The half-reaction occurring at the cathode during electrolysis of an aqueous copper(II) iodide solution is

Answers

Answer 1

The half-reaction occurring at the cathode during electrolysis of an aqueous copper(II) iodide solution is Cu2+ + 2e = Cu ( E° = -0.34 V)

The reactions that take place, are:

I2 + 2e =  2I-( E° = 0.54 V)

2I- = I2 + 2e ( E° = -0.54 V)

Cu = Cu2+ + 2e ( E° = 0.34 V)

2e- + 2H2O = H2 + 2OH- ( E° = -0.83 V)

Cu2+ + 2e = Cu ( E° = -0.34 V)

Redox reactions include a change in the oxidation state of the substrate. Oxidation is the loss of electrons or an increase in the oxidation state; when they are gained or the oxidation state decreases, it is called reduction.

A redox reaction's half reaction is either its oxidation or reduction component. By taking into account the shift in oxidation states of the many chemicals participating in the redox reaction, a half reaction is obtained.

The anode half-reaction, where oxidation takes place, and the cathode half-reaction, where reduction takes place The reaction that occurs at an electrode during electrolysis is described by a half equation. It demonstrates what happens when ions pick up or drop off electrons.

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Answer 2

Cu2+ + 2e = Cu (E° = -0.34 V) is the half-reaction that takes place at the cathode during the electrolysis of an aqueous copper(II) iodide solution.

The oxidation or reduction component of a redox reaction is its half reaction. A half reaction is produced by accounting for the change in oxidation states of the several chemicals involved in the redox reaction.

The cathode half-reaction, which involves reduction, and the anode half-reaction, which involves oxidation A half equation can be used to describe the electrolysis reaction that takes place at an electrode. It illustrates what transpires when ions take on or lose electrons.

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Related Questions

four aluminum samples are each reacted with separate 1m copper sulfate solutions under the same conditions of temperature and pressure. which aluminum sample would react most rapidly

Answers

Four aluminum samples are each reacted with separate 1m copper sulfate solutions under the same conditions of temperature and pressure.So all aluminum sample will react with same rate.

The following factors affect rate of reaction.

concentration of reactants, Pressure, Temperature, Catalyst, Nature of reactants, exposure of reacting species, Surface area, Intensity of light.

If all sample of aluminum are reacted with copper sulfate solution under same conditions, then all samples will react with same rate.

In general, adding the attention of a reactant in result, adding the face area of a solid reactant, and adding the temperature of the response system will all increase the rate of a response. A response can also be sped up by adding a catalyst to the response admixture.

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Which of the following is broken when water evaporates?

O Nonpolar Covalent bonds
O Hydrogen bonds
O Polar Covalent bonds
O lonic bonds

Answers

For water to evaporate, the hydrogen bonds inside it must be broken. These bonds are formed when the highly electronegative oxygen atom in water interacts with the more electroneutral hydrogen atom in water.

Since hydrogen bonds must be broken for water molecules to fly off as gas, a lot of heat is needed to raise the temperature of liquid water, and the same is true to evaporate the same amount of water. Hydrogen bonds are weak due to the fact that they are ionic interactions between molecules with unequal charges. Heat absorption causes hydrogen bonds to be broken, allowing water molecules to move about uninhibited. Hydrogen bonds develop in water at lower temperatures, releasing substantial energy.

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A 2.50-L volume of hydrogen measured at -100 degrees Celsius is warmed to 100 degrees Celsius. Calculate the volume of the gas at the higher temperature, assuming no change in pressure.
V1:
T1:
V2:
T2:

Answers

Considering the Charles's law, the volume of the gas at the higher temperature, assuming no change in pressure, is 5.39 L.

Charles's law

Charles' law establishes the relationship between the temperature and the volume of a gas when the pressure is constant: if the temperature increases, the volume of the gas increases, while if the temperature of the gas decreases, the volume decreases.

Mathematically, Charles's law states that the ratio between volume and temperature is constant:

V÷T= k

where:

V is the volume.

T is the temperature.

k is a constant

Being an initial state 1 and a final state 2, it is fulfilled:

V₁÷T₁= V₂÷T₂

Final volume

You know:

V₁= 2.50 LT₁=-100 °C= 173 K V₂= ?T₂= 100 °C= 373 K (being 0°C= 273 K)

Replacing in Charles's law:

2.50 L÷ 173 K= V₂÷ 373 K

Solving:

(2.50 L÷ 173 K)× 373 K= V₂

5.39 L= V₂

Finally, the final volume is 5.39 L.

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Calculate the mole fraction of benzene in a solution containing 30% by mass in carbon tetrachlooride

Answers

Answer:

To calculate the mole fraction of benzene in a solution containing 30% by mass benzene, you will need to know the molar mass of benzene and the mass of the solution.

First, calculate the mass of the benzene in the solution. If the solution is 30% by mass benzene, then the mass of the benzene is 30% of the total mass of the solution. Let's say the mass of the solution is 100 grams. The mass of the benzene in the solution would be 100 g * 30% = 30 g.

Next, calculate the moles of benzene in the solution. You can use the following formula to do this:

Moles = Mass / Molar mass

The molar mass of benzene is 78.11 g/mol, so the number of moles of benzene in the solution is:

Moles = 30 g / 78.11 g/mol = 0.385 moles

To calculate the mole fraction of benzene, you will need to divide the number of moles of benzene by the total number of moles in the solution. To find the total number of moles, you will need to convert the mass of the carbon tetrachloride to moles using the molar mass of carbon tetrachloride. Let's say the mass of the carbon tetrachloride is 70 g. The number of moles of carbon tetrachloride in the solution is:

Moles = 70 g / 153.82 g/mol = 0.455 moles

The total number of moles in the solution is the sum of the moles of benzene and the moles of carbon tetrachloride:

Total moles = 0.385 moles + 0.455 moles = 0.840 moles

To find the mole fraction of benzene, divide the number of moles of benzene by the total number of moles:

Mole fraction of benzene = 0.385 moles / 0.840 moles = 0.457

This means that the mole fraction of benzene in the solution is approximately 45.7%.

Explanation:

The answer is 0.461

step by step explanation:

Let the mass of solution be 100 gm

Mass of Benzene =30 gm

Mass of CCl4 =70 gm

Moles of Benzene =

30/78=0.385

Moles of Ccl4=

70/154=0.45 moles

Mole fraction (Benzene) =

0.385/0.385+0.45

=0.461

When an anion like F gains an electron what element is its outer valence electron configuration like ?

Answers

Fluorine have 7 valence electrons. When it gains one electron, the its outer electronic configuration becomes similar to that of neon.

What is fluorine?

Fluorine is 9th element in periodic table. It have total 9 electrons of which 2 are inner electrons and 7 are valence electrons. Fluorine is a 17th group element and is highly electronegative.

According to octet rule, when elements gains 8 electron in its valence shell they become stable. Hence, fluorine need one more electron to acquire octet.

Neon is 10th element having 8 valence electrons. When Fluorine gain an electron. Its valence electron configuration becomes that of  the neon.

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What is not required on a hazardous material label?

Answers

Provider Information is not required (for secondary containers used in the workplace) on a hazardous material label.

The following components need to be on a label to be GHS compliant:

Identification of the product

warning or danger as a signal word

Risk pictograms

Advisory statements

Statements of caution

Provider Information (not required for secondary containers used in the workplace)

If the primary container fails, secondary containment acts as a backup barrier to prevent leaking into an exposed area. It is necessary to store all containers of hazardous waste and liquid hazardous materials in an appropriate secondary containment system. Systems for secondary containment may include

What information must be on labels for chemicals used at work?

The warning or signal phrase "Danger," "Warning" pictograms, "Hazmat" or "Precautionary" remarks, and "Product" and "Supplier" identification signs (supplier identification is not required for secondary containers used in the workplace)

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Please Help Quick ASAP Hurry Chemistry Unit 4 Review Sheet
3. Refer to the equation below of the reaction of Nitrogen with hydrogen. If 16.7 grams of Nitrogen react, then:
N2(g) + 3H2(g) → 2NH3(g)
a. How many moles of NH3 are produced?
Work:


Ans:__________

Thank you I'm from K12 online School

Answers

Taking into account the reaction stoichiometry, an amount of 1.193 moles of NH₃ are produced.

Reaction stoichiometry

In first place, the balanced reaction is:

N₂ + 3 H₂→ 2 NH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the amounts of moles of each compound that participate in the reaction is:

N₂: 1 moleH₂: 3 molesNH₃: 2 moles

The molar mass of the compounds is:

N₂: 28 g/moleH₂: 2 g/moleNH₃: 17 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

N₂: 1 mole ×28 g/mole= 28 gramsH₂: 3 moles ×2 g/mole= 6 gramsNH₃: 2 moles ×17 g/mole= 34 grams

Mass of NH₃ formed

The following rule of three can be applied: if by reaction stoichiometry 28 grams of N₂ form 2 moles of NH₃, 16.7 grams of N₂ form how many moles of NH₃?

moles of NH₃= (16.7 grams of N₂× 2 moles of NH₃)÷ 28 grams of N₂

moles of NH₃= 1.193 moles

Finally, 1.193 moles of NH₃ are formed.

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Draw structural formulas for each of the following:
A) 3-methyl-2-butanol
B) 2-fluoro-3-methyl-3-pentanol

Answers

The structural formula,3-methyl-2-butanol is [tex]C_5H_{12}O[/tex]

Structural formulas 2-fluoro-3-methyl-3-pentanol [tex]C_6H_{11}FO[/tex]

3-methyl-2-butanol

The chemical molecule known as sec-isoamyl alcohol and designated by the IUPAC as 3-methyl-2-butanol, Structural formula [tex]C_5H_{12}O[/tex]. It is employed in the production of other compounds as an intermediary and a solvent.

A more stable carbocation can be created by rearranging the intermediate carbocation that is created when an alkene receives a proton. We are not shocked to find that rearrangement substitution product exist as SN1-mediated substitution reactions generate carbocation intermediates.

For instance, when 2-Bromo-3-methyl butane reacts with water, it undergoes an SN1 reaction and produces 2-methyl-2-butanol rather than the intended result, 3-methyl-2-butanol.

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which statement correctly decribes microscopes?

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The correct statements that describes microscope are as follows:

Microscopes make small things appear larger (option 1).Hans and Zacharias Janssen created the first microscope (option 3). A lens is a transparent material that helps show the details of things observed (option 4).

What is a microscope?

A microscope is an optical instrument used for observing small objects.

It is an instrument that can be used to observe small objects that cannot be seen with the unaided eye. The image of an object is magnified through at least one lens in the microscope. This lens bends light toward the eye and makes an object appear larger than it actually is.

Therefore, it can be said that options 1, 3 and 4 are the true descriptions of a microscope.

The options to the incomplete question are as follows:

Microscopes make small things appear largerMagnification makes something look smallerHans and Zacharias Janssen created the first microscopeA lens is a transparent material that helps show the details of things observedThe first microscope was made of two tubes with lenses at the ends

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HELP
Can someone explain what this is and what it means?

Answers

These are energy levels in an atoms. There are four energy levels - s, p, d, f in an atom.

The majority of an atom's mass is made up of electrons, which move in set orbits around the nucleus. They are not permitted to move freely or modify their random positions as they orbit the Earth. This is as a result of their particular level of energy.

Therefore, the fixed distance between an atom's nucleus and its electrons is known as its energy level. They go by the name "electron shells" as well. The initial few-electron shells are L, M, and N.

If the necessary energy is there, it will force the electrons to absorb it and move from the lower level of energy to the higher level.

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How do lungs work? (animals)
Task: Performance Task

Answers

Answer:

On the first inhalation, air flows from the trachea to the rear air sacs. On the first exhalation, air flows from the posterior air sacs to the lungs. On the second inhalation, air flows from the lungs to the front air sacs. On the second exhalation, air flows from the front air sacs out through the trachea.

A student sets up and solves the following equation to solve a problem in solution stoichiometry. Fill in the missing part of the student's equation.

Answers

A student sets up and solves the following equation to solve a problem in solution stoichiometry. The missing units are moles/L.

When requested to assess the division's units, we must consider that the units on the other side of the division will be canceled. In this case, considering the following dimensional analysis operation:

(0.63 mol) (1 mL/10⁻³ L)/(7.2mol/L) = 88. mL

Since they are used as both denominators and numerators, we can see that milliliters cancel each other out, resulting in moles/L as the final units.

Therefore, the missing units of equation (0.63 mol) (1 mL/10⁻³ L)/(7.2_) = 88. mL is moles/ L

Your question is incomplete but most probably your full question was

A student sets up and solves the following equation to solve a problem in solution stoichiometry. Fill in the missing part of the student's equation. (0.63 mol) (1 mL/10⁻³ L)/(7.2_) = 88. mL

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3. Find the period 2 elements (atomic numbers #3-10) and the period 3 elements (#11 - 18). Do period 2 and period 3 have the same trend?

Period 2 elements are Lithium (Li), Berillium (Be), Boron (B), Carbon (C), Nitrogen ( N), Oxygen (O),
Fluorine (Fe), Neon (Ne). Period 3 elements are Sodium (Na), Magnesium (Mg), Aluminum (AI), Silicon (Si), Phosphorus (P), Sulfur (S), Chlorine (CI, Argon, (Ar)

do period 2 and period 3 have the same trend ? (if they do can you explain a bit ?)
(brainly !!)

Answers

Period 2 elements are Lithium (Li), Berillium (Be), Boron (B), Carbon (C), Nitrogen ( N), Oxygen (O), Fluorine (Fe), Neon (Ne).

Period 3 elements are Sodium (Na), Magnesium (Mg), Aluminum (AI), Silicon (Si), Phosphorus (P), Sulfur (S), Chlorine (CI, Argon, (Ar)

Define periodic table.

All identified chemical elements are arranged in rows (referred to as periods) and columns (referred to as groups) in the periodic table of chemical elements, also known as the periodic table, in ascending order of atomic number.

Period 3 elements have a tendency toward being hard (APART FROM Group 1), glossy, and having a metallic shine. They are also solids at room temperature and pressure (apart from mercury, which is a liquid metal), and they are good electrical conductors.

All elements in period 2 experience a decrease in atomic radius, an increase in electronegativity, and an increase in ionization energy as their atomic number rises. Only two metals (lithium and beryllium) are present in Period 2, which is fewer than any other period in terms of both quantity and proportion.

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hi, what are the specific body parts that land animals and water animals use to efficiently and effectively used to survive on land and in water?

get free 10 points

Answers

Answer:

REWORD THIS



If this help please set brainly brainliest.



Land animals and water animals have evolved different physical characteristics to enable them to survive and thrive in their respective environments.

For land animals, some important adaptations include strong legs and paws to enable movement on solid ground, and a streamlined body shape to reduce drag while running. Water animals, on the other hand, have evolved fins, flippers, and other appendages to help them swim through the water. They may also have gills or other specialized organs to allow them to breathe underwater.

Some examples of specific body parts that are adapted for living on land or in water include:

- Land animals: paws, hooves, claws

- Water animals: fins, flippers, gills, scales

- Both: Lungs

It's worth noting that some animals, such as amphibians and reptiles, are adapted for both land and water environments, and may have a combination of these physical characteristics.

Answer:

lungs

Explanation:

animal on land use lungs to breathe, the animals in the water use lungs to breath also

The size of an atom generally increases

A) down a group and from right to left across a period.
B) up a group and from left to right across a period.
C) down a group and from left to right across a period
D) up a group and from right to left across a period.
E) up a group and diagonally across the Periodic Table.

Answers

Generally speaking, an atom's size increases along a group and across the periodic table from right to left. Every atom is made up of a nucleus and maybe one or more electrons.

The nucleus is made up of one or more protons and several neutrons. Only the most common type of hydrogen is devoid of neutrons. Every substance solid, liquid, gas, and plasma—is made up of neutral or ionized atoms. an electric charge Having a negative charge, an electron is a particle. The negative charge is 1.602 10-19 coulomb in magnitude. A proton's mass is 1/1837 that of an electron. amount of electrons. Electrons are located in the area termed the electron cloud that surrounds the nucleus of an atom.

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Draw the Lewis structure for a carbon monosulfide (CS) molecule

Answers

The Lewis structure for a carbon monosulfide (CS) molecule is attached in the attachment below.

What are Lewis structure?

Lewis  structures are also called as electron dot structures and can be drawn if the molecular formula of a compound is known. It provides information regarding the nature of bond and the position of atoms .

They are also capable of exhibiting the lone pair if any present in a molecule or compound.Lewis defined a base to be an electron pair donor and an acid to be an electron pair acceptor.

They are capable of reflecting electronic structure of elements and even the pairing of electrons . In the diagram, each dot represents an electron while a pair of dots represent a bond between the atoms.

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1. Examine the IR spectrum of cis-norbornene-5,6-endo-dicarboxylic anhydride, (Fig.48.8, pp. 630): what do the signals at 1750 cm-1 and 1838 cm-1 indicate?2. Explain the following questions regarding the possible contamination of the final isolated product with dicyclopentadiene (the cyclopentadiene dimer).a. Since "cracked" cyclopentadiene can spontaneously dimerize back to dicyclopentadiene, could the dimer be formed as an unwanted "by-product" during the experiment?b. How does the experimental procedure minimize contamination of the final isolated (desired) product with this (undesired) "by-product"?

Answers

   The IR spectrum of cis-norbornene-5,6-endo-dicarboxylic anhydride typically shows signals at 1750 cm-1 and 1838 cm-1. The signal at 1750 cm-1 is typically associated with the carbonyl stretch of the anhydride functional group, while the signal at 1838 cm-1 is typically associated with the C=C stretch of the conjugated double bond.

   a. Yes, it is possible that the dimer, dicyclopentadiene, could be formed as an unwanted "by-product" during the experiment if the cyclopentadiene is "cracked" or thermally degraded.

   b. To minimize contamination of the final isolated product with this "by-product", the experimental procedure should include measures such as:

   Using a low reaction temperature to prevent thermal degradation of the cyclopentadiene    Using a large excess of the starting material to minimize the formation of the dimer    Using a high purity of the starting material to minimize the presence of impurities that could lead to the formation of the dimer    Using a column chromatography to separate the desired product and the by-product    Using a NMR, IR or mass spectrometry to confirm the purity of the final isolated product.

What is IR spectrum?

The IR spectrum is a powerful analytical tool that can be used to identify and confirm the presence of specific functional groups in a molecule. In the case of cis-norbornene-5,6-endo-dicarboxylic anhydride, the signals at 1750 cm-1 and 1838 cm-1 are characteristic of the anhydride and conjugated double bond functional groups, respectively.

The signal at 1750 cm-1 is associated with the stretching of the carbonyl bond of the anhydride functional group, which is a strong absorption band. The signal at 1838 cm-1 is associated with the stretching of the C=C double bond of the conjugated double bond, which is also a strong absorption band.

Therefore, Regarding the contamination of the final isolated product with dicyclopentadiene, it is important to note that cyclopentadiene can spontaneously dimerize back to dicyclopentadiene, especially at high temperatures.

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What volume of 0.0400 M calcium hydroxide is required to neutralize 32.50 mL of 0.0500 M nitric acid

Answers

The volume of 0.0400 M of calcium hydroxide is required to neutralize the 32.50 mL of the 0.0500 M nitric acid is 20.3 mL

The reaction is given as :

Ca(OH)₂  +  2HNO₃ --->  Ca(NO₃)  +  2H₂O

molarity of the nitric acid = 0.0500 M

volume of the nitric acid = 32.50 mL = 0.0325 L

moles of nitric acid = molarity × volume

                                 = 0.0500 × 0.0325

                                 = 0.001625 mol

moles of calcium hydroxide = 0.001625 / 2 = 0.0008125 mol

volume of calcium hydroxide = moles / molarity

                                                 = 0.0008125 / 0.0400

                                                 = 0.0203 L = 20.3 mL
Thus, volume of the calcium hydroxide is 20.3 mL.

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Does an exothermic absorb or release energy?

Answers

Answer:

An exothermic releases the heat.

Answer:

to answer your question, an exothermic reaction releases energy.

Explanation:

An exothermic reaction is a chemical reaction that releases energy in the form of heat, light, or sound. It is a reaction that releases energy to the surroundings.:)

A group of covalently bonded atoms that has an overall electrical charge is called a(n):a. ionic compoundb. anionc. polyatomic iond. catione. molecule

Answers

Answer:

polyatomic ion

Explanation:

Answer and Explanation: A group of covalently bonded atoms that has an overall electrical charge is called a polyatomic ion, which is the choice c.

The mixture of oil and water is an example of ___.

A. a saturated solution
B. two miscible
C. two immiscible
D. a supersaturated solution

Answers

Answer:

C. two immiscible

Explanation:

if it helps pls like or comment b thanks you
c) two immiscible

explanation:

Oil and water are two liquids that are immiscible – they will not mix together. Liquids tend to be immiscible when the force of attraction between the molecules of the same liquid is greater than the force of attraction between the two different liquids.



have an amazing night !

amides having fewer than __________ carbons are generally water soluble.

Answers

Explanation:

gas breath ofo ut by people and animal amount other different

when 20.0 g C2H6 and 60.0 g O2 react to form CO2 and H2O, what is the maximum number of grams of water that can be formed? In other words, what is the theoretical yield of H2O?
a. 36.0 G
b. 58.0 G
c. 18.0 G
d. 20.0 G
e. 28.9 G

Answers

The maximum number of grams of water that can be formed is 28.9 g.the moles of C2H6 and O2

1. Calculate the moles of C2H6 and O2:

Moles of C2H6 = 20.0 g / (2*12.011 g/mol) = 1.665 mol

Moles of O2 = 60.0 g / (2*15.999 g/mol) = 2.50 mol

2. Calculate the mole ratio of C2H6 to O2:

Moles of C2H6 / Moles of O2 = 1.665 mol / 2.50 mol = 0.666

3. Calculate the moles of H2O and CO2 that can be formed:

Moles of H2O = 0.666 * 2.50 mol = 1.665 mol

Moles of CO2 = 0.666 * 1.665 mol = 1.110 mol

4. Calculate the theoretical yield of H2O:

Theoretical yield of H2O = 1.665 moles * (2*1.008 g/mol) = 28.9 g

The maximum number of grams of water that can be formed is 28.9 g.

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undergoing nucleophilic acyl substitution with methanol under reflux conditions to form butanoic acid with a methyl ester substituent on carbon 4. Which structure was most likely the starting CA derivative

Answers

Under acidic or basic circumstances, carboxylic acid (CA) derivatives can undergo nucleophilic acyl substitution. Therefore nucleophilic acyl substitution is most likely the starting CA derivative.

A reaction known as nucleophilic acyl substitution occurs when a nucleophile creates a new bond with an acyl group's carbonyl carbon while simultaneously rupturing the bond between the carbonyl carbon and a leaving group. Due to the fact that a bond is being formed and broken on the same carbon, this reaction is categorised as a substitution.

Anhydrides undergo nucleophilic acyl substitution and are cleaved into two molecules: A carboxylic acid and either an ester or amide, if the nucleophile is an alcohol, or an amine, respectively.

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identify the lewis acid in the following reaction: pt2+(aq)+4nh3(aq)⇌pt(nh3)42+(aq)

Answers

The Lewis acid in the reaction Pt²⁺(aq) + 4NH₃(aq) ⇌ Pt(NH₃)₄²⁺(aq) is Pt²⁺(aq).

A Lewis acid is defined as a chemical species that has an empty orbital that is able to accept a lone pair of electrons from a Lewis base to form a Lewis adduct.

Lewis acids are electron pair acceptors, whereas Lewis bases are electron pair donors. Examples of Lewis acids include metal cations, electron-deficient molecules such as boron trifluoride (BF3) and aluminum chloride (AlCl3), and certain types of organic molecules such as carbenes.

For the given reaction Pt²⁺(aq) + 4NH₃(aq) ⇌ Pt(NH₃)₄²⁺(aq), the Lewis acid is Pt²⁺ (aq).

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All of the following are homogeneous mixtures except A. hydrogen gas and chlorine gas.
B. sodium chloride and potassium chloride.
C. mercury-zinc solution.
OD. hydrochloric acid solution.
E. sodium chloride and potassium chloride solution.

Answers

Answer:C I think it is C

Explanation:

7. What technology can farmers use to gather information if they don't have internet access and they live in a developing country



Answers

Farmers can gather information related to farming through awareness classes and group discussions. One other platform that provides information to farmers is wefarm app sending messages to farmers without internet.

What are technologies aiding farming?

Every industry in the world has been affected by technological improvements, and agriculture is no different. Today's technology greatly aids farmers and producers in a number of ways, including accurate forecasting, data-driven decision making, and more.

Some organizations are now forwarding good strategies to inform farmer with no-internet techniques. Some localities are conducting classes regarding new techniques and farming solutions through gathering farmers directly.

There are similar applications providing farmers relevant information with no need of internet. Farmers can acquire knowledge through TV and radios as well.

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Answer:

A landline phone

Explanation:

faxes, text messaging and apps require internet.

Landline phones is the only feasible answer

The formula for cobalt(III) sulfite is Co2(SOs)s 1. How many GRAMS of Co are present in 1.64 moles of cobalt(II) sulfite? grams 2. How many MOLES of SO3 ion are present in 1.47 grams of cobalt (III) sulfite? moles. Submit Answer Retry Entire Group 8 more group attempts remaining

Answers

Cobalt(II) iodide or cobaltous iodide are the inorganic compounds with the formula CoI2 and the hexahydrate CoI2(H2O)6.

How many GRAMS of Co are present in 1.64 moles of cobalt(II) sulfite?For every one formula unit of CoCl2 there are six molecules of water. The amount of water in a hydrate can be determined experimentally by heating the compound and driving the water off. The compound with the water removed is known as anhydrous.The anhydrous form is a blue crystalline solid; the dihydrate is purple and the hexahydrate is pinkCommercially, cobalt (II) chloride is often used to make sealants, adhesives, and glues. It is also used for electroplating, particularly for plating objects with cobalt metal. Surface treating metal is another common industrial use of the compound.Phosgene is the organic chemical compound with the formula COCl2. It is a toxic, colorless gas; in low concentrations, its musty odor resembles that of freshly cut hay or grass.

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Which of the following is an example of a compound?

Multiple Choice
O O2
O CI
O H2
O C6H1206

Answers

C6H1206 is a compound since it is made up of more than one element.

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HELP
Can someone explain what this is and what it means?

Answers

The names of the orbitals s, p, d, and f stand for names given to the groups of lines that are noted originally in the spectra of the alkali metals.

what it means by spdf orbits?

They are referred to as the acute, primary, diffuse, and fundamental line groups. The s-orbital, p-orbital, d-orbital, and f-orbital are among them. The designations of the orbitals s, p, d, and f refer to groups of lines that were first detected in the spectra of the alkali metals.

The sharp, primary, diffuse, and fundamental line groupings are among them.The s-orbital, p-orbital, d-orbital, and f-orbital are among them.A wave function, which includes orbitals, is a mathematical concept used in physics and chemistry.

Sharp, primary, diffuse, and fundamental are the various abbreviations for the spdf. These letters serve as a visual representation of the fine structure of the spectral lines that results from the interaction of spin orbits. 

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The designations of the orbitals s, p, d, and f correspond to names given to groupings of lines first observed in the spectra of the alkali metals.

What do spdf orbits mean?

The terms "acute," "primary," "diffuse," and "basic line groupings" are used to describe them. There are several of them, including the s-, p-, d-, and f-orbitals. The terms "orbitals s," "p," "d," and "f" refer to collections of lines that were initially identified in the spectra of alkali metals.

They include the fundamental, acute, main, and diffuse line categories.

There are several of them, including the s-, p-, d-, and f-orbitals.

In physics and chemistry, a mathematical notion called a wave function—which also incorporates orbitals—is used.

Various types of sharpness include primary, diffuse, and fundamental acronyms for the spdf. The fine structure of the spectral lines that comes from the interaction of spin orbits is shown visually by these letters.

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