Suppose a square wave signal has a 65 percent duty cycle and an on-state voltage of 40 volts DC. What is the average DC voltage

Answers

Answer 1

Answer:

The voltage is [tex]\= DC _v = 2.6 \ V[/tex]

Explanation:

From the question we are told that

  The duty cycle is  p =  65% = 0.65

   The on - state voltage is  [tex]V = 40 \ volt[/tex]

   

Generally the average DC voltage is mathematically represented as

        [tex]\= DC _v = p * V[/tex]

=>      [tex]\= DC _v = 40 * 0.65[/tex]

=>      [tex]\= DC _v = 2.6 \ V[/tex]


Related Questions

A heater is rated to dissipate 1440 W when connected to a 120 V source. The current drawn by the device is

Answers

Answer:

The current drawn by the heater is 12 A.

Explanation:

Given;

power dissipated by heater, P = 1440 W

Source voltage, V = 120 V

The electric power of the heater is given by;

P = IV

Where;

I is the current drawn by the heater

Make I the subject of the formular;

I = P / V

Substitute the given values and solve for the current "I";

I = 1440 / 120

I = 12 A

Therefore, the current drawn by the heater is 12 A.

Sandy soil has a relatively low thermal conductivity. Therefore, the surface layer over sandy soil will normally reach a lower temperature during the day than it would over soil that is moist or covered with vegetation.

a. True
b. False

Answers

Answer:

False

Explanation:

Granted, sandy soil has low conductivity, but the surface layer of sandy soil isn't low particularly during the day. Sandy soil reacts more to temperature when compared with other types of soil, and as such, during the day under a hot temperature, the texture of sandy soil is usually hot, and not low like the question suggested. Invariably, the inference the question is making is wrong and not correct, so false

Can someone help me with this question please picture is above

Answers

Answer:

It should be B.

Explanation:

Because expansionary monetary policy works by expanding the money supply faster than usual or lowering short-term interest rates. It is enacted by central banks and comes about through open market operations, reserve requirements, and setting interest rates.

I hope this helped!!!

A mouse is running across a room with a speed of 2.2 m/s. The mass of the mouse is 1.4 kg. What is the Kinetic Energy of the mouse?

Answers

Answer:

3.39 J

Explanation:

The kinetic energy of an object can be found by using the formula

[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]

m is the mass

v is the velocity

From the question we have

[tex]k = \frac{1}{2} \times 1.4 \times {2.2}^{2} \\ = 0.7 \times 4.84 \\ = 3.388 \: \: \: \: \: \: \: \: \: [/tex]

We have the final answer as

3.39 J

Hope this helps you

Answer:

im not sure

Explanation:

Suppose a NASCAR race car rounds one end of the Martinsville Speedway. This end of the track is a turn with a radius of approximately 57.0 m . If the track is completely flat and the race car is traveling at a constant 30.5 m/s (about 68 mph ) around the turn, what is the race car's centripetal (radial) acceleration

Answers

Answer:

[tex]a=16.32\ m/s^2[/tex]

Explanation:

Given that,

The radius of the track, r = 57 m

The speed of a race car, v = 30.5 m/s

We need to find the centripetal acceleration of the car. Its formula that is use to find it is given by :

[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{(30.5)^2}{57}\\\\=16.32\ m/s^2[/tex]

So, the car's centripetal acceleration is [tex]16.32\ m/s^2[/tex].

The crowd at a concert lifts a singer to a height of 2.2 m. The crowd uses a total of force of 600 N. How much work has the crowd done?

Answers

Answer:

1320 J

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 600 × 2.2

We have the final answer as

1320 J

Hope this helps you

A material that reflects or absorbs all the light that strikes it is
A. opaque.
B. transparent.
C. translucent.
D. primary.

Answers

Answer:

b. transparent

Explanation:

Photons interact with an object by some combination of reflection, absorption and transmission. Some materials, such as plate glass and clean water, transmit much of the light that falls on them and reflect little of it; such materials are called optically transparent.

Light is shone on a diffraction grating
with d = 1.00 x 10-6 m. The second
order (m = 2) maximum occurs at an
angle of 74.6º. What is the
wavelength of the light IN
NANOMETERS?
[?] nm
Hint: The answer will be between 400 and 700.

Answers

Answer:

    λ = 482.05 nm

Explanation:

The diffraction phenomenon and the diffraction grating is described by the expression

         d sin θ = m λ

where d is the distance between two consecutive slits, λ the wavelength and m an integer representing the order of diffraction

in this case they indicate the distance between slits, the angle and the order of diffraction

         λ = [tex]\frac{d sin \theta }{m}[/tex]d sin θ / m

let's calculate

         λ = 1.00 10⁻⁶ sin 74.6 / 2

         λ = 4.82048 10⁻⁷ m

Let's reduce to nm

         λ = 4.82048 10⁻⁷ m (10⁹ nm / 1 m)

         λ = 482.05 nm

So basically there is this chart and all you just to name what energy will transform into what energy so like here is just an example like solar to mechanical or something like sorry the arrows are a bit scuffed

Answers

Answer:

free points let's gooo

A 135 kg horizontal platform is a uniform disk of radius 1.95 m and can rotate about the vertical axis through its center. A 63.7 kg person stands on the platform at a distance of 1.05 m from the center, and a 30.1 kg dog sits on the platform near the person 1.33 m from the center. Find the moment of inertia of this system, consisting of the platform and its population, with respect to the axis.

Answers

Answer:

the  moment of inertia is 380.14 kg-m^2

Explanation:

The computation of the moment of inertia is as follows:

The net moment of inertia is

= MR^2 ÷ 2 + m_p d_p^2 + m_d d_d^2

= 135 × 1.95^2 ÷2 + 63.7 ×  1.05^2 + 30.1 × 1.33^2

= 380.14 kg-m^2

hence, the  moment of inertia is 380.14 kg-m^2

We simply applied the above formula so that the correct value could come

And, the same is to be considered

A 1990 kg car moving at 20.0 m/s collides and locks together with a 1540 kg car at rest at a stop sign. Show that momentum is conserved in a reference frame moving at 10.0 m/s in the direction of the moving car.

Answers

Answer:

The momentum before collision and momentum after collision is equal in a frame of reference moving at 10.0 m/s in the direction of the moving car.

Explanation:

[tex]m_1[/tex] = Mass of moving car = 1990 kg

[tex]u_1[/tex] = Velocity of moving car in stationary frame = 20 m/s

[tex]m_2[/tex] = Mass of stationary car = 1540 kg

[tex]u_2[/tex] = Velocity of stationary car in stationary frame = 0 m/s

v = Combined velocity in stationary frame

Momentum conservation for stationary frame

[tex]m_1u_1+m_2u_2=(m_1+m_2)v\\\Rightarrow v=\dfrac{m_1u_1+m_2u_2}{m_1+m_2}\\\Rightarrow v=\dfrac{1990\times 20+0}{1990+1540}\\\Rightarrow v=\dfrac{3980}{353}\ \text{m/s}[/tex]

In frame moving at 10 m/s the velocities change in the following ways

[tex]u_1=20-10\\\Rightarrow u_1=10\ \text{m/s}[/tex]

[tex]u_2=0-10\\\Rightarrow u_1=-10\ \text{m/s}[/tex]

[tex]v=\dfrac{3980}{353}-10\\\Rightarrow v=\dfrac{450}{353}\ \text{m/s}[/tex]

Momentum before collision

[tex]m_1u_1+m_2u_2=1990\times 10+1540\times -10\\\Rightarrow m_1u_1+m_2u_2=4500\ \text{kg m/s}[/tex]

Momentum after collision

[tex](m_1+m_2)v=(1990+1540)\times \dfrac{450}{353}\\\Rightarrow (m_1+m_2)v=4500\ \text{kg m/s}[/tex]

The momentum before collision and momentum after collision is equal. So, the momentum is conserved in a reference frame moving at 10.0 m/s in the direction of the moving car.

A lever, inclined plane, pulley, wedge,
screw, and
and axle are all
types of simple machines.
O driving
O wheel

Answers

A lever, wheel, inclined plane, pulley, wedge, screw, and axle are all types of simple machines.

What is a simple machine?

A simple machine can be described as a mechanical device that changes the direction or magnitude of a force. The simplest mechanisms use mechanical advantage to multiply force. A simple machine such as Lever, Wheel and axle, Pulley, Inclined plane, Wedge, and Screw.

A simple machine utilizes a single exerted force to do work against a single load force. Ignoring friction, the work done is equal to the work done by the force.

Simple machines are termed the elementary "building blocks" of which all more complicated machines are composed. The mechanical advantage of a machine is the product of the mechanical advantages of the simple machines of which it is composed.

Learn more about the simple machines, here:

https://brainly.com/question/10075890

#SPJ1

Atoms are split at power plant to create electricity*
O A. Radiant to Mechanical
O B. Nuclear to Electrical
O C. Chemical to Radiant
D. Mechanical to Electrica;
help please I’m in a test that closes at 6

Answers

Answer:

B. Nuclear to Electrical

Explanation:

Atoms are split at power plants to create electricity. The energy conversion in this process is from nuclear to electrical energy.

When atoms are split, nuclear energy is released. Some part of the mass of the atom is converted to energy. The nuclear energy released is expressed as heat energy. This energy is used to heat water in boilers when produces steam that are used to drive the movement of turbines. This in turn generates electricity.

Today, the universe is considered to be in which shape?

Answers

Answer:

is it a spear

Explanation:

The answer is a sphere

What is the water pressure at the deepest part of the ocean in the Challenger Deep in the Mariana Trench at 10,994 m below the surface.

Answers

Answer:

The pressure is 107417976.4 N[tex]m^{-2}[/tex]

Explanation:

The pressure of water at a given height/ depth can be determined by:

Pressure = σhg

Where: σ is the density of water, h is the height/ depth, and g is the gravitational force.

Given that; h = 10994 m, but σ = 997 kg/[tex]m^{3}[/tex] and g = 9.8 m/[tex]s^{2}[/tex]

Thus, the pressure of water at the deepest part of the ocean will be:

Pressure = 997 x 10994 x 9.8

               = 997 x 107741.2

               = 107417976.4

Pressure  = 107 420 KN[tex]m^{-2}[/tex]

The pressure of water at 10994 m below the surface is 107417976.4 N[tex]m^{-2}[/tex]

Amy finds the voice of her text-to-speech tool annoying. What should she do?

try to change the voice
stop using the tool
turn down the volume
reprogram the tool

Answers

Try and change the voice. If that isn’t correct it should be stop using the tool.

Answer:

A

Explanation:

If mechanical energy is converted to thermal energy, then the spring would not compress as far as it would otherwise. This will cause the spring constant to be lower than it really is.

a. True
b. False

Answers

Answer:

False.

Explanation:

Given that if mechanical energy is converted to thermal energy, then the spring would not compress as far as it would otherwise. This will cause the spring constant to be lower than it really is.

This statement is false. Because if mechanical energy is converted to thermal energy, there will be distortions in the solid pattern of the spring. And this will make the spring to compress.

Also, no matter what may happen to the spring, the spring constant remains constant. That is, unchanged.

A typical road bike wheel has a diameter of 70 cm including the tire. In a time trial, when a cyclist is racing along at 12 m/s how fast is a point at the top of the tire moving?

Answers

Answer:

24 m/s

Explanation:

Given that,

A typical road bike wheel has a diameter of 70 cm including the tire.

Speed of the cyclist = 12 m/s

We need to find the speed at the top of the tire moving. The velocity of the topmost point is twice that of the velocity of the object.

v = 2 × 12

= 24 m/s

Hence, the required velocity is 24 m/s.

The speed at which the point at the top of the tire moves is 24 m/s.

Given that,

A typical road bike wheel has a diameter of 70 cm including the tire.In a time trial, when a cyclist is racing along at 12 m/s.

Based on the above information, the calculation is as follows:

We know that the velocity of the point should be the twice of the object velocity.

So,  

= 2 (12)

= 24 m/s

Therefore we can conclude that the speed at which the point at the top of the tire moves is 24 m/s.

Learn more: brainly.com/question/23334479

An experimental electrical generator collects sunlight with mirrors and generates heat at a rate of 1.2 megawatts. The generator is mounted on the roof of an environmentally friendly building and is used to operate an elevator. The elevator has a maximum operating load of 8000 kg and a maximum velocity of 6 m/s.

A. Determine the power that the generator must supply to operate the elevator at its maximum operating

B. What is the efficiency of this system?

Answers

Answer:

a) 0.47MW

b) 39.24%

Explanation:

In order to find the power needed for the elevator to operate at its maximum capacity, we can make use of the following formula:

P=Fv

where P is the power, F is the force and v is the velocity.

The force the elevator must carry can be calculated with the following formula:

F=mg

where m is the mass of the elevator and g is the acceleration of gravity, so:

[tex]F=(8000 kg)(9.81 m/s^{2})[/tex]

F=78 480 N

so now we can make use of the power formula:

P=Fv

P=(78 480N)(6 m/s)

P=470 880W

P=0.47W

b)

In order to find the efficiency, we will suppose that the generator can generate a maximum of 0.47 W so we use the following formula:

[tex]efficiency = \frac{P_{in}}{P_{out}}*100\%[/tex]

[tex]efficiency=\frac{0.470880}{1.2}*100\%[/tex]

efficiency=39.24%


Calculate the time needed to accelerate a 50 kg object from 2 m/s to 12 m/s if a force of 10 N is
applied.

Answers

Hi there!

[tex]\large\boxed{\text{50 seconds.}}[/tex]

Begin by calculating the acceleration on the object by using the formula

F = m · a (Newton's Second Law) where:

F = Force (N)

m = Mass (kg)

a = acceleration (m/s²)

Plug in the given values:

10  = 50 · a

10 = 50a

10 / 50 = a

a = 1/5 = 0.20 m/s²

Solve for the time using the kinematic equation:

Δv / a = t, or (vf - vi) / a = t

Plug in the acceleration along with the initial and final velocites into the equation:

(12 - 2) / 0.20 = 10 / 0.20 = 50 seconds.

The amplitude of oscillations reduces to one-sixth of its original value in 10 oscillations. Find the logarithmic decrement.

Answers

Answer:

Explanation:To describe a damped harmonic oscillator, add a velocity dependent term, bx, where b is the vicious damping coefficient.


A student claimed that thermometers are useless because a thermometer always registers its own
temperature. How would you respond?

Answers

Answer:

I wud respond no, actually it registers ur temperature

Which requires more work: lifting a 100 kg sack a vertical distance of 2 m or lifting a 50 kg sack a vertical distance of 4 m?Explain.

Answers

Answer:

They both require the same amount of work.

Explanation:

Work is said to be done if the force applied to a body cause the boody to move through a distance. Mathematically;

Workdone = Force * Distance

Workdone = mass * acceleration due to gravity * Distance

For the 100kg sack lifted through a distance of 2m:

Workdone = 100 * 9.8 * 2

Workdone = 980 * 2

Workdone = 1960Joules

For 50kg sack lifted through a distance of 4m;

Workdone = 50 * 9.8 * 4

Workdone = 200 * 9.8

Workdone  = 1960Joules.

Since the workdone in carry both sack is the same, hence they both require the same amount of work.

If the original experiment is repeated with a 1.0 kg aluminum block, what is the final temperature of the water and block

Answers

Answer:

T₂ = 36.36°C

Explanation:

The complete question is:

A 0.5 kg block of aluminum (Caluminum = 900J/kg*C)is heated to 200 C. The block is then quickly placed in an insulated tub of cold water at 0C (Cwater=4186J/kg*C) and sealed. At equilibrium, the temperature of the water and block are measured to be 20C.

A)     If the original experiment is repeated with a 1.0 kg {kg} aluminum block, what is the final temperature of the water and block?

Answer: We will apply the law of conservation of energy here:

Heat Loss by Aluminum Block = Heat Gained by Water

m₁C₁ΔT₁ = m₂C₂ΔT₂

where,

m₁ = mass of aluminum block

C₁ = Specific Heat Capacity of Aluminum Block = 900 J/kg °C

ΔT₁ = Change in Temperature of Aluminum Block

m₂ = mass of water

C₂ = Specific Heat Capacity of Water = 4186 J/kg °C

ΔT₂ = Change in Temperature of water

Therefore, for initial given condition:

m₁ = 0.5 kg

ΔT₁ = 200°C - 20°C = 180°C

m₂ = ?

ΔT₂ = 20°C - 0°C = 20°C

Therefore,

(0.5 kg)(900 J/kg °C)(180°C) = m₂(4186 J/kg °C)(20°C)

m₂ = 81000 J/(83720 J/kg)

m₂ = 0.97 kg

Now, we have the mass of water. So, we can solve for the final equilibrium temperature if the mass of block is changed to 1 kg. So, for the new state:

m₁ = 1 kg

m₂ = 0.97 kg

ΔT₁ = 200°C - T₂

ΔT₂ = T₂ - 0°C

T₂ = Final Equilibrium Temperature = ?

Therefore,

(1 kg)(900 J/kg °C)(200°C - T₂) = (0.97 kg)(4186 J/kg °C)(T₂ - 0°C)

180000 J  - (900 J/°C)(T₂) = (4050 J/°C)(T₂)

180000 J = (900 J/°C)(T₂) + (4050 J/°C)(T₂)

T₂ = (180000 J)/(4950 J/°C)

T₂ = 36.36°C

A car is moving with a speed of 32.0 m/s. The driver sees an accident ahead and slams on the brakes, causing the car to slow down with a uniform acceleration of magnitude 3.50 m/s2. How far does the car travel after the driver put on the brakes until it comes to a stop?

Answers

Answer:

292 m

Explanation:

Step one:

given data

initial velocity velocity v= 32 m/s

final  velocity u= 0 m/s

acceleration a= 3.5m/s^2

Required

The distance covered upon the application of the brake

Step two:

we know that acceleration

a= v-u/t

t= v-u/a

t= (0-32)/3.5

t=32/3.5

t=9.14seconds

also, to find distance, we  use s=d/t,

rearrange as d=s*t  

d=32*9.14 s

d=292 m

Janet jumps horizontally off a high diving platform with a velocity of 2.63 m/s and lands in the water 1.9 s later. How high is the platform

Answers

Answer:

The height of the platform is 22.686 m.

Explanation:

Given;

initial velocity of Janet, u = 2.63 m/s

time of her motion, t = 1.9 s

The height of the platform is given by;

h = ut + ¹/₂gt²

substitute the given values and solve for height "h"

h = (2.63 x 1.9) + ¹/₂(9.8)(1.9)²

h = 4.997 + 17.689

h = 22.686 m

Therefore, the height of the platform is 22.686 m.

A solenoid that is 133 cm long has a radius of 2.99 cm and a winding of 1740 turns; it carries a current of 3.91 A. Calculate the magnitude of the magnetic field inside the solenoid.

Answers

Answer:

The value is  [tex]B = 0.0643 \ T[/tex]  

Explanation:

From the question we are told that

   The length of the solenoid is  [tex]L = 133 \ cm = 1.33 \ m[/tex]

     The radius is  [tex]r = 2.99 \ cm = 0.0299 \ m[/tex]

     The number of turns is [tex]N = 1740 \ turns[/tex]

     The current it carries is  [tex]I = 3.91 \ A[/tex]

Generally the magnitude of the magnetic field is mathematically represented as

           [tex]B = \frac{\mu_o * N * I}{L}[/tex]

Here  [tex]\mu_o[/tex]  is the permeability of free space with value  [tex]\mu_o = 4\pi *10^{-7} \ N/A^2[/tex]

=>      [tex]B = \frac{ 4\pi * 10^{-7} * 1740 * 3.91}{0.133}[/tex]  

=>      [tex]B = 0.0643 \ T[/tex]  

What is the only bone of the skull that moves?

Answers

Answer:

Mandible.

Explanation:

The mandible in the bone that allows you to open and close your mouth, otherwise known ad the jawbone.

Answer:

mandible

Explanation:

which is also the lower jaw and it allows the mouth to open and close

hope i helped

Problem 10: A simple pendulum with mass, m=1 kg and length, L=2.0 m is released by
a push when the support string is at an angle of 45° from the vertical direction. The initial
speed of the suspended mass at the release point is 3.0 m/s.
(a) The maximum angle that pendulum moves in the second half of its swing is
(b) The mechanical energy of pendulum (measured relative to its lowest point) is

Answers

Answer:

A student is conducting a pendulum experiment. Which of the following pieces of safety equipment would be the most vital to conduct this test?

Explanation:

A 0.2-kg stone attached to a string is swung in a circle with a radius 0.6 m on a horizontal frictionless surface. What is the tension in the string if the stone makes 150 revolutions per minute?

Answers

Answer:

The value is  [tex]T = 29.58 \ N[/tex]

Explanation:

From the question we are told that

      The mass of the stone is  [tex]m = 0.2 \ kg[/tex]

      The radius of the circle is [tex]r = 0.6 \ m[/tex]

      The angular speed is  [tex]w = 150 \ rpm = \frac{ 2 * \pi * 150 }{ 60 } = 15.7 \ rad/s[/tex]

Generally the tension in the string is mathematically represented as

           [tex]T = m * r * w ^2[/tex]

=>        [tex]T = 0.2 * 0.6 * 15.7 ^2[/tex]

=>        [tex]T = 29.58 \ N[/tex]

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