The graph of the given function is attached below.
x intercept means if there will be no khakis shipped, then there will be 120 jeans shipped.
Also, y -intercept means if there will be no jeans shipped, then there will be 90 khakis shipped.
Given equation:-
15x + 20y = 1800
Where,
x represents the number of jeans shipped and,
y represents the number of khakis shipped
We have to use the x and y-intercepts to graph the equation.
Putting x = 0 to find the y -intercept, we get,
15(0) + 20y =1800
0 + 20y = 1800
y = 1800/20
y = 90
The coordinates of the point will be (0,90).
Putting y = 0 to find the x -intercept, we get,
15x + 20(0) =1800
15x + 0 = 1800
x = 1800/15
x = 120
The coordinates of the point will be (120,0).
Using the coordinates, we have graphed the graph attached.
Here, x intercept means if there will be no khakis shipped, then there will be 120 jeans shipped.
Also, y -intercept means if there will be no jeans shipped, then there will be 90 khakis shipped.
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second number when the list is sorted from greatest to least
5.2% = 0.052
1/7 = 0.14
-11/5 = -2.2
From the greatest to least:
[tex]0.14>0.052>-0.8>-2.2[/tex]The second number is: 5.2%
Answer:
5.2%
Determine which of the following lines, if any, are perpendicular • Line A passes through (2,7) and (-1,10) • Line B passes through (-4,7) and (-1,6)• Line C passed through (6,5) and (7,9)
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
Line A:
point 1 (2,7)
point 2 (-1,10)
Line B:
point 1 (-4,7)
point 2 (-1,6)
Line C:
point 1 (6,5)
point 2 (7,9)
Step 02:
perpendicular lines:
slope of the perpendicular line, m’
m' = - 1 / m
Line A:
slope:
[tex]m\text{ = }\frac{y2-y1}{x2-x1}=\frac{10-7}{-1-2}=\frac{3}{-3}=-1[/tex]Line B:
slope:
[tex]m=\frac{y2-y1}{x2-x1}=\frac{6-7}{-1-(-4)}=\frac{-1}{-1+4}=\frac{-1}{3}[/tex]Line C:
slope:
[tex]m\text{ = }\frac{y2-y1}{x2-x1}=\frac{9-5}{7-6}=\frac{4}{1}=4[/tex]m' = - 1 / m ===> none of the slopes meet the condition
The answer is:
there are no perpendicular lines
A trail mix brand guarantees a peanut to raisin ratio of 5:2. If a bag of that trail mix contains 30 peanuts, how many raisins are in the bag?
Answer:
12
Explanation:
In the bag, the guaranteed ratio of peanut to raisin = 5:2
Number of peanuts = 30
Let the number of raisins =x
We therefore have that:
[tex]\begin{gathered} 5\colon2=30\colon x \\ \frac{5}{2}=\frac{30}{x} \\ 5x=30\times2 \\ x=\frac{30\times2}{5} \\ x=12 \end{gathered}[/tex]The number of raisins in the bag is 12.
Which of the following is NOT a factor of x3 + x2 - 4x - 4?x + 1x + 2x - 1x - 2
Answer: (x - 1)
Explanation
Given:
[tex]x^3+x^2-4x-4[/tex]To factor a third-degree polynomial, we can do it by grouping:
[tex]=(x^3+x^2)+(-4x-4)[/tex]Then, we have to find the common factor between groups:
[tex]=x^2(x+1)-4(x+1)[/tex]Now, we can get the common factor of (x+1):
[tex]=(x^2-4)(x+1)[/tex]Finally, the differences of squares equal the following:
[tex](x^2-a^2)=(x-a)(x+a)[/tex]Then, applying this rule to our factor we get:
[tex]=(x+2)(x-2)(x+1)[/tex]Thus, the only factor that is not correct is (x - 1)
Use the appropriate differenatal formula to find© the derivative of the given function6)3(16) 96) = (x²-1) ²(2x+115
1) We need to differentiate the following functions:
[tex]\begin{gathered} a)\:f(x)=x\sqrt[3]{1+x^2}\:\:\:\:Use\:the\:product\:rule \\ \\ \\ \frac{d}{dx}\left(x\right)\sqrt[3]{1+x^2}+\frac{d}{dx}\left(\sqrt[3]{1+x^2}\right)x \\ \\ \\ 1\cdot \sqrt[3]{1+x^2}+\frac{2x}{3\left(1+x^2\right)^{\frac{2}{3}}}x \\ \\ \sqrt[3]{1+x^2}+\frac{2x^2}{3\left(x^2+1\right)^{\frac{2}{3}}} \\ \\ f^{\prime}(x)=\sqrt[3]{1+x^2}+\frac{2x^2}{3\left(1+x^2\right)^{\frac{2}{3}}} \end{gathered}[/tex]Note that we had to use some properties like the Product Rule, and the Chain Rule.
b) We can start out by applying the Quotient Rule:
[tex]\begin{gathered} g(x)=\frac{(x^2-1)^3}{(2x+1)} \\ \\ f^{\prime}(x)=\frac{\frac{d}{dx}\left(\left(x^2-1\right)^3\right)\left(2x+1\right)-\frac{d}{dx}\left(2x+1\right)\left(x^2-1\right)^3}{\left(2x+1\right)^2} \\ \\ Differentiating\:each\:part\:of\:that\:quotient: \\ \\ ------- \\ \frac{d}{dx}\left(\left(x^2-1\right)^3\right)=3\left(x^2-1\right)^2\frac{d}{dx}\left(x^2-1\right)=6x\left(x^2-1\right)^2 \\ \\ \frac{d}{dx}\left(x^2-1\right)=\frac{d}{dx}\left(x^2\right)-\frac{d}{dx}\left(1\right)=2x \\ \\ \frac{d}{dx}\left(x^2\right)=2x \\ \\ \frac{d}{dx}\left(1\right)=0 \\ \\ \frac{d}{dx}\left(2x+1\right)=2 \\ \\ Writing\:all\:that\:together: \\ \\ f^{\prime}(x)=\frac{6x\left(x^2-1\right)^2\left(2x+1\right)-2\left(x^2-1\right)^3}{\left(2x+1\right)^2} \\ \end{gathered}[/tex]Thus, these are the answers.
Find the x- and y-intercepts of the graph of the equation.5x + 3y = 15x−intercept (x, y) = ( ) y−intercept (x, y) = ( )
Consider that the intercept form of equation of a line whose x-intercept is (a,0) and y-intercept is (0,b), is given by,
[tex]\frac{x}{a}+\frac{y}{b}=1[/tex]The equation of the line is given as,
[tex]5x+3y=15[/tex]Convert this equation into intercept form,
[tex]\begin{gathered} \frac{5x}{15}+\frac{3y}{15}=1 \\ \frac{x}{3}+\frac{y}{5}=1 \end{gathered}[/tex]Comparing with the standard equation,
[tex]\begin{gathered} a=3 \\ b=5 \end{gathered}[/tex]Thus, the x-intercept and y-intercept of the equation, respectively, are,
[tex](3,5)\text{ and }(0,5)[/tex]Kathryn needs to include a scale drawing of a race car on her science science fair project. Her actual race car is 180 inches long and 72 inches tall. if she uses a scale factor of 1 inch= 8 inches, what will the dimensions of her scale drawing?
To find the scaled measures of the race car, you have to divide the original measures by the scale. This is:
[tex]\text{length}=\frac{182in}{8}=22.75in[/tex][tex]\text{height}=\frac{72in}{8}=9in[/tex]So the scaled measures of the race car are: length=22.75in and height=9in
Solve the inequality 3.5 >b + 1.8. Then graph the solution.
Collect like terms
[tex]\begin{gathered} 3.5-1.8\ge b \\ 1.7\ge b \\ b\leq\text{ 1.7} \end{gathered}[/tex]The midpoint of AB is M(4,1). If the coordinates of A are (2,8), what are thecoordinates of B?
Ben works at a mobile phone store, where he earns a flat $80 for each 8-hour shift. He also earns a commission of $20 for each phone that he sells. If e stands for Ben's earnings and m is the number of mobile phones he sells, which of the following equations describes the amount of money that he earns in one shift?Question 5 options:A) e = m + 80B) e = m + 100C) e = –20m + 80D) e = 20m + 80
fixed earnings = $80 ( for 8 hour shift)
Number of mobile phones he sells = m
Commision for each mobile phone sold = $20
Amount he earns in 1 shift (e) = flat + number of phones* commision
e = 80 + 20m
e= 20m + 80 (D)
4+4x=2x+8+2x-5 help please
Simplify the expression.
[tex]\begin{gathered} 4+4x=2x+8+2x-5 \\ 4x-2x-2x=8-5-4 \\ 0=-1 \end{gathered}[/tex]Thus, the equation is solved.
Question 9 (1 point) Jennifer is a car saleswoman. She is paid a salary of $2200 per month plus $300 for each car that she sells. Write a linear function that describes the relationship between the number of cars sold x and the monthly salary y. Then, graph the function to show the relationship.
A rectangle has a length of 9 inches and a widt of 5 inches whose sides are changing. The length is increasing by 3 in/sec and the width is shrinking at 9 in/sec. What is the rate of change of the perimeter?
Given:
A rectangle has a length of 9 inches and a width of 5 inches whose sides are changing. The length is increasing by 3 in/sec and the width is shrinking at 9 in/sec.
To find:
The rate of change of the perimeter.
Solution:
It is known that the perimeter of the rectangle is twice the sum of length and width.
[tex]P=2(l+w)[/tex]DIfferentiate the perimeter with respect to t:
[tex]\frac{dP}{dt}=2(\frac{dl}{dt}+\frac{dw}{dt})[/tex]From the given information:
[tex]\begin{gathered} \frac{dP}{dt}=2(3-9) \\ =2(-6) \\ =-12 \end{gathered}[/tex]Thus, the perimeter of the rectangle is decreasing at the rate of 12 inches per second.
find the circumference of the circle L. Write your answer as a decimal, rounded to the nearest hundredth. the circumference is blank feet
Let us call C the circumference of the circle.
We know that the ratio of angle to circumference must be
[tex]\frac{106}{360}=\frac{1.25}{C}[/tex]cross multipication gives
[tex]106(C)=360\cdot1.25[/tex]Dividing both sides by 106 gives
[tex]C=\frac{360\cdot1.25}{106}[/tex][tex]C=4.25[/tex]which is our answer!
Pedro can't decide which size pizza to order. The 10-inch cheese and sausage pizza is $4.99, while the 12-inch deluxe is $5.99. If he gets the 10-inch pizza, the total price will be divided among 3people. If he chooses the 12-inch pizza, then the total price will be divided among 4 people. Which is the better buy? How much will each person pay? (Use 3.14 for r.)A. 10-inch pizza; $1.50B. 12-inch pizza; $1.50C. 10-inch pizza; $1.66 D. 12-inch pizza; $1.66
Answer: The better buy is the the 12-inch deluxe for $5.99.
B. 12-inch pizza; $1.50
Explanation:
From the information given, the 10-inch cheese and sausage pizza is $4.99, while the 12-inch deluxe is $5.99. If he gets the 10-inch pizza. We would calculate the area of both pizzas by applying the formula for calculating the area of a circle which is expressed as
Area = πr^2
where
π = 3.14
r is the radius of the circle
For the 10-inch cheese and sausage pizza,
diameter = 10
r = 10/2 = 5
Area = 3.14 x 5^2 = 78.5
If it is divided among 3 people,
each person gets 78.5/3 = 26.2 in^2
Amount that each person pays = 4.99/3 = $1.66
This means that each person pays $1.66 for 26.2 in^2
For the 12-inch cheese and sausage pizza,
diameter = 12
r = 12/2 = 6
Area = 3.14 x 6^2 = 113.04
If it is divided among 4 people,
each person gets 113.04/4 = 28.26 in^2
Amount that each person pays = 5.99/4 = $1.5
This means that each person pays $1.5 for 28.26 in^2
Thus, the better buy is the the 12-inch deluxe for $5.99.
The amount that each person pays is
B. 12-inch pizza; $1.50
A machine worked for 4hours and used 6kilowatts of electricity.What is the rate ofenergy consumed inkilowatts per hour?*Enter your answer as a decimal
4 hours ---> 6 kilowatts
1 hour -----> x kilowatts
[tex]\begin{gathered} 4\times x=1\times6 \\ 4x=6 \\ \frac{4x}{4}=\frac{6}{4} \\ x=\frac{3}{2}=1.5 \end{gathered}[/tex]answer:
1.5 kilowatts per hour
How do you slove this promblem 207.4÷61
we have
207.4÷61
[tex]207.4\div61=\frac{207.4}{61}=\frac{2,074}{610}=\frac{1,830}{610}+\frac{244}{610}=3+\frac{244}{610}=3\frac{244}{610}[/tex]simplify
244/610=122/305=4/10=2/5
therefore
the answer is 3 2/5Which x-value is in the domain of the function? Thank you!
Solution:
Given the function;
[tex]f(x)=4\cot(2x)+3[/tex]The graph of the function is;
ANSWER:
[tex]\frac{\pi}{3}[/tex]SKIPPYTHEWALRUS U CAN'T ANSWER THIS QUESTIONI NEED CORRECT ANSWER 100 POINTS ONLY ANSWER CORRECTLY
A line passes through the points (7,9) and (10,1). What is its equation in point-slope form?
Use one of the specified points in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.
Answer:
y - 1 = -8/3(x - 10)
also valid:
y - 9 = -8/3(x - 7)
Step-by-step explanation:
Point-slope equation is a fill-in-the-blank formula that is sort of a shortcut for writing the equation of a line. Point-slope is named that bc you fill in a point and the slope.
Point-slope Eq:
y - Y = m(x - X)
fill in the slope for the m and fill in any point on the line for the X,Y.
First slope:
Slope is y-y over x-x
9-1 / 7-10
= 8/ -3
= -8/3
So slope is -8/3 fill that in for the m.
y -Y = -8/3(x-X)
Pick one of the points (either one it totally doesn't matter)
Let's use (10,1)
fill in 10 for X and 1 in place of Y.
the y in the very front stays a y and the first x in the parentheses stays an x, so there will be two variables in your completed answer.
y - 1 = -8/3(x - 10)
make sure the parentheses on the right is beside the -8/3 fraction and is NOT written on the bottom, beside the 3 only.
A landscape supply business charges $35 to deliver mulch. The cost of the mulch is
$29 per cubic yard. Write a linear equation to find the cost of having x cubic yards of
mulch delivered to a site.
The linear function to represent the number of mulch delivered to a site is y = 29x + 35
What is a linear function?In mathematics, the term linear function refers to two distinct but related notions: In calculus and related areas, a linear function is a function whose graph is a straight line, that is, a polynomial function of degree zero or one.
For this question, we can represent the cost of having x cubic yards of mulch delivered to a site. For a standard linear function, it can be represented as y = mx + c
m = slope
c = intercept
We can use this concept to write a linear function to represent this problem:
y = mx + c
y = 29x + 35
In this case, the slope is 29 and the intercept is 35. The slope in this situation is the cost of the mulch and the amount charged by the business is the intercept.
The equation representing this problem is y = 29x + 35
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Find the distance d(P1, P2) between the given points P1 and P2: P1 =(0,0) P2 = (2,3)d(P1,P2) = (Simplify your answer using radical as needed)
Recall that given points (a,b) and (c,d) the distance between them would be
[tex]d=\sqrt[2]{(c\text{ -a\rparen}^2+(d\text{ -b\rparen}^2}[/tex]In our case we are given a=0,b=0,c=2,d=3. So the distance would be
[tex]d=\sqrt[2]{(2\text{ -0\rparen}^2+(3\text{ -0\rparen}^2}=\sqrt[2]{2^2+3^2}=\sqrt[2]{4+9}=\sqrt[2]{13}[/tex]so the distance between them is the square root of 13.
i am stuck and need help ASAP with itfind the area
Given:
Required:
We want to find the area of given
Explanation:
As we can see that measurement of given figure is 5 by 5 so it is square and the area of square is
[tex]5*5=25\text{ unit}^2[/tex]Final answer:
25 sq unit
Simplify 3√12 +8✓12 - √6 how
In order to simplify this equation, we are going to start by simplifying the radicals.
[tex]\sqrt[]{12}=\sqrt[]{2^2\cdot3}=\text{2}\sqrt[]{3}[/tex]Now we have the radicals simplified and we are going to replace them on the equation that we already have.
[tex]\begin{gathered} 3\cdot(2\sqrt[]{3})+8\cdot(2\sqrt[]{3})-\sqrt[]{6} \\ 6\sqrt[]{3}+16\sqrt[]{3}-\sqrt[]{6} \\ 22\sqrt[]{3}-\sqrt[]{6} \end{gathered}[/tex]5.) y = -5/4 x + 10 (Use Slope Int. Method Make apparent your Int. Point AND the point from your slope = RISE/RUN)
what's the answer for proportions 7/9=b/b-10
Answer:
-35
Step-by-step explanation:
[tex]\frac{7}{9}[/tex] = [tex]\frac{b}{b - 10}[/tex] multiply both sides by 9(b -10)
[tex]\frac{9(b - 10)}{1}[/tex] [tex](\frac{7}{9})[/tex] = [tex]\frac{9(b -10)}{1}[/tex] [tex](\frac{b}{b-10})[/tex] On the right side of the equation, the 9's cancel out and on the right side of the equation the (b -10) cancels out to leave
7(b -10) = 9b Distribute the 7
7b - 70 = 9b Subtract 7b from both sides
-70 = 2b Divide both sides by 2
-35 = b
What is the x-intercept of the line y=-2x+6? (3,0) -6,0) (0,3) (-3,3)
The given equation is expressed as
y = - 2x + 6
The x intercept of a line is the point at which y = 0
By applying this concept, it means that
0 = - 2x + 6
Adding 2x to both sides of the equation, it becomes
0 + 2x = - 2x + 2x + 6
2x = 6
Dividing both sides by 2, it becomes
2x/2 = 6/2
x = 3
Therefore, the correct option is (3, 0)
Si A = 5x 2 + 4 x 2 - 2 (3x2), halla su valor numérico para x= 2.
Based on the calculations, the numerical value of A is equal to 12.
How to determine the numerical value of A?In this exercise, you're required to determine the numerical value of A when the value of x is equal to 2. Therefore, we would evaluate the given equation based on its exponent as follows:
Numerical value of A = 5x² + 4x² - 2(3x²)
Numerical value of A = 5(2)² + 4(2)² - 2(3 × (2)²)
Numerical value of A = 5(4) + 4(4) - 2(3 × 4)
Numerical value of A = 20 + 16 - 24
Numerical value of A = 36 - 24
Numerical value of A = 12
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Complete Question:
If A = 5x² + 4x² - 2(3x²), find its numerical value for x = 2.
Solve for the remaining angles and side of the one triangle that can be created. Round to the nearest hundredth:A = 100"a = 3.5, b = 3
Given:
• A = 100 degrees
,• a = 3.5
,• b = 3
Let's solve for the remaining angles and side of the triangle.
Here, we are given one angle and two sides.
To solve, apply the Law of Sines:
[tex]\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}[/tex]• To solve for measure of angle B, we have:
[tex]\begin{gathered} \frac{\sin A}{a}=\frac{\sin B}{b} \\ \\ \frac{\sin100}{3.5}=\frac{\sin B}{3} \\ \\ \sin B=\frac{3\sin 100}{3.5} \\ \\ \sin B=\frac{2.954}{3.5} \\ \\ \sin B=0.844 \end{gathered}[/tex]Take the sine inverse of both sides:
[tex]\begin{gathered} B=\sin ^{-1}(0.844) \\ \\ B=57.58^0 \end{gathered}[/tex]Therefore, the measue of angle B is = 57.58 degrees.
• To solve for angle C, apply the Triangle Angle Sum Theorem.
m∠A + m∠B + m∠C = 180
m∠C = 180 - m∠A - m∠B
m∠C = 180 - 100 - 57.68
m∠C = 22.32
The measure of angle C is 22.32 degrees.
• To find the length of c, apply the Law of Sines:
[tex]\begin{gathered} \frac{\sin A}{a}=\frac{\sin C}{c} \\ \\ \frac{\sin100}{3.5}=\frac{\sin 22.32}{c} \\ \\ c=\frac{3.5\sin 22.32}{\sin 100}\tan ^{-1}\tan ^{-1} \\ \\ c=\frac{1.329}{0.9848} \\ \\ c=1.35 \end{gathered}[/tex]The length of side c is 1.35 units.
ANSWER:
• B = 57.58,°
,• C = 22.32,°
,• c = 1.35
It is question 16 pls help
Answer: yes it is 16 i did my work let me know if you want me to show my work
Step-by-step explanation:
An auto mechanic recommends that 3 ounces of isopropyl alcohol be mixed with a tankful of gas (14 gallons ) to increase the octane of the gasoline for better engine performance. At this rate, how many gallons of gas can be treated with a 16-ounce bottle of alcohol (You don’t need to translate or understand just solve the word problem please )
Let be "x" the number of gallons of gas that can be treated with a 16-ounce bottle of alcohol.
According to the information given in the exercise, 3 ounces of isopropyl alcohol should be mixed with 14 gallons of gas.
Then, you can set up the following proportion:
[tex]\frac{14}{3}=\frac{x}{16}[/tex]Now you have to solve for "x":
[tex]\begin{gathered} (16)(\frac{14}{3})=x \\ \\ \frac{224}{3}=x \\ \\ x\approx74.67 \end{gathered}[/tex]Therefore, the answer is:
[tex]\approx74.67\text{ }gallons[/tex]