Find out the division
3x^4-6x^3-8x+16 : (x-2)
3x^3-8
-3x^4+6x^3
-----------------------
-8x+16
8x-16
------------
0
The remainder is zero
that means
The expression (x-2) is a factor of the polynomial
so
3x^4-6x^3-8x+16=(x-2)(3x^3-8)
Enter your solution as an ordered pair, with no spaces and with parentheses. OR the answer could be: Infinitely many OR No Solution
Given the equation system:
[tex]\begin{gathered} 1)y=4x \\ 2)3x+2y=55 \end{gathered}[/tex]The first step is to replace the first equation in the second equation
[tex]3x+2(4x)=55[/tex]With this, we have a one unknown equation. Now we can calculate the value of x:
[tex]\begin{gathered} 3x+8x=55 \\ 11x=55 \\ \frac{11x}{11}=\frac{55}{11} \\ x=5 \end{gathered}[/tex]Now that we know the value of x, we can determine the value of y, by replacing x=5 in the first equation
[tex]\begin{gathered} y=4x \\ y=4\cdot5 \\ y=20 \end{gathered}[/tex]This system has only one solution and that is (5,20)
Given that p = 6 and q = 2, which yields a quotient greater than -9? ОА -3 a -р B 3 O a O С Зр. (-9) (0) D (-p) (-39)
solve for missing variable: 11y-36=63
The equation can be solved as,
[tex]\begin{gathered} 11y-36=63 \\ 11y=63+36 \\ 11y=99 \\ y=\frac{99}{11} \\ y=9 \end{gathered}[/tex]Therefore, the value of y is 9.
Matt and Amy each had summer jobs. Matt worked at a restaurant as a bus boy. He earned $10 per hour, plus tips. Amy worked as a dog-groomer. She earned $8 per hour, plus tips.A) Create an equation to represent their total earnings in each situation. Explain what each of the variables represent.
Given:-
Matt and Amy each had summer jobs. Matt worked at a restaurant as a bus boy. He earned $10 per hour, plus tips. Amy worked as a dog-groomer. She earned $8 per hour, plus tips.
To find:-
An equation to represent their total earnings in each situation.
The dog looked at the cat warily A with interestb viciously c hungrily d with caution
Answer
Option D is correct.
The dog looked at the cat with caution.
is the same as
The dog looked at the cat warily.
Explanation
The word warily means 'using caution' or 'cautiously'.
Hope this Helps!!!
In gym class, a student can do 30 sit-ups in 60 seconds and 90 sit-ups in 180 seconds.
Graph the proportional relationship.
graph with x axis labeled time seconds and y axis labeled sit ups, with a line from 0 comma 0 going through 90 comma 60
graph with x axis labeled time seconds and y axis labeled sit ups, with a line from 0 comma 0 going through 120 comma 60
graph with x axis labeled time seconds and y axis labeled sit ups, with a line from 0 comma 0 going through 60 comma 50
graph with x axis labeled time seconds and y axis labeled sit ups, with a line from 0 comma 0 going through 90 comma 30
A graph of the proportional relationship is given by: D. graph with x axis labeled time seconds and y axis labeled sit ups, with a line from 0 comma 0 going through 90 comma 30.
What is a graph?A graph can be defined as a type of chart that's commonly used for the graphical representation of data points on both the horizontal and vertical lines of a cartesian coordinate, which are the x-coordinate and y-coordinate.
Mathematically, a proportional relationship can be modeled by the following linear equation:
y = kx
Where:
y and x are the variables.k represents the constant of proportionality.Furthermore, the graph of any proportional relationship is characterized by a straight line with data points passing through the origin (0, 0) because as the values on the x-coordinate (x-axis) decreases or increases, the values on the y-coordinate (y-axis) decreases or increases simultaneously.
In this context, we can reasonably infer and logically deduce that the relationship between the values on the x-coordinate (x-axis) and y-coordinate (y-axis) of this graph is proportional and given by this equation:
y = 3x
Where:
y represent the number of sit-ups.x represent the time.Read more on graphs here: brainly.com/question/4546414
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Answer:
A graph of the proportional relationship is given by: D. graph with x axis labeled time seconds and y axis labeled sit ups, with a line from 0 comma 0 going through 90 comma 30.
Step-by-step explanation:
The product two consequences positive even numbers is 728. Find the smaller of the two numbers. The smaller number is
Let the first number = n
So second number = n+2
the product of number is 728.
That mean:
[tex]n(n+2)=728[/tex]Solve the equation:
[tex]\begin{gathered} n(n+2)=728 \\ n^2+2n=728 \\ n^2+2n-728=0 \end{gathered}[/tex][tex]\begin{gathered} n^2+2n-728=0 \\ n^2+28n-26n-728=0 \\ n(n+28)-26(n+28)=0 \\ (n+28)(n-26)=0 \\ n=-28;n=26 \end{gathered}[/tex]For positive number is n=26.
scond number is:
[tex]\begin{gathered} =n+2 \\ =26+2 \\ =28 \end{gathered}[/tex]So smaller number is 26.
A math teacher said that 18 out of 25 students passed the test. What percent of thestudents did NOT pass the test?C.72%A.18%D.28%B.82%
Let's begin by listing out the given information:
18 students passed
Total students = 25
Number of people who did not pass = 25 - 18 = 7
7 out of 25 students did not pass. This has its percentage as:
[tex]\begin{gathered} \frac{7}{25}\cdot100\text{\%}=28\text{\%} \\ \Rightarrow28\text{\%} \end{gathered}[/tex]Therefore, 28% of the students did not pass
what does y= 75-29 equal?
Starting with the expression:
[tex]y=75-29[/tex]Substract the numbers to find the value of y:
[tex]y=46[/tex]Answer:
if y = 75-29 the we subtract 29 from 15
75-29=46
y=46
Maggie has $30 in an account. The interest rate is 10% compounded annually.To the nearest cent, how much will she have in 1 year?Use the formula B=p(1+r)t, where B is the balance (final amount), p is the principal (starting amount), r is the interest rate expressed as a decimal, and t is the time in years.
Solution:
Using the formula;
[tex]\begin{gathered} B=p(1+r)^t \\ \\ \text{ Where }B=balance,p=principal,r=rate,t=time \end{gathered}[/tex][tex]p=30,r=10\text{ \%}=0.1,t=1[/tex]Thus;
[tex]\begin{gathered} B=30(1+0.1)^1 \\ \\ B=33 \end{gathered}[/tex]ANSWER: $33
which transformation occurred to create the graph shown below from square root parent function?
Solution:
Given the function:
[tex]f(x)=\sqrt{x+4}[/tex]whose graph is shown below:
Suppose that the parent function is expressed as
[tex]f(x)=\sqrt{x}[/tex]This implies that the parent function is transformed by a horizontal shift to the left by four spaces.
The correct option is
find the missing value in the given equivalent ratios 9:5=__:35
First, let's express the proportion as an equation, where the blank space is the variable x.
[tex]\frac{9}{5}=\frac{x}{35}[/tex]To find the value of x, we multiply both sides by 35.
[tex]\begin{gathered} \frac{9}{5}\cdot35=\frac{x}{35}\cdot35 \\ x=63 \end{gathered}[/tex]Therefore, the missing value is 63.Which phrase best describes the translation from the graph y = 2(x-15)² + 3 to the graph of y = 2(x-11)² + 3?O4 units to the left4 units to the rightO 8 units to the leftO 8 units to the rightMark this and returnSave and ExitNextSubmit
Given:
it is given that a graph of the function y = 2(x-15)^2 + 3 is translated to the graph of the function y =2(x - 11)^2 + 3
Find:
we have to choose the correct option for the given translation.
Explanation:
we will draw the graphs of both the functions as following
The graph of the function y = 2(x - 15)^2 + 3 is represented by red colour and the graph of the translated function y = 2(x - 11)^2 + 3 is represented by blue colour in the above graph.
From, the graphs of both functions, it is concluded that the graph of the translated function is shifted 4 units to the left.
2. Simba pays $15 per month
for the phone he bought. His cell phone plan costs $49
per month and includes 15GB of
data. He also pays $5 for each additional 1GB
of data he uses over the 15GB limit. Using x to represent the GB of data
he uses over 15 GB, write an equation to represent Simba's monthly cell
phone bill and determine how much he will pay if one month he uses
23GB of data.
The equation can be given as B=64+5x
And the cost of phone bill if he uses 23GB will $104
What is an linear equation is one variable?
An linear equation is an equation of degree one. the highest exponent is 1 and one variable is number of variable is 1 in the equation
We are given that, Simba pays $15 per month for the phone he bought. His cell phone plan costs $49 per month.
He pay additional $5 for 1 gb data after 15gb data limit got over
Let the number of gb's used be x
Hence the total bill will be given by the equation
B= 15+49+5x
B= 64+5x
If he uses 23 gb of data the first 15 Gb are covered in his phone plan
And he has to pay $5 for each gb
The total cost is 8*5=$40
Hence the total phone bill is B=64+40
B=$104
Hence the equation can be given as B=64+5x
And the cost of phone bill if he uses 23GB will $104
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You purchase a TV set that is originally valued at $1090. You receive a 45% discount on the purchase of a promo. Your sales tax rate is 7%. What is the total cost of the merchandise?
Answer:
The answer would be $641.47 I believe.
Step-by-step explanation:
can you help me with discount tax tip and markup
Answer:
Final Price = $24.5
Explanation:
To found the final price, we first need to find 30% of $35 as follows:
[tex]35\times30\text{ \% = 35}\times\frac{30}{100}=10.5[/tex]So, there will be a discount of $10.5
Then, the final price will be the original price less the 30% of $35, so the final price will be equal to:
Final Price = Original Price - Discount
Final Price = $35 - $10.5
Final Price = $24.5
So, the answer is $24.5
find the sum to infinity 16,4,1,1/4
Answer:
The sum to infinity of the given series is;
[tex]S_{\infty}=21\frac{1}{3}[/tex]Explanation:
From the given series, we can see that the series is a Geometric Progression (GP) because it has a common ratio;
[tex]\begin{gathered} r=\frac{4}{16}=\frac{1}{4} \\ r=0.25 \end{gathered}[/tex]The formula to calculate the sum to infinity of a GP is;
[tex]\begin{gathered} S_{\infty}=\frac{a}{1-r} \\ \text{For;} \\ 0Where;a = first term = 16
r = common ratio = 0.25.
substituting we have;
[tex]\begin{gathered} S_{\infty}=\frac{16}{1-0.25}=\frac{16}{0.75} \\ S_{\infty}=21\frac{1}{3} \\ S_{\infty}=21.33 \end{gathered}[/tex]Therefore, the sum to infinity of the given series is;
[tex]S_{\infty}=21\frac{1}{3}[/tex]On December 13, 2007, one South African rand was worth 0.15 U.S. dollars.(a) On that date, how many rand was 44.11 dollars worth?Round your answer to the nearest hundredth of a rand.rand(b) On that date, how many dollars was 168.18 rand worth?Round your answer to the nearest hundredth of a dollars. I need help with this math problem.
Explanation
Part A
Given that one South African rand was worth 0.15 U.S. dollars. 44.11 dollars will be worth
[tex]\frac{44.11}{0.15}=294.07[/tex]Answer: 294.07 rands
Part B
On that date, how many dollars was 168.18 rand worth?
[tex]168.18\times0.15=25.23[/tex]Answer: 25.23 dollars
Which of the following numbers are greater than 6 and less than 8? Explainhow you know.
Let's analyze each case and see if they are less than 8 first:
[tex]7<8,therefore(7)^{\frac{1}{2}}<8[/tex][tex]\sqrt[]{64}=8[/tex]thus
[tex]\sqrt[]{60}<\sqrt[]{64}=8[/tex][tex]\sqrt[]{60}<8[/tex]Finally,
[tex]64<80[/tex][tex]\sqrt[]{64}<\sqrt[]{80}[/tex]thus
[tex]8<\sqrt[]{80}[/tex]In sumary, the first two options are less than 8, but not the third.
Now let's see if they are greater than 6
[tex]9>7[/tex][tex]\sqrt[]{9}>\sqrt[]{7}[/tex][tex]3>\sqrt[]{7}[/tex]and
[tex]6>3>\sqrt[]{7}[/tex]thus
[tex]6>\sqrt[]{7}[/tex]Now
[tex]36<60[/tex][tex]\sqrt[]{36}<\sqrt[]{60}[/tex]and so
[tex]6<\sqrt[]{60}[/tex]Finally
[tex]\sqrt[]{80}>\sqrt[]{60}>6[/tex]thus
[tex]\sqrt[]{80}>6[/tex]In conclussion, the second and third options are greater than 6, but not the first.
Find the rational number halfway between and 1/6 and 3/4
In order to find the middle number between them we can simply add them together and divide the result by 2 as follows:
[tex]\begin{gathered} \frac{1}{6}+\frac{3}{4}=\frac{11}{12} \\ Now_{\text{ }}divide_{\text{ }}by_{\text{ }}2: \\ \frac{11}{12}\div2=\frac{11}{24} \end{gathered}[/tex]Answer:
11/24
Which is equal to 2 over 5? A. 2%B. 2.5%C. 20%D. 25%E. 40%
Calculating the value of 2 over 5 in percentage, we have:
[tex]\begin{gathered} \frac{2}{5}=\frac{20}{50}=\frac{40}{100}=40\text{\%} \\ or \\ \frac{2}{5}=0.4=40\text{\%} \end{gathered}[/tex]So the correct option is E.
Quincy has a jewelry business in which he designs and sells bracelets. His daily profit, Q(x), can be modeled by the function Q(x) = 7.25x − 36.25, where x is the number of bracelets he sells. What is the value of Q(5), and what is its interpretation?
Q(5) = 0; If Quincy sells 0 bracelets, he will earn $5.
Q(5) = 0; If Quincy sells 5 bracelets, he will earn $0.
Q(5) = 5.69; If Quincy sells 5.69 bracelets, he will earn $5.
Q(5) = 5.69; If Quincy sells 5 bracelets, he will earn $5.69.
The value of Q(5) is zero and represents the zero profit on selling 5 bracelets thus option (B) is correct.
What is a function?A certain kind of relationship called a function binds inputs to essentially one output.
The machine will only accept specified inputs, described as the function's domain, and will potentially produce one output for each input.
As per the given,
Daily profit function Q(x) = 7.25x − 36.25 where x is the number of bracelets he sells.
At x = 5 ( selling 5 bracelets)
Q(5) = 7.25(5) - 36.25
Q(5) = 36.25 - 36.25 = 0
It means selling 5 bracelets doesn't give any profit.
Hence "The value of Q(5) is zero and represents the zero profit on selling 5 bracelets".
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PLS HELP WILL ASAP WILL GIVE BRAINLIST
Answer:
if the bottom side is 4n + 15, then n=8
n times 5 is 40
40+7=47
Please help i need the answers for a test and how to work em out for the future
Given: The angles as shown in the image
[tex]\begin{gathered} m\angle DEY=105^0 \\ m\angle DEF=27x+3 \\ m\angle YEF=6x+3 \end{gathered}[/tex]To Determine: The measure of angle DEF
Solution
It can be observed that
[tex]\begin{gathered} m\angle DEY+m\angle YEF=m\angle DEF \\ Therefore \end{gathered}[/tex][tex]\begin{gathered} 105^0+6x+3=27x+3 \\ 105=27x-6x+3-3 \\ 105=21x \\ x=\frac{105}{21} \\ x=5 \end{gathered}[/tex][tex]\begin{gathered} m\angle DEF=21x+3 \\ =21(5)+3 \\ =105+3 \\ =108 \end{gathered}[/tex]Question 12
Given:
[tex]\begin{gathered} m\angle UIJ=x+43 \\ m\angle HIJ=66 \\ m\angle HIU=x+37 \end{gathered}[/tex]To Determine: The measure of angle HIU
Solution:
It can be observed that
[tex]m\angle UIJ+m\angle HIU=m\angle HIJ[/tex][tex]\begin{gathered} x+43+x+37=66^0 \\ Collect-like-terms \\ x+x+43^0+37^0=66^0 \\ 2x+80^0=66^0 \\ 2x=66^0-80^0 \\ 2x=-14^0 \\ x=-\frac{14^0}{2} \\ x=-7^0 \end{gathered}[/tex]Therefore, the measure of angle HIU would be
[tex]\begin{gathered} m\angle HIU=x+37^0 \\ m\angle HIU=-7+37^0 \\ m\angle HIU=30^0 \end{gathered}[/tex]Hence, the measure of angle HIU is 30⁰
About how much more is the total weight of the pacific halibut and conger than the weight of the yellowfin tuna ? Explain
The weight of pacific halibut is 459 pounds and weight of yellowfin tuna is 387 pounds.
There is 72 pounds more is the total weight of pacific halibut than the yellowfin tuna.
the Anderson are going on a long sailing trip during the summer however one of the sails on their sailboat ripped and they have to replace it the sail is pictured below if the sailboat sails are sale for 2$ per square foot how much will the new sail cost?
Firs we need to calculate the area of a triangle
[tex]A=\frac{b\cdot h}{2}[/tex]b= base
h=heigth
in our case
b=8ft
h=12ft
[tex]A=\frac{8\cdot12}{2}=\frac{96}{2}=48ft^2[/tex]then we will calculate the total cost
1 square foot ----- $2
48 square feet ----- x
the total cost is 48*2=96
total cost is $96
I thought of a number. from ²/₇ parts of that number I subtracted 0,4 and got ⅗. The number is: A: ²⁄₇ B: ⅖ C: 3,5D: 4,5
Note : The use of comma as number separator represent point in this solution
Step 1: Let the number be x, thus, 2/7 parts of the number means
[tex]\frac{2}{7}x[/tex]Step 2: Subtract 0,4 from 2/7 parts of x
[tex]\frac{2}{7}x-0,4\Rightarrow\frac{2}{7}x-\frac{4}{10}[/tex]Step 3: Equate the expression above to 3/5
[tex]\frac{2}{7}x-\frac{4}{10}=\frac{3}{5}[/tex]Step 4: Simplify the equation above
[tex]\begin{gathered} \frac{2}{7}x-\frac{4}{10}=\frac{3}{5} \\ \frac{20x-28}{70}=\frac{3}{5}(\text{cross multiply)} \\ 5(20x-28)=70(3) \\ 100x-140=210 \\ 100x=210+140 \\ 100x=350 \\ \frac{100x}{100}=\frac{350}{100}(\text{Divide both side by 100)} \\ x=3,5 \end{gathered}[/tex]Hence, the number is 3,5
Option C is correct
Two airplanes are flying in the air at the same height. Airplane A is flying east at 451 mi/h and airplane B is flying north at 494 mi/h. If they are both heading to the same airport, located 3 miles east of airplane A and 3 miles north of airplane B, at what rate is the distance between the airplanes changing?
The rate at which the distance between the airplanes is changing is 668.2 mi/h.
In the given question,
Speed of Airplane A:
dA/dt = 451 mi/h
and the Speed of Airplane B:
dB/dt = 494 mi/h
Aircraft A and B will form a right triangle because Aircraft A is flying east and Aircraft B is flying north, and we can use Pythagoras' theorem to calculate their distance from one another.
Let P be the distance.
P² = A² + B²
Differentiating the above equation with respect to t,
2P(dP/dt) = 2A(dA/dt) + 2B(dB/dt)
Dividing each side of the equation by 2,
P( dP/dt ) = A( dA/dt ) + B( dB/dt ) ..........(1)
Where dP/dt is the rate of change in distance between the two aircraft.
Now,
P² = A² + B²
P = √(A² + B²)
Substituting, A = 3 miles and B = 3miles;
P = √(3² + 3²)
P = √( 9+ 9)
P = √18
P = 3√2 miles
Substituting the value in the equation (i)
3√2 (dP/dt) = (3× 451) + (3× 494)
3√2 (dP/dt) = 2835
4.2426 × dP/dt = 2835
dP/dt = 2835/4.2426
dP/dt = 668.2 mi/h
Therefore, the rate at which the distance between the airplanes is changing is 668.2 mi/h
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Solve for x. Then find m
(8x+4)°
(10x-6)°
Both lines are intersecting and the two equations are vertical pairs
Answer:
x = 5
m∠QRT = 44
Step-by-step explanation:
8x + 4 = 10x - 6
-10x -10x
------------------------
-2x + 4 = -6
-4 -4
---------------------
-2x = -10
÷-2 ÷-2
--------------------
x = 5
m∠QRT
8x + 4
8(5) + 4
40 + 4 = 44
I hope this helps!
From the image, [tex](8x + 4 )° = (10x - 6)°[/tex]
Reason: Vertically opposite angles are equal.
Now, we solve for x
[tex]8x + 4 = 10x - 6[/tex]
collect like terms
[tex] 4 + 6 = 10x - 8x[/tex]
[tex]→ 10 = 2x[/tex]
Divide both sides by the coefficient of x to find the value of x
[tex] x = 5[/tex]
Now, substitute for the value of x in the expression for m∠QRT to find the degree
[tex](8x + 4 )° → (8(5) + 4)°[/tex]
Therefore: m∠QRT = 44°
I hope this helpsIf the function rule is to add 6, and an output value is 6, what is the input value?options:01-612
Given,
If the function rule is to add 6, and an output value is 6.
To find: What is the input value?
Solution:
When we add 0 to any number, we got the same number.
So adding 0 with 6 we get the same number 6.
[tex]6+0=6[/tex]Thus, the answer 0 is the correct option.
