players ages for team Appleton vary less than others.
Therefore, the correct statements are:
• Team Coalvale's players ages and Team Summerton's players ages vary about the same amount.
• Team Appleton's players ages vary less than do Team Summerton's players ages.
ANSWER:
• Team Coalvale's players ages and Team Summerton's players ages vary about the same amount.
• Team Appleton's players ages vary less than do Team Summerton's players ages.
What point in the feasible reign maximizes the objective function? constraints: x => 0 y => 0 y<= x - 4 x + y <= 6
Objective Function: C = 2x + y
The point in the feasible region maximizes the objective function is (5, 1)
How to determine the feasible region?The given parameters are
Objective function: C = 2x + y
Subject to (i.e. the constraints)
x >= 0, y >= 0
y <= x - 4, x + y <= 6
Represent y <= x - 4, x + y <= 6 as equations
y = x - 4 and x + y = 6
Substitute y = x - 4 in x + y = 6
So, we have
x + x - 4 = 6
Evaluate the like terms
2x = 10
This gives
x = 5
Substitute x = 5 in y = 6 - x
y = 6 - 5
Evaluate
y = 1
So, we have
(x, y)= (5, 1)
Hence, the coordinates is (5, 1)
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log (2x+ 9) = 1+ log(x- 8)
x = 11.125
STEP - BY - STEP EXPLANATION
What to do?
Solve the given equation.
Given:
log (2x+ 9) = 1+ log(x- 8)
To solve, we will follow the steps below:
Step 1
Re-arrange by subtracting log(x-8) from both-side of the equation.
[tex]log(2x+9)-log(x-8)=1[/tex]Step 2
Apply the law of logarithm that is applicable to the given problem.
[tex]log\frac{(2x+9)}{(x-8)}=1[/tex]Step 3
Replace 1 by log10
Step 4
[tex]log\frac{(2x+9)}{(x-8)}=log10[/tex]Step 5
Cancel-out the log from both-side of the equation.
[tex]\frac{2x+9}{x-8}=10[/tex]Step 6
Cross - multiply
[tex]2x+9=10(x-8)[/tex]Step 7
Open the parenthesis.
[tex]2x+9=10x-80[/tex]Step 8
Collect like term.
[tex]10x-2x=80+9[/tex][tex]8x=89[/tex]Step 9
Divide both-side of the equation by 8
[tex]\frac{8x}{8}=\frac{89}{8}[/tex][tex]x=11.125[/tex]Therefore, the value of x is 11.125
What is the smallest fraction?5/1210/15 1/32/4
Answer:
1/3
Explanation:
In order to get the smallest fraction, we will need to express each of the fractions as a percentage as shown below:
For 5/12;
[tex]\begin{gathered} =\frac{5}{12}\times100 \\ =\frac{500}{12} \\ =41.7\% \end{gathered}[/tex]For 10/15;
[tex]\begin{gathered} =\frac{10}{15}\times100 \\ =\frac{1000}{15} \\ =66.7\% \end{gathered}[/tex]For the fraction 1/3
[tex]\begin{gathered} =\frac{1}{3}\times100 \\ =\frac{100}{3} \\ =33.3\% \end{gathered}[/tex]For the fraction:
[tex]\begin{gathered} =\frac{2}{4}\times100 \\ =\frac{200}{4} \\ =50\% \end{gathered}[/tex]From the resulting percentage, we can see that the smallest among the fraction is 1/3.
ok so the question is Write an expression to rubbers in the area of the figure the figure is a right triangle with 2X -2 and 4X plus 2 in the answer to that is 4X to the power of 2 - 2X -2 and that's part a and amp RP is what would the area be if X equals negative 2
ANSWERS
a) A = 4x² - 2x - 2
b) if x = -2, A = 18 units²
EXPLANATION
The area of a triangle is the length of the base, multiplied by its height and divided by 2:
[tex]A=\frac{b\cdot h}{2}[/tex]In this triangle, b = 4x + 2 and h = 2x - 2. The area is:
[tex]A=\frac{(4x+2)(2x-2)}{2}[/tex]We can simplify this expression. First we have to multiply the binomials in the numerator:
[tex]\begin{gathered} A=\frac{4x\cdot2x-4x\cdot2+2\cdot2x-2\cdot2}{2} \\ A=\frac{8x^2-8x+4x-4}{2} \\ A=\frac{8x^2-4x-4}{2} \end{gathered}[/tex]Now, using the distributive property for the division:
[tex]\begin{gathered} A=\frac{8x^2}{2}-\frac{4x}{2}-\frac{4}{2} \\ A=4x^2-2x-2 \end{gathered}[/tex]For part b, we just have to replace x with -2 in the expression above and solve:
[tex]\begin{gathered} A=4(-2)^2-2(-2)-2 \\ A=4\cdot4+4-2 \\ A=16+2 \\ A=18 \end{gathered}[/tex]POSSIBLE POINTS: 1One-half of a number increased by 16 is 4 less than two-thirds of the number. What is the number?
Let the number be x.
[tex]\begin{gathered} \frac{1}{2}x+16=\frac{2}{3}x-4 \\ \\ \frac{2}{3}x-\frac{1}{2}x=20 \\ \frac{4-3}{6}x=20 \\ \frac{1}{6}x=20 \\ x=120 \end{gathered}[/tex]The number is 120
Jan plans to tell two people each day and will ask that person to tell two other people each day through the day of the opening, and so on. Assume that each new person who hears about the soft opening is also asked to tell two other people each day through the day of the opening and that each one starts the process of telling their friends on the day after he or she first hears. When should Jan begin telling others about the soft opening in order to have at least 700 people know about it by the day it occurs?
Explanation:
From the given question, we can sketch the pattern observed
The figure above helps show how the number of people increases
Initially, Jan tells 2 more people, then the two people tell two more people, then they also tell two more people
Thus
we can see that the model is given by
[tex]\begin{gathered} (2)^n \\ where\text{ n is the number of days} \end{gathered}[/tex]In order to have at least 700 (it also means a minimum of 700), we will have the equation
[tex]2^n\ge700[/tex]We then solve for n
Taking the log of both sides
[tex]n\text{ }log2\ge log700[/tex][tex]n\ge\frac{log700}{log2}[/tex]So that
[tex]\begin{gathered} n\ge\frac{2.845}{0.301} \\ \\ n\ge9.451 \end{gathered}[/tex]So, the number of days will be at least 10 days (Rounded to the nearest whole day )
As cashier, you need to record all over times you worked in hours. If you worked 330 mnts of over time how many hours will you record ?
First, we need the next equivalence
1 hour = 60 min
we have 330 min in order to know the number of hours we need to divide the 330 min between 60
[tex]\frac{330}{60}=5.5[/tex]He will record 5.5 hours
A student takes out 2 loans to pay for college. One loan at 8% interest and the other at 9% interest. The total amount borrowed is $3,500, and the interest after 1 year for both loans is $294. Find the amount of each loan.
The amount of each loan are $2,100 and $1,400.
What is mean by Simple interest?
The simple interest is defined as;
Simple interest = P r t
Where, P is principal amount.
r is rate and t is time period.
Given that;
Student take 2 loans for pay the college.
One loan at 8% interest and the other at 9% interest.
And, The total borrowed amount = $3,500
and, The interest loan = $294
Let The first amount of loan = x
And, The other amount of loan = y
So, We can formulate;
x + y = $3,500 ..... (i)
And, The interest loan = $294
So, We can formulate;
8x/100 + 9y/100 = $294
8x + 9y = 29400 ... (ii)
Solve equation (i) and (ii) , we get;
Multiply by 8 in equation (i) and subtract from (ii), we get;
y = $1400
Hence,
x + y = $3,500
x + 1400 = 3500
x = 3500 - 1400
x = $2,100
Therefore, The amount of each loan are $2,100 and $1,400.
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Find the volume of a cube with a side length of 2.8 in, to the nearest tenth of a cubic inch (if necessary).
Given:
Length of side = 2.8 in
Let's find the volume of the cube.
To find the volume of a cube, apply the formula:
[tex]V=a^3[/tex]Where:
a is the side length = 2.8 in
Hence, to find the volume, we have:
[tex]\begin{gathered} V=2.8^3 \\ \\ V=2.8*2.8*2.8 \\ \\ V=21.952\approx22.0\text{ in}^3 \end{gathered}[/tex]Therefore, the volume of the cube is 22.0 cubic inch.
ANSWER:
22.0 in³
I need help with the entire problem. The question is about a sketchy hotel.
Let d and s be the cost of a double and single- occupancy room, respectively. Since a double-occupancy room cost $20 more than a single room, we can write
[tex]d=s+20\ldots(A)[/tex]On the other hand, we know that 15 double-rooms and 26 single-rooms give $3088, then, we can write
[tex]15d+26s=3088\ldots(B)[/tex]Solving by substitution method.
In order to solve the above system, we can substitute equation (A) into equation (B) and get
[tex]15(s+20)+26s=3088[/tex]By distributing the number 15 into the parentheses, we have
[tex]15s+300+26s=3088[/tex]By collecting similar terms, it yields,
[tex]41s+300=3088[/tex]Now, by substracting 300 to both sides, we obtain
[tex]41s=2788[/tex]then, s is given by
[tex]s=\frac{2788}{41}=68[/tex]In order to find d, we can substitute the above result into equation (A) and get
[tex]\begin{gathered} d=68+20 \\ d=88 \end{gathered}[/tex]Therefore, the answer is:
[tex]\begin{gathered} \text{ double occupancy room costs: \$88} \\ \text{ single occupancy room costs: \$68} \end{gathered}[/tex]Which value of w makes 6W + 7 = 12 true
6W + 7 = 12
to solve this, just isolate W
[tex]\begin{gathered} 6W+7=12 \\ \text{substract 7 in both sides} \\ 6W+7-7=12-7 \\ 6W=5 \\ divide\text{ each side by 6} \\ \frac{6W}{6}=\frac{5}{6} \\ W=\frac{5}{6} \end{gathered}[/tex]so, the answer is w=5/6
Solve x4 + 8x2 + 15 = 0.X = +15 and x = 113x = 5 and x = 13x = 113 and x = 15X = 3/1/3 and x = 1115
Answer
Option D is correct.
x = ±i√(5) OR ±i√(3)
Explanation
The question wants us to solve
x⁴ + 8x² + 15 = 0
To solve this, we first say that
Let x² = y
So that,
x⁴ = (x²)² = y²
So, the equation becomes
y² + 8y + 15 = 0
This is a simple quadratic equation, we then solve this
y² + 8y + 15 = 0
y² + 3y + 5y + 15 = 0
y (y + 3) + 5 (y + 3) = 0
(y + 5) (y + 3) = 0
y + 5 = 0 OR y + 3 = 0
y = -5 OR y = -3
But, Recall that x² = y
If y = -5
x² = y = -5
x² = -5
x = √(-5)
If y = -3
x² = y = -3
x² = -3
x = √(-3)
So,
x = √(-5) OR x = √(-3)
Note that
√(-1) = i
√(-5) = √(-1) × √(5)
= i√5
And
√(-3) = √(-1) × √(3)
= i√3
Hence
x = ±i√(5) OR ±i√(3)
Hope this Helps!!!
i need help please help
Answer:
I think d)
Step-by-step explanation:
if A (0, 2) and B (2, 0) dilation is a transformation, which is used to resize the object, so it can only mean that both are bigger and like the same number, hope that makes sense
f(x)=x^6+10x^4 - 11x^2
You can notice that the given function is symmetric respect to the y-axis.
It means that the value of the function for both x and -x is the same:
[tex]f(-x)=f(x)[/tex]This is the characteristic of a even function.
Hence, the answer is B
3 1/2 ÷ 47/815/88/73/4
the given expression is,
[tex]\begin{gathered} 3\frac{1}{2}\div4=\frac{7}{2}\div4 \\ =\frac{\frac{7}{2}}{4}=\frac{7}{8} \end{gathered}[/tex]so the answer is option A
Identify whether the following real world examples should be modeled by a linear quadratic or exponential function
Solution
- Linear:
The general form of a linear function is
[tex]\begin{gathered} y=ax+b \\ where, \\ a,\text{ and b are constants} \end{gathered}[/tex]- Quadratic:
The general form of a quadratic function is:
[tex]\begin{gathered} y=ax^2+bx+c \\ where, \\ a,b,c\text{ are constants} \end{gathered}[/tex]- Exponential:
The general form of an exponential function is:
[tex]\begin{gathered} y=ab^x \\ where, \\ a,b\text{ are constants} \end{gathered}[/tex]- Now that we know the general forms of these functions, we can proceed to solve the question.
- The amount a person is paid per hour in wages is the amount that the person collects for every hour that he works
- Let us imagine that a person receives $a for every hour worked.
- This means that:
After 1 hour, the person makes $a
After 2 hours, the person makes $a + $a = $2a
After 3 hours, the person makes $a + $a +$a = $3a
- We can therefore generalize as follows:
Thus, after x hours, the person makes:
[tex]x\times a=\$ax[/tex]- Thus, the function representing the amount a person makes per hour of work is given by:
[tex]y=ax[/tex]- Comparing this result with the 3 function definitions above, we can see that this corresponds to a Linear function
Final Answer
The answer is Linear
Petrolyn motor oil is a combination of natural oil and synthetic oil. It contains 5 liters of natural oil for every 4 liters of synthetic oil. In order to make 531 litersof Petrolyn oll, how many liters of synthetic oil are needed?
The ratio 4 : 5 means that in every 9 liters of oil, we will have 4L of synthetic oil and 5L of natural oil.
Divide the 531 by 9 to get how many times we have to amplify the ratio:
[tex]\frac{531}{9}=59[/tex]Multiply the ratio by 59:
[tex]4\colon5\rightarrow(4)(59)\colon(5)(59)\rightarrow236\colon295[/tex]Meaning that for the 531L of oil, 236L would be synthetic and 295L natural.
Answer: 236 Liters.
An advertising company plans to market a product to low-income families. A study states that for a particular area the mean income per family is $25,174 and the standard deviation is $8,700. If the company plans to target the bottom 18% of the families based on income, find the cutoff income. Assume the variable is normally distributed.
pls help i Dont get it
Answer:
what do you need
Step-by-step explanation:
zero and negative exponentswrite in simplest form without zero or negative exponents
We have the following rule for exponents:
[tex]a^0=1[/tex]then, in this case we have:
[tex](-17)^0=1[/tex]I already wrote the answer I just need you to work it out for me please and thank you
Answer:
[tex]A=470\frac{1}{4}ft^2[/tex]Detailed Explanation: The area of the figure provided is the sum of two areas, a rectangle, and a triangle:
The total area is calculated next, and the necessary steps are shown as follows
[tex]\begin{gathered} A=A_1+A_2 \\ A_1=\frac{1}{2}(b\cdot h)=\frac{1}{2}\cdot\lbrack(25ft-22.5ft)\times19.8ft\rbrack \\ A_1=\frac{1}{2}\cdot\lbrack2.5ft\times19.8ft\rbrack=\frac{49.5ft^2}{2}=24.75ft^2 \\ A_1=24.75ft^2 \\ A_2=w\cdot h=22.5ft\cdot19.8ft=445.5ft^2 \\ A_2=445.5ft^2 \\ \therefore\Rightarrow \\ A=A_1+A_2=24.75ft^2+445.5ft^2 \\ A=470.25ft^2 \\ A=470\frac{1}{4}ft^2 \end{gathered}[/tex]What is the axis of symmetry for the following quadratic?(x-3)(x+7)
The symmetry of a quadratic equation is given by the line that passes through its vertex, so in order to find the axis of symmetry we need to find the coordinate of the vertex, which is done below.
[tex]x_{\text{vertex}}=\frac{-b}{2a}[/tex]Where "a" is the number multiplying the square factor and "b" is the number multiplying the factor that isn't squared. To find these two constants we need to expand the equation given.
[tex]\begin{gathered} (x-3)\cdot(x+7) \\ x^2+7x-3x-21 \\ x^2+4x-21 \end{gathered}[/tex]We have that a = 1 and b = 4, therefore:
[tex]x_{\text{vertex}}=\frac{-4}{2\cdot1}=-2[/tex]The axis of symmetry for this quadratic equation is x=-2.
You are clinic manager. You must schedule the equivalent of 1 1/2 nurses for each doctor on a shift, The friday day shift has 6 doctors scheduled How many nurses you will you need to schedule?
Data Given:
Nurses = 1 1/2 of each doctor
This can be interpreted as
[tex]\begin{gathered} 1\frac{1}{2}\text{ = }\frac{3}{2} \\ \\ 1\text{ Doctor requires }\frac{3}{2}\text{ times nurses} \end{gathered}[/tex]If there are 6 doctors in the day shift, then there will be
[tex]\frac{3}{2}\text{ x 6 nurs}es[/tex]=>
[tex]\begin{gathered} \frac{3\text{ x 6}}{2} \\ \\ =\text{ 3 x 3 } \\ \\ =\text{ 9 nurses} \end{gathered}[/tex]This means that I will have to schedule 9 nurses for the day shift on Friday
I will show you a pic
GIven the table above :
We have that
x y
2 8
4 4
6 0
8 4
The table represents a Non - Linear Function
Reason: It is because there is no constant ratio or proportion between x and y.