Suppose that an airline uses a seat width of 16.2 in. Assume men have hip breadths that are normally distributed with a mean of 14 in. and a standard deviation of 1 in. Complete parts (a) through (c) below.

Suppose That An Airline Uses A Seat Width Of 16.2 In. Assume Men Have Hip Breadths That Are Normally

Answers

Answer 1

Given:

population mean (μ) = 14 inches

population standard deviation (σ) = 1 inch

sample size (n) = 126

Find: the probability that a sample mean > 16.2 inches

Solution:

To determine the probability, first, let's convert x = 16.2 to a z-value using the formula below.

[tex]x=\frac{\bar{x}-\mu}{\sigma\div\sqrt{n}}[/tex]

Let's plug into the formula above the given information.

[tex]z=\frac{16.2-14}{1\div\sqrt{126}}[/tex]

Then, solve.

[tex]z=\frac{2.2}{0.089087}[/tex][tex]z=24.6949[/tex]

The equivalent z-value of x = 16.2 is z = 24.6949

Since we are looking for the probability of greater than 16.2 inches, let's find the area under the normal curve to the right of z = 24.6949.

Based on the standard normal distribution table, the area from the center to z = 24.6949 is 0.5

Since we want the area to the right, let's subtract 0.5 from 0.5.

[tex]0.5-0.5=0[/tex]

Therefore, the probability that a sample mean of 126 men is greater than 16.2 inches is 0.


Related Questions

Joe is painting his wooden fence post before putting them in his yard. They are each 8 feel tall and have a diameter of 1 foot. There are 12 fence post in all. How much Paint will Joe need to paint all the surfaces of the 12 fencepost? Use 3:14 for tt and round your final answer to the nearest number Total paint needed: _______

Answers

Given

The number of fence post is 12.

The dimension of each fence post is 8ft tall and 1ft diameter.

To find: How much paint is needed to paint all the surfaces of the 12 fenceposts.

Explanation:

It is given that,

The number of fence post is 12.

The dimension of each fence post is 8ft tall and 1ft diameter.

Therefore,

The fencepost is cylindrical in shape.

Then, the total surface area of the cylinder is,

[tex]\begin{gathered} TSA\text{ of cylinder}=2\pi r(h+r) \\ =2\times3.14\times\frac{1}{2}\times(8+\frac{1}{2}) \\ =3.14\times\frac{17}{2} \\ =26.69ft^2 \end{gathered}[/tex]

That implies,

[tex]\begin{gathered} Required\text{ }quantity\text{ }of\text{ }paint=12\times26.69 \\ =320.28 \\ =320ft^2 \end{gathered}[/tex]

Hence, the required quantity of paint is 320ft^2.

Given g=(1+2a)/a, solve for the variable a.

Answers

We are given the equality

[tex]g=\frac{1+2a}{a}[/tex]

and told to solve for a. That is, we should apply mathematical operations on both sides of the equality so we "isolate" variable a on one side of the equality. We start by multiplying both sides by a, so we get

[tex]a\cdot g=1+2a[/tex]

Now, we subtract 2a from both sides. We get

[tex]a\cdot g-2a=1[/tex]

We can factor on the left side a as a common factor, so we get

[tex]a\cdot(g-2)=1[/tex]

Finally, we divide by (g-2) on both sides, so we get

[tex]a=\frac{1}{g-2}[/tex]

State the rational number represented by each letter on the number line as a decimal.

Answers

The rational number represented by the letter D is -43/100 and by the letter R is -46/100.

What is rational number?

A rational number is one that can be written as the ratio or fraction p/q of two numbers, where p and q are the numerator and denominator, respectively.

Here the number line is divided into 10 division with equal distance.

Each division is of the distance 0.01

So, the decimal number represented by letter D is -0.43 and by the letter R is -0.46.

To convert decimal number into rational number,

-0.43 = -43/100

-0.46 = -46/100

Therefore, the rational number represented by each letter on the number line as a decimal are D = -43/100 and R = -46/100.

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The width of a rectangle measures (4.3q - 3.1) centimeters, and its length
measures (9.6q-3.6) centimeters. Which expression represents the perimeter, in
centimeters, of the rectangle?

Answers

The expression that represents the perimeter and the of the rectangle is: 14.6q - 13.4.

What is the Perimeter of a Rectangle?

A rectangle's perimeter if the length of its surrounding borders. Thus, the perimeter of a rectangle is the sum of all the length of the sides of the rectangle which can be calculated using the formula below:

Perimeter of a rectangle = 2(length + width).

Given the following:

Width of the rectangle =  (4.3q - 3.1) centimetersLength of the rectangle =  (9.6q - 3.6) centimeters

Therefore, substitute the expression for the width and length of the rectangle into the perimeter of the rectangle formula:

Perimeter of rectangle = 2(9.6q - 3.6 + 4.3q - 3.1)

Combine like terms

Perimeter of rectangle = 2(7.3q - 6.7)

Perimeter of rectangle = 14.6q - 13.4

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Give two examples when you would need to know the perimeter and two examples of when you would need to know the area.

Answers

Perimeter is the distance around a figure. The instances where we need to find perimeter include

1) The total length of the boundary of a marked field. This would involve adding the distance around it. Both the curved and straight paths

2) The length of barbed wire to be placed on a fence would require us to find the distance round the fence

The area of a shape is the space enclosed within the perimeter of the shape. The instances where we need to find area include

1) The area of a wall is calculated to determine how much paint is needed to paint it. The paint is used per square unit.

2) The area of a field is calculated to determine the cost of mowing it since the cost is calculated per unit square

Find all X values where the tangent line to the graph of the function…

Answers

Consider the function,

[tex]f(x)=6\sin x+\frac{9}{8}[/tex]

The first derivative gives the slope (m) of the tangent of the curve,

[tex]\begin{gathered} m=f^{\prime}(x) \\ m=\frac{d}{dx}(6\sin x+\frac{9}{8}) \\ m=6\cos x+0 \\ m=6\cos x \end{gathered}[/tex]

The equation of the line is given as,

[tex]y-3\sqrt[]{3}x=\frac{7}{3}[/tex]

This can be written as,

[tex]y=3\sqrt[]{3}x+\frac{7}{3}[/tex]

Comparing with the slope-intercept form of the equation of a line, it can be concluded that the given line has a slope,

[tex]m^{\prime}=3\sqrt[]{3}[/tex]

Given that the tangent to the curve is parallel to this line, so their slopes must also be equal,

[tex]\begin{gathered} m=m^{\prime} \\ 6\cos x=3\sqrt[]{3} \\ \cos x=\frac{\sqrt[]{3}}{2} \\ \cos x=\cos (\frac{\pi}{6}) \end{gathered}[/tex]

Consider the formula,

[tex]\cos A=\cos B\Rightarrow A=2k\pi\pm B[/tex]

Applying the formula,

[tex]x=2k\pi\pm\frac{\pi}{6}[/tex]

Thus, the required values of 'x' are,

[tex]x=2k\pi\pm\frac{\pi}{6}[/tex]

Therefore, options 1st and 2nd are the correct choices.

The rat population in major metropolitan city is given by the formula n(t)=40e^0.015t where t is measured in years since 1991 and n(t) is measured in millions. What does the model predict the rat population was in the year 2008?

Answers

To use the model we need to find the value of t. To do this we substract the year we want to know from the year the model began, then:

[tex]t=2008-1991=17[/tex]

Now that we have t we plug it in the function:

[tex]n(17)=40e^{0.015\cdot17}=51.618[/tex]

Therefore the model predict that there were 51.618 millions of rats in 2008.

Select the correct answerVector u has its initial point at (15, 22) and its terminal point at (5, 4). Vector v points in a direction opposite that of u, and its magnitude is twicethe magnitude of u. What is the component form of v?OA V=(-20, 36)OB. V=(-20, 52)Ocv = (20, 36)ODV= (20, 52)

Answers

Answer

Option C is correct.

v = (20, 36)

Explanation

If the initial and terminal points of a vector are given, the vector itself is obtained, per coordinate, by doing a terminal point coordinate minus initial point coordinate.

u = [(5 - 15), (4 - 22)]

u = (-10, -18)

Then, we are told that vector v points in the opposite direction as that of vector u and its magnitude is twice that of vector u too.

In mathematical terms,

v = -2u

v = -2 (-10, -18)

v = (20, 36)

Hope this Helps!!!

Please help with the question below (please try to answer in maximum 5/10 minutes).

Answers

Given

Joshira can create 1 item in 3/4 of an hour.

To find:

How many items can she create in 8 hours?

Explanation:

It is given that,

Joshira can create 1 item in 3/4 of an hour.

That implies,

[tex]\begin{gathered} Number\text{ }of\text{ }items\text{ }created\text{ }in\text{ }\frac{3}{4}\text{ }hour=1 \\ Number\text{ }of\text{ }items\text{ }created\text{ }in\text{ }1\text{ }hour=1\div(\frac{3}{4}) \\ =1\times\frac{4}{3} \\ =\frac{4}{3} \end{gathered}[/tex]

Therefore, number of items created in 8 hours is,

[tex]\begin{gathered} Number\text{ }of\text{ }items\text{ }created\text{ }in\text{ }8\text{ }hours=\frac{4}{3}\times8 \\ =\frac{32}{3} \\ =\frac{30+2}{3} \\ =\frac{30}{3}+\frac{2}{3} \\ =10+\frac{2}{3} \\ =10\frac{2}{3}\text{ }items \end{gathered}[/tex]

Hence, she can create 10 2/3 items in 8 hours.

Max packs cereal boxes into a larger box. The volume of each cereal box is 175 cubic inches. What is the approximate volume of the large box? Please help!!

Answers

Using mathematical operations, we can conclude that the volume of the larger box is approximately 2,800 in³.

What are mathematical operations?The rules governing the order of operations specify the order in which multiple operations should be performed to solve an expression. Parentheses, Exponents, Multiplication, Division (from left to right), Addition, and Subtraction are the order in which the operations are performed (from left to right).

So, in the image, we can observe that the large box contains 6 boxes of cereals in front and possibly 8 boxes of cereals at the back.

In total, there are 16 small boxes in the big box.

Then, the volume of the larger box can be:

175 × 16 = 2,800 in³

Therefore, using mathematical operations, we can conclude that the volume of the larger box is approximately 2,800 in³.

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Directions: Identify the slope and y-intercept of the line on the graph. Then, write the equation of the line in slope-intercept form.

Answers

To find out the slope, we need two points

so

looking at the graph

we take

(-4,5) and (0,-3)

m=(-3-5)/(0+4)

m=-8/4

m=-2

the y-intercept (value of y when the value of x is zero) is the point (0,-3)

the equation of the line in slope-intercept form is

y=mx+b

where

m is the slope

b is the y-coordinate of the y-intercept

so

m=-2

b=-3

substitute

y=-2x-3

Find two points on the graph of this function other than the origin that fits in the given grid express each coordinate as an integer or simplified fraction or around four decimal places as necessary another coordinates to plot points on

Answers

Substitute arbitrary values of x for which -10 < h(x) < 10.

In this instance, we can use x = 1, and x = -1

[tex]\begin{gathered} h(x)=-\frac{5}{8}x^5 \\ h(1)=-\frac{5}{8}(1)^5 \\ h(1)=-\frac{5}{8} \\ h(1)=-0.625 \\ \\ h(x)=-\frac{5}{8}x^{5} \\ h(-1)=-\frac{5}{8}(-1)^5 \\ h(-1)=\frac{5}{8} \\ h(-1)=0.625 \end{gathered}[/tex]

Therefore, the points that fits in the grid in the function h(x) are (1, -0.625) and (-1, 0.625).

=GEOMETRYPythagorean TheoremFor the following right triangle, find the side length x. Round your answer to the nearest hundredth.

Answers

From the triangle, we have:

c = 13

b = 7

Let's solve for a.

The triangle is a right triangle.

To find the length of the missing sides, apply Pythagorean Theorem:

[tex]c^2=a^2+b^2[/tex]

We are to solve for a.

Rewrite the equation for a:

[tex]a^2=c^2-b^2[/tex]

Thus, we have:

[tex]\begin{gathered} a^2=13^2-7^2 \\ \\ a^2=169-49 \\ \\ a^2=120 \end{gathered}[/tex]

Take the square root of both sides:

[tex]\begin{gathered} \sqrt[]{a^2}=\sqrt[]{120} \\ \\ a=10.95 \end{gathered}[/tex]

ANSWER:

[tex]10.95[/tex]

9) Professor Elderman has given the same multiple-choice final exam in his Principles ofMicroeconomics class for many years. After examining his records from the past 10 years, hefinds that the scores have a mean of 76 and a standard deviation of 12.Professor Elderman offers his class of 36 a pizza party if the class average is above 80. What isthe probability that he will have to deliver on his promise?

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

data:

score:

mean = 76

standard deviation = 12

Step 02:

probability:

normal distribution:

normal distribution diagram:

mean + 1 standard deviation = 76 + 12 = 88

probability (class average score is above 80):

p (score > 80) = 34% + 13.5% + 2.4% + 0.1% = 50% = 0.5

The answer is:

p (score > 80) = 50% = 0.5

HELP I JUST WANT TO FINISH GET MY CREDIT AND GRADUATE 70 POINTS HELP ASAP What are the values of x and y in the matrix subtraction below? [[- 20, 16], [4, 0], [9, - 6]] - [[- 5, 1], [- 6, 7], [0, 11]] = [[x, y], [10, - 7], [9, - 17]]

Answers

SOLUTION

We want to solve the question below

We can see that a matrix was subtracted from another. In Addition or subtraction of matrix, we just add or subtract the element. So

We have in the first row

[tex]\begin{gathered} -20-(-5)=x \\ -20+5=x_ \\ x=-15 \end{gathered}[/tex]

And

[tex]\begin{gathered} 16-1=y \\ 15=y \\ y=15 \end{gathered}[/tex]

Hence x = -15 and y = 15, the first option is correct

Which equation has the same solution as x2 + 8x – 17 = -8? Submit Answer (3-4)2 = -7 O (2+4)2 = 25 O (x – 4)2 = 25 (x - 1)² = -7 problem 3 out of max 6

Answers

Given

[tex]x^2+8x-17=-8[/tex]

Procedure

[tex]\begin{gathered} x^2+8x+16-16-17=-8 \\ (x+4)^2=16+17-8 \\ (x+4)^2=25 \end{gathered}[/tex]

The answer would be (x+4)^2 = 25

Hello, can you help me with a Standard deviation question, please?

Answers

To now how many had a score under 66, we have to calculate the following probability

[tex]P(X<66)=P(Z<\frac{66-81}{5})=P(Z<-3)=0.0013[/tex]

So the amount of people that had a score under 66 is

[tex]4502\cdot0.0013=5.86\approx6[/tex]

So 6 people get a score under 66

Lawn20 meters-WalkwayGazeboRHQ15 metersA bag of grass seed costs $64.26. If agardener wants to calculate the costofgrass seed required to plant the lawn,what additional information wouldhe need to know?A the location of the walkwayBthe perimeter of the lawnс the weight of one bag of grass seedD the area that can be covered byone bag of seed

Answers

He needs option D. Because the perimeter is not the total area (it is only the distance in meters/centimeters that surround the lawn, we need to know how much area a bag of grass seeds covers, for us to know how many to buy. Also, we need the area of the walkway, since it is not covered by grass

The area of a triangle is:

[tex]Area\text{ = }\frac{b(h)}{2}[/tex]

But, since there is a walkway that isn't covered in grass, we need to subtract the circle area from the triangle area

Area of circle:

[tex]Area\text{ = }\pi r^2[/tex]

Then the total area of the lawn :

[tex]Area\text{ Lawn = }\frac{b(h)}{2}\text{ - \lparen}\pi r^2)[/tex]

if q(x)= int 0 ^ x^ 3 sqrt 4+z^ 6 dz then

Answers

Solution:

Given that:

1. Which of the following is NOT a linear function? (1 point ) Oy=* -2 x x Оy - 5 ya 0 2. 3*- y = 4 3.

Answers

hello

to solve this question we need to know or understand the standard form of a linear equation

the standard form of a linear equation is given as

[tex]\begin{gathered} y=mx+c \\ m=\text{slope} \\ c=\text{intercept} \end{gathered}[/tex]

from the options given in the question, only option D does not corresponds with the standard form of a linear equation

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Determine whether each expression can be used to find the length of side RS.

Answers

ANSWER:

[tex]\begin{gathered} \sin (R)\rightarrow\text{ Yes} \\ \tan (T)\rightarrow\text{ No} \\ \cos (R)\rightarrow\text{ No} \\ tan(R)\rightarrow\text{ No} \end{gathered}[/tex]

STEP-BY-STEP EXPLANATION:

Since we know a side and the hypotenuse, we can rule out tangent and cotangent, since these are related to the two legs.

Therefore, if we want to know that side we must apply sine or cosine, just like this:

[tex]\begin{gathered} \sin \theta=\frac{\text{opposite }}{\text{ hypotenuse}} \\ \text{therefore, in this case:} \\ \sin R=\frac{21}{35} \\ \cos \theta=\frac{\text{adjacent}}{\text{ hypotenuse}} \\ \cos R=\frac{\text{unknown}}{35} \end{gathered}[/tex]

Therefore, the way to calculate the value of the missing side is by means of the sine of the angle R

5. Prove triangle ABD is congruent to triangle CDB. DC|AB D

Answers

[tex]\begin{gathered} \text{The hypotaneous is common for both the triangle} \\ \text{Them angle}\angle A\text{ and }\angle C\text{ both are }\Rightarrow90^{\circ} \\ \text{The length of DC and AB are same.} \\ \text{Thus triangle ADB and triangle CDB both are congruent.} \end{gathered}[/tex]

As a test engineer, you are in charge of maintaining an experimental aircraft . According to the maintence manual, you need to inspect a wing every 10 flight hours. The aircraft flown 3 flights, each lasting 2.75 hours Since the last inspection. How many hours do you need before the wing should be inspected?

Answers

EXPLANATION

Let's see the facts:

Inspect period = 10 flight hours

Flown= 3 flights/2.75 hours

Total flights hours = 3x2.75 = 8.25 hours

The difference is 10-8.25 = 1.75 hours.

We need 1.75 hours more before the next wing inspection.

For which equation would x = 12 be a solution?x - 12 = 12x - 24 = 12x - 14 = 2x - 5 = 7

Answers

Explanation

We are required to solve each equation till we arrive at the one that satisfies the "x=12" question.

First equation:

[tex]\begin{gathered} x-12=12 \\ Collect\text{ like terms} \\ x=12+12 \\ x=24 \end{gathered}[/tex]

Second equation:

[tex]\begin{gathered} x-24=12 \\ Collect\text{ like terms} \\ x=12+24 \\ x=36 \end{gathered}[/tex]

Third equation:

[tex]\begin{gathered} x-14=2 \\ Collect\text{ like terms} \\ x=2+14 \\ x=16 \end{gathered}[/tex]

Last equation:

[tex]\begin{gathered} x-5=7 \\ Collect\text{ like terms} \\ x=7+5 \\ x=12 \end{gathered}[/tex]

Hence, the last equation is the solution.

in the figure below, RTS is an isosceles triangle with sides SR=RT, TVU is an equilateral triangle, WT is the bisected of angle STV, points S, T, and U are collinear, and c= 40 degrees.I'm completely lost and have to answer for a, b+c, f, b+f, a+d, e+g

Answers

Step 1: Concept

Triangle SRT is an isosceles triangle with equal base angles a = b

Triangle TUV is an equilateral triangle with all angles equal: g = d = h

Step 2: Apply sum of angles in a triangle theorem to find angle a and b.

[tex]\begin{gathered} a+b+c=180^o \\ c=40^o \\ \text{Let a = b = x} \\ \text{Therefore} \\ x\text{ + x + 40 = 180} \\ 2x\text{ = 180 - 40} \\ 2x\text{ = 140} \\ x\text{ = }\frac{140}{2} \\ x\text{ = 70} \\ a\text{ = 70 and b = 70} \end{gathered}[/tex]

Step 3:

2) a = 70

3) b + c = 70 + 40 = 110

Step 4:

Since WT is a bisector of angle STV,

Angle f = e = x

b + f + e = 180 sum of angles on a straight line.

b = 70

70 + x + x = 180

2x = 180 - 70

2x = 110

x = 110/2

x = 55

Hence, f = 55

4) f = 55

5) f + b = 55 + 70 = 125

Step 5:

Since triangle TUV is an equilateral triangle, angle g = h = d = 60

g = 60

h = 60

d = 60

6) Angle a + d = 70 + 60 = 130

7) e + g = 55 + 60 = 115

as the x increases by 1, what will the rate of change for y in this equation y=-3x+10

Answers

Answer:

Rate of change = -3

Explanation:

Given the equation:

[tex]y=-3x+10[/tex]

When x=1

[tex]\begin{gathered} y=-3(1)+10 \\ =-3+10 \\ =7 \end{gathered}[/tex]

When x=2

[tex]\begin{gathered} y=-3(2)+10 \\ =-6+10 \\ =4 \end{gathered}[/tex]

Observe that the value of y decreases by 3 as the x increases by 1.

Thus, the rate of change is -3.

Alternate Route

Another way is to express and compare the line with the slope-intercept form:

[tex]\begin{gathered} y=mx+b \\ y=-3x+10 \end{gathered}[/tex]

The rate of change is the coefficient of x.

Coefficient of x = -3

Thus, the rate of change is -3.

What are the x- and y-intercepts of a line with slope 2 passing through the point (1, 8)?

Answers

The x- and y-intercepts of a line with slope 2 passing through the point (1, 8) is x-intercept=(3,0) and y-intercept=(0,6) as defined "The slope intercept formula y = mx + b is used when you know the slope of the line to be examined and the point given is also the y intercept (0, b)."

What is slope intercept?

The slope intercept form in math is one of the forms used to calculate the equation of a straight line, given the slope of the line and intercept it forms with the y-axis. The slope intercept form is given as, y = mx + b, where 'm' is the slope of the straight line and 'b' is the y-intercept.

Here,

Let (x1, y1) = (1, 8) and m = 2.

Then, y - y1 = m(x - x1)

y - (8) = 2(x -1)

y-8= 2(x-1)

y -8 = 2x -2

y = 2x + 6

y=(0,6)

x=(3,0)

According to the definition "The slope intercept formula y = mx + b is used when you know the slope of the line to be examined and the point given is also the y intercept (0, b)," the x- and y-intercepts of a line with slope 2 passing through the point (1, 8) are x-intercept=(3,0) and y-intercept=(0,6).

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A net of arectangular pyramidis shown. Therectangular base haslength 24 cm andwidth 21 cm. Thenet of the pyramidhas length 69.2 cmand width 64.6 cm.Find the surfacearea of the pyramid.

Answers

Solution

The Image will be of help

To find x

[tex]\begin{gathered} x+24+x=69.2 \\ 2x+24=69.2 \\ 2x=69.2-24 \\ 2x=45.2 \\ x=\frac{45.2}{2} \\ x=22.6 \end{gathered}[/tex]

To find y

[tex]\begin{gathered} y+21+y=64.6 \\ 2y+21=64.6 \\ 2y=64.6-21 \\ 2y=43.6 \\ y=\frac{43.6}{2} \\ y=21.8 \end{gathered}[/tex]

The diagram below will help us to find the Surface Area of the Pyramid

The surface area is

[tex]SurfaceArea=A_1+2A_2+2A_3[/tex]

To find A1

[tex]A_1=24\times21=504[/tex]

To find A2

[tex]\begin{gathered} A_2=\frac{1}{2}b\times h \\ 2A_2=b\times h \\ 2A_2=21\times22.6 \\ 2A_2=474.6 \end{gathered}[/tex]

To find A3

[tex]\begin{gathered} A_3=\frac{1}{2}bh \\ 2A_3=b\times h \\ 2A_3=24\times21.8 \\ 2A_3=523.2 \end{gathered}[/tex]

The surface Area

[tex]\begin{gathered} SurfaceArea=A_1+2A_2+2A_3 \\ SurfaceArea=504+474.6+523.2 \\ SurfaceArea=1501.8cm^2 \end{gathered}[/tex]

Thus,

[tex]SurfaceArea=1501.8cm^2[/tex]

hello, in the picture you can see a graph and my teacher said that the domain and range would be all real numbers possible. could you please help me because I don't understand why.

Answers

The domain is all the values of the independent variable (in this case, x) for which the function is defined.

In this case, as it is indicated with the arrows in both ends, the function continues for greater and smaller values of x.

As there is no indication that for some value or interval of x the function is not defined (a discontinuity, for example), then it is assumed that the function domain is all the real values.

Example function:

We have the function y=1/(x-2)

We can look if there is some value of x that makes the function not defined.

The only value of x where f(x) is not defined is x=2. When x approximates to 2, the value of the function gets bigger or smaller whether we are approaching from the right or from the left.

Then, the function is not defined for x=2. So, the domain of f(x) is all the real numbers different from x=2.

The domain is, by default, all the real numbers, but we have to exclude all the values of x (or intervals, in some cases like the square roots) for which f(x) is not defined.

Plot the vertex of f(x) = (x − 2)2 + 2.

Answers

Take into account that the general function of a parabola in vertex form is given by:

[tex]f(x)=a(x-h)^2+k[/tex]

where (h,k) is the vertex of the parabola.

By comparing the previous general function with the given function:

[tex]f(x)=(x-2)^2+2[/tex]

you can notice that:

h = 2

k = 2

Hence, you can conclude that the vertex of the given function is (2,2)

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