triangle OPQ is similar to triangle RST. Find the measure of side RS. Round your answer to the nearest tent if necessary

Triangle OPQ Is Similar To Triangle RST. Find The Measure Of Side RS. Round Your Answer To The Nearest

Answers

Answer 1

To answer this question, we have that, if two triangles are similar, they maintain the same proportion on their corresponding sides.

We have that the corresponding sides are QP and TS, OP and RS, and QO and TR, so we can write:

[tex]\frac{TS}{QP}=\frac{RS}{OP}=\frac{TR}{QO}[/tex]

Then, since we have the values for QP, TS, and OP, we can find RS using the above proportion:

[tex]\frac{TS}{QP}=\frac{RS}{OP}\Rightarrow\frac{41.4}{11}=\frac{RS}{8}\Rightarrow RS=\frac{41.4\cdot8}{11}=\frac{331.2}{11}\Rightarrow RS=30.109090\ldots[/tex]

Then, we have that we can round this value to 30.11 units, and if we round the answer to the nearest tenth, we finally have that RS = 30.1 units.

Triangle OPQ Is Similar To Triangle RST. Find The Measure Of Side RS. Round Your Answer To The Nearest
Answer 2

Answer:

x = 30.1  (round 30)

Step-by-step explanation:

being similar we can solve with a simple equation

11 : 8 = 41.4 : x

x = 8 × 41.4 : 11

x = 331,2 : 11

x = 30.1  (round 30)


Related Questions

Which set can represent the side lengths of a right triangle?

Answers

The set that represents a right triangle has to satisfy Pythagorean's Theorem where the greatest side is the hypothenuse. Let's evaluate each of them until we get the right set.

[tex]\begin{gathered} 7^2=6^2+(\sqrt[]{21})^2 \\ 49=36+21 \\ 49=57 \end{gathered}[/tex][tex]\begin{gathered} (5\sqrt[]{3})^2=7^2+5^2 \\ 25\cdot3=49+25 \\ 75=74 \end{gathered}[/tex]

[tex]\begin{gathered} (2\sqrt[]{5})^2=4^2+2^2 \\ 4\cdot5=16+4 \\ 20=20 \end{gathered}[/tex]

As you can observe, set B satisfies the theorem.

Hence, B is the answer.

Choose the equation below that represents the line passing through the point (2, -4) with a slope of(1 point)Oy=kx-3Oy -x+5Oy-1x+3Oy=1x-5

Answers

The equation of a line in slope-intercept form can be written like this:

y = mx + b

Where m is the slope and b is the y-intercept of the line.

In this case, the slope of the line is 1/2, then we can rewrite the above equation like this:

y = (1/2)x + b

We are also told that this line passes through (2, -4), by replacing 2 for x and -4 for y into the above equation, we can solve for the value of b, like this:

-4 = 2(1/2) + b

-4 = 1 + b

-4 - 1 = 1 - 1 + b

-5 = b

b = -5

Then, we can rewrite the equation of the line, like this:

y = (1/2)x - 5

Then, the last option is the correct answer

In how many ways can the letters in the word PAYMENT be arranged using 4 letters?A. 42B. 840C. 2520D. 1260

Answers

The word PAYMENT has 7 letters. They can be arranged in groups of 4 like shown below:

PYNT, TA

What is the opposite of the given number?-10.1

Answers

According to the given data we have the following number:

-10.1

Therefore, the opposite of this given number would be the number 10.1

Instead of -10.1 the opposite would always be with the contrary sign. In this case is the opposite is a positive number.

In this case is -10.1. but for example if we the have to find the opposite number of 1 that would be the -1.

All real number would have and opposite number, except for the number 0.

Tom said that the difference in length between the longest trail and the shortest trail is 2 5/8 miles. Does Tom's answer make sense? What mistake did he make? Answer in at least two complete sentences. Use the sentences below to get started: "Tom's answer (makes sense/does not make sense). His mistake was ________."

Answers

Solution:

Given:

From the trail lengths given,

[tex]\begin{gathered} The\text{ longest trail is }1\frac{7}{8} \\ The\text{ shortest trail is }\frac{3}{4} \end{gathered}[/tex]

The difference in length between the longest trail and the shortest trail:

[tex]\begin{gathered} 1\frac{7}{8}-\frac{3}{4}=\frac{15}{8}-\frac{3}{4} \\ =\frac{15-6}{8} \\ =\frac{9}{8} \\ =1\frac{1}{8} \end{gathered}[/tex]

The sum of the longest trail and the shortest trail.

[tex]\begin{gathered} 1\frac{7}{8}+\frac{3}{4}=\frac{15}{8}+\frac{3}{4} \\ =\frac{15+6}{8} \\ =\frac{21}{8} \\ =2\frac{5}{8} \end{gathered}[/tex]

From the calculations above, the conclusion can be reached that:

Tom's answer does not make sense. His mistake was he did the sum of the longest trail and the shortest trail.

Refer to attached image.
213 and 131 are incorrect.

Answers

Answer:

P(X<16) = 0.64P(X>12) = 0.64

Step-by-step explanation:

Given a graph of a probability density function, you want the probabilities ...

P(X < 16)P(X > 12)

Probability from PDF

The probability of a given range of values of X is the area under the density curve for those values of x.

P(X < 16)

The triangular area to the left of X=16 has a base of 16 and a height of 0.08. Its area is given by the area formula for a triangle:

  A = 1/2bh

  A = 1/2(16)(0.08) = 0.64

The probability is P(X<16) = 0.64.

P(X > 12)

The area to the right of X=12 is a trapezoid with parallel "bases" of 0.06 and 0.10. The "height" of the trapezoid is 20-12 = 8. The area is given by the formula ...

  A = 1/2(b1 +b2)h

  A = 1/2(0.06 +0.10)(8) = 0.64

The probability is P(X>12) = 0.64.

a cyclist rides her bike at a speed of 30 kilometers per hour. what is the speed in miles per hour? how many miles will the cyclist travel in 5 hours?

Answers

Answer:

the answer is 9.321 miles

Consider the following system of equations.ſ x - 4y = -34x - 2y = -12Step 2 of 2: Determine if the point (3, 1) lies on both of the lines in the system of equations by substituting theordered pair into both equations.

Answers

Given:

x - 4y = -3

4x - 2y = -12

To determine if the point (3, 1) lies on both of the lines in the system of equations:

Substitute (3, 1) in the first equation, we get

3 - 4(1) = -3

3 - 4 =-3

-1 = -3

But,

[tex]-1\ne-3[/tex]

Substitute (3, 1) in the second equation, we get

4(3) - 2(1) = -12

12 - 2 = -12

10 = -12

But,

[tex]10\ne-12[/tex]

Hence, the answer is, No.

The point (3, 1) does not lie on both of the lines in the system of equations.

The standard normal curve is grafted below. Shade the region under the standard normal curve to the left of x=1.00Use the table to find the area under the standard normal curve to the left of x=1.00

Answers

Explanation

Part A

The shaded area under the standard normal curve to the left of z=1.00 can be seen below.

Part B

Using the z table, the area under the standard normal curve to the left of z.=1.00 is

Answer: 0.8413

Let p be "x+4=13" and q be "x=9." Which of the following statements is a biconditional?Select the correct answer below:x+4=13 and x=9.If x+4=13, then x=9.x+4=13 if and only if x=9.x+4=13 only if x=9.

Answers

For two given simple statements P and Q, if they are connected with the logical connectivity 'if and only if', then the compund statement is called biconditional statement.

Now,

P: x+4=13

q: x=9

Then, their biconditional statement is x+4=13 if an donly if x=9

Hence the correct answer is (c)

which of the following would be an acceptable first step in simplifying the expression?

Answers

Solution:

Given:

[tex]\frac{cos\text{ }x}{1-sin\text{ }x}[/tex]

The only acceptable first step in simplifying the expression from the options that would not change or alter the values of the expression is by multiplying (1 + sin x) to both the numerator and the denominator.

Therefore, the correct answer is OPTION B.

How many terms are included in the expression below?x² – 3x+7A. 2B. 7o oC. 1D. 3

Answers

Answer:

Choice D: 3 terms

Explanation:

The term of a expressions constant or a variable of an equation, The variable

Which property is used in the following calculation?

4 (18) (5)
4 (5) (18)
20 (18)
360

A. Identity Property of Multiplication
B. Distributive Property
C. None of these
D. Associative Property of Multiplication
E. Associative Property of Addition

Answers

The property which is used in the following calculation is referred to as Associative Property of Multiplication and is denoted as option D.

What is Associative Property of Multiplication?

This is referred to as the process in which the the result of the multiplication of three numbers is always the same regardless of the way and manner in which they are arranged.

We were given: 4 (18) (5)

= 4 (5) (18)

= 20 (18)

= 360

The multiplication of the numbers will give the same result of 360 no matter how the numbers are arranged which is why it was chosen as the correct choice.

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Is Ari’s answer to the question, correct? If not, where did Ari make a mistake? If his answer is incorrect, explain what the correct answer is and why it is correct.

Answers

None of Ari's answer to the question is correct. The right application of the laws of exponents to get the correct answer is explained below.

What are the Laws of Exponents?

Some of the laws of exponents can be summarized as follows.

The product law of exponents: This states that we are to add the exponents together if we are multiplying two numbers that have the same base. For example, [tex]x^m \times x^n = x^{m + n}[/tex].The division law of exponents: this states that when dividing two numbers that have the same base, we are to find the difference of their exponents. For example,  [tex]\frac{x^m}{x^n} = x^{m - n}[/tex].The negative law of exponents: This state that, [tex]x^{-m} = \frac{1}{x^m}[/tex].

Based on the above laws of exponents, none of Ari's answer is correct. Below are the correct way to solve the questions:

1. [tex]4^2 \times 4^5 = 4^{2 + 5} = 4^7[/tex]

2. [tex](2^{-5})^3 = 2^{-3 \times 5} = 2^{-15} = \frac{1}{2^{15}}[/tex]

3. [tex]\frac{(\frac{1}{4})^4 \times (\frac{1}{4})^5 }{(\frac{1}{4})^3} = \frac{(\frac{1}{4})^{4 + 5} }{(\frac{1}{4})^3} = \frac{(\frac{1}{4})^9 }{(\frac{1}{4})^3} = (\frac{1}{4})^{9 - 3}} = (\frac{1}{4})^6[/tex]

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282The number of germs in a sample can be measured by the equation f(x)=15x + 145. Temperature represents the domain of the sample while the range isthe number of germs. If a doctor wants to keep the amount of germs to be less than 300,what is the approximate domain of temperatures to keep the sample under 300?

Answers

Answer

The approximate domain temperature is 10

Step-by-step explanation:

Given the following model function

f(x) = 15x + 145

Mathematically

15x + 145 < 300

Collect the like terms

15x < 300 - 145

15x < 155

Divide both sides by 15

15x/15 < 155/15

x < 10.33

The figure below is an iscoceles trapezoid. If m

Answers

..Given an isosceles trapezoid

The following are the properties of an isosceles trapezoid

The legs are congruent by definition (From the diagram, the legs are JM and KL)

The lower base angles are congruent. The lower base angles are

[tex]m\angle M\cong m\angle L[/tex]

The upper base angles are congruent. The upper base angles are

[tex]m\angle J\cong m\angle K[/tex]

Any lower base angle is supplementary to any upper base angle. This means that

[tex]\begin{gathered} m\angle J+m\angle M=180^0 \\ m\angle K+m\angle L=180^0 \end{gathered}[/tex][tex]\begin{gathered} \text{If} \\ m\angle K=61^0 \\ \text{Therefore} \\ m\angle J\cong m\angle K=61^0 \\ m\angle J=61^0 \end{gathered}[/tex]

Also,

[tex]\begin{gathered} m\angle L+m\angle K=180^0 \\ m\angle L+61^0=180^0 \\ m\angle L=180^0-61^0 \\ m\angle L=119^0 \end{gathered}[/tex][tex]\begin{gathered} m\angle L\cong m\angle M,m\angle L=119^0 \\ Therefore\colon \\ m\angle M=119^0 \end{gathered}[/tex]

Hence

m∠J = 61⁰

m∠L = 119⁰

m∠M = 119⁰

The nutrition label on Erin's box of animal crackers states that 16 crackers contain 24 grams of carbohydrates. Erin ate 12 animal crackers from the box. What is the number of grams of carbohydrates in 12 animal crackers? A.8 grams B. 12 grams C. 18 gramsD. 20 grams

Answers

16 crackers are proportional to 24 grams of carbohydrates. To find the number of grams of carbohydrates in 12 animal crackers, we can use the next proportion:

[tex]\frac{16\text{ crackers}}{12\text{ crackers}}=\frac{24\text{ grams}}{x\text{ grams}}[/tex]

Solving for x,

[tex]\begin{gathered} 16\cdot x=24\cdot12 \\ x=\frac{288}{16} \\ x=18\text{ grams} \end{gathered}[/tex]

help video S-(x – 6)² +7 for 2 2 +3 x = 3 for Find f(3)

Answers

Explanation:

This is a function defined by parts. When x is not 3, the function has the equation on top, but when x is 3, the function has one value: 2.

Answer:

f(3) = 2

A bag contains 6 red, 5 blue and 4 yellow marbles. Two marbles are drawn, but the first marble drawn is not replaced. Find P(red, then blue).

Answers

5 + 6 + 4 = 15

red is 6/15 then taken out

then blue is 5/14

6/15 * 5/14 = 1/7

1/7 or about 0.143

Hi I am the mom can you help me on this question so I can show my daughter too because I am confused

Answers

Using the area method in finding the quotient.

The values of A and B are as follows,

A = C/6

B = D/6

A is the quotient of C and 6,

B is the quotient of D and 6.

From the problem, we only have choices of number to input in the boxes.

48, 9, 90, 8, 540, 36 and 0

We will select one to number to be the value of C and the value A must be in the given numbers to be used.

Let's say C = 48

A = 48/6 = 8

Since 8 is included in the list of numbers. This is applicable.

Now for D and B,

Note that the sum of C and D must be equal to the given dividend, the dividend from the problem is 588

Since we already have the value of C = 48, the value of D must be :

588 - C = D

588 - 48 = 540

And 540 is also included in the list of numbers, so D = 540

The value of B will be :

B = D/6

B = 540/6

B = 90

90 is also included in the list of numbers.

The final diagram will be :

For part B, the quotient is the sum of A and B

A = 8, B = 90

Quotient = A + B

= 8 + 90

Quotient = 98

A diesel train left Abuja and traveled west. One hour later a freight train left traveling 50 mph faster in an effort to catch up to it. After three hours of freight train finally caught up. Find the diesel train’s average speed.

Answers

The speed at which diesel train was moving is = 150mph

In the above question, it is given that,

Let the speed of the diesel train which left Abuja be x mph

then, speed of freight train which is moving 50 mph faster than diesel train = (50 + x)mph

Further, the freight train finally caught up the diesel train after three hours

So time taken by freight train = 3 hours

While time taken by diesel train would 1 hour more than freight train as its moving slower = 3 + 1 = 4 hours

Now, it is given that both the trains finally catch up, it means the distance travelled by both the trains would be equal

We know that,

Speed = [tex]\frac{Distance}{Time}[/tex]

Distance = Speed x Time

Distance travelled by Diesel train = distance travelled by Freight train

4x = 3(50 + x)

4x = 150 + 3x

x = 150 mph

Hence, the speed at which diesel train was moving is = 150mph

While, the speed at which freight train was moving is = (150 + x)mph = (150 + 50)= 200mph

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Write the following numbers in decreasing order: −4; 1 2/3 ; 0.5; −1 3/4 ; 0.03; −1; 1; 0; -103; 54

Answers

Decreasing order means from largest to smallest

The ordered list is:

54, 1 2/3, 1, 0.5, 0.03, 0, -1, -1 3/4, -4, -103

In a recent poll, 13% of all respondents said that they were afraid of heights. Suppose this percentage is true for allAmericans. Assume responses from different individuals are independent.

Answers

[tex]\begin{gathered} 13\text{ \% are afraid of their height} \\ So, \\ if\text{ we select 3 random american people } \\ \text{then,} \\ Probability=3\times\frac{13}{100} \\ \text{Probability}=\frac{39}{100}(\text{Ans)} \end{gathered}[/tex]

64XOA. VZ is the smallest side.OB. vz is the longest side.OC. XV is the smallest side.OD. XV is the longest side.5759Z

Answers

SOLUTION

The triangle XYZ shown below :

The angle with the longest side is said to be the angle with the largest angle:

The largest angle faces the longest side

Hence the Option B is t

[tex]YZ=x=longest\text{ side}[/tex]

Write a cosine function that has a midline of 4, an amplitude of 3 and a period of 8/5

Answers

A cosine function has the form

[tex]y=A\cdot\cos (Bx+C)+D[/tex]

Where A is the amplitude, B is 2pi/T, and C is null in this case because the phase is not being specified, and D is the vertical shift (midline).

Using all the given information, we have

[tex]y=3\cdot\cos (\frac{2\pi}{T}x)+4[/tex]

Then,

[tex]y=3\cdot\cos (\frac{2\pi}{\frac{8}{5}}x)+4=3\cdot\cos (\frac{10\pi}{8}x)+4=3\cdot\cos (\frac{5\pi}{4}x)+4[/tex]

Hence, the function is

[tex]y=3\cos (\frac{5\pi}{4}x)+4[/tex]

please help me asap, Evaluate 9 exponent 2

Answers

81

Explanation

Remember

[tex]a^b=\text{ a multiplied by itself b times}[/tex]

Step 1

apply

[tex]\begin{gathered} 9^2=9\cdot9 \\ 9\cdot9=81 \end{gathered}[/tex]

Identify the x intercept(s) from the graphType your answer using set notation {x,x} listing x values in order from least to greatest

Answers

The x-intercept is where the graph passes the x-axis.

The graph extends from {-5 ≤ x ≤ 3}

The x-intercept is {x = -1}.

a. Solve for c: E = mc^2

Answers

ANSWER

[tex]\text{c = }\sqrt[]{\frac{E}{m}}[/tex]

EXPLANATION

We want to solve for c in:

[tex]E=mc^2[/tex]

To do that, we will make c the subject of the formula:

[tex]\begin{gathered} E=mc^2 \\ \Rightarrow\text{ }\frac{E}{m}=c^2 \\ Find\text{ the square root of both sides:} \\ \Rightarrow\text{ c = }\sqrt[]{\frac{E}{m}} \end{gathered}[/tex]

We have solved for c.

solve by square roots: 16k^2-1=24

Answers

we have

[tex]16k^2-1=24​[/tex]

step 1

Adds 1 both sides

[tex]\begin{gathered} 16k^2-1+1=24​+1 \\ 16k^2=25 \end{gathered}[/tex]

step 2

Divide by 16 both sides

[tex]\begin{gathered} \frac{16}{16}k^2=\frac{25}{16} \\ \text{simplify} \\ k^2=\frac{25}{16} \end{gathered}[/tex]

step 3

Applying square root both sides

[tex]k=\pm\frac{5}{4}[/tex]

Khloe is going to invest $7,100 and leave it in an account for 9 years. Assuming the interest is compounded continuously, what interest rate, to the nearest hundredth of a percent, would be required in order for Khloe to end up with $12,600?

Answers

Solution

For this case we can use the following formula:

[tex]A=Pe^{rt}^{}[/tex]

and for this case we have the following:

P= 12600

A= 7100

t = 9 years

And r is the value that we need to find, so we can do the following:

[tex]12600=7100e^{9r}[/tex]

We can do the following:

[tex]\ln (\frac{12600}{7100})=9r[/tex]

And we got for r:

[tex]r=\frac{\ln (\frac{12600}{7100})}{9}=0.0637[/tex]

And then the rate would be:

6.37%

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