If the velocity-time equation for a golf cart is v = (1 m/s) + (-0.5 m/s)t , then the initial velocity of the cart would be 1 m / s and the acceleration of the cart would be - 0.5 m / s² .
What is acceleration?The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds².
As given in the problem the velocity-time equation for a golf cart is
v = (1 m/s) + (-0.5 m/s)t ,
The initial velocity of the cart at t = 0 would be 1 m / s.
By differentiating the given equation of the velocity,
The acceleration of the cart would be -0.5 m / s.
Thus, the initial velocity would be 1 m / s and the acceleration would be -0.5 m / s.
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Use the velocity vs time graph below for objects A and B to answer the given question.If A has the greater value pick answer choice AIf B has the greater value pick answer choice Bif A = B pick answer choice =.Which object has the greater Instantaneous Velocity at t = 5s?
Given the velocity versus time graph of an object.
From the graph, the velocity of object A is constant as the line representing its velocity is horizontal. The velocity of object a is decreasing with time. That is, object B is decelerating.
From the graph, at t=5 s the value of the instantaneous velocity of object A is 0 m/s.
And the value of the instantaneous velocity of object B is the same throughout the graph. And the value is 4 m/s.
Thus the value of the instantaneous velocity of object B is greater than that of object A.
Thus the correct answer is B has the greater value
a lighthouse is located on a small island 3 km away from the nearest point p on a straight shoreline and its light makes four revolutions per minute. how fast (in km/min) is the beam of light moving along the shoreline when it is 1 km from p?
A lighthouse is located on a small island 3 km away from the nearest point p on a straight shoreline is the beam of light moving along the shoreline when it is 1 km from p is 83.78 km/min
3*10/9*8pi = dx/dt
80pi/3 = dx/dt
dx/dt = 83.78 km/min
Thus, the beam of light is sweeping along the shore at the rate of 83.78 km/min when the beam is 1 km from the point P and light makes four revolutions per minute.
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similar to the case in the experiment you use two rubber bands, side to side first, to hold a weight of 3 reference objects. then, as in the experiment, the bands are pulled apart in their free ends until they form an angle of 30 degrees with respect to the horizontal. what are the deformations observed in these bands? ...
Three units deformations observed in these bands.
What forces do a rubber band encounter?Elastic force is the force that permits some materials to regain their former shape after being stretched or crushed. Thus, a stretched rubber band is subject to an elastic force.
The rubber band experiment uses a straightforward rubber band to show entropic force and a refrigeration cycle. The rubber band experiment involves stretching and then releasing a rubber band while measuring its temperature.
Always acting in the opposite direction of motion is friction. This indicates that if friction is there, it cancels out some of the force driving the motion (if the object is being accelerated). This results in a decreased acceleration and a smaller net force.
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a 95 kg man lying on a surface of negligible friction shoves a 74 g stone away from himself, giving it a speed of 4.0 m/s. what speed does the man acquire as a result?
As a result of the law of conservation of momentum, the man will acquire a speed of 3 . 10⁻³ m/s
The law of conservation of momentum states thta:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Where:
u₁ , u₂ = initial velocity of object 1 and object 2
v₁ , v₂ = final velocity of object 1 and object 2
Since both the man and the shove are initially at rest, hence u₁ , u₂ = 0.
Therefore,
m₁v₁ + m₂v₂ = 0
Parameters given:
m₁ = 95 kg
m₂ = 74 gram = 74 . 10⁻³ kg
v₂ = 4 m/s
Plug these parameters into the equation:
95 . v₁ + 74 . 10⁻³ . 4 = 0
v₁ = 3 . 10⁻³ m/s
Hence, the man acquire a speed of 3 . 10⁻³ m/s, which is very small.
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Mr. Mangan now sees a hoard of zombies running toward him. There are toomany for him to fight, so he makes a run for it. Starting from rest andaccelerating at a rate of 7 m/s2, he reaches a final velocity of 25 m/s. Howmuch time did it take for him to reach his final velocity?
Given data
*The given initial velocity is u = 0 m/s
*The given acceleration is a = 7 m/s^2
*The given final velocity is v = 25 m/s
The formula for the time taken to reach his final velocity is given by the kinematic equation of motion as
[tex]\begin{gathered} v=u+at \\ t=\frac{v-u}{a} \end{gathered}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} t=\frac{25-0}{7} \\ =3.57\text{ s} \end{gathered}[/tex]Thus, the time taken to reach his final velocity is t = 3.57 s
A car starts from rest and reaches a speed of 26 m/s in 8.5 seconds. What is the acceleration of the car? Round to 4 decimal places if necessary
ANSWER
3.0588 m/s²
EXPLANATION
Given:
• The final speed of the car, v = 26 m/s
,• The initial speed of the car, u = 0 m/s - remember that it starts from rest
,• The time it takes the car to reach the final speed, t = 8.5 s
Find:
• The acceleration of the car, a
The speed of an object is given by the equation,
[tex]v=u+at[/tex]In this case, u = 0 m/s, so we have,
[tex]v=at[/tex]Solving for a and replacing the known values,
[tex]a=\frac{v}{t}=\frac{26\text{ }m/s}{8.5\text{ }s}\approx3.0588\text{ }m/s^2[/tex]Hence, the acceleration of the car is 3.0588 m/s², rounded to four decimal places.
during keon's golf drive, the angular velocity of his club is zero at the top of the backswing and 33 rad/s at the bottom of the downswing just before ball impact. the downswing lasts 0.29 s, and the distance from the club head to the axis of rotation is 1.88 m at the bottom of the downswing. what is the average tangential acceleration of the club during the downswing (in m/s2)?
The average tangential acceleration of the club during the downswing is 113.79 rad/s².
Centripetal acceleration is due to the change within the direction of tangential speed, whereas tangential acceleration is due to any trade inside the value of the tangential speed.
The tangential acceleration is while the rotational velocity adjustments, that is 0 for uniform circular motion. while vector speed adjustments path however not important. for this reason Tangential acceleration =zero. Angular acceleration is the trade in angular velocity divided by using time, whilst tangential acceleration is the change in linear speed divided through time.
given,
∆ ω = 33 rad/s
∆t = 0.29 sec
α = (change in ω)/(change in t)
α = 33 rad/s / 0.29 s = 113.79 rad/s²
tangential acceleration = r α = 1.88*113.79 = 213.93 m/s2
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10 N of force is applied to a spring and its length increases by 4 cm. If the spring is obeying Hooke's law, what will its extension be if 30 N of force is applied?
I think Twelve is the answer
a young weightlifter raises a weight from a height of 0.6 m to a height of 1.3 m in a time of 3.2 seconds. his applied force has put out an average power of 43 w. if the weight does not accelerate at all in the process, what must be its mass?
The mass is 20.038 Kg.
Mass is the amount of count in a physical body. it's also a degree of the frame's inertia, the resistance to acceleration while a net pressure is carried out. An item's mass additionally determines the power of its gravitational attraction to different bodies. The SI base unit of mass is the kilogram.
F = mg
Displacement of weight = h
= 0.7 m
work done by weight lifter W = F × h
W = (mgh)
= 0.7mg
work done in 3.2 seconds
power P = W/Δt = 0.7 mg/3.2
Given,
P = 43 W = 43 J/s
⇒ 0.7 mg/3.2 = 43 j/s
⇒ M = (43 × 3.2)/(0.7 × 9.8)
M = 20.038 Kg ans.
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In a resonance a turning fork of frequency 330hz produced the first loud sound when water level in a pipe was 17.8cm from the open-end ant the second at 57.3cm. calculate the wavelength of the sound, speed of sound in air, water level of the next resonant length ?
The wavelength, the speed of sound and the water level of the next resonant length (the fifth harmonics) are as follows;
The calculated wavelength of the sound from the tuning fork is 0.79 metersThe speed of the sound is 260.7 m/sThe water level of the fifth harmonics is 96.8 cmWhat is an harmonics of a sound wave?An harmonics are waves with a frequency that is an integer multiple of the fundamental frequency.
The given frequency of the sound wave, f = 330 hz
The first water level that gives the first loud sound, l₁ = 17.8 cm
The water level from the open end at the second loud sound, l₂ = 57.3 cm
First part;
The first harmonics that gives the fundamental frequency for the pipe is expressed as follows;
[tex]\dfrac{\lambda}{4} = l_1+e[/tex]
Where;
e = The distance to the antinode of the wave above the top of the pipe
The third harmonics is given by the formula
[tex]\dfrac{3\cdot \lambda}{4} = l_2+e[/tex]
[tex]\dfrac{3\cdot \lambda}{4}- \dfrac{\lambda}{4} = \dfrac{\lambda}{2} = (l_2+e) - (l_1+e) = l_2 - l_1[/tex]
[tex]\dfrac{\lambda}{2} = l_2 - l_1[/tex]
λ = 2 × (l₂ - l₁)
λ = 2 × (57.3 - 17.8) = 79
The wavelength of the wave, λ = 79 centimeters = 0.79 meters
Second part;
Speed of sound, v = f × λ
Therefore; v = 330 Hz × 0.79 m = 260.7 m/s
The speed of sound in air, v = 260.7 m/sThird part;
[tex]\dfrac{\lambda}{4} = l_1+e[/tex]
[tex]\dfrac{3\cdot \lambda}{4} = l_2+e[/tex]
Which gives; 3·(l₁ + e) = l₂ + e
3·l₁ + 3·e = l₂ + e
3·e - e = l₂ - 3·l₁
2·e = l₂ - 3·l₁
Therefore, 2·e = 57.3 - 3 × 17.8 = 2.9
e = 3.9 ÷ 2 = 1.95The water level for the next resonant length, which is the fifth harmonics, is given by the formula;
[tex]\dfrac{5\cdot \lambda}{4} = l_3+e[/tex]
Which gives;
[tex]l_3 = \dfrac{5\cdot \lambda}{4} - e[/tex]
Therefore;
[tex]l_3 = \dfrac{5\times 79 }{4} - 1.95 = 96.8[/tex]
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a satellite used in a cellular telephone network has a mass of 2440 kg and is in a circular orbit at a height of 660 km above the surface of the earth. part a what is the gravitational force fgrav on the satellite? take the gravitational constant to be g
Gravitational constant to be G = 6.67×10−11 N⋅m2/kg2 , the mass of the earth to be me = 5.97×1024 kg , and the radius of the Earth to be re = 6.38×106 m then Gravitational force Fgrav on the satellite is 19383.7 N
Given value for constant Gravitational G = 6.67 x 10-11 N.m²/kg²
Earth mass is M = 5.97 x 1024
Mass of the satellite m = 2440
Earth's radius RE = 6.38 x 106 m
Height of the satellite from the surface of the Earth = H = 700 km = 700 x 103 m = 0.7 x 106 m
Radius of the satellite = R
R = RE + H
R = 6.38x106 + 0.7x106
R = 7.08 x 106 m
Gravitational force of Earth on the satellite = Fg
F, GMm R2
F,= (6.67 * 10-11)(5.97* 104) (2440) (7.08 * 106)2
Fg = 19383.7 N
Free-fall acceleration at the surface of the Earth = g = 9.8 m/s2
Weight of the satellite at the surface of the Earth = W
W = mg
W = (2440)(9.8)
W = 23912 N
Ratio of the gravitational force on the satellite to it's weight on the surface = P
P = Fg/W
p= 19383/23912
P = 0.8106
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what is the maximum speed with which a 1200- kgkg car can round a turn of radius 95.0 mm on a flat road if the coefficient of static friction between tires and road is 0.60?
The maximum speed will be 0.74m/s
What is friction force?Friction, the force that resists a solid object from sliding or rolling over another. Frictional forces, such as the traction required to walk without slipping, can be beneficial, but they also present significant resistance to motion. About 20% of a car's engine power is expended to overcome the frictional forces of moving parts.
The speed that corresponds to the maximum centripetal force (Fₓ) that could be provided by the friction is given as:
f = Fₓ
f = μN is the friction force. where, μ is the coefficient of static friction and this is the maximum force the friction can provide.
Fₓ = mv²/r
N = mg (flat road)
Thus:
μ mg = mv²/r
So, according to the given question:
μ = 0.60
m = 1200kg
r = 95.0 mm or 95×10⁻³m
μ mg = mv²/r
0.60 × 9.8 = v²/ 95×10⁻³
v² = 558.6 ×10⁻³
v = 0.74m/s
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Both speed and velocity measure how fast something is moving. However, since speed is not a _________ it does not require a(n) ___________ .
Responses
A scalar, directionscalar, direction
B quantity, unitquantity, unit
C magnitude, unitmagnitude, unit
D vector, direction
you are given a 1/5 model of a car that normally runs at 30 mph. what wind tunnel speed should you use to test the car? (assume kinematic viscosity does not change and )
The wind tunnel speed that must be used to test the car 1 / 5 model of a car that normally runs at 30 mph is 150 mph
Re = u L / ν
Re = Reynold's number
u = Flow speed
L = Characteristic linear dimension
ν = Kinematic viscosity
ν[tex]_{p}[/tex] = 1.516 * [tex]10^{-5}[/tex] m² / s
ν[tex]_{p}[/tex] = ν[tex]_{m}[/tex] = 1.516 * [tex]10^{-5}[/tex] m² / s
L[tex]_{m}[/tex] = L[tex]_{p}[/tex] / 5
u[tex]_{p}[/tex] = 30 mph
Re[tex]_{m}[/tex] = u[tex]_{m}[/tex] L[tex]_{p}[/tex] / 5 * 1.516 * [tex]10^{-5}[/tex]
Re[tex]_{p}[/tex] = 30 L[tex]_{p}[/tex] / 1.516 * [tex]10^{-5}[/tex]
In tunnel,
Re[tex]_{m}[/tex] = Re[tex]_{p}[/tex]
u[tex]_{m}[/tex] L[tex]_{p}[/tex] / 5 * 1.516 * [tex]10^{-5}[/tex] = 30 L[tex]_{p}[/tex] / 5 * 1.516 * [tex]10^{-5}[/tex]
u[tex]_{m}[/tex] = 30 * 5
u[tex]_{m}[/tex] = 150 mph
Therefore, the wind tunnel speed that must be used to test the car is 150 mph
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If a magnifying glass uses a convex lens of focus length 6.25 cm when it is held 5.20 cm in front of an object what is the image distanceMind your minus signs Unit cm
Answer:
30.95 cm
Explanation:
The focal length f, the object distance do, and the image distance di are related with the following equation:
[tex]\frac{1}{f}=\frac{1}{d_0}+\frac{1}{d_i}[/tex]So, replacing the values, we get:
[tex]\frac{1}{6.25}=\frac{1}{5.20}+\frac{1}{d_i}[/tex]Then, solving for di, we get:
[tex]\begin{gathered} \frac{1}{6.25}-\frac{1}{5.2}=\frac{1}{d_i} \\ -\frac{21}{650}=\frac{1}{d_i}_{} \\ -\frac{650}{21}=d_i \\ -30.95\operatorname{cm}=d_i \end{gathered}[/tex]Therefore, the image distance is 30.95 cm
a car is traveling at 100 mph down the highway. at some time the driver sees an obstruction in the road and slams on the brakes skidding to a halt reducing its kinetic energy to zero. what happened to the kinetic energy of the car?
The kinetic energy is changed to thermal energy by brake friction and turns to zero.
We need to know about kinetic energy to solve this problem. Kinetic energy is the energy from a moving object. It can be determined as
KE = 1/2 . m . v²
where KE is kinetic energy, m is mass and v is speed.
From the question above, we know that
v1 = 100 mph
KE2 = 0 joule
When the car moves at 100 mph, the car has kinetic energy. But on the way when the driver brakes the car, the kinetic energy is changed to thermal energy by brake friction. Hence, the kinetic energy is reduced every time and finally turns to zero.
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If you wanted to visit a area with very little wind whear might you go
Answer:Ohio
Explanation:
A force of 10 n stretches a particular spring by 2 cm. How far would a 20 n force stretch that same spring?.
For the same spring, the value of spring constant must be same. The relation between the force and the spring constant is given by Hooke's law
so, 20 N force stretch 4 cm.
What is the Hooke's law ?Hooke's law is a law of elasticity discovered by the English scientist Robert Hooke in 1660 that states that the displacement or size of a deformation is directly proportional to the deforming force or load for relatively small deformations of an object.It is the fundamental principle underlying the manometer, spring scale, and clock balance wheel. Hooke's law is the underlying principle of seismology, acoustics, and molecular mechanics.Hooke's spring law usually applies to any elastic object of any complexity, as long as the deformation and stress can be expressed by a single number that can be both positive and negative.For the same spring, the value of spring constant must be same. The relation between the force and the spring constant is given by Hooke's law as :
F=kx
where
F = Force
k = is spring
constant
x = stretches
here
10/ 2 = 20/ x
x -= 4 cm .
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the circuit breaker that protects a power window circuit opens whenever the window is lowered. technician a says the internal resistance of the motor is too high. technician b says the window regulator may be sticking causing high mechanical resistance. who is correct?
Both technicians A and B are correct. Hence, option C.
An ammeter is used to measure the electrical current in the circuit. An ammeter should be placed into series with the circuit being tested.
The ammeter can be connected either on the power side or on the ground side of the motor but the only condition is it should be connected in the series.
Internal resistance refers back to the opposition to the float of cutting-edge supplied by using the cells and batteries themselves ensuing inside the era of heat. internal resistance is measured in Ohms. the connection among inner resistance (r) and emf (e) of cell s given through. e = I (r + R)
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Disclaimer:- your question is incomplete, please see below for the complete question.
The circuit breaker that protects a power window circuit opens whenever the window is lowered. technician a says the internal resistance of the motor is too high. technician b says the window regulator may be sticking causing high mechanical resistance. who is correct?
A. A only
B. B only
C. Both A and B
D. Neither A nor B
Calculator A dog has a kinetic energy of 111J and is running at a speed of 10m/s. What is the mass of the dog? Give your answer to 2 decimal places.
Explanation:
MASS=2.22
VELOCITY=10m/s
KINETIC ENERGY=111
PLEASE MARK ME AS BRILLIANT
a powerful motorcycle can produce an acceleration of while traveling at 90.0 km/h. at that speed, the forces resisting motion, including friction and air resistance, total 400.0 n. (air resistance is analogous to air friction. it always opposes the motion of an object.) what is the magnitude of the force that motorcycle exerts backward on the ground to produce its acceleration if the mass of the motorcycle with rider is 245 kg? 34. a car with a mass o
1257.5 N is the magnitude of the force that motorcycle exerts backward on the ground to produce its acceleration.
What is a magnitude in physics?The definition of magnitude is simply "distance or quantity." It displays an object's size, direction, or speed, whether relative or absolute. It's used to indicate that something has a certain size or scope.
Briefing:A = 3.50 m/s² is the motorcycle's acceleration.
f = 400.0 N, the force of resistance to motion
M = 245 kg for the motorcycle's mass
F is the amount of force a motorcycle exerts when moving rearward.
The amount of force a motorcycle exerts when moving rearward is described as
F = f + ma
Inserting the values
F = 400.0 + (245) (3.50)
F = 1257.5 N
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The complete question is -
A powerful motorcycle can produce an acceleration of 3.50 m/s² while traveling at 90.0 km/h. At that speed, the forces resisting motion, including friction and air resistance, total 400.0 N. (Air resistance is analogous to air friction. It always opposes the motion of an object.) What is the magnitude of the force that motorcycle exerts backward on the ground to produce its acceleration if the mass of the motorcycle with rider is 245 kg?
A force of 2.0 × 102 newtons is applied to a lever to lift a crate. If the mechanical advantage of the lever is 3.43, what is the weight of the crate?
A force of 2.0 × 10² newtons is applied to a lever to lift a crate. If the mechanical advantage of the lever is 3.43, then the weight of the crane would be 686 Newtons.
What is the mechanical advantage?Mechanical advantage is defined as a measure of the ratio of output force to input force in a system, It is used to analyze the forces in simple machines like levers and pulleys.
Mechanical advantage = output force(load) /input force (effort)
As given in the problem a force of 2.0 × 10² newtons is applied to a lever to lift a crate. If the mechanical advantage of the lever is 3.43,
The weight of the crane = 200 × 3.43
= 686 Newtons
Thus, the weight of the crane would be 686 Newtons.
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a very thin horizontal, 2.00-m long, 5.00-kg uniform beam that lies along the east-west direction is acted on by two forces. at the east end of the beam, a 200-n force pushes downward. at the west end of the beam, a 200-n force pushes upward. what is the angular acceleration of the beam?
The angular acceleration of the beam of length 2 meters and mass 5 kg is 240 radian/s².
The length of the rod is 2 meters, the mass of the rod is 5kg, a force of 200N is applied downward in the east direction while a force of 200N applied upward in west direction.
We know,
That the torque on a body is,
T = Fr
T is torque,
F is the force,
r is the perpendicular distance from the axis of rotation.
So, assuming the centre of the beam as the axis of rotation, the torque on the body is,
T = 200(1)+200(1)
T = 400N-m
We also know,
That torque on the body is,
T = IA
Where I is moment of inertia of the beam,
A is the angular acceleration of the body,
We know, moment of inertia of the beam assuming the centre of the rod as axis of rotation is,
I = MR²/12
M is the mass of the body,
R is the length of the rod,
So,
I = 5(2)²/12
I = 20/12 kg-m²
So, now we can write,
T = 20/12A
As both are value of torque, so,
20/12A = 400
A = 240 radian/s²
The angular acceleration is 240 radian/s².
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Need help putting all of these in the correct spots.
Physical property- color, density, melting point, boiling point, hardness Chemical property- neutralizes an acid, reacts with base to form water, reacts with water to form gas, neutralizes a base, flammability.
What is the physical property?A quality of matter that is unrelated to a change inside its chemical makeup is called a physical property. Density, colour, hardness, melting & boiling points, and conductivity are a few common instances of physical qualities.
How are physical properties observed?Without altering the makeup of the substance, physical qualities can be seen or quantified. In order to observe and describe matter, physical attributes are used. The following are only a few examples of physical characteristics: appearance, texture, colour, smell, melting and boiling points, density, solubility, polarity, and many more.
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a car is traveling at on a horizontal highway. if the coefficient of kinetic friction between road and tires on a rainy day is , what is the minimum distance (in m) in which the car will stop?
The minimum distance in which car will stop is 256m.
What is distance?
distance is the length of the space between two points.
distance is a numerical or its the occasionally qualitative measurement of how to far apart objects or points .
Sol-here we can apply Newton’s second law to the car of to determine of the maximum static friction to the force acting on the car:
€Fy=ma^y+ n-mg=0
Fs≤us mg
This maximum magnitude of static friction acts so long as the tires roll without skidding.
€Fx=ma^x-----> -fs=ma
The maximum acceleration is
a=-u^s g
The initial and final conditions are- xi=0, vi=50.0mi/h =22.4 m/s and vf =0.Then,
v^2=v^2+2a(xf-xi)---->v^2
f i I
Xf=(22.4m/s)^2/2(0.100)(9.80m/s^2)=256
Thus through the minimum distance in which car will stop is 256m.
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how do astronomers measure that sunspots come in north pole / south pole magnetic pairs? how do they view the sun's magnetic field? from helioseismology and doppler shifts spectral lines can be split into multiple lines, further apart the stronger the magnetic field is from neutrino telescopes revealing where the proton-proton chain is broken from the motion of iron filings naturally streaming out of the radiation zone
The Zeeman effect, a feature of atoms, is used to quantify the solar magnetic field. To do this, scientists look at the spectral lines that originate from sunspots and calculate by how much these lines are split.
The Zeeman effect is the result of a spectral line splitting into many components when a static magnetic field is present. It bears the name Pieter Zeeman after the Dutch physicist who made the discovery in 1896 and won the Nobel Prize for it. The magnetic dipole interaction between the nuclear spin moment and the internal magnetic field at the nucleus is what causes magnetic splitting (also known as the nuclear Zeeman effect). Three different varieties of the Zeeman Effect can be seen: the standard Zeeman effect, the anomalous Zeeman effect, and the diamagnetic Zeeman effect. The Zeeman effect is the splitting of atomic energy levels caused by an external magnetic field. This effect is also known as the Bohr's Magneton and is further characterised by orbital and spin angular momentum.
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Study the graph shown below. It is a graphic of a car trip taken by Amber and Ken. The starting position (0,0) is their home.
Graph of position versus time, with position on the y axis from 0 to 75 miles and time on the x axis from 0 to 8.5 hours. Segment 1 goes from 0,0 to 1,30. Segment 2 goes from 1,30 to 3,50. Segment 3 goes from 3,50 to 4,50. Segment 4 goes from 4,50 to 5,70. Segment 5 goes from 5,70 to 6,70. Segment 6 goes from 6,70 to 7,30. Segment 7 goes from 7,30 to 8,0.
How far had they traveled after four hours of travel?
a
30 miles
b
40 miles
c
50 miles
d
60 miles
The distance that they had traveled after four hours is given by:
c 50 miles.
How to find the distance traveled?We are given the a set of points (x,y) in this problem, in which the input and the output are defined as follows:
Input: x is the number of hours.Output: y is the distance traveled, in miles, after a time of x hours.The endpoints of the segments are as follows:
(0,0): Initially, 0 miles were traveled.(1,30): 30 miles were traveled in one hour.(3, 50): 50 miles were traveled in three hours.(4,50): 50 miles were traveled in four hours.Hence, the distance that they had traveled after four hours is given by 50 miles, and option c is the correct option in the context of this problem (how long they had traveled).
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the spacecraft voyager was launched and continues traveling in space, even though it doesn't have an engine that pushes it forward. the fact that voyager travels in space is an example of
The fact that voyager travels in space is an example of Newton's First Law of Motion.
What are Newton's Laws of Motion?
Newton's laws of motion are three basic laws of classical mechanics that describe the relationship between the motion of an object and the forces acting on it. These laws can be paraphrased as follows:
A body remains at rest, or in motion at a constant speed in a straight line, unless acted upon by a force.When a body is acted upon by a force, the time rate of change of its momentum equals the force.If two bodies exert forces on each other, these forces have the same magnitude but opposite directions.When the voyager was launched, it was already moving forward in motion. So, because of the Newton's First law of motion the voyager remained in motion as there is no air friction present in the space to stop its motion.
Thus, this situation is an example of Newton's First law of motion.
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Scripture Spotlight: Proverbs 6:6-11
the term sluggard comes from slugs, which move like snails, s-l-o-w-l-y. What is the message of the above passage? Read it in several Bible versions
Answer: A sluggard is someone who is habitually lazy or inactive. Such a person does not take personal responsibility for his own life. The word sluggard is used 14 times in the book of Proverbs. In each case, the Bible condemns laziness and warns of the consequences of being a sluggard.
Proverbs 6:9 asks two rhetorical questions, highlighting one of the main traits of a sluggard: “How long will you lie there, you sluggard? / When will you get up from your sleep?” Verse 6 tells the sluggard to learn a lesson from an industrious insect: “Go to the ant, you sluggard; / consider its ways and be wise!”
Explanation:
a group of students are provided with three objects all of the same mass and radius. the objects include a solid cylinder, a thin hoop (or cylindrical shell), and a solid sphere. the students are asked to predict which will get to the bottom of a ramp first if all three are released together from the same distance up the ramp. which prediction is correct if the objects are listed in order from fastest to slowest?
Sphere, cylinder, hoop is the correct prediction. Moment of inertia is defined as the quantity represented by a body that resists an angular acceleration that is the sum of the product of each particle's mass times the square of its distance from the axis of rotation.
Ball moment of inertia Is = 2/5 M r²
Cylinder Ic = ½ M r²
Tire Ih = M r²
Substitute each to calculate time
Ball
ts = (d / √2gy) √ ( 1 + 2/5 Mr² / mr²)
ts = (d / √ 2gy) √ (1 +2/5) = (d / √ 2gy) √(1.4)
ts = (d / √ 2gy) 1.1
Cylinder
tc = (d / √2gy) √ (1 + 1/2 Mr² / Mr²)
tc = (d / √2gy) √ (1 + ½) = (d / √ 2gy) √ 1.5
tc = (d / √ 2gy ) 1.2
tires
th = (d / √2gy) √ (1 + mr² / mr²)
th = (d / √2gy) √(1 + 1) = (d / √ 2gy ) √ 2
th = ( d / √ 2gy) 1.41
The result is that the bullet hits the fastest and the body with the most tires. So the correct answer is
ts < . tc < th
ball, cylinder tire
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