Car B travels a distance x after time t (measured in seconds) of
x = (80 m/s) t
so that at 6:40 AM (which is 40 min = 2400 s after the starting time of 6:00 AM), it will have moved
(80 m/s) * (2400 s) = 192,000 m
If we take t = 0 to refer to 6:40 AM, the cars' respective positions x at time t are given by
A: x = (280 m/s) t
B: x = 192,000 m + (80 m/s) t
(i) After 1 h = 3600 s, their positions are
A: (280 m/s) * (3600 s) = 1,008,000 m
B: 192,000 m + (80 m/s) * (3600 s) = 480,000 m
away from the point X, so the distance between the two cars is
1,008,000 m - 480,000 m = 528,000 m = 582 km
(ii) Car A moves faster than car B, so A overtakes B as soon as their positions are equal, which happens for
(280 m/s) t = 192,000 m + (80 m/s) t
(200 m/s) t = 192,000 m
t = (192,000 m) / (200 m/s)
t = 960 s = 16 min
So after 16 min, both cars have a position of
(280 m/s) * (960 s) = 268,800 m = 268.8 km
beyond point X.
What are three ways people manipulate light.
Answer:
refracted, reflected, or absorbed.Explanation:
Plz solve this question..
Answer:
Explanation:
Voltage = 12 (the two batteries are in series and the voltage adds).
Resistance = 3 ohms
I = V / R
I = 12/3
I = 4 amperes.
None of the answers are the right ones. If there is a fifth one that reads 4 amperes then it is the correct answer.
Which statement best compares and contrasts two physical properties of matter?
Density and solubility are similar because they both involve water, but they are different because density involves dissolving a material and solubility involves floating or sinking a material.
Density and solubility are similar because they both involve a material’s mass and volume, but they are different because density involves floating materials and solubility involves sinking materials.
Boiling points and melting points are similar because they both involve changing the heat of a material, but they are different because boiling point involves adding heat to a material and melting point involves removing heat from a material.
Boiling points and melting points are similar because they both involve the change in a state of a material, but they are different because boiling point involves a change from a liquid to a gas and melting point involves a change from a solid to a liquid.
Answer:
D
Explanation:
Boiling points and melting points are similar because they both involve the change in a state of a material, but they are different because boiling point involves a change from a liquid to a gas and melting point involves a change from a solid to a liquid.
Answer:
D
Explanation:
I answered on eng and got it right
A car is travelling to the right with a speed of 42 m/s when the driver slams on the brakes the car skids 4.0 second
Answer:
84m
Explanation:
A.) If its booster rockets accelerate the space shuttle at 15m/s2, how high will it be one minute after launch?
B.) What was its average velocity
during that time?
Answer:
27,000 m
450 m/s
Explanation:
Assuming the initial velocity is 0 m/s:
v₀ = 0 m/s
a = 15 m/s²
t = 60 s
A) Find: Δy
Δy = v₀ t + ½ at²
Δy = (0 m/s) (60 s) + ½ (15 m/s²) (60 s)²
Δy = 27,000 m
B) Find: v_avg
v_avg = Δy / t
v_avg = 27,000 m / 60 s
v_avg = 450 m/s
Gravity is affected by (2 points)
force only
force and distance
mass and distance
force and mass
Answer:
Mass and distance
Explanation:
Answer:
Mass and distance
Explanation:
the larger the mass the faster it falls or more gravity is applied same goes for the distance the farther it is from the ground its heavier however if its to far gravity then does not apply
hope this helps :)
can have brainlist please
Two 11.5-mg balls are connected by a 28.9-cm-long insulating rod of negligible mass. One ball has a charge of +q and the other has a charge of −q. The system is placed in a 592 N/C uniform electric field. Initially the system is at rest and makes an angle α= 58.9° with respect to the field. It is then released, and when it is momentarily aligned with the electric field, its kinetic energy is 4.86 mJ. What is the magnitude of q?
Answer:
58.8 μC
Explanation:
The two balls create a dipole of dipole moment , p = qd where q = charge and d = distance between the charges = 28.9 cm = 0.289 m. The potential energy change ΔU = -W where W is the work done by the electric field of magnitude E = 592 N/C.
Now U = -pdEcosФ = -qdEcosФ where Ф is the angle between p and E. Since Ф is initially 58.9° and then becomes 0° when p and E align, the potential energy change is thus.
ΔU = -qdEcos0 - (-qdEcos58.9°) = qdE(cos58.9° - 1) = qdE(0.5165 - 1) = -0.4835qdE.
W = - ΔU = -(-0.4835qdE) = 0.4835qdE
This work equals the kinetic energy of the systems. Since K.E = 4.86 mJ = 4.86 × 10⁻³ J.
So K.E = W
K.E = 0.4835qdE
making q subject of the formula
q = K.E/0.4835dE
q = 4.86 × 10⁻³ J/(0.4835 × 0.289 m × 592 N/C)
q = 4.86 × 10⁻³ J/82.72
q = 0.0588 × 10⁻³ C
q = 58.8 × 10⁻⁶ C
q = 58.8 μC
the resistance of a wire the resistance of a wire of length 100 cm and a diameter of 0.3 mm is found to be 3.0 ohms calculate the resistivity and conduct conductivity
Answer:
The resistivity of this wire is approximately [tex]2.1\times 10^{-7}\; \rm \Omega \cdot m[/tex].
The conductivity of this wire is approximately [tex]4.7\times 10^6\; \rm (\Omega \cdot m)^{-1}[/tex].
Assumption: the perpendicular cross-section of this wire is circular.
Explanation:
Convert all unit to standard ones:
Length of this wire: [tex]l = 100\; \rm cm = 1.00\; \rm m[/tex].Diameter of this wire: [tex]0.3\; \rm mm = 3\times 10^{-4}\; \rm m[/tex].Assume that a wire has a resistivity of [tex]\rho[/tex], a length of [tex]l[/tex], and a cross-section area of [tex]A[/tex]. The formula for the resistance of this wire would be:
[tex]R = \displaystyle \frac{\rho \cdot l}{A}[/tex].
Rearrange this equation to find an expression for [tex]\rho[/tex], the resistivity of this wire:
[tex]\displaystyle \rho = \frac{R\cdot A}{l}[/tex].
For the wire in this question, both length [tex]l[/tex] and resistance [tex]R[/tex] are already given. However, the cross-section area [tex]A[/tex] of this wire needs to be calculated from its diameter, [tex]d[/tex]:
[tex]A = \displaystyle \pi\, \left(\frac{d}{2}\right)^2 \approx 7.08\times 10^{-8}\; \rm m^2[/tex].
Calculate the resistivity of this wire:
[tex]\displaystyle \rho = \frac{R\cdot A}{l} \approx \frac{3.0\; \Omega\times 7.08\times 10^{-8}\; \rm m^2}{1.00\; \rm m} \approx 2.1\times 10^{-7}\; \rm \Omega\cdot m[/tex].
The conductivity of a material is the reciprocal of its resistivity:
[tex]\displaystyle C = \frac{1}{\rho} \approx \frac{1}{2.1\times 10^{-7}\; \Omega\cdot m}\approx 4.7\times 10^{6}\; \rm (\Omega \cdot m)^{-1}[/tex].
Unimpressed with your previous stunt, the director of the new James
Bond movie has come to you with a more exciting idea. In this stunt,
Bond will run towards a bridge that is 18m above a river. His partner
is in a speedboat 60 meters away from the bridge. Bond jumps
horizontally off the bridge with a speed of 6.7 m/s toward where
his partner is waiting. Starting from rest, his partner begins racing
toward the bridge the moment Bond jumps. What is the minimum
acceleration his partner will need in order to catch Bond before he
hits the water?
Answer:
The minimum acceleration his partner will need in order to catch Bond before he hits the water is 25.688 meters per square second.
Explanation:
Let be the initial position of the sppedboat the reference location, James Bond jumps horizontally and experiments a parabolic motion, which consists in a horizontal motion at constant velocity and an vertical uniform accelerated motion due to gravity.
Speedboat must accelerate from rest and get Bond at right location and instant. Now we describe the appropriate equations of motion for James Bond and for the speedboat:
James Bond
[tex]x_{B} = x_{B,o} + v_{B,o,x} \cdot t[/tex]
[tex]y_{B} = y_{B,o} + v_{B, o, y}\cdot t + \frac{1}{2}\cdot g \cdot t^{2}[/tex]
Speedboat
[tex]x_{S} = x_{S,o}+v_{S,o}\cdot t + \frac{1}{2}\cdot a_{S}\cdot t^{2}[/tex]
Where:
[tex]x_{B,o}[/tex], [tex]x_{S,o}[/tex] - Initial horizontal positions for James Bond and the speedboat, measured in meters.
[tex]x_{B}[/tex], [tex]x_{S}[/tex] - Current horizontal positions for James Bond and the speedboat, measured in meters.
[tex]v_{B,o,x}[/tex], [tex]v_{S,o}[/tex] - Initial horizontal velocities of James Bond and the speedboat, measured in meters per second.
[tex]v_{B,o, y}[/tex] - Initial vertical velocity of James Bond, measured in meters per second.
[tex]t[/tex] - Time, measured in seconds.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]a_{S}[/tex] - Acceleration of the speedboat, measured in meters per square second.
We must observe the following conditions such as we may calculate the minimum acceleration of the speedboat:
1) [tex]x_{B} = x_{S}[/tex]
2) [tex]y_{B} = 0\,m[/tex]
Now, if we know that [tex]x_{B,o} = 60\,m[/tex], [tex]x_{S,o} = 0\,m[/tex], [tex]y_{B, o} = 18\,m[/tex], [tex]y_{B} = 0\,m[/tex], [tex]v_{B,o, x} = -6.7\,\frac{m}{s}[/tex], [tex]v_{S,o} = 0\,\frac{m}{s}[/tex], [tex]v_{B,o,y} = 0\,\frac{m}{s}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], the resulting system of equations is:
[tex]60\,m +\left(-6.7\,\frac{m}{s} \right)\cdot t = 0\,m +\left(0\,\frac{m}{s} \right)\cdot t +\frac{1}{2}\cdot a_{S}\cdot t^{2}[/tex]
[tex]\frac{1}{2}\cdot a_{S}\cdot t^{2} +\left(6.7\,\frac{m}{s} \right)\cdot t -60\,m = 0[/tex] (Eq. 1)
[tex]0\,m = 18\,m +\left(0\,\frac{m}{s} \right)\cdot t +\frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right) \cdot t^{2}[/tex]
[tex]\frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right) \cdot t^{2}+18\,m = 0[/tex] (Eq. 2)
At first we get the time from (Eq. 2) by using the Quadratic Formula:
[tex]t_{1} \approx 1.916\,s[/tex] and [tex]t_{2}\approx -1.916\,s[/tex]
Only the first root is physically reasonable. ([tex]t\approx 1.916\,s[/tex])
Then, we substitute time in (Eq. 1) and clear the acceleration of the speedboat:
[tex]\frac{1}{2}\cdot a_{S}\cdot (1.916\,s)^{2} +\left(6.7\,\frac{m}{s} \right)\cdot (1.916\,s) -60\,m = 0[/tex]
[tex]1.836\cdot a_{S}-47.163\,m = 0[/tex]
[tex]a_{S} = 25.688\,\frac{m}{s^{2}}[/tex]
The minimum acceleration his partner will need in order to catch Bond before he hits the water is 25.688 meters per square second.
3. A sample of argon of mass 6.56 g occupies 18.5 dm? at 305 K. (a) Calculate the work done when the gas expands isothermally against a constant external pressure of 7.7 kPa until its volume has increased by 2.5 dm'. (b) Calculate the work that would be done if the same expansion occurred reversibly.
Answer:
(a) [tex]W=-19.25J[/tex]
(b) [tex]W=-52.8J[/tex]
Explanation:
Hello.
(a) In this case, since the initial volume is 18.5 dm³ and the final volume is 21 dm³ (18.5 +2.5), we can compute the work at constant pressure as shown below:
[tex]W=-P\Delta V=-7.7kPa*\frac{1000Pa}{1kPa} (21dm^3-18.5dm^3)*\frac{1m^3}{1000dm^3}\\ \\W=-19.25J[/tex]
Which is negative as it expands against the given pressure.
(b) Moreover, of the process is carried out reversibly, the pressure can change, therefore, we need to compute the work via:
[tex]W=nRTln(\frac{V_1}{V_2} )[/tex]
Whereas the moles are computed from the given mass of argon:
[tex]n=6.56g*\frac{1mol}{39.95g}=0.164mol[/tex]
Thus, the work is:
[tex]W=0.164mol*8.314\frac{J}{mol*K} *305Kln(\frac{18.5dm^3}{21dm^3} )\\\\W=-52.8J[/tex]
Regards.
The work done at isothermal expansion is [tex]19.25 J[/tex] ,The work done where there is reverse expansion is [tex]52.7J[/tex]
From the question, we were givenas[tex](21 dm^3)[/tex]
But the Initial volume increased by [tex](2.5 dm^3),[/tex]
hence final volume= [tex](21 dm^3) + (2.5 dm^3) = 21dm^3.[/tex]
But[tex]1kpa=1000pa[/tex], and [tex]1cm^3=1000dm^3[/tex]
At constant pressure, we can get the workdone asW= -(P Δ V)
If substitute the values we have
[tex]=-[(7.7 *1000pa) *(21-18.5)*(0.001m^3)[/tex]
Then, Workdone [tex]= -19.25 J[/tex]
B) incase there is a reverse expansion, the workdone can be gotten as
[tex]W= nRTIn (V1/V2)[/tex]
[tex]R= 8.314J/mole.K[/tex]
[tex]T=305K[/tex]
we can get the moles from mass of argon and its molar mass. The mass= 6.56g, mm= 39.95gThen number of [tex]mole(n) = (6.56/39.95)* 1 mole= 0.164 mole.[/tex]
Then we can substitute into the formula
[tex]W= - 0.164*8.314*305In(18.5/21)[/tex]
[tex]=-52.7J.[/tex]
Therefore, the work done, when there is reverse expansion is -52.7J
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Can someone explain what would happen if you changed something in the past or in the future then time traveled right back to the present day how it would affect the present day.
Answer:
it would affect the present day because you changed what happened so what is happening in present time would be different. think about it this way, our lives right now and what is happening right now is all based on what has happened in the past. If something else were to happen in the past our lives right now would be different.
Answer:
it would affect the present day because you changed what happened so what is happening in present time would be different.
Explanation:
In a test of a new UV-curable polymeric material (with thermal conductivity 0.15 W/(m K)) for dental prostheses, a 2.8 mm thick slab is subjected to monochromatic light with wavelength 313 nm, which is absorbed by the polymeric material according to the Beer Lambert Law of exponential attenuation. The material's surface is exposed to light at z = 0 , the rate at which light is absorbed (with dimensions of photons per unit volume per unit time) is 0 z I e γ γ − , where 0 I is the incident photon flux (with dimensions of photons per unit area per unit time), and 4 1 γ 3 10 m− − = × . (This approximation neglects the temporal decrease in absorption, among other things.) We also assume that all absorbed radiation is converted to thermal energy. (This neglects thermochemical change in the material.) If the two surfaces of the polymeric material (at z = 0 and z = 2.8 mm ) are held at 38°C, what is the largest allowable value of 0 I so that, at steady state, the maximum temperature in the polymeric material does not exceed 44°C
Answer:
The largest allowable Io = 5.863 * 10^26 photons
Explanation:
thickness of slab = 2.8 mm
First we express the energy of each photon
[tex]E = \frac{hc}{wavelength}[/tex]
wavelength = 313 nm
attached below is the detailed solution on how i arrived at the answer above
note : we use 2 in the integral because the slab is exposed to light from two different direction
a car of mass 500 kg is moving with an instantaneous speed of 80.0 km/h. what is its kinetic energy
Answer:7.5. 10^4 J
Explanation:
Answer:
The Kinetic Energy of the car at that instant will be 123,210 Joules.
Explanation:
Given:
Mass=500 Kg
[tex]Speed= 80 km/h=\frac{80*1000}{3600}\ m/s =22.2 m/s[/tex]
Required:
Kinetic energy (K.E)=?
Formula:
[tex]K.E=\frac{1}{2}mv^{2}[/tex]
Where:
m is the mass.
v is the speed.
Solution:
[tex]K.E=\frac{1}{2}mv^{2}\\K.E=\frac{1}{2} *500* (22.2)^{2} \\K.E=123,210 J[/tex]
The Kinetic Energy of the car at that instant will be 123,210 Joules.
If a set of scores has a mean of 100.00 and
a standard deviation of 5.00, what is the
variance of the standard scores?
Answer:
Variance is 25
Explanation:
Recall that the standard deviation is defined as the square root of the variance. therefore, if you know the standard deviation [tex](\sigma)[/tex], square it and you get the variance:
[tex]Variance= \sigma^2\\Variance= 5^2= 25[/tex]
how many Kingdoms are there?
Answer:
5
Explanation:
Answer:
There are 5 kingdoms
Explanation:
The scheme most often used currently divides all living organisms into five kingdoms: Moneran (bacteria), Protista, Fungi, Plantae, and Animalia. This coexisted with a scheme dividing life into two main divisions: the Prokaryote (bacteria, etc.) and the Eukaryotae (animals, plants, fungi, and protists).
A 5 kg object is dropped from the top of a 40 m tall building. What is its initial potential energy? What is its velocity the instant it hits the ground? What is its velocity after it has fallen 25 m?
Answer:
GPE = mgh = 5.00 kg .
2.20 + 0.30 m = 122.5 J
Explanation:
Please help me with this and if I have good answer u will be marked as brilliant !!!!
Help ASAP). Describe the Net Force lab and explain what the lab demonstrated? Will Mark Brainliest. Working on it now can someone please help
Answer:
In the statement of Newton's first law, the unbalanced force refers to that force that does not become completely balanced (or canceled) by the other individual forces. If either all the vertical forces (up and down) do not cancel each other and/or all horizontal forces do not cancel each other, then an unbalanced force exists. The existence of an unbalanced force for a given situation can be quickly realized by looking at the free-body diagram for that situation. Free-body diagrams for three situations are shown below. Note that the actual magnitudes of the individual forces are indicated on the diagram.
In each of the above situations, there is an unbalanced force. It is commonly said that in each situation there is a net force acting upon the object. The net force is the vector sum of all the forces that act upon an object. That is to say, the net force is the sum of all the forces, taking into account the fact that a force is a vector and two forces of equal magnitude and opposite direction will cancel each other out. At this point, the rules for summing vectors (such as force vectors) will be kept relatively simple. Observe the following examples of summing two forces:
Observe in the diagram above that a downward vector will provide a partial or full cancellation of an upward vector. And a leftward vector will provide a partial or full cancellation of a rightward vector. The addition of force vectors can be done in the same manner in order to determine the net force (i.e., the vector sum of all the individual forces). Consider the three situations below in which the net force is determined by summing the individual force vectors that are acting upon the objects.
Since illness can be caused by bacteria that live in water, pollution in water can lead to serious illness. true or false
Answer:
true, there are certain forms of bacteria in water that can cause permanent brain damage (although its rare) so further contamination of water can lead to higher chances of contracting serious illnesses caused by such bacteria.
The slope of a displacement position) vs time graph is a measurement called ____?
a) distance
b ) velocity
c ) speed
d) correlation
Answer:
velocity
Explanation:
velocity = displacement/ time
The speed of sound in air changes with the temperature. When the temperature T is 32 degrees Fahrenheit, the speed S of sound is 1087.5 feet per second. For each degree increase in temperature, the speed of sound increases by 1.1 feet per second. (Round your answers to two decimal places.) (a) Explain why speed S is a linear function of temperature T. Because S always increases by 1.1 when T increases by 1 Correct: Your answer is correct. , S has a constant rate of change and is a linear function of T. Identify the slope of the function. 1.1 Correct: Your answer is correct. (b) Use a formula to express S as a linear function of T. S = Incorrect: Your answer is incorrect. (c) Solve for T in the equation from part (b) to obtain a formula for temperature T as a linear function of speed S. T = (d) Explain in practical terms the meaning of the slope of the function you found in part (c). The slope of T as a linear function of S is , and this means that an increase in the speed of sound by 1 foot per second corresponds to an increase of degree in temperature.
Answer and Explanation:
A. We have temperature t = 32
Speed of sound, s = 1087.5
As t increases by 1⁰f speed increases by 1.2
So that
S = 1088.6
T= 33⁰f
We have 2 equations
1087.5 = k(32) + c
1088.6 = k(33) + c
Subtracting both equations
(33-32)k = 1088.6-1087.5
K = 1.1
b.). S = kT + c
1087.5 = 32(1.1) + c
Such that
C = 1052.3
Therefore
S = 1.1(t) + 1052.3
C.). S = 1.1t + 1052.3
We make t subject of the formula
T = s/1.1 - 1052.3/1.1
T = 0.90(s) - 956.3
D. This means that We have temperature to rise by 0.90 whenever speed is increased
A Gatorade bottle is dropped on a waterslide. It accelerates at 4.0 m/s2 for 9.0s from rest. What is the slide’s length?
With an acceleration of 4.0 m/s², the bottle attains a speed of
(4.0 m/s²) * (9.0 s) = 36 m/s
so that the slide has length ∆x such that
(36 m/s)² - 0² = 2 * (4.0 m/s²) * ∆x
==> ∆x = 162 m ≈ 160 m
Alternatively, we know the bottle covers a distance ∆x with acceleration a at time t according to
∆x = 1/2 a t²
so that
∆x = 1/2 * (4.0 m/s²) * (9.0 s)² = 162 m ≈ 160 m
Which of the following is true about conduction? Question 2 options: It is heat transfer through direct contact It can only occur in a liquid It is heat transfer in currents through a liquid It is heat transfer as a form of light
Answer:
through direct contact
Explanation:
took the test!
what do you understand by diffusion?
Answer:
Diffusion is a result of the kinetic properties of particles of matter. The particles will mix until they are evenly distributed. Diffusion may also be thought of as the movement of particles down a concentration gradient. The term "diffusion" comes from the Latin word diffundere, which means "to spread out."
Explanation:
Bob runs 1800 seconds at an average speed of 1.5 m/sec. How far did he go? 25 Points!!!!
Distance= Time×Speed
= 1800×1.5
= 2700 m
I am not sure it's right. the question itself is confusing.
Could you add two vectors and have the sum be smaller in magnitude than one of the vectors?
Also, why is it either yes or no?
Answer:
Let there be vectors A and B where B = -A
Then A + B = 0
Convert 0.0000004372896 to scientific notation.
O 4.372896 x 10^7
O 4.372896 x 10^-7
O 0.437 x 10^-7
O 4.37 x 10^7
Answer:
Based on the scientific notation ,
4.372896 x10^-7 is the answer.
A body moving in the positive x direction passes the origin at time t=0 . Between t=0 and t=1 second , the body has a constant speed of 24 metres per second . At t=1 second , the body is given a constant acceleration of 6 metres per second squared in the negative x direction . The position at t=11 seconds is?
Answer:
The position at t=11 seconds is -96 m or 96 m to the left of the origin
Explanation:
Constant speed and constant acceleration motion
If a body travels the same distance per unit of time, the body has a constant speed. The equation for the distance x is:
[tex]x=v.t[/tex]
Where v is the constant speed and t is the time.
At time t=0 the body is moving at a constant speed of v=24 m/s in the positive x-direction. It keeps that condition for t=1 sec. The distance traveled is:
[tex]x=24m/s\cdot 1\ s=24\ m[/tex]
Now the body is given a constant acceleration of 6 m/s^2 in the negative x-direction, that is, a=-6 m/s^2
The distance traveled by a body at constant acceleration is given by:
[tex]\displaystyle x=v_o.t+\frac{a.t^2}{2}[/tex]
Where vo is the initial speed and t is the time.
We need to find the position at t=11 sec, but we must subtract the one second already passed, thus t=10 s
[tex]\displaystyle x=24m/s\cdot 10s+\frac{-6m/s^2.(10)^2}{2}[/tex]
[tex]\displaystyle x=240\ m-360\ m=-120\ m[/tex]
This distance must be added to the actual position of the body, that is:
-120 m + 24 m = -96 m
The position at t=11 seconds is -96 m or 96 m to the left of the origin
When a certain air-filled parallel-plate capacitor is connected across a battery, it acquires a charge of 200 µC on each plate. While the battery connection is maintained, a dielectric slab is inserted into, and fills, the region between the plates. This results in the accumulation of an additional charge of 250 µC on each plate. What is the dielectric constant of the dielectric slab?
Answer:
The value is [tex]\epsilon = 2.25 [/tex]
Explanation:
From the question we are told that
The charge acquired on each plate is [tex]q = 200 \mu C = 200 *10^{-6} \ C[/tex]
The additional charge accumulated on each plate is [tex]q_a = 250 \mu C = 250 *10^{-6} \ C[/tex]
Generally the capacitance of the capacitor before a dielectric slab is inserted is
[tex]C_i = \frac{q}{V}[/tex]
=> [tex]C_i = \frac{200 \mu C}{V}[/tex]
Generally the total charge on each plate of the capacitor when the dielectric slab was inserted is
[tex]Q = q + q_a[/tex]
=> [tex]Q = ( 200 + 250 ) \mu C[/tex]
=> [tex]Q = 450 \mu C[/tex]
Generally the capacitance of the capacitor after a dielectric slab is inserted is mathematically represented as
[tex]C = \frac{450 \mu C}{V}[/tex]
Generally the dielectric constant is mathematically represented as
[tex]\epsilon = \frac{C}{C_i}[/tex]
=> [tex]\epsilon = \frac{450 \mu C}{200 \mu C}[/tex]
=> [tex]\epsilon = 2.25 [/tex]
The dielectric constant of the dielectric slab is 2.25.
Calculation of the dielectric constant:Since the charge on each playe should be q = 200 µC = 200*10^-6C
Now the additional charge accumulated should be
qa = 250µC = 250*10^-6C
Now we know that
Ci = q/v
Ci = 200µC/ V
Also,
Q = q+ qa
= 9200 + 250)µC
= 450µC
Now C = 450µC / V
So here the dielectric constant should be
= 450µC/200µC
= 2.25
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A computer model is a very complex type of _______________ model.
Answer:
mathematical model
Explanation:
A computer model is a very complex type of mathematical model.
These complex mathematical models involves series of equations or algorithms known as set of instructions for the computer to perform difficult computations. These mathematical models include dynamical systems, statistical models, or differential equations.
