STEP 1: Identify and Set Up
We have a trapezoid divided by a straight line that divides it assymetrically. We know from the all too famous geometric rule that adjacent angles in a trapezoid are supplementary. Mathematically, we can express thus:
[tex]100^o+<2+<3^{}=180^o=50^o+110^o+<1[/tex]Hence, from this relation, we can find our unknown angles.
STEP 2: Execute
For <1
[tex]\begin{gathered} 180^o=50^o+110^o+<1 \\ 180^o=160^o+<1 \\ \text{Subtracting 160}^o\text{ from both sides gives} \\ <1=180-120=60^o \end{gathered}[/tex]<1 = 60 degrees
For <2 & <3
We know from basic geometry that a transversal across two parallel lines gives a pair of alternate angles and as such, <1 = <3 = 60 degrees
We employ our first equation to solve for <2 as seen below:
[tex]\begin{gathered} 100^o+<2+<3^{}=180^o \\ 100^o+<2+60^o=180^o \\ 160^o+<2=180^o \\ \text{Subtracting 160}^{o\text{ }}\text{ from both sides gives:} \\ <2=180-160=20^o \end{gathered}[/tex]Therefore, <1 = <3 = 60 degrees and <2 = 20
Question 1 4 pts Match each quadratic expression that is written as a product with an equivalent expression that is expanded. A. (x + 2)(x + 6) [Choose ] [Choose ] B. (2x + 3)(x + 2) 2x^2 + 10x + 12 X^2 + 12x + 32 C. (X + 8)(x + 4) x^2 + 8x + 12 2x^2 + 12x + 16 D. (x + + 2)(2x + 6) [Choose ]
(x +2) (x +6) ------> x^2 +8X + 12
(2x + 8) (x +2) -------> 2x^2 +12x + 16
(x +8) (x+4) ------------> x^2 +12x +32
(x + 2) (2x+6) ----------> 2x^2 +10x +12
Look at the expression below.2h + y 4h^2_______ - _____9h^2-y^2 3h+yWhich of the following is the least common denominator for the expression?
Answer:
(3h+y)*(3h-y)
Step-by-step explanation:
We are given the following expression:
[tex]\frac{2h+y}{9h^2-y^2}-\frac{4h^2}{3h+y}[/tex]We want to find the LCD for:
9h²-y² and 3h + y.
3h+y is already in it's most simplified way.
9h²-y² , according to the notable product of (a²-b²) = (a-b)*(a+b), can be factored as:
(3h-y)*(3h+y).
The factors of each polynomial is:
3h + y and (3h-y)*(3h+y)
The LCD uses all unique factors(If a factor is present in more than one polynomial, it only appears once).
So the LCD is:
(3h+y)*(3h-y)
Which is option B.
given the function r(t)=t^2, solve for r(t)=4
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
r(t)=t^2
r(t)=4
t = ?
Step 02:
r(t)=4
t ² = 4
t = √4
t = 2
The answer is:
t = 2
Answer: t=2
Step-by-step explanation:
Because we know that for some value of t, r(t)= 4, and for ALL values of t, r(t)= t^2, then we know for some value of t, that t^2 = 4.
Based off of this information, we can take the square root of both sides, resulting in this equation.
t = [tex]\sqrt{4}[/tex]
This can be simplified.
t=2
i need help please and thank youthere are 2 pictures bc i couldn’t get it all in 1!
we have the system
y < -2x^2+4x-2
The solution for this inequality is the shaded area below the vertical dashed parabola
and
[tex]y\ge\frac{2}{3}x-3[/tex]the solution for this inequality is the shaded area above the solid line y=(2/3)x-3
therefore
the solution for this system of inequalities
Is the shaded area below the vertical dashed parabola y=-2x^2+4x-2 and above the solid line y=(2/3)x-3
see the attached figure to better understand the problem
Solve the inequality and write the solution using:
Inequality Notation:
The solution for the given inequality is x >7.
InequalityIt is an expression mathematical that represents a non-equal relationship between a number or another algebraic expression. Therefore, it is common the use following symbols: ≤ (less than or equal to), ≥ (greater than or equal to), < (less than), and > (greater than).
The solutions for inequalities can be given by: a graph in a number line or numbers.
For solving this exercise, it is necessary to find a number and a graph solution for the given inequality.
The given inequality is [tex]1-\frac{6}{7}x < -5[/tex] . Then,
Move the number 1 for the other side of inequality and simplify.[tex]-\frac{6}{7}x < -5 -1\\ \\ -\frac{6}{7}x < -6[/tex]
Multiply both sides by -1 (reverse the inequality )[tex]-\frac{6}{7}x < -6 *(-1)\\ \\ \frac{6}{7}x > 6[/tex]
Solve the inequality for x[tex]\frac{6}{7}x > 6\\ \\ 6x > 42\\ \\ x > \frac{42}{6} \\ \\ x > 7[/tex]
You should also show the results t > 7 in a number line. Thus, plot the number line. See the attached image.
Read more about inequalities here.
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which describes the solution of the inequality y>-15? a) solid vertical line through (0,-15) with shading to the left of the line. b) dashed vertical line through (0,-15) with shading to the left of line. c) solid horizontal line through (0,-15) with shaing below line. d) dashed horizontal line through (0,-15) with shaing above line.
The solution to the inequality y > - 15 is all values of y greater than -15. This means the number -15 itself is not included; therefore, the line is a dashed line that passes through (0, -15). Furthermore, the > sign implies that the shaded region is found above the dashed line. Hence, the solution to our inequality is a dashed horizontal line through (0, -15), with shading above the line.
Quinton will flip a coin and roll a die.What is the probability that he will flip "tails" and roll a "2
Answer:
there is a 50 percent chance he will land tails, and about a 33 percent chance he will rol a 2
Step-by-step explanation:
Each of the letters a through H has one of the 8 values listed. no 2 letters have the same value. The Simple arithmetic problems are clues for determining the value of each letter. Simply guess and check to find the values for letters a through H. You must use numbers listed below.
We have the following:
Let's start from the number C, which has two numbers that when adding it gives a number and subtracting two other numbers gives the same number C
C = 9, therefore:
[tex]\begin{gathered} F-D=9 \\ F=14 \\ D=5 \\ G+B=9 \\ G=3 \\ B=6 \\ 5+E=6\Rightarrow E=1 \\ 6+H=14\Rightarrow H=8 \\ A-9=8\Rightarrow A=17 \end{gathered}[/tex]Find the area of the yellow region. Round to the nearest tenth. 7.53cm
The figure shows a square inscribed in a circle of radius r = 7.53 cm.
The yellow region corresponds to the area of the circle minus the area of the square.
The area of a circle of radius r is:
[tex]A_c=\pi r^2[/tex]Calculating:
[tex]A_c=\pi(7.53\text{ cm})^2=178.13\text{ }cm^2[/tex]The radius of the circle is half the diagonal of the square. The diagonal of the square is:
d = 2 x 7.53 cm = 15.06 cm
The area of a square, given the diagonal d, is calculated as follows:
[tex]A_s=\frac{d^2}{2}[/tex]Calculating:
[tex]\begin{gathered} A_s=\frac{(15.06\text{ cm})^2}{2} \\ \\ A_s=113.40\text{ }cm^2 \end{gathered}[/tex]The required area is:
A = 178.13 - 113.40 = 64.73 square cm
helpppppppppp!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
A. y = -250x + 3750
B. $2125
Step-by-step explanation:
A.
(5, 2500), (7, 2000)
(x₁, y₁) (x₂, y₂)
y₂ - y₁ 2000 - 2500 -500
m = ----------------- = ---------------------- = ---------- = -250
x₂ - x₁ 7 - 5 2
y - y₁ = m(x - x₁)
y - 2500 = -250(x - 5)
y - 2500 = -250x + 1250
+2500 +2500
-------------------------------------
y = -250x + 3750
B.
y = -250x + 3750
y = -250(6.50) + 3750
y = -1625 + 3750
y = 2125
(6.50, 2125)
I hope this helps!
ava's family drove to disneyland for spring break. Her mom and dad shared the driving duties for a total of 24 hours. Her mom drove 75 miles per hour, and her dad drove 60 miles per hour. If they drove a total of 1,710 miles, how many hours did each person drive for?
Total driving time =24
Mom drove =75 mile per hours
Dad drove = 60 miles per hours
Total distance =1710
Let
[tex]\begin{gathered} \text{ mom driving time =}^{}t_1 \\ \text{dad driviving time=}^{}t_2 \\ \text{Mom driving distance =}x \\ \text{ So dad driving distance=}^{}1710-x \end{gathered}[/tex]Total time:
[tex]t_1+t_2=24[/tex]Formula:
[tex]\text{ Spe}ed=\frac{\text{ Distance}}{\text{ Time}}[/tex]For Ava's mom:
[tex]\begin{gathered} \text{Speed}=\frac{\text{ Distance}}{\text{ time}} \\ 75=\frac{x}{t_1} \\ x=75t_1^{} \end{gathered}[/tex]For Ava's dad:
[tex]\begin{gathered} \text{ Spe}ed=\frac{\text{ Distance}}{\text{ Time}} \\ 60=\frac{1710-x}{t_2} \\ 60t_2=1710-x \\ x=1710-60t_2 \end{gathered}[/tex]Put the value of "x" then:
[tex]\begin{gathered} x=75t_1 \\ x=1710-60t_2 \\ so\colon \\ 75t_1=1710-60t_2 \\ 75t_1+60t_2=1710 \\ 15(5t_1+4t_2)=15\times114 \\ 5t_1+4t_2=114 \end{gathered}[/tex]Solve the both eq then:
[tex]\begin{gathered} t_1+t_2=24 \\ 4t_1+4t_2=96 \\ 5t_1+4t_2=114 \\ \text{then:} \\ 5t_1-4t_1+4t_2-4t_2=114-96 \\ t_1=18 \\ \end{gathered}[/tex]So Ava's mom drive 18 hours
[tex]\begin{gathered} t_1+t_2=24 \\ 18+t_2=24 \\ t_2=24-18 \\ t_2=6 \end{gathered}[/tex]Ava's dad driving 6 houras
Find the volume of each rectangular prism. Round to the tenths.
Answer:
To find the volume of the given cuboid.
Length of the cuboid = 6.8 yd
Breadth of the cuboid = 4.5 yd
Height of the cuboid = 3.4 yd
We get,
Volume of a cuboid is,
[tex]=l\times b\times h[/tex]where l,b and h are the length, breadth and height respectively.
Substitute the values we get,
[tex]=6.8\times4.5\times3.4[/tex][tex]=104.04\text{ yd}^3[/tex]Answer is: Volume of the cuboid is 104.04 cubic yards.
The table shows the volume of water released by a dam over a certain period of time. Graph a line representing the data in the table, and find the slope and y-intercept of the line from the graph. Then enter the equation for the graph in slope-intercept form.
Okay, here we have this:
Considering the provided information. we are going to calculate the slope, and y-intercept of the line, so we obtain the following:
First we will calculate the slope using the following formula:
m=(y2-y1)/(x2-x1)
m=(80000-40000)/(10-5)
m=40000/5
m=8000
y-intercept:
y=mx+b
40000=(8000)5+b
40000=40000+b
b=0
Finally we obtain that the equation of the line is: y=8000x.
Let's graph the equation:
¿Por qué NO puede encontrar el punto medio de una línea?
Las líneas en un plano cartesiano son infinitas, no tienen un punto de inicio o final, por lo que no es posible determinar un punto medio para ellas.
A taxi service charges $3 for the first mile and then $2.25 for every mile after that. The farthest the taxi will travel is 35 miles. If X represents the number of miles traveled, and Y represents the total cost of the taxi ride, what is the most appropriate domain for the solutions?
Solution:
Given:
[tex]\begin{gathered} A\text{ taxi service charges \$3 for the first mile} \\ \text{ \$2.25 for every mile after that.} \\ \text{The farthest the taxi will travel is 35 miles.} \end{gathered}[/tex]Since x represents the number of miles traveled
y represents the total cost of the taxi ride
From the description, the number of miles the taxi will travel is between 0 and 35miles since 35 miles is the farthest it could go.
This means the domain which refers to the set of possible input values will be;
[tex]\begin{gathered} x>0\text{ because the service is charged once a certain distance is covered.} \\ \text{when no distance is covered, no charge is made.} \\ \text{Also,} \\ x\le35\text{ because the farthest is 35miles. This means the ta}\xi\text{ can not travel beyond 35miles.} \\ \\ \text{From the descriptions made, the domain will be:} \\ 0Therefore, the most appropriate domain for the solutions is;
[tex]0 The correct answer is OPTION B.A dog walker charges a flat rate of $6 per walk plus an hourly rate of $30. How much does the dog walkercharge for a 45 minute walk? Write an equation in function notation for the situation, and then use it tosolve the problem. Determine if the given statement is True or False.
hello
from the question given, the dog walker charges a flat rate of $6 and an extra $30 per hour.
we can write out an equation in function notation
let the number of hours be represented by x
[tex]f(x)=6+30x[/tex]now we can proceed to solve the cost of the walk for 45 minutes
[tex]\begin{gathered} 1hr=60\min s \\ \text{xhr}=45\min s \\ x=\frac{45}{60} \\ x=\frac{3}{4} \\ \text{therefore 45mins = 3/4 hours} \end{gathered}[/tex]now we can input the value into the equation and know the cost for 45 minutes walk
[tex]\begin{gathered} f(x)=6+30x \\ x=\frac{3}{4} \\ f(x)=6+30(\frac{3}{4}) \\ f(x)=6+22.5 \\ f(x)=28.5 \end{gathered}[/tex]from the calculation above, the cost of 45 minutes walk will cost $28.5
9 - 6 - 19 c) y - 12 OC p = b) y 24 c) = 9
x=70, y= -50 and x=80
1) Let's solve each equation, plugging in the given value for x
y=5x -300
a) y=50
y=5x -300 Plug y=50
50=5x -300 Add 300 to both sides
50+300=5x
350 = 5x Divide both sides by 5
x=70
b) x = 50
y=5x -300 Plug x=50
y=5(50) -300 Distribute the factor
y= 250 -300
y= -50
c) y=100
y=5x -300 Plug y=100
100 = 5x -300 Add 300 to both sides
400 = 5x
x =80
Hence, the answer is
x=70, y= -50 and x=80
Use the information given to find the equation of the line using the point-slope formula (y-y_1=m(x-x_1)). Then convert your answer to slope-intercept form (y=mx+b).(0,3) with a slope of 4The point slope form is (y-Answer)=Answer(x-Answer)Converting it to slope intercept form gives us y=Answerx+Answer
we have
m=4
point (0,3)
y-y1=m(x-x1)
substitute given values
y-3=4(x-0) ----> equation in point slope formConvert to slope-intercept form
y=mx+b
y-3=4x
adds 3 both sides
y=4x+3 ----> equation in slope-intercept formIf 340 grams of a substance are present initially and 50 years later only 170 grams remain, how much of the substance will be present after 120 years?Round to the nearest tenth of a graim.grams
Given -
Substance present initially = 340 grams
Substance present 50 years later = 170 grams
To Find -
How much of the substance will be present after 120 years =?
Step-by-Step Explanation -
Since the substance was reduced to half of what it is initially in 50 years.
So,
The half-life time of the substance = 50 Years.
It means that every 50 years, the substance will reduce to half of its quantity.
And, we know the formula:
[tex]\text{ A = S\lparen}\frac{1}{2}\text{\rparen}^{\frac{t}{h}}[/tex]Where,
A = the remaining amount of Substance =?
S = the amount of Substance you start with = 340grams
t = the amount of time in years = 120 years
h = the half-life time = 50 years
Simply putting the values, we get:
[tex]\begin{gathered} A\text{ = 340}\times(\frac{1}{2})^{\frac{120}{50}} \\ \\ A\text{ = 17\lparen}\frac{1}{2}\text{\rparen}^{2.4} \\ \\ A\text{ = 17}\times(0.5)^{2.4} \\ \\ A\text{ = 17}\times0.1894 \\ \\ A\text{ = 3.22 gram} \end{gathered}[/tex]Final Answer -
The substance that will remain after 120 years = 3.22 gram
f(a)=92.39 and the average rate of change of f over the interval from x=a to x=a+266 is 0.16. What is the value of f(a+266)?f(a+266)=
Average rate is f(a+266)-f(a))/266
so f(a+266) equals (0.16 x 266) + f(a)
f (a+266)= (0.16 x 266) + 92.39
N8) solve the system using substitution method and then graph the equations.2x - 4y = -23x + 2y = 3-
Solution
Given:
2x - 4y = -2
3x + 2y = 3
Substitution method
[tex]\begin{gathered} From\text{ 3x+2y=3} \\ 3x=3-2y \\ x=\frac{3-2y}{3} \end{gathered}[/tex][tex]\begin{gathered} Substitute\text{ }x=\frac{3-2y}{3}\text{ into the first equation} \\ 2x-4y=-2 \\ 2(\frac{3-2y}{3})-4y=-2 \\ \frac{6-4y}{3}-4y=-2 \\ Multiply\text{ }trough\text{ by 3} \\ 6-4y-12y=-6 \\ 6-16y=-6 \\ -16y=-6-6 \\ -16y=-12 \\ y=\frac{-12}{-16} \\ y=\frac{3}{4} \end{gathered}[/tex][tex]\begin{gathered} Substitute\text{ y=}\frac{3}{4}\text{ into }x=\frac{3-2y}{3} \\ x=\frac{3-2(\frac{3}{4})}{3}=\frac{3-\frac{3}{2}}{3}=\frac{\frac{6-3}{2}}{3}=\frac{\frac{3}{2}}{3} \\ x=\frac{3}{6} \\ x=\frac{1}{2} \end{gathered}[/tex][tex]Thus,\text{ x=}\frac{1}{2},y=\frac{3}{4}[/tex]Graphical method:
Plot the graph of the two equations on the same graph
The point of intersection of the two graphs gives the solution to the system of equations
The point of intersection is (0.5, 0.75)
Which in fraction gives (1/2, 3/4)
Thus. x = 1/2, y= 3/4
2. A wooden cube with volume 64 is sliced in half horizontally. The two halves are then glued together to form a rectangular solid which is not a cube. What is the surface area of this new solid? A.128 B. 112 C. 96 D. 56
we have that
the volume of the cube is equal to
V=b^3
64=b^3
b^3=4^3
b=4 unit
see the attached figure
the surface area of the new figure is equal to
SA=2B+PH
where
B is the area of the base
P is the perimeter of the base
H is the height
we have
B=4*8=32 unit2
P=2(4+8)=24 unit
H=2 unit
so
SA=2(32)+24*2
SA=64+48
SA=112 unit2
the answer is option Bpls help. i dont get it
Answer:
hey what don't u get? u didn't show the question
For each ordered pair, determine whether it is a solution to the system of equations. 7x - 4y=8 -2x+3y=7 Is it a solution? (x, y) Yes No (0, -2) a (-9,-6) (4,5) (7.7)
7x - 4y = 8 (eq. 1)
-2x + 3y = 7 (eq. 2)
Isolating y from equation 1:
-4y = 8 - 7x
y = 8/(-4) - 7/(-4)x
y = -2 + 7/4x
Isolating y from equation 2:
3y = 7 + 2x
y = 7/3 + 2/3x
Given that the slopes of the equations are different, then there is a solution, which can be found as follows,
[tex]\begin{gathered} -2+\frac{7}{4}x=\frac{7}{3}+\frac{2}{3}x \\ \frac{7}{4}x-\frac{2}{3}x=\frac{7}{3}+2 \\ \frac{^{}_{}7\cdot3-2\cdot4}{4\cdot3}x=\frac{7+3\cdot2}{3} \\ \frac{13}{12}x=\frac{13}{3} \\ x=\frac{13}{3}\cdot\frac{12}{13} \\ x=4 \end{gathered}[/tex]Replacing x = 4 into one of the equations, we get:
[tex]\begin{gathered} y=-2+\frac{7}{4}x \\ y=-2+\frac{7}{4}\cdot4 \\ y=-2+7 \\ y=5 \end{gathered}[/tex]The solution is (4,5)
To check if an ordered pair is a solution, we have to replace the x-coordinate and the y-coordinate of the pair into the equation, as follows:
(0, -2)
7(0) - 4(-2) = 8
8 = 8
-2(0) + 3(-2) = 7
-6 ≠ 7
Given that the second equation is not satisfied, then (0, -2) is not a solution
(-9, -6)
7(-9) - 4(-6) = 8
-81 + 24 ≠ 8
-2(-9) + 3(-6) = 7
18 - 18 ≠ 7
Given that the equations are not satisfied, then (-9, -6) is not a solution
(7,7)
7(7) - 4(7) = 8
49 - 28 ≠ 8
-2(7) + 3(7) = 7
-14 + 21 = 7
Given that the first equation is not satisfied, then (7, 7) is not a solution
If the given is -3x+20=8 What should the subtraction property of equality be?
Given the equation
[tex]-3x+20=8[/tex]To apply the subtraction property of equality, we subtract 20 from both sides.
[tex]-3x+20-20=8-20[/tex]The graphs depict IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15 (as on the Wechsler IQ test).
a.find the Z score. Write that answer to the 2nd decimal place.
b. solve for x
The required Z-score with a value of 120 would be 1.33.
What is Z -score?A Z-score is defined as the fractional representation of data point to the mean using standard deviations.
The given graph depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15.
As per the given information, the solution would be as
ц = 100
σ = 15
X = 120 (consider the value)
⇒ z-score = (X - ц )/σ₁
Substitute the values,
⇒ z-score = (120 - 100)/15
⇒ z-score = (20)/15
⇒ z-score = 1.33
Thus, the required Z-score with a value of 120 would be 1.33.
Learn more about the z-score here:
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I inserted a picture of the question Please don’t ask tons of questions. & please state whether it’s a b c or d
As given by the question
There are given that the graph of the triangle.
Now,
According to the properties,
If the point (x, y) or (-x, y) rotated about the origin by the angle of 360 degrees.
That means,
There is no difference between rotating 360 degrees clockwise or anti-clockwise around the origin.
Then,
From the vertices of the triangle ABC is:
[tex]\text{A is (-6, 3), B is (-5, 7) and C is (-4, 3).}[/tex]Since the triangle map onto itself
[tex]\begin{gathered} A=A^{\prime} \\ B=B^{\prime} \\ C=C^{\prime} \end{gathered}[/tex]So, the triangle is rotated 360 degrees about the origin
Hence, the correct option is D.
For the given f(x), solve the equation f(x)=0 analytically and then use a graph of y=f(x) to solve the inequalities f(x)<0 and f(x)≥0. f(x)=ln(x+3)(1) What is the solution of f(x)=0?(2) What is the solution of f(x)<0?(3) What is the solution of f(x)≥0?
Explanation:
f(x) is a logarithmic function. Logarithmic functions are zero when the argument is 1:
[tex]\begin{gathered} f(x)=\ln (x+3)=0 \\ x+3=1 \\ x=1-3 \\ x=-2 \end{gathered}[/tex]For greater values, the function is positive and for less values the function is negative.
Answers:
(1) x = -2
(2) x < -2. In interval notation x:(-∞, -2)
(3) x ≥ -2. In interval notation x:[-2, ∞)
Write a numerical expression for the word expression.The product of 2 groups of 7
The given statement is the product of 2 groups of 7.
This statement can be expressed as
[tex]7\cdot7[/tex]Where each seven represent one group.
I need help simplify each expression look for the terms first
8k + 3 +4k
________________
First, add the k
8k + 4k = (8+4) k = 12 k
________________
you add if there are other variables or numbers
3
________________
12k + 3
Do you have any questions regarding the solution?