Predator? like they hunt their prey
Answer:
prey
Explanation:
An object that has the ability to do work has __________ energy. (4 points)
a. magnetic
b. kinetic
c. potential
d. electrical
Answer:
c. potential
Explanation:
A car and a train move together along straight, parallel paths with the same constant cruising speed v0. At t=0 the car driver notices a red light ahead and slows down with constant acceleration −a0. Just as the car comes to a full stop, the light immediately turns green, and the car then accelerates back to its original speed v0 with constant acceleration a0. During the same time interval, the train continues to travel at the constant speed v0.Part A :- How much time does it take for the car to come to a full stop? Express your answer in terms of v0 and a0Part B:- How much time does it take for the car to accelerate from the full stop to its original cruising speed? Express your answer in terms of v0 and a0.Part C:- The train does not stop at the stoplight. How far behind the train is the car when the car reaches its original speed v0 again? Express the separation distance in terms of v0 and a0 . Your answer should be positive.
Answer:
a) t1 = v0/a0
b) t2 = v0/a0
c) v0^2/a0
Explanation:
A)
How much time does it take for the car to come to a full stop? Express your answer in terms of v0 and a0
Vf = 0
Vf = v0 - a0*t
0 = v0 - a0*t
a0*t = v0
t1 = v0/a0
B)
How much time does it take for the car to accelerate from the full stop to its original cruising speed? Express your answer in terms of v0 and a0.
at this point
U = 0
v0 = u + a0*t
v0 = 0 + a0*t
v0 = a0*t
t2 = v0/a0
C)
The train does not stop at the stoplight. How far behind the train is the car when the car reaches its original speed v0 again? Express the separation distance in terms of v0 and a0 . Your answer should be positive.
t1 = t2 = t
Distance covered by the train = v0 (2t) = 2v0t
and we know t = v0/a0
so distanced covered = 2v0 (v0/a0) = (2v0^2)/a0
now distance covered by car before coming to full stop
Vf2 = v0^2- 2a0s1
2a0s1 = v0^2
s1 = v0^2 / 2a0
After the full stop;
V0^2 = 2a0s2
s2 = v0^2/2a0
Snet = 2v0^2 /2a0 = v0^2/a0
Now the separation between train and car
= (2v0^2)/a0 - v0^2/a0
= v0^2/a0
The train took 2 h 30 min to travel 3/5 of a journey at an
average speed of 96 km/h. If the train would complete the
journey in 4.1 h, what is the train's average speed for the
remaining journey?
km/h
Answer:
100km/h
Explanation:
96km•2.5=240km
240÷3/5=240•5/3=400km
400-240=160km
4.1-2.5=1.6h
160÷1.6=100km/h
The atomic number of beryllium (Be) is 4, and the atomic number of barium (Ba) is 56. Which comparison is best supported by this information? They are in the same group because they have similar atomic masses, but they are in different periods because they have different chemical properties. They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers. They are in the same group because their atomic numbers are each multiples of four, but they are in different periods because they have different chemical properties. They are in the same group because they have similar atomic masses, but they are in different periods because they have very different atomic numbers.
Answer: They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers.
Explanation: On Edgenuity!!
The comparison is best supported by the information given in option 4. They differ due to their atomic number.
Write about beryllium?A star is a bright spheroid of plasma held together by gravity. The Sun is the most distant star from Earth.
Many additional stars may be seen with the normal eye at night, but their enormous distance from Earth causes them to appear as stationary points of light in the sky.
We are discussing the two-element beryllium (Be) and barium (Ba). The comparison is best supported by this information will be;
They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers.
Hence option 4 is correct.
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4. A 49-N block is pulled by a horizontal force of 50.0 N along a rough horizontal
surface at a constant acceleration of 6 m/s2. What is the coefficient of friction?
Household electricity in a particular country is supplied in the form of alternating current that varies from 180 V to −180 V with a frequency of 100 cycles per second (Hz). The voltage is thus given by the equation E(t) = 180 sin(200πt) where t is the time in seconds. Voltmeters read the RMS (root-mean-square) voltage, which is the square root of the average value of [E(t)]2 over one cycle. (a) Calculate the RMS voltage of household current in this particular country. (Round your answer to the nearest whole number of volts.) V (b) Many electric stoves require an RMS voltage of 220 V. Find the corresponding amplitude A needed for the voltage E(t) = A sin(200πt). (Round your answer to the nearest whole number of volts.) A = V
Answer:
a. 127 V b 311 V
Explanation:
a. The RMS value of E(t) = 1/T∫[E(t)]². E(t) = 180 sin(200πt). Since the frequency f = 100 cycles per second, the period, T = 1/f = 1/100 = 0.01 s.
So, 1/T∫[E(t)]² = 1/T∫[180 sin(200πt)]² = 180²/0.01∫sin(200πt)]²
Using trigonometric identity sin²Ф = (1 - cos2Ф)/2 where Ф = ωt
1/T∫[E(t)]² = 180²/0.01∫(1 - cos2Ф)/2. We integrate from 0 to T, , we have
1/T∫[E(t)]² = 180²/(0.01 × 2)(t - sin2ωt/2ω)
1/T∫[E(t)]² = 180²/(0.02[(T - (sin2π)/(2 × 200π) ) - (0 - [sin(2 × 0)]/(2 × 200π))
1/T∫[E(t)]² = 180²/(0.02)[(0.01 - 0)
1/T∫[E(t)]² = 180²/2
E(t)RMS = √1/T∫[E(t)]²
= √180²/2
= 180/√2
= 127.28 V
= 127 V to the nearest whole number
b. Since E(t)(RMS) = A/√2 where A = voltage amplitude and E(t)(RMS) = 220 V,
A = √2E(t)(RMS) =
√2 × 220 V
= 311.13 V
= 311 V to the nearest whole number
what does a magnetic field look like
Answer:Magnetic fields are invisible, at least usually. But scientists from NASA's Space Sciences Laboratory have made them visible as "animated photographs," using sound-controlled CGI and 3D compositing.
Explanation:
The gravitational acceleration on earth is 9.8m/s. What is the weight of a car on earth (to the nearest whole number) if it has a mass of 1360kg
Answer:
1360*9.8
=13328 joules
(a) Is the velocity of car A greater than, less than, or the same as the
velocity of car B?
(b) Is the initial position of car A greater than, less than, or equal to the
initial position of car B?
(c) In the time period from t = 0 tot = 1 s, is car A ahead of car B,
behind car B, or at the same position as car B?
Answer:
a. less than, b. greater than, c. ahead
Explanation:
a. ) Is the velocity of car A less than the velocity of car B b. the initial position of car A greater than the initial position of car B c. ahead In the time period from t = 0 tot = 1 s, is car A ahead of car B?.
what is velocity ?Velocity is the parameter which is different from speed, can be defined as the rate at which the position of the object is changed with respect to time, it is basically speeding the object in a specific direction in a specific rate.
Velocity is a vector quantity which shows both magnitude and direction and The SI unit of velocity is meter per second (ms-1). If there is a change in magnitude or the direction of velocity of a body, then it is said to be accelerating.
Finding the final velocity is simple but few calculations and basic conceptual knowledge are needed.
For more details regarding velocity, visit
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A ball of mass 3 kg is released at the top of a track, as shown in the image below. The top of the ramp is 1 metre higher than
the lower, horizontal section of the track. This horizontal section is 5 metres long.
Assumptions:
• There is no loss of energy due to friction or air resistance.
• Gravitational acceleration is 9.8 m/s?
3 kg
1 m
5 m
(a) [1 MARK] What type of energy does the ball have when it is being held at the top of the track?
potential energy
(b) How much work must be done to hold the ball at the top of the track?
• [0.5 MARK] Write the amount of work done (number only) here: 0
[0.5 MARKI Write the unit for the work done here (symbol, not words):
.
(C) (1 MARK] What is the velocity (in m/s) of the ball when it is at the start of the horizontal section of the track? (Write the
number only to two decimal places. Do not include the unit.)
(d) [1 MARK] What is the velocity (in m/s) of the ball when it is at the end of the horizontal section of the track? (Write the
number only to two decimal places. Do not include the unit.)
Answer:
potential energy
Explanation:
can result.
When lost fluid is not replaced adequately,
A. heat stroke
B. hypothermia
C. dehydration
D. emphysema
Answer:
Dehydration could possibly take place if lost fluid is not replaced adequately. Hypothermia can not possibly take place due to loss of fluid. Nor can emphysema. So, dehydration looks to be the more suitable answer
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Using the equation for for Newton's Second law, F=ma, solve the following problem. You have been given an object with a mass of 6g and an acceleration of 2 m/s2, what is the force?
Group of answer choices
1. 12N
2. 3N
3. 8N
4. 120N
Answer:
Should be 1.12N
Explanation:
Cause 6×2=12
Answer:
1.12 Newtons
Explanation:
F=ma, so if you convert the numbers, it's just 6 times 2.
Don't be distracted or intimidated by the units, they don't matter in this case. Force will always be in newtons, mass in grams, acceleration in m/s2 and velocity in m/s. They would only convert to their own smaller measurements.
An automobile is traveling at a constant 15 m/s, then it undergoes acceleration from that moment forward. Which statement best describes the automobile's new motion?
Answer:
d
Explanation:
We are required to write a statement that best describes the automobile's new motion.
The statement that best describes the automobile's new motion is uniform acceleration.
Motion is the change of position of a body or object with time.
Uniform Acceleration is defined as the motion of an object whose velocity increases by equal amounts in equal intervals of time, however small the time intervals may be.
The best statement to describe the automobile's new motion is called Uniform Acceleration
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A maser is a laser-type device that produces electromagnetic waves with frequencies in the microwave and radio-wave bands of the electromagnetic spectrum. You can use the radio waves generated by a hydrogen maser as a standard of frequency. The frequency of these waves is 1,420,405,751.786 hertz. (A hertz is another name for one cycle per second.) A clock controlled by a hydrogen maser is off by only 1 s in 100,000 years. (The large number of significant figures given for the frequency simply illustrates the remarkable accuracy to which it has been measured.)A. What is the time for one cycle of the radio wave? Express your answer to three significant figures and include the appropriate units.B. How many cycles occur in 4 h ? Express your answer using three significant figures.C. How many cycles would have occurred during the age of the earth, which is estimated to be 4.6×109 years? Express your answer using three significant figures.D. By how many seconds would a hydrogen maser clock be off after a time interval equal to the age of the earth? Express your answer using three significant figures.
Answer:
a) t₀ = 0.704 10⁻¹² s, b) #cycle = 2.05 10¹⁶ cycles ,
c) #_cycles = 7,418 10³² cycles, d) Δt = 4.6 10⁴ s
Explanation:
For this exercise we must use the relationship between the period and the frequency
f = 1 / T
T = 1 / f
let's apply this equation to our case
a) The time of a cycle is
t = 1 / 1.420405 10¹²
t₀ = 0.704 10⁻¹² s
b) number of cycles in 4 h
t = 4 h (3600 s / 1h) = 14400 s
Let's use a direct rule of proportions (rule of three). If there is 1 cycle in t₀, how much cycle is there
#_cycles = t (1 / t₀)
#_cycle = 14400 s (1 cycle / 0.704 10⁻¹² s)
#_cycle = 2.0454 10¹⁶ cycles
#cycle = 2.05 10¹⁶ cycles
c) cycles since the age of the Earth
t = 4.6 10⁹ years (365 days / year) (24 h / 1 day) (3600 s / 1 h)
t = 5.2224 10²⁰ s
#_cycles = t (1 / to)
# _cycles = 5.2224 10²⁰ (1 / 0.704 10⁻¹²)
#_cycles = 7,418 10³² cycles
d) Let's use the direct proportion rule. If you have a lag of Δt₁ = 1s at t₁ = 1 10⁵ years, what is the lag (Δt) at t = 4.6 10⁹ years
Δt = t (Δt₁ / t₁)
Δt = 4.6 10⁹ years (1 s / 10⁵ years)
Δt = 4.6 10⁴ s
It’s important to measure exercise shoes with the type of exercise in which you will be participating.
Answer:
True
Explanation
the right shoes will help with the comfort & it will help with limits you have on your legs.. Weights, posture,& will help with injury...
explain what nuclear fusion is in the role it plays in Stars. DO NOT LOOK UP ANSWERS
Answer:
Stars are powered by nuclear fusion in their cores, mostly converting hydrogen into helium. The production of new elements via nuclear reactions is called nucleosynthesis. A star's mass determines what other type of nucleosynthesis occurs in its core (or during explosive changes in its life cycle).
A house is maintained at a comfortable temperature by means of an electrical resistor heater during winter. The heater is operated at a constant current (I) under an applied voltage of 110 V. For simplicity, let us assume that the heater operates at a steady state, with 100% of conversion efficiency from the electrical energy to the internal energy of air in the house. (a) (5p) Find I if the homeowner pays $8.80/day for heating, with electricity cost $0.09/kWh. (b) (5p) Calculate the heat produced by the heater in an hour.
Answer:
a) I = 0.01029 A , b) Q = 4074.05 J
Explanation:
a) Let's work in parts, let's start by looking for the energy consumed.
For this we use a rule of three or direct proportions if 1 kWh costs $ 0.09, how much kWh is $ 8.80
Energy = 8.80 / 0.09
Energy = 97,778 kWh
to calculate the current, we must have the energy consumed per second
Let's use a rule of three if 97,778 kWh were consumed in 24 h = 86,400 s how much was consumed in 1 s
E₀ = 97.778 1/86400
E₀ = 1.13168 Ws
the power consumed is
P = E₀ / t
P = 1.13168 / 1
P = 1.13168 W
power is
P = I V
I = P / V
I = 1.13168 / 110
I = 0.01029 A
b) the heat is given by
as the efficiency is 100%
E = P t = Q
Q = 1.131368 3600
Q = 4074.05 J
As θ increases towards 90 what happens to the horizontal and vertical components of F?
Horizontal component , F cos θ.
Vertical component , F sin θ.
Now, as θ increases towards 90° cos θ decreases and
As θ increases towards 90° sin θ increases.
Therefore, horizontal component of F will decrease and vertical component will increase.
Hence, this is the required solution.
How much force is needed to keep a 25 N rock moving with constant speed across the level, frictionless ice?
Answer:
Explanation:
Hello friend!!!!!
The answer is 0 Newton
hope this helps
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An airport has a moving walkway in a long corridor (of lengthL) designed to savepassengers time. If Tom walks through the corridor (not on the moving walkway), it takes him150 s to reach the far end. If Tom stands on the moving walkway, it takes him 100 s to reach thefar end. How long would it take Tom to reach the far end if he got on the moving walkway andwalked at his normal speed relative to the walkway itself?
Answer: 60 seconds
Explanation:
The following information can be derived from the question:
rt=d,
150r = 100
Divide through by 150
r = 100/150
r = 0.67
r = 0.67 feet/second
Fir the second part of the question,
100r=100
r = 100/100
r = 1
r= 1 feet/second
combined rate will now be:
= 0.67+1
= 1.67 feet/second
We then slot it back into the formula
rt = d
1.67t = 100
t = 100/1.67
t= 59.88 seconds
t = 60 seconds approximately
Question 4 (1 point)
Having the ability to play or stay active longer without getting tired explains which
Health-Related Fitness Component?
cardiovascular endurance :))
Calculate What force is needed to accelerate an object 5m/s2 if the object has a mass of 10 kg?
Answer:
50N
Explanation:
F =ma
m=10kg and a=5m\s^2
f= (10)*5
f= 50 N
If you do this quick and and you get it right, I will give you branilest and 5 stars!
1) State Newton’s 3rd Law.
2) While driving down the road, a firefly strikes the windshield of a bus and makes a quite obvious mess in front of the face of the driver. This is a clear case of Newton's third law of motion. The firefly hit the bus and the bus hits the firefly. Which of the two forces is greater: the force on the firefly or the force on the bus?
3) By applying the third law of motion, which force is greater when you push on a wall? Your force, the wall’s force, your force and the wall’s force are equal or the force saved before pushing the wall.
4) If the forces on an object are balanced, the object will do what?
Answer:
1) If you put force on one side of an object, then there is an equal reaction.
2) Force on the firefly
3) Force saved
4) Will not move
104 kg and a volume of 1,278 m3 what is the density
Answer: 0.081 kilogram/cubic meter
Explanation: p=m/v so 104/1278 is 0.081377151799687 or 0.081.
A fly flaps its wings back and forth 25 times in one second. The period of wing flapping is _____.
Answer:
The period is 0.04 secExplanation:
This problem is based on oscillatory motion.
What is the period of oscillation?
This can be defined as the time taken to complete one full revolution or oscillation.
given that the fly flaps its wings back and forth 25 times in one second. then the frequency is 25 Hz
we know that period T= 1/F
T= 1/25
T=0.04 sec
A 7.00-kg block is stacked on top of the 2.90-kg block. What is the magnitude Fof the force, acting horizontally on the 2.90-kg block
as before, that is required to make the two blocks start to move together?
Answer:
F = 19.42 [N]
Explanation:
In order to solve this problem, we must first make a free body diagram and determine the forces acting on each body. In the attached image we can see the respective free body diagrams with the respective equilibrium equations.
In order to determine the value of the force, a static analysis must be performed on the block of 2.9 [kg] so that the value of the Force F can be determined.
A coefficient of friction value between the block of 2.9 [kg] and the ground must be taken into account in order to find the force F. a coefficient of friction value of 0.2 shall be taken
By the sum of forces on the Y-axis equal to zero, the value of the normal force N can be determined on the block of 2.9 [kg].
Then knowing that the frictional force is equal to the product of the normal force by the coefficient of friction, we can determine the frictional force.
By the sum of forces on the X-axis equal to zero, we can determine the value of the Force F, as seen in the equations posed in the attached image.
Note: the value of the Force F depends on the value of the coefficient of friction between surfaces.
where ν is the frequency of light shining on the metal; W is the energy needed to remove an electron from the metal; and me and u are the mass and speed of the ejected electron, respectively. In an experiment, a student found that a maximum wavelength of 371 nm is needed to just dislodge electrons from a metal surface. Calculate the velocity (in m/s) of an ejected electron when the student employed light with a wavelength of 283 nm.
Answer:
v = 6.05 10⁵ m / s
Explanation:
This is an exercise of the photoelectric effect, which consists of the emission of electrons from a metal by the action of incident light, this phenomenon was explained by Einstein, assuming that the light rays are composed of particular called photons, for which the process is can explain by the collision of two particles,
h f = K + Φ
where hv is the energy of the photons, K the kinetic energy of the electrons and fi the work function of the metal
speed, wavelength and frequency are related by
c = λ f
we substitute
h c /λ = K + Φ
let's apply this expression to our problem
λ = 371 nm = 371 10⁻⁹ m
the kinetic energy of zero electrons K = 0
h c /λ = Ф
Ф = 6.63 10⁻³⁴ 3 10⁸/371 10⁻⁹
Ф = 5.36 10⁻¹⁹ J
this value is constant since the metal does not change
for λ = 283 nm = 283 10⁻⁹ m
K = hc /λ - fi
K = 6.63 10⁻³⁴ 3 10⁸/283 10⁻⁹ - 5.36 10⁻¹⁹
K = (7.028 - 5.36) 10⁻¹⁹
K = 1,668 10⁻¹⁹ J
the expression of kinetic energy is
K = ½ m v²
v = √ (2K / m)
v = √(2 1,668 10⁻¹⁹ / 9,1 10⁻³¹)
v = RA (0.36659 10¹²)
v = 0.605 10⁶ m / s
v = 6.05 10⁵ m / s
I need help with this physics question, "A skateboarder rolled down the sidewalk with an initial velocity of 2.5m/s. If her acceleration was 1.7 m/s^2, what was her velocity after she had skated 130m?"
Recall that
[tex]{v_f}^2={v_i}^2+2a\Delta x[/tex]
where [tex]v_i[/tex] and [tex]v_f[/tex] are the skateboarder's velocity, respectively; [tex]a[/tex] is her acceleration; and [tex]\Delta x[/tex] is the change in her position.
Substitute everything you know and solve for [tex]v_f[/tex]:
[tex]{v_f}^2=\left(2.5\dfrac{\rm m}{\rm s}\right)^2+2\left(1.7\dfrac{\rm m}{\mathrm s^2}\right)(130\,\mathrm m)\implies v_f=448.25\dfrac{\mathrm m^2}{\mathrm s^2}\implies\boxed{v_f\approx21\dfrac{\rm m}{\rm s}}[/tex]
A wildebeest runs with an average speed of
4.0
m
s
4.0
s
m
What was its distance travelled in meters?
what is the difference between weak and strong forces I need help now I will give brainliest
Answer:
weak forces are more close to loosing and strong forces are more close to wining
Explanation:
a weak force probably has less staingh than the stronger force hats probably because they don't get enough people to fight, they don't have strong weapons, or they are not getting medical treatment that probably means they are sick some may have a disease and can spread they may not have food water or other supplies.
