The marginal cost in dollars of producing x units is given by the next equation:
[tex]C=2.6\sqrt[]{x}+600[/tex]a)
To find the marginal cost (in dollars per unit) when x= 9.
Then, we need to replace x=9 on the derivation of the cost equation:
So:
[tex]\frac{d}{dx}C=\frac{1.3}{\sqrt[]{x}}[/tex]Where:
[tex]\frac{d}{dx}2.6\sqrt[]{x}=2.6\frac{d}{dx}\sqrt[]{x}=2.6\frac{d}{dx}^{}x^{\frac{1}{2}}=2.6\cdot\frac{1}{2}x^{\frac{1}{2}-1}=1.3\cdot x^{-\frac{1}{2}}=\frac{1.3}{\sqrt[]{3}}[/tex]and, the derivate of a constant is equal to zero.
[tex]\frac{d}{dx}600=0[/tex]Replacing x= 9
[tex]\frac{d}{dx}C=\frac{1.3}{\sqrt[]{9}}[/tex]Hence, the marginal cost is equal to:
[tex]\frac{d}{dx}C=0.43[/tex]b) Now, when the production increases 9 to 10. It's the same as the cost of producing one more machine beyond 9.
Then, it would be x=10 on the cost equation:
[tex]C=2.6\sqrt[]{x}+600[/tex][tex]C=2.6\sqrt[]{10}+600[/tex][tex]C=608.22[/tex]and x= 9
[tex]C=2.6\sqrt[]{9}+600[/tex][tex]C=2.6(3)+600[/tex][tex]C=607.8[/tex]Then, we calculate C(10) - C(9) =
[tex]608.22-607.8[/tex][tex]=0.43[/tex]C)
Both results are equal.
Hence, the marginal cost when x=9 is equal to the additional cost when the production increases from 9 to 10.
Which best represents the number of square centimeters in a square foot?A 366 square centimeters B 144 square centimeters C 930 square centimeters D 61 square centimeters
Answer:
C. 930 square centimeters
Explanation:
First, recall the standard conversion between cm and ft.
[tex]1\text{ ft}=30.48\operatorname{cm}[/tex]Therefore:
[tex]\begin{gathered} (1\times1)ft^2=(30.48\times30.48)cm^2 \\ =929.03\operatorname{cm}^2 \\ \approx930\text{ square cm} \end{gathered}[/tex]The correct choice is C.
A woman who has recovered from a serious illness begins a diet regimen designed to get her back to a healthy weight. She currently weighs 106 pounds. She hopes each week to multiply her weight by 1.04 each week.
The required exponential function would be W = 106 × 1.04ⁿ for the weight after n weeks.
What is an exponential function?An exponential function is defined as a function whose value is a constant raised to the power of an argument is called an exponential function.
It is a relation of the form y = aˣ in mathematics, where x is the independent variable
The given starting weight for the diet program is 106 pounds. Because the weight is expected to be multiplied by 1.04 pounds each week, the weight will develop exponentially with an initial value of 106 pounds and a growth factor of 1.04 pounds. Then, for the weight after weeks, the exponential function is given by,
W = W(n) = Pb'
Here P = 106 and b = 1.04
Hence the required formula is,
⇒ W = 106 × 1.04ⁿ
Thus, the required exponential function would be W = 106 × 1.04ⁿ for the weight after n weeks.
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The question seems to be incomplete the correct question would be
A woman who has recovered from a serious illness begins a diet regimen designed to get her back to a healthy weight. She currently weighs 106 pounds. She hopes each week to multiply her weight by 1.04 each week. Then, find the exponential function for the weight after weeks.
Identify the following forms of factoring with the correct method of solving
Given:
There are given the equation:
[tex]90x^3-20x[/tex]Explanation:
To find the factor of the given equation, first, we need to take a common variable from the given equation:
[tex]90x^3-20x=x(90x^2-20)[/tex]Then,
[tex]\begin{gathered} 90x^3-20x=x(90x^2-20) \\ =10x(9x^2-2) \end{gathered}[/tex]Final answer:
Hence, the factor of the given equation is shown below:
[tex]\begin{equation*} 10x(9x^2-2) \end{equation*}[/tex]explain pleaeeeeeeez
Answer:
So first we can assume x= 1 bc there is no number for x
Step-by-step explanation:
So we Evaluate for x=1
1+|2−1|−5
1+|2−1|−5
=−3
Evaluate for x=1
So x+|x-5|+9
1+|1−5|+9
1+|1−5|+9
=14
A chemist is using 357 milliliters of a solution of acid and water. If 18.6%of the solution is acid, how many milliliters of acid are there? Round your answer to the nearest tenth.
There are 66.4 milliliters of acid in the solution
Explanation:The amount of the solution of acid and water = 357
Percentage composition of acid in the solution = 18.6%
Amount of acid in the solution = (18.6/100) x 357
Amount of acid in the solution = 66.402 milliliters
Amount of acid in the solution = 66.4 milliliters (to the nearest tenth)
There are 66.4 milliliters of acid in the solution
Ms. Kirk has at most $75 to spend on workout supplements. She boughtthree containers of protein powder for $47. She wants to buy protein barsthat cost $4 each. How many protein bars can she buy?
total money is 75$
protein cost = 47$
so the remaining money is
75 - 47 = 28 $
now she bought the protein bars of 28$
cost of one protein bar is 4$
so the number of protein bars that she bought is
[tex]=\frac{28}{4}=7[/tex]so she bought 7 protein bars.
Two containers designed to hold water are side by side, both in the shape of acylinder. Container A has a diameter of 8 feet and a height bf 16 feet. Container B hasa diameter of 10 feet and a height of 8 feet. Container A is full of water and the wateris pumped into Container B until Conainter B is completely full.To the nearest tenth, what is the percent of Container A that is empty after thepumping is complete?
Okay, here we have this:
Considering the provided information, we are going to calculate what is the percent of Container A that is empty after the pumping is complete, so we obtain the following:
First we will calculate the volume of each cylinder using the following formula:
[tex]V=\pi\cdot r^2\cdot h[/tex]Applying:
[tex]\begin{gathered} V_A=\pi\cdot4^2\cdot16 \\ V_A=\pi\cdot16\cdot16 \\ V_A=256\pi \end{gathered}[/tex][tex]\begin{gathered} V_B=\pi\cdot5^2\cdot8 \\ V_B=\pi\cdot25\cdot8 \\ V_B=200\pi \end{gathered}[/tex]After pumping the water from container A to container B, the following amount remains in container A:
Remaining amount of water in A=256π-200π
Remaining amount of water in A=56π
Now, we obtain that the empty percentage that results in A is:
Empty percentage that results in A=200/256*100
Empty percentage that results in A=78.125%
Empty percentage that results in A≈78.1%
What's the equation of the axis of symmetry of g(x)=x^{2}+4 x+3?A) x=0B) x=-2C) x=2D) x=3
Given a quadratic equation of the form:
[tex]f(x)=ax^2+bx+c[/tex]The equation of the axis of symmetry is obtained using the formula:
[tex]x=-\frac{b}{2a}[/tex]From the given quadratic equation:
[tex]\begin{gathered} g\mleft(x\mright)=x^2+4x+3 \\ a=1 \\ b=4 \end{gathered}[/tex]Therefore, the equation of the axis of symmetry of g(x) is:
[tex]\begin{gathered} x=-\frac{4}{2\times1} \\ x=-2 \end{gathered}[/tex]The correct option is B.
ZA and ZB are supplementary angles. If mZA= (8x – 27) and m ZB = (4x + 3), then find the measure of ZA.
Supplementary angles sum up to 180 degrees.
Since mZA and mZB are given to be (8x - 27) and (4x + 3) respectively, we need to know the value of x to be able to find
Supplementary angles sum up to 180 degrees.
Since mZA and mZB are given to be (8x - 27) and (4x + 3) respectively, we need to know the value of x to be able to find
Find the distance between:(4,-9) and(-8,0)Round your answer to the nearest hundredth.
The distance between 2 points (x1, y1) and (x2, y2) is calculated as:
[tex]\text{distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]So, if we replace (x1, y1) by (4, -9) and (x2, y2) by (-8,0), we get:
[tex]\begin{gathered} \text{distance}=\sqrt{(-8-4)^2+(0-(-9))^2} \\ \text{distance}=\sqrt{(-12)^2+(9)^2} \\ \text{distance}=\sqrt{144+81} \\ \text{distance}=\sqrt{225} \\ \text{distance}=15 \end{gathered}[/tex]Answer: the distance is 15
I need help with a math question. I linked it below
1) We can fill in the gaps, this way since we can write the following when we translate into mathematical language:
[tex]\begin{gathered} \frac{b}{55}+8>6 \\ \frac{b}{55}>-8+6 \\ \frac{b}{55}>-2 \\ 55\cdot\frac{b}{55}>-2\cdot55 \\ b>-110 \end{gathered}[/tex]Note that we could do it in two steps. Subtracting and then multiplying and dividing
mark wrote this description of a quadrilateral he drew it has one pair of parallel lines and two congruent lines but the lines that are congruent are not parallel
First, draw two parallel lines:
Next, draw to additional lines of the same length that connect both parallel lines:
Notice that this can be done in two different ways. In the case in red, both lines are not parallel. In the case shown in blue, they are. Since the problem asks for the case when they are not parallel, keep in mind the figure with the lines in red. That figure is a trapezoid.
Select the correct answer from the drop-down menu.Find the polynomial,{4'" is the solution set of
Let P(x) be the polynomial such that the given set is its solution set.
Now notice that:
[tex]\begin{gathered} x=-\frac{1}{3}\Rightarrow x+\frac{1}{3}=0\Rightarrow3x+1=0, \\ x=4\Rightarrow x-4=0. \end{gathered}[/tex]Therefore (x-4) and (3x+1) divide to P(x), then:
[tex]\begin{gathered} Exists\text{ k such that:} \\ P(x)=k(x-4)(3x+1). \end{gathered}[/tex]Simplifying the above result we get:
[tex]P(x)=k(3x^2-11x-4).[/tex]Setting k=1 we get that:
[tex]P(x)=3x^2-11x-4.[/tex]Answer: Second option.
Write the equation of the line when the slope is 1/5 and the y-intercept is 13.
Given:
• Slope, m = 1/5
,• y-intercept = 13
Let's write the equation of the line.
To write the equation of the line, apply the slope-intercept equation of a line:
[tex]y=mx+b[/tex]Where:
m is the slope
b is the y-intercept.
Thus, we have:
m = 1/5
b = 13
Plug in the values in the equation:
[tex]y=\frac{1}{5}x+13[/tex]Therefore, the equation of the line is:
[tex]y=\frac{1}{5}x+13[/tex]Write a quadratic equationwith vertex (3,-6) and otherpoint (-7,14). Solve for a!
We have to find the parameter a of a quadratic equation knowing the following
• The vertex is (3,-6).
,• A random point is (-7,14).
Based on the given information, we have the following
[tex]\begin{gathered} h=3 \\ k=-6 \\ x=-7 \\ y=14 \end{gathered}[/tex]The vertex form of a quadratic equation is
[tex]y=a(x-h)^2+k[/tex]Replacing all the givens, we have
[tex]14=a(-7-3)^2-6[/tex]Now, we solve for a
[tex]\begin{gathered} 14=a(-10)^2-6 \\ 14=a(100)-6 \\ 14+6=100a \\ 100a=20 \\ a=\frac{20}{100}=\frac{1}{5} \end{gathered}[/tex]Therefore, a is equal to 1/5.2-x+ 3-X-4
where a and b are integers.
Work out the value of a and the value of b.
can be written as a single fraction in the form
ax+b
x²-16
Answer:
2-×+3-×-4=0
Step-by-step explanation:
×=1\2
0.5,2`1
Consider the right triangle shown below where a=8.09, b=9.4, and c=12.4. Note that θ and ϕ are measured in radians.What is the value of cos(θ)?cos(θ)= What is the value of sin(θ)?sin(θ)=What is the value of tan(θ)?tan(θ)= What is the value of θ?θ=
By definition
[tex]\cos (angle)=\frac{\text{ adjacent side}}{\text{ hipotenuse}}[/tex]From the picture
[tex]\begin{gathered} \cos (\theta)=\frac{a}{c} \\ \cos (\theta)=\frac{8.09}{12.4} \\ \cos (\theta)=0.65 \end{gathered}[/tex]By definition
[tex]\sin (angle)=\frac{\text{ opposite side}}{\text{ hipotenuse}}[/tex]From the picture:
[tex]\begin{gathered} \sin (\theta)=\frac{b}{c} \\ \sin (\theta)=\frac{9.4}{12.4} \\ \sin (\theta)=0.76 \end{gathered}[/tex]By definition
[tex]\tan (angle)=\frac{\text{ opposite side}}{\text{ adjacent side}}[/tex]From the picture
[tex]\begin{gathered} \tan (\theta)=\frac{b}{a} \\ \tan (\theta)=\frac{9.4}{8.09} \\ \tan (\theta)=1.16 \end{gathered}[/tex]Isolating θ from the previous equations:
[tex]\begin{gathered} \theta=\arccos (0.65)=49.46\text{ \degree}\approx49\text{ \degree} \\ \theta=\arcsin (0.76)=49.46\text{ \degree}\approx49\text{ \degree} \\ \theta=\arctan (1.16)=49.24\text{ \degree}\approx49\text{ \degree} \end{gathered}[/tex](The difference between the values is caused by rounding errors)
Simplify cot(t)/csc(t)-sin(t) to a single trig function
The single trig function that simplifies the function is sec(t)
How can we simplify the function?Trigonometry deals with the functions of angles and how they're applied.
Given cot(t)/csc(t)-sin(t)
since csc(t) = 1/sin(t) , we have:
[tex]\frac{ cot(t)}{csc(t)-sin(t)} = \frac{cot(t)}{\frac{1}{sin(t)} - sin(t) }[/tex]
[tex]\frac{ cot(t)}{csc(t)-sin(t)} = \frac{cot(t)}{\frac{1-sin^{2}(t) }{sin(t)} }[/tex]
since:
cos²(t) = 1 - sin²(t)
Therefore we have:
cot(t) / csc(t)-sin(t) = cot(t)/ cos²(t)/sin(t)
cot(t) / csc(t)-sin(t) = cot(t) / cos(t).cos(t)/sin(t)
Since cos(t) / sin(t) = 1/tan(t) = cot(t)
Therefore:
cot(t) / csc(t)-sin(t) = cot(t)/ cot(t)×cos(t)
cot(t) / csc(t)-sin(t) = 1/cos(t)
Since 1/cost = sec(t)
Finally, cot(t) / csc(t)-sin(t) is sec(t).
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Determine the value of b for which x = 1 is a solution of the equation shown.
2x + 14 = 10x + b
B=
The linear equation has the solution x = 1 only if the value of b is 6
For which value of b is x = 1 a solution?
Here we have the linear equation:
2x + 14 = 10x + b
If we replace x by 1 in that equation, we will get:
2*1 + 14 = 10*1 + b
2 + 14 = 10 + b
16 = 10 + b
To find the value of b such that x = 1 is a solution, we need to isolate b, to do so we need to subtract 10 in both sides.
16 - 10 = 10 + b - 10
6 = b
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Find the length of AB given that DB is a median of the triangle AC is 46
ANSWER:
The value of AB is 23
STEP-BY-STEP EXPLANATION:
We know that AB is part of AC, and that DB cuts into two equal parts (half) since it is a median, therefore the value of AB would be
[tex]\begin{gathered} AB=\frac{AC}{2} \\ AB=\frac{46}{2} \\ AB=23 \end{gathered}[/tex]A seamstress has three colours of ribbon; the red is 126cm, the blue is 196cm and the green
is 378cm long. She wants to cut them up so they are all the same length, with no ribbon
wasted. What is the greatest length, in cm, that she can make the ribbons?
Answer:
14cm is the greatest length
Step-by-step explanation:
Hi!
So the question is basically asking for the greatest common factor between each of these numbers (if I understood the question right so here we go) :
The GCF in this case is 14:
126 / 14 = 9
196 / 14 = 14
378 / 14 = 27
Please feel free to ask me any more questions that you may have!
and Have a great day! :)
Rectangle ABCD has vertex coordinates
A(1, -2), B(4, -2), C(4, -4), and D(1,
-4). It is translated 1 unit to the left and 1 3 units up. What are the coordinates
of B?
A vertex is a point on a polygon where two rays or line segments meet, the sides, or the edges of the object come together. Vertex is the plural form of vertices.
Response: C
What is a graph's vertex?A node of a graph, or one of the points on which the graph is defined and which may be connected by graph edges, is referred to as a "vertex" in computing.
For instance, a rectangle's four sides result in its four vertices.
Response: C . The coordinates are obtained by first subtracting 1 from 4 to obtain 3 and then adding 3 to -2 to obtain 1. (3, 1)
The vertex is the collective endpoint. Vertex, on the other hand, refers to the common terminal point where two rays converge to make an angle. In a similar manner, we must understand an angle's arm. The term "arm of an angle" refers to the two rays that unite to make an angle.
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numbers in order from greatest to least 1/5 0.12 0.17
1/5 = 0.2
the order is:
1/5
0.17
0.12
A tree casts you say shadow that is 9 feet long at the same time a person standing nearby casts a shadow that is 3 feet long if the person is five point feet tall how tall is the tree
we have that
Applying proportion
x/9=5.5/3
solve for x
x=9*(5.5/3)
x=16.5 ft
therefore
the answer is 16.5 ftWhich tool would be best to solve this problem?Pythagorean TheoremTriangle Angle Sum TheoremTangent RatioSine RatioCosine RatioUse that tool to solve for x. Show all work on the sketchpad or on your paper.
To get the value of x,
We use triangle sum theorem:
Triangle Sum Theorem:
The sum of all angles in a triangle is equal to 180 degrees.
In the triangle
We have 90 degree, 22 degree and one x
So,
x + 90 + 22 =180
x + 112 = 180
x = 180-112
x = 68 degree
Answer: x = 68
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided
From the given picture we can see
ACB is a right triangle at C
AC = b
CB = a
AB = c
Since mSince a = 5 ft
Then to find b and c we will use the trigonometry ratios
[tex]\begin{gathered} \sin A=\frac{a}{c} \\ \sin 60=\frac{5}{c} \end{gathered}[/tex]Substitute the value of sin 60
[tex]\begin{gathered} \sin 60=\frac{\sqrt[]{3}}{2} \\ \frac{\sqrt[]{3}}{2}=\frac{5}{c} \end{gathered}[/tex]By using the cross multiplication
[tex]\begin{gathered} \sqrt[]{3}\times c=2\times5 \\ \sqrt[]{3}c=10 \end{gathered}[/tex]Divide both sides by root 3
[tex]\begin{gathered} \frac{\sqrt[]{3}c}{\sqrt[]{3}}=\frac{10}{\sqrt[]{3}} \\ c=\frac{10}{\sqrt[]{3}} \end{gathered}[/tex]To find b we will use the tan ratio
[tex]\begin{gathered} \tan 60=\frac{a}{b} \\ \tan 60=\frac{5}{b} \end{gathered}[/tex]Substitute the value of tan 60
[tex]\begin{gathered} \tan 60=\sqrt[]{3} \\ \sqrt[]{3}=\frac{5}{b} \end{gathered}[/tex]Switch b and root 3
[tex]b=\frac{5}{\sqrt[]{3}}[/tex]The exact values of b and c are
[tex]\begin{gathered} b=\frac{5}{\sqrt[]{3}} \\ c=\frac{10}{\sqrt[]{3}} \end{gathered}[/tex]Simplify the expression using order of operation 9/g + 2h + 5, when g = 3 and h = 6
9/g + 2h + 5
When g = 3 and h = 6
First, replace the values of g and h by the ones given:
9/(3) + 2(6) + 5
9/3 + 2(6)+5
Then, divide and multiply:
3+12+5
Finally, add
20
The next algebra test is worth 100 points and contains 35 problems. Multiple-Choice questions are worth 2 points each and word problems are 7 points each. How many of each type equation are there?
Let
x ----->number of multiple-choice questions
y ----> number of word problems
so
we have
x+y=35 --------> equation 1
2x+7y=100 -----> equation 2
solve the system of equations
Solve by graphing
using a graphing tool
see the attached figure
therefore
x=29
y=6
number of multiple-choice questions is 29
number of word problems is 6
(4xy³y⁴)(5x²y) expand and simplify
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
(4xy³y⁴)(5x²y)
Step 02:
[tex](4xy^3y^4)(5x^2y)=(4xy^7)(5x^2y)=20x^3y^8^{}[/tex]This is the solution.
[tex]20x^3y^8^{}[/tex]Questlon 5 Refer to the figure. HJ I JE. HII IE. HJ HI J H E Complete the explanation to show triangle EJH is congruent to triangle EIH. The two triangles given are _____triangles. The leg and hypotenuse of triangle EJH are congrue hypotenuse of triangle EIH. By the ______ Theorem the third side ma triangles are congruent by the____ Triangle Congruence Theorem.choice 1.acute,obtuse or right angleschoice 2.corresponding parts of congruent triangles, pythagorean,or side-angle-side triangle congruence.choice 3. side-side-side, side-angle-side,or angle-side-angle
In the given figure, we have two triangles △EJH and △EIH
We are given the following information
[tex]\begin{gathered} \bar{HJ}\perp\bar{JE} \\ \bar{HI}\perp\bar{IE} \\ \bar{HJ}\cong\bar{HI} \end{gathered}[/tex]This means that these two triangles are "Right Triangles"
Therefore.
Choice 1 = right angles
When the hypotenuse and a leg of one right triangle are congruent to the hypotenuse and a leg of a second right triangle, then the triangles are congruent.
Therefore,
Choice 2 = side-angle-side triangle congruence
Choice 3 = side-angle-side
Answer: choice 1 -Right Angle
Choice 2 -Pythagorean
Choice 3- Side-Side-Side
Step-by-step explanation:other guy is completely wrong lol