Answer:
This function is a method of a class object that checks a message path and register or update the previous messages list with only new messages.
Explanation:
def message_check(self ) :
If message.pathThrough == True and \ message.origin not in self.activeLinks:
Self.activeLinks.append( message.origin )
Elif message.pathThrouh == False and \ message.origin in self.activeLinks:
Self.activeLinks.remove( message.origin )
A company that offers services for accessing and using the Internet is: *
a public Wi-Fi provider
an Internet Service Provider (ISP)
a network
a modem
Answer:
The answer to this question is given below in the explanation section
Explanation:
A company that offers services for accessing and using Internet is an Internet Service Provider (ISP). ISP provides internet services to its customer for accessing the Internet and to connect with the world.
However, a public wifi provider is just a router who is sharing with other people the ISP services for Internet. It is also noted that a network is a connection between networks/computers etc. But a network can't provide services for accessing and using the internet.
Modem is used to modulate and demodulate the internet signal provided by ISP to the client.
Answer:
B. ISP
Explanation:
Consider the following method.
public double secret(int x, double y) { return x/2.0; }
Which of the following lines of code, if located in a method in the same class as secret, will compile without
error?
int result = secret(4, 4);
double result = secret(4.0, 4);
int result = secret(4, 4.0);
double result = secret(4.0, 4.0);
double result = secret(4, 4.0);
Answer:
The answer to this question is given below in the explanation section.
Explanation:
Consider the following method.
public double secret(int x, double y)
{
return x/2.0;
}
The return type of this function is double, so where it will store the result in a variable, that variable should be of double type. So, among given options, the correct option is double result = secret(4, 4.0);
All others options are incorrect and will give the error.
for example:
int result = secret(4, 4);
in it, the function secret is accepting first integer and second double parameters, while you are passing all integer variables.
int result = secret(4, 4.0);
you are not allowed to store double value into integer.
double result = secret(4.0, 4.0); in it you are passing incorrect types of parameter.
Portrait and Landscape are
Question 4 options:
Page layout
Paper size
Page orientation
All of the above
Answer:
Page orientation
Explanation:
Required
What does portrait and landscape represent?
For better understanding, I'll narrow down the question to Microsoft Office Word. The explanation can be applied to other concepts.
Analysing the option one after the other.
Page layout: This is a term that describes the graphical representation of each document page, visually.
Page Size: This is a term that represents the length and width of the page. Common page sizes are LETTER, A4, A3, and so on.
The above (2) do not in any way represent what portrait and landscape represent.
Page orientation: This is a way the document is represented and it's a direct synonym for landscape and portrait.
Since (1) & (2) do not represented the given term, the last option is incorrect.
Hence,
Page orientation correctly answers the question
Answer:
Page orientation
Explanation:
I took the test
Write a program to read in two consumer price indexes and print out the inflation rate.
1. Start with the student starter code and follow the instructions in the code.
2. Instructions to complete are tagged in comments like the ones below. They will always begin with // TODO. // TODO #1: declare two float variables for the old consumer price index (cpi) and the new cpi // TODO #2: Read in two float values for the cpi and store them in the variables
// TODO #3: call the function InflationRate with the two cpis // TODO #4: print the results
3. Once you have this program working, submit for credit.
4. Advance to the next lab InflationRate Part2.
Answer:
Here is the C++ program:
#include<iostream> //to use input output functions
#include<cmath> //to use math functions
using namespace std; //to identify objects cin cout
double InflationRate(float oldCPI,float newCPI); //function prototype
int main() { //start of main function
float oldCPI,newCPI,rate; //declares two float variables for the old and consumer price indices
char choice; //stores user choice to continue
double sum=0.0; // computes the sum of inflation rates
int count = 0; //to count the number of inflation rates computed
double average = 0.0; //to compute the average inflation rate
do { //this loop continues to execute and ask user to enter cpis
cout << "Enter the old and new consumer price indices: "; //prompts user to enter new and old cpi
cin>>oldCPI>>newCPI; // Read in two float values for the cpi
rate = InflationRate(oldCPI,newCPI); //call the function InflationRate with the two cpis
cout << "Inflation rate is: "<< rate<< endl; //displays the result
sum = sum + rate; //computes sum of inflation rates
count++; //counts number of computed inflation rates
cout<<"Try again? (Y or y): "; //prompts if user wants to continue
cin>>choice; //reads choice of user y or Y
}while((choice=='Y')||(choice=='y')); //the loop continues to repeat as long as user enters small or capital y
average = sum/count; //computes the average inflation rate
cout<<"Average rate is: "<<average;} //displays the average inflation rate
double InflationRate(float oldCPI,float newCPI){ // function that takes two arguments oldCPI and new CPI and computes the inflation rate
return (newCPI - oldCPI) / oldCPI * 100;} //formula to compute inflation rate
Explanation:
1.
/*This program computes the inflation rate using two consumer price indexes. It takes as parameters, the previous price index and current price index and computes inflation rate by the formula:
(newCPI- oldCPI) / oldCPI and multiply the result by 100 */
#include <iostream> //to use input output functions
using namespace std; //to identify objects cin cout
2.
float oldCPI, newCPI; //declare two float variables for old and new consumer price index
cout << "Enter the old and new consumer price indices: "; //prompts user to enter values for old and new cpi
cin>>oldCPI>>newCPI; //read in two float values for the cpi and store them in the variables oldCPI and newCPI
double result = InflationRate(oldCPI,newCPI); //call the function InflationRate with the two cpis
cout << "Inflation rate is: " << result<< endl; //prints the result
3. and 4.
The complete program is given in the Answer section
For example if user enters 238.343 as old cpi and 238.250 as new cpi then the program works as follows:
oldCPI =238.343
newCPI = 238.250
Now the function InflationRate is called by passing these two parameter and this function returns :
return (newCPI - oldCPI) / oldCPI * 100;}
this becomes
(newCPI - oldCPI) / oldCPI * 100
(238.250 - 238.343) / 238.343 * 100
-0.093/238.343 * 100
- 0.00039 * 100
= -0.039 0204
Hence
result = -0.039 0204
Next, sum = sum + rate; statement computes the sum as:
sum = 0.0 + (-0.039 0204)
sum = -0.039 0204
count++ increases the count by 1
count = 1
Next user is asked if he/she wants to continues. If user presses y or Y then user is asked again to enter values for new and old cpi. Suppose user enters the following values:
oldCPI =238.250
newCPI = 237.852
Now the function InflationRate is called by passing these two parameter and this function returns :
return (237.852- 238.250) / 238.250* 100;}
this becomes
(newCPI - oldCPI) / oldCPI * 100
(237.852- 238.250) / 238.250* 100
−0.398/238.250* 100
- 0.001670491 * 100
= -0.167049
Hence
result = -0.167049
Next, sum = sum + rate; statement computes the sum as:
sum = -0.039 0204 + (-0.167049)
sum = -0.206069
count++ increases the count by 1
count = 2
Now lets say the user enters n or any other key when asked if user wants to continue. So the loop breaks and program moves to the statement:
average = sum/count;
This becomes:
average = -0.206069/2
average = −0.103034
Hence
Average rate is: −0.103034
In Outlook 2016, what are the three format options when sending an email message? Check all that apply.
bold
quick style
plain text
rich text
HTML
basic text
Answer:
C: plain text
D: rich text
E: HTML
The is context sensitive, meaning it will display options that relate to an active tool.
Answer:
Option bar
Explanation:
The Options Bar seems to be the parallel bar in photo editing software that operates under it's main menu. You will use the Software panel to turn it on and off, but if you're not seeing it on your phone, you probably want Software > Settings to power it on. The role of the Options Bar is to customize the tool settings when you're about to use.
Answer:
(A) The ribbon
Explanation:
my name Jeff
what movie is this off of
Answer:
there is no movie name off of
How does pharming work?
Answer:
Pharming, on the other hand, is a two-step process. One, cybercriminals install malicious code on your computer or server. Two, the code sends you to a bogus website, where you may be tricked in providing personal information. Computer pharming doesn’t require that initial click to take you to a fraudulent website.
Explanation:
Suppose that we are working for an online service that provides a bulletin board for its users. We would like to give our users the option of filtering out profanity. Suppose that we consider the words cat, dog, and llama to be profane. Write a program that reads a string from the keyboard and tests whether the string contains one of our profane words. Your program should find words like cAt that differ only in case. Option: As an extra challenge, have your program reject only lines that contain a profane word exactly. For example, Dogmatic concatenation is a small category should not be considered profane.
Answer:
Here is the JAVA program:
import java.util.*; //to use Scanner class, Lists
public class Main{ //name of class
public static void main(String[] args) { //start of main function
String sentence = "CaT and catalog are not same"; //a string
sentence = sentence.toLowerCase(); // converts the words in the sentence to lowercase
Scanner sc = new Scanner(sentence); //creates Scanner class object
List<String> profane_words = profaneList(); // creates a list of profane words i.e. cat, dog and llama
int count = 0; //count the number of profane words
while (sc.hasNext()) { //reads string as tokens and returns true if scanner has another token
String word = sc.next(); //returns the next complete token (word) and store it into word variable
for (String profane : profane_words) { // looks for each profane in profane_words list
if (word.matches(".*\\b" + profane + "\\b.*") && ! sentence.matches(".*" + profane + "[a-z].*\\b" + profane + "\\b.*") && ! sentence.matches(".*[a-z]" + profane + ".*\\b" + profane + "\\b.*")) { //uses matches() method that identifies whether a word in the string matches the given regular expression.
count++; //each time if the word of sentence matches with word given in profane_list then 1 is added to count
System.out.println("The word " + profane + " is a profane!"); //displays the word which is profane
} } }
System.out.println("Number of profane words: "+ count); } //displays the number of profane words found in the sentence
private static List<String> profaneList() { //list of profane words
List<String> profane_words = new ArrayList<>(); //creates an array list of profane words named as profane_words
profane_words.add("dog"); //adds word "dog" to the list of profane words
profane_words.add("cat"); //adds word "cat" to the list of profane words
profane_words.add("llama"); //adds word "llama" to the list of profane words
return profane_words; }} //returns the list of profane words
Explanation:
I will explain the program with an example:
sentence = "CaT and catalog are not same";
First this sentence is converted to lower case as:
sentence = "cat and catalog are not same";
Now the while loop uses hasNext() which keeps returning the next token and that token is stored in word variable.
Next the for loop iterates through the list of profane_words to check each profane word with the word in a sentence.
Next this statement:
if (word.matches(".*\\b" + profane + "\\b.*") && ! sentence.matches(".*" + profane + "[a-z].*\\b" + profane + "\\b.*") && ! sentence.matches(".*[a-z]" + profane + ".*\\b" + profane + "\\b.*"))
uses regular expressions to find the profane words in the sentence. The logical operator&& AND between the three expressions is used so all of the three must hold for the if condition to evaluate to true.
word.matches(".*\\b" + profane + "\\b.*") expression uses \b to check an exact match of the word. \b is meta-character to find a match at the beginning and at the end. So this checks if the word of a sentence matches with the profane in the profane list.
! sentence.matches(".*" + profane + "[a-z].*\\b" + profane + "\\b.*") && ! sentence.matches(".*[a-z]" + profane + ".*\\b" + profane + "\\b.*"))
These two expressions check if profane does not include as a part of another word in the sentence. This solves the extra challenge. Like here in the sentence we have a word catalog which is not a profane but a profane cat is included in this. So this will not be considered as a profane.
Every time a word matches with the profane from profane list, the value of count variable is incremented to 1.
In the end the statement:
System.out.println("Number of profane words: "+ count);
prints the number of profane words in the sentence.
List<String> profane_words = new ArrayList<>(); creates the list of profane words and add() method adds the words to the list profane_words. So profane_words list contain "cat", "dog" and "llama"
Hence the output of this program is:
The word cat is a profane! Number of profane words: 1
The program output is attached in screenshot
Major stress in your life can cause:
O a. headaches and Insomnia
O b. Fatigue and dry mouth
O c. Muscular and abdominal pain
O d. All of the above
#include using namespace std;class RunnerInfo { public: void SetTime(int timeRunSecs); // Time run in seconds void SetDist(double distRunMiles); // Distance run in miles double GetSpeedMph(); // Speed in miles/hour __(A)__ int timeRun; double distRun;};void __(B)__::SetTime(int timeRunSecs) { timeRun = timeRunSecs; // timeRun refers to data member}void __(C)__SetDist(double distRunMiles) { distRun = distRunMiles;}double RunnerInfo::GetSpeedMph() const { return distRun / (timeRun / 3600.0); // miles / (secs / (hrs / 3600 secs))}int main() { RunnerInfo runner1; // User-created object of class type RunnerInfo RunnerInfo runner2; // A second object runner1.SetTime(360); runner1.SetDist(1.2); runner2.SetTime(200); runner2.SetDist(0.5); cout << "Runner1's speed in MPH: " << runner1.__(D)__ << endl; cout << "Runner2's speed in MPH: " << __(E)__ << endl; return 0;}Complete the missing parts of the figure above.(b) -> Ru?(c) -> Ru?::(d) -> Get?()(e) -> runner2.?
Answer:
Here is the complete program:
#include <iostream>
using namespace std;
class RunnerInfo {
public:
void SetTime(int timeRunSecs); // Time run in seconds
void SetDist(double distRunMiles); // Distance run in miles
double GetSpeedMph(); // Speed in miles/hour
private:
int timeRun;
double distRun; };
void RunnerInfo::SetTime(int timeRunSecs) {
timeRun = timeRunSecs; // timeRun refers to data member
}
void RunnerInfo::SetDist(double distRunMiles) {
distRun = distRunMiles; }
double RunnerInfo::GetSpeedMph() {
return distRun / (timeRun / 3600.0); // miles / (secs / (hrs / 3600 secs)) }
int main() {
RunnerInfo runner1; // User-created object of class type RunnerInfo
RunnerInfo runner2; // A second object
runner1.SetTime(360);
runner1.SetDist(1.2);
runner2.SetTime(200);
runner2.SetDist(0.5);
cout << "Runner1's speed in MPH: " << runner1.GetSpeedMph() << endl;
cout << "Runner2's speed in MPH: " << runner2.GetSpeedMph() << endl;
return 0; }
Explanation:
(A):
private:
The variables timeRun and distRun are the data members of class RunnerInfo so they should be set to be private in order to prevent access from outside the class. So they are set to private which is an access specifier.
(B):
RunnerInfo
Here the name of the class RunnerInfo is used with double colon operator (::) which is used to qualify a C++ member function. This is used to define a function outside a class. So here the function name is SetTime() and it is defined outside class RunnerInfo. So we use resolution operator to define this function. The basic syntax is:
class_name :: function_name (args)
(C):
RunnerInfo::
This is missing in the above code. This works the same as (B).
:: double colons are called resolution operator :: and it is used to define a function outside a class.
(D):
GetSpeedMph()
runner1 is the object of class RunnerInfo which represents Runner 1. So in order to display the Runner 1's speed in Mph, the method GetSpeedMph() is called using the object runner1. The object is basically used to access the method of class RunnerInfo. This method GetSpeedMph() computes the speed using formula distRun / (timeRun / 3600.0); and returns the computed speed in MPH.
(E):
runner2.GetSpeedMph()
If we see the print statement:
Runner2's speed in MPH:
This shows that the speed of 2nd Runner is required. So for this purpose, the object runner2 is used. So using this object we can call the method that computes the speed of the 2nd runner. This method is GetSpeedMph(). So using runner2 for 2nd runner we access the method GetSpeedMph() to compute the Runner2's speed in MPH.
The entire program after correction gives the following result:
Runner1's speed in MPH: 12 Runner2's speed in MPH: 9
NEED HELP AS SOON AS POSSIBLE
A guideline for visual composition is to make use of lines. What do the following types of lines represent?
Vertical lines
Horizontal lines
Curved lines
Diagonal lines
You can run a macro by:
-Selecting the button assigned
-Using the shortcut keys assigned
-Using the view tab
-Selecting run macro from the status bar
Selecting the button assigned
Using the shortcut Keys assigned
Explanation:
By clicking the assigned button one can run a macro and we can assign a short cut key to macro which we created.
So, the two options we can use to run a macro.
what are the Technologies in regarding of communication technology? Please help me I'll rate you as brainliest!
Answer:
Internet, multimedia, email and many more.
Explanation:
Communications technology, refers to all equipment and programs that are used to process and communicate information.
Communication Technology includes the Internet, multimedia, e-mail, telephone and other sound-based and video-based communication means.
Catherine took her camera to the repair shop. The technician at the shop told her that acid had leaked into her camera. What could be the possible reason for acid leaking into Catherine’s camera?
A. She used the camera even though the battery was almost empty.
B. She wiped the camera lens with a moist cloth.
C. She left the camera in harsh daylight.
D. She left fully discharged batteries in her camera.
Answer:
B
Explanation:
Which term is not related with font?
Question 5 options:
Font grammar
Font color
Font size
Font face
Answer:
Font Grammar
Explanation:
Thank Google, lol!
The term that is not related to the font is font grammar. There is nothing such thing as font grammar. The correct option is a.
What are fonts?Fonts are the shape and design for the different alphabetic. These are present in computers and phones. We can create multiple designs shaped by these fonts.
Web designers could choose a common typeface (like Sans serif) if they want everyone to view the same font because not all machines can display all fonts.
Some designers may opt to use a fancier typeface and then specify a more straightforward font as a "backup" that a computer can use if the fancier font cannot be seen. The theme is a predetermined collection of hues, fonts, and visual effects.
Therefore, the correct option is a, Font grammar.
To learn more about fonts, refer to the link:
https://brainly.com/question/10878884
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A robot worker and a human worker are both vulnerable to
Answer:
fire
Explanation:
Which rules should be remembered when creating formulas using nested functions? Check all that apply.
Use an equal sign at the beginning of the formula.
Use open and close parenthesis for each set of nested functions. o
Use an equal sign before each function. All arguments should be in CAPS. Functions should be in CAPS.
Separate functions with commas.
Answer:
Use an equal sign at the beginning of the formula (A)
Use open and close parenthesis for each set of nested functions (B)
Functions should be in CAPS (E)
Separate functions with commas (F)
Explanation:
Got it right on edj :)
Suppose you need a spreadsheet application. When shopping for the right one, what is the most important factor to consider?
a. the keyboard layout
b. the type of pointing device you use
c. the operating system platform
d. the monitor size
Answer:
C.
Explanation:
A platform consists of an operating system, and the hardware. The hardware consists of the microprocessor, main storage, data bus and attached I/O devices (disks, display, keyboard, etc.). The operating system must be designed to work with the particular microprocessor's set of instructions.
C. the operating system platform
What is the most important program in an OS?The most important systems program is the operating system. The operating system is always present when the computer is running. It coordinates the operation of all the hardware and software components of the computer system.
What is a platform system?In IT, a platform is any hardware or software used to host an application or service. An application platform, for example, consists of hardware, an OS and coordinating programs that use the instruction set for a particular processor or microprocessor.
To learn more about operating system platform, refer
https://brainly.com/question/23880398
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List five differences a wiki has to a blog
Answer:
Blog :
Blogs are built to attract attention of business or product. Content written in the blog are more responsive.Blogs content tend to be more casual and approachable.Blogs contains single self-contained articles.Blogs doesn't require continuous updating and maintenance.Blogs belong to one department in a business.Wiki:
Wiki is generally intended for internal use and doesn't benefit from the content.Wiki content is Straightforward ,informative and more formal.A useful wiki is encyclopedic on the topics it contains Wiki requires continuous updating and maintenance to individual pages after publishing.Wiki is handled by all the collaborators who contribute.Consider two different implementations of the same instruction set architecture. The instructions can be divided into four classes according to their CPI (class A, B, C and D). P1 with a clock rate of 3GHz and CPIs of 3, 2, 1, 4, and P2 with a clock rate of 2.5GHz and CPIs of 2, 2, 2, 2.Processor Class A Class B Class C Class DP1 3 2 1 4P2 2 2 2 2Given a program with a dynamic instruction count of 1.0E5 instructions divided into classes as follows: 10% class A, 30% class B, 40% class C, and 20% class D.1. Which implementation is faster?2. What is the global CPI for each implementation?3. Find the clock cycles required in both cases?
Answer:
Follows are the solution to this question:
Explanation:
The architecture of two separate iterations with the same the instruction set can be defined in the attached file please find it.
Calculating the value of total instruction count:
[tex]= 1 \times 10^{5} \\\\= 10^5[/tex]
[tex]\text{P1 clock rate} = 3 \ GHz \\ \\\text{P2 clock rate} = 2.5 \ GHz \\\\\text{Class Division: 10 \% of class A,} \text{30 \% of class B, 40 \% of class C, 20 \% of class D} \\\\[/tex]
In point a:
Calculating P1 device mean CPI:
[tex]Average CPI = \frac{summation \times instruction \ count \times CPI}{total \ instruction \ count}\\[/tex]
[tex]= (10^5 \times 10 \% \times 3 + 10^5 \times 30 \% \times 2 + 10^5 \times 40 \% \times 2 + 10^5 \times 20%[/tex] [tex]\times 4) \times \frac{1} {1 \times 10^5}\\\\[/tex]
[tex]= \frac{(3 \times 10^4 + 6 \times 10^4 + 8 \times 10^4 + 8 \times 10^4)}{1 \times 10^5}\\\\ = \frac{25\times 10^4}{1 \times 10^5}\\\\= 2.5[/tex]
Estimating P2 device Average CPI:
[tex]= (1 \times 10^5 \times 10 \% \times2 + 1 \times 10^5 \times 30 \% \times 2 + 1 \times 10^5 \times 40 \% \times 2 + 1 \times 10^5 \times 20 \%[/tex][tex]\times 2) \times \frac{1}{ 1 \times 10^5}[/tex]
[tex]= \frac{(2 \times 10^4 + 6 \times 10^4 + 8 \times 10^4 + 4 \times 10^4)}{1 \times 10^5} \\\\= \frac{20 \times 10^4}{1 \times 10^5} \\\\= 2 \\[/tex]
[tex]\text{Execution time} = \frac{\text{instruction count} \times \text{average CPI}}{clock rate}}[/tex]
[tex]= \frac{1 \times 10^5 \times 2.5}{3} \ GHz \\\\ = \frac{1 \times 10^5 \times 2.5}{3 \times 10^9} \ sec \ as \ 1 \ GHz \\\\ = 10^9 \ Hz \\\\= 0.083 \ msec \ as \ 1 \ sec \\\\ = 10^3 \ msec[/tex]
Calculating processor execution time P2:
[tex]= \frac{1 \times 10^5 \times 2}{2.5} \ GHz \\\\= \frac{1 \times 10^5 \times 2}{2.5 \times 10^9} \ sec \ as\ 1 \ GHz \ = 10^9 \ Hz \\\\ = 0.080 \ msec \ as \ 1 \ sec \\\\ = 10^3 \ msec[/tex]
Since P2 is less than P1 for processor execution time, P2 is therefore faster than P1.
In point b:
Global processor P1 CPI = 2.5
Global processor P2 CPI = 2
In point c:
Finding Processor P1 clock cycles:
[tex]\text{Clock cycle = instruction count} \times \text{average CPI}[/tex]
[tex]= 1 \times 10^5 \times 2.5 \\\\ = 2.5 \times 10^5 \ cycles[/tex]
Finding Processor P2 clock cycles:
[tex]\text{Clock cycle = instruction count} \times \text{average CPI} \\\\[/tex]
[tex]= 1 \times 10^{5} \times 2\\\\ = 2 \times 10^{5} \ cycles\\\\[/tex]
Return the "centered" average of an array of ints, which we'll say is the mean average of the values, except ignoring the largest and smallest values in the array. If there are multiple copies of the smallest value, ignore just one copy, and likewise for the largest value. Use int division to produce the final average. You may assume that the array is length 3 or more.centeredAverage({1, 2, 3, 4, 100}) → 3centeredAverage({1, 1, 5, 5, 10, 8, 7}) → 5centeredAverage({-10, -4, -2, -4, -2, 0}) → -3
Answer:
The code to this question can be defined as follows:
public double centeredAverage(ArrayList<Integer> nums) //defining a method centeredAverage that accepts an array nums
{
if ((nums == null) || (nums.size() < 3))//define if block for check simple case value
{
return 0.0;//return float value
}
double sum = 0; //defining a double variable sum
int smallest = nums.get(0);//defining integer variable and assign value
int largest = nums.get(0);//defining integer variable and assign value
for (int i = 0; i < nums.size(); i++) //defining for loop for stor ith value
{
int value = nums.get(i);//defining integer value variable to hold nums value
sum = sum + value;//use sum variable for add value
if (value < smallest)//defining if block to check value less then smallest
smallest = value;//hold value in smallest variable
else if (value > largest)//defining else if block that checks value greater them largest value
largest = value; //hold value in largest variable
}
sum = sum - largest - smallest; // use sum to decrease the sum largest & smallest value
return (sum / (nums.size() - 2)); //use return keyword for return average value
}
Explanation:
In the question, data is missing, that's why the full question is defined in the attached file please find it.
In the given code a method "centeredAverage" is used that accepts an array in its parameter and inside the method, if block is used that checks the cash value if it is true, it will return a float value.
In the next step, two integers and one double variable is defined, that use the conditional statement for check hold value in its variable and at the last use return keyword for return average value.
1. What is wrong with the following code?
#include
#include
int *get_val(int y) {
int x = 200;
x += y;
return &x;
}
int main() {
int *p, y = 10;
p = get_val(y);
printf("%d\n", *p);
exit(0);
}
Answer:
Aye dog I don't know nothing about code, yes its true, but I hope that you get an answer for you!
Explanation:
Facts...
Write a single if-test using Boolean operators and relaional operators to determine if a double variable x is between zero (exclusive) and one (inclusive). Print a message indicating that x is between zero and one inclusive. Use deMorgan’s law to show the complement of the previous if-test. Simplify the complement statement so there is no "!" in your final if-test statement. 5. In the following questions, assume Boolean values have been assigned to A, B, and C as follows: boolean AA = true; boolean BB = false; boolean CC = true; Indicate what is printed by each statement: System.out.println( ((AA && BB) || (AA && CC)) ); System.out.println( ((AA || !BB) && (!AA || CC) ); 6. Write a program to determine if an input integer is an even number or odd number. 7. How can the effect of the following program fragment best be described? if (x > y) z = x; if (x == y) z = 0; if (x < y) z = y; a. The smaller of x and y is stored in z. b. The larger of x and y is stored in z. c. The larger of x and y is stored in z, unless x and y are equal, in which case z is assigned 0. d. The larger of x and y is stored in z, unless x and y are not equal, in which case z is assigned 0. e. None of the above.
Answer:
The following are the solution to this question:
Explanation:
In the given question multiple questions have been asked about, that is defined as follows:
#include<iostream>//defining header file
using namespace std;
int main()//defining main method
{
double x1;//defining double variable
cout<<"enter value: ";//print message
cin>>x1;//input value from the user-end
if(x1>0 && x1<=1)//use boolean operators
{
cout<<"x is between zero and one";//print message
}
return 0;
}
Output:
enter value: 1
x is between zero and one
5)
public class Main//defining a class main
{
public static void main(String[] args) //defining main method
{
boolean AA = true; //defining boolean variable
boolean BB = false;//defining boolean variable
boolean CC = true; //defining boolean variable
if ((AA && BB) || (AA && CC)) //defining if block to check value
{
System.out.println("True");//print message
}
if ((AA || !BB) && (!AA || CC))//defining if block to check value
{
System.out.println("True");//print message
}
}
}
Output:
True
True
6)
#include <stdio.h>//defining header file
int main()//defining main method
{
int x;
printf("Enter a value: ");
scanf("%d", &x);
if (x%2==0)// check number
{
printf("Even number");//print message
}
else
{
printf("Odd Number");//print message
}
return 0;
}
Output:
Enter a value: 22
Even number
7)
The answer is "Option C".
In the first question, a double variable "x1" is defined that inputs the value from the user end and use the boolean operators to check the value and print its value.
In question 5, three boolean variables "AA, BB, and CC" are defined that hold boolean value and use if block to check the given value.
In question 6, an integer variable has defined, that input the value and use if block to check even or odd number and print its value.
In question 7, option c is correct.
What is an accurate definition of experience?
Answer:
I hope this helps
Explanation:
An accurate definition of experience might be a process of observing, encountering, or undergoing something. Experience can help your knowledge or practical wisdom gained up because of what one has observed, encountered, or undergone.
Which of the following is a function of an audio programmer?
Answer:function of audio programmer
1. The audio programmer at a game development studio works under to integrate sound into the game and write code to manipulate and trigger audio cues like sound effects and background music.
Your answer is D. to integrate sound and music into the game
Hope this helps you
how is the flower be
Answer:
healthy cause they need water and sunshine
what is the purpose of primary manufacturing processes?
Answer:
Primary manufacturing processes are used to turn a raw material into an industrial material. Here's one type of primary manufacturing process 1)Chemical processes- using chemicals to change a raw material into an industrial material.
Answer:
used to turn a raw material into an industrial material.
Explanation:
Which of the following statements is true concerning the Internet of Things (IoT)? Wearable technologies are the only devices that currently connect to the Internet of Things. IoT is not affecting many businesses and the products they offer. Growth is expected to slow down over the next five years. IoT technology is relatively new and is expanding exponentially.
Answer:
i was looking and i think the answer would be growth slowing down but i might be wrong
Explanation:
Which of the following statements is true concerning the Internet of Things IoT is that the technology is relatively new and is expanding exponentially.
The IoT is regarded as a large network of connected things and individual. They collect and share data about the way they are used and about the environment around them.It is aimed to connect all potential objects to interact each other on the internet to provide secure and a more comfort life for people.
The future of IoT has the prediction to be limitless with great advances and the industrial internet will be accelerated.
Conclusively, the Internet of Things (IoT) connect the world together.
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Who PLAYS Apex Legend?
Answer:
me
Explanation:
Answer:
me :)
Explanation:
