TRUE or FALSE: You maintain a healthy body composition by balancing your food intake with your exercise

Answer:

B: At the launch point

Explanation:

We are told that after the explosion, one of the halves landed at the point Y, which is a distance 2R to the right of the launch point. Now, if air resistance is negligible, it means the other half will land at the launch point. This is clear from the model projectile motion curve of this explosion I've done in wolfram and attached.

How would each react?

Jennifer is trying out for the soccer team and really wants to make varsity. After tryouts, she learns she is on the junior varsity team.

Carlos is struggling with math. It is his most challenging subject and he is worried about a big test tomorrow. He has time to study, but isn't sure it is worth it.

Answer:

It's D!

Explanation:

The two most common isotopes of tin have atomic masses of 118 and 120 and have the key difference that the heavier isotope has 2 more neutrons than the lighter one.

Tin is the element that has the largest number of stable isotopes, only out of the ten are potentially radioactive but have not been observed to decay.

We know that Tin 118 and Tin 120 are the isotopes of the tin, but the key difference between them is that the Tin 120 has two more neutrons than Tin118, therefore, the isotopic mass of the two is different as well.

Mass of Tin118 < Mass of Tin120

Therefore, from all the provided options the correct option is that the heavier isotope has two more neutrons than the lighter isotope.

Hence, the correct option is d.

Learn more about Isotopes:

https://brainly.com/question/13214440

Answer:

v = v_o/(1 + (tv_o(μ_k)/R))

Explanation:

We are told that the coefficient of friction between the block and the wall is μ_k.

Now, formula for the frictional force will be;

F_fric = -μ_k × mv²/R

mv²/r is used because it is a centripetal motion.

Now, we know that F = ma = m(dv/dt)

Thus;

m(dv/dt) = -μ_k × mv²/R

m will cancel out to give;

dv/dt = -μ_k × v²/R

Rearranging to get;

dv/v² = -μ_k × (1/r)dt

We are told the initial velocity is v_o.

Thus, let the final velocity be v.

The initial time is 0 and thus the final time will be represented by t.

Thus;

(v,v_o)∫dv/v² = (t, 0)∫-μ_k × (1/R)dt

Integrating this we have;

-1/v - (-1/v_o) = -((μ_k)/R) × (t - 0)

-(1/v) + (1/v_o) = -t(μ_k)/R

Rearranging to get;

1/v = (1/v_o) + t(μ_k)/R

Simplifying the right hand side gives;

[R + tv_o(μ_k)]/Rv_o

Thus;

1/v = [R + tv_o(μ_k)]/Rv_o

v = Rv_o/[R + tv_o(μ_k)]

Simplifying further gives;

v = v_o/(1 + (tv_o(μ_k)/R))

Answer:

The number of images formed by two adjacent plane mirrors depends on the angle between the mirror. If (in degrees) is angle between the plane mirrors then number of images are given by, n = 360 θ − 1.

Answer:

1428.6m/s²

Explanation:

Given parameters:

Force applied on the body  = 40N

Mass of the body  = 28g

                    1000g  = 1kg

                      28g will therefore be 0.028kg

Unknown:

Acceleration  = ?

Solution:

To solve this problem, we use the expression derived from Newton's second law of motion.

         Force  = mass x acceleration

Insert the parameters and solve;

            40  = 0.028 x acceleration

           Acceleration  = [tex]\frac{40}{0.028}[/tex]   = 1428.6m/s²

Answer:

The least number of forces required to stretch a spring is one.

Explanation:

Let suppose that spring is ideal, that is, that effects from its mass can be neglected since it is insignificant in comparison with external forces. In addition, let the spring have a linear behavior, meaning that net external longitudinal force exerted on spring is directly proportional to defomation. (Hooke's Law) That is:

[tex]F \propto x[/tex] (1)

[tex]F = k\cdot x[/tex] (2)

Where:

[tex]F[/tex] - Net external force, measured in newtons.

[tex]k[/tex] - Spring constant, measured in newtons per meter.

[tex]x[/tex] - Deformation of spring, measured in meters.

Hence, the least number of forces required to stretch a spring is one.

Answer:

4

Explanation:

Answer:

Explained below.

Explanation:

Nature is defined as all of the genes as well as hereditary factors that influence both the physical appearance and personality manifestations of any individual.

For example, a child could inherit certain physical traits and characters from his/her parents which in turn shapes the physique and personality of such an individual in the world.

Answer:

F = 1,875 N

Explanation:

force=

[tex] \frac{change \: in \: momentum}{time \: taken} [/tex]

∆H = m∆V

where ∆H ----> change in momentum.

( final momentum - initial momentum )

and ∆V ----> change in velocity

( final velocity - initial velocity )

and m ----> is mass

then f =

[tex] \frac{1500 \times (25 - 15)}{8} [/tex]

= 1,875 N

Digital storage of data is more secure than analog storage because a stronger password is needed to access digital data and fingerprint can be used to control access to digital data.

Content that employs a technique in which data is represented by continuously varying physical quantities is known as analog device storage

In paper,cave,microfilm is the best example of analog data storage.

Digital storage of data is more secure than analog storage;

B. A fingerprint can be used to control access to digital data.

D. A stronger password is needed to access digital data.

To learn more about analog device storage, refer to the link;

brainly.com/question/11599772

#SPJ2

Answer: A, B

Explanation: did the test

Answer:

110.7Joules

Explanation:

Work is said to be done when the force applied to a body cause the body to move through a distance. Mathematically:

Work done = Force * Distance

Given the following

Force = 270 -0  = 270N

Distance moved = 0.410m

Required

The work done

Substitute the given parameters into the formula

Workdone = 270 * 0.41

Workdone = 110.7Joules

Hence the work done in pulling the bow is 110.7Joules

Answer:

the length of an antenna one-half wavelength long for sending radio at 300 Hz is 500 km

Explanation:

Given the data in the question;

we know that wave length is;

λ = c/f

c is the speed of voice ( 3 × 10⁸  m/s )

frequency f = 300 Hz

so we substitute

λ = 3 × 10⁸ / 300

λ = 1000000 m

we know that; 1 km = 1000 m

so

λ = 1000000 m / 1000

λ = 1000 km

hence, an antenna one-half wavelength will be;

λ /2

=  1000 km / 2

= 500 km

Therefore, the length of an antenna one-half wavelength long for sending radio at 300 Hz is 500 km

Answer:

a) The velocity of the rock during ascent at 180 meters above the surface is approximately 17.799 meters per second.

b) The height of the rock from the ground is 219 meters from the ground.

Explanation:

a) The rock experiments a free fall, in which this element is projected upwards, decelerated until rest is reached and then it falls down. Please notice that free fall is a case of uniformly accelerated motion, in which object is accelerated by gravity. The velocity of the rock is described by the following kinematic equation:

[tex]v = \sqrt{v_{o}^{2}+2\cdot a\cdot \Delta s}[/tex] (1)

Where:

[tex]v_{o}[/tex] - Initial velocity, measured in meters per second.

[tex]v[/tex] - Final velocity, measured in meters per second.

[tex]a[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]\Delta s[/tex] - Travelled distance, measured in meters.

If we know that [tex]v_{o} = 30\,\frac{m}{s}[/tex], [tex]a = -1.62\,\frac{m}{s^{2}}[/tex] and [tex]\Delta s = 180\,m[/tex], then the velocity during ascent at 180 meters is:

[tex]v =\sqrt{\left(30\,\frac{m}{s} \right)^{2}+2\cdot \left(-1.62\,\frac{m}{s^{2}}\right)\cdot (180\,m) }[/tex]

[tex]v \approx 17.799\,\frac{m}{s}[/tex]

The velocity of the rock during ascent at 180 meters above the surface is approximately 17.799 meters per second.

b) The height of the rock is calculated from this kinematic formula:

[tex]s = s_{o}+v_{o}\cdot t +\frac{1}{2}\cdot a \cdot t^{2}[/tex] (2)

Where:

[tex]s_{o}[/tex] - Initial position of the rock, measured in meters.

[tex]s[/tex] - Final position of the rock, measured in meters.

[tex]v_{o}[/tex] - Initial velocity of the rock, measured in meters per second.

[tex]t[/tex] - Time, measured in seconds.

[tex]a[/tex] - Acceleration, measured in meters per square second.

If we know that [tex]s_{o} = 0\,m[/tex], [tex]v_{o} = 30\,\frac{m}{s}[/tex], [tex]t = 10\,s[/tex] and [tex]a = -1.62\,\frac{m}{s^{2}}[/tex], then the height of the rock from the ground is:

[tex]s = 0\,m + \left(30\,\frac{m}{s} \right)\cdot (10\,s)+\frac{1}{2}\cdot \left(-1.62\,\frac{m}{s^{2}} \right)\cdot (10\,s)^{2}[/tex]

[tex]s = 219\,m[/tex]

The height of the rock from the ground is 219 meters from the ground.

Answer:

Acceleration = 9.55m/s²

Explanation:

Given the following data;

Initial velocity = 0m/s

Final velocity = 27.7m/s

Time = 2.9 secs

To find the acceleration;

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Mathematically, acceleration is given by the equation;

[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]

Substituting into the equation, we have;

[tex]a = \frac{27.7 - 0}{2.9}[/tex]

[tex]a = \frac{27.7}{2.9}[/tex]

Acceleration = 9.55m/s²

Answer:

pendulums

Explanation:

Answer:

Explanation:

Time period of oscillation T = 3 s .

Frequency of oscillation = 1 / T = 1 / 3 = .333 per second .

The mass is  pulled down an additional 0.25 meters so amplitude of oscillation A = .25 m .

Full range of vertical motion = .25 x 2 = 0.5 m .

The period of the spring = 3 s .

Answer:

Acid rain is caused by a chemical reaction that begins when compounds like sulfur dioxide and nitrogen oxides are released into the air. These substances can rise very high into the atmosphere, where they mix and react with water, oxygen, and other chemicals to form more acidic pollutants, known as acid rain.

Answer:

Acid rain is caused by a chemical reaction that begins when compounds like sulfur dioxide and nitrogen oxides are released into the air.

Explanation:

Acid rain results when sulfur dioxide (SO2) and nitrogen oxides (NOX) are emitted into the atmosphere and transported by wind and air currents.

Explanation:

hold I will tell u the answer 1 sec

Answer:

Hug g g fed gvgcgcgcg

Explanation:

G gcgvhcvkgj

Answer:

The Basal Metabolic Rate of 88 kilocalories per hour is equal to 102.276 watts.

Explanation:

A watt is equal to 1 joule per second, a kilocalory equals 4184 joules and a hour equals 3600 seconds. We convert the Basal Metabolic Rate (BMR) from kilocalories per hour into watts by following conversion:

[tex]x = 88\,\frac{kcal}{hr}\times \frac{4184\,J}{1\,kcal}\times \frac{1\,h}{3600\,s}[/tex]

[tex]x = 102.276\,W[/tex]

The Basal Metabolic Rate of 88 kilocalories per hour is equal to 102.276 watts.

Answer: A chemical change occurs.

Explanation:

A. A chemical change occurs.

B. A base neutralizes an acid.

C. An acid neutralizes a base.

D. A physical change occurs.

Answer:

Explained below

Explanation:

The relationship between dipole moment and bind moment is that Dipole moment of a molecule is defined as the resultant of all the bond moments and moments that are due to any existing lone pair.

For example, If a covalent bond is formed between two different elements that have different electronegativity, it means that the bond will become polar. Now, thee shared electron pair existing in the covalent bond gets more attracted to the more electronegative atom. As a result of that, the negative pole will now develop on that atom and thereby making positive pole to develop on the other atom.

If a molecule has a symmetrical shape and as a result all of its bond moments are equal, it means that the molecule will be non-polar. Examples that exhibit this are: CO2, CH4, BF3, etc.

Answer:

The material that Emily invented can be easily repaired by shining ultraviolet light on it.

Explanation:

Hope it helps! Please mark brainliest.

Answer:

The material that Emily invented can be easily repaired by shining ultraviolet light on it.

Explanation:

Answer:

a) a = [tex]- \frac{v_1}{T}[/tex] i ^ +[tex]\frac{v_3 - v_2}{T}[/tex] j^, b) r = 2 v₃ T j ^, c)    v = -v₁ i ^ + (2 v₃ - v₂) j ^

Explanation:

This is a two-dimensional kinematics problem

a) Let's find the acceleration of the body, for this let's use a Cartesian coordinate system

X axis

initial velocity v₀ₓ = v₁ for t = 0, velocity reaches vₓ = 0 for t = T, let's use

          vₓ = v₀ₓ + aₓ t

we substitute

          for t = T

           0 = v₁ + aₓ T

           aₓ = - v₁ / T

y axis  

the initial velocity is [tex]v_{oy}[/tex] = v₂ at t = 0 s, for time t = T s the velocity is v_{y} = v₃

             v₃ = v₂ + a_{y} T

              a_{y} = [tex]\frac{v_3 - v_2}{T}[/tex]

therefore the acceleration vector is

             a = [tex]- \frac{v_1}{T}[/tex] i ^ +[tex]\frac{v_3 - v_2}{T}[/tex] j^

b) the position vector at t = 2T, we work on each axis

X axis

             x = v₀ₓ t + ½ aₓ t²

we substitute

             x = v₁ 2T + ½ (-v₁ / T) (2T)²

              x = 2v₁ T - 2 v₁ T

              x = 0

Y axis  

             y = [tex]v_{oy}[/tex] t + ½ a_{y} t²

             y = v₂ 2T + ½ [tex]\frac{v_3 - v_2}{T}[/tex] 4T²

             y = 2 v₂ T + 2 (v₃ -v₂) T

            y = 2 v₃ T

the position vector is

            r = 2 v₃ T j ^

c) the velocity vector for t = 2T

X axis

            vₓ = v₀ₓ + aₓ t

we substitute

           vₓ = v₁ - [tex]\frac{v_1}{T}[/tex] 2T = v₁ - 2 v₁

           vₓ = -v₁

Y axis  

           [tex]v_{y}[/tex] = v_{oy} + a_{y} t

           v_{y} = v₂ + [tex]\frac{ v_3 - v_2}{T}[/tex] 2T

           v_{y} = v₂ + 2 v₃ - 2v₂

           v_{y} = 2 v₃ - v₂

the velocity vector is

           v = -v₁ i ^ + (2 v₃ - v₂) j ^

Answer:

the correct answer is B      r =√2   R

Explanation:

To solve this exercise we will use the force of gravity, at two points when the rocket is on the platform and when it is at the desired height.

Rocket with cargo on the platform

              [tex]F_{g} = G \frac{ m M }{R^2} = W[/tex]

where m is the mass of the rocket and the charge, M the mass of the earth and R the distance from the center of the earth

Rocket loaded at desired height

              [tex]F_{g} = G \frac{m M}{r^2 } = \frac{W}{2}[/tex]

we write our two equations

        W = g m M / R²

        [tex]\frac{W}{2}[/tex] = G m M / r²

we match to solve them

         Gm M / R² = 2 Gm M / r²

         1 / R² = 2 / r²

          r =√2   R

therefore the correct answer is B