Answer: 490
Explanation:
Metal reactivity
a. increases
b. decreases
from left to right in the periodic table.
C. stays the same
d. can increase or decrease depending on the
element
Answer:
i think its A
Explanation:
What the density of pure water?
a)1.0kg/l
b) 0.1 kg/l
c)100kg/l
d)10kg/l
Answer:
a) 1.0(kg/l) = 1 [kg/Lt]
Explanation:
The density of pure water is taken as 1000 [kg/m3], now we must convert the units to (kg/liters)
[tex]1000[\frac{kg}{m^{3}}]*\frac{1m^{3} }{1000Lt} = 1000[\frac{kg}{lt} ][/tex]
1st block
Worksheet: Metric Prefixes
A. Circle the larger unit:
1.millimeter, centimeter
2. kilogram, megagram
3. microsecond, millisecond
4.dL, mL
5.mg, kg
6. Mm,mm
7. S, cs
8. M, mm
9. U s, ks
Solution:
1. millimeter, centimeter
1 centimeter = 10 millimeter
So, centimeter is the larger unit here.
2. kilogram, megagram
1 megagram = 1000 kilogram
So, megagram is the larger unit here.
3. microsecond, millisecond
1 millisecond = 1000 microsecond
So, millisecond is the larger unit here.
4.dL, mL
1 dL = 100 mL
So, dL is the larger unit here.
5.mg, kg
1 mg = 0.000001 kg
So, kg is the larger unit here.
6. Mm,mm
1 mm = 1 mm
Both are same
7. S, cs
1 second = 100 centisecond
So, S is the larger unit.
8. M, mm
1 M = 1000 mm
So, M is the larger unit here.
9. U s, ks
Us is larger.
Scientists launch a rocket, and they monitor its acceleration and the force exerted by its engines. As the rocket gets higher, the monitors show that the acceleration of the rocket is increasing but the force exerted stays the same. How do Newton’s laws explain why the scientists could expect this to happen? The total force stays the same, but the action force is increasing as the reaction decreases. The mass of the rocket decreases as fuel is burned, so the acceleration increases. The inertia of the rocket increases, which reduces the force needed to change its speed. The reaction force is increasing as fuel is burned, which causes a greater acceleration.
Newton’s laws explain why scientists could expect this to happen , The mass of the rocket decreases as fuel is burned, so the acceleration increases, therefore the correct answer is option B.
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum. The mathematical expression for Newton's second law is as follows
As given in the problem Scientists launch a rocket, and they monitor its acceleration and the force exerted by its engines. As the rocket gets higher, the monitors show that the acceleration of the rocket is increasing but the force exerted stays the same.
Newton's laws clarify why scientists may anticipate this to occur. The right response is option B because as fuel is burnt, the rocket's mass reduces, and its acceleration rises.
Learn more about Newton's second law here,refer to the link given below ;
brainly.com/question/13447525
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An rescue airplane flies horizontally over level terrain with a speed of 251 m/s and at an altitude of 2.73 km. The airplane releases one package. (a) How far does the package travel horizontally between its release and its impact on the ground? Ignore air resistance. m (b) If the pilot maintains the airplane's original course, altitude, and speed, where will the plane be when the package hits the ground? Ignore air resistance. behind the bomb directly above the bomb ahead of the bomb (c) The package hits the target seen in the airplane's telescopic "bombsight" at the moment of the package's release. At what angle from the vertical was the bombsight set? ° from the vertical
Answer:
a) x = 5923.6 m , b) directly above the bomb ahead of the bomb,
c) θ = 65.3º
Explanation:
This is a projectile launching exercise
a) As the package is released from the plane at its same speed, vox 0 251 m / s, they indicate that the plane flies horizontally, therefore the initial vertical speed is zero, let's calculate the time of arrival to the ground
y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²
to the ground y = 0
0 = y₀ + 0 - ½ g t²
t = √ (2y₀ / g)
t = √ (2 2730 / 9.8)
t = 23.60 s
the horizontal distance traveled is
x = v₀ₓ t
x = 251 23.6
x = 5923.6 m
b) since there is no acceleration on the x-axis and it is indicated that the air resistance is zero in part it must be just below the plane
directly above the bomb ahead of the bomb
c) for this part we can use trigonometry
since the angle with respect to the vertical is requested, the opposite leg is the horizontal distance
tan θ = x / y
θ = tan⁻¹ (x / y)
θ = tan⁻¹ (5923.6 / 2730)
θ = 65.3º
What must be the units for the gravitational constant G in order for gravitational force to have units of newtons?
m3/(kg⋅s)
m3/(kg2⋅s2)
m3/(kg2⋅s)
m3/(kg⋅s2)
Answer:
m³/(kg⋅s²)
Explanation:
Hello.
In this case, since the involved formula is:
[tex]F=G*\frac{m_1m_2}{r^2}[/tex]
By writing a dimensional analysis with the proper algebra handling, we obtain:
[tex]N[=]G*\frac{kg*kg}{m^2}\\ \\kg*\frac{m}{s^2}[=]G *\frac{kg*kg}{m^2}\\\\G[=]\frac{kg*m*m^2}{kg^2*s^2}\\ \\G[=]\frac{m^3}{kg*s^2}[/tex]
Thus, answer is:
m³/(kg⋅s²)
Note that the [=] is used to indicate the units of G.
Best regards
3. How does the resistance of the light bulbs differ when the bulbs are cold and when the bulbs are hot? Why do you think this happens?
Answer:
the hot bulb will have high resistance to the flow of current. While the cold bulb will have a low resistance to the flow of current.
Explanation:
A conductor that does not obey Ohm's law is described as non - ohmic. An example is a filament lamp. It glows as the current passes through it.
How does the resistance of the light bulbs differ when the bulbs are cold and when the bulbs are hot ?
The resistance of the light bulbs increase gradually as its temperature is increased.
So, the hot bulb will have high resistance to the flow of current. While the cold bulb will have a low resistance to the flow of current.
Because the resistance of an impure metal wire is greater than the resistance of a pure metal wire of the same dimension.
An object experiences a net acceleration to the left. Which of the following statements about this object are true? There may be more than one true statement below. Group of answer choices If there is one force to the left on the object, there must at least be one force on it to the right as well. There must be two or more forces on the object. The object cannot be slowing down. The net force on the object is to the right. If there is one force down on the object, there must at least be one force up on it as well. If the mass of the object was doubled, it would experience an acceleration of half the magnitude. Assume the forces on the object are unchanged. The object might be in equilibrium. If the mass of the object were halved, it would experience an acceleration to the right. Assume the forces on the object are unchanged. The net force on the object is to the left.
Answer:
When an object experiences acceleration to the left, the net force acting on this object will also be to the left.If the mass of the object was doubled, it would experience an acceleration of half the magnitudeExplanation:
When an object experiences acceleration to the left, the net force acting on this object will also be to the left.
From Newton's second law of motion, the acceleration of the object is given as;
a = ∑F / m
a = -F / m
The negative value of "a" indicates acceleration to the left
where;
∑F is the net force on the object
m is the mass of the object
At a constant force, F = ma ⇒ m₁a₁ = m₂a₂
If the mass of the object was doubled, m₂ = 2m₁
a₂ = (m₁a₁) / (m₂)
a₂ = (m₁a₁) / (2m₁)
a₂ = ¹/₂(a₁)
Therefore, the following can be deduced from the acceleration of this object;
When an object experiences acceleration to the left, the net force acting on this object will also be to the left.If the mass of the object was doubled, it would experience an acceleration of half the magnitudeA snapshot of three racing cars is shown in the diagram. All three cars start the race at the same time, at the same place, and move along a straight track. As they approach the finish line, which car has the lowest average speed?
Answer:
The car furthest from the finish line: Car III (Choice C).
Explanation:
It's asking for lowest average speed throughout the entire race. Therefore, whoever is last technically has the lowest average speed.
Car III is far behind Car I and Car II so Choice A and B aren't correct. Choice D is incorrect since the three cars aren't in the same position. Choice E is incorrect because there is enough information to see that Choice C has the lowest average speed.
A cloud mass moving across the ocean at an altitude of 2000 m encounters a coastal mountain range. As it rises to a height of 3500 m to pass over the mountains, it undergoes an adiabatic expansion. The pressure at 2000 m is 0.802 atm and at 3500 is 0.602 atm. If the initial temperature of the cloud mass is 288 K, what is the cloud temperature as it passes over the mountains? Assume that Cp,m for air is 28.86 J K-1 mol-1 and that the air obeys the ideal gas law. If you are on the mountain, should you expect rain or snow?
Answer:
snow
Explanation:
Since the process undergoes adiabatic expansion, hence q = 0 and ΔU = w.
We can sole this problem using the following derivation:
[tex]ln(\frac{T_2}{T_1} )=-(\gamma -1)ln(\frac{V_f}{V_i} )=-(\gamma -1)ln(\frac{T_2}{T_1}\frac{P_i}{P_f} )\\=-(\gamma -1)ln(\frac{T_2}{T_1})-(\gamma -1)ln(\frac{P_i}{P_f})\\=-(\frac{\gamma -1}{\gamma})ln(\frac{P_i}{P_f})\\=-(\frac{\frac{C_{p,m}}{C_{p,m}-R} -1}{\frac{C_{p,m}}{C_{p,m}-R}})ln(\frac{P_i}{P_f})\\\\ln(\frac{T_2}{T_1} )==-(\frac{\frac{C_{p,m}}{C_{p,m}-R} -1}{\frac{C_{p,m}}{C_{p,m}-R}})ln(\frac{P_i}{P_f})\\\\Substituting\ values:\\\\[/tex]
[tex]ln(\frac{T_2}{T_1} )=-(\frac{\frac{28.86}{28.86-8.314} -1}{\frac{28.86}{28.86-8.314}})ln(\frac{0.802\ atm}{0.602\ atm})=-0.0826\\\\ln(\frac{T_2}{T_1} )=-0.0826\\\\Taking\ exponential\ of\ both \ sides:\\\\\frac{T_2}{T_1} =e^{-0.0826}\\\\T_2=0.9207T_1\\\\T_2=0.9207*288\\\\T_2=265\ K\\[/tex]
Since T2 = 265 K, we should expect a snow
The electric field everywhere on the surface of a thin, spherical shell of radius 0.710 m is of magnitude 936 N/C and points radially toward the center of the sphere. (a) What is the net charge within the sphere's surface? nC (b) What is the distribution of the charge inside the spherical shell? The positive charge has an asymmetric charge distribution. The negative charge has an asymmetric charge distribution. The positive charge has a spherically symmetric charge distribution. The negative charge has a spherically symmetric charge distribution.
Explanation:
Given that,
Radius of a spherical shell, r = 0.71 m
Electric field that points radially toward the center of the sphere is 936 N/C
(a) Let q is the net charge within the sphere's surface. Using Gauss's law, we can find it :
[tex]\dfrac{1}{q}\times \epsilon_0=EA\\\\q=\dfrac{\epsilon_0}{EA}\\\\q=\dfrac{8.85\times 10^{-12}}{936\times \pi \times (0.71)^2}\\\\q=5.97\times 10^{-15}\ C[/tex]
(b) Gauss's law is used to find the amount of charge enclosed within a surface. It doesn't say anything about the distribution of the charge inside the spherical shell.
A student pushes a 0.5 kg lab cart with a force of 3 Newtons. Determine the acceleration of the cart in
m/s2.
Answer:
The acceleration is 6 [tex]\frac{m}{s^2}[/tex]
Explanation:
Use Newton's second law to solve the problem:
[tex]Force = mass\,\,*\,\,acceleration\\3\,N = 0.5\,\,kg\,*\,a\\a = \frac{3}{0.5} \frac{m}{s^2} \\a=6\,\,\frac{m}{s^2}[/tex]
the acceleration of the cart given its mass and force exerted is 6m/s².
Given the data in the question;
Mass of lab cart; [tex]m = 0.5kg[/tex]
Force applied; [tex]F = 3N[/tex]
Acceleration of cart; [tex]a = \ ?[/tex]
To determine the acceleration of the cart, we use the expression from Newton's second law of Motion:
[tex]F = m* a[/tex]
Where F is force exerted, m is mass and a is acceleration
We substitute our given values into the equation
[tex]3N = 0.5kg \ * \ a\\\\3kgm/s^2 = 0.5kg\ *\ a\\\\a = \frac{3kgm/s^2}{0.5kg} \\\\a = 6m/s^2[/tex]
Therefore, the acceleration of the cart given its mass and force exerted is 6m/s².
Learn more: https://brainly.com/question/15839425
A student throws a ball straight down off a very high building with a magnitude of 3m/s and
accelerates in free fall for 2.0 s.
What is the velocity of the ball at 2.0 s?
Answer:
Vf = 22.62 [m/s] in 2 seconds.
Explanation:
In order to solve this problem we must use the following kinematics equation
[tex]v_{f} = v_{i} + (g*t)[/tex]
where:
Vf = final velocity [m/s]
Vi = initial velocity = 3 [m/s]
g = gravity acceleration = 9.81 [m/s^2]
t = time = 2 [s]
Vf = 3 + (9.81*2)
Vf = 22.62 [m/s]
In this example, we will consider conservation of momentum in an isolated system consisting of an astronaut and a wrench. An astronaut is floating in space 100 m from her ship when her safety cable becomes unlatched. She and the ship are motionless relative to each other. The astronaut's mass (including space suit) is 100 kg; she has a 1.0 kg wrench and only a 20 minute air supply. Thinking back to her physics classes, she devises a plan to use conservation of momentum to get back to the ship safely by throwing the wrench away from her. In what direction should she throw the wrench
Answer:
She must throw it in the opposite direction away from herself and the ship at a velocity of -8.33 m/s.
Explanation:
She must throw it in the opposite direction away from herself and the ship. To find the velocity with which she throws it, we consider the law of conservation of momentum.
Since initial momentum = final momentum and the initial momentum of the astronaut and wrench = 0
0 = final momentum
0 = mv + MV where m = mass of wrench = 1.0 kg, v = velocity of wrench, M = mass of astronaut + suit = 100 kg and V = velocity of astronaut.
So. mv = -MV
v = -MV/m
Now, if the astronaut is supposed to cover a distance of 100 m from the space ship in 20 minutes, her velocity should be, V = distance/time = 100 m/ 20 min = 100 m/(20 × 60 s) = 100 m/1200 = 0.0833 m/s
So v = -MV/m
= -100 kg × 0.0833 m/s ÷ 1.0 kg
= -8.33 m/s
She must throw the wrench in the opposite direction away from herself and the ship at a velocity of -8.33 m/s.
What are the products in the reaction in the introduction above? Select all that apply.
1: H2O
2: catalase
3:H2O2
4:O2
Answer:
h2o and o2
Explanation:
015
10.0 points
A car traveling in a straight line has a velocity
of 5.25 m/s at some instant. After 4.27 s, its
velocity is 9.38 m/s.
What is its average acceleration in this time
interval?
Answer in units of m/s.
Divide the change in speed by the given time:
a = (9.38 m/s - 5.25 m/s) / (4.27 s) ≈ 0.967 m/s²
A physics student rolls a ball down a hill with an initial velocity of 2.5m/s. If it accelerates down the hill at a rate of 6.3m/s^2, How long will it take to reach the bottom of the hill, 150 meters away?
Please help!!!
I'll assume you mean the hill is 150 m along its slope, since that's the direction the ball rolls.
The distance x it rolls after time t is
x = (2.5 m/s) t + 1/2 (6.3 m/s²) t²
Set x = 150 m and solve for t :
150 m = (2.5 m/s) t + 1/2 (6.3 m/s²) t²
(3.15 m/s²) t² + (2.5 m/s) t - 150 m = 0
t = 1/2 [(-2.5 m/s) + √((2.5 m/s)² - 4 * (3.15 m/s²) * (-150 m))]
(Use the quadratic formula, and take the positive root)
t ≈ 6.52 s
Imagine you are standing in the hallway. If the gravitational field strength were to suddenly double, what would change?
Answer:
If the gravitational field strength were to suddenly double while I was standing in the hallway, I'd suddenly feel like heavier.
Explanation:
The weight of a matter is given as the production between it's mass and the acceleration of gravity.
Mathematically, this is expressed as:
m x g that is m.g or mg.
Where m = mass and
g = gravity.
If the value of gravity was to double then weight (w) will become
w = m×2g
Assume for a moment that before the increase m was 5 and g was 5, it means that w would be 25.
But if g doubled, then we would have
w = 5 x 10
which is equals 50.
Thus, with the increase in gravitational field strenght, I'd find myself exerting more effort to stand upright, jump or run.
Cheers!
What is the difference in quark model of a meson and a baryon?
The coordinate of a particle in meters is given by x(t)=1 6t- 3.0t , where the time tis in seconds. The
particle is momentarily at rest at t is:
Select one:
a. 9.3s
b. 1.3s
C. 0.75s
d.5.3s
e. 7.3s
Complete question:
The coordinate of a particle in meters is given by x(t)=1 6t- 3.0t³ , where the time tis in seconds. The
particle is momentarily at rest at t is:
Select one:
a. 9.3s
b. 1.3s
C. 0.75s
d.5.3s
e. 7.3s
Answer:
b. 1.3 s
Explanation:
Given;
position of the particle, x(t)=1 6t- 3.0t³
when the particle is at rest, the velocity is zero.
velocity = dx/dt
dx /dt = 16 - 9t²
16 - 9t² = 0
9t² = 16
t² = 16 /9
t = √(16 / 9)
t = 4/3
t = 1.3 s
Therefore, the particle is momentarily at rest at t = 1.3 s
a piano dropped from a plane in the air. As it falls, upward force of air resistance gets greater as the piano picks up speed eventually, the resistance forces equal to the downward force of gravity. the piano now
Answer:
When the piano is dropped, the first force acting on it will be the gravitational force, that accelerates the piano at 9.8m/s^2 downwards.
As the piano accelerates, the velocity increases, now appears other force, the air resistance, that opposes to the motion of the piano.
As the velocity of the piano increases, also does the force that the air applies on the piano.
There is a point where the velocity of the piano is such that the air resistance is equal in magnitude, but in the opposite direction, to the force of gravity.
Then the net force on the piano is zero, which means that there is no acceleration, so the piano will keep falling down at constant velocity after this point.
The kinetic energy of an object depends upon its speed and its... what?
Answer:
Mass
Explanation:
kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity (speed) squared.
The distance, x, covered by a particle in time, t, is given as x=a +bc+ct^2 +dt^3
.find the dimension of the constants a, b, c and d
Answer:
[tex]a[/tex] has units of distance
[tex]b[/tex] has units of distance over time
[tex]c[/tex] has units of distance over [tex]time^2[/tex]
[tex]d[/tex] has units of distance over [tex]time^3[/tex]
Explanation:
Since the expression for the distance is:
[tex]x = a+b\,t+c\,t^2+d\,t^3[/tex]
then:
[tex]a[/tex] has units of distance
[tex]b[/tex] has units of distance over time
[tex]c[/tex] has units of distance over [tex]time^2[/tex]
[tex]d[/tex] has units of distance over [tex]time^3[/tex]
because we are supposed to be able to add all of the terms and get a distance. So the products on each term that contains factors of time (t) should be cancelling those time units with units in the denominator of the multiplicative constant s that accompany them.
what determines the amplitude of a wave of the type shown
Atoms are spherical in shape. Therefore, the Pt atoms in the cube cannot fill all the available space. If only 74.0 percent of the space inside the cube is taken up by Pt atoms, calculate the radius in picometers of a Pt atom. The mass of a single Pt atom is 3.240 × 10−22 g. [The volume of a sphere of radius r is (4/3) πr3. The volume of a cube is l3, where l is the length of a side. Avogadro's number is 6.022 × 1023.]
Answer:
A)6.6×10^22atoms of Pt in the cube
B)1.4×10^-8m
Explanation:
(a) Calculate the number of Pt atoms in the cube.
an edge length of platinum (Pt) = 1.0 cm.
Then Volume= 1.0 cm×1.0 cm×1.0 cm=1cm^3
Then we have volume of the cube as 1cm^3
Given:
The density Pt = 21.45 g/cm3
the mass of a single Pt atom =3.240 x 10^-22 g
Then with 1atom of the platinum element, we can calculate the number of Pt atoms in the cube as
Density of pt/mass of a single Pt atom
=(21.45 /=3.240 x 10^-22)
=6.6×10^22atoms of Pt in the cube
B)Volume of cube V=4/3πr^3
V= 4/3 ×π×r^3
V= 4.19067r^3
r^3= V/4.19067
But volume is not total volume but just 74% of it, then With 74% of the space inside the cube is taken up by Pt atoms, then we need to find 74% of volume of the cube which is 1cm^3
74/100 ×1= 0.74cm^3
Then our new volume V is 0.74cm^3
r^3=0.74/4.19067×6.620 x 10^22
r^3=2.6674×10^-24
r= 3√2.6674×10^-24
r=1.4×10^-8m
Which of the following equations defines the law of conservation of energy?
total energy = kinetic energy - potential energy
total energy = kinetic energy - potential energy
total energy = potential energy - kinetic energy
total energy = potential energy - kinetic energy
total energy = kinetic energy + potential energy
total energy = kinetic energy + potential energy
total energy = kinetic energy x potential energy
Answer:
Total energy =kinetic energy +potential energy.
Answer:
Kinetic Energy + Potential Energy = total energy
Explanation:
The conservation of mechanical energy can be written as “KE + PE = const”. Though energy cannot be created nor destroyed in an isolated system, it can be internally converted to any other form of energy.
How to find average speed
Answer:
Average speed (s) = total distance/total elapsed tiime
Explanation:
To calculate the average speed of an object, you must know the total distance an object travels and the total elapsed time of its whole journey.
Answer:
To find the average speed of an object, divide the total distance covered by the object by the total time it takes the object to cover such distance.
average speed= total distance covered/total time
Calculate the distance moved by a runner who runs with a speed of 5 km/h for a period of 1.5 hours.
7.5 km
10 km
2.5 km
5 km
Answer:
7.5 km
Explanation:
h5 per hour means that he traveled 5 km in 1 our. And then half of the hour, which means half an hour 5 km which is 2.5.
5 + 2.5 = 7.5
or just 1.5 x 5 = 7.5
(25 pts) Estimate how much collector area and storage capacity would be required for an active solar hot-water system designed to supply the total needs for two four-person families, one living in Manchester, New Hampshire, where the latitude is 44+o north and the other in Albuquerque, New Mexico, at 35+o North. The heat capacity of water is about 4200 J/kgoC and the hot water supply temperature in both houses is 60oC (140oF). State and justify all additional assumptions made.
Answer:
The required total area is 1.48 m²
Explanation:
Given that,
Latitude = 44+° N
New Mexico,
Latitude= 35+° N
Heat capacity = 4200 J/Kg°C
Temperature = 60°C
Let us assume the input temperature 22°C
Estimate volume of water 100 ltr for 4 person.
We need to calculate the heat
Using formula of heat
[tex]H=mc_{p}\Delta T[/tex]
[tex]H=mc_{p}(T_{f}-T_{i})[/tex]
Put the value into the formula
[tex]H=100\times4200\times(60-22)[/tex]
[tex]H=15960\ KJ[/tex]...(I)
Let solar radiation for 6 hours/day.
We need to calculate the total energy per unit area
Using formula of energy
[tex]E=1000\times6\times3600\ J/m^2[/tex]
[tex]E=21600\ KJ/m^2[/tex]
Let the efficiency of collector is 50 %
Then, the total energy per unit area will be
[tex]E=21600\times\dfrac{50}{100}[/tex]
[tex]E=10800\ KJ/m^2[/tex]....(II)
We need to calculate the required total area
Using equation (I) and (II)
[tex]A=\dfrac{H}{E}[/tex]
Where, H = heat
E = total energy
Put the value into the formula
[tex]A=\dfrac{15960}{10800}[/tex]
[tex]A=1.48\ m^2[/tex]
Hence, The required total area is 1.48 m²
PLEASE HELP!!! THANKS I GIVE BRAINLIEST !!A student examines the effect of the number of D batteries in a closed circuit on the brightness of a light bulb. In the experiment, four circuits were built with 1, 2, 3, and 4 batteries respectively. For each trial, the brightness of the light bulb was measured using a light meter. Which variable should the student keep constant
Answer:
The batteries
Explanation:
