The perimeter of a parallelogram is 76 meters. The width of the parallelogram is 2 meters less that it’s length. Find the length and the width of the parallelogram.
Answers
Answer:
The length of the parallelogram is 20 meters.
The width of the parallelogram is 18 meters.
Explanation:
The perimter of a parallelogram is calculated by addition of the lengths of all the enclosed sides.
⇒ x + (x - 2) + x + (x -2) = 76
Remove the brackets
x + x - 2 + x + x - 2 = 76
Collecting the like terms, we have
4x - 4 = 76
4x = 80
x = 80/4
x = 20 meters, which is the length of the parallelogram.
For width, we have,
20 - 2 = 18 meters.
Answer:
The length of the parallelogram is 20 meters.
The width of the parallelogram is 18 meters.
Explanation:
The perimter of a parallelogram is calculated by addition of the lengths of all the enclosed sides.
⇒ x + (x - 2) + x + (x -2) = 76
Remove the brackets
x + x - 2 + x + x - 2 = 76
Collecting the like terms, we have
4x - 4 = 76
4x = 80
x = 80/4
x = 20 meters, which is the length of the parallelogram.
For width, we have,
20 - 2 = 18 meters.
Related Questions
A student entering a doctoral program in educational psychology is required to select two courses from the list provided as part of his or her program (a)List all possible two-course selections (b)Comment on the likelihood that you EPR 625 and EPR 686 will be selected The course list EPR 613, EPR 664, EPR 625, EPR 685, EPR 686(a)select all the possible two-course selections belowA. 613, 686B. 625,686C. 613,613,664D. 664,685E. 625,685F. 625,672G. 613,625H. 685,686I. 664,625J 686,686K. 613,613L. 613,685M. 664, 686N. 613,664
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List of courses that the student entering a doctoral program in educational psychology can take:
EPR 613, EPR 664, EPR 625, EPR 685, EPR 686
Therefore, the possible two-course selections for the student are:
A. Both courses are on the list given: 613, 686
B. Both courses are on the list given: 625, 686
C. It's not possible. This option contains three courses.
D. Both courses are on the list given: 664, 685
E. Both courses are on the list given: 625, 685
F. It's not possible, Course 672 isn't available.
G. Both courses are on the list given: 613, 625
H. Both courses are on the list given: 685, 686
I. Both courses are on the list given: 664, 625
J. It's not possible. Just one course is given.
K. Same case than J. Just one course.
L. Both courses are on the list given: 613, 685
M. Both courses are on the list given: 664, 686
N. Both courses are on the list given: 613, 664
I just need someone to show how to brake down and solve this?
Answers
0.75 greater than 1/2
Answers
True
0.75 is greater than 0.5
Explanation
Step 1
remember
[tex]\frac{a}{b}=\text{ a divided by b}[/tex]then
[tex]\frac{1}{2}=\text{ 1 divided by 2 = 0.5}[/tex]Step 2
compare
0.75 and 0.5
[tex]0.75\text{ is greater than 0.5}[/tex]I hope this helps you
FOR GREATER THAN WE ADD THE TERMS.
MATHEMATICALLY THIS MEANS
[tex] = 0.75 + \frac{1}{2} \\ = 0.75 + 0.5 \\ = 1.25[/tex]
1.25 is the answer.
Old-Tyme Fashions specializes in hats modelled after fashions from the past. It purchases these hats for $42 each. It can provide a custom service to print the new owner’s name on the hatband. The printing machine costs $243 per month to rent. If Old-Tyme sells the hats at a price of $69 each, how many does it need to sell to break even?
Answers
Old-Tyme Fashions needs to sell 9 hats to break even at a price of $69 each.
Given, Old-Tyme Fashions specializes in hats modelled after fashions from the past.
It purchases these hats for $42 each.
It can provide a custom service to print the new owner’s name on the hatband.
The printing machine costs $243 per month to rent. If Old-Tyme sells the hats at a price of $69 each, how many does it need to sell to break even=?
The cost function to make n hats is:
C(n) = 42*n + 243 dollars.
The revenue function is
R(n) = 69*n dollars.
The break event equation/inequality is
R(n) ≥ C(n), or
69*n ≥ 243 + 42*n.
Simplify and solve for n:
(69-42)*n ≥ 243
27n ≥ 243
n ≥ 243/27 = 9.
hence 9 hats should be sold to break even.
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Figure L is the result of a transformation on Figure K. Which transformation would accomplish this? FigureL Figurek 5 4 2 2 -4
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Answer is the first option, a reflection over the y-axis
The graph shows the absolute value parent function. 6 Which statement is true? A. (0,1) is the x- and y-intercept of the function. B. (1,1) is the x- and y-intercept of the function. O C. (0,0) is the x- and y-intercept of the function. D. The function has no intercepts.
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From the graph;
(0,0) is the (x, y) intercept of the graph
since the function passes through (0,0)
Find the second endpoint of the segment that has an endpoint at (9,5) and its midpointat (4, 2).
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it
Please help and no I cannot show a picture of it. 5+5×0+5
Answers
Answer:
Solving the expression gives;
[tex]5+5\times0+5=10[/tex]Explanation:
Given the expression;
[tex]5+5\times0+5[/tex]Applying the rule of BODMAS or PEMDAS;
multiplication comes first;
[tex]\begin{gathered} 5+5\times0+5 \\ 5+0+5 \end{gathered}[/tex]Then we can do the addition;
[tex]\begin{gathered} 5+0+5 \\ =5+5 \\ =10 \end{gathered}[/tex]Therefore, solving the expression gives;
[tex]5+5\times0+5=10[/tex]Needing assistance with question in the photo (more than one answer)
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By definition, the probability of an event has to be between 0 and 1.
Given that definition the options 1.01, -0.9, -5/6 and 6/5 cannot be the probability of an event.
Gary is saving money to buy a ticket to a New York Jets game that costs $225. Healready has saved $18. What is the least amount of money Gary must save each week, sothat at the end of 9 weeks he has enough money to buy the ticket? (Only an algebraic- solution will be accepted.)
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lillyvong13, this is the solution:
Cost of the ticket to a New York Jets game = $ 225
Savings up to now = $ 18
Difference = 225-18 = 207
Number of weeks = 9
Let x to represent the amount of money Gary must save each week for buying the ticket, as follows:
x = 207/9
x = 23
Gary must save $ 23 at the end of 9 weeks to have enough money to buy the ticket
The table shows a function. Is the function linear or nonlinear?x y0 1918 1200
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By plotting the points, we get a non-linear function
You choose a marble from the bag. What is the probability you will NOT choose blue?1/25/72/72
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Given a sample and required to get the probability of a particular outcome, we make a couple of considerations including:
- Sample Space: The universal set
- Required Outcome
We can identify these variables as:
Sample space: total number of marbles = 7
Required outcome: Not blue = 7 - 2 = 5
Probability is given as:
[tex]\begin{gathered} P=\text{ }\frac{\text{number of required outcome}}{Sample\text{ space}}=\frac{5}{7} \\ P=\frac{5}{7} \end{gathered}[/tex]use pie=3.14 to estimate the unknown measures for each circle.c=132 ind=r=A=I'll upload a picture
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Problem N 25
we know that
C=132 in
Remember that
The formula to calculate the circumference is given by
[tex]C=pi*D[/tex]using pi=3.14
C=132 in
substitute given values in the formula
[tex]\begin{gathered} 132=3.14*D \\ solve\text{ for D} \\ D=\frac{132}{3.14} \\ D=42.04\text{ in} \end{gathered}[/tex]The diameter D=42.04 in ( with pi=22/7 the diameter is 42 in exact)
Find out the radius r
r=D/2=42.04/2=21.02 in -----> the radius is half the diameter
Find out the area of the circle
The area is given by the formula
[tex]A=pi*r^2[/tex]we have
r=21.02 in
pi=3.14
substitute
[tex]\begin{gathered} A=3.14*21.02^2 \\ A=1,387.38\text{ in}^2 \end{gathered}[/tex]therefore
the answer isd=42.04 inr=21.02 inA=1,387.38 in21. Write a linear equation of the form y1 = mx + b for your first set of data.2. Write a linear equation of the form y2 = mx + b for the other equation in your system. 3. Graph and explain the solution.
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Given:
Company A: transport 56 people in one hour for $40 per person in 30 minutes
Company B:
Solve radical∛x²-8=4
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Let's determine the value of x on the given radical expression:
[tex]\text{ }\sqrt[3]{x^2-8}\text{ = 4}[/tex]An airplane is taking off at angle of 9 degrees and traveling at a speed of 200 feet per second in relation to the ground. If the clouds begin at an altitude of 4,000 feet, how many seconds will it take for the airplane to be in the clouds?
Answers
ANSWER
[tex]\begin{equation*} 127.85\text{ }seconds \end{equation*}[/tex]EXPLANATION
First, let us make a sketch of the problem:
To find the time it will take the airplane to be in the clouds, we first have to find the distance flown by the airplane in attaining that height, x.
To do this, apply trigonometric ratios SOHCAHTOA for right triangles:
[tex]\sin9=\frac{4000}{x}[/tex]Solve for x:
[tex]\begin{gathered} x=\frac{4000}{\sin9} \\ x=25,569.81\text{ }ft \end{gathered}[/tex]Now, that we have the distance, we can solve for the time by applying the relationship between speed and distance:
[tex]\begin{gathered} speed=\frac{distance}{time} \\ \Rightarrow time=\frac{distance}{speed} \end{gathered}[/tex]Substitute the given values into the formula above and solve for time:
[tex]\begin{gathered} time=\frac{25569.81}{200} \\ time=127.85\text{ }seconds \end{gathered}[/tex]That is the number of seconds that it will take.
what is an identityA) an identity is a false equation relating to a mathematical expression to a real numberB) an identity is a true equation relating to a mathematical expression to a real numberC) an identity is a true equation relating one mathematical expression to another expressionD) an identity is a false equation relating to one mathematical expression to another expression
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The right answer is C
Please help me with the question below(also please answer the question in a maximum of 5-10 minutes).
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Given that Tom's yard is in the shape of a trapezoid, you know that the formula for calculating the area of a trapezoid is:
[tex]A=\frac{(b_1+b_2)}{2}\cdot h[/tex]Where "h" is the height of the trapezoid and these are the bases:
[tex]\begin{gathered} b_1 \\ b_2 \end{gathered}[/tex]In this case, you can identify that:
[tex]\begin{gathered} b_1=65\text{ }ft \\ b_2=50\text{ }ft \\ h=30\text{ }ft \end{gathered}[/tex]Then, you can substitute values into the formula and evaluate:
[tex]A=\frac{(65\text{ }ft+50\text{ }ft)}{2}\cdot30\text{ }ft[/tex][tex]A=\frac{115\text{ }ft}{2}\cdot30\text{ }ft[/tex][tex]A=\frac{3450\text{ }ft^2}{2}[/tex][tex]A=\frac{3450\text{ }ft^2}{2}[/tex][tex]A=1725\text{ }ft^2[/tex]Hence, the answer is:
[tex]1725\text{ }ft^2[/tex]Can someone help me with this geometry question? I will provide more information.
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So you are given a triangle ABC and you need to build another one DEF that meets the following:
[tex]\begin{gathered} AB=DE \\ m\angle E=90^{\circ} \\ EF=BC \end{gathered}[/tex]First of all we should find the lengths of sides AB and BC. For this purpose we can use the coordinates of points A, B and C. The length of AB is the distance between A and B and the length of BC is the distance between B and C. The distance between two generic points (a,b) and (c,d) is given by:
[tex]\sqrt[]{(a-c)^2+(b-d)^2}[/tex]Then the length of AB is:
[tex]AB=\sqrt[]{(1-1)^2+(6-1)^2}=\sqrt[]{0+5^2}=5[/tex]And that of BC is:
[tex]BC=\sqrt[]{(1-5)^2+(1-1)^2}=\sqrt[]{4^2}=4[/tex]Then the triangle DEF must meet these three conditions:
[tex]\begin{gathered} DE=5 \\ EF=4 \\ m\angle E=90^{\circ} \end{gathered}[/tex]Since there is no rules about its position we can draw it anywhere. For example you can choose E=(-4,1). Then if D=(-4,6) we have that the length of DE is 5:
[tex]DE=\sqrt[]{(-4-(-4))^2+(6-1)^2}=\sqrt[]{0+5^2}=5[/tex]And if we take F=(0,1) we get EF=4:
[tex]EF=\sqrt[]{(-4-0)^2+(1-1)^2}=\sqrt[]{16}=4[/tex]Then a possibility for triangle DEF is:
As you can see it also meets the condition that the measure of E is 90°. And that would be part A.
In part B we have to use the pythagorean theorem to state a relation between the sides of DEF. For a right triangle with legs a and b the theorem states that its hypotenuse h is given by:
[tex]h^2=a^2+b^2[/tex]We can do the same for DEF. Its legs are DE and EF whereas its hypotenuse is DF so we get:
[tex]DF^2=DE^2+EF^2[/tex]And that's the equation requested in part B.
Neptune is about how many times as far from the Sun as Mars is fronthe Sun?Neptune = 2,600, 000,000MarS= 143,000,000Solution:
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Enter a rule for each function f and g, and then compare their domains, ranges, slopes, and y-intercepts.The function f(x) has a slope of -2 and has a y-intercept of 3. The graph shows the function g(x).
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The rule of the function f(x) is : -2x + 3
To find the rule of the function g(x) let's calculate the slope of the line
[tex]m=\frac{y2-y1}{x2-x1}=\frac{-11-5}{4-0}=\frac{-16}{4}=-4[/tex]The slope of the line is -4 and the intercept is 5 ( from the graph).
The rule of the function g(x) is : -4x + 5
The domains of f(x) and g(x) is All real numbers, because there is not any number of x which doesn't have a corresponding y-coordinate.
The ranges of f(x) and g(x) is All real numbers, because there is not any number of y which doesn't have a corresponding x-coordinate.
The slope of f(x) is greater than g(x) (-2 is greater than -4)
The y-intercept of f(x) is less than the y-intercept of g(x).(3 is less than 5)
Line segment AB is on square ABCD. Segment EF on equilateral triangle EFG is 12 units longer than AB. Square ABCD and triangle EFG have equal perimeters. What is the length of AB?
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The length of segment AB when the line segment AB is on square ABCD is 36 units.
What is the length of segment AB?From the task content, the length of the line segment AB which is a side of the square ABCD is to be determined.
In this case, since the perimeters of triangle EFG and square ABCD are equal as given;
Let the length of segment AB = x.
Therefore, EF = x + 12.
Therefore, the perimeter of the equilateral triangle = 3(x +12).
While the perimeter of square ABCD is; 4x.
Therefore, since the perimeters are equal, we equate them and this will be:
3(x + 12) = 4x
3x + 36 = 4x
36 = x.
Therefore, the length is 36 units.
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help in this question
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A vertex is a point on a polygon where two rays or line segments meet, the sides, or the edges of the object come together. Vertex is the plural form of vertices.
A vertex example is what?f(x)=3(x−1)2
Find the given parabola's characteristics.
Lessen the steps you tap...
Vertex form is to be used, y=a(x−h)2+k,
to calculate the values of a, h, and k.
a=3
h=1
k=0
The parabola widens because the value of an is positive.
opens up
Find the (h,k) vertex. ( 1 , 0 )
Calculate p, the distance between the focus and the vertex.
To continue, tap...
1/ 12
Locate your focus.
To continue, tap... ( 1 , 1/ 12 )
By identifying the line that connects the vertex with the focus, you may determine the axis of symmetry.
x = 1
The horizontal line that results from deducting p from the vertex's y-coordinate k depends on whether the parabola opens up or down. This line is known as the directrix.
y = k − p
Simplify the formula after substituting the known p and k values.
y = − 1 /12
Analyze and graph the parabola using its characteristics.
Direction: opens up
vertices: ( 1, 0 )
Focus: ( 1 , 1 /12 )
x = 1 is the symmetry axis.
Direction: y = /1 12.
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Out of 3500 students at a college 1760 are enrolled in a computer class. What is the per cent of students taking the computer class?
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Using percentages we can conclude that 50.2% of students are taking a computer class.
What is the percentage?A value or ratio that may be stated as a fraction of 100 is referred to as a percentage in mathematics. If we need to calculate a percentage of a number, we should divide it by its entirety and then multiply it by 100. By dividing the value by the entire value and multiplying the result by 100, one may determine the percentage. The percentage calculation formula is (value/total value)100%.So, the percentage of students taking computer classes:
The total number of students is 3500.The number of students enrolled in a computer class is 1760.Now, calculate as follows:
1760/3500 × 1000.502 × 10050.2Therefore, using percentages we can conclude that 50.2% of students are taking a computer class.
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(06.03 MC) Use the expression 5(6 + 4x) to answer the following: Part A: Describe the two factors in this expression. (4 points) Part B: How many terms are in each factor of this expression? Part C: What is the coefficient of the variable term? (2 points)
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In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
Expression:
5(6 + 4x)
Step 02:
5(6 + 4x)
A.
5 = factor 1
(6 + 4x) = factor 2
B.
5 = factor 1 ( 1 term)
(6 + 4x) = factor 2 (2 terms)
C.
variable term: 4x
coefficient = 4
That is the full solution.
Z A I + 5 4x - 3 3r-1 2x + 1 What value of x makes ASTW - AXYZ? s 3 + 1 T 4r-5 x = 2 X = 3 X=4 X=1
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Here, we have two congruent triangles.
Given:
ST = 3x - 1 XY = 4x - 5
SW = 3x + 1 XZ = 4x - 3
TW = 2x + 1 YZ = x + 5
Since triangle STW and triangle XYZ are congruent, they have exactly the same corresponding sides.
To find the value of x, equate the corresponding sides and evaluate.
ST = XY
SW = XZ
TW = YZ
Take one of the corresponding sides.
We have:
ST = XY
3x - 1 = 4x - 5
Subtract 4x from both sides:
3x - 4x - 1 = 4x - 4x - 5
-x - 1 = -5
Add 1 to both sides:
-x - 1 + 1 = -5 + 1
-x = -4
Divide both sides by -1:
[tex]\begin{gathered} \frac{-x}{-1}=\frac{-4}{-1} \\ \\ x=4 \end{gathered}[/tex]Therefore, the value of x that makes ΔSTW ≅ ΔXYZ is 4
ANSWER:
x = 4
I need help with #1 and 2 please I’m struggling
Answers
The slope of a line perpendicular to other line is the negative reciprocal of the slope.
This means, if the slope of a line is x, the slope of a perpendicular line will be:
[tex]-\frac{1}{x}[/tex]Then , the first thing we should do is to find the slope of f(x).
To find the slope of a line that passes two points P and Q we use:
[tex]\begin{gathered} \begin{cases}P=(x_p,y_p) \\ Q=(x_q,y_q)\end{cases} \\ \text{slope}=\frac{y_p-y_q}{x_p-x_q} \end{gathered}[/tex]In this case, we can use P = (1, 4) and Q = (-3, 2)
Then:
[tex]\text{slope}=\frac{4-2}{1-(-3)}=\frac{2}{4}=\frac{1}{2}[/tex]Now, we know that the slope of g(x) is perpendicular to f(x) which has a slope of 1/2
The reciprocal is:
[tex]\frac{1}{2}\Rightarrow\frac{2}{1}=2[/tex]And to make it the negative, we multiply by (-1):
[tex]2\cdot(-1)=-2[/tex]Thus, g(x) has a slope equal to -2
Make the following conversions. Round to 2 decimal places, where necessary.8 feet 9 inches toa. Inches: in.b. Feet: ft
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Given the measurement
[tex]8feet\text{ 9inches}[/tex]a) To convert to inches,
Where
[tex]1ft=12in[/tex][tex]8ft\text{ to inches}=8\times12=96[/tex]8 feet 9 inches in inches is
[tex]\begin{gathered} 8ft\text{ 9in}=8ft+9in=96+9=105in \\ 8ft\text{ 9in}=105in \end{gathered}[/tex]Hence, 8 feet 9 inches in inches is 105in
b) To convert to feet,
Where
[tex]1in=\frac{1}{12}ft[/tex][tex]9in\text{ to f}eet=9\times\frac{1}{12}=\frac{9}{12}=0.75ft[/tex]8 feet 9 inches in feet is
[tex]8ft\text{ 9in}=8ft+9in=8+0.75=8.75ft[/tex]Hence, 8 feet 9 inches in feet is 8.75ft
The function is defined by h(x) = x - 2 . Find h(n + 1) .
Answers
SOLUTION:
Case: Functions
Method:
The function
[tex]\begin{gathered} h(x)=x-2 \\ Hence \\ h(n+1)=(n+1)-2 \\ h(n+1)=n+1-2 \\ h(n+1)=n-1 \end{gathered}[/tex]Final answer:
[tex]h(n+1)=n-1[/tex]Tommy paid $8.25 for three pounds of gummy candy.Tommy created a graph from the data on his chart. Is his graph correct? Why or Why not?
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Notice that the relationship between the number of pounds of gummy candy and the number of dollars that that number of pounds costs is a function because there cannot be two prices for the same number of pounds.
Now, notice that the graph that Tommy creates does not represent a function because it fails the vertical line test at x=3.
Also, from the given table we get that (4,11) is a point of the graph.
Then the graph that Tommy creates is not correct.
Answer: No, because the graph does not represent a function and the point (4,11) is not part of the graph.
