The force needed to be applied by each person is 5.150×10^3 N.
The required acceleration is 3.4 m/s2 and the mass of the car is 2,159 kg.
According to Newton's second law:
F = ma
F = 2,159 × 3.4.
F = 7340.6 N
Adding the force of friction into it
F = 7340 + 310
F = 7650.6 N
Since two people need to apply the force
F = 7650 N / 2
F = 3,825.3 N
or
F = 3.825×10^3 N
The force applied by each person to push the car is 3.825×10^3 N.
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a small container of water is placed on a carousel inside a microwave oven, at a radius of 12.5 cm from the center. the turntable rotates steadily, turning through one revolution each 7.45 s. what angle does the water surface make with the horizontal?
θ = 0.0090 degree is the angle does the water surface make with the horizontal
At a radius of 12.5 cm from the center, or r = 13.5 cm, a tiny container of water is positioned on a rotating carousel within a microwave oven.
Time for every rotation is 7.15 seconds.
Fc=mrω^2
Fc=mr(2 π/T^2)^2
Fc=m12.5x10^-2(2 π/7.45)^2.....(1)
Gravitational force is caused by:
Fg=mg
Fg=mx9.8........(2)
Letθ is the angle between the water's surface and the horizontal be. Equations (1) and (2) can be used to compute it as follows:
tanθ=Fc/Fg
tanθ=m12.5x10^-2(2 π/7.45)^2/mx9.8
tanθ=0.0090
θ=0.0090 degree
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Answer: The angle between the water's surface and the horizontal is = 0.0090 degrees.
Explanation: The angle between the water's surface and the horizontal is = 0.0090 degrees.
A little container of water is placed on a revolving carousel within a microwave oven at a radius of 12.5 cm from the center, or r = 13.5 cm.
7.15 seconds pass throughout each revolution.
Fc=mrω^2
Fc=mr(2 π/T^2)^2
Fc=m12.5x10^-2(2 π/7.45)^2....(1) (1)
There is a gravitational force because of:
Fg=mg
Fg=mx9.8........(2)
Take as an example the angle formed by the water's surface and the horizontal. It can be calculated using Equations (1) and (2) as follows:
tanθ=Fc/Fg
tan = (m12.5x10-2(2 /7.45)/mx9.8)
tanθ=0.0090
0.09 degrees.
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A 4 coulombs charged particle experiences an electric force of 200 N when placed at point P in an electric field. The magnitude of the electric field at point P is :
a) 5 N/C
b) 800 N/C
c) 0.02 N/C
d) 50 N/C
(d) 50N/C
The magnitude of the electric field at point 'P' is 50N/C.
It is derived from the basic concepts of Electrostatics. Coulomb's Law is the basis of relations in Electrostatics. It resembles Newton's Law of Gravitation.
Using the relation between Electric force, charge, and Electric field:
F = qE
F = 200N; q = 4C200 = (4)E
E = 50N/C
It is widely used in the calculation of Electric Force and Electric Field. The S.I. Unit of the Electric Force is Newton. The S.I. Unit of the Electric Field is N/C. The S.I. Unit of charge is Coulomb.
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Law of Reflection :
The law of reflection states that when light rays strike a smooth surface, the angle of reflection equals the angle of incidence, and the incident ray, reflected ray, and normal to the surface all lie in the same plane.
Here, let us consider, the ray A as the normal , as it is perpendicular to the surface of the plane mirror. When the incident ray hits the plane mirror at an angle say, θ with the normal ( here, incident ray A) , then, θ will be the angle of reflection.
Now if we consider all the incident rays A, B, C and D. Among them, let the ray C make an angle Θ, with the normal ( here, incident ray A).
Therefore, from the image given, clearly, θ = Θ, hence Θ is the angle of reflection, thus ray C best represents the reflected ray.
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A car with a weight of 6996 N is subjected to a net force of 1.74e4. The cars acceleration will be
Answer: 24.37 m/s/s [forward] = a
Explanation:
First, find mass with the Fgrav formula.
Fgrav=mg
6996=m(9.8)
713.88 kg
Then, plug the answer into Newton's second law formula.
Fnet = ma
1.74e4 = (713.88)a
(1.74e4)/(713.88) = a
24.37 m/s^2 = a
If the mass of a system is halved (m’=m/2) and the net force acting on it is doubled (F’=2F), then its acceleration would be:* 7 points unchanged (x1) halved (x0.5) quartered (x0.25) doubled (x2) quadrupled (x4)
Given:
The mass of the system is m' =m/2
The net force acting on it is F' = 2F
To find the acceleration.
Explanation:
The acceleration will be
[tex]\begin{gathered} a^{\prime}=\frac{F^{\prime}}{m^{\prime}} \\ =\frac{2F}{\frac{m}{2}} \\ =\frac{4F}{m} \\ a^{\prime}=4a \end{gathered}[/tex]Thus, the acceleration would be quadrupled(x4).
What is the equation for momentum (p)?
Answer:
p(momentum) = mass(kg) x velocity (m/s)
True or false? The period of an AC supply is equal to the time between an adjacent peak and trough on an oscilloscope trace.
Answer:
false
Explanation:
the time period is for a whole cycle of the wave, so peak-to-peak on an oscilloscope trace.
pls the answer.........................................................................................................................
a) The motion of the motorcyclist is a uniform motion
b) The distance is 600 m
c) The speed is 20 m/s.
What is the motion?We now that motion has to do with the change in the position of an object with time. In this case, we have the graph that described the motion of the motorcyclist . It is clear that the distance is increasing in equal amounts, in equal time intervals thus this is a uniform motion.
Looking at the graph, we can see that the motorcyclist covers 600 meters of distance within 30 seconds.
We can obtain the speed as the ratio of the distance to the time or the slope of the graph. Hence the speed is obtained from;
Speed = distance / time
Using the slope concept;
[tex]y_{2} - y_{1} /x_{2} - x_{1}[/tex]
= 600 - 0/30 - 0
= 20 m/s
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Two electromagnetic waves are traveling through a material. Wave 1 has a maximum electric field strength that is three times the maximum field strength of wave 2. How do the average intensities of the waves compare?.
The average intensities of the waves compare I1 = 9 x I2.
The electric field of an electromagnetic wave points in the positive y direction. At the same time, the magnetic field of this wave points in the positive z direction. In the electromagnetic field, electric and magnetic fields exist in the form of waves in horizontal and vertical patterns. To exist in this pattern requires maximum amplitude. Charged particles create electric fields.
This electric field exerts forces on other charged particles. A positive charge accelerates in the direction of the electric field, and a negative charge accelerates in the direction of the electric field. Magnetic fields are generated when charged particles move. In electromagnetic waves, the electric and magnetic fields are perpendicular to each other and both are also perpendicular to the direction of wave propagation.
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The concept of inertia forms the basis for Newton's Third Law of Motion True False
Given
The concept of inertia forms the basis for Newton's Third Law of Motion
To find
The given statement is true or false
Explanation
The third law of motion states that every action has a equal and opposite reaction
Inertia is the property by virtue of which an object at rest tends to be at rest and object at motion tends to be at motion
Thus both the concept are not similar
Conclusion
The given statement is false
the cliff divers of acapulco push off horizontally from rock platforms about 35 m above the water, but they must clear the rocky outcrops at water level that extend out into the water 5 m from the base of the cliff directly under their launch point. what minimum speed is necessary to clear the rocks? how long are they in the air?
The minimum speed necessary for the diver to clear the rocks 10.59m/s and the diver will be in air for about 2 seconds.
From the provided situation, we can analyze that the path of travel of the diver will be a projectile.
The maximum horizontal range is 35 meters.
And the height required is 5 meters.
We know, for a projectile,
Horizontal range R is given by U²sin(2A)/g
The height H attained is given by U²sin²A/2g
Dividing the height by range,
H/R = tanA/4
TanA = 20/7
Now, we can find,
SinA = 21.18
We know,
H = U²sin²A/2g
U²=2Hg/Sin²A
U²=2(5)(10)/(20/21.18)²
U = 10.59m/s.
The diver should start with speed of 10.59m/s to clear the rocks.
The time of flight is given by,
T = 2UsinA/g
Putting the values,
T = 2(10.59)(20/21.18)/10
T = 2 seconds.
The diver will be in air for 2 seconds.
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24) A 0.042-kg pet lab mouse sits on a 0.35 kg air-track cart. The cart is at rest, as is a second cart with a mass of 0.25 kg. The lab mouse now jumps to the second cart. After the jump, the 0.35-kg cart has a speed of u1=0.88m/s. What is the speed v2 of the mouse and the 0.25-kg cart? |
The mass of the mouse, m₁=0.042 kg
The mass of the 1st cart, m₂=0.35 kg
The mass of the second cart, m₃=0.25 kg
The speed of the 1st car after the jump, u₁=0.88 m/s
From the law of conservation of momentum, the momentum of a system should always remain the same.
Before the mouse jumps from one cart to another, all the objects were at rest. Therefore the total momentum of the system was zero.
Thus after the mouse jumps, the total momentum of the system should be equal to zero.
Thus the momentum of the second cart and the mouse will be equal in magnitude to the momentum of the first cart but it will be in the opposite direction.
Thus,
[tex]m_2u_1=(m_1+m_3)v_2[/tex]On substituting the known values,
[tex]\begin{gathered} 0.35\times0.88=(0.042+0.25)v_2 \\ \Rightarrow v_2=\frac{0.35\times0.88}{(0.042+0.25)} \\ =1.05\text{ m/s} \end{gathered}[/tex]Thus the speed of the mouse and the second cart after the mouse jumps is 1.05 m/s
A race car speeds up from 0 m/s to 40.0 m/s in 4 seconds. What is the vehicle's acceleration?
A. 16 m/s²
B. 10.0 m/s²
C. 4.0 m/s²
D. 8.0 m/s²
Answer: b) 10.0 m/s
Explanation: Acceleration = [tex]\frac{v-u}{t}[/tex]
V-U
T
v= final velocity
u= initial velocity
t= time in secs
Answer:
ur mom go study nerd u for real
A 33-N force is applied to a 7-kg object to move it with a constant velocity of 6.3 m/s across a level surface. The coefficient of friction between the object and the surface is approximately ____. Round your answer to the hundredths place.(Use the approximation g ≈ 10 m/s2.)
Given:
The applied force is,
[tex]F=33\text{ N}[/tex]The mass of the object is,
[tex]m=7\text{ kg}[/tex]The constant velocity of the object is,
[tex]v=6.3\text{ m/s}[/tex]To find:
The coefficient of friction between the object and the surface
Explanation:
The object is moving with a constant velocity which means the object is under equilibrium. So, the applied force is equal to the frictional force on the object.
If the coefficient of friction between the object and the surface is
[tex]\mu[/tex]we can write the frictional force as,
[tex]f=\mu mg[/tex]For equilibrium condition,
[tex]\begin{gathered} \mu mg=F \\ \mu=\frac{F}{mg} \\ \mu=\frac{33}{7\times10} \\ \mu=0.47 \end{gathered}[/tex]Hence, the coefficient of friction between the object and the surface is 0.47.
. is a major factor in dictating how much energy the vehicle can absorb to protect the occupants. a. frictional energy b. angle of attack c. speed d. all of the above
The correct answer is option c, speed.
Speed is the rate at which someone or something moves or operate. It is measured by the velocity and time.
Velocity is the total distance in total time taken.
Speed tells the amount of energy absorbed by the vehicle. The energy is used in the movement of the vehicle and it also helps the vehicle to move accordingly.
Speed is the major factor that helps to protect the occupants.
It is speed only that we can adjust a according to the situation. This also keeps the vehicle in control. It is the main factor in any vehicle that causes the vehicle to move and also it helps to keep it in control as well. Other controls are the supporting factors that helps to keep the speed in control.
Be it the weather, the climate, roads or traffic, it is speed that helps to keep the occupants safe.
Therefore, Speed is a major factor in dictating how much energy the vehicle can absorb to protect the occupants
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what is the loudness and softness of music related to specifically? multiple choice question. beats of two tones that are similar in frequency tone color of the instrument producing the sound frequency of the vibration that produces the sound amplitude of the vibration that produces the sound
The correct answer choice from above among loudness and softness of music in a wave system is connected by means of amplitude of the vibration that produces the sound.
The correct answer choice is option d.
How the loudness and softness of music is linked with amplitude.In general, the amplitude of a wave of a music is related to how soft or loud a music is as this depends largely on that force of vibration in the the musical system. For instance, when you hit the the wooden or iron door of a building, a soft sound is produced. This happens simply because amplitude.
Be that as it may, a wave is referred to as a disturbance which travels through a particular medium, transferring energy from one point to another point.
So therefore, the amplitude of a wave goes a long way to determine the loudness and softness of music.
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Question 6:A particle of mass 0.2 kg is moving in a straight line at speed 2.5ms, a constant force of magnitude FN is applied to it in the direction in which it is moving. The speed of the particle 5 seconds later is 4.5ms Find the value of F, magnitude of the force applied.
First, let's calculate the particle acceleration, using the formula below:
[tex]\begin{gathered} V=V_0+a\cdot t \\ 4.5=2.5+a\cdot5 \\ 5a=4.5-2.5 \\ 5a=2 \\ a=\frac{2}{5}=0.4\text{ m/s}^2 \end{gathered}[/tex]Now, to find the force applied, let's use the second law of Newton:
[tex]\begin{gathered} F=m\cdot a \\ F=0.2\cdot0.4 \\ F=0.08\text{ N} \end{gathered}[/tex]Therefore the value of F is 0.08 N.
a circuit consists of a 10.0-volt battery, its internal resistor of 2.00 ohms, a resistor of 4.00 ohms, and an ammeter. the battery and the resistors are connected in series in a closed loop. the ammeter is parallel to the battery and its internal resistor. part a find the reading of the ammeter.
The ammeter will read the current as 1.67 A.
An ammeter is a device that measures the current through the conductor. The reading of the ammeter depends on the resistance and voltage. Resistance can be defined as the ratio of the voltage applied to the current flow It can be written as
R = V / I
where R is resistance, V is voltage and I is current.
From the question above, we know that
V = 10 V
r = 2 Ω
R = 4 Ω
Find the current by substituting the given parameters
V = I . ( R + r )
10 = I ( 4 + 2 )
10 = 6 I
I = 10 / 6
I = 1.67 A
Hence, the ammeter will read the following current.
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a cat slides down a slippery slanted roof at an acceleration of 2.2 m/s2 (it won't get hurt because it has nine lives). if it started at the top with zero initial speed, how far will the cat have slipped after 3 seconds? answer in meters and include two digits after the decimal point.
The cat will have slipped till the distance of 9.90 seconds in 3 seconds.
The acceleration of the cat is 2.2m/s², the initial velocity of the cat is 0m/s and the time take the cat takes to come down is 3 seconds.
Now, using equation of motion,
S = Ut + 1/2at²
Where,
U is initial velocity of the body,
t is the time period of the body,
S is the displacement of the body,
a is the acceleration of the body.
Putting all the values,
S = 1/2at²
S = 1/2(2.2)(3)²
S = 9.90 meters.
The distance to which the cat will fall is 9.90 meters.
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a 2 900-kg truck moving at 11.0 m/s strikes a car waiting at a traffic light, hooking bumpers. the two continue to move together at 7.00 m/s. what was the mass of the struck car?
The mass of the car that was stuck is 1657 Kg.
What is the mass of the struck car?We know that we have to use the laws of the conservation of the linear momentum here. It is known that the momentum before collision must be equal to the total momentum that we have after collision.
In this case, we have;
m1u1 + m2u2 = m1v1 + m2v2
m1 = mass of the truck
m2 = mass of the car
u1 and v1 = the initial and final velocities of the truck
u2 and v2 = initial and final velocities of the car
Again we are told that the two continue to move together hence v1 + v2 = v
m1u1 + m2u2 = (m1 + m2) v
(2900 * 11.0) + 0 = (2900 + m2) 7
31900 = 20300 + 7m2
31900 - 20300 = 7m2
m2 = 31900 - 20300 /7
m2 = 1657 Kg
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Show how you got the answer, please
Question:
A wave with a frequency of 14 Hz has a wavelength of 3 meters. At what speed with this wave travel?
Answer:
42m/s
Explanation:
v= λf
Frequency of wave: f= 14Hz
the wavelength of the wave: λ=3m
speed of wave: s=?
speed = frequency * wavelength
s = 14 * 3 = 42 m/s.
the temperature of the earth is determined by the amount of solar radiation received, the amount of solar energy reflected, and the amount of heat retained by the what?
The temperature of the Earth is determined by the amount of solar radiation received, the amount of solar energy reflected, and the amount of heat retained by the atmosphere.
What is temperature?
The physical concept of temperature expresses in numerical form how hot or cold something is. A thermometer is used to determine temperature. Thermometers are calibrated using a variety of temperature scales, which historically defined various reference points as well as thermometric substances. The most popular scales are the Celsius scale, also known as centigrade, with the unit symbol °C, the Fahrenheit scale (°F), as well as the Kelvin scale (K), with the latter being primarily used for scientific purposes. One of the International System of Units' seven base units is the Kelvin (SI).
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a rocket started at rest.after initiating the launch,it had an acceleration of 90m/s2.how long did it take to reach a speed of 2430 m/s2
The time taken for the rocket to reach a speed of 2430m/s from rest is 27.0 seconds.
What is the time taken for the rocket to reach a speed of 2430m/s?Motion is simply the change in position of an object over time.
From the First Equation of Motion;
v = u + at
Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.
Given the data in the question;
Since it starts from rest, Initial velocity u = 0m/sFinal velocity v = 2430m/sAcceleration a = 90m/s²Elapsed time t = ?To determine the time, substitute the given values into the formula above and solve for t.
v = u + at
2430m/s = 0 + ( 90m/s² × t )
2430m/s = 90m/s² × t
t = 2430m/s / 90m/s²
t = 27.0s
Therefore, the elapsed time is 27.0 seconds.
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A rocket launched with an acceleration of 90 m/s², and a final speed of 2430 m/s. So the time required to reach the final speed is 27 seconds.
What is acceleration?The ratio of change in velocity to time is referred to as acceleration. It has a SI unit m/s² with dimension formula MLT⁻².
According to the question, the given values are,
Final velocity, v = 2430 m/s
Initial velocity, u = 0 m/s
The acceleration is given as, a = 90 m/s².
Use the equation of motion to find the time required to reach the final speed,
v = u + at
2430 = 0 + ( 90 × t )
2430 = 90 × t
t = 2430 / 90
t = 27.0 seconds.
Hence, the time taken to reach the final speed is 27 seconds.
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1. a circular coil 0.0500 m in radius, with 30 turns of wire, lies in a horizontal plane. it carries a counterclockwise (as viewed from above) current of 5.00 a. the coil is in a uniform 1.20 t magnetic field directed toward the right. find the magnitudes of the magnetic moment and the torque on the coil.
Magnetic moment of the given coil is 1.178 Am²
Torque of the given coil is 1.414 TAm²
Radius of the coil = 0.05 m
Number of turns in the coil = 30 turns
Current passing through the coil = 5 A
Magnetic field in the coil = 1.2 T
The current flows in counterclockwise direction. Therefore by thumbs rule, the magnetic field flows towards right side.
The magnetic moment of the coil
M = N x I x A
where N is the number of turns in the coil
I is the current passing through the coil
A is the area of the coil
Let us substitute the known values in the above equation,
M = 30 x 5 x πr²
= 30 x 5 x 3.14 x (0.05)²
= 471 x 0.0025
= 1.178
The magnetic moment of the given coil is 1.178 Am²
The torque of the coil can be found using
τ = M x B
where M is the magnetic moment and
B is the magnetic field produced due to the coil.
τ = 1.178 x 1.20
= 1.414 TAm²
Therefore , the torque of the coil is 1.414 TAm²
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An atmospheric layer of a specific gas provides shielding from harmful ultraviolet light from the sun, allowing life to thrive on earth. What gas makes up this layer?.
Since stratospheric ozone shields life on Earth from harmful ultraviolet (UV) radiation, it is frequently referred to as "good" ozone.
How does the atmosphere safeguard life on Earth?It not only has the oxygen we require to survive, but it also shields us from dangerous UV sun radiation. It generates the pressure necessary for liquid water to exist on the surface of our planet. Additionally, it heats our planet and maintains conditions that allow life to exist on Earth.
The ozone layer, located higher up in the stratosphere, absorbs solar ultraviolet radiation and modulates the amount of heat that is returned to space from the Sun. Overexposure to UV radiation may cause sunburn, skin cancer, and eye damage. The ozone layer protects humans from these negative consequences.
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To program a digital turtle to trace the outline of a hexagon, what code should be used?
A.
forward 50
B.
repeat 6 [forward 50 right 60]
C.
repeat 3 [forward 50 right 90]
D.
repeat 4 [forward 50 right 60]
To program a digital turtle to trace the outline of a hexagon, the code that should be used is repeat 6 [forward 50 and right 60]. Hence, option B is correct.
What is a program?A computer utilizes a program, which is a collection of instructions, to carry out a particular task. A program is like a computer's recipe, to use an analogy. It has a list of components (known as variables, which can stand for text, graphics, or numeric data) and a list of instructions (known as statements), which instruct the computer on how to carry out a certain operation.
Programming languages with particular syntax, like C++, Python, and Ruby, are used to develop programs. These high-level programming languages are written and readable by humans.
According to the question, the hexagon has six sides so the turtle has to repeat 6 times. Hence, option B is correct.
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Victor is using his Geiger-counter to record the amount of radiation that is leaking into the soil from a nearby nuclear disposal site. This radiation decreases by the square of the distance from the source. If he starts measurements 100 m from the disposal site how close will he need to stand if he hopes to measure soil with 4 times the radiation?
According to inverse square proportionality, measuring 4 times more radiation will require Victor to _____ his distance. Victor will need to stand _____ m from the disposal site.
If Victor starts measurements 100 m from the disposal site, he needs to stand 50 m from the source if he hopes to measure soil with 4 times the radiation.
I = 1 / r²
I = Intensity
r = Distance
At a distance of 100 m from the source,
I = 1 / 100²
I = 1 / 10000
I = [tex]10^{-4}[/tex] J / m² s
Four times this radiation will have an intensity of,
I = 4 * [tex]10^{-4}[/tex] J / m² s
4 * [tex]10^{-4}[/tex] = 1 / d²
d² = 1 / 4 * [tex]10^{-4}[/tex]
d² = 0.25 * [tex]10^{4}[/tex]
d = √ 25 * 10²
d = 5 * 10
d = 50 m
Therefore, he needs to stand 50 m from the source
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A box measures 3 centimeters on each side and has a mass of 47 grams , what is the density
Answer:
[tex]3 \times 47 = [/tex]
141
what is the velocity (in m/s) of a 925 kg car initially moving at 29.5 m/s, just after it hits a 145 kg deer initially running at 12.5 m/s in the same direction? assume the deer remains on the car. (enter the magnitude.)
The velocity after the collision is 27.19 m/s
What is the law of conservation of momentum?For a collision between Object 1 and Object 2 in an isolated system, the total momentum of the two objects before collision equals the total momentum of the two objects after collision. That is, the momentum lost from object 1 is equal to the momentum gained from object 2 (a constant or unchanging value). It can be stated by following equation:
Pₙ = mₙvₙ
mₙvₙ = m₁v₁ + m₂v₂
Where, Pₙ = final momentum
mₙ = total mass of the system
vₙ = final velocity of the system
For the given case,
Since, mₙvₙ = m₁v₁ + m₂v₂
(m₁ + m₂)vₙ = m₁v₁ + m₂v₂
(925 + 145)vₙ = (925 × 29.5) + (145 × 12.5)
1070 vₙ = 27287.5 + 1812.5
1070 vₙ = 29100
vₙ = [tex]\frac{29100}{1070}[/tex]
vₙ = 27.19 m/s
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Please I need at least 3 differences between high and low specific heat capacity I will mark you brainliest
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| Specific Heat Capacity |"What Is It and What Are Some Differences Between High and Low Specific Heat Capacity?"
===========================================================
Hello! Today, let's begin with discussing what specific heat capacity is.
"What is Specific Heat Capacity?"
It is the amount of heat per unit required to increase the temperature by 1°C. Most of the time, specific heat is used for determining the processing temperatures as well as amount of heat that is necessary for processing. It is helpful in differentiating between that of two polymeric composites.XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
"What is High and Low Specific Heat Capacity?"
Now, this specific situation is asking a question regarding the differences between high and low specific heat capacity. When the specific heat capacity is high, this means that it takes more energy to either increase or decrease its temperature. Take water for instance; water has a high specific heat, meaning it will take more energy to increase the temperature of the liquid compared to other substances. That's why when you are boiling water in a pot, the water needs time to absorb heat before it begins to boil at the increase in temperature.On the other hand, when the specific heat capacity is low, this means that it doesn't take as much energy to increase or lower as high SHC does. For example, any metals such as iron have low specific heat. It doesn't take long for the substance's energy to increase the temperature. The same thing occurs when you place a spoon in a cup of hot coffee. It is said that even other substances like sand have relatively low specific heat.______________________________________________________
Hopefully this sort of helps you have a better understanding of what specific heat is, as well as the differences between that of high and low specific heat capacity. Also, if this is a write your answer response, it is better to dive further into your studies and notes regarding this topic so you can properly answer the question and follow the guidelines. Anyways, I wish you the best of luck on your assignment. Thanks for reading!
