The emission spectrum of the hydrogen atom shows that: c. Discrete emission lines at very specific wavelengths are observed, because only specific H atom energy levels are possible.
The emission spectrum of the hydrogen atom shows the specific wavelengths of light that are emitted when the electron in the hydrogen atom jumps from a higher energy level to a lower energy level. These wavelengths correspond to specific colors of light, and are unique to hydrogen.
The most well-known example is the Balmer series, which produces the visible lines in the hydrogen spectrum. This is used to identify the presence of hydrogen in stars and other astronomical objects.
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The newest bonanza for recycling scarce and toxic metals is to recover them from ________.
A. car batteries B. construction dump sites C. landfills from the 1960s D. e-wastes such as computers E. compact discs, LPs and 8-track tapes
The newest bonanza for recycling scarce and toxic metals is to recover them from car batteries.
Recycled aluminum items cost more than 10 times more than metal metal is shiny. Thanks to their shiny appearance, they can be used in jewelry and decorations. Gold and silver are especially used in jewelry. In the past, mirrors were made of shiny metals, such as silver.
Silver is a very good reflector. It reflects around 90% of the light that hits it. All modern mirrors have a thin metal coating. Metals are usually more difficult to cut. Their hardness varies from metal to metal. Some metals, such as sodium, potassium and magnesium, are easy to cut.
In danger, metals can be beaten into thinner plates. This function is called editable. Most metals are malleable. Gold and silver metals are the most ductile metals. They can be forged into very thin sheets. Thin aluminum foils are widely used for safe packaging of medicines, chocolates and food.
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How many equivalent resonance forms can be drawn for so2 without expanding octet on the sulfur atom (sulfur is the central atom)?.
Answer:
2
Explanation:
Resonance is a way of describing bonding in certain molecules or polyatomic ions by the combination of several contributing structures.
When we draw out the Lewis Structure for SO2 without expanding the octet, we see the two structures below.
Rank the following ions in order of decreasing radius: O2?,S2?,Se2?,Te2?, and Po2?.
Rank the following items in order of decreasing radius: Mg, Mg2+, and Mg2?.
The following ions contain the same number of electrons. Rank them in order of decreasing ionic radii.(Cs^+, I^-, La^3+, Sb^3-, Ba^2+, Te^2-)
Rank from largest to smallest radius. To rank items as equivalent, overlap them.
The following ions in order of decreasing atomic radius are:
1) [tex]Po^{2-} > Te^{2-} > Se^{2-} > S^{2-} > O^{2-}[/tex]
2) [tex]Mg^{2-} > Mg > Mg^{2+}[/tex]
3) [tex]Sb^{3-} > Te^{2-} > I^{-} > Cs^{+1} > Ba^{2+} > La^{3+}[/tex]
There are two primary trends in atomic radius. One atomic radius trend appears as you walk across the periodic table from left to right (doing so within a period), and the other trend appears as you move from the periodic table's top down (moving within a group).
In other words, as protons are added, the nucleus gains a higher positive charge, which in turn attracts the electrons more strongly and draws them in toward the nucleus of the atom. The radius of the atom decreases as the electrons are drawn inward toward the nucleus.
The atom gains one extra electron shell for every group down. The atomic radius grows when each additional shell is positioned farther from the atom's nucleus.
According to the question
for the first point all the atoms are in the period so the order will be,
[tex]Po^{2-} > Te^{2-} > Se^{2-} > S^{2-} > O^{2-}[/tex]
and in the second point Mg is losing electrons. more it lose the electrons, less will be the radius.
[tex]Mg^{2-} > Mg > Mg^{2+}[/tex]
and at last it undergoes both period and group trend.
[tex]Sb^{3-} > Te^{2-} > I^{-} > Cs^{+1} > Ba^{2+} > La^{3+}[/tex]
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A solution is made containing 20.8 g phenol (C6H5OH) in 455 g ethanol (CH3CH2OH).
Part A Calculate the mole fraction of phenol.
Part B Calculate the mass percent of phenol.
Part C Calculate the molality of phenol.
0.0219 is the phenol mole fraction. And 4.37% of the bulk is made up of phenol. 0.486 m is the molality of phenol. The number of molecules in a given component can be determined by looking at its mole fraction.
The sum of all the moles in the given combination, in a mixture. It's a way to show how concentrated a solution is. As a result, the mole fraction of all the components combined is always one.
mass/molar mass for phenol moles is 20.8 / 94.11 = 0.221.
455/46 = 9.89 moles of ethanol Moles of phenol equal moles of ethanol when divided by two and multiplied by three.
The formula for calculating the mass percent of phenol is: mass of phenol / total mass) x 100 = 20.8 / 20.8 + 455) x 100 = 4.37%.
Molality is calculated as 0.221 / 0.455 / 0.486m, or moles divided by solvent mass.
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The chemistry behind perfume
Chemistry is involved in the production of perfume since most of the ingredients used in perfumes are organic compounds. This includes the synthesis of molecules like essential oils, aromatic compounds, and other molecular compounds used to create different fragrance profiles. Fragrance molecules typically contain long hydrocarbon chains which produce a pleasant aroma when the perfume is applied. They also contain functional groups like alcohols and esters which contribute to the volatile properties of the fragrances. Additionally, some of the perfume fixatives contain natural organic compounds such as musk and ambergris for longer-lasting fragrances.
The chemistry of perfumes the preparation of a perfume basically includes the following components: denatured ethanol [tex] \bold{C_2H_6O}[/tex], essence or fragrance, fixative, propylene glycol [tex] \bold{C_3H_8O_2}[/tex], and distilled water[tex] \bold{H_2O}[/tex]. The fragrance, for its part, can be synthetic or natural.
the energy (kcalories) provided by one gram each of protein, fat, carbohydrate and alcohol is:
There are 4 calories per gram of carbohydrate, 4 calories per gram of protein, 9 calories per gram of fat and 7 calories per gram of alcohol.
What is calories?Calories are the amount of energy released when your body breaks down digests and absorbs food. The more calories a food has the more energy it can provide to your body. When you eat more calories than you need your body stores the extra calories as body fat.
Therefore when we eat and drink more calories than we use up our bodies store the excess as body fat. If this continues over time we may put on weight. As a guide an average man needs around 2,500kcal [10,500kJ]a day to maintain a healthy body weight.
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What can Isaiah conclude about identity of sample b
Answer:sample B is non metal
Explanation:
what is the ka of the amino acid glycine if it is 75.0% dissociated at ph = 10.08?
The Ka of the amino acid glycine is 2.49 * [tex]10^{-10}[/tex] . This is calculated using the Henderson-Hasselbalch equation.
initial 1 0 0
final 1-x x x
x = 0.75
1-x = 0.25
A buffer is a solution you add to another solution in order to balance its pH, its relative acidity or its alkalinity. To determine a buffer's pH--or extrapolate from its pH the concentration of any one of its components--you can make a series of calculations based on the Henderson-Hasselbalch equation, which is also known as the "buffer equation." We can use the buffer equation to determine the pH of an acidic buffer solution, given certain acid-base concentrations. The Henderson-Hasselbalch equation is as follows,
pH = pKa + log ( [A-] / [HA] )
Ka = 2.49 * [tex]10^{-10}[/tex]
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Combustion analysis of fluorene, a polycyclic aromatic hydrocarbon used to make dyes, plastics, and pesticides, produces 11.44 g CO2 and 1.80 g H2O. Calculate the empirical formula for fluorene.
Combustion analysis of fluorene, a polycyclic aromatic hydrocarbon used to make dyes, plastics, and pesticides, produces 11.44 g CO2 and 1.80 g H2O. The empirical formula of fluorene C₆H₄.
CₓHₐ + O2 → CO2 + H2O Since the combustion is complete, so the total mass of the reactants is equal to the total mass of the reactants Therefore, Mass of O2 = (17.9 + 9.14) – 5.9 = 21.14 grams Here, the empirical formula for the hydrocarbon is CₓHₐ. So, now we have to need to determine the number of moles of the O2, CO2, and H2O :- Mole of CO2 = 17.9/44 = 0.4068 Mole of H2O = 9.14/18 = 0.5078 Mole of O2 = 21.14/32 = 0.6606. The empirical formula for the compound containing uranium and fluorine is UF6. Explanation: The empirical formula of a compound represents the lowest whole number ratio of elements in the compound. This ratio is represented by subscripts in the formula. by this information, we can consider that combustion analysis of fluorene, a polycyclic aromatic hydrocarbon used to make dyes, plastics, and pesticides, produces 11.44 g CO2 and 1.80 g H2O. The empirical formula of fluorene C₆H₄.
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A student generates a plot of ln(k) vs ln[OH-].
The result yields a straight line with the equation: y = 1.01x + -0.92
According to this data, what is the order of the reaction in OH-, to the nearest whole number?
The order of the reaction is First Order with respect to the hydroxide ion (OH-) can be determined by examining the slope of the line generated in the plot of ln(k) vs ln[OH-].
Since the line's slope in this instance is 1.01, the reaction in question is first-order with regard to OH-. The power to which the concentration order of a reactant is elevated in the rate equation is referred to as the order of a chemical reaction.
The rate equation, a mathematical statement that connects the rate of the reaction to the concentrations of the reactants, is often used to explain the rate of a reaction. By measuring the rate of a reaction at various reactant concentrations and fitting the results to a rate equation, the order of a reaction can be experimentally determined.
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What is the acceleration of a 0.30-kilogram ball that is hit with a force of 50 N?
Answer:
0.006 [tex]m/s^{2}[/tex]
Explanation:
using the formula;
F = ma
force = mass x acceleration
a = m/F
a = 0.30/50
= 0.006 [tex]m/s^{2}[/tex]
can molecular interactions (like h-bonds, ionic bonds, and hydrophobic interactions) occur between substrates and the atoms of the enzyme's active site?
Yes ,molecular interactions (like h-bonds, ionic bonds, and hydrophobic interactions) occur between substrates and the atoms of the enzyme's active site
To create the enzyme-substrate complex, substrates attach to the enzyme's active site via hydrogen bonds, hydrophobic contacts, ionic bonds, brief covalent connections (Van der Waals' interactions), or a mixture of all of these. The study of biology, chemistry, and biochemistry all depend on the phenomenon of hydrophobicity. It is described as the interaction of low solubility nonpolar molecules or groups with water. Numerous water-related processes, such as complexation, surfactant aggregation, and coagulation, are impacted by hydrophobic interactions.These interactions are essential for the development and maintenance of proteins or biological membranes. The effect of ionic strength, solute size, and shape on hydrophobic interactions between pairs of nonpolar particles was examined in the current work.
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Which method of heat transfer is used in this cooler?
Answer: Convection
Explanation:
Convection is the transfer of heat from a surface by mean of a fluid such as air. Natural convection occurs as air is heated : it expands , rises, and is replaced by cooler air.
Convert 7.15 x 10^24 particles of NO₂ to moles.
7.15 x 10²⁴ particles of NO₂ equals 11.87moles.
A mole is defined as the amount of substance that contains 6.022 x 10²³ elementary particles (atoms, ions, molecules). 6.022 x 10²³ is known as Avogadro's number.
6.022 x 10²³ particles = 1 mole
According to the question,
The number of NO₂ particles = 7.15 x 10²⁴.
Using the equation, 6.022 x 10²³ particles = 1 mole
6.022 x 10²³ particles = 1 mole
1 particle of NO₂ = 1/6.022 x 10²³ mole
7.15 x 10²⁴ particles of NO₂ = (1/6.022 x 10²³) x 7.15 x 10²⁴
7.15 x 10²⁴ particles of NO₂ = 11.87 moles
Thus, 7.15 x 10²⁴ particles of NO₂= 11.87 moles.
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identify the 13c nmr chemical shift for each carbon atom in a molecule of 1-penten-3-one.
The principles governing 13 C NMR chemical shifts are the same as those governing 1 H, even though the normal range of chemical shifts is much wider (by a factor of about 20).
The carbons in tetramethylsilane (TMS), whose chemical shift is thought to be 0.0 ppm, serve as the chemical shift reference standard for 13 C. Typical 13 C-NMR chemical shiftsFormula for 1-Penten-3-one: C5H8O 84.1164 molecular weightA pentene molecule has five carbon atoms since the prefix pent- implies "five." The pentene molecule is an alkene, as indicated by the prefix -ene. A substance known as an alkene is an organic compound that has at least one C=C double bond. This indicates that two of the carbons in pentene are doubly bonded.
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TEXT ANSWER
How and why have scientists developed various models of the atom?
Practice
My scientific explanation is:
Your answer should include at least six complete sentences to explain the claim, evidence and reasoning.
Be sure to check your grammar and spelling.
Answer:Scientists used the model to make predictions. Sometimes the results of their experiments were a surprise and they did not fit with the existing model. Scientists changed the model so that it could explain the new evidence. The discovery of electrons. Atoms can be broken down into smaller parts.
Explanation:
Using a table that lists standard heats of formation, you can calculate the change in enthalpy for a given chemical reaction. The change in enthalpy is equal to.
A chemical reaction's change in enthalpy is equal to the ∆hf0 of products minus ∆hf0 of reactants.
Chemists can determine how much energy is consumed or created in a chemical process by measuring the change in enthalpy.
A reaction is exothermic, or one that generates heat in the environment, if the change in enthalpy is negative (i.e. 0).
The reaction is endothermic, meaning that it absorbs heat from the environment, if the change in enthalpy is positive (i.e. > 0).
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The complete question is
Using a table that lists standard heats of formation, you can calculate the change in enthalpy for a given chemical reaction. the change in enthalpy is equal to _____.
a) ∆hf0 of reactants minus ∆hf0 of products
b) ∆hf0 of products plus ∆hf0 of reactants
c) ∆hf0 of products divided by ∆hf0 of reactants
d) ∆hf0 of products minus ∆hf0 of reactants
what is the mole fraction of glucose (180.0 g/mol) in a 10.0% aqueous glucose solution?
0.01 is the mole fraction of glucose (180.0 g/mol) in a 10.0% aqueous glucose solution.
The example of the mole fraction. 2.82 g of glucose is dissolved in 30 g of water. The mole fraction of glucose in the solution is: An Aq. solution has urea and glucose in mass ratio 3:1 and water and glucose in 10:1 then mole fraction of glucose is. A solution is prepared by dissolving 5.64 g of glucose in 60 g of water. mole fraction is the ratio of number of moles of some element and to the number of moles of the whole solution and then we will get our desired mole fraction of the number of moles of an element to the number of moles to the solution. mole fraction has no dimensions, hence it is dimensionless. By this information, we can firmly consider that 0.01 is the mole fraction of glucose (180.0 g/mol) in a 10.0% aqueous glucose solution.
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A chemist wants to extract copper metal from copper chloride solution. the chemist places 0.25 grams of aluminum foil in a solution of 0.40 grams of copper (ii) chloride. a single replacement reaction takes place. what are the likely observations when the reaction stops? unbalanced equation: cucl2 + al → alcl3 + cu a. about 0.90 grams of copper (ii) is formed, and some aluminum is left in the reaction mixture b. about 0.20 grams of copper (ii) is formed, and some aluminum is left in the reaction mixture c. about 0.90 grams of copper (ii) is formed, and some copper chloride is left in the reaction mixture d. about 0.20 grams of copper (ii) is formed, and some copper chloride is left in the reaction mixture
A chemist wants to extract copper metal from copper chloride solution. the chemist places 0.25 grams of aluminum foil in a solution of 0.40 grams of copper (ii) chloride. a single replacement reaction takes place. About 0.20 grams of copper (II) is formed, and some aluminum is left in the reaction mixture. The correct answer is B.
Copper and aluminum make up the following balanced chemical equation:
3Al +3CuCl₂ ⇒ 3Cu + 3AlCl₂
Mass Al= 0.25 grams
Mass molar Al = 26.98 g
first we should calculate the moles of Al
moles Al = mass/ mass molar
moles Al = 0.25 grams/ 26.98 g
moles Al = 0.00926 mol
CuCl₂ has a mass of 0.40 grams.
CuCl₂has a molar mass of 134.5 grams.
Moles CuCl₂ = 0.00297 moles
By using the unitary technique, 3 moles of CuCl₂ will react with 2 moles of Al, resulting in a reaction between 0.00297 moles of CuCl₂ and 0.00198 moles of Al.
Since there is more Al present than is necessary, CuCl₂ would be the limiting reagent.
Cu = 0.00297 moles in quantity.
This Cu's mass is 0.1885 g of Cu.
As a result, the reaction mixture contains some aluminum and about 0.20 grams of copper (II).
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person above is right
explanation; because person above is right
MgCl2 has a theoretical van’t Hoff factor of 3 because it dissociates into three ions when dissolved in water. The measured value of the van’t Hoff factor for MgCl2 is typically no higher than 2.7. Explain why measured values of the van’t Hoff factors for ionic compounds are always lower than the theoretical values.
Magnesium iodide will dissociate into 1 mole of Mg2+ M g 2 + and 2 moles of I− . This means that it has a Van't Hoff factor of 3.
What is the vant Hoff factor of mgi2?MgCl2 dissociates into three ions when it dissolves in water, giving it a theoretical van't Hoff factor of 3. The van't Hoff factor for MgCl2 is normally tested at a value of no more than 2.7.
The van 't Hoff factor is virtually 1 for the majority of non-electrolytes dissolved in water. The van 't Hoff factor for the majority of ionic compounds dissolved in water is equal to the number of discrete ions in the substance's formula unit.
Only perfect solutions can claim this as ion pairing occasionally happens in solutions. The quantity of ions that develop during the dissociation of an ionic molecule is known as the van't Hoff factor. In the case of a non-ionizing molecule, the van't Hoff factor is 1.
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Which has the correct name-formula combination? A) Chlorine pentafluoride - CIF B) Diphosphorus pentoxide - P2O C) Carbon tetraiodide - CI4 D) Sulfur tetrafluoride - SF
Sulfur tetrafluoride - SF4 has the correct name-formula combination.
Which has the correct name-formula combination?The name of a compound is a combination of the names of its component elements, usually derived from the periodic table.In this case, the compound contains sulfur, which is a non-metal element, and fluorine, a halogen element.The subscript for sulfur is 4, and the subscript for fluorine is 4, so the overall formula for the compound is SF4.The prefixes are used to indicate the number of atoms in a molecule.In this case, the prefix "tetra" indicates that there are four atoms of sulfur, and the prefix "fluoro" indicates that there are four atoms of fluorine.The combination of the two elements and their respective subscripts gives us the name-formula combination of sulfur tetrafluoride - SF4.This combination is therefore the correct name-formula combination for this compound.To learn more about the correct name-formula combination refer to:
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The success of Bohr's model that demanded the scientific community's attention was its ability to: Select the correct answer below: calculate Planck's constant corroborate wave-particle duality explain the gold foil experiment calculate the Rydberg constant Choose the homogeneous mixtures from this list of substances.
The success of Bohr's model that demanded the scientific community's attention was its ability to: explain the gold foil experiment.
Gold foil experiment: Rutherford began a series of ground-breaking experiments in 1911 with the assistance of his associates Hans Geiger and Ernest Marsden, which would fundamentally alter the conventional concept of the atom. They sprayed incredibly thin sheets of gold foil with alpha particles that move quickly. Positively charged particles having a mass about equal to that of an atom of hydrogen, alpha particles are a type of naturally radioactive particle. A relatively small fraction of alpha particles were deflected after being bombarded with gold foil. In the nuclear model of the atom, the positively charged interior is compact and enclosed by an electron cloud.
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From where does the energy for the Earth’s water cycle come from?
Answer: the sun
Explanation:
The sun is what makes the water cycle work. The sun provides what almost everything on Earth needs to go—energy, or heat.
Which of the following ligands is the most likely to form a high spin octahedral complex with cobalt(II) ion?
A. CN-
B. H2O
C. NH3
D. F-
F- is the most likely ligand to form a high spin octahedral complex with cobalt(II) ion.
In coordination chemistry, a ligand is an ion or molecule that binds to a central metal atom to form a coordination complex. The bonding with the metal generally involves formal donation of one or more of the ligand's electron pairs, often through Lewis bases. F- is the most likely ligand to form a high spin octahedral complex with cobalt(II) ion. It is so because it is weak field ligand. Weak field ligands are ones that produce small splitting between the d orbitals and form high spin complexes.
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Write the orbital diagram for the valence electrons of Ne. Drag the appropriate labels to their respective targets. Labels can be used once, more than once, or not at all. S d 2 G3 G3 G3 G3 G2 G1 | G2 Gi 11 Write the orbital diagram for the valence electrons of I. Drag the appropriate labels to their respective targets. Labels can be used once, more than once, or not at all. р 2 G3 G3 G3 63 3 G2G1 G2 G1 5 11 Write the orbital diagram for the valence electrons of Sr. Drag the appropriate labels to their respective targets. Labels can be used once, more than once, or not at all. S a 2 11 G3 G3 G3 دن 5 G2 G1 11 11 Vrite the orbital diagram for the valence electrons of Ge. rag the appropriate labels to their respective targets. Labels can be used once, more than once, or not at all. р d 2 G3 G3 G3 G3 G2 G1 G2G1 4 11 1
electronic configuration of Ge is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p2. Thus, the orbital diagram of Ge is: G2 G1 | G2 | G3 G3 G3 G3 4 11 1
Ne:
The electronic configuration of Ne is 1s2 2s2 2p6. Thus, the orbital diagram of Ne is:
G2 G1 | G2 | G3 G3 G3 G3
I:
The electronic configuration of I is 1s2 2s2 2p6 3s2 3p6. Thus, the orbital diagram of I is:
G2 G1 | G2 | G3 G3 G3 G3 5
Sr:
The electronic configuration of Sr is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6. Thus, the orbital diagram of Sr is:
G2 G1 | G2 | G3 G3 G3 G3 11
Ge:
The electronic configuration of Ge is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p2. Thus, the orbital diagram of Ge is:
G2 G1 | G2 | G3 G3 G3 G3 4 11 1
Br:
The electronic configuration of Br is 1s2 2s2 2p6 3
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The hybridizations of nitrogen in NF3 and NH3 are __________ and __________, respectively. A) sp2, sp2 B) sp3, sp3 C) sp, sp3 D) sp2, sp3 E) sp3, sp
The nitrogen hybridizations in NF3 and NH3 are, respectively, sp3 and sp3.
Describe hybridizations.When two atomic orbitals combine, a new degenerate hybrid orbital with the same energy levels is created. This phenomenon is known as hybridization. Compared to non-hybridized orbitals, hybridization increases bond formation stability. We can forecast a molecule's form thanks to its hybridization.Hybridization contributes to the explanation of molecular structure because the angles between bonds are essentially equivalent to the angles between hybrid orbitals.The nitrogen is sp3 hybridised, and as a result, it has four sp3 hybrid orbitals. Two of the sp3 hybridised orbitals overlap with hydrogen-derived s orbitals to create the two N-H sigma bonds. One of the sp3 hybridised orbitals overlaps with a carbon sp3 hybridised orbital to produce the C-N sigma bond.To learn more about hybridization visit:
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When sulfuric acid is added to solid sodium chloride and the mixture is heated, hydrogen chloride gas is generated, leaving a residue of sodium sulfate
The balanced chemical equation for the reaction between sulfuric acid and sodium chloride to produce hydrogen chloride gas and sodium sulfate is:
2H₂SO₄ + 2NaCl -> 2HCl + Na₂SO₄
What is the equation about?The equation given above is:
Sulfuric acid + sodium chloride -> hydrogen chloride + sodium sulfate
Therefore, In this equation, sulfuric acid (H₂SO₄) is the acid and sodium chloride (NaCl) is the base. The acid donates protons (H+ ions) to the base, resulting in the production of hydrogen chloride gas (HCl) and a salt (Na₂SO₄).
The overall reaction is an example of an acid-base reaction, in which the acid and base react to produce a salt and a neutralization product (in this case, HCl).
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See full question below
When sulfuric acid is added to solid sodium chloride and the mixture is heated, hydrogen chloride gas is generated, leaving a solid residue of sodium sulfate. Give the balanced chemical equation for this reaction.
Draw the structure of the conjugate acid of acetone (CH3COCH3)
Given here is the resonance structure of the acetone c-h bond, (ch3)2c-o, which has a pka of 19.2.
What is acetone give an example?Acetone is a liquid solvent that can disintegrate and break down other materials. Products like varnish remover, paint remover, and nail polish remover all include acetone. Some people produce plastics, lacquers, and textiles using acetone as well. Acetone is a ketone, whereas alcohols belong to a separate class known as alcohols. Alcohols can be created from ketones (reacting with hydrogen or another reducing agent). Ketones can isomerize to unsaturated alcohols under specific circumstances.
What is the acetone used for?As a solvent, acetone can disintegrate or break down materials like paint and varnish. Because of this, it is a component of paint, varnish, and nail polish removers. Ammonia and acetone are the two substances that are most frequently used around the world to remove paint off metal surfaces.
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Please Help Quick ASAP Hurry Chemistry Unit 4 Review Sheet
N2(g) + 3H2(g) → 2NH3(g)
b. How many grams of NH3 result from this reaction?
Work:____________
Ans:_________
The amount, in grams, of [tex]NH_3[/tex] produced with 16.7 grams of nitrogen reacting would be 40.63 grams.
Stoichiometric problemThe balanced equation of the reaction shows that the mole ratio of nitrogen that reacts to ammonia produced is 1:2.
Recall that: mole = mass/molar mass. The molar mass of nitrogen is 14.
Thus, mole of 16.7 grams nitrogen = 16.7/14 = 1.192857 mol
From the mole ratio, the equivalent mole of ammonia that is produced would be: 1.192857 x 2 = 2.39 mol
Mass of ammonia = mole x molar mass. the molar mass of ammonia is 17 g/mol.
Mass of 2.39 mol ammonia = 2.39 x 17 = 40.63 grams
In other words, 40.63 grams of [tex]NH_3[/tex] will result from the reaction.
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Refer to the equation below of the reaction of Nitrogen with hydrogen. If 16.7 grams of Nitrogen react, then:
N2(g) + 3H2(g) → 2NH3(g)
a. How many moles of NH3 are produced?
what do the terms ""isobaric"" and ""isochoric"" mean in the context of the thermodynamics of a gas?
An isobaric method is a method going on at regular stress. The isochoric method is a chemical method that takes region in a thermodynamic machine beneath neath a regular extent.
An Isobaric method is a thermodynamic method taking region at regular stress. The time period isobaric has been derived from the Greek words “iso” and “bars” which mean the same stress. As such, regular stress is received whilst the extent is accelerated or contracted.
An isochoric method is one wherein the extent remains regular, and the temperature and stress extrude relative to every other. An isothermal method is one wherein the temperature remains regular, and the stress and extent extrude relative to every other.
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