The function g is defined as follows for the domain given g(x) = 3x - 2 , omain = \{- 2, - 1, 0, 1\} Write the range of g using set notation. Then graph g
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Given: The function below
[tex]\begin{gathered} g(x)=3x-2 \\ Domain:\lbrace-2,-1,-0,1\rbrace \end{gathered}[/tex]To Determine: The range and the graph of g
Solution
The range is as given below
[tex]\begin{gathered} x=-2 \\ g(-2)=3(-2)-2=-6-2=-8 \\ x=-1 \\ g(-1)=3(-1)-2=-3-2=-5 \end{gathered}[/tex][tex]\begin{gathered} x=0 \\ g(0)=3(0)-2=0-2=-2 \\ x=1 \\ g(1)=3(1)-2=3-2=1 \end{gathered}[/tex]Hence, the range is
{-8, -5, -2, 1}
Let us form a table showing the domain(x) and the range (g(x))
Let us use the table to plot graph of the domain(x) against the range(g(x)) as below
Related Questions
what do I do to compute the exact average of the fractions, in decimal form?
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Average is computed as follows:
[tex]\begin{gathered} \text{Avg=}\frac{\text{ sum of terms}}{\text{ number of terms}} \\ \text{Avg}=\frac{5+0.2+2}{3} \\ \text{Avg}=\frac{7.2}{3} \\ Avg=2.4 \end{gathered}[/tex]A. What is the common ratio of the pattern?B. Write the explicit formula for the pattern?C. If the pattern continued how many stars would be in the 11th set?
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Given:
The sequence of number of stars is 2,4,8,16
a) To find the common ratio of the pattern.
[tex]\begin{gathered} \text{Common ratio=}\frac{2nd\text{ term}}{1st\text{ term}} \\ r=\frac{4}{2} \\ r=2 \end{gathered}[/tex]Hence the common ratio is 2.
b) To find the explicit formula for the pattern.
The general for a geometric progression sequence is,
[tex]a_n=a_1(r)^{n-1}_{}_{}[/tex]Hence, the formula for the above pattern will be,
[tex]a_n=2(2)^{n-1}[/tex]c) To find the number of stars in 11th set.
Substitute n=11 in the explicit formula of the pattern.
[tex]\begin{gathered} a_{11}=2(2)^{11-1} \\ a_{11}=2(2)^{10} \\ a_{11}=2(1024) \\ a_{11}=2048 \end{gathered}[/tex]Hence, the number of stars in 11th set will be 2048.
You are given the equation 12 = 3x + 4 with no solution set. Part A: Determine two values that make the equation false. Part B: Explain why your integer solutions are false. Show all work.
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[tex]12=3x+4 \\ \\ 8=3x \\ \\ x=8/3[/tex]
So, two integer values are 1 and 2 since they are not the solution to the equation.
a standard Normal distribution, what percentage of observationnd the z-table here.4.95%5.48%6.06%95.05%
Answers
SOLUTION:
Case: Z-scores and probabilities
Given: z-score of standard normal distribution, z= 1.65
Required: To get the percentage of observation
Method: We will be reading it off the z-score table
Step 1: First we see what the table looks like
Step 2: From the table, we trace 1.65 by looking at 1.6 on the column title and 0.05 on the row title
Step 3: We observe the value is 0.4505
This translates to 45.05%.
However, we are interested in the values above the 45.05%. So everything from the left of that line to the 50th percentile is 45.05% of the populations. In addition to that you have another 50% of the people below the 50th percentile. That's a total of 95.05% below this z score
To get the z-score above this, we do:
1 - 0.9505
P(> z) = 0.0495 or 4.95%
Final answer:
A) The answer is 4.95%
how would u decide if 3/5 or 59% is greater?
Answers
SOLUTION
Step 1 : One of the easiest ways to determine which one of the quantities is greater is by expressing the quantities as a decimal.
[tex]\begin{gathered} \frac{3}{5}\text{ = 0.6} \\ \\ 59\text{ \% = 0.59} \end{gathered}[/tex]Step 2: From the two quantities expressed as decimals, we can see that :
[tex]\frac{3}{5}\text{ is greater.}[/tex]CONCLUSION :
[tex]\frac{3}{5}\text{ is greater.}[/tex]how does the common ratio and ratio of the perimeters of FDE to CAB compare
Answers
Answer
The common ratio and the ratio of the perimeters of the two triangles are exactly the same (2/3).
Explanation
The common ratio is obtained by expressing corresponding sides as a fraction of each other.
The common ratio for this triangles = (8/12) = (6/9) = (12/18) = (2/3)
Perimeter is expressed as the sum of all the exterior dimensions of a figure.
For the first figure, Perimeter = 8 + 6 + 12 = 26 inches
For the second figure, Perimeter = 12 + 9 + 18 = 39 inches
Ratio of perimeters = (26/39) = (2/3)
Hope this Helps!!!
jamals lawn is shaped like a square with an area of 224.9ft2 .which measurement is closest to the side length of his lawn in feet
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We use the formula for the area "A" of a square with equal sides of length "l":
[tex]A=l^2[/tex]Since we know the value of the area is:
[tex]A=224.9ft^2[/tex]We substitute that value into the formula for the area:
[tex]224.9ft^2=l^2[/tex]Next, we take the square root of both sides of the equation:
[tex]\sqrt[]{224.9ft^2}=\sqrt[]{l^2}[/tex]On the right side, the exponent and the square root will cancel, and we will get "l", and on the left side, we calculate the square root:
[tex]14.99ft=l[/tex]Which can be rounded to the closest value, that is 15 ft.
Answer: 15 feet
Find the (x , y) coordinate(s) of any hole(s) in h( x ). If there is none, write “n/a”.Round to two decimals.
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The hole appears in the rational function when the numerator and the denominator have the same zeroes
Since the rational function is
[tex]h(x)=\frac{x+7}{x^2-49}[/tex]Factorize the denominator
[tex]x^2-49=(x+7)(x-7)[/tex]The rational function h(x) is
[tex]h(x)=\frac{x+7}{(x+7)(x-7)}[/tex]Since (x + 7) is in both numerator and denominator
Then there is a hole at x + 7 = 0
Let us find the value of x
[tex]\begin{gathered} x+7=0 \\ x+7-7=0-7 \\ x=-7 \end{gathered}[/tex]The whole is at x = -7
Then simplify the fraction to find the value of y at x = -7
[tex]h(x)=\frac{(x+7)}{(x+7)(x-7)}[/tex]Cancel the bracket (x+7) up by the same bracket down
[tex]h(x)=\frac{1}{x-7}[/tex]Substitute x by -7
[tex]\begin{gathered} h(-7)=\frac{1}{-7-7} \\ h(-7)=\frac{1}{-14} \\ y=-\frac{1}{14} \end{gathered}[/tex]The hole is at (-7, -1/14)
describe the center and spread of the data using the more appropriate status either the mean median range interquartile range or standard division
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2064 is divisible by 2, 4 and 8 true or false
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Explanation:
2064/2 is 1032
1032/2 is 258
And 258 is divisible by 2 so 2 and 2x2 and 2x2x2.
One evening 1400 concert tickets were sold for the Fairmont Summer Jazz Festival. Tickets cost $30 for covered pavilion seats and $20 for lawn seats. Total receipts were $32,000. Howmany tickets of each type were sold?How many pavilion seats were sold?
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Let p be the number of pavilion seats and l be the number of lawn seats. Since there were sold 1400 tickets, we can write
[tex]p+l=1400[/tex]and since the total money was $32000, we can write
[tex]30p+20l=32000[/tex]Then,we have the following system of equations
[tex]\begin{gathered} p+l=1400 \\ 30p+20l=32000 \end{gathered}[/tex]Solving by elimination method.
By multiplying the first equation by -30, we have an equivalent system of equation
[tex]\begin{gathered} -30p-30l=-42000 \\ 30p+20l=32000 \end{gathered}[/tex]By adding these equations, we get
[tex]-10l=-10000[/tex]then, l is given by
[tex]\begin{gathered} l=\frac{-10000}{-10} \\ l=1000 \end{gathered}[/tex]Now, we can substitute this result into the equation p+l=1400 and obtain
[tex]p+1000=1400[/tex]which gives
[tex]\begin{gathered} p=1400-1000 \\ p=400 \end{gathered}[/tex]Then, How many tickets of each type were sold? 400 for pavilion seats and 1000 for lawn seats
How many pavilion seats were sold? 400 tickets
can you help with this question please
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We need to give the steps for proving the corresponding angles theorem for parallel lines crossed by a transverse line.
Westart with the
p || q as Given info
Next we use that
< 1 = <7 due to internal alternate angles among parallel lines
< 7 = <5 due to angles opposed by vertex
<1 = <5 due to transitive property <1 = <7 = <5
10 ftA4 ftThe following are the dimension of four rectangles. Which rectangle has the same area as the triangle above?a 1.6 ft by 25 ftC. 3.5 ft by 4 ftb. 5 ft by 16 ftd. 0.4 ft by 50 ft
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step 1: Find the area of the triangle
The area of the triangle given is:
[tex]\begin{gathered} \text{Area = }\frac{1}{2}\times base\times height \\ =\frac{1}{2}\times4\times10 \\ =20ft^2 \end{gathered}[/tex]step 2: Find the dimension of rectangles that will give the same area as the triangle
The area of a rectangle is given by:
[tex]\text{Area}=\text{ length x width}[/tex][tex]\begin{gathered} \text{ option a: }1.6ftx25ft=40ft^2 \\ \text{option b: 5 ft x 16 ft =}80ft^2 \\ \text{option c: }3.5ftx4ft=14ft^2 \\ \text{option d: }0.4\text{ ft x 50 ft=}20ft^2 \end{gathered}[/tex]Therefore, the dimension of the rectangle with the same area as the triangle is
[tex]0.4\text{ ft}\times50\text{ ft}[/tex]OptionD is correct
what is the geometric sequence of 2 4
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an = ar^ (n- 1)
for n = 3 (3rd term)
r = common ratio = 4/ 2 = 2
a3 = 2 (2) ^ (3-1)
a3 = 2 (2)^2
a3 = 2 (4)
a3 = 8
n= 4 (4th term)
a4 = 2 (2)^(4-1)
a4 = 2 (2)^3
a4 = 2 (8)
a4 = 16
2, 4 , 8 , 16
what is the area of the regular 15-gon with radius 12mm?
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The regular pentagon can divide into 5 congruent isosceles triangles
The equal sides of each triangle have length r and vertex angle of measure 72 degrees
Then we will use the sine rule of the area to find the area of each triangle, then multiply it by 5 to get the area of the pentagon
Since the radius is 7mm, then
r = 7
[tex]A=5\times\frac{1}{2}\times r\times r\times sin72[/tex]Substitute r by 7
[tex]\begin{gathered} A=5\times\frac{1}{2}\times7\times7\times sin72 \\ \\ A=116.5044232\text{ mm}^2 \end{gathered}[/tex]Round it to the nearest whole number
A = 117 mm^2
The area of the pentagon is 117 mm^2
determine whether the given by binomial is a factor of the polynomial p(x) . If so, find the remaining factors of p(x).
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The given binomial is a factor of the polynomial p(x) with remaining factors of (x + 1)(x - 1).
What is termed as the factors of polynomial?Factorisation is the process of determining the factors of a given value as well as mathematical expression. Factors are integers which are multiplied together to create the original number.For the given question.
The polynomial is given as; x³ + 2x² -x - 2.
The binomial is given as; (x +2).
The, to get the remainder, divide the polynomial with the binomial.
= (x³ + 2x² - x - 2)/ (x +2)
Taking x² common from the first two terms of the numerator and (-1) from the last two terms.
= x²(x + 2) - (x + 2)/ (x +2)
Taking (x + 2) common from two terms.
= (x + 2)(x² - 1)/(x + 2)
Cancel (x + 2) from both.
= (x² - 1)
Now use the identity to open the square.
(a² + b² ) = (a + b) (a - b)
= (x + 1)(x - 1).
Thus, the given binomial is a factor of the polynomial p(x) with remaining factors of (x + 1)(x - 1).
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The correct question is-
Determine whether the given binomial is a factor of the polynomial p(x).
If so, find the remaining factors of p(x).
p(x) = x³ + 2x² -x - 2 ; (x +2)
Answer:
a
Step-by-step explanation:
Describe 4 types of Quadrilaterals
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Answer:
Parallelograms, Squares, Rectangles, and Rhombuses
Step-by-step explanation:
how do you find the sale price of the item if original price $71 and mark down to 34% the sale price is
Answers
Answer:
The sale price is $46.86
Explanation:
Given an original price of $71, and a markdown of 34%
The sale price is:
$71 - (34% of $71)
= $71 - (0.34 * $71)
= $71 - $24.14
= $46.86
Answer:
The sale price is $46.86
Explanation:
Given an original price of $71, and a markdown of 34%
The sale price is:
$71 - (34% of $71)
= $71 - (0.34 * $71)
= $71 - $24.14
= $46.86
The mean height of women in a country (ages 20-29) is 63.6 inches. A random sample of 70 women in this age group are selected. What is the probability that the mean height for the sample is greater than 64 inches?Assuming sigma= 2.53 inches
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We have a mean of 63.6 inches and a standard deviation of 2.53 inches. We want to find the probability for our random sample to have a greater mean than 64 inches. We can do that by finding the probability of getting women higher than 64 inches in the original group. To do that, we're going to use a z-table.
First, let's convert 64 inches to a z-score:
[tex]\begin{gathered} z(64)=\frac{64-\mu}{\sigma/\sqrt[]{n}}=\frac{64-63.6}{2.53/\sqrt[]{70}}=\frac{0.4\sqrt[]{70}}{2.53}=1.32278265065\ldots \\ z(64)\approx1.32 \end{gathered}[/tex]Using a right z-table, we have
This z-table gives us the area between the middle of the bell curve and our desired value.
This means, the probability of getting a sample higher than our value, will be 0.5 minus the probability given by the z-table.
[tex]0.5-0.4066=0.0934[/tex]Then, we have our result.
[tex]P(\bar{x}>64)=0.0934[/tex]Abdul will rent a car for a day. The rental company offers two pricing options: Option A and Option B. For each pricing option, cost (in dollars) depends on miles driven, as shown below.
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From the graph, we are to determine the following:
(a) We are to find the option that costs less if Abdul drives 300 miles of the rental car and also how much less is it from the other option.
Option A: when x = 300, y = 140
Option B: when x = 300, y = 120
So the difference is:
140 - 120 = 20
So the option that costs less is B
And it costs $20 lesser than option A
(b) For what number of miles does the option costs the same and if Abdul drives less than that amount, what option cost more.
Option A: when x = 100, y = 60
Option B: when x = 100, y = 60
Therefore, the number of miles where the options cost the same is 100 miles.
If Abdul drives less than the amount:
That is x < 100, the B > A,
Which means, if Abdul drives less than 100 miles, Option B, costs more.
Answer For Brainiest!
What 3D Objects' do EACH Net Make?
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Looking at the 4th net, we see it has what seems to be 4 squares in a line. And two of them are each one united into another square.
Then, when we join the left side of the left square and the right side of the right square, we obtain a 3D object with 4 square faces, and 2 empty faces also in the form of a square.
After that, we can fold down the upper square face, and fold up the other one.
We will get the following 3D object, that is a cube:
Therefore, the 4th net makes a cube.
Andre and Elena are each saving money, Andre starts with 100 dollars in his savings account and adds 5 dollars per week, Elena starts with 10 dollars in her savings account and adds 20 dollars each week.After 4 weeks who has more money in their savings account?? Explain how you know.After how many weeks will Elena and Andre have the same amount of money in their savings account? How do you know?
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We can model each savings account balance in function of time as a linear function.
Andre starts with $100 and he adds $5 per week. If t is the number of weeks, we can write this as:
[tex]A(t)=100+5\cdot t[/tex]In the same way, as Elena starts with $10 and saves $20 each week, we can write her balance as:
[tex]E(t)=10+20\cdot t[/tex]We can evaluate their savings after 4 weeks (t=4) as:
[tex]\begin{gathered} A(4)=100+5\cdot4=100+20=120 \\ E(4)=10+20\cdot4=10+80=90 \end{gathered}[/tex]After 4 weeks, Andre will have $120 and Elena will have $90.
We can calculate at which week their savings will be the same by writing A(t)=E(t) and calculating for t:
[tex]\begin{gathered} A(t)=E(t) \\ 100+5t=10+20t \\ 5t-20t=10-100 \\ -15t=-90 \\ t=\frac{-90}{-15} \\ t=6 \end{gathered}[/tex]In 6 weeks, their savings will be the same. We know it beca
What is the row echelon form of this matrix?
Answers
The row echelon form of the matrix is presented as follows;
[tex]\begin{bmatrix}1 &-2 &-5 \\ 0& 1 & -7\\ 0&0 &1 \\\end{bmatrix}[/tex]
What is the row echelon form of a matrix?The row echelon form of a matrix has the rows consisting entirely of zeros at the bottom, and the first entry of a row that is not entirely zero is a one.
The given matrix is presented as follows;
[tex]\begin{bmatrix}-3 &6 &15 \\ 2& -6 & 4\\ 1&0 &-1 \\\end{bmatrix}[/tex]
The conditions of a matrix in the row echelon form are as follows;
There are row having nonzero entries above the zero rows.The first nonzero entry in a nonzero row is a one.The location of the leading one in a nonzero row is to the left of the leading one in the next lower rows.Dividing Row 1 by -3 gives:
[tex]\begin{bmatrix}1 &-2 &-5 \\ 2& -6 & 4\\ 1&0 &-1 \\\end{bmatrix}[/tex]
Multiplying Row 1 by 2 and subtracting the result from Row 2 gives;
[tex]\begin{bmatrix}1 &-2 &-5 \\ 0& -2 & 14\\ 1&0 &-1 \\\end{bmatrix}[/tex]
Subtracting Row 1 from Row 3 gives;
[tex]\begin{bmatrix}1 &-2 &-5 \\ 0& -2 & 14\\ 0&2 &4 \\\end{bmatrix}[/tex]
Adding Row 2 to Row 3 gives;
[tex]\begin{bmatrix}1 &-2 &-5 \\ 0& -2 & 14\\ 0&0 &18 \\\end{bmatrix}[/tex]
Dividing Row 2 by -2, and Row 3 by 18 gives;
[tex]\begin{bmatrix}1 &-2 &-5 \\ 0& 1 & -7\\ 0&0 &1 \\\end{bmatrix}[/tex]
The above matrix is in the row echelon form
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Find the zeros of the following logarithmic function: f(x) = 2logx - 6.
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During a game, 65% of the pitches Tina threw were strikes. She threw 120 2 poi total pitches during the game. How many throws were strikes? * a) 92 O b) 65 c) 78 d) 44
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The first five multiples for the numbers 4 and 6 are shown below.Multiples of 4: 4, 8, 12, 16, 20Multiples of 6: 6, 12, 18, 24, 30,What is the least common multiple of 4 and 6?241224
Answers
We have
Multiples of 4: 4, 8, 12, 16, 20
Multiples of 6: 6, 12, 18, 24, 30,
the least common multiple is the first number share between these numbers as we can see the first number share is 12
5. 8.G.1.5 Right triangle ABC and right triangle ACD overlap as shown below. Angle DAC measures 20° and angle BCA measures 30°. B D to 20- A 30° C not drawn to scale What are the values of and y?
Answers
In any triangle, the sum of the internal angle is always up to 180º.
Then, for triangle ABC:
[tex]90º+30º+(x+20º)=180º[/tex]Use it to solve x:
[tex]\begin{gathered} 90º+30º+x+20º=180º \\ x=180º-90º-30º-20º \\ x=40º \end{gathered}[/tex]In the triangle ACD:
[tex]90º+20º+(y+30º)=180º[/tex]Use it to solve y:
[tex]\begin{gathered} 90º+20º+y+30º=180º \\ y=180º-90º-20º-30º \\ y=40º \end{gathered}[/tex]Then, the value for x is 40º and the value for y is also 40ºPlease see attached picture of problem I need help with.
Answers
Step 1
List the elements of D
[tex]D=\lbrace2,.........\rbrace[/tex]List the elements of E
[tex]E=\lbrace........,8\rbrace[/tex]Find
[tex]D\cap E[/tex][tex]D\cap E=(1,8]--(\text{what is common\rparen}[/tex]Find
[tex]D\cup E[/tex][tex]\begin{gathered} D\cup E=(1,\infty)\cup(-\infty,8]--(Listing\text{ all elements in D and E\rparen} \\ D\cup E=(-\infty,\infty) \end{gathered}[/tex]Answers;
[tex]\begin{gathered} \begin{equation*} D\cap E=(1,8] \end{equation*} \\ \begin{equation*} D\cup E=(-\infty,\infty) \end{equation*} \end{gathered}[/tex]In gym class, a student can do 40 sit-ups in 60 seconds and 100 sit-ups in 150 seconds.
Graph the proportional relationship.
graph with x axis labeled time seconds and y axis labeled sit ups, with a line from 0 comma 0 going through 90 comma 60
graph with x axis labeled time seconds and y axis labeled sit ups, with a line from 0 comma 0 going through 60 comma 30
graph with x axis labeled time seconds and y axis labeled sit ups, with a line from 0 comma 0 going through 60 comma 50
graph with x axis labeled time seconds and y axis labeled sit ups, with a line from 0 comma 0 going through 90 comma 30
Question 6 (Essay Worth 4 points)
Answers
By using the linear equation y=3x we draw the graph for proportional relationship.
What is Graph?Graph is a mathematical representation of a network and it describes the relationship between lines and points.
A proportional relationship graph between two variables is a relationship where the ratio between the two variables is always the same
the graph of any proportional relationship is characterized by a straight line with data points passing through the origin (0, 0).
By the definition of proportional relationship of graph, we can reduce relationship between the values on the x-coordinate and y-coordinate of the given graph
As they are proportional and represented by euation
y = 3x
Where, x represent the time and y represent the number of sit-ups.
Hence by using the linear equation y=3x we draw the graph for proportional relationship.
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Please help me with this problem just wanted to be sure that I am correct in order to help my son to under stand the break down of this problem. I believe that the answer is -3 but I am not sure please help?Solve for x.14x−1/2(4x+6)=3(x−4)−18 Enter your answer in the box.x =
Answers
SOLUTION
We want to solve for x in the equation
[tex]14x-\frac{1}{2}\mleft(4x+6\mright)=3\mleft(x-4\mright)-18[/tex]First we expand the brackets in both sides of the equation, this becomes
[tex]\begin{gathered} 14x-\frac{1}{2}(4x+6)=3(x-4)-18 \\ 14x-2x-3=3x-12-18 \end{gathered}[/tex]Note that the minus sign multiplies the items in the brackets too
Now, we collect like terms we have
[tex]\begin{gathered} 14x-2x-3x=-12-18+3 \\ 9x=-27 \\ \text{divide both sides by 9, we have } \\ \frac{9x}{9}=\frac{-27}{9} \\ x=-3 \end{gathered}[/tex]Hence x = -3
